human
Solve the following python programming problem given the following code:
def match_pattern(self) : 
    ' 
        Match the tree against patterns specified in the dictionary. For a more illustrated explanation
        of how this process works, see the Petrarch2.pdf file in the documentation. 
        
        
        Parameters
        -----------
        self: VerbPhrase object that called the method
        
        Returns
        -------
        False if no match, dict of match if present.
        
        ' 
    meaning = self.verbclass 
    code = self.code 
    def match_phrase(path, phrase) : 
        if (not phrase) : 
            return False 
for item in filter ((lambda b : (b.text in path)), phrase.children) : 
            subpath = path [item.text] 
            match = reroute (subpath, (lambda a : match_phrase (a, item.head_phrase))) 
            if match : 
                item.color = True 
                return match 
return reroute (path, (lambda a : match_phrase (a, phrase.head_phrase))) 
def match_noun(path, phrase = (self if (not self.check_passive ()) else self.get_S ()), preplimit = 0) : 
        noun_phrases = [] 
        if (not phrase) : 
            return False 
if preplimit : 
            for sib in phrase.children : 
                if (isinstance (sib, PrepPhrase) and (len (sib.children) > 1) and (sib.get_prep () in ['BY', 'FROM'])) : 
                    noun_phrases.append (sib.children [1]) 
else : 
            for child in phrase.children : 
                if (child.label in ('NP', 'ADVP')) : 
                    noun_phrases.append (child) 
if isinstance (phrase, NounPhrase) : 
                noun_phrases.append (phrase) 
for item in noun_phrases : 
            (head, headphrase) = item.get_head () 
            if (head and (head in path)) : 
                subpath = path [head] 
                skip = (lambda a : False) 
                match = reroute (subpath, skip, skip, (lambda a : match_prep (a, item)), skip, 0) 
                if match : 
                    headphrase.children [(- 1)].color = True 
                    return...

    
    

    Fix the buggy line: return match_noun (code, self, 1)
assistant
#Here is Python code to fix the buggy line: return match_noun (code, self, 1)
.

return match_noun (path, self, 1)