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Minimum Cost required to generate a balanced Bracket Sequence | Function to calculate the minimum cost required to generate a balanced bracket sequence.
Stores the count of unbalanced open brackets.
Stores the count of unbalanced closed brackets.
Stores the count of open brackets.
Stores the count of closed brackets.
If open brace is encountered.
Otherwise.
If no unbalanced open brackets are present.
Increase count of unbalanced closed brackets.
Otherwise.
Reduce count of unbalanced open brackets.
Increase count of closed brackets.
Calculate lower bound of minimum cost.
Reduce excess open or closed brackets to prevent counting them twice.
Update answer by adding minimum of removing both unbalanced open and closed brackets or inserting closed unbalanced brackets to end of String.
Prthe result.
Driver Code"
Solution in Python:

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Give me a code to minimum Cost required to generate a balanced Bracket Sequence and the other steps required?
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#Here is code to minimum Cost required to generate a balanced Bracket Sequence and the other steps required.
 def minCost ( str , a , b ) :
	openUnbalanced = 0 ;
	closedUnbalanced = 0 ;
	openCount = 0 ;
	closedCount = 0 ;
	for i in range ( len ( str ) ) :
		if ( str [ i ] == ' ( ' ) :
			openUnbalanced += 1 ;
			openCount += 1 ;
		else :
			if ( openUnbalanced == 0 ) :
				closedUnbalanced += 1 ;
			else :
				openUnbalanced -= 1 ;
			closedCount += 1 ;
	result = a * ( abs ( openCount - closedCount ) ) ;
	if ( closedCount > openCount ) :
		closedUnbalanced -= ( closedCount - openCount ) ;
	if ( openCount > closedCount ) :
		openUnbalanced -= ( openCount - closedCount ) ;
	result += min ( a * ( openUnbalanced + closedUnbalanced ) , b * closedUnbalanced ) ;
	print ( result ) ;
if __name__ == ' _ _ main _ _ ' : str = " ) ) ( ) ( ( ) ( ) ( " ;
	A = 1 ; B = 3 ;
	minCost ( str , A , B ) ;