human
Solve in Python:
The [Sharkovsky's Theorem](https://en.wikipedia.org/wiki/Sharkovskii%27s_theorem) involves the following ordering of the natural numbers:
```math
3≺5≺7≺9≺ ...\\
≺2·3≺2·5≺2·7≺2·9≺...\\
≺2^n·3≺2^n·5≺2^n·7≺2^n·9≺...\\
≺2^{(n+1)}·3≺2^{(n+1)}·5≺2^{(n+1)}·7≺2^{(n+1)}·9≺...\\
≺2^n≺2^{(n-1)}≺...\\
≺4≺2≺1\\
```
 
Your task is to complete the function which returns `true` if `$a≺b$` according to this ordering, and `false` otherwise.
 
You may assume both `$a$` and `$b$` are non-zero positive integers.

=====
What is a the Python code you requested?
assistant
#Here is the Python code you requested.

def sharkovsky(a,b):
    
    def Answer(n):
        con = True
        p = 0
        while con == True:
            if n %2!=0:
                ans =  (p,n)
                con = False
            else:
                n= n /2
                p +=1
        return ans
    ans_a = Answer(a)    
    ans_b = Answer(b) 
    
    if ans_a[1]==1 and ans_b[1]!=1:
        return False
    elif ans_a[1]!=1 and ans_b[1]==1:
        return True
    elif ans_a[1]==1 and ans_b[1]==1:
        return ans_a[0]>ans_b[0]
    else:
        if ans_a[0]>ans_b[0]:
            return False
        elif ans_a[0]<ans_b[0]:
            return True
        else:
            return ans_a[1]<ans_b[1]