human
Write me a code to calculate the number of set bits for every number from 0 to N and the other steps required given the following:
Calculate the number of set bits for every number from 0 to N | Function to find the count of set bits in all the integers from 0 to n.
dp [ i ] will store the count of set bits in i Initialise the dp array.
Count of set bits in 0 is 0.
For every number starting from 1.
If current number is even.
Count of set bits in i is equal to the count of set bits in ( i / 2 ).
If current element is odd.
Count of set bits in i is equal to the count of set bits in ( i / 2 ) + 1.
Print the count of set bits in i.
Driver code"
Solution in Python:
assistant
#Here is code to calculate the number of set bits for every number from 0 to N and the other steps required.
 def findSetBits ( n ) :
	dp = [ 0 ] * ( n + 1 ) ;
	print ( dp [ 0 ] , end = " ▁ " ) ;
	for i in range ( 1 , n + 1 ) :
		if ( i % 2 == 0 ) :
			dp [ i ] = dp [ i // 2 ] ;
		else :
			dp [ i ] = dp [ i // 2 ] + 1 ;
		print ( dp [ i ] , end = " ▁ " ) ;
if __name__ == " _ _ main _ _ " :
	n = 5 ;
	findSetBits ( n ) ;