human
XOR and OR of all N | Function to check if a number is Armstrong or not.
Function to find XOR of all N - digits Armstrong number.
To store the XOR and OR of all Armstrong number.
Starting N - digit Armstrong number.
Ending N - digit Armstrong number.
Iterate over starting and ending number.
To check if i is Armstrong or not.
Print the XOR and OR of all Armstrong number.
Driver Code"
How can the above be solved in Python?

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What is a code to xOR and OR of all N and the other steps required?
assistant
#Here is code to xOR and OR of all N and the other steps required.
 def isArmstrong ( x , n ) :
	sum1 = 0
	temp = x
	while temp > 0 :
		digit = temp % 10
		sum1 += digit ** n
		temp //= 10
	return sum1 == x
def CalculateXORandOR ( n ) :
	CalculateXOR = 0
	CalculateOR = 0
	start = 10 ** ( n - 1 )
	end = ( 10 ** n ) - 1
	for i in range ( start , end + 1 ) :
		if ( isArmstrong ( i , n ) ) :
			CalculateXOR = CalculateXOR ^ i
			CalculateOR = CalculateOR | i
	print ( " XOR ▁ = ▁ " , CalculateXOR )
	print ( " OR ▁ = ▁ " , CalculateOR )
if __name__ == " _ _ main _ _ " :
	n = 4 ;
	CalculateXORandOR ( n ) ;