human
Write me a code to maximum number of groups that can receive fresh donuts distributed in batches of size K and the other steps required given the following:
Maximum number of groups that can receive fresh donuts distributed in batches of size K | Recursive function to find the maximum number of groups that will receive fresh donuts.
Store the result for the current state.
Check if the leftover donuts from the previous batch is 0.
If true , then one by one give the fresh donuts to each group.
Decrement arr [ i ].
Update the maximum number of groups.
Increment arr [ i ].
Otherwise , traverse the given array , arr [ ].
Decrement arr [ i ].
Update the maximum number of groups.
Increment arr [ i ].
Return the value of q.
Function to find the maximum number of groups that will receive fresh donuts.
Stores count of remainder by K.
Traverse the array arr [ ].
Stores maximum number of groups.
Return the answer.
Driver Code"
Solution in Python:
assistant
#Here is code to maximum number of groups that can receive fresh donuts distributed in batches of size K and the other steps required.
 def dfs ( arr , left , K ) :
	q = 0
	if ( left == 0 ) :
		for i in range ( 1 , K , 1 ) :
			if ( arr [ i ] > 0 ) :
				arr [ i ] -= 1
				q = max ( q , 1 + dfs ( arr , K - i , K ) )
				arr [ i ] += 1
	else :
		for i in range ( 1 , K , 1 ) :
			if ( arr [ i ] > 0 ) :
				arr [ i ] -= 1
				nleft = left - i if i <= left else K + left - i
				q = max ( q , dfs ( arr , nleft , K ) )
				arr [ i ] += 1
	return q
def maxGroups ( K , arr , n ) :
	V = [ 0 for i in range ( K ) ]
	for x in range ( n ) :
		V [ arr [ x ] % K ] += 1
	ans = V [ 0 ] + dfs ( V , 0 , K )
	return ans
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 3 , 4 , 5 , 6 ]
	n = len ( arr )
	K = 3
	print ( maxGroups ( K , arr , n ) )