human
Delete an element from array ( Using two traversals and one traversal ) | This function removes an element x from arr [ ] and returns new size after removal . Returned size is n - 1 when element is present . Otherwise 0 is returned to indicate failure ..
If x is last element , nothing to do.
Start from rightmost element and keep moving elements one position ahead ..
If element was not found.
Else move the next element in place of x.
Driver code.
Delete x from arr [ ]"
How can the above be solved in Python?
assistant
#Here is code to delete an element from array ( Using two traversals and one traversal ) and the other steps required.
 def deleteElement ( arr , n , x ) :
	if arr [ n - 1 ] == x :
		return n - 1
	prev = arr [ n - 1 ]
	for i in range ( n - 2 , 1 , - 1 ) :
		if arr [ i ] != x :
			curr = arr [ i ]
			arr [ i ] = prev
			prev = curr
	if i < 0 :
		return 0
	arr [ i ] = prev
	return n - 1
arr = [ 11 , 15 , 6 , 8 , 9 , 10 ]
n = len ( arr )
x = 6
n = deleteElement ( arr , n , x )
print ( " Modified ▁ array ▁ is " )
for i in range ( n ) :
	print ( arr [ i ] , end = " ▁ " )