human
Count of elements not divisible by any other elements of Array | Function to count the number of elements of array which are not divisible by any other element in the array arr [ ].
Iterate over the array.
Check if the element is itself or not.
Check for divisibility.
Return the final result.
Driver Code.
Given array.
Function Call"
Solution in Python:
 Can you provide a code to count of elements not divisible by any other elements of Array and the other steps required?
assistant
#Here is code to count of elements not divisible by any other elements of Array and the other steps required.
 def count ( a , n ) :
	countElements = 0
	for i in range ( n ) :
		flag = True
		for j in range ( n ) :
			if ( i == j ) :
				continue
			if ( a [ i ] % a [ j ] == 0 ) :
				flag = False
				break
		if ( flag == True ) :
			countElements += 1
	return countElements
if __name__ == " _ _ main _ _ " :
	arr = [ 86 , 45 , 18 , 4 , 8 , 28 , 19 , 33 , 2 ]
	n = len ( arr )
	print ( count ( arr , n ) )