human
Solve in Python:
You are given an array nums of non-negative integers. nums is considered special if there exists a number x such that there are exactly x numbers in nums that are greater than or equal to x.
Notice that x does not have to be an element in nums.
Return x if the array is special, otherwise, return -1. It can be proven that if nums is special, the value for x is unique.
 
Example 1:
Input: nums = [3,5]
Output: 2
Explanation: There are 2 values (3 and 5) that are greater than or equal to 2.

Example 2:
Input: nums = [0,0]
Output: -1
Explanation: No numbers fit the criteria for x.
If x = 0, there should be 0 numbers >= x, but there are 2.
If x = 1, there should be 1 number >= x, but there are 0.
If x = 2, there should be 2 numbers >= x, but there are 0.
x cannot be greater since there are only 2 numbers in nums.

Example 3:
Input: nums = [0,4,3,0,4]
Output: 3
Explanation: There are 3 values that are greater than or equal to 3.

Example 4:
Input: nums = [3,6,7,7,0]
Output: -1

 
Constraints:

1 <= nums.length <= 100
0 <= nums[i] <= 1000
 ... Can you provide a the Python code you requested?
assistant
#Here is the Python code you requested.

class Solution:
    def specialArray(self, nums: List[int]) -> int:
        # n --> length of given array
        n = len(nums)
        
        # temporary array with all elements 0
        temp = [0 for i in range(n)]
        
        # if all elements are 0 then given array is not special
        if nums==temp:
            return -1
        
        # check for each number from 0 to 1000 that for ith number there are exactly i numbers greater than or equal to i.
        for x in range(1001):
            cnt = 0
            for i in nums:
                if i>=x:
                    cnt+=1
            if cnt==x:
                return x
        return -1