human
Minimum number of intervals to cover the target interval | Function to find the minimum number of intervals in the array A [ ] to cover the entire target interval.
Sort the array A [ ] in increasing order of starting point.
Insert a pair of INT_MAX to prevent going out of bounds.
Stores start of current interval.
Stores end of current interval.
Stores the count of intervals.
Iterate over all the intervals.
If starting point of current index <= start.
Update the value of start.
Increment the value of count.
If the target interval is already covered or it is not possible to move then break the loop.
If the entire target interval is not covered.
Return Answer.
Driver Code"
How can the above be solved in Python?

Can you provide a code to minimum number of intervals to cover the target interval and the other steps required?
assistant
#Here is code to minimum number of intervals to cover the target interval and the other steps required.
 def minimizeSegment ( A , X ) :
	A . sort ( )
	INT_MAX = 2147483647
	A . append ( [ INT_MAX , INT_MAX ] )
	start = X [ 0 ]
	end = X [ 0 ] - 1
	cnt = 0
	for i in range ( 0 , len ( A ) ) :
		if ( A [ i ] [ 0 ] <= start ) :
			end = max ( A [ i ] [ 1 ] , end )
			i = i + 1
		else :
			start = end
			cnt = cnt + 1
			if ( A [ i ] [ 0 ] > end or end >= X [ 1 ] ) :
				break
	if ( end < X [ 1 ] ) :
		return - 1
	return cnt
if __name__ == " _ _ main _ _ " :
	A = [ [ 1 , 3 ] , [ 2 , 4 ] , [ 2 , 10 ] , [ 2 , 3 ] , [ 1 , 1 ] ]
	X = [ 1 , 10 ]
	print ( minimizeSegment ( A , X ) )