human
I found an interesting problem on https://leetcode.com/problems/k-th-symbol-in-grammar/:
On the first row, we write a 0. Now in every subsequent row, we look at the previous row and replace each occurrence of 0 with 01, and each occurrence of 1 with 10.

Given row N and index K, return the K-th indexed symbol in row N. (The values of K are 1-indexed.) (1 indexed).

Examples:
Input: N = 1, K = 1
Output: 0

Input: N = 2, K = 1
Output: 0

Input: N = 2, K = 2
Output: 1

Input: N = 4, K = 5
Output: 1

Explanation:
row 1: 0
row 2: 01
row 3: 0110
row 4: 01101001

Note:

       N will be an integer in the range [1, 30].
       K will be an integer in the range [1, 2^(N-1)].

I tried it in Python, but could not do it. Can you solve it?

Write me a the Python code you requested?
assistant
#Here is the Python code you requested.

import math
 class Solution:
     def maxChunksToSorted(self, arr):
         count = 0
 
         minVal = [0] * len(arr)
         minSofar = math.inf
         for idx in reversed(range(len(arr))):
             minVal[idx] = min(minSofar, arr[idx])
             minSofar = minVal[idx]
 
         maxSofar = -math.inf
         for idx in range(len(arr)):
             maxSofar = max(maxSofar, arr[idx])
             if idx == len(arr) - 1:
                 count += 1
             elif maxSofar <= minVal[idx+1]:
                 count+=1
 
 
         return count