human
Koko Eating Bananas | Python implementation for the above approach.
to get the ceil value.
in case of odd number.
in case of even number.
check if time is less than or equals to given hour.
as minimum speed of eating must be 1.
Maximum speed of eating is the maximum bananas in given piles.
Check if the mid ( hours ) is valid.
If valid continue to search lower speed.
If cant finish bananas in given hours , then increase the speed.
Driver code"
How can the above be solved in Python?
 What is a code to koko Eating Bananas and the other steps required?
assistant
#Here is code to koko Eating Bananas and the other steps required.
 def check ( bananas , mid_val , H ) :
	time = 0 ;
	for i in range ( len ( bananas ) ) :
		if ( bananas [ i ] % mid_val != 0 ) :
		time += bananas [ i ] // mid_val + 1 ;
		else :
		time += bananas [ i ] // mid_val
	if ( time <= H ) :
		return True ;
	else :
		return False ;
def minEatingSpeed ( piles , H ) :
	start = 1 ;
	end = sorted ( piles . copy ( ) , reverse = True ) [ 0 ]
	while ( start < end ) :
		mid = start + ( end - start ) // 2 ;
		if ( check ( piles , mid , H ) == True ) :
		end = mid ;
		else :
		start = mid + 1 ;
	return end ;
piles = [ 30 , 11 , 23 , 4 , 20 ] ;
H = 6 ;
print ( minEatingSpeed ( piles , H ) ) ;