human
Minimize cost to modify the Array such that even indices have even elements and vice versa | Function to find the minimum cost to modify the array according to the given criteria.
Count of wrong positioned odd and even elements.
Odd Count.
Even Count.
Swapping Cost.
Decrementing cost after swapping.
Only decrementing cost.
Return the minimum cost of the two cases.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to minimize cost to modify the Array such that even indices have even elements and vice versa and the other steps required.
 def minimumCost ( arr , N , X , Y ) :
	even_count = 0
	odd_count = 0
	for i in range ( 0 , N ) :
		if ( ( arr [ i ] & 1 ) and ( i % 2 == 0 ) ) :
			odd_count += 1
		if ( ( arr [ i ] % 2 ) == 0 and ( i & 1 ) ) :
			even_count += 1
	cost1 = X * min ( odd_count , even_count )
	cost2 = Y * ( max ( odd_count , even_count ) - min ( odd_count , even_count ) )
	cost3 = ( odd_count + even_count ) * Y
	return min ( cost1 + cost2 , cost3 )
if __name__ == " _ _ main _ _ " :
	arr = [ 5 , 3 , 7 , 2 , 1 ]
	X = 10
	Y = 2
	N = len ( arr )
	print ( minimumCost ( arr , N , X , Y ) )