human
Minimize increments required to make count of even and odd array elements equal | Function to find min operations to make even and odd count equal.
Odd size will never make odd and even counts equal.
Stores the count of even numbers in the array arr [ ].
Stores count of odd numbers in the array arr [ ].
Traverse the array arr [ ].
If arr [ i ] is an even number.
Update cntEven.
Odd numbers in arr [ ].
Return absolute difference divided by 2.
Driver Code.
Function call"
Solution in Python:
assistant
#Here is code to minimize increments required to make count of even and odd array elements equal and the other steps required.
 def minimumIncrement ( arr , N ) :
	if ( N % 2 != 0 ) :
		print ( " - 1" )
		return
	cntEven = 0
	cntOdd = 0
	for i in range ( N ) :
		if ( arr [ i ] % 2 == 0 ) :
			cntEven += 1
	cntOdd = N - cntEven
	return abs ( cntEven - cntOdd ) // 2
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 3 , 4 , 9 ]
	N = len ( arr )
	print ( minimumIncrement ( arr , N ) )