human
Solve in Python:
On a broken calculator that has a number showing on its display, we can perform two operations:

Double: Multiply the number on the display by 2, or;
Decrement: Subtract 1 from the number on the display.

Initially, the calculator is displaying the number X.
Return the minimum number of operations needed to display the number Y.
 
Example 1:
Input: X = 2, Y = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.

Example 2:
Input: X = 5, Y = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.

Example 3:
Input: X = 3, Y = 10
Output: 3
Explanation:  Use double, decrement and double {3 -> 6 -> 5 -> 10}.

Example 4:
Input: X = 1024, Y = 1
Output: 1023
Explanation: Use decrement operations 1023 times.

 
Note:

1 <= X <= 10^9
1 <= Y <= 10^9

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Give me a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        cnt=0
        while Y>X:
            cnt+=1
            if Y%2==0:
                Y//=2
            else:
                Y+=1
        return cnt+X-Y