human
Count prime numbers that can be expressed as sum of consecutive prime numbers | Function to check if a number is prime or not.
Base Case.
Iterate till [ 5 , sqrt ( N ) ] to detect primality of numbers.
If N is divisible by i or i + 2.
Return 1 if N is prime.
Function to count the prime numbers which can be expressed as sum of consecutive prime numbers.
Initialize count as 0.
Stores prime numbers.
If i is prime.
Initialize the sum.
Find all required primes upto N.
Add it to the sum.
Return the final count.
Given number N.
Function call"
Solution in Python:
assistant
#Here is code to count prime numbers that can be expressed as sum of consecutive prime numbers and the other steps required.
 def isprm ( n ) :
	if ( n <= 1 ) :
		return 0
	if ( n <= 3 ) :
		return 1
	if ( n % 2 == 0 or n % 3 == 0 ) :
		return 0
	i = 5
	while ( i * i <= n ) :
		if ( n % i == 0 or n % ( i + 2 ) == 0 ) :
			return 0
		i = i + 6
	return 1
def countprime ( n ) :
	count = 0
	primevector = [ ]
	for i in range ( 2 , n + 1 ) :
		if ( isprm ( i ) == 1 ) :
			primevector . append ( i )
	sum = primevector [ 0 ]
	for i in range ( 1 , len ( primevector ) ) :
		sum += primevector [ i ]
		if ( sum > n ) :
			break
		if ( isprm ( sum ) == 1 ) :
			count += 1
	return count
N = 45
print ( countprime ( N ) )