human
Count pairs made up of an element divisible by the other from an array consisting of powers of 2 | Function to count the number of pairs as per the given conditions.
Initialize array set_bits as 0.
Store the total number of required pairs.
Traverse the array arr [ ].
Store arr [ i ] in x.
Store the position of the leftmost set bit in arr [ i ].
Increase bit position.
Divide by 2 to shift bits in right at each step.
Count of pairs for index i till its set bit position.
Increasing count of set bit position of current elelement.
Prthe answer.
Driver Code.
Function Call"
Solution in Python:

=====
Give me a code to count pairs made up of an element divisible by the other from an array consisting of powers of 2 and the other steps required?
assistant
#Here is code to count pairs made up of an element divisible by the other from an array consisting of powers of 2 and the other steps required.
 def numberOfPairs ( arr , N ) :
	set_bits = [ 0 ] * 31
	count = 0
	for i in range ( N ) :
		x = arr [ i ]
		bitpos = - 1
		while ( x > 0 ) :
			bitpos += 1
			x //= 2
		for j in range ( bitpos + 1 ) :
			count += set_bits [ j ]
		set_bits [ bitpos ] += 1
	print ( count )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 4 , 16 , 8 , 64 ]
	N = len ( arr )
	numberOfPairs ( arr , N )