human
Rearrange array to maximize count of local minima | Function to rearrange array elements to maximize count of local minima in the array.
Sort the array in ascending order.
Stores index of left pointer.
Stores index of right pointer.
Traverse the array elements.
if right is less than N.
Print array element.
Update right.
Print array element.
Update left.
Driver Code"
Solution in Python:
 Can you provide a code to rearrange array to maximize count of local minima and the other steps required?
assistant
#Here is code to rearrange array to maximize count of local minima and the other steps required.
 def rearrangeArrMaxcntMinima ( arr , N ) :
	arr . sort ( )
	left = 0
	right = N // 2
	while ( left < N // 2 or right < N ) :
		if ( right < N ) :
			print ( arr [ right ] , end = " ▁ " )
			right += 1
		if ( left < N // 2 ) :
			print ( arr [ left ] , end = " ▁ " )
			left += 1
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 , 4 , 5 ]
	N = len ( arr )
	rearrangeArrMaxcntMinima ( arr , N )