human
Give me a code to generate a circular permutation with number of mismatching bits between pairs of adjacent elements exactly 1 and the other steps required given the following:
Generate a circular permutation with number of mismatching bits between pairs of adjacent elements exactly 1 | Function to find the permutation of integers from a given range such that number of mismatching bits between pairs of adjacent elements is 1.
Initialize an arrayList to store the resultant permutation.
Store the index of rotation.
Iterate over the range [ 0 , N - 1 ].
Traverse all the array elements up to ( 2 ^ k ) - th index in reverse.
If current element is S.
Check if S is zero.
Rotate the array by index value to the left.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to generate a circular permutation with number of mismatching bits between pairs of adjacent elements exactly 1 and the other steps required.
 def circularPermutation ( n , start ) :
	res = [ 0 ]
	ret = [ ]
	index , add = - 1 , 1
	for k in range ( n ) :
		add = 1 << k
		for i in range ( len ( res ) - 1 , - 1 , - 1 ) :
			if ( res [ i ] + add == start ) :
				index = len ( res )
			res . append ( res [ i ] + add )
		add = 1 << k
	if ( start == 0 ) :
		return res
	while ( len ( ret ) < len ( res ) ) :
		ret . append ( res [ index ] )
		index = ( index + 1 ) % len ( res )
	return ret
if __name__ == ' _ _ main _ _ ' :
	N , S = 2 , 3
	print ( circularPermutation ( N , S ) )