human
What is a code to an in and the other steps required given the following:
An in | A utility function to reverse string str [ low . . high ].
Cycle leader algorithm to move all even positioned elements at the end ..
odd index.
even index.
keep the back - up of element at new position.
The main function to transform a string . This function mainly uses cycleLeader ( ) to transform.
Step 1 : Find the largest prefix subarray of the form 3 ^ k + 1.
Step 2 : Apply cycle leader algorithm for the largest subarrau.
Step 4.1 : Reverse the second half of first subarray.
Step 4.2 : Reverse the first half of second sub - string.
Step 4.3 Reverse the second half of first sub - string and first half of second sub - string together.
Increase the length of first subarray.
Driver Code"
Solution in Python:
assistant
#Here is code to an in and the other steps required.
 def Reverse ( string : list , low : int , high : int ) :
	while low < high :
		string [ low ] , string [ high ] = string [ high ] , string [ low ]
		low += 1
		high -= 1
def cycleLeader ( string : list , shift : int , len : int ) :
	i = 1
	while i < len :
		j = i
		item = string [ j + shift ]
		while True :
			if j & 1 :
				j = len // 2 + j // 2
			else :
				j //= 2
			string [ j + shift ] , item = item , string [ j + shift ]
			if j == i :
				break
		i *= 3
def moveNumberToSecondHalf ( string : list ) :
	k , lenFirst = 0 , 0
	lenRemaining = len ( string )
	shift = 0
	while lenRemaining :
		k = 0
		while pow ( 3 , k ) + 1 <= lenRemaining :
			k += 1
		lenFirst = pow ( 3 , k - 1 ) + 1
		lenRemaining -= lenFirst
		cycleLeader ( string , shift , lenFirst )
		Reverse ( string , shift // 2 , shift - 1 )
		Reverse ( string , shift , shift + lenFirst // 2 - 1 )
		Reverse ( string , shift // 2 , shift + lenFirst // 2 - 1 )
		shift += lenFirst
if __name__ == " _ _ main _ _ " :
	string = " a1b2c3d4e5f6g7"
	string = list ( string )
	moveNumberToSecondHalf ( string )
	print ( ' ' . join ( string ) )