human
Write me a code to minimum product subset of an array and the other steps required given the following:
Minimum product subset of an array | def to find maximum product of a subset.
Find count of negative numbers , count of zeros , maximum valued negative number , minimum valued positive number and product of non - zero numbers.
If number is 0 , we don 't  multiply it with product..
Count negatives and keep track of maximum valued negative ..
Track minimum positive number of array.
If there are all zeros or no negative number present.
If there are all positive.
If there are even number of negative numbers and count_neg not 0.
Otherwise result is product of all non - zeros divided by maximum valued negative ..
Driver code"
How can the above be solved in Python?
assistant
#Here is code to minimum product subset of an array and the other steps required.
 def minProductSubset ( a , n ) :
	if ( n == 1 ) :
		return a [ 0 ]
	max_neg = float ( ' - inf ' )
	min_pos = float ( ' inf ' )
	count_neg = 0
	count_zero = 0
	prod = 1
	for i in range ( 0 , n ) :
		if ( a [ i ] == 0 ) :
			count_zero = count_zero + 1
			continue
		if ( a [ i ] < 0 ) :
			count_neg = count_neg + 1
			max_neg = max ( max_neg , a [ i ] )
		if ( a [ i ] > 0 ) :
			min_pos = min ( min_pos , a [ i ] )
		prod = prod * a [ i ]
	if ( count_zero == n or ( count_neg == 0 and count_zero > 0 ) ) :
		return 0
	if ( count_neg == 0 ) :
		return min_pos
	if ( ( count_neg & 1 ) == 0 and count_neg != 0 ) :
		prod = int ( prod / max_neg )
	return prod
a = [ - 1 , - 1 , - 2 , 4 , 3 ]
n = len ( a )
print ( minProductSubset ( a , n ) )