human
Total number of non | python program to count non - decreasing numner with n digits.
Compute value of N * ( N + 1 ) / 2 * ( N + 2 ) / 3 * ... . * ( N + n - 1 ) / n.
Driver program"
How can the above be solved in Python?
 Can you provide a code to total number of non and the other steps required?
assistant
#Here is code to total number of non and the other steps required.
 def countNonDecreasing ( n ) :
	N = 10
	count = 1
	for i in range ( 1 , n + 1 ) :
		count = int ( count * ( N + i - 1 ) )
		count = int ( count / i )
	return count
n = 3 ;
print ( countNonDecreasing ( n ) )