human
Rearrange array to make Bitwise XOR of similar indexed elements of two arrays is same | Function to rearrange the array B [ ] such that A [ i ] ^ B [ i ] is same for each element.
Store frequency of elements.
Stores xor value.
Taking xor of all the values of both arrays.
Store frequency of B [ ].
Find the array B [ ] after rearrangement.
If the updated value is present then decrement its frequency.
Otherwise return empty vector.
Utility function to rearrange the array B [ ] such that A [ i ] ^ B [ i ] is same for each element.
Store rearranged array B.
If rearrangement possible.
Otherwise return - 1.
Driver Code.
Given vector A.
Given vector B.
Size of the vector.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to rearrange array to make Bitwise XOR of similar indexed elements of two arrays is same and the other steps required.
 def rearrangeArray ( A , B , N ) :
	m = { }
	xor_value = 0
	for i in range ( 0 , N ) :
		xor_value ^= A [ i ]
		xor_value ^= B [ i ]
		if B [ i ] in m :
		m [ B [ i ] ] = m [ B [ i ] ] + 1
		else :
		m [ B [ i ] ] = 1
	for i in range ( 0 , N ) :
		B [ i ] = A [ i ] ^ xor_value
		if B [ i ] in m :
		m [ B [ i ] ] = m [ B [ i ] ] - 1
		else :
		X = [ ]
		return X
	return B
def rearrangeArrayUtil ( A , B , N ) :
	ans = rearrangeArray ( A , B , N )
	if ( len ( ans ) > 0 ) :
		for x in ans :
			print ( x , end = ' ▁ ' )
	else :
		print ( " - 1" )
if __name__ == ' _ _ main _ _ ' :
	A = [ 13 , 21 , 33 , 49 , 53 ]
	B = [ 54 , 50 , 34 , 22 , 14 ]
	N = len ( A )
	rearrangeArrayUtil ( A , B , N )