human
Make all the elements of array odd by incrementing odd | Function to count minimum subarrays whose odd - indexed elements need to be incremented to make array odd.
Stores the minimum number of operations required.
Iterate over even - indices.
Check if the current element is odd.
If true , continue.
Otherwise , mark the starting of the subarray and iterate until i < n and arr [ i ] is even.
Increment number of operations.
Iterate over odd indexed positions of arr [ ].
Check if the current element is odd.
If true , continue.
Otherwise , mark the starting of the subarray and iterate until i < n and arr [ i ] is even.
Increment the number of operations.
Print the number of operations.
Driver Code.
Function Call"
Solution in Python:

Give me a code to make all the elements of array odd by incrementing odd and the other steps required?
assistant
#Here is code to make all the elements of array odd by incrementing odd and the other steps required.
 def minOperations ( arr , n ) :
	flips = 0 ;
	i = 0 ;
	while i < n :
		if ( arr [ i ] % 2 == 1 ) :
			i += 2 ;
			continue ;
		while ( i < n and arr [ i ] % 2 == 0 ) :
			i += 2 ;
		flips += 1 ;
		i += 2 ;
	i = 1
	while i < n :
		if ( arr [ i ] % 2 == 1 ) :
			i += 2 ;
			continue ;
		while ( i < n and arr [ i ] % 2 == 0 ) :
			i += 2 ;
		flips += 1 ;
		i += 2 ;
	print ( flips ) ;
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 3 , 4 , 3 , 5 , 3 , 2 ] ;
	N = len ( arr ) ;
	minOperations ( arr , N ) ;