human
Write me a code to sum of all proper divisors from 1 to N and the other steps required given the following:
Sum of all proper divisors from 1 to N | Utility function to find sum of all proper divisor of number up to N.
Loop to iterate over all the numbers from 1 to N.
Find all divisors of i and add them.
Subtracting ' i ' so that the number itself is not included.
Driver Code"
Solution in Python:
assistant
#Here is code to sum of all proper divisors from 1 to N and the other steps required.
 def properDivisorSum ( n ) :
	sum = 0
	for i in range ( n + 1 ) :
		for j in range ( 1 , i + 1 ) :
			if j * j > i :
				break
			if ( i % j == 0 ) :
				if ( i // j == j ) :
					sum += j
				else :
					sum += j + i // j
		sum = sum - i
	return sum
if __name__ == ' _ _ main _ _ ' :
	n = 4
	print ( properDivisorSum ( n ) )
	n = 5
	print ( properDivisorSum ( n ) )