human
Give me a code to number of occurrences of 2 as a digit in numbers from 0 to n and the other steps required given the following:
Number of occurrences of 2 as a digit in numbers from 0 to n | Counts the number of 2 s in a number at d - th digit.
if the digit in spot digit is.
Counts the number of '2' digits between 0 and n.
Convert integer to String to find its length.
Traverse every digit and count for every digit.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to number of occurrences of 2 as a digit in numbers from 0 to n and the other steps required.
 def count2sinRangeAtDigit ( number , d ) :
	powerOf10 = int ( pow ( 10 , d ) ) ;
	nextPowerOf10 = powerOf10 * 10 ;
	right = number % powerOf10 ;
	roundDown = number - number % nextPowerOf10 ;
	roundup = roundDown + nextPowerOf10 ;
	digit = ( number // powerOf10 ) % 10 ;
	if ( digit < 2 ) :
		return roundDown // 10 ;
	if ( digit == 2 ) :
		return roundDown // 10 + right + 1 ;
	return roundup // 10 ;
def numberOf2sinRange ( number ) :
	s = str ( number ) ;
	len1 = len ( s ) ;
	count = 0 ;
	for digit in range ( len1 ) :
		count += count2sinRangeAtDigit ( number , digit ) ;
	return count ;
print ( numberOf2sinRange ( 22 ) ) ;
print ( numberOf2sinRange ( 100 ) ) ;