human
Find a triplet ( A , B , C ) such that 3 * A + 5 * B + 7 * C is equal to N | Function to find a triplet ( A , B , C ) such that 3 * A + 5 * B + 7 * C is N.
Iterate over the range [ 0 , N7 ].
Iterate over the range [ 0 , N5 ].
Find the value of A.
If A is greater than or equal to 0 and divisible by 3.
Otherwise , print - 1.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to find a triplet ( A , B , C ) such that 3 * A + 5 * B + 7 * C is equal to N and the other steps required.
 def CalculateValues ( N ) :
	for C in range ( 0 , N // 7 + 1 ) :
		for B in range ( 0 , N // 5 + 1 ) :
			A = N - 7 * C - 5 * B
			if ( A >= 0 and A % 3 == 0 ) :
				print ( " A ▁ = " , A / 3 , " , ▁ B ▁ = " , B , " , ▁ \ ▁ C ▁ = " , C , sep = " ▁ " )
				return
	print ( - 1 )
	return
if __name__ == ' _ _ main _ _ ' :
	N = 19
	CalculateValues ( 19 )