human
Count of N digit Numbers whose sum of every K consecutive digits is equal | Set 2 | Function to count the number of N - digit numbers such that sum of every K consecutive digits are equal.
Print the answer.
Driver Code"
How can the above be solved in Python?

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Write me a code to count of N digit Numbers whose sum of every K consecutive digits is equal and the other steps required?
assistant
#Here is code to count of N digit Numbers whose sum of every K consecutive digits is equal and the other steps required.
 def count ( n , k ) :
	count = ( pow ( 10 , k ) - pow ( 10 , k - 1 ) ) ;
	print ( count ) ;
if __name__ == ' _ _ main _ _ ' :
	n = 2 ;
	k = 1 ;
	count ( n , k ) ;