human
Count of Ordered Pairs ( X , Y ) satisfying the Equation 1 / X + 1 / Y = 1 / N | Function to find number of ordered positive integer pairs ( x , y ) such that they satisfy the equation.
Initialize answer variable.
Iterate over all possible values of y.
For valid x and y , ( n * n ) % ( y - n ) has to be 0.
Increment count of ordered pairs.
Print the answer.
Driver Code.
Function call"
How can the above be solved in Python?
assistant
#Here is code to count of Ordered Pairs ( X , Y ) satisfying the Equation 1 / X + 1 / Y = 1 / N and the other steps required.
 def solve ( n ) :
	ans = 0
	y = n + 1
	while ( y <= n * n + n ) :
		if ( ( n * n ) % ( y - n ) == 0 ) :
			ans += 1
		y += 1
	print ( ans )
n = 5
solve ( n )