human
Give me a code to circular Matrix ( Construct a matrix with numbers 1 to m * n in spiral way ) and the other steps required given the following:
Circular Matrix ( Construct a matrix with numbers 1 to m * n in spiral way ) | Fills a [ m ] [ n ] with values from 1 to m * n in spiral fashion ..
Initialize value to be filled in matrix ..
k - starting row index m - ending row index l - starting column index n - ending column index.
Print the first row from the remaining rows ..
Print the last column from the remaining columns ..
Print the last row from the remaining rows ..
Print the first column from the remaining columns ..
Driver program"
Solution in Python:
assistant
#Here is code to circular Matrix ( Construct a matrix with numbers 1 to m * n in spiral way ) and the other steps required.
 def spiralFill ( m , n , a ) :
	val = 1
	k , l = 0 , 0
	while ( k < m and l < n ) :
		for i in range ( l , n ) :
			a [ k ] [ i ] = val
			val += 1
		k += 1
		for i in range ( k , m ) :
			a [ i ] [ n - 1 ] = val
			val += 1
		n -= 1
		if ( k < m ) :
			for i in range ( n - 1 , l - 1 , - 1 ) :
				a [ m - 1 ] [ i ] = val
				val += 1
			m -= 1
		if ( l < n ) :
			for i in range ( m - 1 , k - 1 , - 1 ) :
				a [ i ] [ l ] = val
				val += 1
			l += 1
if __name__ == ' _ _ main _ _ ' :
	m , n = 4 , 4
	a = [ [ 0 for j in range ( m ) ] for i in range ( n ) ]
	spiralFill ( m , n , a )
	for i in range ( m ) :
		for j in range ( n ) :
			print ( a [ i ] [ j ] , end = ' ▁ ' )
		print ( ' ' )