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Minimum number of adjacent swaps required to convert a permutation to another permutation by given condition | Function to find the minimum number of swaps.
New array to convert to 1 - based indexing.
Keeps count of swaps.
Check if it is an ' X ' position.
Corner Case.
Swap.
Print the minimum swaps.
Given number N.
Given permutation of N numbers.
Function call"
Solution in Python:

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What is a code to minimum number of adjacent swaps required to convert a permutation to another permutation by given condition and the other steps required?
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#Here is code to minimum number of adjacent swaps required to convert a permutation to another permutation by given condition and the other steps required.
 def solve ( P , n ) :
	arr = [ ]
	arr . append ( 0 )
	for x in P :
		arr . append ( x )
	cnt = 0
	for i in range ( 1 , n ) :
		if ( arr [ i ] == i ) :
			arr [ i ] , arr [ i + 1 ] = arr [ i + 1 ] , arr [ i ]
			cnt += 1
	if ( arr [ n ] == n ) :
		arr [ n - 1 ] , arr [ n ] = arr [ n ] , arr [ n - 1 ]
		cnt += 1
	print ( cnt )
N = 9
P = [ 1 , 2 , 4 , 9 , 5 , 8 , 7 , 3 , 6 ]
solve ( P , N )