human
Minimum number to be added to all digits of X to make X > Y | Function to check if X is lexicographically larger Y.
It is lexicographically larger.
Utility function to check minimum value of d.
If X is already larger do not need to add anything.
Adding d to all elements of X.
If X is larger now print d.
else print d + 1.
Driver Code.
Taking the numbers as sequences"
Solution in Python:

Can you provide a code to minimum number to be added to all digits of X to make X > Y and the other steps required?
assistant
#Here is code to minimum number to be added to all digits of X to make X > Y and the other steps required.
 def IsLarger ( X , Y , n ) :
	for i in range ( n ) :
		if ( X [ i ] < Y [ i ] ) :
			return False ;
	return True ;
def solve ( X , Y , n ) :
	ans = 0 ;
	if ( IsLarger ( X , Y , n ) ) :
		ans = 0 ;
	else :
		d = Y [ 0 ] - X [ 0 ] ;
		for i in range ( n ) :
			X [ i ] += d ;
		if ( IsLarger ( X , Y , n ) ) :
			ans = d ;
		else :
			ans = d + 1 ;
	return ans ;
if __name__ == " _ _ main _ _ " :
	X = [ 2 , 3 , 6 , 9 ] ;
	Y = [ 3 , 4 , 8 , 1 ] ;
	n = len ( X ) ;
	print ( solve ( X , Y , n ) ) ;