human
Sort the given stack elements based on their modulo with K | Function to sort the stack using another stack based on the values of elements modulo k.
Pop out the first element.
While temporary stack is not empty.
The top of the stack modulo k is greater than ( temp & k ) or if they are equal then compare the values.
Pop from temporary stack and push it to the input stack.
Push temp in temporary of stack.
Push all the elements in the original stack to get the ascending order.
Print the sorted elements.
Driver code"
Solution in Python:

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Can you provide a code to sort the given stack elements based on their modulo with K and the other steps required?
assistant
#Here is code to sort the given stack elements based on their modulo with K and the other steps required.
 def sortStack ( input1 , k ) :
	tmpStack = [ ]
	while ( len ( input1 ) != 0 ) :
		tmp = input1 [ - 1 ]
		input1 . pop ( )
		while ( len ( tmpStack ) != 0 ) :
			tmpStackMod = tmpStack [ - 1 ] % k
			tmpMod = tmp % k
			if ( ( tmpStackMod > tmpMod ) or ( tmpStackMod == tmpMod and tmpStack [ - 1 ] > tmp ) ) :
				input1 . append ( tmpStack [ - 1 ] )
				tmpStack . pop ( )
			else :
				break
		tmpStack . append ( tmp )
	while ( len ( tmpStack ) != 0 ) :
		input1 . append ( tmpStack [ - 1 ] )
		tmpStack . pop ( )
	while ( len ( input1 ) != 0 ) :
		print ( input1 [ - 1 ] , end = " ▁ " )
		input1 . pop ( )
if __name__ == " _ _ main _ _ " :
	input1 = [ ]
	input1 . append ( 10 )
	input1 . append ( 3 )
	input1 . append ( 2 )
	input1 . append ( 6 )
	input1 . append ( 12 )
	k = 4
	sortStack ( input1 , k )