human
Total count of sorted numbers upto N digits in range [ L , R ] ( Magnificent necklace combinatorics problem ) | Function to count total number of ways.
Stores all DP - states.
Stores the result.
Traverse the range [ 0 , N ].
Traverse the range [ 1 , R - L ].
Update dp [ i ] [ j ].
Assign dp [ 0 ] [ R - L ] to ans.
Traverse the range [ 1 , N ].
Traverse the range [ 1 , R - L ].
Update dp [ i ] [ j ].
Increment ans by dp [ i - 1 ] [ j ].
Return ans.
Driver Code.
Input.
Function call"
Solution in Python:
 ... What is a code to total count of sorted numbers upto N digits in range [ L , R ] ( Magnificent necklace combinatorics problem ) and the other steps required?
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#Here is code to total count of sorted numbers upto N digits in range [ L , R ] ( Magnificent necklace combinatorics problem ) and the other steps required.
 def Count ( N , L , R ) :
	dp = [ [ 0 for i in range ( R - L + 1 ) ] for i in range ( N ) ]
	ans = 0
	for i in range ( N ) :
		dp [ i ] [ 0 ] = 1
	for i in range ( 1 , len ( dp [ 0 ] ) ) :
		dp [ 0 ] [ i ] = dp [ 0 ] [ i - 1 ] + 1
	ans = dp [ 0 ] [ R - L ]
	for i in range ( 1 , N ) :
		for j in range ( 1 , len ( dp [ 0 ] ) ) :
			dp [ i ] [ j ] = dp [ i - 1 ] [ j ] + dp [ i ] [ j - 1 ]
		ans += dp [ i ] [ R - L ]
	return ans
if __name__ == ' _ _ main _ _ ' :
	N = 3
	L = 6
	R = 9
	print ( Count ( N , L , R ) )