human
What is a code to count of Reverse Bitonic Substrings in a given String and the other steps required given the following:
Count of Reverse Bitonic Substrings in a given String | Function to calculate the number of reverse bitonic substrings.
Stores the count.
All possible lengths of substrings.
Starting poof a substring.
Ending poof a substring.
Condition for reverse bitonic substrings of length 1.
Check for decreasing sequence.
If end of substring is reache.
For increasing sequence.
If end of substring is reached.
Return the number of bitonic substrings.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count of Reverse Bitonic Substrings in a given String and the other steps required.
 def CountsubString ( strr , n ) :
	c = 0
	for len in range ( n + 1 ) :
		for i in range ( n - len ) :
			j = i + len - 1
			temp = strr [ i ]
			f = 0
			if ( j == i ) :
				c += 1
				continue
			k = i + 1
			while ( k <= j and temp > strr [ k ] ) :
				temp = strr [ k ]
				k += 1
			if ( k > j ) :
				c += 1
				f = 2
			while ( k <= j and f != 2 and temp < strr [ k ] ) :
				temp = strr [ k ]
				k += 1
			if ( k > j and f != 2 ) :
				c += 1
				f = 0
	return c
if __name__ == ' _ _ main _ _ ' :
	strr = " bade "
	print ( CountsubString ( strr , len ( strr ) ) )