human
Given a sorted and rotated array , find if there is a pair with a given sum | This function returns True if arr [ 0. . n - 1 ] has a pair with sum equals to x ..
Find the pivot element.
l is now index of smallest element.
r is now index of largest element.
Keep moving either l or r till they meet.
If we find a pair with sum x , we return True.
If current pair sum is less , move to the higher sum.
Move to the lower sum side.
Driver program to test above function"
Solution in Python:
 Give me a code to given a sorted and rotated array , find if there is a pair with a given sum and the other steps required?
assistant
#Here is code to given a sorted and rotated array , find if there is a pair with a given sum and the other steps required.
 def pairInSortedRotated ( arr , n , x ) :
	for i in range ( 0 , n - 1 ) :
		if ( arr [ i ] > arr [ i + 1 ] ) :
			break ;
	l = ( i + 1 ) % n
	r = i
	while ( l != r ) :
		if ( arr [ l ] + arr [ r ] == x ) :
			return True ;
		if ( arr [ l ] + arr [ r ] < x ) :
			l = ( l + 1 ) % n ;
		else :
			r = ( n + r - 1 ) % n ;
	return False ;
arr = [ 11 , 15 , 6 , 8 , 9 , 10 ]
sum = 16
n = len ( arr )
if ( pairInSortedRotated ( arr , n , sum ) ) :
	print ( " Array ▁ has ▁ two ▁ elements ▁ with ▁ sum ▁ 16" )
else :
	print ( " Array ▁ doesn ' t ▁ have ▁ two ▁ elements ▁ with ▁ sum ▁ 16 ▁ " )