human
Find the last remaining element after repeated removal of odd and even indexed elements alternately | Function to calculate the last remaining element from the sequence.
If dp [ n ] is already calculated.
Base Case :.
Recursive Call.
Return the value of dp [ n ].
Given N.
Stores the.
Function Call"
How can the above be solved in Python?

What is a code to find the last remaining element after repeated removal of odd and even indexed elements alternately and the other steps required?
assistant
#Here is code to find the last remaining element after repeated removal of odd and even indexed elements alternately and the other steps required.
 def lastRemaining ( n , dp ) :
	if n in dp :
		return dp [ n ]
	if n == 1 :
		return 1
	else :
		dp [ n ] = 2 * ( 1 + n // 2 - lastRemaining ( n // 2 , dp ) )
	return dp [ n ]
N = 5
dp = { }
print ( lastRemaining ( N , dp ) )