human
Flip all 0 s in given Binary Strings K times with different neighbours | Function to modify the given string K number of times by flipping 0 s having different adjacent characters.
Size of the string.
Stores modified string after each iteration.
Iterate over the range [ 0 k ].
Traverse the string S.
If '0' is present at 0 th index then replace it with 1 st index.
If '0' is present at the last index then replace it with last index - 1 character.
Otherwise , convert 0 s to 1 if the adjacent characters are different.
If during this iteration there is no change in the string then break this loop.
Update the string S.
Print the updated string.
Driver Code"
How can the above be solved in Python?
 What is a code to flip all 0 s in given Binary Strings K times with different neighbours and the other steps required?
assistant
#Here is code to flip all 0 s in given Binary Strings K times with different neighbours and the other steps required.
 def convertString ( S , k ) :
	n = len ( S )
	temp = S
	temp = list ( temp )
	for i in range ( k ) :
		for j in range ( n - 1 ) :
			if ( j == 0 and S [ j ] == '0' ) :
				temp [ j ] = S [ j + 1 ]
			elif ( j == n - 1 and S [ j ] == '0' ) :
				temp [ j ] = S [ j - 1 ]
			elif ( S [ j - 1 ] != S [ j + 1 ] and S [ j ] == '0' ) :
				temp [ j ] = '1'
		if ( S == temp ) :
			break
		temp = ' ' . join ( temp )
		S = temp
	print ( S )
if __name__ == ' _ _ main _ _ ' :
	S = "10010001"
	K = 1
	convertString ( S , K )