human
Give me a code to non and the other steps required given the following:
Non | A dynamic programming based function to find nth Catalan number.
Table to store results of subproblems.
Fill entries in catalan [ ] using recursive formula.
Return last entry.
Returns count of ways to connect n points on a circle such that no two connecting lines cross each other and every point is connected with one other point ..
Throw error if n is odd.
Else return n / 2 'th Catalan number.
Driver Code"
Solution in Python:
assistant
#Here is code to non and the other steps required.
 def catalanDP ( n ) :
	catalan = [ 1 for i in range ( n + 1 ) ]
	for i in range ( 2 , n + 1 ) :
		catalan [ i ] = 0
		for j in range ( i ) :
			catalan [ i ] += ( catalan [ j ] * catalan [ i - j - 1 ] )
	return catalan [ n ]
def countWays ( n ) :
	if ( n & 1 ) :
		print ( " Invalid " )
		return 0
	return catalanDP ( n // 2 )
print ( countWays ( 6 ) )