human
Write me a code to fill the missing numbers in the array of N natural numbers such that arr [ i ] not equal to i and the other steps required given the following:
Fill the missing numbers in the array of N natural numbers such that arr [ i ] not equal to i | Function to fill the position with arr [ i ] = 0.
Inserting all elements in missing [ ] set from 1 to N.
Inserting unfilled positions.
Removing allocated_elements.
Loop for filling the positions with arr [ i ] != i.
Checking for any arr [ i ] = i.
Finding the suitable position in the array to swap with found i for which arr [ i ] = i.
Checking if the position is present in unfilled_position.
Swapping arr [ i ] & arr [ pos ] ( arr [ pos ] = pos ).
Function to Print the array.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to fill the missing numbers in the array of N natural numbers such that arr [ i ] not equal to i and the other steps required.
 def solve ( arr , n ) :
	unfilled_indices = { }
	missing = { }
	for i in range ( n ) :
		missing [ i ] = 1
	for i in range ( 1 , n ) :
		if ( arr [ i ] == 0 ) :
			unfilled_indices [ i ] = 1
		else :
			del missing [ arr [ i ] ]
	it2 = list ( missing . keys ( ) )
	m = len ( it2 )
	for it in unfilled_indices :
		arr [ it ] = it2 [ m - 1 ]
		m -= 1
	pos = 0
	for i in range ( 1 , n ) :
		if ( arr [ i ] == i ) :
			pos = i
	x = 0
	if ( pos != 0 ) :
		for i in range ( 1 , n ) :
			if ( pos != i ) :
				if i in unfilled_indices :
					x = arr [ i ]
					arr [ i ] = pos
					arr [ pos ] = x
					break
	printArray ( arr , n )
def printArray ( arr , n ) :
	for i in range ( 1 , n ) :
		print ( arr [ i ] , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 0 , 7 , 4 , 0 , 3 , 0 , 5 , 1 ]
	n = len ( arr )
	solve ( arr , n )