human
Count Distinct Subsequences | Returns count of distinct subsequences of str ..
Iterate from 0 to length of s.
Iterate from 0 to length of s.
Check if i equal to 0.
Replace levelCount withe allCount + 1.
If map is less than 0.
Return answer.
Driver Code"
How can the above be solved in Python?

Give me a code to count Distinct Subsequences and the other steps required?
assistant
#Here is code to count Distinct Subsequences and the other steps required.
 def countSub ( s ) :
	Map = { }
	for i in range ( len ( s ) ) :
		Map [ s [ i ] ] = - 1
	allCount = 0
	levelCount = 0
	for i in range ( len ( s ) ) :
		c = s [ i ]
		if ( i == 0 ) :
			allCount = 1
			Map = 1
			levelCount = 1
			continue
		levelCount = allCount + 1
		if ( Map < 0 ) :
			allCount = allCount + levelCount
		else :
			allCount = allCount + levelCount - Map
		Map = levelCount
	return allCount
List = [ " abab " , " gfg " ]
for s in List :
	cnt = countSub ( s )
	withEmptyString = cnt + 1
	print ( " With ▁ empty ▁ string ▁ count ▁ for " , s , " is " , withEmptyString )
	print ( " Without ▁ empty ▁ string ▁ count ▁ for " , s , " is " , cnt )