human
Maximum removals possible from an array such that sum of its elements is greater than or equal to that of another array | Function to maximize the count of elements required to be removed from arr [ ] such that the sum of arr [ ] is greater than or equal to sum of the array brr [ ].
Sort the array arr [ ].
Stores index of smallest element of arr [ ].
Stores sum of elements of the array arr [ ].
Traverse the array arr [ ].
Update sumArr.
Stores sum of elements of the array brr [ ].
Traverse the array brr [ ].
Update sumArr.
Stores count of removed elements.
Repeatedly remove the smallest element of arr [ ].
Update sumArr.
Remove the smallest element.
If the sum of remaining elements in arr [ ] >= sum of brr [ ].
Update cntRemElem.
Driver Code"
How can the above be solved in Python?
 Can you provide a code to maximum removals possible from an array such that sum of its elements is greater than or equal to that of another array and the other steps required?
assistant
#Here is code to maximum removals possible from an array such that sum of its elements is greater than or equal to that of another array and the other steps required.
 def maxCntRemovedfromArray ( arr , N , brr , M ) :
	arr . sort ( reverse = False )
	i = 0
	sumArr = 0
	for i in range ( N ) :
		sumArr += arr [ i ]
	sumBrr = 0
	for i in range ( M ) :
		sumBrr += brr [ i ]
	cntRemElem = 0
	while ( i < N and sumArr >= sumBrr ) :
		sumArr -= arr [ i ]
		i += 1
		if ( sumArr >= sumBrr ) :
			cntRemElem += 1
	return cntRemElem
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 4 , 6 ]
	brr = [ 7 ]
	N = len ( arr )
	M = len ( brr )
	print ( maxCntRemovedfromArray ( arr , N , brr , M ) )