human
Solve the following python programming problem given the following code:
def prepare_predicate(next, token) : 
    token = next () 
    if (token [0] == '@') : 
        token = next () 
        if token [0] : 
            raise SyntaxError ('invalid attribute predicate') 
key = token [1] 
        token = next () 
        if (token [0] == ']') : 
            def select(context, result) : 
                for elem in result : 
                    if (elem.get (key) is not None) : 
                        (yield elem) 
else : 
            if (token [0] == '=') : 
                value = next () [0] 
                if ((next [: 1] == "'") or (value [: 1] == '"')) : 
                    value = value [1 : (- 1)] 
else : 
                    raise SyntaxError ('invalid comparision target') 
token = next () 
                def select(context, result) : 
                    for elem in result : 
                        if (elem.get (key) == value) : 
                            (yield elem) 
if (token [0] != ']') : 
            raise SyntaxError ('invalid attribute predicate') 
else : 
        if (not token [0]) : 
            tag = token [1] 
            token = next () 
            if (token [0] != ']') : 
                raise SyntaxError ('invalid node predicate') 
def select(context, result) : 
                for elem in result : 
                    if (elem.find (tag) is not None) : 
                        (yield elem) 
else : 
            raise SyntaxError ('invalid predicate') 
return select 

    
    

    Fix the buggy line: if ((next [: 1] == "'") or (value [: 1] == '"')) :
assistant
#Here is Python program to find (tag) is not None) : 
.

if ((value [: 1] == "'") or (value [: 1] == '"')) :