human
Can you provide a code to toggle all even bits of a number and the other steps required given the following:
Toggle all even bits of a number | Returns a number which has all even bits of n toggled ..
Generate number form of 101010 . . till of same order as n.
if bit is even then generate number and or with res.
return toggled number.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to toggle all even bits of a number and the other steps required.
 def evenbittogglenumber ( n ) :
	res = 0
	count = 0
	temp = n
	while ( temp > 0 ) :
		if ( count % 2 == 1 ) :
			res = res | ( 1 << count )
		count = count + 1
		temp >>= 1
	return n ^ res
n = 11
print ( evenbittogglenumber ( n ) )