human
Subsequences of given string consisting of non | Function to find all the subsequences of the str1ing with non - repeating ch1aracters.
Base case.
Insert current subsequence.
If str1 [ i ] is not present in the current subsequence.
Insert str1 [ i ] into the set.
Insert str1 [ i ] into the current subsequence.
Remove str1 [ i ] from current subsequence.
Remove str1 [ i ] from the set.
Not including str1 [ i ] from the current subsequence.
Utility function to print all subsequences of str1ing with non - repeating ch1aracters.
Stores all possible subsequences with non - repeating ch1aracters.
Stores subsequence with non - repeating ch1aracters.
Traverse all possible subsequences containing non - repeating ch1aracters.
Print subsequence.
Driver Code"
Solution in Python:
 ... Can you provide a code to subsequences of given string consisting of non and the other steps required?
assistant
#Here is code to subsequences of given string consisting of non and the other steps required.
 def FindSub ( sub , ch1 , str1 , res , i ) :
	if ( i == len ( str1 ) ) :
		sub . add ( res )
		return
	if ( str1 [ i ] not in ch1 ) :
		ch1 . add ( str1 [ i ] )
		FindSub ( sub , ch1 , str1 , res + str1 [ i ] , i + 1 )
		res += str1 [ i ]
		res = res [ 0 : len ( res ) - 1 ]
		ch1 . remove ( str1 [ i ] )
	FindSub ( sub , ch1 , str1 , res , i + 1 )
def printSubwithUniquech1ar ( str1 , N ) :
	sub = set ( )
	ch1 = set ( )
	FindSub ( sub , ch1 , str1 , " " , 0 )
	temp = [ ]
	for substr1ing in sub :
	temp . append ( substr1ing )
	temp . sort ( reverse = False )
	for x in temp :
	print ( x , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	str2 = " abac "
	N = len ( str2 )
	printSubwithUniquech1ar ( str2 , N )