human
Can you provide a code to number of non and the other steps required given the following:
Number of non | Function to return the count of increasing subarrays of length k.
To store the final result.
Two pointer loop.
Initialising j.
Looping till the subarray increases.
Updating the required count.
Updating i.
Returning res.
Driver code"
Solution in Python:
assistant
#Here is code to number of non and the other steps required.
 def cntSubArrays ( arr , n , k ) :
	res = 0 ;
	i = 0 ;
	while ( i < n ) :
		j = i + 1 ;
		while ( j < n and arr [ j ] >= arr [ j - 1 ] ) :
			j += 1 ;
		res += max ( j - i - k + 1 , 0 ) ;
		i = j ;
	return res ;
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 , 2 , 5 ] ;
	n = len ( arr ) ;
	k = 2 ;
	print ( cntSubArrays ( arr , n , k ) ) ;