human
Can you provide a code to minimize count of unequal elements at corresponding indices between given arrays and the other steps required given the following:
Minimize count of unequal elements at corresponding indices between given arrays | Function that count of the mismatched pairs in bot the array.
Create a parent array and initialize it.
Preprocessing of the given pairs of indices.
1 - based indexing.
If both indices doesn 't belong  to same component.
Insert the indices in same component.
HashMap to get the indices of array A.
If current element is not present in array B then count this as mismatched.
Get the index of the element in array B.
Check if both indices belong to same connected component if not increment the count.
Return answer.
Function that gives the connected component of each index.
Function that creates the connected components.
Find parent of a and b recursively.
Update the parent of a.
Driver Code.
Given arrays A [ ] , B [ ].
List of indices.
Function call"
How can the above be solved in Python?
assistant
#Here is code to minimize count of unequal elements at corresponding indices between given arrays and the other steps required.
 def countPairs ( A , B , N , M , List ) :
	count = 0
	par = [ 0 ] * ( N + 1 )
	for i in range ( N + 1 ) :
		par [ i ] = i
	for i in range ( M ) :
		index1 = find ( par , List [ i ] [ 0 ] - 1 )
		index2 = find ( par , List [ i ] [ 1 ] - 1 )
		if ( index1 != index2 ) :
			union ( par , index1 , index2 )
	map = { }
	for i in range ( N ) :
		map [ A [ i ] ] = i
	for i in range ( N ) :
		if ( A [ i ] != B [ i ] ) :
			if ( B [ i ] not in map . keys ( ) ) :
				count += 1
				continue
			j = map [ B [ i ] ]
			if ( find ( par , i ) != find ( par , j ) ) :
				count += 1
	return count
def find ( par , x ) :
	if ( par [ x ] == x ) :
		return x
	else :
		par [ x ] = find ( par , par [ x ] )
		return par [ x ]
def union ( par , a , b ) :
	a = find ( par , a )
	b = find ( par , b )
	if ( a == b ) :
		return
	par [ a ] = b
N = 5
M = 4
A = [ 1 , 5 , 9 , 2 , 3 ]
B = [ 2 , 4 , 5 , 1 , 3 ]
List = [ [ 1 , 4 ] , [ 2 , 3 ] , [ 3 , 5 ] , [ 2 , 5 ] ]
print ( countPairs ( A , B , N , M , List ) )