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Super | Function to check if N is a super - d number.
Driver Code"
Solution in Python:
assistant
#Here is code to super and the other steps required.
 def isSuperdNum ( n ) :
	for d in range ( 2 , 10 ) :
		substring = str ( d ) * d ;
		if substring in str ( d * pow ( n , d ) ) :
			return True
	return False
n = 261
if isSuperdNum ( n ) == True :
	print ( " Yes " )
else :
	print ( " No " )