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Count subsequences having odd Bitwise OR values in an array | Function to count the subsequences having odd bitwise OR value.
Stores count of odd elements.
Stores count of even elements.
Traverse the array arr [ ].
If element is odd.
Return the final answer.
Driver Code.
Given array arr [ ]"
How can the above be solved in Python?
 What is a code to count subsequences having odd Bitwise OR values in an array and the other steps required?
assistant
#Here is code to count subsequences having odd Bitwise OR values in an array and the other steps required.
 def countSubsequences ( arr ) :
	odd = 0 ;
	even = 0 ;
	for x in arr :
		if ( x & 1 ) :
			odd += 1 ;
		else :
			even += 1 ;
	return ( ( 1 << odd ) - 1 ) * ( 1 << even ) ;
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 4 , 1 ] ;
	print ( countSubsequences ( arr ) ) ;