human
N | Return the n - th number in the sorted list of multiples of two numbers ..
Generating first n multiple of a ..
Sorting the sequence ..
Generating and storing first n multiple of b and storing if not present in the sequence ..
If not present in the sequence.
Storing in the sequence ..
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to n and the other steps required.
 def nthElement ( a , b , n ) :
	seq = [ ] ;
	for i in range ( 1 , n + 1 ) :
		seq . append ( a * i ) ;
	seq . sort ( ) ;
	i = 1 ;
	k = n ;
	while ( i <= n and k > 0 ) :
		try :
			z = seq . index ( b * i ) ;
		except ValueError :
			seq . append ( b * i ) ;
			seq . sort ( ) ;
			k -= 1 ;
		i += 1 ;
	return seq [ n - 1 ] ;
a = 3 ;
b = 5 ;
n = 5 ;
print ( nthElement ( a , b , n ) ) ;