human
Minimum moves to make count of lowercase and uppercase letters equal | Function to calculate minimum number of moves required to convert the string.
Stores Count of upper and lower case characters.
Traverse the S.
If current character is uppercase.
Increment count of Uppercase characters.
Otherwise ,.
Increment count of Lowercase characters.
Stores minimum number of moves needed.
If there are more upper case characters.
Iterate until upper is greater than N / 2.
Convert uppercase into lowercase until upper = N / 2.
Increment the pointer.
If there are more lower case characters.
Iterate until lower is greater than N / 2.
Convert lowercase into uppercase until lower = N / 2.
Increment the pointer.
Print moves required.
Print resultant string.
Driver Code.
Given string.
Function call"
How can the above be solved in Python?
 Can you provide a code to minimum moves to make count of lowercase and uppercase letters equal and the other steps required?
assistant
#Here is code to minimum moves to make count of lowercase and uppercase letters equal and the other steps required.
 def minimumTimeToConvertString ( S , N ) :
	S = [ i for i in S ]
	upper = 0
	lower = 0
	for i in range ( N ) :
		c = S [ i ]
		if ( c . isupper ( ) ) :
			upper += 1
		else :
			lower += 1
	moves = 0
	if ( upper > N // 2 ) :
		i = 0
		while ( upper > N // 2 and i < N ) :
			if ( S [ i ] . isupper ( ) ) :
				S [ i ] += 32
				moves += 1
				upper -= 1
				lower += 1
			i += 1
	elif ( lower > N // 2 ) :
		i = 0
		while ( lower > N // 2 and i < N ) :
			if ( S [ i ] . islower ( ) ) :
				S [ i ] = chr ( ord ( S [ i ] ) - 32 )
				moves += 1
				upper += 1
				lower -= 1
			i += 1
	print ( moves )
	print ( " " . join ( S ) )
if __name__ == ' _ _ main _ _ ' :
	S = " AbcdEf "
	N = len ( S )
	minimumTimeToConvertString ( S , N )