human
Generate k digit numbers with digits in strictly increasing order | number -- > Current value of number . x -- > Current digit to be considered k -- > Remaining number of digits.
Try all possible greater digits.
Generates all well ordered numbers of length k ..
Driver code"
Solution in Python:
assistant
#Here is code to generate k digit numbers with digits in strictly increasing order and the other steps required.
 def printWellOrdered ( number , x , k ) :
	if ( k == 0 ) :
		print ( number , end = " ▁ " )
		return
	for i in range ( ( x + 1 ) , 10 ) :
		printWellOrdered ( number * 10 + i , i , k - 1 )
def generateWellOrdered ( k ) :
	printWellOrdered ( 0 , 0 , k )
if __name__ == " _ _ main _ _ " :
	k = 3
	generateWellOrdered ( k )