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Check if bits in range L to R of two numbers are complement of each other or not | function to check whether all the bits are set in the given range or not.
calculating a number ' num ' having ' r ' number of bits and bits in the range l to r are the only set bits.
new number which will only have one or more set bits in the range l to r and nowhere else.
if both are equal , then all bits are set in the given range.
else all bits are not set.
function to check whether all the bits in the given range of two numbers are complement of each other.
Driver Code"
Solution in Python:

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What is a code to check if bits in range L to R of two numbers are complement of each other or not and the other steps required?
assistant
#Here is code to check if bits in range L to R of two numbers are complement of each other or not and the other steps required.
 def allBitsSetInTheGivenRange ( n , l , r ) :
	num = ( ( 1 << r ) - 1 ) ^ ( ( 1 << ( l - 1 ) ) - 1 )
	new_num = n & num
	if ( num == new_num ) :
		return True
	return False
def bitsAreComplement ( a , b , l , r ) :
	xor_value = a ^ b
	return allBitsSetInTheGivenRange ( xor_value , l , r )
if __name__ == " _ _ main _ _ " :
	a = 10
	b = 5
	l = 1
	r = 3
	if ( bitsAreComplement ( a , b , l , r ) ) :
		print ( " Yes " )
	else :
		print ( " No " )