human
Longest Common Subsequence | DP using Memoization | Returns length of LCS for X [ 0. . m - 1 ] , Y [ 0. . n - 1 ].
Driver Code.
Find the length of string"
Solution in Python:

Can you provide a code to longest Common Subsequence and the other steps required?
assistant
#Here is code to longest Common Subsequence and the other steps required.
 def lcs ( X , Y , m , n ) :
	if ( m == 0 or n == 0 ) :
		return 0
	if ( X [ m - 1 ] == Y [ n - 1 ] ) :
		return 1 + lcs ( X , Y , m - 1 , n - 1 )
	else :
		return max ( lcs ( X , Y , m , n - 1 ) , lcs ( X , Y , m - 1 , n ) )
if __name__ == ' _ _ main _ _ ' :
	X = " AGGTAB "
	Y = " GXTXAYB "
	m = len ( X )
	n = len ( Y )
	print ( " Length ▁ of ▁ LCS : " , lcs ( X , Y , m , n ) )