human
What is a code to check given string is oddly palindrome or not and the other steps required given the following:
Check given string is oddly palindrome or not | Set 2 | Function to check if string formed by odd indices is palindromic or not.
Check if length of OddString odd , to consider edge case.
Push odd index character of first half of str in stack.
Middle element of odd length palindromic string is not compared.
If stack is empty then return true.
Driver code.
Given string"
How can the above be solved in Python?
assistant
#Here is code to check given string is oddly palindrome or not and the other steps required.
 def isOddStringPalindrome ( str , n ) :
	oddStringSize = n // 2 ;
	lengthOdd = True if ( oddStringSize % 2 == 1 ) else False
	s = [ ]
	i = 1
	c = 0
	while ( i < n and c < oddStringSize // 2 ) :
		s . append ( str [ i ] )
		i += 2
		c += 1
	if ( lengthOdd ) :
		i = i + 2
	while ( i < n and len ( s ) > 0 ) :
		if ( s [ len ( s ) - 1 ] == str [ i ] ) :
			s . pop ( )
		else :
			break
		i = i + 2
	if ( len ( s ) == 0 ) :
		return True
	return False ;
if __name__ == " _ _ main _ _ " :
	N = 10
	s = " aeafacafae "
	if ( isOddStringPalindrome ( s , N ) ) :
		print ( " Yes " )
	else :
		print ( " No " )