human
Can you provide a code to check whether two strings can be made equal by reversing substring of equal length from both strings and the other steps required given the following:
Check whether two strings can be made equal by reversing substring of equal length from both strings | function to count inversion count of the string.
for storing frequency.
we 'll add all the characters  which are less than the ith  character before i..
adding the count to inversion count.
updating the character in the frequency array.
function to check whether any of the string have a repeated character.
function to check whether the string S1 and S2 can be made equal by reversing sub strings ofsame size in both strings.
frequency array to check whether both string have same character or not.
adding the frequency.
.
if the character is not in S1.
decrementing the frequency.
If both string does not have same characters or not.
finding inversion count of both strings.
If inversion count is same , or have same parity or if any of the string have a repeated character then the answer is Yes else No.
Driver Code"
Solution in Python:
assistant
#Here is code to check whether two strings can be made equal by reversing substring of equal length from both strings and the other steps required.
 def inversionCount ( s ) :
	freq = [ 0 for _ in range ( 26 ) ]
	inv = 0
	for i in range ( len ( s ) ) :
		temp = 0
		for j in range ( ord ( s [ i ] ) - ord ( ' a ' ) ) :
			temp += freq [ j ]
		inv += ( i - temp )
		freq [ ord ( s [ i ] ) - ord ( ' a ' ) ] += 1
	return inv
def haveRepeated ( S1 , S2 ) :
	freq = [ 0 for _ in range ( 26 ) ]
	for i in range ( len ( S1 ) ) :
		if freq [ ord ( S1 [ i ] ) - ord ( ' a ' ) ] > 0 :
			return 1
		freq [ ord ( S1 [ i ] ) - ord ( ' a ' ) ] += 1
	for i in range ( 26 ) :
		freq [ i ] = 0
	for i in range ( len ( S2 ) ) :
		if freq [ ord ( S2 [ i ] ) - ord ( ' a ' ) ] > 0 :
			return 1
		freq [ ord ( S2 [ i ] ) - ord ( ' a ' ) ] += 1
	return 0
def checkToMakeEqual ( S1 , S2 ) :
	freq = [ 0 for _ in range ( 26 ) ]
	for i in range ( len ( S1 ) ) :
		freq [ ord ( S1 [ i ] ) - ord ( ' a ' ) ] += 1
	flag = 0
	for i in range ( len ( S2 ) ) :
		if freq [ ord ( S2 [ i ] ) - ord ( ' a ' ) ] == 0 :
			flag = 1
			break
		freq [ ord ( S2 [ i ] ) - ord ( ' a ' ) ] -= 1
	if flag == 1 :
		print ( " No " )
		return
	invCount1 = inversionCount ( S1 )
	invCount2 = inversionCount ( S2 )
	if ( ( invCount1 == invCount2 ) or ( ( invCount1 % 2 ) == ( invCount2 % 2 ) ) or haveRepeated ( S1 , S2 ) == 1 ) :
		print ( " Yes " )
	else :
		print ( " No " )
S1 = " abbca "
S2 = " acabb "
checkToMakeEqual ( S1 , S2 )