human
Can you provide a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/long-pressed-name/:
Your friend is typing his name into a keyboard.  Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.
You examine the typed characters of the keyboard.  Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.
 
Example 1:
Input: name = "alex", typed = "aaleex"
Output: true
Explanation: 'a' and 'e' in 'alex' were long pressed.

Example 2:
Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: 'e' must have been pressed twice, but it wasn't in the typed output.

Example 3:
Input: name = "leelee", typed = "lleeelee"
Output: true

Example 4:
Input: name = "laiden", typed = "laiden"
Output: true
Explanation: It's not necessary to long press any character.

 
Constraints:

1 <= name.length <= 1000
1 <= typed.length <= 1000
The characters of name and typed are lowercase letters.

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution:
    def isLongPressedName(self, name: str, typed: str) -> bool:
        n = 0
        t = 0
        
        while n < len(name) and t < len(typed):
            if name[n] == typed[t]:
                n += 1
                t += 1
            else:
                if t and typed[t] == typed[t - 1]:
                    t += 1
                else:
                    return False
        
        if n != len(name):
            return False
            
        while t < len(typed):
            if typed[t] == typed[t - 1]:
                t += 1
            else:
                return False
        
        return True