human
Minimum replacements required to have at most K distinct elements in the array | Function to find minimum count of array elements required to be replaced such that count of distinct elements is at most K.
Store the frequency of each distinct element of the array.
Traverse the array.
Update frequency of arr [ i ].
Store frequency of each distinct element of the array.
Traverse the map.
Stores key of the map.
Insert mp [ i ] into Freq [ ].
Sort Freq [ ] in descending order.
Stores size of Freq [ ].
If len is less than or equal to K.
Stores minimum count of array elements required to be replaced such that count of distinct elements is at most K.
Iterate over the range [ K , len ].
Update cntMin.
Driver code"
How can the above be solved in Python?

=====
Give me a code to minimum replacements required to have at most K distinct elements in the array and the other steps required?
assistant
#Here is code to minimum replacements required to have at most K distinct elements in the array and the other steps required.
 def min_elements ( arr , N , K ) :
	mp = { }
	for i in range ( N ) :
		if arr [ i ] in mp :
			mp [ arr [ i ] ] += 1
		else :
			mp [ arr [ i ] ] = 1
	Freq = [ ]
	for it in mp :
		i = it
		Freq . append ( mp [ i ] )
	Freq . sort ( )
	Freq . reverse ( )
	Len = len ( Freq )
	if ( Len <= K ) :
		return 0
	cntMin = 0
	for i in range ( K , Len ) :
		cntMin += Freq [ i ]
	return cntMin
arr = [ 5 , 1 , 3 , 2 , 4 , 1 , 1 , 2 , 3 , 4 ]
N = len ( arr )
K = 3 ;
print ( min_elements ( arr , N , K ) )