human
Search for an element in a Mountain Array | Function to find the index of the peak element in the array.
Stores left most index in which the peak element can be found.
Stores right most index in which the peak element can be found.
Stores mid of left and right.
If element at mid is less than element at ( mid + 1 ).
Update left.
Update right.
Function to perform binary search in an a subarray if elements of the subarray are in an ascending order.
Stores mid of left and right.
If X found at mid.
If X is greater than mid.
Update left.
Update right.
Function to perform binary search in an a subarray if elements of the subarray are in an ascending order.
Stores mid of left and right.
If X found at mid.
Update right.
Update left.
Function to find the smallest index of X.
Stores index of peak element in array.
Stores index of X in the array.
If X greater than or equal to first element of array and less than the peak element.
Update res.
If element not found on left side of peak element.
Update res.
Print res.
Driver Code.
Given X.
Given array.
Function Call"
Solution in Python:

Give me a code to search for an element in a Mountain Array and the other steps required?
assistant
#Here is code to search for an element in a Mountain Array and the other steps required.
 def findPeak ( arr ) :
	left = 0
	right = len ( arr ) - 1
	while ( left < right ) :
		mid = left + ( right - left ) // 2
		if ( arr [ mid ] < arr [ ( mid + 1 ) ] ) :
			left = mid + 1
		else :
			right = mid
	return left
def BS ( X , left , right , arr ) :
	while ( left <= right ) :
		mid = left + ( right - left ) // 2
		if ( arr [ mid ] == X ) :
			return mid
		elif ( X > arr [ mid ] ) :
			left = mid + 1
		else :
			right = mid - 1
	return - 1
def reverseBS ( X , left , right , arr ) :
	while ( left <= right ) :
		mid = left + ( right - left ) // 2
		if ( arr [ mid ] == X ) :
			return mid
		elif ( X > arr [ mid ] ) :
			right = mid - 1
		else :
			left = mid + 1
	return - 1
def findInMA ( X , mountainArr ) :
	peakIndex = findPeak ( mountainArr )
	res = - 1
	if ( X >= mountainArr [ 0 ] and X <= mountainArr [ peakIndex ] ) :
		res = BS ( X , 0 , peakIndex , mountainArr )
	if ( res == - 1 ) :
		res = reverseBS ( X , peakIndex + 1 , mountainArr . size ( ) - 1 , mountainArr )
	print ( res )
if __name__ == " _ _ main _ _ " :
	X = 3
	arr = [ 1 , 2 , 3 , 4 , 5 , 3 , 1 ]
	findInMA ( X , arr )