human
Find number of pairs ( x , y ) in an Array such that x ^ y > y ^ x | Set 2 | Function to return the count of pairs.
Compute suffix sums till i = 3.
Base Case : x = 0.
No valid pairs.
Base Case : x = 1.
Store the count of 0 's.
Base Case : x = 2.
Store suffix sum upto 5.
Base Case : x = 3.
Store count of 2 and suffix sum upto 4.
For all other values of x.
For all x >= 2 , every y = 0 and every y = 1 makes a valid pair.
Return the count of pairs.
Driver code"
Solution in Python:

Can you provide a code to find number of pairs ( x , y ) in an Array such that x ^ y > y ^ x and the other steps required?
assistant
#Here is code to find number of pairs ( x , y ) in an Array such that x ^ y > y ^ x and the other steps required.
 def countPairs ( X , Y , m , n ) :
	suffix = [ 0 ] * 1005
	total_pairs = 0
	for i in range ( n ) :
		suffix [ Y [ i ] ] += 1
	for i in range ( int ( 1e3 ) , 2 , - 1 ) :
		suffix [ i ] += suffix [ i + 1 ]
	for i in range ( m ) :
		if ( X [ i ] == 0 ) :
			continue
		elif ( X [ i ] == 1 ) :
			total_pairs += suffix [ 0 ]
			continue
		elif ( X [ i ] == 2 ) :
			total_pairs += suffix [ 5 ]
		elif ( X [ i ] == 3 ) :
			total_pairs += ( suffix [ 2 ] + suffix [ 4 ] )
		else :
			total_pairs += suffix [ X [ i ] + 1 ]
		total_pairs += suffix [ 0 ] + suffix [ 1 ]
	return total_pairs
if __name__ == ' _ _ main _ _ ' :
	X = [ 10 , 19 , 18 ]
	Y = [ 11 , 15 , 9 ]
	m = len ( X )
	n = len ( Y )
	print ( countPairs ( X , Y , m , n ) )