human
Smallest number greater than or equal to N using only digits 1 to K | Function to count the digits greater than K.
Function to print the list.
Function to find the number greater than or equal to n , which is only made of first k digits.
If the number itself satisfy the conditions.
Check digit from back.
If digit > K is present previously and current digit is less than K.
If current digit is greater than K.
If an extra digit needs to be added.
Print the number.
Driver Code"
Solution in Python:

Can you provide a code to smallest number greater than or equal to N using only digits 1 to K and the other steps required?
assistant
#Here is code to smallest number greater than or equal to N using only digits 1 to K and the other steps required.
 def CountGreater ( n , k ) :
	a = 0
	while ( n > 0 ) :
		if ( ( n % 10 ) > k ) :
			a += 1
		n = n // 10
	return a
def PrintList ( ans ) :
	for i in ans :
		print ( i , end = ' ' )
def getNumber ( n , k ) :
	count = CountGreater ( n , k )
	if ( count == 0 ) :
		print ( n )
		return
	ans = [ ]
	changed = False
	while ( n > 0 ) :
		digit = n % 10
		if ( changed == True ) :
			ans . insert ( 0 , digit )
		else :
			if ( count == 0 and digit < k ) :
				ans . insert ( 0 , digit + 1 )
				changed = True
			else :
				ans . insert ( 0 , 1 )
				if ( digit > k ) :
					count -= 1
		n = n // 10
	if ( changed == False ) :
		ans . insert ( 0 , 1 )
	PrintList ( ans )
	return
N = 51234
K = 4
getNumber ( N , K )