human
Queries to find minimum swaps required to sort given array with updates | Function to return the position of the given value using binary search.
Return 0 if every value is greater than the given value.
Return N - 1 if every value is smaller than the given value.
Perform Binary Search.
Iterate till start < end.
Find the mid.
Update start and end.
Return the position of the given value.
Function to return the number of make the array sorted.
Index x to update.
Increment value by y.
Set newElement equals to x + y.
Compute the new index.
Print the minimum number of swaps.
Driver Code.
Given array arr [ ].
Given Queries.
Function Call"
How can the above be solved in Python?

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Give me a code to queries to find minimum swaps required to sort given array with updates and the other steps required?
assistant
#Here is code to queries to find minimum swaps required to sort given array with updates and the other steps required.
 def computePos ( arr , n , value ) :
	if ( value < arr [ 0 ] ) :
		return 0
	if ( value > arr [ n - 1 ] ) :
		return n - 1
	start = 0
	end = n - 1
	while ( start < end ) :
		mid = ( start + end + 1 ) // 2
		if ( arr [ mid ] >= value ) :
			end = mid - 1
		else :
			start = mid
	return start
def countShift ( arr , n , queries ) :
	for q in queries :
		index = q [ 0 ]
		update = q [ 1 ]
		newElement = arr [ index ] + update
		newIndex = computePos ( arr , n , newElement )
		print ( abs ( newIndex - index ) , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 3 , 4 , 5 , 6 ]
	N = len ( arr )
	queries = [ [ 0 , - 1 ] , [ 4 , - 11 ] ]
	countShift ( arr , N , queries )