human
Give me a code to maximize sum of all elements which are not a part of the Longest Increasing Subsequence and the other steps required given the following:
Maximize sum of all elements which are not a part of the Longest Increasing Subsequence | Function to find maximum sum.
Find total sum of array.
Maintain a 2D array.
Update the dp array along with sum in the second row.
In case of greater length update the length along with sum.
In case of equal length find length update length with minimum sum.
Find the sum that need to be subtracted from total sum.
Return the sum.
Driver code"
Solution in Python:
assistant
#Here is code to maximize sum of all elements which are not a part of the Longest Increasing Subsequence and the other steps required.
 def findSum ( arr , n ) :
	totalSum = 0
	for i in range ( n ) :
		totalSum += arr [ i ]
	dp = [ [ 0 ] * n for i in range ( 2 ) ]
	for i in range ( n ) :
		dp [ 0 ] [ i ] = 1
		dp [ 1 ] [ i ] = arr [ i ]
	for i in range ( 1 , n ) :
		for j in range ( i ) :
			if ( arr [ i ] > arr [ j ] ) :
				if ( dp [ 0 ] [ i ] < dp [ 0 ] [ j ] + 1 ) :
					dp [ 0 ] [ i ] = dp [ 0 ] [ j ] + 1
					dp [ 1 ] [ i ] = dp [ 1 ] [ j ] + arr [ i ]
				elif ( dp [ 0 ] [ i ] == dp [ 0 ] [ j ] + 1 ) :
					dp [ 1 ] [ i ] = min ( dp [ 1 ] [ i ] , dp [ 1 ] [ j ] + arr [ i ] )
	maxm = 0
	subtractSum = 0
	for i in range ( n ) :
		if ( dp [ 0 ] [ i ] > maxm ) :
			maxm = dp [ 0 ] [ i ]
			subtractSum = dp [ 1 ] [ i ]
		elif ( dp [ 0 ] [ i ] == maxm ) :
			subtractSum = min ( subtractSum , dp [ 1 ] [ i ] )
	return totalSum - subtractSum
arr = [ 4 , 6 , 1 , 2 , 3 , 8 ]
n = len ( arr )
print ( findSum ( arr , n ) )