human
Minimize sum of adjacent difference with removal of one element from array | Function to find the element.
Value variable for storing the total value.
Declaring maximum value as zero.
If array contains on element.
Storing the maximum value in temp variable.
Adding the adjacent difference modulus values of removed element . Removing adjacent difference modulus value after removing element.
Returning total value - maximum value.
Drivers code"
How can the above be solved in Python?
 ... What is a code to minimize sum of adjacent difference with removal of one element from array and the other steps required?
assistant
#Here is code to minimize sum of adjacent difference with removal of one element from array and the other steps required.
 def findMinRemoval ( arr , n ) :
	value = 0
	maximum = 0
	if ( n == 1 ) :
		return 0
	for i in range ( n ) :
		if ( i != 0 and i != n - 1 ) :
			value = value + abs ( arr [ i ] - arr [ i + 1 ] )
			temp = ( abs ( arr [ i ] - arr [ i + 1 ] ) + abs ( arr [ i ] - arr [ i - 1 ] ) - abs ( arr [ i - 1 ] - arr [ i + 1 ] ) )
		elif ( i == 0 ) :
			value = value + abs ( arr [ i ] - arr [ i + 1 ] )
			temp = abs ( arr [ i ] - arr [ i + 1 ] )
		else :
			temp = abs ( arr [ i ] - arr [ i - 1 ] )
		maximum = max ( maximum , temp )
	return ( value - maximum )
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 5 , 3 , 2 , 10 ]
	n = len ( arr )
	print ( findMinRemoval ( arr , n ) )