human
Sum of product of all unordered pairs in given range with update queries | Function to calculate the Pairwise Product Sum in range from L to R.
Loop to iterate over all possible pairs from L to R.
Print answer.
Function to update the Array element at index P to X.
Update the value at Pth index in the array.
Function to solve Q queries.
If Query is of type 1.
If Query is of type 2.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to sum of product of all unordered pairs in given range with update queries and the other steps required.
 def pairwiseProductSum ( a , l , r ) :
	sum = 0
	for j in range ( l - 1 , r , 1 ) :
		for k in range ( j + 1 , r , 1 ) :
			sum += ( a [ j ] * a [ k ] ) ;
	print ( sum )
def updateArray ( a , p , x ) :
	a [ p - 1 ] = x
def solveQueries ( a , n , Q , query ) :
	for i in range ( Q ) :
		if ( query [ i ] [ 0 ] == 1 ) :
			pairwiseProductSum ( a , query [ i ] [ 1 ] , query [ i ] [ 2 ] )
		else :
			updateArray ( a , query [ i ] [ 1 ] , query [ i ] [ 2 ] )
if __name__ == ' _ _ main _ _ ' :
	A = [ 5 , 7 , 2 , 3 , 1 ]
	N = len ( A )
	Q = 3
	query = [ [ 1 , 1 , 3 ] , [ 2 , 2 , 5 ] , [ 1 , 2 , 5 ] ]
	solveQueries ( A , N , Q , query )