human
Minimize swaps between two arrays such that sum of the first array exceeds sum of the second array | Function to find the minimum count of swaps required between the two arrays to make the sum of arr1 [ ] greater than that of arr2 [ ].
Stores the sum of the two arrays.
Calculate sum of arr1 [ ].
Calculate sum of arr2 [ ].
Sort the arrays arr1 [ ] and arr2 [ ].
Traverse the array arr [ ].
If the sum1 is less than or equal to sum2.
Swapping the elements.
Update the sum1 and sum2.
Increment the count.
Return the final count.
Driver Code.
Function Call"
How can the above be solved in Python?

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Can you provide a code to minimize swaps between two arrays such that sum of the first array exceeds sum of the second array and the other steps required?
assistant
#Here is code to minimize swaps between two arrays such that sum of the first array exceeds sum of the second array and the other steps required.
 def maximumCount ( arr1 , arr2 , s1 , s2 ) :
	sum1 = 0
	sum2 = 0
	for i in range ( s1 ) :
		sum1 += arr1 [ i ]
	for j in range ( s2 ) :
		sum2 += arr2 [ j ]
	len = 0
	if ( s1 >= s2 ) :
		lenn = s2
	else :
		lenn = s1
	arr1 . sort ( ) ;
	arr2 . sort ( ) ;
	j = 0
	k = s2 - 1
	count = 0
	for i in range ( lenn ) :
		if ( sum1 <= sum2 ) :
			if ( arr2 [ k ] >= arr1 [ i ] ) :
				dif1 = arr1 [ j ]
				dif2 = arr2 [ k ]
				sum1 -= dif1
				sum1 += dif2
				sum2 -= dif2
				sum2 += dif1
				j += 1
				k -= 1
				count += 1
			else :
				break
		else :
			break
	return count
arr1 = [ 1 , 3 , 2 , 4 ]
arr2 = [ 6 , 7 , 8 ]
N = len ( arr1 )
M = len ( arr2 )
print ( maximumCount ( arr1 , arr2 , N , M ) )