human
Give me a code to count of pairs from 1 to a and 1 to b whose sum is divisible by N and the other steps required given the following:
Count of pairs from 1 to a and 1 to b whose sum is divisible by N | Function to find the distinct pairs from 1 - a & 1 - b such that their sum is divisible by n ..
if first element is bigger then swap.
count is store the number of pair ..
we use temp for breaking a loop ..
count when a is greater ..
Count when a is smaller but b is greater.
Count when a and b both are smaller.
For storing The pair in count ..
return the number of pairs ..
Driver code"
Solution in Python:
assistant
#Here is code to count of pairs from 1 to a and 1 to b whose sum is divisible by N and the other steps required.
 def findCountOfPairs ( a , b , n ) :
	if ( a > b ) :
		a , b = b , a
	temp = 1
	count = 0
	i = n
	while ( temp > 0 ) :
		if ( a >= i ) :
			temp = i - 1
		elif ( b >= i ) :
			temp = a
		elif ( i > b ) :
			temp = a - ( i - b ) + 1
		if ( temp > 0 ) :
			count += temp
		i += n
	return count
a = 5
b = 13
n = 3
print ( findCountOfPairs ( a , b , n ) )