human
Ways of filling matrix such that product of all rows and all columns are equal to unity | Returns a raised power t under modulo mod.
Counting number of ways of filling the matrix.
Function calculating the answer.
if sum of numbers of rows and columns is odd i . e ( n + m ) % 2 == 1 and k = - 1 then there are 0 ways of filiing the matrix ..
If there is one row or one column then there is only one way of filling the matrix.
If the above cases are not followed then we find ways to fill the n - 1 rows and m - 1 columns which is 2 ^ ( ( m - 1 ) * ( n - 1 ) ) ..
Driver Code"
Solution in Python:

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Can you provide a code to ways of filling matrix such that product of all rows and all columns are equal to unity and the other steps required?
assistant
#Here is code to ways of filling matrix such that product of all rows and all columns are equal to unity and the other steps required.
 def modPower ( a , t ) :
	now = a ;
	ret = 1 ;
	mod = 100000007 ;
	while ( t ) :
		if ( t & 1 ) :
			ret = now * ( ret % mod ) ;
		now = now * ( now % mod ) ;
		t >>= 1 ;
	return ret ;
def countWays ( n , m , k ) :
	mod = 100000007 ;
	if ( k == - 1 and ( ( n + m ) % 2 == 1 ) ) :
		return 0 ;
	if ( n == 1 or m == 1 ) :
		return 1 ;
	return ( modPower ( modPower ( 2 , n - 1 ) , m - 1 ) % mod ) ;
n = 2 ;
m = 7 ;
k = 1 ;
print ( countWays ( n , m , k ) ) ;