human
Decode the string encoded with the given algorithm | Function to decode and print the original string.
To store the decoded string.
Getting the mid element.
Storing the first element of the string at the median position.
If the length is even then store the second element also.
k represents the number of characters that are already stored in the c [ ].
If string length is odd.
If it is even.
Print the decoded string.
Driver code"
How can the above be solved in Python?
 ... Write me a code to decode the string encoded with the given algorithm and the other steps required?
assistant
#Here is code to decode the string encoded with the given algorithm and the other steps required.
 def decodeStr ( str , len ) :
	c = [ " " for i in range ( len ) ]
	pos = 1
	if ( len % 2 == 1 ) :
		med = int ( len / 2 )
	else :
		med = int ( len / 2 - 1 )
	c [ med ] = str [ 0 ]
	if ( len % 2 == 0 ) :
		c [ med + 1 ] = str [ 1 ]
	if ( len & 1 ) :
		k = 1
	else :
		k = 2
	for i in range ( k , len , 2 ) :
		c [ med - pos ] = str [ i ]
		if ( len % 2 == 1 ) :
			c [ med + pos ] = str [ i + 1 ]
		else :
			c [ med + pos + 1 ] = str [ i + 1 ]
		pos += 1
	print ( * c , sep = " " )
str = " ofrsgkeeeekgs "
len = len ( str )
decodeStr ( str , len )