human
Count elements of same value placed at same indices of two given arrays | Function to count maximum matched elements from the arrays A [ ] and B [ ].
Stores position of elements of array A [ ] in the array B [ ].
Keep track of difference between the indices.
Traverse the array A [ ].
Traverse the array B [ ].
If difference is negative , add N to it.
Keep track of the number of shifts required to place elements at same indices.
Return the max matches.
Driver Code.
Returns the count of matched elements"
How can the above be solved in Python?

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Give me a code to count elements of same value placed at same indices of two given arrays and the other steps required?
assistant
#Here is code to count elements of same value placed at same indices of two given arrays and the other steps required.
 def maxMatch ( A , B ) :
	Aindex = { }
	diff = { }
	for i in range ( len ( A ) ) :
		Aindex [ A [ i ] ] = i
	for i in range ( len ( B ) ) :
		if i - Aindex [ B [ i ] ] < 0 :
			if len ( A ) + i - Aindex [ B [ i ] ] not in diff :
				diff [ len ( A ) + i - Aindex [ B [ i ] ] ] = 1
			else :
				diff [ len ( A ) + i - Aindex [ B [ i ] ] ] += 1
		else :
			if i - Aindex [ B [ i ] ] not in diff :
				diff [ i - Aindex [ B [ i ] ] ] = 1
			else :
				diff [ i - Aindex [ B [ i ] ] ] += 1
	return max ( diff . values ( ) )
A = [ 5 , 3 , 7 , 9 , 8 ]
B = [ 8 , 7 , 3 , 5 , 9 ]
print ( maxMatch ( A , B ) )