human
Count different Bitwise OR values of equal length strings S1 and S2 by swapping exactly one pair of characters from the first string | Function to find the number of ways to obtain different Bitwise OR.
Stores the count of pairs t00 , t10 , t01 , t11.
Traverse the characters of the string S1 and S2.
Count the pair ( 0 , 0 ).
Count the pair ( 1 , 0 ).
Count the pair ( 1 , 1 ).
Count the pair ( 0 , 1 ).
Number of ways to calculate the different bitwise OR.
Print the result.
Driver Code"
Solution in Python:
assistant
#Here is code to count different Bitwise OR values of equal length strings S1 and S2 by swapping exactly one pair of characters from the first string and the other steps required.
 def differentBitwiseOR ( s1 , s2 ) :
	n = len ( s1 )
	t00 = 0
	t10 = 0
	t01 = 0
	t11 = 0
	for i in range ( n ) :
		if ( s1 [ i ] == '0' and s2 [ i ] == '0' ) :
			t00 += 1
		if ( s1 [ i ] == '1' and s2 [ i ] == '0' ) :
			t10 += 1
		if ( s1 [ i ] == '1' and s2 [ i ] == '1' ) :
			t11 += 1
		if ( s1 [ i ] == '0' and s2 [ i ] == '1' ) :
			t01 += 1
	ans = t00 * t10 + t01 * t10 + t00 * t11
	print ( ans )
S1 = "01001"
S2 = "11011"
differentBitwiseOR ( S1 , S2 )