human
Find even occurring elements in an array of limited range | Function to find the even occurring elements in given array.
do for each element of array.
left - shift 1 by value of current element.
Toggle the bit every time element gets repeated.
Traverse array again and use _xor to find even occurring elements.
left - shift 1 by value of current element.
Each 0 in _xor represents an even occurrence.
print the even occurring numbers.
set bit as 1 to avoid printing duplicates.
Driver code"
How can the above be solved in Python?

Can you provide a code to find even occurring elements in an array of limited range and the other steps required?
assistant
#Here is code to find even occurring elements in an array of limited range and the other steps required.
 def printRepeatingEven ( arr , n ) :
	axor = 0 ;
	for i in range ( 0 , n ) :
		pos = 1 << arr [ i ] ;
		axor ^= pos ;
	for i in range ( 0 , n - 1 ) :
		pos = 1 << arr [ i ] ;
		if ( not ( pos & axor ) ) :
			print ( arr [ i ] , end = " ▁ " ) ;
			axor ^= pos ;
arr = [ 9 , 12 , 23 , 10 , 12 , 12 , 15 , 23 , 14 , 12 , 15 ] ;
n = len ( arr ) ;
printRepeatingEven ( arr , n ) ;