human
I found an interesting problem on https://leetcode.com/problems/alert-using-same-key-card-three-or-more-times-in-a-one-hour-period/:
LeetCode company workers use key-cards to unlock office doors. Each time a worker uses their key-card, the security system saves the worker's name and the time when it was used. The system emits an alert if any worker uses the key-card three or more times in a one-hour period.
You are given a list of strings keyName and keyTime where [keyName[i], keyTime[i]] corresponds to a person's name and the time when their key-card was used in a single day.
Access times are given in the 24-hour time format "HH:MM", such as "23:51" and "09:49".
Return a list of unique worker names who received an alert for frequent keycard use. Sort the names in ascending order alphabetically.
Notice that "10:00" - "11:00" is considered to be within a one-hour period, while "22:51" - "23:52" is not considered to be within a one-hour period.
 
Example 1:
Input: keyName = ["daniel","daniel","daniel","luis","luis","luis","luis"], keyTime = ["10:00","10:40","11:00","09:00","11:00","13:00","15:00"]
Output: ["daniel"]
Explanation: "daniel" used the keycard 3 times in a one-hour period ("10:00","10:40", "11:00").

Example 2:
Input: keyName = ["alice","alice","alice","bob","bob","bob","bob"], keyTime = ["12:01","12:00","18:00","21:00","21:20","21:30","23:00"]
Output: ["bob"]
Explanation: "bob" used the keycard 3 times in a one-hour period ("21:00","21:20", "21:30").

Example 3:
Input: keyName = ["john","john","john"], keyTime = ["23:58","23:59","00:01"]
Output: []

Example 4:
Input: keyName = ["leslie","leslie","leslie","clare","clare","clare","clare"], keyTime = ["13:00","13:20","14:00","18:00","18:51","19:30","19:49"]
Output: ["clare","leslie"]

 
Constraints:

1 <= keyName.length, keyTime.length <= 105
keyName.length == keyTime.length
keyTime are in the format "HH:MM".
[keyName[i], keyTime[i]] is unique.
1 <= keyName[i].length <= 10
keyName[i] contains only lowercase English letters.

I tried it in Python, but could not do it. Can you solve it?

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Can you provide a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def alertNames(self, keyName: List[str], keyTime: List[str]) -> List[str]:
        from collections import defaultdict
        
        key_pairs = [(time, name) for name, time in zip(keyName, keyTime)]
        key_pairs.sort()
        keys = defaultdict(list)
        names = set()
        for pair in key_pairs:
            time, name = pair
            if name in names:
                continue
                
            keys[name].append(time)
            
            if len(keys[name]) < 3:
                continue
            
            hour, minute = time.split(':')
            hour, minute = int(hour), int(minute)
            first_access_time = keys[name][-3]
            first_hour, first_minute = first_access_time.split(':')
            first_hour, first_minute = int(first_hour), int(first_minute)
            if hour - first_hour <= 1:
                if hour - first_hour == 1:
                    if minute - first_minute > 0:
                        continue
                    else:
                        names.add(name)
                else:
                    names.add(name)
        res = list(names)
        res.sort()
        
        return res