human
Queries to update array elements in a range [ L , R ] to satisfy given conditions | Function to prthe array.
Function to perform the query in range [ L , R ] such that arr [ i ] += i - L + 1.
Initialize array.
Traverse the query array.
Stores range in 1 - based index.
Update arr1 [ L ].
Update arr1 [ R + 1 ].
Update arr2 [ R + 1 ].
Calculate prefix sum.
Traverse the array , arr2 [ ].
Copy arr2 [ ] into arr [ ].
Driver Code.
Given array.
Size of the array.
Stores count of query.
Function Call"
How can the above be solved in Python?

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Write me a code to queries to update array elements in a range [ L , R ] to satisfy given conditions and the other steps required?
assistant
#Here is code to queries to update array elements in a range [ L , R ] to satisfy given conditions and the other steps required.
 def printArray ( arr , N ) :
	print ( * arr )
def modifyArray ( arr , N , Q , cntQuery ) :
	arr1 = [ 0 for i in range ( N + 2 ) ]
	arr2 = [ 0 for i in range ( N + 2 ) ]
	for i in range ( cntQuery ) :
		L = Q [ i ] [ 0 ] + 1
		R = Q [ i ] [ 1 ] + 1
		arr1 [ L ] += 1
		arr1 [ R + 1 ] -= 1
		arr2 [ R + 1 ] -= R - L + 1
	for i in range ( 1 , N + 1 ) :
		arr1 [ i ] += arr1 [ i - 1 ]
	for i in range ( 1 , N + 1 ) :
		arr2 [ i ] += arr2 [ i - 1 ] + arr1 [ i ]
	for i in range ( 1 , N + 1 ) :
		arr [ i - 1 ] = arr2 [ i ]
	printArray ( arr , N )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 0 , 0 , 0 , 0 ]
	N = len ( arr )
	Q = [ [ 1 , 3 ] , [ 0 , 1 ] ]
	cntQuery = len ( Q )
	modifyArray ( arr , N , Q , cntQuery )