human
Solve the following python programming problem given the following code:
def assertDictListMatch(self, L1, L2, approx_equal = False, tolerance = 0.001) : 
    'Assert a list of dicts are equivalent.' 
    def raise_assertion(msg) : 
        L1str = str (L1) 
        L2str = str (L2) 
        base_msg = ('List of dictionaries do not match: %(msg)s L1: %(L1str)s L2: %(L2str)s' % locals ()) 
        raise AssertionError (base_msg) 
L1count = len (L1) 
    L2count = len (L2) 
    if (L1count != L2count) : 
        raise_assertion (('Length mismatch: len(L1)=%(L1count)d != len(L2)=%(L2count)d' % locals ())) 
for (d1, d2) in zip (L1, L2) : 
        self.assertDictMatch (d1, d2, approx_equal = approx_equal, tolerance = self) 

    
    

    Fix the buggy line: self.assertDictMatch (d1, d2, approx_equal = approx_equal, tolerance = self)
assistant
#Here is Python code to fix the buggy line: self.

self.assertDictMatch (d1, d2, approx_equal = approx_equal, tolerance = tolerance)