human
Minimum removal to make palindrome permutation | function to find minimum removal of characters.
hash to store frequency of each character to set hash array to zeros.
count frequency of each character.
count the odd frequency characters.
if count is 0 , return 0 otherwise return count.
Driver 's Code"
How can the above be solved in Python?
assistant
#Here is code to minimum removal to make palindrome permutation and the other steps required.
 def minRemoval ( strr ) :
	hash = [ 0 ] * 26
	for char in strr :
		hash [ ord ( char ) - ord ( ' a ' ) ] = hash [ ord ( char ) - ord ( ' a ' ) ] + 1
	count = 0
	for i in range ( 26 ) :
		if hash [ i ] % 2 :
			count = count + 1
	return 0 if count == 0 else count - 1
if __name__ == " _ _ main _ _ " :
	strr = " geeksforgeeks " ;