human
Find the last element after repeatedly removing every second element from either end alternately | Function to find the last element remaining in the array after performing the given operations.
Checks if traversal is from left to right or vice versa.
Store the elements currently present in the array.
Store the distance between 2 consecutive array elements.
Store the first element of the remaining array.
Iterate while elements are greater than 1.
If left to right turn.
Update head.
Otherwise , check if the remaining elements are odd.
If true , update head.
Eleminate half of the array elements.
Double the steps after each turn.
Alter the turn.
Print the remaining element.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to find the last element after repeatedly removing every second element from either end alternately and the other steps required.
 def printLastElement ( arr , N ) :
	leftTurn = True
	remainElements = N
	step = 1
	head = 1
	while ( remainElements > 1 ) :
		if ( leftTurn ) :
			head = head + step
		else :
			if ( remainElements % 2 == 1 ) :
				head = head + step
		remainElements = remainElements // 2
		step = step * 2
		leftTurn = not leftTurn
	print ( arr [ head - 1 ] )
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 3 , 5 , 6 ]
	N = len ( arr )
	printLastElement ( arr , N )