human
Minimize Cost to sort a String in Increasing Order of Frequencies of Characters | Python3 program to implement the above approach.
For a single character.
Stores count of repetitions of a character.
If repeating character.
Otherwise.
Store frequency.
Reset count.
Insert the last character block.
Sort the frequencies.
Stores the minimum cost of all operations.
Store the absolute difference of i - th frequencies of ordered and unordered sequences.
Return the minimum cost.
Driver Code"
How can the above be solved in Python?

Can you provide a code to minimize Cost to sort a String in Increasing Order of Frequencies of Characters and the other steps required?
assistant
#Here is code to minimize Cost to sort a String in Increasing Order of Frequencies of Characters and the other steps required.
 def sortString ( S ) :
	sorted1 = [ ]
	original = [ ]
	insert = False
	if ( len ( S ) == 1 ) :
		print ( 0 )
	curr = 1
	for i in range ( len ( S ) - 1 ) :
		if ( S [ i ] == S [ i + 1 ] ) :
			curr += 1
			insert = False
		else :
			sorted1 . append ( curr )
			original . append ( curr )
			curr = 1
			insert = True
	if ( ( S [ ( len ( S ) - 1 ) ] != S [ ( len ( S ) - 2 ) ] ) or insert == False ) :
		sorted1 . append ( curr )
		original . append ( curr )
	sorted1 . sort ( )
	t_cost = 0
	for i in range ( len ( sorted1 ) ) :
		t_cost += abs ( sorted1 [ i ] - original [ i ] )
	return ( t_cost // 2 )
if __name__ == " _ _ main _ _ " :
	S = " aabbcccdeffffggghhhhhii "
	print ( sortString ( S ) )