human
Write me a code to sum of largest prime factor of each number less than equal to n and the other steps required given the following:
Sum of largest prime factor of each number less than equal to n | function to find sum of largest prime factor of each number less than equal to n.
Create an integer array " prime [ 0 . . n ] " and initialize all entries of it as 0. A value in prime [ i ] will finally be 0 if ' i ' is a prime , else it will contain the largest prime factor of ' i ' ..
If prime [ p ] is '0' , then it is a prime number.
Update all multiples of p.
Sum up the largest prime factor of all the numbers.
if ' p ' is a non - prime number then prime [ p ] gives its largesr prime factor.
' p ' is a prime number.
required sum.
Driver code to test above function"
How can the above be solved in Python?
assistant
#Here is code to sum of largest prime factor of each number less than equal to n and the other steps required.
 def sumOfLargePrimeFactor ( n ) :
	prime = [ 0 ] * ( n + 1 )
	sum = 0
	max = int ( n / 2 )
	for p in range ( 2 , max + 1 ) :
		if prime [ p ] == 0 :
			for i in range ( p * 2 , n + 1 , p ) :
				prime [ i ] = p
	for p in range ( 2 , n + 1 ) :
		if prime [ p ] :
			sum += prime [ p ]
		else :
			sum += p
	return sum
n = 12
print ( " Sum ▁ = " , sumOfLargePrimeFactor ( n ) )