human
Complete the below
def get_file_path_validator(default_file_param=None):

    ''''Creates a namespace validator that splits out \'path\' into \'directory_name\' and \'file_name\'.
    Allows another path-type parameter to be named which can supply a default filename.'
    '''

Give me a the Python program you requested?
assistant
#Here is the Python program you requested.
    def validator(namespace):
        if (not hasattr(namespace, 'path')):
            return
        path = namespace.path
        (dir_name, file_name) = (os.path.split(path) if path else (None, ''))
        if (default_file_param and ('.' not in file_name)):
            dir_name = path
            file_name = os.path.split(getattr(namespace, default_file_param))[1]
        namespace.directory_name = dir_name
        namespace.file_name = file_name
        del namespace.path
    return validator