human
Delannoy Number | Return the nth Delannoy Number ..
Base cases.
Driven code"
How can the above be solved in Python?
 What is a code to delannoy Number and the other steps required?
assistant
#Here is code to delannoy Number and the other steps required.
 def dealnnoy ( n , m ) :
	dp = [ [ 0 for x in range ( n + 1 ) ] for x in range ( m + 1 ) ]
	for i in range ( m ) :
		dp [ 0 ] [ i ] = 1
	for i in range ( 1 , m + 1 ) :
		dp [ i ] [ 0 ] = 1
	for i in range ( 1 , m + 1 ) :
		for j in range ( 1 , n + 1 ) :
			dp [ i ] [ j ] = dp [ i - 1 ] [ j ] + dp [ i - 1 ] [ j - 1 ] + dp [ i ] [ j - 1 ] ;
	return dp [ m ] [ n ]
n = 3
m = 4
print ( dealnnoy ( n , m ) )