human
Complete the below
def _escaped_text_from_text(text, escapes='eol'):

    ''''Return escaped version of text.
    "escapes" is either a mapping of chars in the source text to
    replacement text for each such char or one of a set of
    strings identifying a particular escape style:
    eol
    replace EOL chars with \'\r\' and \'\n\', maintain the actual
    EOLs though too
    whitespace
    replace EOL chars as above, tabs with \'\t\' and spaces
    with periods (\'.\')
    eol-one-line
    replace EOL chars with \'\r\' and \'\n\'
    whitespace-one-line
    replace EOL chars as above, tabs with \'\t\' and spaces
    with periods (\'.\')'
    '''
 ... Write me a the Python code you requested?
assistant
#Here is the Python code you requested.
    import re
    if isinstance(escapes, basestring):
        if (escapes == 'eol'):
            escapes = {'\r\n': '\\r\\n\r\n', '\n': '\\n\n', '\r': '\\r\r'}
        elif (escapes == 'whitespace'):
            escapes = {'\r\n': '\\r\\n\r\n', '\n': '\\n\n', '\r': '\\r\r', ' DCTB ': '\\t', '    ': '.'}
        elif (escapes == 'eol-one-line'):
            escapes = {'\n': '\\n', '\r': '\\r'}
        elif (escapes == 'whitespace-one-line'):
            escapes = {'\n': '\\n', '\r': '\\r', ' DCTB ': '\\t', '    ': '.'}
        else:
            raise ValueError(('unknown    text    escape    style:    %r' % escapes))
    escapes_keys = escapes.keys()
    try:
        escapes_keys.sort(key=(lambda a: len(a)), reverse=True)
    except TypeError:
        escapes_keys.sort((lambda a, b: cmp(len(a), len(b))))
        escapes_keys.reverse()
    def repl(match):
        val = escapes[match.group(0)]
        return val
    escaped = re.sub(('(%s)' % '|'.join([re.escape(k) for k in escapes_keys])), repl, text)
    return escaped