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Minimum array elements to be changed to make Recaman 's sequence | Python3 implementation of the approach.
First term of the sequence is always 0.
Fill remaining terms using recursive formula.
If arr [ i - 1 ] - i is negative or already exists.
Function that returns minimum changes required.
Set to store first n Recaman numbers.
Generate and store first n Recaman numbers.
Insert first n Recaman numbers to set.
If current element of the array is present in the set.
Return the remaining number of elements in the set.
Driver code"
Solution in Python:
 Give me a code to minimum array elements to be changed to make Recaman 's sequence and the other steps required?
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#Here is code to minimum array elements to be changed to make Recaman 's sequence and the other steps required.
 def recamanGenerator ( arr , n ) :
	arr [ 0 ] = 0
	for i in range ( 1 , n ) :
		temp = arr [ i - 1 ] - i
		j = 0
		for j in range ( i ) :
			if ( ( arr [ j ] == temp ) or temp < 0 ) :
				temp = arr [ i - 1 ] + i
				break
		arr [ i ] = temp
def recamanArray ( arr , n ) :
	s = dict ( )
	recaman = [ 0 for i in range ( n ) ]
	recamanGenerator ( recaman , n )
	for i in range ( n ) :
		s [ recaman [ i ] ] = s . get ( recaman [ i ] , 0 ) + 1
	for i in range ( n ) :
		if arr [ i ] in s . keys ( ) :
			del s [ arr [ i ] ]
	return len ( s )
arr = [ 7 , 11 , 20 , 4 , 2 , 1 , 8 , 6 ]
n = len ( arr )
print ( recamanArray ( arr , n ) )