human
Breaking a number such that first part is integral division of second by a power of 10 | Python3 program to count ways to divide a string in two parts a and b such that b / pow ( 10 , p ) == a.
substring representing int a.
no of digits in a.
consider only most significant l1 characters of remaining string for int b.
if any of a or b contains leading 0 s discard this.
if both are equal.
driver code to test above function"
Solution in Python:
 ... Can you provide a code to breaking a number such that first part is integral division of second by a power of 10 and the other steps required?
assistant
#Here is code to breaking a number such that first part is integral division of second by a power of 10 and the other steps required.
 def calculate ( N ) :
	length = len ( N )
	l = int ( ( length ) / 2 )
	count = 0
	for i in range ( l + 1 ) :
		s = N [ 0 : 0 + i ]
		l1 = len ( s )
		t = N [ i : l1 + i ]
		try :
			if s [ 0 ] == '0' or t [ 0 ] == '0' :
				continue
		except :
			continue
		if s == t :
			count += 1
	return count
N = str ( "2202200" )
print ( calculate ( N ) )