human
Can you provide a code to count of unordered pair of indices such that ratio of elements at these indices is same as ratio of indices and the other steps required given the following:
Count of unordered pair of indices such that ratio of elements at these indices is same as ratio of indices | Function of find the count of unordered pairs ( i , j ) in the array such that arr [ j ] / arr [ i ] = j / i ..
Stores the count of valid pairs.
Iterating over all possible pairs.
Check if the pair is valid.
Return answer.
Driver Code.
Function Call"
Solution in Python:
assistant
#Here is code to count of unordered pair of indices such that ratio of elements at these indices is same as ratio of indices and the other steps required.
 def countPairs ( arr , n ) :
	count = 0
	for i in range ( n - 1 ) :
		for j in range ( i + 1 , n ) :
			if ( ( arr [ j ] % arr [ i ] == 0 ) and ( j + 1 ) % ( i + 1 ) == 0 and ( arr [ j ] // arr [ i ] == ( j + 1 ) // ( i + 1 ) ) ) :
				count += 1
	return count
if __name__ == " _ _ main _ _ " :
	arr = [ 5 , - 2 , 4 , 20 , 25 , - 6 ]
	n = len ( arr )
	print ( countPairs ( arr , n ) )