human
Count removal of pairs required to be empty all Balanced Parenthesis subsequences | Function to find the maximum count of pairs required to be removed such that subsequence of string does not contain any valid parenthesis.
Stores count of pairs of balanced parenthesis.
Stores count of curly balanced parenthesis.
Stores count of small balanced parenthesis.
Stores count of square balanced parenthesis.
Iterate over characters of the string.
Update cntCurly.
Update cntSml.
Update cntSqr.
Update cntCurly.
Update cntPairs.
Update cntSml.
Update cntPairs.
Update cntSml.
Update cntPairs.
Driver Code.
Given String.
Function call"
Solution in Python:
 Write me a code to count removal of pairs required to be empty all Balanced Parenthesis subsequences and the other steps required?
assistant
#Here is code to count removal of pairs required to be empty all Balanced Parenthesis subsequences and the other steps required.
 def cntBalancedParenthesis ( s , N ) :
	cntPairs = 0 ;
	cntCurly = 0 ;
	cntSml = 0 ;
	cntSqr = 0 ;
	for i in range ( N ) :
		if ( ord ( s [ i ] ) == ord ( ' { ' ) ) :
			cntCurly += 1 ;
		elif ( ord ( s [ i ] ) == ord ( ' ( ' ) ) :
			cntSml += 1 ;
		elif ( ord ( s [ i ] ) == ord ( ' [ ' ) ) :
			cntSqr += 1 ;
		elif ( ord ( s [ i ] ) == ord ( ' } ' ) and cntCurly > 0 ) :
			cntCurly -= 1 ;
			cntPairs += 1 ;
		elif ( ord ( s [ i ] ) == ord ( ' ) ' ) and cntSml > 0 ) :
			cntSml -= 1 ;
			cntPairs += 1 ;
		elif ( ord ( s [ i ] ) == ord ( ' ] ' ) and cntSqr > 0 ) :
			cntSqr -= 1 ;
			cntPairs += 1 ;
	print ( cntPairs ) ;
if __name__ == ' _ _ main _ _ ' :
	s = " { ( } ) " ;
	N = len ( s ) ;
	cntBalancedParenthesis ( s , N ) ;