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Minimum cost to generate any permutation of the given string | Function to find the minimum cost to form any permutation of string s.
Base Case.
Return the precomputed state.
Iterate over the string and check all possible characters available for current position.
Check if character can be placed at current position.
As there is no previous character so the cost for 1 st character is 0.
Find the cost of current character and move to next position.
Store the answer for each current state.
Function that returns True if the current bit is set.
Function that generates any permutation of the given string with minimum cost.
Initialize dp table.
Set all the bits of the current character id.
Minimum cost of generating the permutation.
Driver Code.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to minimum cost to generate any permutation of the given string and the other steps required.
 def solve ( a , s , n , prev , mask , dp ) :
	if ( mask == 0 ) :
		return 0 ;
	if ( dp [ mask ] [ prev + 1 ] != - 1 ) :
		return dp [ mask ] [ prev + 1 ] ;
	ans = 10000 ;
	for i in range ( len ( s ) ) :
		id = ord ( s [ i ] ) - ord ( ' a ' ) ;
		if ( check ( mask , id ) ) :
			if ( prev == - 1 ) :
				ans = min ( ans , solve ( a , s , n , id , mask ^ ( 1 << id ) , dp ) ) ;
			else :
				ans = min ( ans , a [ prev ] [ id ] + solve ( a , s , n , id , mask ^ ( 1 << id ) , dp ) ) ;
	dp [ mask ] [ prev + 1 ] = ans ;
	return ans ;
def check ( mask , i ) :
	c = ( mask & ( 1 << i ) ) ;
	return c != 0 ;
def generatePermutation ( mask , n , a , s ) :
	dp = [ [ - 1 for i in range ( n + 5 ) ] for j in range ( ( 1 << n ) + 5 ) ]
	for i in range ( len ( s ) ) :
		id = ord ( s [ i ] ) - ord ( ' a ' ) ;
		mask |= ( 1 << id ) ;
	print ( solve ( a , s , n , - 1 , mask , dp ) ) ;
if __name__ == ' _ _ main _ _ ' :
	N = 5 ;
	str = " abcde " ;
	mat = [ [ 0 , 5 , 1 , 5 , 3 ] , [ 4 , 0 , 9 , 4 , 2 ] , [ 7 , 9 , 0 , 10 , 7 ] , [ 1 , 2 , 8 , 0 , 2 ] , [ 3 , 9 , 7 , 7 , 0 ] ] ;
	generatePermutation ( 0 , N , mat , str ) ;