human
Rotate digits of a given number by K | Function to find the count of digits in N.
Stores count of digits in N.
Calculate the count of digits in N.
Update digit.
Update N.
Function to rotate the digits of N by K.
Stores count of digits in N.
Update K so that only need to handle left rotation.
Stores first K digits of N.
Remove first K digits of N.
Stores count of digits in left_no.
Append left_no to the right of digits of N.
Driver Code.
Function Call"
How can the above be solved in Python?

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Write me a code to rotate digits of a given number by K and the other steps required?
assistant
#Here is code to rotate digits of a given number by K and the other steps required.
 def numberOfDigit ( N ) :
	digit = 0
	while ( N > 0 ) :
		digit += 1
		N //= 10
	return digit
def rotateNumberByK ( N , K ) :
	X = numberOfDigit ( N )
	K = ( ( K % X ) + X ) % X
	left_no = N // pow ( 10 , X - K )
	N = N % pow ( 10 , X - K )
	left_digit = numberOfDigit ( left_no )
	N = N * pow ( 10 , left_digit ) + left_no
	print ( N )
if __name__ == ' _ _ main _ _ ' :
	N , K = 12345 , 7
	rotateNumberByK ( N , K )