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Minimize remaining array element by removing pairs and replacing them by their absolute difference | function to find the smallest element left in the array by the given operations.
Base Case.
If this subproblem has occurred previously.
Including i - th array element into the first subset.
If i - th array element is not selected.
Update dp [ i ] [ sum ].
Utility function to find smallest element left in the array by the given operations.
Stores sum of the array elements.
Traverse the array.
Update total.
Stores overlapping subproblems.
Driver Code"
Solution in Python:
 ... What is a code to minimize remaining array element by removing pairs and replacing them by their absolute difference and the other steps required?
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#Here is code to minimize remaining array element by removing pairs and replacing them by their absolute difference and the other steps required.
 def smallestLeft ( arr , total , sum , i , dp ) :
	if ( i == 0 ) :
		return abs ( total - 2 * sum )
	if ( dp [ i ] [ sum ] != - 1 ) :
		return dp [ i ] [ sum ]
	X = smallestLeft ( arr , total , sum + arr [ i - 1 ] , i - 1 , dp )
	Y = smallestLeft ( arr , total , sum , i - 1 , dp )
	dp [ i ] [ sum ] = min ( X , Y )
	return dp [ i ] [ sum ]
def UtilSmallestElement ( arr , N ) :
	total = 0
	for i in range ( 0 , N ) :
		total += arr [ i ]
	dp = [ [ - 1 for y in range ( total ) ] for x in range ( N + 1 ) ]
	print ( smallestLeft ( arr , total , 0 , N , dp ) )
arr = [ 2 , 7 , 4 , 1 , 8 , 1 ]
N = len ( arr )
UtilSmallestElement ( arr , N )