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Minimum Steps to obtain N from 1 by the given operations | Python3 program to implement the above approach.
Base Case.
Recursive Call for n - 1.
Check if n is divisible by 2.
Check if n is divisible by 3.
Returns a tuple ( a , b ) , where a : Minimum steps to obtain x from 1 b : Previous number.
Function that find the optimal solution.
Print the length.
Exit condition for loop = - 1 when n has reached 1.
Return the sequence in reverse order.
Given N.
Function Call"
How can the above be solved in Python?
 ... Can you provide a code to minimum Steps to obtain N from 1 by the given operations and the other steps required?
assistant
#Here is code to minimum Steps to obtain N from 1 by the given operations and the other steps required.
 def find_sequence ( n ) :
	if n == 1 :
		return 1 , - 1
	ans = ( find_sequence ( n - 1 ) [ 0 ] + 1 , n - 1 )
	if n % 2 == 0 :
		div_by_2 = find_sequence ( n // 2 )
		if div_by_2 [ 0 ] < ans [ 0 ] :
			ans = ( div_by_2 [ 0 ] + 1 , n // 2 )
	if n % 3 == 0 :
		div_by_3 = find_sequence ( n // 3 )
		if div_by_3 [ 0 ] < ans [ 0 ] :
			ans = ( div_by_3 [ 0 ] + 1 , n // 3 )
	return ans
def find_solution ( n ) :
	a , b = find_sequence ( n )
	print ( a )
	sequence = [ ]
	sequence . append ( n )
	while b != - 1 :
		sequence . append ( b )
		_ , b = find_sequence ( b )
	return sequence [ : : - 1 ]
n = 5
print ( * find_solution ( n ) )