human
Generate a Matrix such that given Matrix elements are equal to Bitwise OR of all corresponding row and column elements of generated Matrix | Function to find the matrix , A [ ] [ ] satisfying the given conditions.
Store the final matrix.
Initialize all the elements of the matrix A with 1.
Traverse the matrix B [ ] [ ] row - wise.
If B [ i ] [ j ] is equal to 0.
Mark all the elements of ith row of A [ ] [ ] as 0.
Mark all the elements of jth column of A [ ] [ ] as 0.
Check if the matrix B [ ] [ ] can be made using matrix A [ ] [ ].
Store the bitwise OR of all elements of A [ ] [ ] in ith row and jth column.
Traverse through ith row.
Traverse through jth column.
If B [ i ] [ j ] is not equal to c , pr " Not ▁ Possible ".
Print the final matrix A [ ] [ ].
Driver Code.
Function Call"
How can the above be solved in Python?

=====
Give me a code to generate a Matrix such that given Matrix elements are equal to Bitwise OR of all corresponding row and column elements of generated Matrix and the other steps required?
assistant
#Here is code to generate a Matrix such that given Matrix elements are equal to Bitwise OR of all corresponding row and column elements of generated Matrix and the other steps required.
 def findOriginalMatrix ( B , N , M ) :
	A = [ [ 0 ] * M ] * N
	for i in range ( N ) :
		for j in range ( M ) :
			A [ i ] [ j ] = 1
	for i in range ( N ) :
		for j in range ( M ) :
			if ( B [ i ] [ j ] == 0 ) :
				for k in range ( M ) :
					A [ i ] [ k ] = 0
				for k in range ( N ) :
					A [ k ] [ j ] = 0
	for i in range ( N ) :
		for j in range ( M ) :
			c = 0
			for k in range ( M ) :
				if ( c == 1 ) :
					break
				c += A [ i ] [ k ]
			for k in range ( N ) :
				if ( c == 1 ) :
					break
				c += A [ k ] [ j ]
			if ( c != B [ i ] [ j ] ) :
				print ( " Not ▁ Possible " )
				return
	for i in range ( N ) :
		for j in range ( M ) :
			print ( A [ i ] [ j ] , end = " ▁ " )
		print ( )
B = [ [ 1 , 1 , 1 ] , [ 1 , 1 , 1 ] ]
N = len ( B )
M = len ( B [ 0 ] )
findOriginalMatrix ( B , N , M )