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Minimum number of swaps required to make the string K periodic | Python3 code to find the minimum number of swaps required to make the string K periodic.
Mark all allowed characters as true.
Initialize the freq array to 0.
Increase the frequency of each character.
Total number of periods of size K in the string.
Check if the current character is present in allowed and whether the current frequency is greater than all previous frequencies for this position.
Update the answer by subtracting the maxfrequency from total positions if there exist extra character at the end of the string apart from the n / k characters then add 1..
Driver code"
Solution in Python:

Write me a code to minimum number of swaps required to make the string K periodic and the other steps required?
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#Here is code to minimum number of swaps required to make the string K periodic and the other steps required.
 def minFlip ( s , n , k , a , p ) :
	allowed = [ 0 ] * 26
	for i in range ( p ) :
		allowed [ ord ( a [ i ] ) - ord ( ' a ' ) ] = True
	freq = [ [ 0 for x in range ( 26 ) ] for y in range ( k ) ]
	for i in range ( k ) :
		for j in range ( 26 ) :
			freq [ i ] [ j ] = 0
	for i in range ( n ) :
		freq [ i % k ] [ ord ( s [ i ] ) - ord ( ' a ' ) ] += 1
	ans = 0
	totalpositions = n // k
	for i in range ( k ) :
		maxfrequency = 0
		for j in range ( 26 ) :
			if ( freq [ i ] [ j ] > maxfrequency and allowed [ j ] == True ) :
				maxfrequency = freq [ i ] [ j ]
		ans += ( totalpositions - maxfrequency )
		if ( i % k < n % k ) :
			ans += 1
	print ( ans )
if __name__ == " _ _ main _ _ " :
	S = " nihsiakyt "
	n = len ( S )
	K = 3
	A = [ ' n ' , ' i ' , ' p ' , ' s ' , ' q ' ]
	p = len ( A )
	minFlip ( S , n , K , A , p )