human
Minimize bits to be flipped in X and Y such that their Bitwise OR is equal to Z | This function returns minimum number of bits to be flipped in X and Y to make X | Y = Z.
If current bit in Z is set and is also set in either of X or Y or both.
If current bit in Z is set and is unset in both X and Y.
Set that bit in either X or Y.
If current bit in Z is unset and is set in both X and Y.
Unset the bit in both X and Y.
If current bit in Z is unset and is set in either X or Y.
Unset that set bit.
Driver Code"
How can the above be solved in Python?
 Write me a code to minimize bits to be flipped in X and Y such that their Bitwise OR is equal to Z and the other steps required?
assistant
#Here is code to minimize bits to be flipped in X and Y such that their Bitwise OR is equal to Z and the other steps required.
 def minimumFlips ( X , Y , Z ) :
	res = 0
	while ( X > 0 or Y > 0 or Z > 0 ) :
		if ( ( ( X & 1 ) or ( Y & 1 ) ) and ( Z & 1 ) ) :
			X = X >> 1
			Y = Y >> 1
			Z = Z >> 1
			continue
		elif ( not ( X & 1 ) and not ( Y & 1 ) and ( Z & 1 ) ) :
			res += 1
		elif ( ( X & 1 ) or ( Y & 1 ) == 1 ) :
			if ( ( X & 1 ) and ( Y & 1 ) and not ( Z & 1 ) ) :
				res += 2
			elif ( ( ( X & 1 ) or ( Y & 1 ) ) and not ( Z & 1 ) ) :
				res += 1
		X = X >> 1
		Y = Y >> 1
		Z = Z >> 1
	return res
if __name__ == " _ _ main _ _ " :
	X = 5
	Y = 8
	Z = 6
	print ( minimumFlips ( X , Y , Z ) )