human
You are given an array a of n integers, and another integer k such that 2k ≤ n.

You have to perform exactly k operations with this array. In one operation, you have to choose two elements of the array (let them be a_i and a_j.
they can be equal or different, but their positions in the array must not be the same), remove them from the array, and add ⌊ (a_i)/(a_j) ⌋ to your score, where ⌊ x/y ⌋ is the maximum integer not exceeding x/y.

Initially, your score is 0. After you perform exactly k operations, you add all the remaining elements of the array to the score.

Calculate the minimum possible score you can get.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.

Each test case consists of two lines. The first line contains two integers n and k (1 ≤ n ≤ 100.
0 ≤ k ≤ ⌊ n/2 ⌋).

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 2 ⋅ 10^5).

Output

Print one integer — the minimum possible score you can get.

Example

Input

5
7 3
1 1 1 2 1 3 1
5 1
5 5 5 5 5
4 2
1 3 3 7
2 0
4 2
9 2
1 10 10 1 10 2 7 10 3

Output

2
16
0
6
16

Note

Let's consider the example test.

In the first test case, one way to obtain a score of 2 is the following one:

  1. choose a_7 = 1 and a_4 = 2 for the operation.
the score becomes 0 + ⌊ 1/2 ⌋ = 0, the array becomes [1, 1, 1, 1, 3].

  2. choose a_1 = 1 and a_5 = 3 for the operation.
the score becomes 0 + ⌊ 1/3 ⌋ = 0, the array becomes [1, 1, 1].

  3. choose a_1 = 1 and a_2 = 1 for the operation.
the score becomes 0 + ⌊ 1/1 ⌋ = 1, the array becomes [1].

  4. add the remaining element 1 to the score, so the resulting score is 2. 


In the second test case, no matter which operations you choose, the resulting score is 16.

In the third test case, one way to obtain a score of 0 is the following one:

  1. choose a_1 = 1 and a_2 = 3 for the operation.
the score becomes 0 + ⌊ 1/3 ⌋ = 0, the array becomes [3, 7].

  2. choose a_1 = 3 and a_2 = 7 for the operation.
the score becomes 0 + ⌊ 3/7 ⌋ = 0, the array becomes...
Using python3 can you solve the prior task?
 What is a Python program to print one integer — the minimum possible score you can get?
assistant
#Here is Python program to print one integer — the minimum possible score you can get.

#Mamma don't raises quitter.................................................
#manan is improving, keep hustling manan bhai ;)
from collections import deque as de
import math
import sys
from math import sqrt as sq
from math import floor as fl
from math import ceil as ce
from sys import stdin, stdout
import time

sys.setrecursionlimit(10**7)
from collections import Counter as cnt
from functools import  reduce

from itertools import groupby as gb
#from fractions import Fraction as fr
from bisect import bisect_left as bl, bisect_right as br
from typing import Coroutine

def factors(n):    
    return set(reduce(list.__add__, 
                ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
    
class My_stack():
    def __init__(self):
        self.data = []
    def my_push(self, x):
        return (self.data.append(x))
    def my_pop(self):
        return (self.data.pop())
    def __iter__(self):
        return iter(self.data)
    def my_peak(self):
        return (self.data[-1])
    def my_contains(self, x):
        return (self.data.count(x))
    def my_show_all(self):
        return (self.data)
    def isEmpty(self):
      return len(self.data)==0
    def len(self):
        return len(self.data)
    

arrStack = My_stack() 

class graph():
    def __init__(self):
        self.graphdict = {}
    def add_edge(self, node, neighbor):
        if node not in self.graphdict:
            self.graphdict[node]=[neighbor]
        else:
            self.graphdict[node].append(neighbor)
    def show_edge(self):
        for node in self.graphdict:
            for neighbors in self.graphdict:
                print(node, neighbors)
    def show_graph(self):
        return self.graphdict

    

    
            

#decimal to binary   
def decimalToBinary(n): 
    return bin(n).replace("0b", "")
#binary to decimal
def binarytodecimal(n):
    return int(n,2)

def isPrime(n) : 
	if (n <= 1) : 
		return False
	if (n <= 3) : 
		return True
	if (n % 2 == 0 or n % 3 == 0) : 
		return False
	i = 5
	while(i * i <= n) :...