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Modify given array to make sum of odd and even indexed elements same | Function to modify array to make sum of odd and even indexed elements equal.
Stores the count of 0 s , 1 s.
Stores sum of odd and even indexed elements respectively.
Count 0 s.
Count 1 s.
Calculate odd_sum and even_sum.
If both are equal.
Print the original array.
Otherwise.
Print all the 0 s.
For checking even or odd.
Update total count of 1 s.
Print all 1 s.
Given array arr [ ].
Function call"
How can the above be solved in Python?

Give me a code to modify given array to make sum of odd and even indexed elements same and the other steps required?
assistant
#Here is code to modify given array to make sum of odd and even indexed elements same and the other steps required.
 def makeArraySumEqual ( a , N ) :
	count_0 = 0
	count_1 = 0
	odd_sum = 0
	even_sum = 0
	for i in range ( N ) :
		if ( a [ i ] == 0 ) :
			count_0 += 1
		else :
			count_1 += 1
		if ( ( i + 1 ) % 2 == 0 ) :
			even_sum += a [ i ]
		elif ( ( i + 1 ) % 2 > 0 ) :
			odd_sum += a [ i ]
	if ( odd_sum == even_sum ) :
		for i in range ( N ) :
			print ( a [ i ] , end = " ▁ " )
	else :
		if ( count_0 >= N / 2 ) :
			for i in range ( count_0 ) :
				print ( "0" , end = " ▁ " )
		else :
			is_Odd = count_1 % 2
			count_1 -= is_Odd
			for i in range ( count_1 ) :
				print ( "1" , end = " ▁ " )
arr = [ 1 , 1 , 1 , 0 ]
N = len ( arr )
makeArraySumEqual ( arr , N )