human
Give me a code to maximum elements that can be removed from front of two arrays such that their sum is at most K and the other steps required given the following:
Maximum elements that can be removed from front of two arrays such that their sum is at most K | Function to find the maximum number of items that can be removed from both the arrays.
Stores the maximum item count.
Stores the prefix sum of the cost of items.
Build the prefix sum for the array A [ ].
Update the value of A [ i ].
Build the prefix sum for the array B [ ].
Update the value of B [ i ].
Iterate through each item of the array A [ ].
If A [ i ] exceeds K.
Store the remaining amount after taking top i elements from the array A.
Store the number of items possible to take from the array B [ ].
Store low and high bounds for binary search.
Binary search to find number of item that can be taken from stack B in rem amount.
Calculate the mid value.
Update the value of j and lo.
Update the value of the hi.
Store the maximum of total item count.
Print the result.
Driver Code"
Solution in Python:
assistant
#Here is code to maximum elements that can be removed from front of two arrays such that their sum is at most K and the other steps required.
 def maxItems ( n , m , a , b , K ) :
	count = 0
	A = [ 0 for i in range ( n + 1 ) ]
	B = [ 0 for i in range ( m + 1 ) ]
	for i in range ( 1 , n + 1 , 1 ) :
		A [ i ] = a [ i - 1 ] + A [ i - 1 ]
	for i in range ( 1 , m + 1 , 1 ) :
		B [ i ] = b [ i - 1 ] + B [ i - 1 ]
	for i in range ( n + 1 ) :
		if ( A [ i ] > K ) :
			break
		rem = K - A [ i ]
		j = 0
		lo = 0
		hi = m
		while ( lo <= hi ) :
			mid = ( lo + hi ) // 2
			if ( B [ mid ] <= rem ) :
				j = mid
				lo = mid + 1
			else :
				hi = mid - 1
		count = max ( j + i , count )
	print ( count )
if __name__ == ' _ _ main _ _ ' :
	n = 4
	m = 5
	K = 7
	A = [ 2 , 4 , 7 , 3 ]
	B = [ 1 , 9 , 3 , 4 , 5 ]
	maxItems ( n , m , A , B , K )