human
Steps to reduce N to zero by subtracting its most significant digit at every step | Function to count the number of digits in a number m.
Function to count the number of steps to reach 0.
count the total number of stesp.
iterate till we reach 0.
count the digits in last.
decrease it by 1.
find the number on whose division , we get the first digit.
first digit in last.
find the first number less than last where the first digit changes.
find the number of numbers with same first digit that are jumped.
count the steps.
the next number with a different first digit.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to steps to reduce N to zero by subtracting its most significant digit at every step and the other steps required.
 def countdig ( m ) :
	if ( m == 0 ) :
		return 0
	else :
		return 1 + countdig ( m // 10 )
def countSteps ( x ) :
	c = 0
	last = x
	while ( last ) :
		digits = countdig ( last )
		digits -= 1
		divisor = pow ( 10 , digits )
		first = last // divisor
		lastnumber = first * divisor
		skipped = ( last - lastnumber ) // first
		skipped += 1
		c += skipped
		last = last - ( first * skipped )
	return c
n = 14
print ( countSteps ( n ) )