human
Replace every array element by Bitwise Xor of previous and next element | Python3 program to update every array element with sum of previous and next numbers in array.
Nothing to do when array size is 1.
store current value of arr [ 0 ] and update it.
Update rest of the array elements.
Store current value of next interaction.
Update current value using previous value.
Update previous value.
Update last array element separately.
Driver Code.
Print the modified array"
Solution in Python:
assistant
#Here is code to replace every array element by Bitwise Xor of previous and next element and the other steps required.
 def ReplaceElements ( arr , n ) :
	if n <= 1 :
		return
	prev = arr [ 0 ]
	arr [ 0 ] = arr [ 0 ] ^ arr [ 1 ]
	for i in range ( 1 , n - 1 ) :
		curr = arr [ i ]
		arr [ i ] = prev ^ arr [ i + 1 ]
		prev = curr
	arr [ n - 1 ] = prev ^ arr [ n - 1 ]
arr = [ 2 , 3 , 4 , 5 , 6 ]
n = len ( arr )
ReplaceElements ( arr , n )
for i in range ( n ) :
	print ( arr [ i ] , end = " ▁ " )