human
Next higher number with same number of set bits | This function returns next higher number with same number of set bits as x ..
right most set bit.
reset the pattern and set next higher bit left part of x will be here.
nextHigherOneBit is now part [ D ] of the above explanation . isolate the pattern.
right adjust pattern.
correction factor.
rightOnesPattern is now part [ A ] of the above explanation . integrate new pattern ( Add [ D ] and [ A ] ).
Driver Code"
How can the above be solved in Python?

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Can you provide a code to next higher number with same number of set bits and the other steps required?
assistant
#Here is code to next higher number with same number of set bits and the other steps required.
 def snoob ( x ) :
	next = 0
	if ( x ) :
		rightOne = x & - ( x )
		nextHigherOneBit = x + int ( rightOne )
		rightOnesPattern = x ^ int ( nextHigherOneBit )
		rightOnesPattern = ( int ( rightOnesPattern ) / int ( rightOne ) )
		rightOnesPattern = int ( rightOnesPattern ) >> 2
		next = nextHigherOneBit | rightOnesPattern
	return next
x = 156
print ( " Next ▁ higher ▁ number ▁ with ▁ " + " same ▁ number ▁ of ▁ set ▁ bits ▁ is " , snoob ( x ) )