human
Solve the following python programming problem given the following code:
def FormattedTable(self, width = 80, force_display = False, ml_delimiter = True, color = True, display_header = True, columns = None) : 
    "Returns whole table, with whitespace padding and row delimiters.

    Args:
      width: An int, the max width we want the table to fit in.
      force_display: A bool, if set to True will display table when the table
          can't be made to fit to the width.
      ml_delimiter: A bool, if set to False will not display the multi-line
          delimiter.
      color: A bool. If true, display any colours in row.colour.
      display_header: A bool. If true, display header.
      columns: A list of str, show only columns with these names.

    Returns:
      A string.  The tabled output.

    Raises:
      TableError: Width too narrow to display table.
    " 
    def _FilteredCols() : 
        'Returns list of column names to display.' 
        if (not columns) : 
            return self._Header ().values 
return [col for col in self._Header ().values if (col in columns)] 
largest = { 
        
} 
    smallest = { 
        
} 
    for key in _FilteredCols () : 
        largest [key] = 0 
        smallest [key] = 0 
for row in self._table : 
        for (key, value) in row.items () : 
            if (key not in _FilteredCols ()) : 
                continue 
if isinstance (value, list) : 
                value = ', '.join (value) 
value = terminal.StripAnsiText (value) 
            largest [key] = max (len (value), largest [key]) 
            smallest [key] = max (self._SmallestColSize (value), smallest [key]) 
min_total_width = 0 
    multi_word = [] 
    for key in _FilteredCols () : 
        largest [key] += 2 
        smallest [key] += 2 
        min_total_width += smallest [key] 
        if (largest [key] != smallest [key]) : 
            multi_word.append (key) 
if ((min_total_width > width) and (not force_display)) : 
        raise TableError ('Width too narrow to display table.') 
if multi_word : 
        desired_width = 0 
        spare_width = (width -...

    
    

    Fix the buggy line: header_list.append (result_dict [row_idx] [row_idx])
assistant
#Here is Python code to fix the buggy line: header_list.

header_list.append (result_dict [key] [row_idx])