human
Check if an array contains all elements of a given range | Function to check the array for elements in given range.
Range is the no . of elements that are to be checked.
Traversing the array.
If an element is in range.
Checking whether elements in range 0 - range are negative.
Element from range is missing from array.
All range elements are present.
Defining Array and size.
A is lower limit and B is the upper limit of range.
True denotes all elements were present.
False denotes any element was not present"
How can the above be solved in Python?

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What is a code to check if an array contains all elements of a given range and the other steps required?
assistant
#Here is code to check if an array contains all elements of a given range and the other steps required.
 def check_elements ( arr , n , A , B ) :
	rangeV = B - A
	for i in range ( 0 , n ) :
		if ( abs ( arr [ i ] ) >= A and abs ( arr [ i ] ) <= B ) :
			z = abs ( arr [ i ] ) - A
			if ( arr [ z ] > 0 ) :
				arr [ z ] = arr [ z ] * - 1
	count = 0
	for i in range ( 0 , rangeV + 1 ) :
		if i >= n :
			break
		if ( arr [ i ] > 0 ) :
			return False
		else :
			count = count + 1
	if ( count != ( rangeV + 1 ) ) :
		return False
	return True
arr = [ 1 , 4 , 5 , 2 , 7 , 8 , 3 ]
n = len ( arr )
A = 2
B = 5
if ( check_elements ( arr , n , A , B ) ) :
	print ( " Yes " )
else :
	print ( " No " )