human
Find if a degree sequence can form a simple graph | Havel | Function that returns true if a simple graph exists.
Keep performing the operations until one of the stopping condition is met.
Sort the list in non - decreasing order.
Check if all the elements are equal to 0.
Store the first element in a variable and delete it from the list.
Check if enough elements are present in the list.
Subtract first element from next v elements.
Check if negative element is encountered after subtraction.
Driver code"
Solution in Python:
 What is a code to find if a degree sequence can form a simple graph and the other steps required?
assistant
#Here is code to find if a degree sequence can form a simple graph and the other steps required.
 def graphExists ( a ) :
	while True :
		a = sorted ( a , reverse = True )
		if a [ 0 ] == 0 and a [ len ( a ) - 1 ] == 0 :
			return True
		v = a [ 0 ]
		a = a [ 1 : ]
		if v > len ( a ) :
			return False
		for i in range ( v ) :
			a [ i ] -= 1
			if a [ i ] < 0 :
				return False
a = [ 3 , 3 , 3 , 3 ]
if ( graphExists ( a ) ) :
	print ( " Yes " )
else :
	print ( " No " )