human
Can you provide a code to count number of triangles possible for the given sides range and the other steps required given the following:
Count number of triangles possible for the given sides range | Function to count the number of possible triangles for the given sides ranges.
Iterate for every possible of x.
Range of y is [ b , c ] From this range First we will find the number of x + y greater than d.
For x + y greater than d we can choose all z from [ c , d ] Total permutation will be.
Now we will find the number of x + y in between the [ c , d ].
[ l , r ] will be the range from total [ c , d ] x + y belongs For any r such that r = x + y We can choose z , in the range [ c , d ] only less than r , Thus total permutation be.
Driver Code"
Solution in Python:
assistant
#Here is code to count number of triangles possible for the given sides range and the other steps required.
 def count_triangles ( a , b , c , d ) :
	ans = 0
	for x in range ( a , b + 1 ) :
		num_greater_than_d = ( max ( d , c + x ) - max ( d , b + x - 1 ) )
		ans = ( ans + num_greater_than_d * ( d - c + 1 ) )
		r = min ( max ( c , c + x ) , d ) - c ;
		l = min ( max ( c , b + x - 1 ) , d ) - c ;
		x1 = int ( ( r * ( r + 1 ) ) / 2 )
		x2 = int ( ( l * ( l + 1 ) ) / 2 )
		ans = ans + ( x1 - x2 )
	return ans
a = 2
b = 3
c = 4
d = 5
print ( count_triangles ( a , b , c , d ) , end =   ' ' )