human
Sum of Bitwise XOR of elements of an array with all elements of another array | Function to calculate sum of Bitwise XOR of elements of arr [ ] with k.
Initialize sum to be zero.
Iterate over each set bit.
Stores contribution of i - th bet to the sum.
If the i - th bit is set.
Stores count of elements whose i - th bit is not set.
Update value.
Update value.
Add value to sum.
Move to the next power of two.
Stores the count of elements whose i - th bit is set.
Traverse the array.
Iterate over each bit.
If the i - th bit is set.
Increase count.
Driver Code"
Solution in Python:

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What is a code to sum of Bitwise XOR of elements of an array with all elements of another array and the other steps required?
assistant
#Here is code to sum of Bitwise XOR of elements of an array with all elements of another array and the other steps required.
 def xorSumOfArray ( arr , n , k , count ) :
	sum = 0
	p = 1
	for i in range ( 31 ) :
		val = 0
		if ( ( k & ( 1 << i ) ) != 0 ) :
			not_set = n - count [ i ]
			val = ( ( not_set ) * p )
		else :
			val = ( count [ i ] * p )
		sum += val
		p = ( p * 2 )
	return sum
def sumOfXors ( arr , n , queries , q ) :
	count = [ 0 for i in range ( 32 ) ]
	for i in range ( n ) :
		for j in range ( 31 ) :
			if ( arr [ i ] & ( 1 << j ) ) :
				count [ j ] += 1
	for i in range ( q ) :
		k = queries [ i ]
		print ( xorSumOfArray ( arr , n , k , count ) , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 5 , 2 , 3 ]
	queries = [ 3 , 8 , 7 ]
	n = len ( arr )
	q = len ( queries )
	sumOfXors ( arr , n , queries , q )