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Longest palindromic string formed by concatenation of prefix and suffix of a string | Function used to calculate the longest prefix which is also a suffix.
Traverse the string.
Update the lps size.
Returns size of lps.
Function to calculate the length of longest palindromic substring which is either a suffix or prefix.
Append a character to separate the string and reverse of the string.
Reverse the string.
Append the reversed string.
Function to find the Longest palindromic string formed from concatenation of prefix and suffix of a given string.
Calculating the length for which prefix is reverse of suffix.
Append prefix to the answer.
Store the remaining string.
If the remaining string is not empty that means that there can be a palindrome substring which can be added between the suffix & prefix.
Calculate the length of longest prefix palindromic substring.
Reverse the given string to find the longest palindromic suffix.
Calculate the length of longest prefix palindromic substring.
If the prefix palindrome is greater than the suffix palindrome.
Append the prefix to the answer.
If the suffix palindrome is greater than the prefix palindrome.
Append the suffix to the answer.
Finally append the suffix to the answer.
Return the answer string.
Driver Code"
Solution in Python:

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Can you provide a code to longest palindromic string formed by concatenation of prefix and suffix of a string and the other steps required?
assistant
#Here is code to longest palindromic string formed by concatenation of prefix and suffix of a string and the other steps required.
 def kmp ( s ) :
	lps = [ 0 ] * ( len ( s ) )
	for i in range ( 1 , len ( s ) ) :
		previous_index = lps [ i - 1 ]
		while ( previous_index > 0 and s [ i ] != s [ previous_index ] ) :
			previous_index = lps [ previous_index - 1 ]
		lps [ i ] = previous_index
		if ( s [ i ] == s [ previous_index ] ) :
			lps [ i ] += 1
	return lps [ - 1 ]
def remainingStringLongestPallindrome ( s ) :
	t = s + " ? "
	s = s [ : : - 1 ]
	t += s
	return kmp ( t )
def longestPrefixSuffixPallindrome ( s ) :
	length = 0
	n = len ( s )
	i = 0
	j = n - 1
	while i < j :
		if ( s [ i ] != s [ j ] ) :
			break
		i += 1
		j -= 1
		length += 1
	ans = s [ 0 : length ]
	remaining = s [ length : length + ( n - ( 2 * length ) ) ]
	if ( len ( remaining ) ) :
		longest_prefix = remainingStringLongestPallindrome ( remaining ) ;
		remaining = remaining [ : : - 1 ]
		longest_suffix = remainingStringLongestPallindrome ( remaining ) ;
		if ( longest_prefix > longest_suffix ) :
			remaining = remaining [ : : - 1 ]
			ans += remaining [ 0 : longest_prefix ]
		else :
			ans += remaining [ 0 : longest_suffix ]
	ans += s [ n - length : n ]
	return ans
if __name__ == " _ _ main _ _ " :
	st = " rombobinnimor "
	print ( longestPrefixSuffixPallindrome ( st ) )