human
Give me a code to minimum removals required to make frequency of each array element equal to its value and the other steps required given the following:
Minimum removals required to make frequency of each array element equal to its value | Function to find the minimum count of elements required to be removed such that frequency of arr [ i ] equal to arr [ i ].
Stores frequency of each element of the array.
Traverse the array.
Update frequency of arr [ i ].
Stores minimum count of removals.
Traverse the map.
Stores key value of the map.
If frequency of i is less than i.
Update cntMinRem.
If frequency of i is greater than i.
Update cntMinRem.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to minimum removals required to make frequency of each array element equal to its value and the other steps required.
 def min_elements ( arr , N ) :
	mp = { } ;
	for i in range ( N ) :
		if arr [ i ] in mp :
			mp [ arr [ i ] ] += 1 ;
		else :
			mp [ arr [ i ] ] = 1 ;
	cntMinRem = 0 ;
	for it in mp :
		i = it ;
		if ( mp [ i ] < i ) :
			cntMinRem += mp [ i ] ;
		elif ( mp [ i ] > i ) :
			cntMinRem += ( mp [ i ] - i ) ;
	return cntMinRem ;
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 4 , 1 , 4 , 2 ] ;
	N = len ( arr ) ;
	print ( min_elements ( arr , N ) ) ;