human
Minimum number of bits of array elements required to be flipped to make all array elements equal | Function to count minimum number of bits required to be flipped to make all array elements equal.
Stores the count of unset bits.
Stores the count of set bits.
Traverse the array.
Traverse the bit of arr [ i ].
If current bit is set.
Increment fre1 [ j ].
Otherwise.
Increment fre0 [ j ].
Right shift x by 1.
Stores the count of total moves.
Traverse the range [ 0 , 32 ].
Update the value of ans.
Return the minimum number of flips required.
Driver Code"
How can the above be solved in Python?
 ... Give me a code to minimum number of bits of array elements required to be flipped to make all array elements equal and the other steps required?
assistant
#Here is code to minimum number of bits of array elements required to be flipped to make all array elements equal and the other steps required.
 def makeEqual ( arr , n ) :
	fre0 = [ 0 ] * 33
	fre1 = [ 0 ] * 33
	for i in range ( n ) :
		x = arr [ i ]
		for j in range ( 33 ) :
			if ( x & 1 ) :
				fre1 [ j ] += 1
			else :
				fre0 [ j ] += 1
			x = x >> 1
	ans = 0
	for i in range ( 33 ) :
		ans += min ( fre0 [ i ] , fre1 [ i ] )
	return ans
if __name__ == ' _ _ main _ _ ' :
	arr = [ 3 , 5 ]
	N = len ( arr )
	print ( makeEqual ( arr , N ) )