human
Can you provide a code to maximum sum of pairs with specific difference and the other steps required given the following:
Maximum sum of pairs with specific difference | method to return maximum sum we can get by get by finding less than K difference pair.
Sort input array in ascending order ..
dp [ i ] denotes the maximum disjoint pair sum we can achieve using first i elements.
if no element then dp value will be 0.
first give previous value to dp [ i ] i . e . no pairing with ( i - 1 ) th element.
if current and previous element can form a pair.
update dp [ i ] by choosing maximum between pairing and not pairing.
last index will have the result.
Driver code to test above methods"
Solution in Python:
assistant
#Here is code to maximum sum of pairs with specific difference and the other steps required.
 def maxSumPairWithDifferenceLessThanK ( arr , N , K ) :
	arr . sort ( )
	dp = [ 0 ] * N
	dp [ 0 ] = 0
	for i in range ( 1 , N ) :
		dp [ i ] = dp [ i - 1 ]
		if ( arr [ i ] - arr [ i - 1 ] < K ) :
			if ( i >= 2 ) :
				dp [ i ] = max ( dp [ i ] , dp [ i - 2 ] + arr [ i ] + arr [ i - 1 ] ) ;
			else :
				dp [ i ] = max ( dp [ i ] , arr [ i ] + arr [ i - 1 ] ) ;
	return dp [ N - 1 ]
arr = [ 3 , 5 , 10 , 15 , 17 , 12 , 9 ]
N = len ( arr )
K = 4
print ( maxSumPairWithDifferenceLessThanK ( arr , N , K ) )