human
Count number of pairs ( i , j ) such that arr [ i ] * arr [ j ] = arr [ i ] + arr [ j ] | Function to return the count of pairs ( i , j ) such that arr [ i ] * arr [ j ] = arr [ i ] + arr [ j ].
Increment count if condition satisfy.
Return count of pairs.
Driver code.
Get and print count of pairs"
How can the above be solved in Python?

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Write me a code to count number of pairs ( i , j ) such that arr [ i ] * arr [ j ] = arr [ i ] + arr [ j ] and the other steps required?
assistant
#Here is code to count number of pairs ( i , j ) such that arr [ i ] * arr [ j ] = arr [ i ] + arr [ j ] and the other steps required.
 def countPairs ( arr , n ) :
	count = 0 ;
	for i in range ( n - 1 ) :
		for j in range ( i + 1 , n ) :
			if ( arr [ i ] * arr [ j ] == arr [ i ] + arr [ j ] ) :
				count += 1 ;
	return count ;
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 0 , 3 , 2 , 0 ] ;
	n = len ( arr ) ;
	print ( countPairs ( arr , n ) ) ;