human
Smallest non | Function to return the length of the smallest subdivisible by 2 ^ k.
To store the final answer.
Left pointer.
Right pointer.
Count of the number of zeros and ones in the current substring.
Loop for two pointers.
Condition satisfied.
Updated the answer.
Update the pointer and count.
Update the pointer and count.
Driver code"
Solution in Python:
assistant
#Here is code to smallest non and the other steps required.
 def findLength ( s , k ) :
	ans = 10 ** 9
	l = 0
	r = 0
	cnt_zero = 0
	cnt_one = 0
	while ( l < len ( s ) and r <= len ( s ) ) :
		if ( cnt_zero >= k and cnt_one >= 1 ) :
			ans = min ( ans , r - l )
			l += 1
			if ( s [ l - 1 ] == '0' ) :
				cnt_zero -= 1
			else :
				cnt_one -= 1
		else :
			if ( r == len ( s ) ) :
				break
			if ( s [ r ] == '0' ) :
				cnt_zero += 1
			else :
				cnt_one += 1
			r += 1
	if ( ans == 10 ** 9 ) :
		return - 1
	return ans
s = "100"
k = 2
print ( findLength ( s , k ) )