human
Boyer Moore Algorithm | Good Suffix heuristic | preprocessing for strong good suffix rule.
m is the length of pattern.
if character at position i - 1 is not equivalent to character at j - 1 , then continue searching to right of the pattern for border.
the character preceding the occurrence of t in pattern P is different than the mismatching character in P , we stop skipping the occurrences and shift the pattern from i to j.
Update the position of next border.
p [ i - 1 ] matched with p [ j - 1 ] , border is found . store the beginning position of border.
Preprocessing for case 2.
set the border position of the first character of the pattern to all indices in array shift having shift [ i ] = 0.
suffix becomes shorter than bpos [ 0 ] , use the position of next widest border as value of j.
Search for a pattern in given text using Boyer Moore algorithm with Good suffix rule.
s is shift of the pattern with respect to text.
initialize all occurrence of shift to 0.
do preprocessing.
Keep reducing index j of pattern while characters of pattern and text are matching at this shift s.
If the pattern is present at the current shift , then index j will become - 1 after the above loop.
pat [ i ] != pat [ s + j ] so shift the pattern shift [ j + 1 ] times.
Driver Code"
Solution in Python:

Can you provide a code to boyer Moore Algorithm and the other steps required?
assistant
#Here is code to boyer Moore Algorithm and the other steps required.
 def preprocess_strong_suffix ( shift , bpos , pat , m ) :
	i = m
	j = m + 1
	bpos [ i ] = j
	while i > 0 :
		while j <= m and pat [ i - 1 ] != pat [ j - 1 ] :
			if shift [ j ] == 0 :
				shift [ j ] = j - i
			j = bpos [ j ]
		i -= 1
		j -= 1
		bpos [ i ] = j
def preprocess_case2 ( shift , bpos , pat , m ) :
	j = bpos [ 0 ]
	for i in range ( m + 1 ) :
		if shift [ i ] == 0 :
			shift [ i ] = j
		if i == j :
			j = bpos [ j ]
def search ( text , pat ) :
	s = 0
	m = len ( pat )
	n = len ( text )
	bpos = [ 0 ] * ( m + 1 )
	shift = [ 0 ] * ( m + 1 )
	preprocess_strong_suffix ( shift , bpos , pat , m )
	preprocess_case2 ( shift , bpos , pat , m )
	while s <= n - m :
		j = m - 1
		while j >= 0 and pat [ j ] == text [ s + j ] :
			j -= 1
		if j < 0 :
			print ( " pattern ▁ occurs ▁ at ▁ shift ▁ = ▁ % d " % s )
			s += shift [ 0 ]
		else :
			s += shift [ j + 1 ]
if __name__ == " _ _ main _ _ " :
	text = " ABAAAABAACD "
	pat = " ABA "
	search ( text , pat )