human
Solve the following python programming problem given the following code:
@dual_decorator
def retry(retry_exception=None, tries=5, delay=2, backoff=2, logger=None):
assistant
#Here is the Python program you requested.

    """Retry calling the decorated function using an exponential backoff.
    An exception from a final attempt will propogate.
    :param retry_exception: exception (or tuple of exceptions) to check for and retry on.
    If None, use (AssertionError, CallFailure).
    :param tries: number of times to try (not retry) before giving up
    :param delay: initial delay between retries in seconds
    :param backoff: backoff multiplier
    :param logger: logger to use. If None, use \gmusicapi.utils\ logger
    Modified from
    http://www.saltycrane.com/blog/2009/11/trying-out-retry-decorator-python.
    """
    if (logger is None):
        logger = logging.getLogger(u'gmusicapi.utils')
    if (retry_exception is None):
        retry_exception = (AssertionError, CallFailure)
    @decorator
    def retry_wrapper(f, *args, **kwargs):
        (mtries, mdelay) = (tries, delay)
        while (mtries > 1):
            try:
                return f(*args, **kwargs)
            except retry_exception as e:
                logger.info(u'%s,    retrying    in    %s    seconds...', e, mdelay)
                time.sleep(mdelay)
                mtries -= 1
                mdelay *= backoff
        return f(*args, **kwargs)
    return retry_wrapper