human
Give me a code to numbers having difference with digit sum more than s and the other steps required given the following:
Numbers having difference with digit sum more than s | function for digit sum.
function to calculate count of integer s . t . integer - digSum > s.
if n < s no integer possible.
iterate for s range and then calculate total count of such integer if starting integer is found.
if no integer found return 0.
driver code"
Solution in Python:
assistant
#Here is code to numbers having difference with digit sum more than s and the other steps required.
 def digitSum ( n ) :
	digSum = 0
	while ( n > 0 ) :
		digSum += n % 10
		n //= 10
	return digSum
def countInteger ( n , s ) :
	if ( n < s ) :
		return 0
	for i in range ( s , min ( n , s + 163 ) + 1 ) :
		if ( ( i - digitSum ( i ) ) > s ) :
			return ( n - i + 1 )
	return 0
n = 1000
s = 100
print ( countInteger ( n , s ) )