human
Maximum of minimum difference of all pairs from subsequences of given size | Function to check a subsequence can be formed with min difference mid.
If a subsequence of size B with min diff = mid is possible return true else false.
Function to find the maximum of all minimum difference of pairs possible among the subsequence.
Sort the Array.
Stores the boundaries of the search space.
Store the answer.
Binary Search.
If subsequence can be formed with min diff mid and size B.
Right half.
Left half.
Driver code"
Solution in Python:
 ... Write me a code to maximum of minimum difference of all pairs from subsequences of given size and the other steps required?
assistant
#Here is code to maximum of minimum difference of all pairs from subsequences of given size and the other steps required.
 def can_place ( A , n , B , mid ) :
	count = 1
	last_position = A [ 0 ]
	for i in range ( 1 , n ) :
		if ( A [ i ] - last_position >= mid ) :
			last_position = A [ i ]
			count = count + 1
			if ( count == B ) :
				return bool ( True )
	return bool ( False )
def find_min_difference ( A , n , B ) :
	A . sort ( )
	s = 0
	e = A [ n - 1 ] - A [ 0 ]
	ans = 0
	while ( s <= e ) :
		mid = ( int ) ( ( s + e ) / 2 )
		if ( can_place ( A , n , B , mid ) ) :
			ans = mid
			s = mid + 1
		else :
			e = mid - 1
	return ans
A = [ 1 , 2 , 3 , 5 ]
n = len ( A )
B = 3
min_difference = find_min_difference ( A , n , B )
print ( min_difference )