human
Count integers from a given range with no odd divisors | Function to count integers in the range 1 to N having no odd divisors.
Traverse the array.
Stores the nearest power of two less than arr [ i ].
Stores the count of integers with no odd divisor for each query.
Iterate until powerOfTwo is less then or equal to arr [ i ].
Print the answer for the current element.
Driver Code.
Given array.
Size of the array"
Solution in Python:
 ... Give me a code to count integers from a given range with no odd divisors and the other steps required?
assistant
#Here is code to count integers from a given range with no odd divisors and the other steps required.
 def oddDivisors ( arr , N ) :
	for i in range ( N ) :
		powerOfTwo = 2 ;
		count = 0 ;
		while ( powerOfTwo <= arr [ i ] ) :
			count += 1 ;
			powerOfTwo = 2 * powerOfTwo ;
		print ( count , end = " ▁ " ) ;
if __name__ == " _ _ main _ _ " :
	arr = [ 15 , 16 , 20 , 35 ] ;
	N = len ( arr ) ;
	oddDivisors ( arr , N ) ;