human
Count of integers K in range [ 0 , N ] such that ( K XOR K + 1 ) equals ( K + 2 XOR K + 3 ) | Function to count all the integers less than N satisfying the given condition.
Store the count of even numbers less than N + 1.
Return the count.
Driver Code.
Given Input.
Function Call"
Solution in Python:

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What is a code to count of integers K in range [ 0 , N ] such that ( K XOR K + 1 ) equals ( K + 2 XOR K + 3 ) and the other steps required?
assistant
#Here is code to count of integers K in range [ 0 , N ] such that ( K XOR K + 1 ) equals ( K + 2 XOR K + 3 ) and the other steps required.
 def countXor ( N ) :
	cnt = N // 2 + 1
	return cnt
if __name__ == ' _ _ main _ _ ' :
	N = 4
	print ( countXor ( N ) )