human
Write a function to check if the given number is woodball or not. Here is a solution in Python:
assistant
#Here is the Python code you requested.
 def is_woodall(x): 
	if (x % 2 == 0): 
		return False
	if (x == 1): 
		return True
	x = x + 1 
	p = 0
	while (x % 2 == 0): 
		x = x/2
		p = p + 1
		if (p == x): 
			return True
	return False