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Count ways to generate an array having distinct elements at M consecutive indices | Modular function to calculate factorial.
Stores factorial of N.
Iterate over the range [ 1 , N ].
Update result.
Function to count ways to replace array elements having 0 s with non - zero elements such that any M consecutive elements are distinct.
Store m consecutive distinct elements such that arr [ i ] is equal to B [ i % M ].
Stores frequency of array elements.
Traverse the array arr.
If arr [ i ] is non - zero.
If B [ i % M ] is equal to 0.
Update B [ i % M ].
Update frequency of arr [ i ].
If a duplicate element found in M consecutive elements.
Handling the case of inequality.
Stores count of 0 s in B.
Traverse the array , B.
If B [ i ] is 0.
Update cnt.
Calculate factorial.
Driver Code.
Given M.
Given array.
Size of the array.
Function Call"
How can the above be solved in Python?
 Can you provide a code to count ways to generate an array having distinct elements at M consecutive indices and the other steps required?
assistant
#Here is code to count ways to generate an array having distinct elements at M consecutive indices and the other steps required.
 def Fact ( N ) :
	result = 1
	for i in range ( 1 , N + 1 ) :
		result = ( result * i )
	return result
def numberOfWays ( M , arr , N ) :
	B = [ 0 ] * ( M )
	counter = [ 0 ] * ( M + 1 )
	for i in range ( 0 , N ) :
		if ( arr [ i ] != 0 ) :
			if ( B [ i % M ] == 0 ) :
				B [ i % M ] = arr [ i ]
				counter [ arr [ i ] ] += 1
				if ( counter [ arr [ i ] ] > 1 ) :
					print ( 0 )
					return
			elif ( B [ i % M ] != arr [ i ] ) :
				print ( 0 )
				return
	cnt = 0
	for i in range ( 0 , M ) :
		if ( B [ i ] == 0 ) :
			cnt += 1
	print ( Fact ( cnt ) )
if __name__ == ' _ _ main _ _ ' :
	M = 4
	arr = [ 1 , 0 , 3 , 0 , 0 ]
	N = len ( arr )
	numberOfWays ( M , arr , N )