human
Count array elements having sum of digits equal to K | Function to calculate the sum of digits of the number N.
Stores the sum of digits.
Return the sum.
Function to count array elements.
Store the count of array elements having sum of digits K.
Traverse the array.
If sum of digits is equal to K.
Increment the count.
Prthe count.
Given array.
Given value of K.
Size of the array.
Function call to count array elements having sum of digits equal to K"
How can the above be solved in Python?

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Give me a code to count array elements having sum of digits equal to K and the other steps required?
assistant
#Here is code to count array elements having sum of digits equal to K and the other steps required.
 def sumOfDigits ( N ) :
	sum = 0
	while ( N != 0 ) :
		sum += N % 10
		N //= 10
	return sum
def elementsHavingDigitSumK ( arr , N , K ) :
	count = 0
	for i in range ( N ) :
		if ( sumOfDigits ( arr [ i ] ) == K ) :
			count += 1
	print ( count )
arr = [ 23 , 54 , 87 , 29 , 92 , 62 ]
K = 11
N = len ( arr )
elementsHavingDigitSumK ( arr , N , K )