human
Solve the following python programming problem given the following code:
def numIslands2(self, m, n, positions) : 
    '
        :type m: int
        :type n: int
        :type positions: List[List[int]]
        :rtype: List[int]
        ' 
    def node_id(node, n) : 
        return ((node [0] * n) + node [1]) 
def find_set(x) : 
        if (set [x] != x) : 
            set [x] = find_set (set [x]) 
return set [x] 
def union_set(x, y) : 
        (x_root, y_root) = (find_set (x), find_set (y)) 
        set [min (x_root, y_root)] = max (x_root, y_root) 
numbers = [] 
    number = 0 
    directions = [(0, (- 1)), (0, 1), ((- 1), 0), (1, 0)] 
    set = { 
        
} 
    for position in positions : 
        node = (position [0], position [1]) 
        set [node_id (node, n)] = node_id (node, n) 
        number += 1 
        for d in directions : 
            neighbor = ((position [0] + d [0]), (position [1] + d [1])) 
            if ((0 <= neighbor [0] < m) and (0 <= neighbor [1] < n) and (node_id (find_set, n) in set)) : 
                if (find_set (node_id (node, n)) != find_set (node_id (neighbor, n))) : 
                    union_set (node_id (node, n), node_id (neighbor, n)) 
                    number -= 1 
numbers.append (number) 
return numbers 

    
    

    Fix the buggy line: if ((0 <= neighbor [0] < m) and (0 <= neighbor [1] < n) and (node_id (find_set, n) in set)) :
assistant
#Here is Python code to fix the buggy line: if ((0 <= neighbor [0] < m) and (0 <= neighbor [1] < n) and (node_id (find_set, n) in set)) :
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if ((0 <= neighbor [0] < m) and (0 <= neighbor [1] < n) and (node_id (neighbor, n) in set)) :