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Count numbers whose XOR with N is equal to OR with N | Function to calculate count of numbers with XOR equals OR.
variable to store count of unset bits.
Driver code"
Solution in Python:
assistant
#Here is code to count numbers whose XOR with N is equal to OR with N and the other steps required.
 def xorEqualsOrCount ( N ) :
	count = 0
	while ( N > 0 ) :
		bit = N % 2
		if bit == 0 :
			count += 1
		N //= 2
	return int ( pow ( 2 , count ) )
if __name__ == " _ _ main _ _ " :
	N = 7
	print ( xorEqualsOrCount ( N ) )