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What is a Python code to find the minimal possible number of inversions in the deque after the whole array is processed given the following:
In fact, the problems E1 and E2 do not have much in common. You should probably think of them as two separate problems.

You are given an integer array a[1 … n] = [a_1, a_2, …, a_n].

Let us consider an empty [deque](https://tinyurl.com/pfeucbux) (double-ended queue). A deque is a data structure that supports adding elements to both the beginning and the end. So, if there are elements [3, 4, 4] currently in the deque, adding an element 1 to the beginning will produce the sequence [\color{red}{1}, 3, 4, 4], and adding the same element to the end will produce [3, 4, 4, \color{red}{1}].

The elements of the array are sequentially added to the initially empty deque, starting with a_1 and finishing with a_n. Before adding each element to the deque, you may choose whether to add it to the beginning or to the end.

For example, if we consider an array a = [3, 7, 5, 5], one of the possible sequences of actions looks like this:    1. |  add 3 to the beginning of the deque: |  deque has a sequence [\color{red}{3}] in it.
  
---|---|---  
  2. |  add 7 to the end of the deque: |  deque has a sequence [3, \color{red}{7}] in it.
  
  3. |  add 5 to the end of the deque: |  deque has a sequence [3, 7, \color{red}{5}] in it.
  
  4. |  add 5 to the beginning of the deque: |  deque has a sequence [\color{red}{5}, 3, 7, 5] in it.
  
  
Find the minimal possible number of inversions in the deque after the whole array is processed. 

An inversion in sequence d is a pair of indices (i, j) such that i < j and d_i > d_j. For example, the array d = [5, 3, 7, 5] has exactly two inversions — (1, 2) and (3, 4), since d_1 = 5 > 3 = d_2 and d_3 = 7 > 5 = d_4.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases.

The next 2t lines contain descriptions of the test cases. 

The first line of each test case description contains an integer n (1 ≤ n ≤ 2 ⋅ 10^5) — array size. The second line of the description contains n space-separated integers a_i (-10^9 ≤ a_i ≤ 10^9) — elements of the array.

It is...
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#Here is Python code to find the minimal possible number of inversions in the deque after the whole array is processed.
t sys,math,itertools
from collections import Counter,deque,defaultdict
from bisect import bisect_left,bisect_right 
from heapq import heappop,heappush,heapify
mod = 10**9+7
INF = float('inf')
def inp(): return int(sys.stdin.readline())
def inpl(): return list(map(int, sys.stdin.readline().split()))
def inpl_1(): return list(map(lambda x:int(x)-1, sys.stdin.readline().split()))
def inps(): return sys.stdin.readline()
def inpsl(x): tmp = sys.stdin.readline(); return list(tmp[:x])
def err(x): print(x); exit()

class BIT:
    def __init__(self, n):
        self.n = n
        self.data = [0]*(n+1)
        self.el = [0]*(n+1)
    def sum(self, i):
        s = 0
        while i > 0:
            s += self.data[i]
            i -= i & -i
        return s
    def add(self, i, x):
        # assert i > 0
        self.el[i] += x
        while i <= self.n:
            self.data[i] += x
            i += i & -i
    def get(self, i, j=None):
        if j is None:
            return self.el[i]
        return self.sum(j) - self.sum(i)

# 1_indexed
# n = 6
# a = [1,2,3,4,5,6]
# bit = BIT(n)
# for i,e in enumerate(a):
#     bit.add(i+1,e)
# print(bit.get(2,5)) #12 (3+4+5)

for _ in range(inp()):
    n = inp()
    a = inpl()
    se = set(list(a))
    d = {}
    for i,x in enumerate(sorted(list(se)),2):
        d[x] = i
    for i,x in enumerate(a):
        a[i] = d[x]
    bit = BIT(n+100)
    res = 0
    for x in a:
        f = bit.get(1,x-1)
        l = bit.get(x,n+10)
        res += min(f,l)
        bit.add(x,1)
    print(res)