human
Count possible ways to construct buildings | Returns count of possible ways for N sections.
Base case.
2 for one side and 4 for two sides.
countB is count of ways with a building at the end countS is count of ways with a space at the end prev_countB and prev_countS are previous values of countB and countS respectively . Initialize countB and countS for one side.
Use the above recursive formula for calculating countB and countS using previous values.
Result for one side is sum of ways ending with building and ending with space.
Result for 2 sides is square of result for one side.
Driver program"
How can the above be solved in Python?

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Write me a code to count possible ways to construct buildings and the other steps required?
assistant
#Here is code to count possible ways to construct buildings and the other steps required.
 def countWays ( N ) :
	if ( N == 1 ) :
		return 4
	countB = 1
	countS = 1
	for i in range ( 2 , N + 1 ) :
		prev_countB = countB
		prev_countS = countS
		countS = prev_countB + prev_countS
		countB = prev_countS
	result = countS + countB
	return ( result * result )
if __name__ == " _ _ main _ _ " :
	N = 3
	print ( " Count ▁ of ▁ ways ▁ for ▁ " , N , " ▁ sections ▁ is ▁ " , countWays ( N ) )