human
Minimum bit swaps between given numbers to make their Bitwise OR equal to Bitwise AND | Function for counting number of set bit.
Function to return the count of minimum operations required.
cnt to count the number of bits set in A and in B.
If odd numbers of total set bits.
one_zero = 1 in A and 0 in B at ith bit similarly for zero_one.
When bitpos is set in B , unset in B.
When bitpos is set in A , unset in B.
Number of moves is half of number pairs of each group.
Odd number pairs.
Driver code.
Input.
Function call to compute the result"
How can the above be solved in Python?
 Can you provide a code to minimum bit swaps between given numbers to make their Bitwise OR equal to Bitwise AND and the other steps required?
assistant
#Here is code to minimum bit swaps between given numbers to make their Bitwise OR equal to Bitwise AND and the other steps required.
 def countSetBits ( n ) :
	count = 0
	while ( n ) :
		n = n & ( n - 1 )
		count += 1
	return count
def minOperations ( A , B ) :
	cnt1 = 0
	cnt2 = 0
	cnt1 += countSetBits ( A )
	cnt2 += countSetBits ( B )
	if ( ( cnt1 + cnt2 ) % 2 != 0 ) :
		return - 1
	oneZero = 0
	zeroOne = 0
	ans = 0
	for i in range ( max ( cnt1 , cnt2 ) ) :
		bitpos = 1 << i
		if ( ( not ( bitpos & A ) ) and ( bitpos & B ) ) :
			zeroOne += 1
		if ( ( bitpos & A ) and ( not ( bitpos & B ) ) ) :
			oneZero += 1
	ans = ( zeroOne // 2 ) + ( oneZero // 2 )
	if ( zeroOne % 2 != 0 ) :
		ans += 2
	return ans
if __name__ == ' _ _ main _ _ ' :
	A = 27
	B = 5
	print ( minOperations ( A , B ) )