human
I found an interesting problem on https://leetcode.com/problems/score-after-flipping-matrix/:
We have a two dimensional matrix A where each value is 0 or 1.
A move consists of choosing any row or column, and toggling each value in that row or column: changing all 0s to 1s, and all 1s to 0s.
After making any number of moves, every row of this matrix is interpreted as a binary number, and the score of the matrix is the sum of these numbers.
Return the highest possible score.
 


Example 1:
Input: [[0,0,1,1],[1,0,1,0],[1,1,0,0]]
Output: 39
Explanation:
Toggled to [[1,1,1,1],[1,0,0,1],[1,1,1,1]].
0b1111 + 0b1001 + 0b1111 = 15 + 9 + 15 = 39
 
Note:

1 <= A.length <= 20
1 <= A[0].length <= 20
A[i][j] is 0 or 1.

I tried it in Python, but could not do it. Can you solve it?

 ... Can you provide a the Python code you requested?
assistant
#Here is the Python code you requested.

class Solution:
    def matrixScore(self, A: List[List[int]]) -> int:
        M, N = len(A), len(A[0])
        ans = (1<<N-1)*M
        for j in range(1, N):
            count = sum(A[i][j]==A[i][0] for i in range(M))
            ans += max(count, M-count)<<N-j-1
        return ans