human
What is a code to count all distinct pairs with difference equal to k and the other steps required given the following:
Count all distinct pairs with difference equal to k | Returns count of pairs with difference k in arr [ ] of size n ..
Sort array elements.
arr [ r ] - arr [ l ] < sum.
Driver code"
Solution in Python:
assistant
#Here is code to count all distinct pairs with difference equal to k and the other steps required.
 def countPairsWithDiffK ( arr , n , k ) :
	count = 0
	arr . sort ( )
	l = 0
	r = 0
	while r < n :
		if arr [ r ] - arr [ l ] == k :
			count += 1
			l += 1
			r += 1
		elif arr [ r ] - arr [ l ] > k :
			l += 1
		else :
			r += 1
	return count
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 5 , 3 , 4 , 2 ]
	n = len ( arr )
	k = 3
	print ( " Count ▁ of ▁ pairs ▁ with ▁ given ▁ diff ▁ is ▁ " , countPairsWithDiffK ( arr , n , k ) )