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Find k ordered pairs in array with minimum difference d | Function to find the required pairs.
There has to be atleast 2 * k elements.
To store the pairs.
Sort the given array.
For every possible pair.
If the current pair is valid.
Insert it into the pair vector.
If k pairs are not possible.
Print the pairs.
Driver code"
Solution in Python:
assistant
#Here is code to find k ordered pairs in array with minimum difference d and the other steps required.
 def findPairs ( arr , n , k , d ) :
	if ( n < 2 * k ) :
		print ( " - 1" )
		return
	pairs = [ ]
	arr = sorted ( arr )
	for i in range ( k ) :
		if ( arr [ n - k + i ] - arr [ i ] >= d ) :
			pairs . append ( [ arr [ i ] , arr [ n - k + i ] ] )
	if ( len ( pairs ) < k ) :
		print ( " - 1" )
		return
	for v in pairs :
		print ( " ( " , v [ 0 ] , " , ▁ " , v [ 1 ] , " ) " )
arr = [ 4 , 6 , 10 , 23 , 14 , 7 , 2 , 20 , 9 ]
n = len ( arr )
k = 4
d = 3
findPairs ( arr , n , k , d )