human
Count of pairs of ( i , j ) such that ( ( n % i ) % j ) % n is maximized | Function to return the count of required pairs.
Special case.
Number which will give the max value for ( ( n % i ) % j ) % n.
To store the maximum possible value of ( ( n % i ) % j ) % n.
Count of possible pairs.
Driver code"
How can the above be solved in Python?

Give me a code to count of pairs of ( i , j ) such that ( ( n % i ) % j ) % n is maximized and the other steps required?
assistant
#Here is code to count of pairs of ( i , j ) such that ( ( n % i ) % j ) % n is maximized and the other steps required.
 def countPairs ( n ) :
	if ( n == 2 ) :
		return 4
	num = ( ( n // 2 ) + 1 ) ;
	max = n % num ;
	count = n - max ;
	return count
if __name__ == " _ _ main _ _ " :
	n = 5 ;
print ( countPairs ( n ) ) ;