human
I found an interesting problem on https://leetcode.com/problems/detect-pattern-of-length-m-repeated-k-or-more-times/:
Given an array of positive integers arr,  find a pattern of length m that is repeated k or more times.
A pattern is a subarray (consecutive sub-sequence) that consists of one or more values, repeated multiple times consecutively without overlapping. A pattern is defined by its length and the number of repetitions.
Return true if there exists a pattern of length m that is repeated k or more times, otherwise return false.
 
Example 1:
Input: arr = [1,2,4,4,4,4], m = 1, k = 3
Output: true
Explanation: The pattern (4) of length 1 is repeated 4 consecutive times. Notice that pattern can be repeated k or more times but not less.

Example 2:
Input: arr = [1,2,1,2,1,1,1,3], m = 2, k = 2
Output: true
Explanation: The pattern (1,2) of length 2 is repeated 2 consecutive times. Another valid pattern (2,1) is also repeated 2 times.

Example 3:
Input: arr = [1,2,1,2,1,3], m = 2, k = 3
Output: false
Explanation: The pattern (1,2) is of length 2 but is repeated only 2 times. There is no pattern of length 2 that is repeated 3 or more times.

Example 4:
Input: arr = [1,2,3,1,2], m = 2, k = 2
Output: false
Explanation: Notice that the pattern (1,2) exists twice but not consecutively, so it doesn't count.

Example 5:
Input: arr = [2,2,2,2], m = 2, k = 3
Output: false
Explanation: The only pattern of length 2 is (2,2) however it's repeated only twice. Notice that we do not count overlapping repetitions.

 
Constraints:

2 <= arr.length <= 100
1 <= arr[i] <= 100
1 <= m <= 100
2 <= k <= 100

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is Python program to find a pattern of length m that is repeated k or more times.

class Solution:
    def containsPattern(self, arr: List[int], m: int, k: int) -> bool:
        for i in range(0, len(arr)-(k-1)*m-m+1):
            found = True
            for j in range(0, m):
                for n in range(1, k):
                    #print(i, j, n, i+j, m*n + i+j)
                    if arr[i+j] != arr[m*n + i+j]:
                        found = False
            if found:
                return True
        return False