human
Chocolate Distribution Problem | Set 2 | Function to return minimum number of chocolates.
decreasing sequence.
add the chocolates received by that person.
end point of decreasing sequence.
val = 1 reset value at that index.
increasing sequence.
flat sequence.
add value of chocolates at position n - 1.
Helper function to get sum of decreasing sequence.
value obtained from decreasing sequence also the count of values in the sequence.
assigning max of values obtained from increasing and decreasing sequences.
sum of count - 1 values & peak value sum of natural numbers : ( n * ( n + 1 ) ) / 2.
Driver code"
Solution in Python:

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Can you provide a code to chocolate Distribution Problem and the other steps required?
assistant
#Here is code to chocolate Distribution Problem and the other steps required.
 def minChocolates ( a , n ) :
	i , j = 0 , 0
	val , res = 1 , 0
	while ( j < n - 1 ) :
		if ( a [ j ] > a [ j + 1 ] ) :
			j += 1
			continue
		if ( i == j ) :
			res += val
		else :
			res += get_sum ( val , i , j )
		if ( a [ j ] < a [ j + 1 ] ) :
			val += 1
		else :
			val = 1
		j += 1
		i = j
	if ( i == j ) :
		res += val
	else :
		res += get_sum ( val , i , j )
	return res
def get_sum ( peak , start , end ) :
	count = end - start + 1
	peak = max ( peak , count )
	s = peak + ( ( ( count - 1 ) * count ) >> 1 )
	return s
if __name__ == ' _ _ main _ _ ' :
	a = [ 5 , 5 , 4 , 3 , 2 , 1 ]
	n = len ( a )
	print ( ' Minimum ▁ number ▁ of ▁ chocolates ▁ = ' , minChocolates ( a , n ) )