human
Count of Ks in the Array for a given range of indices after array updates for Q queries | ''Function to perform all the queries.
''Stores the count of 0s.
''Count the number of 0s for  query of type 1.
'' Update the array element for  query of type 2.
''Driver Code"
Solution in Python:
 ... Can you provide a code to count of Ks in the Array for a given range of indices after array updates for Q queries and the other steps required?
assistant
#Here is code to count of Ks in the Array for a given range of indices after array updates for Q queries and the other steps required.
 def performQueries ( n , q , k , arr , query ) :
	for i in range ( 1 , q + 1 , 1 ) :
	count = 0
	if ( query [ i - 1 ] [ 0 ] == 1 ) :
for j in range ( query [ i - 1 ] [ 1 ] , query [ i - 1 ] [ 2 ] + 1 , 1 ) :
	if ( arr [ j ] == k ) :
count += 1
	print ( count )
	else :
arr [ query [ i - 1 ] [ 1 ] ] = query [ i - 1 ] [ 2 ]
if __name__ == ' _ _ main _ _ ' :
	arr = [ 9 , 5 , 7 , 6 , 9 , 0 , 0 , 0 , 0 , 5 , 6 , 7 , 3 , 9 , 0 , 7 , 0 , 9 , 0 ]
	Q = 5
		query = [ [ 1 , 5 , 14 ] , [ 2 , 6 , 1 ] , [ 1 , 0 , 8 ] , [ 2 , 13 , 0 ] , [ 1 , 6 , 18 ] ]
	N = len ( arr )
K = 0
	performQueries ( N , Q , K , arr , query )