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Count the number of operations required to reduce the given number | Python3 implementation of the approach.
To store the normalized value of all the operations.
Minimum possible value for a series of operations.
If k can be reduced with first ( i + 1 ) operations.
Impossible to reduce k.
Number of times all the operations can be performed on k without reducing it to <= 0.
Perform operations.
Final check.
Driver code"
Solution in Python:
assistant
#Here is code to count the number of operations required to reduce the given number and the other steps required.
 def operations ( op , n , k ) :
	i , count = 0 , 0
	nVal = 0
	minimum = 10 ** 9
	for i in range ( n ) :
		nVal += op [ i ]
		minimum = min ( minimum , nVal )
		if ( ( k + nVal ) <= 0 ) :
			return ( i + 1 )
	if ( nVal >= 0 ) :
		return - 1
	times = ( k - abs ( minimum ) ) // abs ( nVal )
	k = ( k - ( times * abs ( nVal ) ) )
	count = ( times * n )
	while ( k > 0 ) :
		for i in range ( n ) :
			k = k + op [ i ]
			count += 1
			if ( k <= 0 ) :
				break
	return count
op = [ - 60 , 65 , - 1 , 14 , - 25 ]
n = len ( op )
k = 100000
print ( operations ( op , n , k ) )