human
Count elements of same value placed at same indices of two given arrays | Function to count maximum matched elements from the arrays A [ ] and B [ ].
Stores position of elements of array A [ ] in the array B [ ].
Keep track of difference between the indices.
Traverse the array A [ ].
Traverse the array B [ ].
If difference is negative , add N to it.
Keep track of the number of shifts required to place elements at same indices.
Return the max matches.
Driver Code.
Returns the count of matched elements"
Solution in Python:

=====
Can you provide a code to count elements of same value placed at same indices of two given arrays and the other steps required?
assistant
#Here is code to count elements of same value placed at same indices of two given arrays and the other steps required.
 def maxMatch ( A , B ) :
	Aindex = { }
	diff = { }
	for i in range ( len ( A ) ) :
		Aindex [ A [ i ] ] = i
	for i in range ( len ( B ) ) :
		if i - Aindex [ B [ i ] ] < 0 :
			if len ( A ) + i - Aindex [ B [ i ] ] not in diff :
				diff [ len ( A ) + i - Aindex [ B [ i ] ] ] = 1
			else :
				diff [ len ( A ) + i - Aindex [ B [ i ] ] ] += 1
		else :
			if i - Aindex [ B [ i ] ] not in diff :
				diff [ i - Aindex [ B [ i ] ] ] = 1
			else :
				diff [ i - Aindex [ B [ i ] ] ] += 1
	return max ( diff . values ( ) )
A = [ 5 , 3 , 7 , 9 , 8 ]
B = [ 8 , 7 , 3 , 5 , 9 ]
print ( maxMatch ( A , B ) )