human
Smallest even digits number not less than N | Function to return the answer when the first odd digit is 9.
traverse towwars the left to find the non - 8 digit.
index digit.
if digit is not 8 , then break.
if on the left side of the '9' , no 8 is found then we return by adding a 2 and 0 's.
till non - 8 digit add all numbers.
if non - 8 is even or odd than add the next even ..
add 0 to right of 9.
function to return the smallest number with all digits even.
convert the number to string to perform operations.
find out the first odd number.
if no odd numbers are there , than n is the answer.
if the odd number is 9 , than tricky case handles it.
add all digits till first odd.
increase the odd digit by 1.
add 0 to the right of the odd number.
Driver Code"
Solution in Python:
 What is a code to smallest even digits number not less than N and the other steps required?
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#Here is code to smallest even digits number not less than N and the other steps required.
 def trickyCase ( s , index ) :
	index1 = - 1 ;
	for i in range ( index - 1 , - 1 , - 1 ) :
		digit = s [ i ] - '0' ;
		if ( digit != 8 ) :
			index1 = i ;
			break ;
	if ( index1 == - 1 ) :
		return 2 * pow ( 10 , len ( s ) ) ;
	num = 0 ;
	for i in range ( index1 ) :
		num = num * 10 + ( s [ i ] - '0' ) ;
	if ( s [ index1 ] % 2 == 0 ) :
		num = num * 10 + ( s [ index1 ] - '0' + 2 ) ;
	else :
		num = num * 10 + ( s [ index1 ] - '0' + 1 ) ;
	for i in range ( index1 + 1 , len ( s ) ) :
		num = num * 10 ;
	return num ;
def smallestNumber ( n ) :
	num = 0 ;
	s = " " ;
	duplicate = n ;
	while ( n ) :
		s = chr ( n % 10 + 48 ) + s ;
		n = int ( n / 10 ) ;
	index = - 1 ;
	for i in range ( len ( s ) ) :
		digit = ord ( s [ i ] ) - ord ( '0' ) ;
		if ( digit & 1 ) :
			index = i ;
			break ;
	if ( index == - 1 ) :
		return duplicate ;
	if ( s [ index ] == '9' ) :
		num = trickyCase ( s , index ) ;
		return num ;
	for i in range ( index ) :
		num = num * 10 + ord ( s [ i ] ) - ord ( '0' ) ;
	num = num * 10 + ( ord ( s [ index ] ) - ord ( '0' ) + 1 ) ;
	for i in range ( index + 1 , len ( s ) ) :
		num = num * 10 ;
	return num ;
N = 2397 ;
print ( smallestNumber ( N ) ) ;