human
Solve the following python programming problem given the following code:
def _to_ijv(ss, row_levels = (0,), column_levels = (1,), sort_labels = False) : 
    ' For arbitrary (MultiIndexed) SparseSeries return
    (v, i, j, ilabels, jlabels) where (v, (i, j)) is suitable for
    passing to scipy.sparse.coo constructor. ' 
    _check_is_partition ([row_levels, row_levels], range (ss.index.nlevels)) 
    values = ss._data.internal_values ()._valid_sp_values 
    nonnull_labels = ss.dropna () 
    def get_indexers(levels) : 
        ' Return sparse coords and dense labels for subset levels ' 
        values_ilabels = [tuple ((x [i] for i in levels)) for x in nonnull_labels.index] 
        if (len (levels) == 1) : 
            values_ilabels = [x [0] for x in values_ilabels] 
def _get_label_to_i_dict(labels, sort_labels = False) : 
            ' Return OrderedDict of unique labels to number.
            Optionally sort by label.
            ' 
            labels = Index (lmap (tuple, labels)).unique ().tolist () 
            if sort_labels : 
                labels = sorted (list (labels)) 
d = OrderedDict (((k, i) for (i, k) in enumerate (labels))) 
            return d 
def _get_index_subset_to_coord_dict(index, subset, sort_labels = False) : 
            def robust_get_level_values(i) : 
                try : 
                    return index.get_level_values (index.names [i]) 
except KeyError : 
                    return index.get_level_values (i) 
ilabels = list (zip (* [robust_get_level_values (i) for i in subset])) 
            labels_to_i = _get_label_to_i_dict (ilabels, sort_labels = sort_labels) 
            labels_to_i = Series (labels_to_i) 
            if (len (subset) > 1) : 
                labels_to_i.index = MultiIndex.from_tuples (labels_to_i.index) 
labels_to_i.index.names = [index.names [i] for i in subset] 
            labels_to_i.name = 'value' 
            return labels_to_i 
labels_to_i = _get_index_subset_to_coord_dict (ss.index, levels, sort_labels = sort_labels) 
        i_coord = labels_to_i [values_ilabels].tolist () 
        i_labels =...

    
    

    Fix the buggy line: _check_is_partition ([row_levels, row_levels], range (ss.index.nlevels))
assistant
#Here is Python program to fix the buggy line: _check_is_partition ([row_levels, row_levels], range (ss.

_check_is_partition ([row_levels, column_levels], range (ss.index.nlevels))