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Check if any pair of consecutive 1 s can be separated by at most M 0 s by circular rotation of a Binary String | Function to check if any pair of consecutive 1 s can be separated by at most M 0 s by circular rotation of string S.
Stores the indices of all 1 s.
Store the number of pairs separated by at least M 0 s.
Traverse the string.
Store the current index.
Traverse the array containing indices.
If the number of 0 s > M , then increment cnt by 1.
Increment cnt.
Check if at least M '0' s lie between the first and last occurrence of '1.
Increment cnt.
If the value of cnt <= 1 , then rotation of string is possible.
Otherwise.
Driver Code"
Solution in Python:

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What is a code to check if any pair of consecutive 1 s can be separated by at most M 0 s by circular rotation of a Binary String and the other steps required?
assistant
#Here is code to check if any pair of consecutive 1 s can be separated by at most M 0 s by circular rotation of a Binary String and the other steps required.
 def rotateString ( n , m , s ) :
	v = [ ]
	cnt = 0
	for i in range ( n ) :
		if ( s [ i ] == '1' ) :
			v . append ( i )
	for i in range ( 1 , len ( v ) ) :
		if ( ( v [ i ] - v [ i - 1 ] - 1 ) > m ) :
			cnt += 1
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	if ( len ( v ) >= 2 and ( n - ( v [ - 1 ] - v [ 0 ] ) - 1 ) > m ) :
		cnt += 1
	if ( cnt <= 1 ) :
		print ( " Yes " )
	else :
		print ( " No " )
if __name__ == ' _ _ main _ _ ' :
	S = "101001"
	M = 1
	N = len ( S )
	rotateString ( N , M , S )