human
Longest Common Subsequence ( LCS ) by repeatedly swapping characters of a string with characters of another string | Function to find the length of LCS possible by swapping any character of a with that of another string.
Store the size of the strings.
Stores frequency of characters.
Iterate over characters of the A.
Update frequency of character A [ i ].
Iterate over characters of the B.
Update frequency of character B [ i ].
Store the count of all pairs of similar characters.
Traverse the array freq [ ].
Update cnt.
Print the minimum of cnt , N and M.
Driver Code.
Given strings"
How can the above be solved in Python?

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Give me a code to longest Common Subsequence ( LCS ) by repeatedly swapping characters of a string with characters of another string and the other steps required?
assistant
#Here is code to longest Common Subsequence ( LCS ) by repeatedly swapping characters of a string with characters of another string and the other steps required.
 def lcsBySwapping ( A , B ) :
	N = len ( A )
	M = len ( B )
	freq = [ 0 ] * 26
	for i in range ( len ( A ) ) :
		freq [ ord ( A [ i ] ) - ord ( ' a ' ) ] += 1
	for i in range ( len ( B ) ) :
		freq [ ord ( B [ i ] ) - ord ( ' a ' ) ] += 1
	cnt = 0
	for i in range ( 26 ) :
		cnt += freq [ i ] // 2
	print ( min ( cnt , min ( N , M ) ) )
if __name__ == ' _ _ main _ _ ' :
	A = " abdeff "
	B = " abbet "
	lcsBySwapping ( A , B )