human
Minimum number of swaps required for arranging pairs adjacent to each other | This function updates indexes of elements ' a ' and 'b  .
This function returns minimum number of swaps required to arrange all elements of arr [ i . . n ] become arranged.
If all pairs procesed so no swapping needed return 0.
If current pair is valid so DO NOT DISTURB this pair and move ahead ..
Swap pair of arr [ i ] with arr [ i + 1 ] and recursively compute minimum swap required if this move is made ..
Backtrack to previous configuration . Also restore the previous indices , of one and two.
Now swap arr [ i ] with pair of arr [ i + 1 ] and recursively compute minimum swaps required for the subproblem after this move.
Backtrack to previous configuration . Also restore 3 the previous indices , of one and two.
Return minimum of two cases.
Returns minimum swaps required.
To store indices of array elements.
Store index of each element in array index.
Call the recursive function.
For simplicity , it is assumed that arr [ 0 ] is not used . The elements from index 1 to n are only valid elements.
if ( a , b ) is pair than we have assigned elements in array such that pairs [ a ] = b and pairs [ b ] = a.
Number of pairs n is half of total elements.
If there are n elements in array , then there are n pairs"
How can the above be solved in Python?
assistant
#Here is code to minimum number of swaps required for arranging pairs adjacent to each other and the other steps required.
 def updateindex ( index , a , ai , b , bi ) :
	index [ a ] = ai
	index [ b ] = bi
def minSwapsUtil ( arr , pairs , index , i , n ) :
	if ( i > n ) :
		return 0
	if ( pairs [ arr [ i ] ] == arr [ i + 1 ] ) :
		return minSwapsUtil ( arr , pairs , index , i + 2 , n )
	one = arr [ i + 1 ]
	indextwo = i + 1
	indexone = index [ pairs [ arr [ i ] ] ]
	two = arr [ index [ pairs [ arr [ i ] ] ] ]
	arr [ i + 1 ] , arr [ indexone ] = arr [ indexone ] , arr [ i + 1 ]
	updateindex ( index , one , indexone , two , indextwo )
	a = minSwapsUtil ( arr , pairs , index , i + 2 , n )
	arr [ i + 1 ] , arr [ indexone ] = arr [ indexone ] , arr [ i + 1 ]
	updateindex ( index , one , indextwo , two , indexone )
	one = arr [ i ]
	indexone = index [ pairs [ arr [ i + 1 ] ] ]
	two = arr [ index [ pairs [ arr [ i + 1 ] ] ] ]
	indextwo = i
	arr [ i ] , arr [ indexone ] = arr [ indexone ] , arr [ i ]
	updateindex ( index , one , indexone , two , indextwo )
	b = minSwapsUtil ( arr , pairs , index , i + 2 , n )
	arr [ i ] , arr [ indexone ] = arr [ indexone ] , arr [ i ]
	updateindex ( index , one , indextwo , two , indexone )
	return 1 + min ( a , b )
def minSwaps ( n , pairs , arr ) :
	index = [ ]
	for i in range ( 2 * n + 1 + 1 ) :
		index . append ( 0 )
	for i in range ( 1 , 2 * n + 1 ) :
		index [ arr [ i ] ] = i
	return minSwapsUtil ( arr , pairs , index , 1 , 2 * n )
arr = [ 0 , 3 , 5 , 6 , 4 , 1 , 2 ]
pairs = [ 0 , 3 , 6 , 1 , 5 , 4 , 2 ]
m = len ( pairs )
n = m // 2
print ( " Min ▁ swaps ▁ required ▁ is ▁ " , minSwaps ( n , pairs , arr ) )