human
What is a code to diameter of a Binary Indexed Tree with N nodes and the other steps required given the following:
Diameter of a Binary Indexed Tree with N nodes | Function to find diameter of BIT with N + 1 nodes.
L is size of subtree just before subtree in which N lies.
H is the height of subtree just before subtree in which N lies.
Base Cases.
Size of subtree are power of 2.
3 Cases as explained in Approach.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to diameter of a Binary Indexed Tree with N nodes and the other steps required.
 def diameter ( n ) :
	L , H , templen = 0 , 0 , 0 ;
	L = 1 ;
	H = 0 ;
	if ( n == 1 ) :
		return 1 ;
	if ( n == 2 ) :
		return 2 ;
	if ( n == 3 ) :
		return 3 ;
	while ( L * 2 <= n ) :
		L *= 2 ;
		H += 1 ;
	if ( n >= L * 2 - 1 ) :
		return 2 * H + 1 ;
	elif ( n >= L + ( L / 2 ) - 1 ) :
		return 2 * H ;
	return 2 * H - 1 ;
n = 15 ;
print ( diameter ( n ) ) ;