human
Bitonic string | Function to check if the given string is bitonic.
Check for increasing sequence.
If end of string has been reached.
Check for decreasing sequence.
If the end of string hasn 't  been reached.
Return true if bitonic.
Given string.
Function Call"
How can the above be solved in Python?

Can you provide a code to bitonic string and the other steps required?
assistant
#Here is code to bitonic string and the other steps required.
 def checkBitonic ( s ) :
	i = 0
	j = 0
	for i in range ( 1 , len ( s ) ) :
		if ( s [ i ] > s [ i - 1 ] ) :
			continue ;
		if ( s [ i ] <= s [ i - 1 ] ) :
			break ;
	if ( i == ( len ( s ) - 1 ) ) :
		return True ;
	for j in range ( i + 1 , len ( s ) ) :
		if ( s [ j ] < s [ j - 1 ] ) :
			continue ;
		if ( s [ j ] >= s [ j - 1 ] ) :
			break ;
	i = j ;
	if ( i != len ( s ) - 1 ) :
		return False ;
	return True ;
s = " abcdfgcba "
if ( checkBitonic ( s ) ) :
	print ( " YES " )
else :
	print ( " NO " )