human
Maximizing the elements with a [ i + 1 ] > a [ i ] | Returns the number of positions where A ( i + 1 ) is greater than A ( i ) after rearrangement of the array.
Creating a HashMap containing char as a key and occurrences as a value.
Find the maximum frequency.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to maximizing the elements with a [ i + 1 ] > a [ i ] and the other steps required.
 def countMaxPos ( arr ) :
	n = len ( arr )
	Map = { }
	for x in arr :
		if x in Map :
			Map [ x ] += 1
		else :
			Map [ x ] = 1
	max_freq = 0
	for entry in Map :
		max_freq = max ( max_freq , Map [ entry ] )
	return n - max_freq
if __name__ == " _ _ main _ _ " :
	arr = [ 20 , 30 , 10 , 50 , 40 ]
	print ( countMaxPos ( arr ) )