human
Minimize sum of product of same | Function to print the arrays.
Function to reverse the subarray.
Function to calculate the minimum product of same - indexed elements of two given arrays.
Calculate initial product.
Traverse all odd length subarrays.
Remove the previous product.
Add the current product.
Check if current product is minimum or not.
Traverse all even length subarrays.
Remove the previous product.
Add to the current product.
Check if current product is minimum or not.
Update the pointers.
Reverse the subarray.
Print the subarray.
Driver Code"
How can the above be solved in Python?
 ... Give me a code to minimize sum of product of same and the other steps required?
assistant
#Here is code to minimize sum of product of same and the other steps required.
 def Print ( a , b ) :
	minProd = 0
	for i in range ( len ( a ) ) :
		print ( a [ i ] , end = " ▁ " )
	print ( ) ;
	for i in range ( len ( b ) ) :
		print ( b [ i ] , end = " ▁ " )
		minProd += a [ i ] * b [ i ]
	print ( )
	print ( minProd )
def reverse ( left , right , arr ) :
	while ( left < right ) :
		temp = arr [ left ]
		arr [ left ] = arr [ right ]
		arr [ right ] = temp
		left += 1
		right -= 1
def minimumProdArray ( a , b , l ) :
	total = 0
	for i in range ( len ( a ) ) :
		total += a [ i ] * b [ i ]
	Min = 2147483647
	first = 0 ;
	second = 0 ;
	for i in range ( len ( a ) ) :
		left = i - 1 ;
		right = i + 1 ;
		total1 = total ;
		while ( left >= 0 and right < len ( a ) ) :
			total1 -= a [ left ] * b [ left ] + a [ right ] * b [ right ] ;
			total1 += a [ left ] * b [ right ] + a [ right ] * b [ left ] ;
			if ( Min >= total1 ) :
				Min = total1
				first = left
				second = right
			left -= 1
			right += 1
	for i in range ( len ( a ) ) :
		left = i
		right = i + 1
		total1 = total
		while ( left >= 0 and right < len ( a ) ) :
			total1 -= a [ left ] * b [ left ] + a [ right ] * b [ right ]
			total1 += a [ left ] * b [ right ] + a [ right ] * b [ left ]
			if ( Min >= total1 ) :
				Min = total1
				first = left
				second = right
			left -= 1
			right += 1
	if ( Min < total ) :
		reverse ( first , second , a )
		Print ( a , b )
	else :
		Print ( a , b )
n = 4 ;
a = [ 2 , 3 , 1 , 5 ]
b = [ 8 , 2 , 4 , 3 ]
minimumProdArray ( a , b , n )