human
Minimum number of changes such that elements are first Negative and then Positive | Function to return the count of minimum operations required.
To store the count of negative integers on the right of the current index ( inclusive ).
Find the count of negative integers on the right.
If current element is negative.
To store the count of positive elements.
Find the positive integers on the left.
If current element is positive.
Update the answer.
Return the required answer.
Driver code"
How can the above be solved in Python?

What is a code to minimum number of changes such that elements are first Negative and then Positive and the other steps required?
assistant
#Here is code to minimum number of changes such that elements are first Negative and then Positive and the other steps required.
 def Minimum_Operations ( a , n ) :
	np = [ 0 for i in range ( n + 1 ) ]
	for i in range ( n - 1 , - 1 , - 1 ) :
		np [ i ] = np [ i + 1 ]
		if ( a [ i ] <= 0 ) :
			np [ i ] += 1
	pos = 0
	ans = n
	for i in range ( n - 1 ) :
		if ( a [ i ] >= 0 ) :
			pos += 1
		ans = min ( ans , pos + np [ i + 1 ] )
	return ans
a = [ - 1 , 0 , 1 , 2 ]
n = len ( a )
print ( Minimum_Operations ( a , n ) )