human
Generate an array having sum of Bitwise OR of same | Function to print the resultant array.
Stores the sum of the array.
Calculate sum of the array.
If sum > K.
Not possible to construct the array.
Update K.
Stores the resultant array.
Traverse the array.
Stores the current element.
If jth bit is not set and value of 2 ^ j is less than K.
Update curr.
Update K.
Push curr into B.
If K is greater than 0.
Print the vector B.
Otherwise.
Driver Code.
Input.
Size of the array.
Given input.
Function call to print the required array"
Solution in Python:
assistant
#Here is code to generate an array having sum of Bitwise OR of same and the other steps required.
 def constructArr ( A , N , K ) :
	sum = 0
	for i in range ( N ) :
		sum += A [ i ]
	if ( sum > K ) :
		print ( - 1 )
		return
	K -= sum
	B = [ ]
	for i in range ( N ) :
		curr = A [ i ]
		j = 32
		while ( j >= 0 and K > 0 ) :
			if ( ( curr & ( 1 << j ) ) == 0 and ( 1 << j ) <= K ) :
				curr |= ( 1 << j )
				K -= ( 1 << j )
			j -= 1
		B . append ( curr )
	if ( K == 0 ) :
		for it in B :
			print ( it , end = " ▁ " )
		print ( " " , end ▁ = ▁ " " )
	else :
		print ( " - 1" )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 3 , 4 ]
	N = len ( arr )
	K = 32
	constructArr ( arr , N , K )