human
Largest number smaller than or equal to n and digits in non | Returns the required number.
loop to recursively check the numbers less than or equal to given number.
Keep traversing digits from right to left . For every digit check if it is smaller than prev_dig.
We found the required number.
Driver Code"
Solution in Python:
assistant
#Here is code to largest number smaller than or equal to n and digits in non and the other steps required.
 def nondecdigits ( n ) :
	x = 0
	for x in range ( n , 0 , - 1 ) :
		no = x
		prev_dig = 11
		flag = True
		while ( no != 0 ) :
			if ( prev_dig < no % 10 ) :
				flag = False
				break
			prev_dig = no % 10
			no //= 10
		if ( flag == True ) :
			break
	return x
if __name__ == " _ _ main _ _ " :
	n = 200
	print ( nondecdigits ( n ) )