human
Last element of an array after repeatedly removing the first element and appending it to the end of the array twice exactly K times | Function to find the last element after performing given operations.
Length of the array.
Increment j until condition is satisfied.
In each pair every value is repeating r number of times.
Print the result according to the value of k.
Driver Code.
Given K.
Given arr [ ].
Function call"
How can the above be solved in Python?
 Can you provide a code to last element of an array after repeatedly removing the first element and appending it to the end of the array twice exactly K times and the other steps required?
assistant
#Here is code to last element of an array after repeatedly removing the first element and appending it to the end of the array twice exactly K times and the other steps required.
 def findLastElement ( N , A ) :
	l = len ( A )
	j = 0
	while ( N > l * ( 2 ** j ) ) :
		N = N - l * 2 ** j
		j += 1
	k = 1
	r = 2 ** j
	for i in range ( 1 , l ) :
		if N > r * i :
			k += 1
	for i in range ( 0 , len ( A ) ) :
		if ( i + 1 == k ) :
			print ( A [ i ] )
			return
if __name__ == ' _ _ main _ _ ' :
	K = 7
	A = [ 1 , 2 , 3 ]
	findLastElement ( K , A )