human
Give me a code to check if it is possible to form string B from A under the given constraints and the other steps required given the following:
Check if it is possible to form string B from A under the given constraints | Function that returns true if it is possible to form B from A satisfying the given conditions.
List to store the frequency of characters in A.
Vector to store the count of characters used from a particular group of characters.
Store the frequency of the characters.
If a character in B is not present in A.
If count of characters used from a particular group of characters exceeds m.
Update low to the starting index of the next group.
If count of characters used from a particular group of characters has not exceeded m ;"
Solution in Python:
assistant
#Here is code to check if it is possible to form string B from A under the given constraints and the other steps required.
 def isPossible ( A , B , b , m ) :
	S = [ ]
	for i in range ( 26 ) :
		S . append ( [ ] )
	box = [ 0 ] * len ( A )
	for i in range ( len ( A ) ) :
		S [ ord ( A [ i ] ) - ord ( ' a ' ) ] . append ( i )
	low = 0
	for i in range ( len ( B ) ) :
		indexes = S [ ord ( B [ i ] ) - ord ( ' a ' ) ]
		it = lower_bound ( indexes , low )
		if ( it == len ( indexes ) ) :
			return False
		count = indexes [ it ] // b
		box [ count ] = box [ count ] + 1
		if ( box [ count ] >= m ) :
			count += 1
			low = ( count ) * b
		else :
			low = indexes [ it ] + 1
	return True
def lower_bound ( indexes , k ) :
	low , high = 0 , len ( indexes ) - 1
	while ( low < high ) :
		mid = ( low + high ) // 2
		if ( indexes [ mid ] < k ) :
			low = mid + 1
		else :
			high = mid
	if indexes [ low ] < k :
		return ( low + 1 )
	else :
		return low
/ * Driver code * /
A = " abcbbcdefxyz "
B = " acdxyz "
b = 5
m = 2
if ( isPossible ( A , B , b , m ) ) :
	print ( " Yes " )
else :
	print ( " No " )