human
Count of distinct power of prime factor of N | Function to count the number of distinct positive power of prime factor of integer N.
Iterate for all prime factor.
If it is a prime factor , count the total number of times it divides n ..
Find the Number of distinct possible positive numbers.
Return the final count.
Given number N.
Function call"
How can the above be solved in Python?
assistant
#Here is code to count of distinct power of prime factor of N and the other steps required.
 def countFac ( n ) :
	m = n
	count = 0
	i = 2
	while ( ( i * i ) <= m ) :
		total = 0
		while ( n % i == 0 ) :
			n /= i
			total += 1
		temp = 0
		j = 1
		while ( ( temp + j ) <= total ) :
			temp += j
			count += 1
			j += 1
		i += 1
	if ( n != 1 ) :
		count += 1
	return count
N = 24
print ( countFac ( N ) )