human
Give me a code to count Distinct Non and the other steps required given the following:
Count Distinct Non | This function counts number of pairs ( x , y ) that satisfy the inequality x * x + y * y < n ..
Driver program to test above function"
How can the above be solved in Python?
assistant
#Here is code to count Distinct Non and the other steps required.
 def countSolutions ( n ) :
	res = 0
	x = 0
	while ( x * x < n ) :
		y = 0
		while ( x * x + y * y < n ) :
			res = res + 1
			y = y + 1
		x = x + 1
	return res
if __name__ == ' _ _ main _ _ ' :
	print ( " Total ▁ Number ▁ of ▁ distinct ▁ Non - Negative ▁ pairs ▁ is ▁ " , countSolutions ( 6 ) )