human
Minimum flips required in a binary string such that all K | Function to calculate and return the minimum number of flips to make string valid.
Stores the count of required flips.
Stores the last index of '1' in the string.
Check for the first substring of length K.
If i - th character is '1.
If the substring had no '1.
Increase the count of required flips.
Flip the last index of the window.
Update the last index which contains 1.
Check for remaining substrings.
If last_idx does not belong to current window make it - 1.
If the last character of the current substring is '1' , then update last_idx to i + k - 1.
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If last_idx == - 1 , then the current substring has no 1.
Increase the count of flips.
Update the last index of the current window.
Store the last index of current window as the index of last '1' in the string.
Return the number of operations.
Driver Code"
Solution in Python:
assistant
#Here is code to minimum flips required in a binary string such that all K and the other steps required.
 def minimumMoves ( S , K ) :
	N = len ( S )
	ops = 0
	last_idx = - 1
	for i in range ( K ) :
'
	if ( S [ i ] == '1' ) :
		last_idx = i
'
	if ( last_idx == - 1 ) :
		ops += 1
		S [ K - 1 ] = '1'
		last_idx = K - 1
	for i in range ( N - K + 1 ) :
		if ( last_idx < i ) :
			last_idx = - 1
		if ( S [ i + K - 1 ] == '1' ) :
			last_idx = i + K - 1
		if ( last_idx == - 1 ) :
			ops += 1
			S = S [ : i + K - 1 ] + '1' + S [ i + K : ]
			last_idx = i + K - 1
	return ops
S = "001010000"
K = 3 ;
print ( minimumMoves ( S , K ) )