human
In fact, the problems E1 and E2 do not have much in common. You should probably think of them as two separate problems.

You are given an integer array a[1 … n] = [a_1, a_2, …, a_n].

Let us consider an empty [deque](https://tinyurl.com/pfeucbux) (double-ended queue). A deque is a data structure that supports adding elements to both the beginning and the end. So, if there are elements [3, 4, 4] currently in the deque, adding an element 1 to the beginning will produce the sequence [\color{red}{1}, 3, 4, 4], and adding the same element to the end will produce [3, 4, 4, \color{red}{1}].

The elements of the array are sequentially added to the initially empty deque, starting with a_1 and finishing with a_n. Before adding each element to the deque, you may choose whether to add it to the beginning or to the end.

For example, if we consider an array a = [3, 7, 5, 5], one of the possible sequences of actions looks like this:    1. |  add 3 to the beginning of the deque: |  deque has a sequence [\color{red}{3}] in it.
  
---|---|---  
  2. |  add 7 to the end of the deque: |  deque has a sequence [3, \color{red}{7}] in it.
  
  3. |  add 5 to the end of the deque: |  deque has a sequence [3, 7, \color{red}{5}] in it.
  
  4. |  add 5 to the beginning of the deque: |  deque has a sequence [\color{red}{5}, 3, 7, 5] in it.
  
  
Find the minimal possible number of inversions in the deque after the whole array is processed. 

An inversion in sequence d is a pair of indices (i, j) such that i < j and d_i > d_j. For example, the array d = [5, 3, 7, 5] has exactly two inversions — (1, 2) and (3, 4), since d_1 = 5 > 3 = d_2 and d_3 = 7 > 5 = d_4.

Input

The first line contains an integer t (1 ≤ t ≤ 1000) — the number of test cases.

The next 2t lines contain descriptions of the test cases. 

The first line of each test case description contains an integer n (1 ≤ n ≤ 2 ⋅ 10^5) — array size. The second line of the description contains n space-separated integers a_i (-10^9 ≤ a_i ≤ 10^9) — elements of the array.

It is...
Using python3 can you solve the prior task?
 ... What is a Python code to find the minimal possible number of inversions in the deque after the whole array is processed?
assistant
#Here is Python code to find the minimal possible number of inversions in the deque after the whole array is processed.

import bisect
# from collections import deque

def solve():
    n = int(input())
    p = [int(v) for v in input().split()]
    arr = sorted(set(p))
    tree = [0] * n
    ans = 0

    def inc(i):
        while i < n:
            tree[i] += 1
            i |= i + 1

    def part_sum(i):
        ans = 0
        while i >= 0:
            ans += tree[i]
            i = (i & (i + 1)) - 1
        return ans

    def sum(l, r):
        if l == 0:
            return part_sum(r)
        else:
            return part_sum(r) - part_sum(l - 1)

    inc(bisect.bisect_left(arr, p[0]))

    # breakpoint()
    for i in range(1, n):
        pos = bisect.bisect_left(arr, p[i])
        l = sum(0, pos - 1) if pos else 0
        r = sum(pos + 1, n - 1) if pos + 1 < n else 0
        ans += min(l, r)
        inc(pos)

    print(ans)

for _ in range(int(input())):
    solve()