human
I found an interesting problem on https://www.codewars.com/kata/55aa075506463dac6600010d:
Divisors of 42 are : 1, 2, 3, 6, 7, 14, 21, 42.
These divisors squared are: 1, 4, 9, 36, 49, 196, 441, 1764.
The sum of the squared divisors is 2500 which is 50 * 50, a square!

Given two integers m, n (1 <= m <= n) we want to find all integers 
between m and n whose sum of squared divisors is itself a square.
42 is such a number.

The result will be an array of arrays or of tuples (in C an array of Pair) or a string, each subarray having two elements,
first the number whose squared divisors is a square and then the sum
of the squared divisors.

#Examples:
```
list_squared(1, 250) --> [[1, 1], [42, 2500], [246, 84100]]
list_squared(42, 250) --> [[42, 2500], [246, 84100]]
```

The form of the examples may change according to the language, see `Example Tests:` for more details.

**Note**

In Fortran - as in any other language - the returned string is not permitted to contain any redundant trailing whitespace: you can use dynamically allocated character strings.

I tried it in Python, but could not do it. Can you solve it?

=====
Give me a Python code to find all integers?
assistant
#Here is Python code to find all integers 
.

import math

def store_diviors_squared_sum(func):
    store = {}
    def helper(integer):
        if integer not in store:
            store[integer] = func(integer)
        return store[integer]
    return helper

@store_diviors_squared_sum
def divisors_squared_sum(integer):
    squared_divisors_sum = 1
    for number in range(2, integer+1):
        if integer % number == 0: squared_divisors_sum += number**2
    return squared_divisors_sum

def list_squared(m, n):
    return_array = []
    for integer in range(m, n+1):
        squared_divisors_sum = divisors_squared_sum(integer)
        if math.sqrt(squared_divisors_sum) % 1 == 0:
            return_array.append([integer, squared_divisors_sum])
    return return_array