human
Minimum steps to delete a string after repeated deletion of palindrome substrings | method returns minimum step for deleting the string , where in one step a palindrome is removed.
declare dp array and initialize it with 0 s.
loop for substring length we are considering.
loop with two variables i and j , denoting starting and ending of substrings.
If substring length is 1 , then 1 step will be needed.
delete the ith char individually and assign result for subproblem ( i + 1 , j ).
if current and next char are same , choose min from current and subproblem ( i + 2 , j ).
loop over all right characters and suppose Kth char is same as ith character then choose minimum from current and two substring after ignoring ith and Kth char.
Uncomment below snippet to print actual dp tablex for ( int i = 0.
i < N.
i ++ , cout << endl ) for ( int j = 0.
j < N.
j ++ ) cout << dp [ i ] [ j ] << " ▁ ".
.
Driver Code"
How can the above be solved in Python?

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What is a code to minimum steps to delete a string after repeated deletion of palindrome substrings and the other steps required?
assistant
#Here is code to minimum steps to delete a string after repeated deletion of palindrome substrings and the other steps required.
 def minStepToDeleteString ( str ) :
	N = len ( str )
	dp = [ [ 0 for x in range ( N + 1 ) ] for y in range ( N + 1 ) ]
	for l in range ( 1 , N + 1 ) :
		i = 0
		j = l - 1
		while j < N :
			if ( l == 1 ) :
				dp [ i ] [ j ] = 1
			else :
				dp [ i ] [ j ] = 1 + dp [ i + 1 ] [ j ]
				if ( str [ i ] == str [ i + 1 ] ) :
					dp [ i ] [ j ] = min ( 1 + dp [ i + 2 ] [ j ] , dp [ i ] [ j ] )
				for K in range ( i + 2 , j + 1 ) :
					if ( str [ i ] == str [ K ] ) :
						dp [ i ] [ j ] = min ( dp [ i + 1 ] [ K - 1 ] + dp [ K + 1 ] [ j ] , dp [ i ] [ j ] )
			i += 1
			j += 1
	return dp [ 0 ] [ N - 1 ]
if __name__ == " _ _ main _ _ " :
	str = "2553432"
	print ( minStepToDeleteString ( str ) )