human
Can you provide a Python program to print one integer — the value of $\sum\limits_{i=1}^{n} \sum\limits_{j=1}^{n} f(t, s_i + s_j)$ given the following:
I found an interesting problem on https://codeforces.com/problemset/problem/1202/E:
You are given a string $t$ and $n$ strings $s_1, s_2, \dots, s_n$. All strings consist of lowercase Latin letters.

Let $f(t, s)$ be the number of occurences of string $s$ in string $t$. For example, $f('\text{aaabacaa}', '\text{aa}') = 3$, and $f('\text{ababa}', '\text{aba}') = 2$.

Calculate the value of $\sum\limits_{i=1}^{n} \sum\limits_{j=1}^{n} f(t, s_i + s_j)$, where $s + t$ is the concatenation of strings $s$ and $t$. Note that if there are two pairs $i_1$, $j_1$ and $i_2$, $j_2$ such that $s_{i_1} + s_{j_1} = s_{i_2} + s_{j_2}$, you should include both $f(t, s_{i_1} + s_{j_1})$ and $f(t, s_{i_2} + s_{j_2})$ in answer.

-----Input-----

The first line contains string $t$ ($1 \le |t| \le 2 \cdot 10^5$).

The second line contains integer $n$ ($1 \le n \le 2 \cdot 10^5$).

Each of next $n$ lines contains string $s_i$ ($1 \le |s_i| \le 2 \cdot 10^5$).

It is guaranteed that $\sum\limits_{i=1}^{n} |s_i| \le 2 \cdot 10^5$. All strings consist of lowercase English letters.

-----Output-----

Print one integer — the value of $\sum\limits_{i=1}^{n} \sum\limits_{j=1}^{n} f(t, s_i + s_j)$.

-----Examples-----
Input
aaabacaa
2
a
aa

Output
5

Input
aaabacaa
4
a
a
a
b

Output
33

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is Python program to print one integer — the value of $\sum\limits_{i=1}^{n} \sum\limits_{j=1}^{n} f(t, s_i + s_j)$.

class Node(object):
    def __init__(self):
        super(Node, self).__init__()
        self.next = [-1] * 26
        self.trans = []
        self.matches = 0
        self.leaf = 0
        self.link = 0

class AhoCorasick(object):
    def __init__(self):
        super(AhoCorasick, self).__init__()
        self.T = [Node()]
        self.T[0].link = 0

    def insert_trie(self, s):
        v = 0
        for i in range(len(s)):
            c = ord(s[i]) - ord('a')
            if(self.T[v].next[c] == -1):
                self.T[v].trans.append(c)
                self.T[v].next[c] = len(self.T)
                self.T.append(Node())
            v = self.T[v].next[c]
        self.T[v].leaf += 1
        self.T[v].matches += 1

    def set_suffix_link(self, S):
        Q = []
        for j in range(len(S)):
            Q.append((j, 0, 0, 0))
            #string index, index in string, state, suff state, 
        i = 0
        while(i < len(Q)):
            j,ind,v,suff = Q[i]
            i += 1
            c = ord(S[j][ind]) - ord('a')
            if(ind>0):
                while(suff>0 and self.T[suff].next[c]==-1):
                    suff = self.T[suff].link
                if(self.T[suff].next[c] != -1):
                    suff = self.T[suff].next[c]
            v = self.T[v].next[c]
            self.T[v].link = suff
            if(ind+1 < len(S[j])):
                Q.append((j,ind+1,v,suff))

    def set_matches(self):
        i = 0
        Q = [0]
        while(i < len(Q)):
            v = Q[i]
            self.T[v].matches = self.T[v].leaf + self.T[self.T[v].link].matches
            for c in self.T[v].trans:
                Q.append(self.T[v].next[c])
            i += 1

    def build(self, S):
        for i in range(len(S)):
            self.insert_trie(S[i])
        self.set_suffix_link(S)
        #self.printTree()
        self.set_matches()

    def get(self, s):
        v = 0
        matches = []
        for i in range(len(s)):
            c = ord(s[i]) - ord('a')
            while(v>0 and...