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Count subarrays having even Bitwise XOR | Function to count subarrays having even Bitwise XOR.
Store the required result.
Stores count of subarrays with even and odd XOR values.
Stores Bitwise XOR of current subarray.
Traverse the array.
Update current Xor.
If XOR is even.
Update ans.
Increment count of subarrays with even XOR.
Otherwise , increment count of subarrays with odd XOR.
Print the result.
Given array.
Stores the size of the array"
How can the above be solved in Python?

What is a code to count subarrays having even Bitwise XOR and the other steps required?
assistant
#Here is code to count subarrays having even Bitwise XOR and the other steps required.
 def evenXorSubarray ( arr , n ) :
	ans = 0
	freq = [ 0 ] * n
	XOR = 0
	for i in range ( n ) :
		XOR = XOR ^ arr [ i ]
		if ( XOR % 2 == 0 ) :
			ans += freq [ 0 ] + 1
			freq [ 0 ] += 1
		else :
			ans += freq [ 1 ]
			freq [ 1 ] += 1
	print ( ans )
arr = [ 1 , 2 , 3 , 4 ]
N = len ( arr )
evenXorSubarray ( arr , N )