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Maximum set bit sum in array without considering adjacent elements | Function to count total number of set bits in an integer.
Maximum sum of set bits.
Calculate total number of set bits for every element of the array.
find total set bits for each number and store back into the array.
current max excluding i.
current max including i.
return max of incl and excl.
Driver code"
Solution in Python:

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What is a code to maximum set bit sum in array without considering adjacent elements and the other steps required?
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#Here is code to maximum set bit sum in array without considering adjacent elements and the other steps required.
 def bit ( n ) :
	count = 0
	while ( n ) :
		count += 1
		n = n & ( n - 1 )
	return count
def maxSumOfBits ( arr , n ) :
	for i in range ( n ) :
		arr [ i ] = bit ( arr [ i ] )
	incl = arr [ 0 ]
	excl = 0
	for i in range ( 1 , n ) :
		if incl > excl :
			excl_new = incl
		else :
			excl_new = excl
		incl = excl + arr [ i ] ;
		excl = excl_new
	if incl > excl :
		return incl
	else :
		return excl
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 4 , 5 , 6 , 7 , 20 , 25 ]
	n = len ( arr )
	print ( maxSumOfBits ( arr , n ) )