human
Can you provide a the Python code you requested given the following:
Solve in Python:
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:

Input: intervals = [[1,3],[6,9]], newInterval = [2,5]
Output: [[1,5],[6,9]]

Example 2:

Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]
Output: [[1,2],[3,10],[12,16]]
Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].
assistant
#Here is the Python code you requested.

# Definition for an interval.
 # class Interval:
 #     def __init__(self, s=0, e=0):
 #         self.start = s
 #         self.end = e
 
 class Solution:
     def insert(self, intervals, newInterval):
         """
         :type intervals: List[Interval]
         :type newInterval: Interval
         :rtype: List[Interval]
         """
         if not intervals:
             return [newInterval]
         v = []
         a =newInterval.start
         b =newInterval.end
         flag =0
         s=a
         e=b
         for i in intervals:
             if i.start<=a<=i.end:
                 s = i.start
             if i.start<=b<=i.end:
                 e = i.end
                 v.append(Interval(s,e))
                 flag =1
             if not flag and i.start >b:
                 v.append(Interval(s,e))
                 flag =1
             if i.end<a or i.start>b:
                 v.append(i)
         if not flag:
             v.append(Interval(s,e))
         return v