human
Can you provide a code to remove brackets from an algebraic string containing + and and the other steps required given the following:
Remove brackets from an algebraic string containing + and | Function to simplify the String.
resultant String of max Length equal to Length of input String.
create empty stack.
If top is 1 , flip the operator.
If top is 0 , append the same operator.
x is opposite to the top of stack.
append value equal to top of the stack.
If closing parentheses pop the stack once.
copy the character to the result.
Driver Code"
Solution in Python:
assistant
#Here is code to remove brackets from an algebraic string containing + and and the other steps required.
 def simplify ( Str ) :
	Len = len ( Str )
	res = [ None ] * Len
	index = 0
	i = 0
	s = [ ]
	s . append ( 0 )
	while ( i < Len ) :
		if ( Str [ i ] == ' + ' ) :
			if ( s [ - 1 ] == 1 ) :
				res [ index ] = ' - '
				index += 1
			if ( s [ - 1 ] == 0 ) :
				res [ index ] = ' + '
				index += 1
		elif ( Str [ i ] == ' - ' ) :
			if ( s [ - 1 ] == 1 ) :
				res [ index ] = ' + '
				index += 1
			elif ( s [ - 1 ] == 0 ) :
				res [ index ] = ' - '
				index += 1
		elif ( Str [ i ] == ' ( ' and i > 0 ) :
			if ( Str [ i - 1 ] == ' - ' ) :
				x = 0 if ( s [ - 1 ] == 1 ) else 1
				s . append ( x )
			elif ( Str [ i - 1 ] == ' + ' ) :
				s . append ( s [ - 1 ] )
		elif ( Str [ i ] == ' ) ' ) :
			s . pop ( )
		else :
			res [ index ] = Str [ i ]
			index += 1
		i += 1
	return res
if __name__ == ' _ _ main _ _ ' :
	s1 = " a - ( b + c ) "
	s2 = " a - ( b - c - ( d + e ) ) - f "
	r1 = simplify ( s1 )
	for i in r1 :
		if i != None :
			print ( i , end = " ▁ " )
		else :
			break
	print ( )
	r2 = simplify ( s2 )
	for i in r2 :
		if i != None :
			print ( i , end = " ▁ " )
		else :
			break