human
Count number of right triangles possible with a given perimeter | Function to return the count.
making a list to store ( a , b ) pairs.
no triangle if p is odd.
make ( a , b ) pair in sorted order.
check to avoid duplicates.
store the new pair.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count number of right triangles possible with a given perimeter and the other steps required.
 def countTriangles ( p ) :
	store = [ ]
	if p % 2 != 0 : return 0
	else :
		count = 0
		for b in range ( 1 , p // 2 ) :
			a = p / 2 * ( ( p - 2 * b ) / ( p - b ) )
			inta = int ( a )
			if ( a == inta ) :
				ab = tuple ( sorted ( ( inta , b ) ) )
				if ab not in store :
					count += 1
					store . append ( ab )
		return count
p = 840
print ( " number ▁ of ▁ right ▁ triangles ▁ = ▁ " + str ( countTriangles ( p ) ) )