human
Number of non | Function to return the count of increasing subarrays of length k.
To store the final result.
Two pointer loop.
Initialising j.
Looping till the subarray increases.
Updating the required count.
Updating i.
Returning res.
Driver code"
How can the above be solved in Python?
 ... Write me a code to number of non and the other steps required?
assistant
#Here is code to number of non and the other steps required.
 def cntSubArrays ( arr , n , k ) :
	res = 0 ;
	i = 0 ;
	while ( i < n ) :
		j = i + 1 ;
		while ( j < n and arr [ j ] >= arr [ j - 1 ] ) :
			j += 1 ;
		res += max ( j - i - k + 1 , 0 ) ;
		i = j ;
	return res ;
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 , 2 , 5 ] ;
	n = len ( arr ) ;
	k = 2 ;
	print ( cntSubArrays ( arr , n , k ) ) ;