human
Write me a code to smallest odd number with even sum of digits from the given number N and the other steps required given the following:
Smallest odd number with even sum of digits from the given number N | Function to find the smallest odd number whose sum of digits is even from the given string.
Converting the given string to a list of digits.
An empty array to store the digits.
For loop to iterate through each digit.
If the given digit is odd then the digit is appended to the array b.
Sorting the list of digits.
If the size of the list is greater than 1 then a 2 digit smallest odd number is returned Since the sum of two odd digits is always even.
Else , - 1 is returned.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to smallest odd number with even sum of digits from the given number N and the other steps required.
 def smallest ( s ) :
	a = list ( s )
	b = [ ]
	for i in range ( len ( a ) ) :
		if ( int ( a [ i ] ) % 2 != 0 ) :
			b . append ( a [ i ] )
	b = sorted ( b )
	if ( len ( b ) > 1 ) :
		return int ( b [ 0 ] ) * 10 + int ( b [ 1 ] )
	return - 1
if __name__ == " _ _ main _ _ " :
	print ( smallest ( "15470" ) )