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Rearrange the Array to maximize the elements which is smaller than both its adjacent elements | Function to rearrange array such that count of element that are smaller than their adjacent elements is maximum.
Stores the rearranged array.
Stores the maximum count of elements.
Sort the given array.
Place the smallest ( N - 1 ) / 2 elements at odd indices.
Placing the rest of the elements at remaining indices.
If no element of the array has been placed here.
Print the resultant array.
Input.
Function call"
Solution in Python:

What is a code to rearrange the Array to maximize the elements which is smaller than both its adjacent elements and the other steps required?
assistant
#Here is code to rearrange the Array to maximize the elements which is smaller than both its adjacent elements and the other steps required.
 def maximumIndices ( arr , N ) :
	temp = [ 0 ] * N
	maxIndices = ( N - 1 ) // 2
	arr . sort ( )
	for i in range ( maxIndices ) :
		temp [ 2 * i + 1 ] = arr [ i ]
	j = 0
	i = maxIndices
	while ( i < N ) :
		if ( temp [ j ] == 0 ) :
			temp [ j ] = arr [ i ]
			i += 1
		j += 1
	for i in range ( N ) :
		print ( temp [ i ] , end = " ▁ " )
arr = [ 1 , 2 , 3 , 4 ]
N = len ( arr )
maximumIndices ( arr , N )