human
Solve the following python programming problem given the following code:
def _has_valid_type(self, key, axis) : 
    ax = self.obj._get_axis (axis) 
    if isinstance (key, slice) : 
        return True 
else : 
        if is_bool_indexer (key) : 
            return True 
else : 
            if is_list_like_indexer (key) : 
                if (isinstance (key, tuple) and isinstance (ax, MultiIndex)) : 
                    return True 
if (len (key) and np.all ((ax.get_indexer_for (key) < 0))) : 
                    raise KeyError (('None of [%s] are in the [%s]' % (key, self.obj._get_axis_name (axis)))) 
return True 
else : 
                def error() : 
                    if isnull (key) : 
                        raise TypeError ('cannot use label indexing with a null key') 
raise KeyError (('the label [%s] is not in the [%s]' % (key, self.obj._get_axis_name (axis)))) 
try : 
                    key = self._convert_scalar_indexer (key, axis) 
                    if (key not in ax) : 
                        error () 
except TypeError as e : 
                    if ('unorderable' in str (error)) : 
                        error () 
raise 
except : 
                    error () 
return True 

    
    

    Fix the buggy line: if ('unorderable' in str (error)) :
assistant
#Here is Python code to fix the buggy line: if ('unorderable' in str (error)) :
.

if ('unorderable' in str (e)) :