human
Minimum count of increment of K size subarrays required to form a given Array | Function to find the minimum number of operations required to change all the array of zeros such that every element is greater than the given array.
Declaring the difference array of size N.
Number of operations.
First update the D [ i ] value with the previous value.
The index i has to be incremented.
We have to perform ( b [ i ] - d [ i ] ) operations more.
Increment the range i to i + k by need.
Check if i + k is valid index.
Driver Code.
Function Call"
Solution in Python:

Can you provide a code to minimum count of increment of K size subarrays required to form a given Array and the other steps required?
assistant
#Here is code to minimum count of increment of K size subarrays required to form a given Array and the other steps required.
 def find_minimum_operations ( n , b , k ) :
	d = [ 0 for i in range ( n + 1 ) ]
	operations = 0
	for i in range ( n ) :
		d [ i ] += d [ i - 1 ]
		if b [ i ] > d [ i ] :
			operations += ( b [ i ] - d [ i ] )
			need = ( b [ i ] - d [ i ] )
			d [ i ] += need
			if i + k <= n :
				d [ i + k ] -= need
	return operations
if __name__ == " _ _ main _ _ " :
	n = 5
	b = [ 1 , 2 , 3 , 4 , 5 ]
	k = 2
	print ( find_minimum_operations ( n , b , k ) )