human
I found an interesting problem on https://leetcode.com/problems/domino-and-tromino-tiling/:
We have two types of tiles: a 2x1 domino shape, and an "L" tromino shape. These shapes may be rotated.

XX  <- domino

XX  <- "L" tromino
X

Given N, how many ways are there to tile a 2 x N board? Return your answer modulo 10^9 + 7.

(In a tiling, every square must be covered by a tile. Two tilings are different if and only if there are two 4-directionally adjacent cells on the board such that exactly one of the tilings has both squares occupied by a tile.)


Example:
Input: 3
Output: 5
Explanation: 
The five different ways are listed below, different letters indicates different tiles:
XYZ XXZ XYY XXY XYY
XYZ YYZ XZZ XYY XXY

Note:

       N  will be in range [1, 1000].

I tried it in Python, but could not do it. Can you solve it?

 Write me a the Python code you requested?
assistant
#Here is the Python code you requested.

class Solution:
     def isIdealPermutation(self, A):
         """
         :type A: List[int]
         :rtype: bool
         """
         max_value = A[0]
         for i in range(1,len(A)-1):
             if A[i+1] < max_value:
                 return False
             if A[i] > max_value:
                 max_value = A[i]
         else:
             return True
         # local_count = 0
         # global_count = 0
         # for i in range(len(A)-1):
         #     if A[i] > A[i+1]:
         #         local_count += 1
         #     for j in range(len(A)):
         #         if A[i] > A[j] and i < j:
         #             global_count += 1
         # return local_count == global_count