human
Count of pairs of ( i , j ) such that ( ( n % i ) % j ) % n is maximized | Function to return the count of required pairs.
Number which will give the Max value for ( ( n % i ) % j ) % n.
To store the Maximum possible value of ( ( n % i ) % j ) % n.
To store the count of possible pairs.
Check all possible pairs.
Calculating the value of ( ( n % i ) % j ) % n.
If value is equal to Maximum.
Return the number of possible pairs.
Driver code"
Solution in Python:

Write me a code to count of pairs of ( i , j ) such that ( ( n % i ) % j ) % n is maximized and the other steps required?
assistant
#Here is code to count of pairs of ( i , j ) such that ( ( n % i ) % j ) % n is maximized and the other steps required.
 def countPairs ( n ) :
	num = ( ( n // 2 ) + 1 )
	Max = n % num
	count = 0
	for i in range ( 1 , n + 1 ) :
		for j in range ( 1 , n + 1 ) :
			val = ( ( n % i ) % j ) % n
			if ( val == Max ) :
				count += 1
	return count
n = 5
print ( countPairs ( n ) )