human
Solve in Python:
Implement int sqrt(int x).

Compute and return the square root of x, where x is guaranteed to be a non-negative integer.

Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned.

Example 1:

Input: 4
Output: 2

Example 2:

Input: 8
Output: 2
Explanation: The square root of 8 is 2.82842..., and since 
             the decimal part is truncated, 2 is returned.
 Give me a Python program to compute and return the square root of x, where x is guaranteed to be a non-negative integer?
assistant
#Here is Python program to compute and return the square root of x, where x is guaranteed to be a non-negative integer.

class Solution:
     def mySqrt(self, x):
         """
         :type x: int
         :rtype: int
         """
         return int(x**0.5)