human
Check if the sum of digits of N is palindrome | Function to return the sum of digits of n.
Function that returns true if n is palindrome.
Find the appropriate divisor to extract the leading digit.
If first and last digit not same return false.
Removing the leading and trailing digit from number.
Reducing divisor by a factor of 2 as 2 digits are dropped.
Function that returns true if the digit sum of n is palindrome.
Sum of the digits of n.
If the digit sum is palindrome.
Driver code"
How can the above be solved in Python?

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What is a code to check if the sum of digits of N is palindrome and the other steps required?
assistant
#Here is code to check if the sum of digits of N is palindrome and the other steps required.
 def digitSum ( n ) :
	sum = 0 ;
	while ( n > 0 ) :
		sum += ( n % 10 ) ;
		n //= 10 ;
	return sum ;
def isPalindrome ( n ) :
	divisor = 1 ;
	while ( n // divisor >= 10 ) :
		divisor *= 10 ;
	while ( n != 0 ) :
		leading = n // divisor ;
		trailing = n % 10 ;
		if ( leading != trailing ) :
			return False ;
		n = ( n % divisor ) // 10 ;
		divisor = divisor // 100 ;
	return True ;
def isDigitSumPalindrome ( n ) :
	sum = digitSum ( n ) ;
	if ( isPalindrome ( sum ) ) :
		return True ;
	return False ;
if __name__ == " _ _ main _ _ " :
	n = 56 ;
	if ( isDigitSumPalindrome ( n ) ) :
		print ( " Yes " ) ;
	else :
		print ( " No " ) ;