human
Count of pairs from first N natural numbers with remainder at least K | Function to count the number of pairs ( a , b ) such that a % b is at least K.
Base Case.
Stores resultant count of pairs.
Iterate over the range [ K + 1 , N ].
Find the cycled elements.
Find the remaining elements.
Return the resultant possible count of pairs.
Driver Code"
How can the above be solved in Python?

=====
Give me a code to count of pairs from first N natural numbers with remainder at least K and the other steps required?
assistant
#Here is code to count of pairs from first N natural numbers with remainder at least K and the other steps required.
 def countTotalPairs ( N , K ) :
	if ( K == 0 ) :
		return N * N
	ans = 0
	for b in range ( K + 1 , N + 1 ) :
		ans += ( N // b ) * ( b - K )
		ans += max ( N % b - K + 1 , 0 )
	return ans
N = 5
K = 2
print ( countTotalPairs ( N , K ) )