human
Can you provide a code to count total unset bits in all the numbers from 1 to N and the other steps required given the following:
Count total unset bits in all the numbers from 1 to N | Function to return the count of unset bits in the binary representation of all the numbers from 1 to n.
To store the count of unset bits.
For every integer from the range [ 1 , n ].
A copy of the current integer.
Count of unset bits in the current integer.
If current bit is unset.
Driver code"
Solution in Python:
assistant
#Here is code to count total unset bits in all the numbers from 1 to N and the other steps required.
 def countUnsetBits ( n ) :
	cnt = 0 ;
	for i in range ( 1 , n + 1 ) :
		temp = i ;
		while ( temp ) :
			if ( temp % 2 == 0 ) :
				cnt += 1 ;
			temp = temp // 2 ;
	return cnt ;
if __name__ == " _ _ main _ _ " :
	n = 5 ;
	print ( countUnsetBits ( n ) ) ;