human
Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).

Output

Output the number of participants who advance to the next round.

Examples

Input

8 5
10 9 8 7 7 7 5 5

Output

6

Input

4 2
0 0 0 0

Output

0

Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.
The above is tricky. Write me a correct solution in PYTHON3.

=====
What is a code to contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score?
assistant
#Here is code to contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score.

# def inp():
#     return(int(input()))                    # for int input
# def inlt():
#     return(list(map(int,input().split()))) # for list input
# def insr():
#     s = input()
#     return(list(s[:len(s) - 1]))       # for string input
# def invr():
#     return(map(int,input().split()))   # space separated int input

########## Way too long 71A
# i = input
# for _ in [0]*int(i()):
#     s = i()
#     print(s[0]+str(len(s)-2)+s[-1] if len(s)>10 else s)

########### team 231A

# i = input
# counter = 0
# for _ in [0]*int(i()):
#     n = i()
#     if n.count('1')>=2:
#         counter += 1
# print(counter)

########### next round 158A
def main():
    from sys import stdin, stdout

    inp = [int(x) for x in stdin.read().split()]
    n = inp.pop(0)
    k = inp.pop(0)
    k_th = inp[k-1]
    cnt = 0
    for i in inp:
        if i != 0 and i >= k_th:
            cnt+=1
    stdout.write(str(cnt) + '\n')

main()