human
Panalphabetic window in a string | Return if given string contain panalphabetic window ..
traversing the string.
if character of string is equal to ch , increment ch ..
if all characters are found , return true ..
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to panalphabetic window in a string and the other steps required.
 def isPanalphabeticWindow ( s , n ) :
	ch = ' a '
	for i in range ( 0 , n ) :
		if ( s [ i ] == ch ) :
			ch = chr ( ord ( ch ) + 1 )
		if ( ch == ' z ' ) :
			return True
	return False
s = " abujm ▁ zvcd ▁ acefc ▁ deghf ▁ gijkle ▁ m ▁ n ▁ o ▁ p ▁ pafqrstuvwxyzfap "
n = len ( s )
if ( isPanalphabeticWindow ( s , n ) ) :
	print ( " YES " )
else :
	print ( " NO " )