human
Maximize the decimal equivalent by flipping only a contiguous set of 0 s | Function to print the binary number.
Check if the current number is 0.
Find the continuous 0 s.
Replace initially occurring 0 with 1.
return the string and break the loop.
Driver code"
Solution in Python:

Write me a code to maximize the decimal equivalent by flipping only a contiguous set of 0 s and the other steps required?
assistant
#Here is code to maximize the decimal equivalent by flipping only a contiguous set of 0 s and the other steps required.
 def flip ( s ) :
	s = list ( s )
	for i in range ( len ( s ) ) :
		if ( s [ i ] == '0' ) :
			while ( s [ i ] == '0' ) :
				s [ i ] = '1'
				i += 1
			s = ' ' . join ( map ( str , s ) )
			return s
s = "100010001"
print ( flip ( s ) )