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Minimize difference between maximum and minimum array elements by removing a K | Function to minimize difference between maximum and minimum array elements by removing a K - length subarray.
Size of array.
Stores the maximum and minimum in the suffix subarray [ i . . N - 1 ].
Traverse the array.
Stores the maximum and minimum in the prefix subarray [ 0 . . i - 1 ].
Store the minimum difference.
Traverse the array.
If the suffix doesn 't exceed  the end of the array.
Store the maximum element in array after removing subarray of size K.
Stores the maximum element in array after removing subarray of size K.
Update minimum difference.
Updating the maxPrefix and minPrefix with current element.
Print the minimum difference.
Driver Code"
Solution in Python:
 ... Give me a code to minimize difference between maximum and minimum array elements by removing a K and the other steps required?
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#Here is code to minimize difference between maximum and minimum array elements by removing a K and the other steps required.
 def minimiseDifference ( arr , K ) :
	N = len ( arr )
	maxSuffix = [ 0 for i in range ( N + 1 ) ]
	minSuffix = [ 0 for i in range ( N + 1 ) ]
	maxSuffix [ N ] = - 1e9
	minSuffix [ N ] = 1e9
	maxSuffix [ N - 1 ] = arr [ N - 1 ]
	minSuffix [ N - 1 ] = arr [ N - 1 ]
	i = N - 2
	while ( i >= 0 ) :
		maxSuffix [ i ] = max ( maxSuffix [ i + 1 ] , arr [ i ] )
		minSuffix [ i ] = min ( minSuffix [ i + 1 ] , arr [ i ] )
		i -= 1
	maxPrefix = arr [ 0 ]
	minPrefix = arr [ 0 ]
	minDiff = maxSuffix [ K ] - minSuffix [ K ]
	for i in range ( 1 , N ) :
		if ( i + K <= N ) :
			maximum = max ( maxSuffix [ i + K ] , maxPrefix )
			minimum = min ( minSuffix [ i + K ] , minPrefix )
			minDiff = min ( minDiff , maximum - minimum )
		maxPrefix = max ( maxPrefix , arr [ i ] )
		minPrefix = min ( minPrefix , arr [ i ] )
	print ( minDiff )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 4 , 5 , 8 , 9 , 1 , 2 ]
	K = 2
	minimiseDifference ( arr , K )