human
Partition the digits of an integer such that it satisfies a given condition | Function to generate sequence from the given string.
Initialize vector to store sequence.
First add all the digits of group A from left to right.
Then add all the digits of group B from left to right.
Return the sequence.
Function that returns true if the sequence is non - decreasing.
Initialize result.
Function to partition the digits of an integer such that it satisfies the given conditions.
Convert the integer to string.
Length of the string.
Array to store the digits.
Storing the digits of X in array.
Initialize the result.
Loop through the digits.
Put into group A if digit less than D.
Put into group B if digit greater than D.
Put into group C if digit equal to D.
Loop through the digits to decide for group C digits.
Set flag equal to true if group B digit present.
If flag is true put in group A or else put in B.
Generate the sequence from partition.
Check if the sequence is non decreasing.
Return - 1 if no such partition is possible.
Driver code"
Solution in Python:

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Write me a code to partition the digits of an integer such that it satisfies a given condition and the other steps required?
assistant
#Here is code to partition the digits of an integer such that it satisfies a given condition and the other steps required.
 def makeSeq ( s , a ) :
	seq = [ ] ;
	for i in range ( len ( s ) ) :
		if ( s [ i ] == ' A ' ) :
			seq . append ( a [ i ] ) ;
	for i in range ( len ( s ) ) :
		if ( s [ i ] == ' B ' ) :
			seq . append ( a [ i ] ) ;
	return seq ;
def checkSeq ( v ) :
	check = True ;
	for i in range ( 1 , len ( v ) ) :
		if ( v [ i ] < v [ i - 1 ] ) :
			check = False ;
	return check ;
def digitPartition ( X ) :
	num = str ( X ) ;
	l = len ( num ) ;
	a = [ 0 ] * l ;
	for i in range ( l ) :
		a [ i ] = ( ord ( num [ i ] ) - ord ( '0' ) ) ;
	for D in range ( 10 ) :
		res = " " ;
		for i in range ( l ) :
			if ( a [ i ] < D ) :
				res += ' A ' ;
			elif ( a [ i ] > D ) :
				res += ' B ' ;
			else :
				res += ' C ' ;
		flag = False ;
		for i in range ( l ) :
			if ( res [ i ] == ' B ' ) :
				flag = True ;
			res = list ( res ) ;
			if ( res [ i ] == ' C ' ) :
				res [ i ] = ' A ' if flag else ' B ' ;
		seq = makeSeq ( res , a ) ;
		if ( checkSeq ( seq ) ) :
			return " " . join ( res ) ;
	return " - 1" ;
if __name__ == " _ _ main _ _ " :
	X = 777147777 ;
	print ( digitPartition ( X ) ) ;