human
Count all subarrays whose sum can be split as difference of squares of two Integers | Function to count all the non - contiguous subarrays whose sum can be split as the difference of the squares.
Loop to iterate over all the possible subsequences of the array.
Finding the sum of all the possible subsequences.
Condition to check whether the number can be split as difference of squares.
Driver code"
Solution in Python:

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Give me a code to count all subarrays whose sum can be split as difference of squares of two Integers and the other steps required?
assistant
#Here is code to count all subarrays whose sum can be split as difference of squares of two Integers and the other steps required.
 def Solve ( arr , n ) :
	temp = 0 ; count = 0 ;
	for i in range ( 0 , n ) :
		temp = 0 ;
		for j in range ( i , n ) :
			temp = temp + arr [ j ] ;
			if ( ( temp + 2 ) % 4 != 0 ) :
				count += 1 ;
	return count ;
arr = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 ] ;
N = len ( arr ) ;
print ( Solve ( arr , N ) ) ;