human
Convert an unbalanced bracket sequence to a balanced sequence | Function to return balancedBrackets String.
Initializing dep to 0.
Stores maximum negative depth.
if dep is less than minDep.
if minDep is less than 0 then there is need to add ' ( ' at the front.
Reinitializing to check the updated String.
if dep is not 0 then there is need to add ' ) ' at the back.
Driver code"
How can the above be solved in Python?
 What is a code to convert an unbalanced bracket sequence to a balanced sequence and the other steps required?
assistant
#Here is code to convert an unbalanced bracket sequence to a balanced sequence and the other steps required.
 def balancedBrackets ( Str ) :
	dep = 0
	minDep = 0
	for i in Str :
		if ( i == ' ( ' ) :
			dep += 1
		else :
			dep -= 1
		if ( minDep > dep ) :
			minDep = dep
	if ( minDep < 0 ) :
		for i in range ( abs ( minDep ) ) :
			Str = ' ( ' + Str
	dep = 0
	for i in Str :
		if ( i == ' ( ' ) :
			dep += 1
		else :
			dep -= 1
	if ( dep != 0 ) :
		for i in range ( dep ) : Str = Str + ' ) '
	return Str
Str = " ) ) ) ( ) "
print ( balancedBrackets ( Str ) )