human
I found an interesting problem on https://leetcode.com/problems/decrease-elements-to-make-array-zigzag/:
Given an array nums of integers, a move consists of choosing any element and decreasing it by 1.
An array A is a zigzag array if either:

Every even-indexed element is greater than adjacent elements, ie. A[0] > A[1] < A[2] > A[3] < A[4] > ...
OR, every odd-indexed element is greater than adjacent elements, ie. A[0] < A[1] > A[2] < A[3] > A[4] < ...

Return the minimum number of moves to transform the given array nums into a zigzag array.
 
Example 1:
Input: nums = [1,2,3]
Output: 2
Explanation: We can decrease 2 to 0 or 3 to 1.

Example 2:
Input: nums = [9,6,1,6,2]
Output: 4

 
Constraints:

1 <= nums.length <= 1000
1 <= nums[i] <= 1000

I tried it in Python, but could not do it. Can you solve it?

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What is a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def movesToMakeZigzag(self, nums: List[int]) -> int:
        if len(nums) <= 2:
            return 0
        n = len(nums)
        if n%2 == 0:
            step1 = max(0,nums[-1]-nums[-2]+1)
            for i in range(1,n-1,2):
                step1 += max(0, nums[i] - min(nums[i-1], nums[i+1])+1)
            step2 = max(0, nums[0]-nums[1] +1)
            for i in range(2,n,2):
                step2 += max(0, nums[i] - min(nums[i-1], nums[i+1])+1)
        else:
            step1 = max(0,nums[-1]-nums[-2]+1) + max(0, nums[0]-nums[1] +1)
            for i in range(2,n-1,2):
                step1 += max(0, nums[i] - min(nums[i-1], nums[i+1])+1)
            step2 = 0
            for i in range(1,n,2):
                step2 += max(0, nums[i] - min(nums[i-1], nums[i+1])+1)
        return min(step1, step2)