human
Find a string such that every character is lexicographically greater than its immediate next character | Function that prints the required string.
Find modulus with 26.
Print extra characters required.
Print the given reverse string countOfStr times.
Driver Code.
Initialize a string in reverse order"
Solution in Python:
assistant
#Here is code to find a string such that every character is lexicographically greater than its immediate next character and the other steps required.
 def printString ( n , str ) :
	str2 = " "
	extraChar = n % 26
	if ( extraChar >= 1 ) :
		for i in range ( 26 - ( extraChar + 1 ) , 26 ) :
			str2 += str [ i ]
	countOfStr = n // 26
	for i in range ( 1 , countOfStr + 1 ) :
		for j in range ( 26 ) :
			str2 += str [ j ]
	return str2
if __name__ == " _ _ main _ _ " :
	n = 30
	str = " zyxwvutsrqponmlkjihgfedcba "
	print ( printString ( n , str ) )