human
Count of subarrays with largest element at least twice the largest of remaining elements | Function to find count of subarrays which have max element greater than twice maximum of all other elements.
Stores the count of subarrays.
Generate all possible subarrays.
Stores the maximum element of the subarray.
Stores the maximum of all other elements.
Find the maximum element in the subarray [ i , j ].
Find the maximum of all other elements.
If the maximum of subarray is greater than twice the maximum of other elements.
Print the maximum value obtained.
Driver Code"
How can the above be solved in Python?

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What is a code to count of subarrays with largest element at least twice the largest of remaining elements and the other steps required?
assistant
#Here is code to count of subarrays with largest element at least twice the largest of remaining elements and the other steps required.
 def countSubarray ( arr , n ) :
	count = 0
	for i in range ( n ) :
		for j in range ( i , n , 1 ) :
			mxSubarray = 0
			mxOther = 0
			for k in range ( i , j + 1 , 1 ) :
				mxSubarray = max ( mxSubarray , arr [ k ] )
			for k in range ( 0 , i , 1 ) :
				mxOther = max ( mxOther , arr [ k ] )
			for k in range ( j + 1 , n , 1 ) :
				mxOther = max ( mxOther , arr [ k ] )
			if ( mxSubarray > ( 2 * mxOther ) ) :
				count += 1
	print ( count )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 6 , 10 , 9 , 7 , 3 ]
	N = len ( arr )
	countSubarray ( arr , N )