human
Can you provide a code to number of Longest Increasing Subsequences and the other steps required given the following:
Number of Longest Increasing Subsequences | Function to count the number of LIS in the array nums [ ].
Base Case.
Initialize dp_l array with 1 s.
Initialize dp_c array with 1 s.
If current element is smaller.
Store the maximum element from dp_l.
Stores the count of LIS.
Traverse dp_l and dp_c simultaneously.
Update the count.
Return the count of LIS.
Given array arr [ ].
Function Call"
Solution in Python:
assistant
#Here is code to number of Longest Increasing Subsequences and the other steps required.
 def findNumberOfLIS ( nums ) :
	if not nums :
		return 0
	n = len ( nums )
	dp_l = [ 1 ] * n
	dp_c = [ 1 ] * n
	for i , num in enumerate ( nums ) :
		for j in range ( i ) :
			if nums [ i ] <= nums [ j ] :
				continue
			if dp_l [ j ] + 1 > dp_l [ i ] :
				dp_l [ i ] = dp_l [ j ] + 1
				dp_c [ i ] = dp_c [ j ]
			elif dp_l [ j ] + 1 == dp_l [ i ] :
				dp_c [ i ] += dp_c [ j ]
	max_length = max ( x for x in dp_l )
	count = 0
	for l , c in zip ( dp_l , dp_c ) :
		if l == max_length :
			count += c
	return count
arr = [ 1 , 3 , 5 , 4 , 7 ]
print ( findNumberOfLIS ( arr ) )