human
Can you provide a code to check if 2 * K + 1 non and the other steps required given the following:
Check if 2 * K + 1 non | Function to check if the S can be obtained by ( K + 1 ) non - empty substrings whose concatenation and concatenation of the reverse of these K strings.
Stores the size of the string.
If n is less than 2 * k + 1.
Stores the first K characters.
Stores the last K characters.
Reverse the string.
If both the strings are equal.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to check if 2 * K + 1 non and the other steps required.
 def checkString ( s , k ) :
	n = len ( s )
	if ( 2 * k + 1 > n ) :
		print ( " No " )
		return
	a = s [ 0 : k ]
	b = s [ n - k : n ]
	b = b [ : : - 1 ]
	if ( a == b ) :
		print ( " Yes " )
	else :
		print ( " No " )
if __name__ == ' _ _ main _ _ ' :
	S = " qwqwq "
	K = 1
	checkString ( S , K )