human
Maximum product from array such that frequency sum of all repeating elements in product is less than or equal to 2 * k | Function to return the maximum product value.
To store the product.
Sort the array.
Efficiently finding product including every element once.
Storing values in hash map.
Including the greater repeating values so that product can be maximized.
Driver code"
Solution in Python:
 Can you provide a code to maximum product from array such that frequency sum of all repeating elements in product is less than or equal to 2 * k and the other steps required?
assistant
#Here is code to maximum product from array such that frequency sum of all repeating elements in product is less than or equal to 2 * k and the other steps required.
 def maxProd ( arr , n , k ) :
	product = 1 ;
	s = dict . fromkeys ( arr , 0 ) ;
	arr . sort ( ) ;
	for i in range ( n ) :
		if ( s [ arr [ i ] ] == 0 ) :
			product = product * arr [ i ] ;
		s [ arr [ i ] ] = s [ arr [ i ] ] + 1 ;
	j = n - 1 ;
	while ( j >= 0 and k > 0 ) :
		if ( ( k > ( s [ arr [ j ] ] - 1 ) ) and ( ( s [ arr [ j ] ] - 1 ) > 0 ) ) :
			product *= pow ( arr [ j ] , s [ arr [ j ] ] - 1 ) ;
			k = k - s [ arr [ j ] ] + 1 ;
			s [ arr [ j ] ] = 0 ;
		if ( k <= ( s [ arr [ j ] ] - 1 ) and ( ( s [ arr [ j ] ] - 1 ) > 0 ) ) :
			product *= pow ( arr [ j ] , k ) ;
			break ;
		j -= 1
	return product ;
if __name__ == " _ _ main _ _ " :
	arr = [ 5 , 6 , 7 , 8 , 2 , 5 , 6 , 8 ] ;
	n = len ( arr ) ;
	k = 2 ;
	print ( maxProd ( arr , n , k ) ) ;