human
Reverse a subarray of the given array to minimize the sum of elements at even position | Function that will give the max negative value.
Check for count greater than 0 as we require only negative solution.
Function to print the minimum sum.
Taking sum of only even index elements.
Initialize two vectors v1 , v2.
v1 will keep account for change if 1 th index element goes to 0.
v2 will keep account for change if 1 th index element goes to 2.
Get the max negative value.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to reverse a subarray of the given array to minimize the sum of elements at even position and the other steps required.
 def after_rev ( v ) :
	mini = 0
	count = 0
	for i in range ( len ( v ) ) :
		count += v [ i ]
		if ( count > 0 ) :
			count = 0
		if ( mini > count ) :
			mini = count
	return mini
def print_f ( arr ) :
	sum = 0
	for i in range ( 0 , len ( arr ) , 2 ) :
		sum += arr [ i ]
	v1 , v2 = [ ] , [ ]
	i = 1
	while i + 1 < len ( arr ) :
		v1 . append ( arr [ i + 1 ] - arr [ i ] )
		i += 2
	i = 1
	while i + 1 < len ( arr ) :
		v2 . append ( arr [ i ] - arr [ i + 1 ] )
		i += 2
	change = min ( after_rev ( v1 ) , after_rev ( v2 ) )
	if ( change < 0 ) :
		sum += change
	print ( sum )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 0 , 1 , 4 , 3 ]
	print_f ( arr )