human
What is a code to count the subarray with sum strictly greater than the sum of remaining elements and the other steps required given the following:
Count the subarray with sum strictly greater than the sum of remaining elements | Python3 implementation of the above approach.
Calculating total sum of given array.
For loop for beginning point of a subarray.
initialise subarray_sum to 0.
For loop for calculating subarray_sum and remaining_sum.
Calculating subarray_sum and corresponding remaining_sum.
Checking for the condition when subarray sum is strictly greater than the remaining sum of the array element.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count the subarray with sum strictly greater than the sum of remaining elements and the other steps required.
 def Count_subarray ( arr , n ) :
	total_sum = 0 ;
	count = 0 ;
	for i in range ( n ) :
		total_sum += arr [ i ] ;
	for i in range ( n ) :
		subarray_sum = 0 ;
		for j in range ( i , n ) :
			subarray_sum += arr [ j ] ;
			remaining_sum = total_sum - subarray_sum ;
			if ( subarray_sum > remaining_sum ) :
				count += 1 ;
	return count ;
if __name__ == " _ _ main _ _ " :
	arr = [ 10 , 9 , 12 , 6 ] ;
	n = len ( arr ) ;
	print ( Count_subarray ( arr , n ) ) ;