human
Count the triplets such that A [ i ] < B [ j ] < C [ k ] | Function to return the count of elements in arr [ ] which are less than the given key.
Modified binary search.
Function to return the count of elements in arr [ ] which are greater than the given key.
Modified binary search.
Function to return the count of the required triplets.
Sort all three arrays.
Iterate for all the elements of array B.
Count of elements in A [ ] which are less than the chosen element from B [ ].
Count of elements in C [ ] which are greater than the chosen element from B [ ].
Update the count.
Driver code"
How can the above be solved in Python?

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Write me a code to count the triplets such that A [ i ] < B [ j ] < C [ k ] and the other steps required?
assistant
#Here is code to count the triplets such that A [ i ] < B [ j ] < C [ k ] and the other steps required.
 def countLessThan ( arr , n , key ) :
	l = 0
	r = n - 1
	index = - 1
	while ( l <= r ) :
		m = ( l + r ) // 2
		if ( arr [ m ] < key ) :
			l = m + 1
			index = m
		else :
			r = m - 1
	return ( index + 1 )
def countGreaterThan ( arr , n , key ) :
	l = 0
	r = n - 1
	index = - 1
	while ( l <= r ) :
		m = ( l + r ) // 2
		if ( arr [ m ] <= key ) :
			l = m + 1
		else :
			r = m - 1
			index = m
	if ( index == - 1 ) :
		return 0
	return ( n - index )
def countTriplets ( n , a , b , c ) :
	a . sort
	b . sort ( )
	c . sort ( )
	count = 0
	for i in range ( n ) :
		current = b [ i ]
		a_index = - 1
		c_index = - 1
		low = countLessThan ( a , n , current )
		high = countGreaterThan ( c , n , current )
		count += ( low * high )
	return count
if __name__ == " _ _ main _ _ " :
	a = [ 1 , 5 ]
	b = [ 2 , 4 ]
	c = [ 3 , 6 ]
	size = len ( a )
	print ( countTriplets ( size , a , b , c ) )