human
Write me a code to absolute difference between the count of odd and even factors of N and the other steps required given the following:
Absolute difference between the count of odd and even factors of N | Function to find the smallest prime factor of all the numbers using Sieve Of Eratosthenes.
Stores whether any number is prime or not.
Initialize smallest factor as 2 for all the even numbers.
Iterate over the range [ 3 , N ].
If i is prime.
Iterate all multiples of i.
i is the smallest prime factor of i * j.
Function to find the absolute difference between the count of odd and even factors of N.
Stores the smallest prime factor of i.
Fill values in s [ ] using sieve of eratosthenes.
Stores the total number of factors and the total number of odd and even factors.
Store the current prime factor of the number N.
Store the power of current prime factor.
Loop while N is greater than 1.
If N also has smallest prime factor as curr , then increment cnt by 1.
Update only total number of factors if curr is 2.
Update total number of factors and total number of odd factors.
Update current prime factor as s [ N ] and count as 1.
Calculate the number of even factors.
Print the difference.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to absolute difference between the count of odd and even factors of N and the other steps required.
 def sieveOfEratosthenes ( N , s ) :
	prime = [ False ] * ( N + 1 )
	for i in range ( 2 , N + 1 , 2 ) :
		s [ i ] = 2
	for i in range ( 3 , N , 2 ) :
		if ( prime [ i ] == False ) :
			s [ i ] = i
			for j in range ( i , N , 2 ) :
				if j * i > N :
					break
				if ( not prime [ i * j ] ) :
					prime [ i * j ] = True
					s [ i * j ] = i
def findDifference ( N ) :
	s = [ 0 ] * ( N + 1 )
	sieveOfEratosthenes ( N , s )
	total , odd , even = 1 , 1 , 0
	curr = s [ N ]
	cnt = 1
	while ( N > 1 ) :
		N //= s [ N ]
		if ( curr == s [ N ] ) :
			cnt += 1
			continue
		if ( curr == 2 ) :
			total = total * ( cnt + 1 )
		else :
			total = total * ( cnt + 1 )
			odd = odd * ( cnt + 1 )
		curr = s [ N ]
		cnt = 1
	even = total - odd
	print ( abs ( even - odd ) )
if __name__ == ' _ _ main _ _ ' :
	N = 12
	findDifference ( N )