human
Complete this python program:
def bool_map(bool1, bool2):
assistant
#Here is the Python program you requested.

    """Return the simplified version of bool1, and the mapping of variables
    that makes the two expressions bool1 and bool2 represent the same
    logical behaviour for some correspondence between the variables
    of each.
    If more than one mappings of this sort exist, one of them
    is returned.
    For example, And(x, y) is logically equivalent to And(a, b) for
    the mapping {x: a, y:b} or {x: b, y:a}.
    If no such mapping exists, return False.
    Examples
    >>> from sympy import SOPform, bool_map, Or, And, Not, Xor
    >>> from sympy.abc import w, x, y, z, a, b, c, d
    >>> function1 = SOPform([x, z, y],[[1, 0, 1], [0, 0, 1]])
    >>> function2 = SOPform([a, b, c],[[1, 0, 1], [1, 0, 0]])
    >>> bool_map(function1, function2)
    (y & ~z, {y: a, z: b})
    The results are not necessarily unique, but they are canonical. Here,
    ``(w, z)`` could be ``(a, d)`` or ``(d, a)``:
    >>> eq =  Or(And(Not(y), w), And(Not(y), z), And(x, y))
    >>> eq2 = Or(And(Not(c), a), And(Not(c), d), And(b, c))
    >>> bool_map(eq, eq2)
    ((x & y) | (w & ~y) | (z & ~y), {w: a, x: b, y: c, z: d})
    >>> eq = And(Xor(a, b), c, And(c,d))
    >>> bool_map(eq, eq.subs(c, x))
    (c & d & (a | b) & (~a | ~b), {a: a, b: b, c: d, d: x})
    """
    def match(function1, function2):
        'Return    the    mapping    that    equates    variables    between    two\n                                simplified    boolean    expressions    if    possible.\n\n                                By    "simplified"    we    mean    that    a    function    has    been    denested\n                                and    is    either    an    And    (or    an    Or)    whose    arguments    are    either\n                                symbols    (x),    negated    symbols    (Not(x)),    or    Or    (or    an    And)    whose\n                                arguments    are    only    symbols    or    negated    symbols.    For    example,\n                                And(x,    Not(y),    Or(w,    Not(z))).\n\n                                Basic.match    is    not    robust    enough    (see    issue    4835)    so    this    is\n                                a    workaround    that    is    valid    for    simplified    boolean    expressions\n                                '
        if (function1.__class__ != function2.__class__):
            return None
        if (len(function1.args) != len(function2.args)):
            return None
        if function1.is_Symbol:
            return {function1: function2}
        f1 = _finger(function1)
        f2 = _finger(function2)
        if (len(f1) != len(f2)):
            return False
        matchdict = {}
        for k in f1.keys():
            if (k not in f2):
                return False
            if (len(f1[k]) != len(f2[k])):
                return False
            for (i, x) in enumerate(f1[k]):
                matchdict[x] = f2[k][i]
        return matchdict
    a = simplify_logic(bool1)
    b = simplify_logic(bool2)
    m = match(a, b)
    if m:
        return (a, m)
    return (m is not None)