human
Count pairs with equal Bitwise AND and Bitwise OR value | Function to count pairs in an array whose bitwise AND equal to bitwise OR.
Store count of pairs whose bitwise AND equal to bitwise OR.
Stores frequency of distinct elements of array.
Traverse the array.
Increment the frequency of arr [ i ].
Traverse map.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count pairs with equal Bitwise AND and Bitwise OR value and the other steps required.
 def countPairs ( arr , N ) :
	cntPairs = 0
	mp = { }
	for i in range ( 0 , N ) :
		if arr [ i ] in mp :
			mp [ arr [ i ] ] = mp [ arr [ i ] ] + 1
		else :
			mp [ arr [ i ] ] = 1
	for freq in mp :
		cntPairs += int ( ( mp [ freq ] * ( mp [ freq ] - 1 ) ) / 2 )
	return cntPairs
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 , 1 , 2 , 2 ]
	N = len ( arr )
	print ( countPairs ( arr , N ) )