human
Number formed by deleting digits such that sum of the digits becomes even and the number odd | Function to convert a number into odd number such that digit - sum is odd.
Loop to find any first two odd number such that their sum is even and number is odd.
Print the result.
Driver Code"
Solution in Python:
assistant
#Here is code to number formed by deleting digits such that sum of the digits becomes even and the number odd and the other steps required.
 def converthenumber ( n ) :
	s = str ( n ) ;
	res = " " ;
	for i in range ( len ( s ) ) :
		if ( s [ i ] == '1' or s [ i ] == '3' or s [ i ] == '5' or s [ i ] == '7' or s [ i ] == '9' ) :
			res += s [ i ] ;
		if ( len ( res ) == 2 ) :
			break ;
	if ( len ( res ) == 2 ) :
		print ( res ) ;
	else :
		print ( " - 1" ) ;
if __name__ == " _ _ main _ _ " :
	n = 18720 ;
	converthenumber ( n ) ;