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Count possible removals to make absolute difference between the sum of odd and even indexed elements equal to K | Function to check if difference between the sum of odd and even indexed elements after removing the first element is K or not.
Stores the sum of elements at odd and even indices.
Return 1 if difference is K.
Function to check if difference between the sum of odd and even indexed elements after removing the second element is K or not.
Stores the sum of elements at odd and even indices.
Return 1 if difference is K.
Function to count number of elements to be removed to make sum of differences between odd and even indexed elements equal to K.
Size of given array.
Base Conditions.
Stores prefix and suffix sums.
Base assignments.
Store prefix sums of even indexed elements.
Store prefix sums of odd indexed elements.
Similarly , store suffix sums of elements at even and odd indices.
Stores the count of possible removals.
Traverse and remove the ith element.
If the current element is excluded , then previous index ( i - 1 ) points to ( i + 2 ) and ( i - 2 ) points to ( i + 1 ).
Find count when 0 th element is removed.
Find count when 1 st element is removed.
Count gives the required answer.
Driver Code.
Function call"
How can the above be solved in Python?
 What is a code to count possible removals to make absolute difference between the sum of odd and even indexed elements equal to K and the other steps required?
assistant
#Here is code to count possible removals to make absolute difference between the sum of odd and even indexed elements equal to K and the other steps required.
 def findCount0th ( arr , N , K ) :
	oddsum = 0
	evensum = 0
	for i in range ( 1 , N , 2 ) :
		oddsum += arr [ i ]
	for i in range ( 2 , N , 2 ) :
		evensum += arr [ i ]
	if ( abs ( oddsum - evensum ) == K ) :
		return 1
	else :
		return 0
def findCount1st ( arr , N , K ) :
	evensum = arr [ 0 ]
	oddsum = 0
	for i in range ( 3 , N , 2 ) :
		evensum += arr [ i ]
	for i in range ( 2 , N , 2 ) :
		oddsum += arr [ i ]
	if ( abs ( oddsum - evensum ) == K ) :
		return 1
	else :
		return 0
def countTimes ( arr , K ) :
	N = len ( arr )
	if ( N == 1 ) :
		return 1
	if ( N < 3 ) :
		return 0
	if ( N == 3 ) :
		cnt = 0
		if abs ( arr [ 0 ] - arr [ 1 ] ) == K :
			cnt += 1
		if abs ( arr [ 2 ] - arr [ 1 ] ) == K :
			cnt += 1
		if abs ( arr [ 0 ] - arr [ 2 ] ) == K :
			cnt += 1
		return cnt
	prefix = [ 0 ] * ( N + 2 )
	suffix = [ 0 ] * ( N + 2 )
	prefix [ 0 ] = arr [ 0 ]
	prefix [ 1 ] = arr [ 1 ]
	suffix [ N - 1 ] = arr [ N - 1 ]
	suffix [ N - 2 ] = arr [ N - 2 ]
	for i in range ( 2 , N , 2 ) :
		prefix [ i ] = arr [ i ] + prefix [ i - 2 ]
	for i in range ( 3 , N , 2 ) :
		prefix [ i ] = arr [ i ] + prefix [ i - 2 ]
	for i in range ( N - 3 , - 1 , - 2 ) :
		suffix [ i ] = arr [ i ] + suffix [ i + 2 ]
	for i in range ( N - 4 , - 1 , - 2 ) :
		suffix [ i ] = arr [ i ] + suffix [ i + 2 ]
	count = 0
	for i in range ( 2 , N ) :
		if ( abs ( prefix [ i - 1 ] + suffix [ i + 2 ] - prefix [ i - 2 ] - suffix [ i + 1 ] ) == K ) :
			count += 1
	count += findCount0th ( arr , N , K )
	count += findCount1st ( arr , N , K )
	return count
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 4 , 5 , 6 ]
	K = 2
	print ( countTimes ( arr , K ) )