human
Find minimum time to finish all jobs with given constraints | Utility function to get maximum element in job [ 0. . n - 1 ].
Returns true if it is possible to finish jobs [ ] within given time 'time.
cnt is count of current assignees required for jobs.
time assigned to current assignee.
If time assigned to current assignee exceeds max , increment count of assignees ..
Else add time of job to current time and move to next job ..
Returns true if count is smaller than k.
Returns minimum time required to finish given array of jobs k -- > number of assignees T -- > Time required by every assignee to finish 1 unit m -- > Number of jobs.
Set start and end for binary search end provides an upper limit on time.
Find the job that takes maximum time.
Do binary search for minimum feasible time.
If it is possible to finish jobs in mid time.
ans = min ( ans , mid ) Update answer.
Driver program"
Solution in Python:

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Write me a code to find minimum time to finish all jobs with given constraints and the other steps required?
assistant
#Here is code to find minimum time to finish all jobs with given constraints and the other steps required.
 def getMax ( arr , n ) :
	result = arr [ 0 ]
	for i in range ( 1 , n ) :
		if arr [ i ] > result :
			result = arr [ i ]
	return result
'
def isPossible ( time , K , job , n ) :
	cnt = 1
	curr_time = 0
	i = 0
	while i < n :
		if curr_time + job [ i ] > time :
			curr_time = 0
			cnt += 1
		else :
			curr_time += job [ i ]
			i += 1
	return cnt <= K
def findMinTime ( K , T , job , n ) :
	end = 0
	start = 0
	for i in range ( n ) :
		end += job [ i ]
	job_max = getMax ( job , n )
	while start <= end :
		mid = int ( ( start + end ) / 2 )
		if mid >= job_max and isPossible ( mid , K , job , n ) :
			end = mid - 1
		else :
			start = mid + 1
	return ans * T
if __name__ == ' _ _ main _ _ ' :
	job = [ 10 , 7 , 8 , 12 , 6 , 8 ]
	n = len ( job )
	k = 4
	T = 5
	print ( findMinTime ( k , T , job , n ) )