human
Reduce array to longest sorted array possible by removing either half of given array in each operation | Function to check if the subarray arr [ i . . j ] is a sorted subarray or not.
Traverse all elements of the subarray arr [ i ... j ].
If the previous element of the subarray exceeds current element.
Return 0.
Return 1.
Recursively partition the array into two equal halves.
If atmost one element is left in the subarray arr [ i . . j ].
Checks if subarray arr [ i . . j ] is a sorted subarray or not.
If the subarray arr [ i ... j ] is a sorted subarray.
Stores middle element of the subarray arr [ i . . j ].
Recursively partition the current subarray arr [ i . . j ] into equal halves.
Driver Code"
Solution in Python:
 ... Write me a code to reduce array to longest sorted array possible by removing either half of given array in each operation and the other steps required?
assistant
#Here is code to reduce array to longest sorted array possible by removing either half of given array in each operation and the other steps required.
 def isSortedparitions ( arr , i , j ) :
	for k in range ( i + 1 , j + 1 ) :
		if ( arr [ k ] < arr [ k - 1 ] ) :
			return 0
	return 1
def partitionsArr ( arr , i , j ) :
	if ( i >= j ) :
		return 1
	flag = int ( isSortedparitions ( arr , i , j ) )
	if ( flag != 0 ) :
		return ( j - i + 1 )
	mid = ( i + j ) // 2
	X = partitionsArr ( arr , i , mid ) ;
	Y = partitionsArr ( arr , mid + 1 , j )
	return max ( X , Y )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 11 , 12 , 1 , 2 , 13 , 14 , 3 , 4 ]
	N = len ( arr )
	print ( partitionsArr ( arr , 0 , N - 1 ) )