human
Longest Uncommon Subsequence | function to calculate length of longest uncommon subsequence.
creating an unordered map to map strings to their frequency.
traversing all elements of vector strArr.
Creating all possible subsequences , i . e 2 ^ n.
( ( i >> j ) & 1 ) determines which character goes into t.
If common subsequence is found , increment its frequency.
traversing the map.
if frequency equals 1.
input strings"
How can the above be solved in Python?

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What is a code to longest Uncommon Subsequence and the other steps required?
assistant
#Here is code to longest Uncommon Subsequence and the other steps required.
 def findLUSlength ( a , b ) :
	map = dict ( )
	strArr = [ ]
	strArr . append ( a )
	strArr . append ( b )
	for s in strArr :
		for i in range ( 1 << len ( s ) ) :
			t = " "
			for j in range ( len ( s ) ) :
				if ( ( ( i >> j ) & 1 ) != 0 ) :
					t += s [ j ]
			if ( t in map . keys ( ) ) :
				map [ t ] += 1 ;
			else :
				map [ t ] = 1
	res = 0
	for a in map :
		if ( map [ a ] == 1 ) :
			res = max ( res , len ( a ) )
	return res
a = " abcdabcd "
b = " abcabc "
print ( findLUSlength ( a , b ) )