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Can you provide a code to find a pair ( a , b ) such that Aa + Bb = N and the other steps required given the following:
Find a pair ( a , b ) such that Aa + Bb = N | Function to calculate the minimum power of A and B greater than N.
Stores the power of A which is greater than N.
Increment count by 1.
Divide N by A.
Function to find a pair ( a , b ) such that A ^ a + B ^ b = N.
Calculate the minimum power of A greater than N.
Calculate the minimum power of B greater than N.
Make copy of A and B.
Traverse for every pair ( i , j ).
Check if B ^ j + A ^ i = N To overcome the overflow problem use B = N - A rather than B + A = N.
Increment power B by 1.
Increment power A by 1.
Finally pr - 1 if no pair is found.
Driver Code.
Given A , B and N.
Function Call"
Solution in Python:
assistant
#Here is code to find a pair ( a , b ) such that Aa + Bb = N and the other steps required.
 def power ( A , N ) :
	count = 0 ;
	if ( A == 1 ) :
		return 0 ;
	while ( N > 0 ) :
		count += 1 ;
		N //= A ;
	return int ( count ) ;
def Pairs ( N , A , B ) :
	powerA , powerB = 0 , 0 ;
	powerA = power ( A , N ) ;
	powerB = power ( B , N ) ;
	intialB = B ;
	intialA = A ;
	A = 1 ;
	for i in range ( powerA + 1 ) :
		B = 1 ;
		for j in range ( powerB + 1 ) :
			if ( B == N - A ) :
				print ( i , " ▁ " , j ) ;
				return ;
			B *= intialB ;
		A *= intialA ;
	print ( " - 1" ) ;
	return ;
if __name__ == ' _ _ main _ _ ' :
	N = 106 ;
	A = 3 ;
	B = 5 ;
	Pairs ( N , A , B ) ;