human
Count of squares that can be drawn without lifting the pencil | Function to return the count of squares that can be formed.
Driver code"
How can the above be solved in Python?
 Can you provide a code to count of squares that can be drawn without lifting the pencil and the other steps required?
assistant
#Here is code to count of squares that can be drawn without lifting the pencil and the other steps required.
 def countSquares ( n ) :
	return ( pow ( n , 2 ) - ( 2 * n ) + 2 ) ;
if __name__ == " _ _ main _ _ " :
	n = 2 ;
	print ( countSquares ( n ) ) ;