human
Count of N | Function to calculate and return the reverse of the number.
Function to calculate the total count of N - digit numbers satisfying the necessary conditions.
Initialize two variables.
Calculate the sum of odd and even positions.
Check for divisibility.
Return the answer.
Driver Code"
Solution in Python:
 Give me a code to count of N and the other steps required?
assistant
#Here is code to count of N and the other steps required.
 def reverse ( num ) :
	rev = 0 ;
	while ( num > 0 ) :
		r = int ( num % 10 ) ;
		rev = rev * 10 + r ;
		num = num // 10 ;
	return rev ;
def count ( N , A , B ) :
	l = int ( pow ( 10 , N - 1 ) ) ;
	r = int ( pow ( 10 , N ) - 1 ) ;
	if ( l == 1 ) :
		l = 0 ;
	ans = 0 ;
	for i in range ( l , r + 1 ) :
		even_sum = 0 ;
		odd_sum = 0 ;
		itr = 0 ;
		num = reverse ( i ) ;
		while ( num > 0 ) :
			if ( itr % 2 == 0 ) :
				odd_sum += num % 10 ;
			else :
				even_sum += num % 10 ;
			num = num // 10 ;
			itr += 1 ;
		if ( even_sum % A == 0 and odd_sum % B == 0 ) :
			ans += 1 ;
	return ans ;
if __name__ == ' _ _ main _ _ ' :
	N = 2 ;
	A = 5 ;
	B = 3 ;
	print ( count ( N , A , B ) ) ;