human
Give me a code to median of difference of all pairs from an Array and the other steps required given the following:
Median of difference of all pairs from an Array | Function check if mid can be median index of the difference array.
Size of the array.
Total possible no of pair possible.
The index of the element in the difference of all pairs from the array.
Count the number of pairs having difference <= mid.
If the difference between end and first element is less then or equal to mid.
Checking for the no of element less than or equal to mid is greater than median or not.
Function to calculate the median of differences of all pairs from the array.
Size of the array.
Initialising the low and high.
Binary search.
Calculate mid.
If mid can be the median of the array.
Returning the median of the differences of pairs from the array.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to median of difference of all pairs from an Array and the other steps required.
 def possible ( mid , a ) :
	n = len ( a ) ;
	total = ( n * ( n - 1 ) ) // 2 ;
	need = ( total + 1 ) // 2 ;
	count = 0 ;
	start = 0 ; end = 1 ;
	while ( end < n ) :
		if ( a [ end ] - a [ start ] <= mid ) :
			end += 1 ;
		else :
			count += ( end - start - 1 ) ;
			start += 1 ;
	if ( end == n and start < end and a [ end - 1 ] - a [ start ] <= mid ) :
		t = end - start - 1 ;
		count += ( t * ( t + 1 ) // 2 ) ;
	if ( count >= need ) :
		return True ;
	else :
		return False ;
def findMedian ( a ) :
	n = len ( a ) ;
	low = 0 ; high = a [ n - 1 ] - a [ 0 ] ;
	while ( low <= high ) :
		mid = ( low + high ) // 2 ;
		if ( possible ( mid , a ) ) :
			high = mid - 1 ;
		else :
			low = mid + 1 ;
	return high + 1 ;
if __name__ == " _ _ main _ _ " :
	a = [ 1 , 7 , 5 , 2 ] ;
	a . sort ( )
	print ( findMedian ( a ) ) ;