human
Count subarrays having sum of elements at even and odd positions equal | Function to count subarrays in which sum of elements at even and odd positions are equal.
Initialize variables.
Iterate over the array.
Check if position is even then add to sum hen add it to sum.
else subtract it to sum.
Increment the count if the sum equals 0.
Print the count of subarrays.
Driver Code.
Given array arr [ ].
Size of the array.
Function call"
How can the above be solved in Python?

Can you provide a code to count subarrays having sum of elements at even and odd positions equal and the other steps required?
assistant
#Here is code to count subarrays having sum of elements at even and odd positions equal and the other steps required.
 def countSubarrays ( arr , n ) :
	count = 0
	for i in range ( n ) :
		sum = 0
		for j in range ( i , n ) :
			if ( ( j - i ) % 2 == 0 ) :
				sum += arr [ j ]
			else :
				sum -= arr [ j ]
			if ( sum == 0 ) :
				count += 1
	print ( count )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 4 , 6 , 4 , 2 ]
	n = len ( arr )
	countSubarrays ( arr , n )