human
Can you provide a code to count total set bits in all numbers from 1 to n and the other steps required given the following:
Count total set bits in all numbers from 1 to n | Set 2 | Function to return the sum of the count of set bits in the integers from 1 to n.
Ignore 0 as all the bits are unset.
To store the powers of 2.
To store the result , it is initialized with n / 2 because the count of set least significant bits in the integers from 1 to n is n / 2.
Loop for every bit required to represent n.
Total count of pairs of 0 s and 1 s.
totalPairs / 2 gives the complete count of the pairs of 1 s Multiplying it with the current power of 2 will give the count of 1 s in the current bit.
If the count of pairs was odd then add the remaining 1 s which could not be groupped together.
Next power of 2.
Return the result.
Driver code"
Solution in Python:
assistant
#Here is code to count total set bits in all numbers from 1 to n and the other steps required.
 def countSetBits ( n ) :
	n += 1 ;
	powerOf2 = 2 ;
	cnt = n // 2 ;
	while ( powerOf2 <= n ) :
		totalPairs = n // powerOf2 ;
		cnt += ( totalPairs // 2 ) * powerOf2 ;
		if ( totalPairs & 1 ) :
			cnt += ( n % powerOf2 )
		else :
			cnt += 0
		powerOf2 <<= 1 ;
	return cnt ;
if __name__ == " _ _ main _ _ " :
	n = 14 ;
	print ( countSetBits ( n ) ) ;