human
Solve in Python:
You have an initial power P, an initial score of 0 points, and a bag of tokens.
Each token can be used at most once, has a value token[i], and has potentially two ways to use it.

If we have at least token[i] power, we may play the token face up, losing token[i] power, and gaining 1 point.
If we have at least 1 point, we may play the token face down, gaining token[i] power, and losing 1 point.

Return the largest number of points we can have after playing any number of tokens.
 


Example 1:
Input: tokens = [100], P = 50
Output: 0

Example 2:
Input: tokens = [100,200], P = 150
Output: 1

Example 3:
Input: tokens = [100,200,300,400], P = 200
Output: 2

 
Note:

tokens.length <= 1000
0 <= tokens[i] < 10000
0 <= P < 10000

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Give me a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def bagOfTokensScore(self, tokens: List[int], P: int) -> int:
        if not len(tokens) :
            return 0
        tokens.sort()
        res = 0
        deque = collections.deque(tokens)
        
        while( len( deque ) > 1 and ( P >= deque[0] or res ) ):
            while( deque and P > deque[0] ):
                res += 1
                P -= deque.popleft()
            if( len( deque ) > 1 and res ):
                P += deque.pop()
                res -= 1

        if ( deque and P >= deque[0] ):
            res += 1
        return res