human
Minimum value of N such that xor from 1 to N is equal to K | Function to find the value of N.
handling case for '0.
handling case for '1.
when number is completely divided by 4 then minimum ' x ' will be 'k.
when number divided by 4 gives 3 as remainder then minimum ' x ' will be 'k-1.
else it is not possible to get k for any value of x.
let the given number be 7"
How can the above be solved in Python?
 ... Can you provide a code to minimum value of N such that xor from 1 to N is equal to K and the other steps required?
assistant
#Here is code to minimum value of N such that xor from 1 to N is equal to K and the other steps required.
 def findN ( k ) :
'
	if ( k == 0 ) :
		ans = 3
'
	if ( k == 1 ) :
		ans = 1
'
	elif ( k % 4 == 0 ) :
		ans = k
'
	elif ( k % 4 == 3 ) :
		ans = k - 1
	else :
		ans = - 1
	return ans
k = 7
res = findN ( k )
if ( res == - 1 ) :
	print ( " Not ▁ possible " )
else :
	print ( res )