human
Possible pairs forming a Pythagorean Triple with a given value | Function to generate all possible pairs.
Vector to store all the possible pairs.
Checking all the possible pair in the range of [ 1 , c ).
If the pair satisfies the condition push it in the vector.
Driver code.
If no valid pair exist.
Print all valid pairs"
Solution in Python:

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Write me a code to possible pairs forming a Pythagorean Triple with a given value and the other steps required?
assistant
#Here is code to possible pairs forming a Pythagorean Triple with a given value and the other steps required.
 def Pairs ( C ) :
	ans = [ ]
	for i in range ( C ) :
		for j in range ( i + 1 , C ) :
			if ( ( i * i ) + ( j * j ) == ( C * C ) ) :
				ans . append ( [ i , j ] )
	return ans ;
if __name__ == " _ _ main _ _ " :
	C = 13 ;
	ans = Pairs ( C ) ;
	if ( len ( ans ) == 0 ) :
		print ( " No ▁ valid ▁ pair ▁ exist " )
		exit ( )
	for i in range ( len ( ans ) ) :
		print ( " ( " + str ( ans [ i ] [ 0 ] ) + " , ▁ " + str ( ans [ i ] [ 1 ] ) + " ) " )