human
Can you provide a code to count triplets such that product of two numbers added with third number is N and the other steps required given the following:
Count triplets such that product of two numbers added with third number is N | Python program for the above approach.
function to find the divisors of the number ( N - i ).
Stores the resultant count of divisors of ( N - i ).
Iterate over range [ 1 , sqrt ( N ) ].
Return the total divisors.
def to find the number of triplets such that A * B - C = N.
Loop to fix the value of C.
Adding the number of divisors in count.
Return count of triplets.
Driver Code Driver Code"
Solution in Python:
assistant
#Here is code to count triplets such that product of two numbers added with third number is N and the other steps required.
 import math
def countDivisors ( n ) :
	divisors = 0
	for i in range ( 1 , math . ceil ( math . sqrt ( n ) ) + 1 ) :
		if n % i == 0 :
			divisors = divisors + 1
		if ( i - ( n / i ) == 1 ) :
			i = i - 1
	for i in range ( math . ceil ( math . sqrt ( n ) ) + 1 , 1 , - 1 ) :
		if ( n % i == 0 ) :
			divisors = divisors + 1
	return divisors
def possibleTriplets ( N ) :
	count = 0
	for i in range ( 1 , N ) :
		count = count + countDivisors ( N - i )
	return count
if __name__ == " _ _ main _ _ " :
	N = 10
	print ( possibleTriplets ( N ) )