human
Solve the following python programming problem given the following code:
def dunder_truncate(_dict) : 
    "Returns dict with dunder keys truncated to only the last part

    In other words, replaces the dunder keys with just last part of
    it. In case many identical last parts are encountered, they are
    not truncated further

    eg::

        >>> dunder_truncate({'a__p': 3, 'b__c': 'no'})
        {'c': 'no', 'p': 3}
        >>> dunder_truncate({'a__p': 'yay', 'b__p': 'no', 'c__z': 'dunno'})
        {'a__p': 'yay', 'b__p': 'no', 'z': 'dunno'}

    :param _dict : (dict) to flatten
    :rtype       : (dict) flattened result

    " 
    keylist = list (_dict.keys ()) 
    def decide_key(k, klist) : 
        newkey = dunder_last (k) 
        return (newkey if (list (map (dunder_last, klist)).count (newkey) == 1) else k) 
original_keys = [decide_key (key, key) for key in keylist] 
    return dict (zip (original_keys, _dict.values ())) 

    
    

    Fix the buggy line: original_keys = [decide_key (key, key) for key in keylist]
assistant
#Here is Python code to fix the buggy line: original_keys = [decide_key (key, key) for key in keylist]
.

original_keys = [decide_key (key, keylist) for key in keylist]