human
n | Python3 code to find nth number with digits 0 , 1 , 2 , 3 , 4 , 5.
If the Number is less than 6 return the number as it is ..
Call the function again and again the get the desired result . And convert the number to base 6..
Decrease the Number by 1 and Call ans function to convert N to base 6.
Driver code"
How can the above be solved in Python?

Can you provide a code to n and the other steps required?
assistant
#Here is code to n and the other steps required.
 def ans ( n ) :
	if ( n < 6 ) :
		return n
	return n % 6 + 10 * ( ans ( n // 6 ) ) - 1
def getSpecialNumber ( N ) :
	return ans ( N )
if __name__ == ' _ _ main _ _ ' :
	N = 17
	answer = getSpecialNumber ( N )
	print ( answer )