human
Minimize the maximum difference of any pair by doubling odd elements and reducing even elements by half | Function to minimize the maximum difference between any pair of elements of the array by the given operations.
Traverse the array.
If current element is even.
Insert it into even.
Otherwise.
Make it even by multiplying by 2 and insert it into set.
Calculate difference between first and the last element of the set.
Iterate until difference is minimized.
Erase the current element.
Reduce current element by half and insert it into the Set.
Update difference.
Return the resultant difference.
Driver Code"
Solution in Python:
assistant
#Here is code to minimize the maximum difference of any pair by doubling odd elements and reducing even elements by half and the other steps required.
 def minimumMaxDiff ( nums ) :
	s = { }
	for i in range ( len ( nums ) ) :
		if ( nums [ i ] % 2 == 0 ) :
			s [ nums [ i ] ] = 1
		else :
			s [ nums [ i ] * 2 ] = 1
	sr = list ( s . keys ( ) )
	res = sr [ - 1 ] - sr [ 0 ]
	while ( list ( s . keys ( ) ) [ - 1 ] % 2 == 0 ) :
		r = list ( s . keys ( ) )
		x = r [ - 1 ]
		del s [ x ]
		s [ x // 2 ] = 1
		rr = list ( s . keys ( ) )
		res = min ( res , rr [ - 1 ] - r [ 0 ] )
	return res
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 5 , 9 ]
	print ( minimumMaxDiff ( arr ) )