human
Count numbers from 1 to n that have 4 as a digit | Returns sum of all digits in numbers from 1 to n.
One by one compute sum of digits in every number from 1 to n.
A utility function to compute sum of digits in a given number x.
Driver Program"
How can the above be solved in Python?

=====
Give me a code to count numbers from 1 to n that have 4 as a digit and the other steps required?
assistant
#Here is code to count numbers from 1 to n that have 4 as a digit and the other steps required.
 def countNumbersWith4 ( n ) :
	for x in range ( 1 , n + 1 ) :
		if ( has4 ( x ) == True ) :
			result = result + 1
	return result
def has4 ( x ) :
	while ( x != 0 ) :
		if ( x % 10 == 4 ) :
			return True
		x = x // 10
	return False
n = 328
print ( " Count ▁ of ▁ numbers ▁ from ▁ 1 ▁ to ▁ " , n , " ▁ that ▁ have ▁ 4 ▁ as ▁ a ▁ a ▁ digit ▁ is ▁ " , countNumbersWith4 ( n ) )