human
Can you provide a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/split-a-string-into-the-max-number-of-unique-substrings/:
Given a string s, return the maximum number of unique substrings that the given string can be split into.
You can split string s into any list of non-empty substrings, where the concatenation of the substrings forms the original string. However, you must split the substrings such that all of them are unique.
A substring is a contiguous sequence of characters within a string.
 
Example 1:
Input: s = "ababccc"
Output: 5
Explanation: One way to split maximally is ['a', 'b', 'ab', 'c', 'cc']. Splitting like ['a', 'b', 'a', 'b', 'c', 'cc'] is not valid as you have 'a' and 'b' multiple times.

Example 2:
Input: s = "aba"
Output: 2
Explanation: One way to split maximally is ['a', 'ba'].

Example 3:
Input: s = "aa"
Output: 1
Explanation: It is impossible to split the string any further.

 
Constraints:

1 <= s.length <= 16

s contains only lower case English letters.

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution:
    def maxUniqueSplit(self, s: str) -> int:
        # dp = [[\"\"] for _ in range(len(s))]
        # dp[0] = [s[0]]
        # for i in range(1, len(s)):
        #     maxnum_ = 1
        #     for j in range(i):
        #         if s[j+1:i] not in dp[j]:
        #             maxnum = len(dp[j]) + 1
        #             if maxnum > maxnum_:
        #                 maxnum_ = maxnum
        #                 dp[i] = dp[j].copy() 
        #                 dp[i].append(s[j+1:i])
        # print(dp)
        # return len(dp[len(s)-1])
#         return len(self.maxUniqueSplit_(s, len(s)-1)[-1])
    
#     @lru_cache
#     def maxUniqueSplit_(self, s, i):
#         if i == 0:
#             return [[s[i]]]
#         else:
#             max_ = 0
#             toreturn = []
#             for j in range(i):
#                 maxUniqueSplit_j = self.maxUniqueSplit_(s, j)
#                 for uniquesplit_j in maxUniqueSplit_j:
#                     if s[j+1:i+1] not in uniquesplit_j:
#                         if len(uniquesplit_j) + 1 > max_:
#                             toreturn = [uniquesplit_j + [s[j+1:i+1]]]
#                             max_ = len(uniquesplit_j) + 1
#                         elif len(uniquesplit_j) + 1 == max_:
#                             toreturn.append(uniquesplit_j + [s[j+1:i+1]])
#                     if j == i - 1 and len(toreturn) == 0:
#                         toreturn = [uniquesplit_j]
#             print(toreturn, i)
#             return toreturn
        if len(s) == 1:
            return 1
        def splitter(str):
            for i in range(1, len(str)):
                start = str[0:i]
                end = str[i:]
                yield (start, end)
                for split in splitter(end):
                    result = [start]
                    result.extend(split)
                    yield result
        
        maxnum = 0
        for split in splitter(s):
            if len(set(split)) == len(split):
                maxnum = max(len(split), maxnum)
      ...