human
Minimum number of given operations required to reduce a number to 2 | Function to find the minimum number of operations required to reduce n to 2.
Initialize a dp array.
Handle the base case.
Iterate in the range [ 2 , n ].
Check if i * 5 <= n.
Check if i + 3 <= n.
Return the result.
Driver code.
Given Input.
Function Call.
Print the result"
How can the above be solved in Python?

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Can you provide a code to minimum number of given operations required to reduce a number to 2 and the other steps required?
assistant
#Here is code to minimum number of given operations required to reduce a number to 2 and the other steps required.
 def findMinOperations ( n ) :
	dp = [ 0 for i in range ( n + 1 ) ]
	for i in range ( n + 1 ) :
		dp [ i ] = 999999
	dp [ 2 ] = 0
	for i in range ( 2 , n + 1 ) :
		if ( i * 5 <= n ) :
			dp [ i * 5 ] = min ( dp [ i * 5 ] , dp [ i ] + 1 )
		if ( i + 3 <= n ) :
			dp [ i + 3 ] = min ( dp [ i + 3 ] , dp [ i ] + 1 )
	return dp [ n ]
if __name__ == ' _ _ main _ _ ' :
	n = 28
	m = findMinOperations ( n )
	if ( m != 9999 ) :
		print ( m )
	else :
		print ( - 1 )