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Print all unique digits present in concatenation of all array elements in the order of their occurrence | Function to print unique elements.
Reverse the list.
Traverse the list.
Function which check for all unique digits.
Stores the final number.
Stores the count of unique digits.
Converting string to integer to remove leading zeros.
Stores count of digits.
Iterate over the digits of N.
Retrieve the last digit of N.
Increase the count of the last digit.
Remove the last digit of N.
Converting string to integer again.
Iterate over the digits of N.
Retrieve the last digit of N.
If the value of this digit is not visited.
If its frequency is 1 ( unique ).
Mark the digit visited.
Remove the last digit of N.
Passing this list to print the reversed list.
Function to concatenate array elements.
Stores the concatenated number.
Traverse the array.
Convert to equivalent string.
Concatenate the string.
Passing string to checkUnique function.
Driver Code.
Function call to print unique digits present in the concatenation of array elements"
How can the above be solved in Python?

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What is a code to print all unique digits present in concatenation of all array elements in the order of their occurrence and the other steps required?
assistant
#Here is code to print all unique digits present in concatenation of all array elements in the order of their occurrence and the other steps required.
 def printUnique ( lis ) :
	lis . reverse ( )
	for i in lis :
		print ( i , end = " ▁ " )
def checkUnique ( string ) :
	lis = [ ]
	res = 0
	N = int ( string )
	cnt = [ 0 ] * 10
	while ( N > 0 ) :
		rem = N % 10
		cnt [ rem ] += 1
		N = N // 10
	N = int ( string )
	while ( N > 0 ) :
		rem = N % 10
		if ( cnt [ rem ] != ' visited ' ) :
			if ( cnt [ rem ] == 1 ) :
				lis . append ( rem )
		cnt [ rem ] = ' visited '
		N = N // 10
	printUnique ( lis )
def combineArray ( lis ) :
	string = " "
	for el in lis :
		el = str ( el )
		string = string + el
	checkUnique ( string )
arr = [ 122 , 474 , 612 , 932 ]
combineArray ( arr )