human
A string is called square if it is some string written twice in a row. For example, the strings "aa", "abcabc", "abab" and "baabaa" are square. But the strings "aaa", "abaaab" and "abcdabc" are not square.

For a given string s determine if it is square.

Input

The first line of input data contains an integer t (1 ≤ t ≤ 100) —the number of test cases.

This is followed by t lines, each containing a description of one test case. The given strings consist only of lowercase Latin letters and have lengths between 1 and 100 inclusive.

Output

For each test case, output on a separate line:

  * YES if the string in the corresponding test case is square, 
  * NO otherwise. 


You can output YES and NO in any case (for example, strings yEs, yes, Yes and YES will be recognized as a positive response).

Example

Input

10
a
aa
aaa
aaaa
abab
abcabc
abacaba
xxyy
xyyx
xyxy

Output

NO
YES
NO
YES
YES
YES
NO
NO
NO
YES
Solve the task in PYTHON3.

Give me a Python program to determine if it is square?
assistant
#Here is Python program to determine if it is square.

#Mamma don't raises quitter.................................................
#manan is improving, keep hustling manan bhai ;)
from collections import deque as de
import math
import sys
from math import sqrt as sq
from math import floor as fl
from math import ceil as ce
from sys import stdin, stdout
import time

sys.setrecursionlimit(10**7)
from collections import Counter as cnt
from functools import  reduce

from itertools import groupby as gb
#from fractions import Fraction as fr
from bisect import bisect_left as bl, bisect_right as br
from typing import Coroutine

def factors(n):    
    return set(reduce(list.__add__, 
                ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
    
class My_stack():
    def __init__(self):
        self.data = []
    def my_push(self, x):
        return (self.data.append(x))
    def my_pop(self):
        return (self.data.pop())
    def __iter__(self):
        return iter(self.data)
    def my_peak(self):
        return (self.data[-1])
    def my_contains(self, x):
        return (self.data.count(x))
    def my_show_all(self):
        return (self.data)
    def isEmpty(self):
      return len(self.data)==0
    def len(self):
        return len(self.data)
    

arrStack = My_stack() 

class graph():
    def __init__(self):
        self.graphdict = {}
    def add_edge(self, node, neighbor):
        if node not in self.graphdict:
            self.graphdict[node]=[neighbor]
        else:
            self.graphdict[node].append(neighbor)
    def show_edge(self):
        for node in self.graphdict:
            for neighbors in self.graphdict:
                print(node, neighbors)
    def show_graph(self):
        return self.graphdict

    

    
            

#decimal to binary   
def decimalToBinary(n): 
    return bin(n).replace("0b", "")
#binary to decimal
def binarytodecimal(n):
    return int(n,2)

def isPrime(n) : 
	if (n <= 1) : 
		return False
	if (n <= 3) : 
		return True
	if (n % 2 == 0 or n % 3 == 0) : 
		return False
	i = 5
	while(i * i <= n) :...