human
Can you provide a code to count the number of ordered sets not containing consecutive numbers and the other steps required given the following:
Count the number of ordered sets not containing consecutive numbers | Function to calculate the count of ordered set for a given size.
Base cases.
Function returns the count of all ordered sets.
Prestore the factorial value.
Iterate all ordered set sizes and find the count for each one maximum ordered set size will be smaller than N as all elements are distinct and non consecutive.
Multiply ny size ! for all the arrangements because sets are ordered.
Add to total answer.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count the number of ordered sets not containing consecutive numbers and the other steps required.
 def CountSets ( x , pos ) :
	if ( x <= 0 ) :
		if ( pos == 0 ) :
			return 1
		else :
			return 0
	if ( pos == 0 ) :
		return 1
	answer = ( CountSets ( x - 1 , pos ) + CountSets ( x - 2 , pos - 1 ) )
	return answer
def CountOrderedSets ( n ) :
	factorial = [ 1 for i in range ( 10000 ) ]
	factorial [ 0 ] = 1
	for i in range ( 1 , 10000 , 1 ) :
		factorial [ i ] = factorial [ i - 1 ] * i
	answer = 0
	for i in range ( 1 , n + 1 , 1 ) :
		sets = CountSets ( n , i ) * factorial [ i ]
		answer = answer + sets
	return answer
if __name__ == ' _ _ main _ _ ' :
	N = 3
	print ( CountOrderedSets ( N ) )