human
Print the string after the specified character has occurred given no . of times | Function to print the string.
If given count is 0 print the given string and return.
Start traversing the string.
Increment occ if current char is equal to given character.
Break the loop if given character has been occurred given no . of times.
Print the string after the occurrence of given character given no . of times.
Otherwise string is empty.
Driver code"
Solution in Python:
 ... Can you provide a code to print the string after the specified character has occurred given no?
assistant
#Here is code to print the string after the specified character has occurred given no .
 def printString ( str , ch , count ) :
	occ , i = 0 , 0
	if ( count == 0 ) :
		print ( str )
	for i in range ( len ( str ) ) :
		if ( str [ i ] == ch ) :
			occ += 1
		if ( occ == count ) :
			break
	if ( i < len ( str ) - 1 ) :
		print ( str [ i + 1 : len ( str ) - i + 2 ] )
	else :
		print ( " Empty ▁ string " )
if __name__ == ' _ _ main _ _ ' :
	str = " geeks ▁ for ▁ geeks "
	printString ( str , ' e ' , 2 )