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Efficiently merging two sorted arrays with O ( 1 ) extra space | Function to find next gap ..
comparing elements in the first array ..
comparing elements in both arrays ..
comparing elements in the second array ..
Driver code.
Function Call"
Solution in Python:
assistant
#Here is code to efficiently merging two sorted arrays with O ( 1 ) extra space and the other steps required.
 def nextGap ( gap ) :
	if ( gap <= 1 ) :
		return 0
	return ( gap // 2 ) + ( gap % 2 )
def merge ( arr1 , arr2 , n , m ) :
	gap = n + m
	gap = nextGap ( gap )
	while gap > 0 :
		i = 0
		while i + gap < n :
			if ( arr1 [ i ] > arr1 [ i + gap ] ) :
				arr1 [ i ] , arr1 [ i + gap ] = arr1 [ i + gap ] , arr1 [ i ]
			i += 1
		j = gap - n if gap > n else 0
		while i < n and j < m :
			if ( arr1 [ i ] > arr2 [ j ] ) :
				arr1 [ i ] , arr2 [ j ] = arr2 [ j ] , arr1 [ i ]
			i += 1
			j += 1
		if ( j < m ) :
			j = 0
			while j + gap < m :
				if ( arr2 [ j ] > arr2 [ j + gap ] ) :
					arr2 [ j ] , arr2 [ j + gap ] = arr2 [ j + gap ] , arr2 [ j ]
				j += 1
		gap = nextGap ( gap )
if __name__ == " _ _ main _ _ " :
	a1 = [ 10 , 27 , 38 , 43 , 82 ]
	a2 = [ 3 , 9 ]
	n = len ( a1 )
	m = len ( a2 )
	merge ( a1 , a2 , n , m )
	print ( " First ▁ Array : ▁ " , end = " " )
	for i in range ( n ) :
		print ( a1 [ i ] , end = " ▁ " )
	print ( )
	print ( " Second ▁ Array : ▁ " , end = " " )
	for i in range ( m ) :
		print ( a2 [ i ] , end = " ▁ " )
	print ( )