human
Count all disjoint pairs having absolute difference at least K from a given array | Function to check if it is possible to form M pairs with abs diff at least K.
Traverse the array over [ 0 , M ].
If valid index.
Return 1.
Function to count distinct pairs with absolute difference atleasr K.
Stores the count of all possible pairs.
Initialize left and right.
Sort the array.
Perform Binary Search.
Find the value of mid.
Check valid index.
Update ans.
Print the answer.
Driver Code.
Given array arr [ ].
Given difference K.
Size of the array.
Function call"
Solution in Python:
assistant
#Here is code to count all disjoint pairs having absolute difference at least K from a given array and the other steps required.
 def isValid ( arr , n , m , d ) :
	for i in range ( m ) :
		if ( abs ( arr [ n - m + i ] - arr [ i ] ) < d ) :
			return 0
	return 1
def countPairs ( arr , N , K ) :
	ans = 0
	left = 0
	right = N // 2 + 1
	arr . sort ( reverse = False )
	while ( left < right ) :
		mid = ( left + right ) // 2
		if ( isValid ( arr , N , mid , K ) ) :
			ans = mid
			left = mid + 1
		else :
			right = mid - 1
	print ( ans , end = " " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 3 , 3 , 5 ]
	K = 2
	N = len ( arr )
	countPairs ( arr , N , K )