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Count array elements exceeding sum of preceding K elements | Function to count array elements exceeding sum of preceding K elements.
Iterate over the array.
Update prefix sum.
Check if arr [ K ] > arr [ 0 ] + . . + arr [ K - 1 ].
Increment count.
Check if arr [ i ] > arr [ i - K - 1 ] + . . + arr [ i - 1 ].
Increment count.
Driver Code.
Given array"
Solution in Python:

Give me a code to count array elements exceeding sum of preceding K elements and the other steps required?
assistant
#Here is code to count array elements exceeding sum of preceding K elements and the other steps required.
 def countPrecedingK ( a , n , K ) :
	prefix = [ 0 ] * n
	prefix [ 0 ] = a [ 0 ]
	for i in range ( 1 , n ) :
		prefix [ i ] = prefix [ i - 1 ] + a [ i ]
	ctr = 0
	if ( prefix [ K - 1 ] < a [ K ] ) :
		ctr += 1
	for i in range ( K + 1 , n ) :
		if ( prefix [ i - 1 ] - prefix [ i - K - 1 ] < a [ i ] ) :
			ctr += 1
	return ctr
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 3 , 8 , 10 , - 2 , 7 , 5 , 5 , 9 , 15 ]
	N = len ( arr )
	K = 2
	print ( countPrecedingK ( arr , N , K ) )