human
Minimize increment | Function to calculate the minimum number of operations to convert array A to array B by incrementing and decrementing adjacent elements.
Stores the final count.
Stores the sum of array A and B respectivelly.
Check of the sums are unequall.
Pointer to iterate through array.
Case 1 where A [ i ] > B [ i ].
Stores the extra values for the current index.
Iterate the array from [ i - 1 , 0 ].
Stores the count of values being transfered from A [ i ] to A [ j ].
Add operation count.
Iterate the array in right direction id A [ i ] - B [ i ] > 0.
Iterate the array from [ i + 1 , n - 1 ].
Stores the count of values being transfered from A [ i ] to A [ j ].
Add operation count.
Return Answer.
Driver Code.
Function Call"
How can the above be solved in Python?
 Give me a code to minimize increment and the other steps required?
assistant
#Here is code to minimize increment and the other steps required.
 def minimumMoves ( A , B , N ) :
	ans = 0
	sum_A = 0
	sum_B = 0
	for i in range ( N ) :
		sum_A += A [ i ]
	for i in range ( N ) :
		sum_B += B [ i ]
	if ( sum_A != sum_B ) :
		return - 1
	i = 0
	while ( i < N ) :
		if ( A [ i ] > B [ i ] ) :
			temp = A [ i ] - B [ i ]
			j = i - 1
			while ( j >= 0 and temp > 0 ) :
				if ( B [ j ] > A [ j ] ) :
					cnt = min ( temp , ( B [ j ] - A [ j ] ) )
					A [ j ] += cnt
					temp -= cnt
					ans += ( cnt * abs ( j - i ) )
				j -= 1
			if ( temp > 0 ) :
				j = i + 1
				while ( j < N and temp > 0 ) :
					if ( B [ j ] > A [ j ] ) :
						cnt = min ( temp , ( B [ j ] - A [ j ] ) )
						A [ j ] += cnt
						temp -= cnt
						ans += ( cnt * abs ( j - i ) )
					j += 1
		i += 1
	return ans
if __name__ == ' _ _ main _ _ ' :
	A = [ 1 , 5 , 7 ]
	B = [ 13 , 0 , 0 ]
	N = len ( A )
	print ( minimumMoves ( A , B , N ) )