human
Give me a code to maximize count of odd and the other steps required given the following:
Maximize count of odd | To find maximum number of pairs in array with conversion of at most one element.
Initialize count of even elements.
Initialize count of odd elements.
If current number is even then increment x by 1.
If current number is odd then increment y by 1.
Initialize the answer by min ( x , y ).
If difference in count of odd and even is more than 2 than increment answer.
Return final answer.
Driver code.
Given array"
Solution in Python:
assistant
#Here is code to maximize count of odd and the other steps required.
 def maximumNumberofpairs ( n , arr ) :
	x = 0
	y = 0
	for i in range ( n ) :
		if ( arr [ i ] % 2 == 0 ) :
			x += 1
		else :
			y += 1
	answer = min ( x , y )
	if ( abs ( x - y ) >= 2 ) :
		answer += 1
	return answer
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 4 , 6 , 5 , 10 , 12 ]
	n = len ( arr )
	print ( maximumNumberofpairs ( n , arr ) )