human
Smallest indexed array element required to be flipped to make sum of array equal to 0 | Function to find the smallest indexed array element required to be flipped to make sum of the given array equal to 0.
Stores the required index.
Traverse the given array.
Flip the sign of current element.
Stores the sum of array elements.
Find the sum of the array.
Update sum.
If sum is equal to 0.
Update pos.
Reset the current element to its original value.
Reset the value of arr [ i ].
Driver Code"
How can the above be solved in Python?

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Can you provide a code to smallest indexed array element required to be flipped to make sum of array equal to 0 and the other steps required?
assistant
#Here is code to smallest indexed array element required to be flipped to make sum of array equal to 0 and the other steps required.
 def smallestIndexArrayElementsFlip ( arr , N ) :
	pos = - 1
	for i in range ( N ) :
		arr [ i ] *= - 1
		sum = 0
		for j in range ( N ) :
			sum += arr [ j ]
		if ( sum == 0 ) :
			pos = i
			break
		else :
			arr [ i ] *= - 1
	return pos
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 3 , - 5 , 3 , 4 ]
	N = len ( arr )
	print ( smallestIndexArrayElementsFlip ( arr , N ) )