human
Find the n | function to calculate nth number made of even digits only.
variable to note how many such numbers have been found till now.
bool variable to check if 1 , 3 , 5 , 7 , 9 is there or not.
checking each digit of the number.
If 1 , 3 , 5 , 7 , 9 is found temp is changed to false.
temp is true it means that it does not have 1 , 3 , 5 , 7 , 9.
If nth such number is found , return it.
Driver Code"
Solution in Python:

Can you provide a code to find the n and the other steps required?
assistant
#Here is code to find the n and the other steps required.
 def findNthEvenDigitNumber ( n ) :
	count = 0 ;
	i = 0 ;
	while ( True ) :
		curr = i ;
		isCurrEvenDigit = True ;
		while ( curr != 0 ) :
			if ( curr % 10 == 1 or curr % 10 == 3 or curr % 10 == 5 or curr % 10 == 7 or curr % 10 == 9 ) :
				isCurrEvenDigit = False ;
			curr = curr // 10 ;
		if ( isCurrEvenDigit == True ) :
			count += 1 ;
		if ( count == n ) :
			return i ;
		i += 1 ;
print ( findNthEvenDigitNumber ( 2 ) ) ;
print ( findNthEvenDigitNumber ( 10 ) ) ;