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Number of odd and even results for every value of x in range [ min , max ] after performing N steps | Function that prints the number of odd and even results.
If constant at layer i is even , beven is True , otherwise False . If the coefficient of x at layer i is even , aeven is True , otherwise False ..
If any of the coefficients at any layer is found to be even , then the product of all the coefficients will always be even ..
Checking whether the constant added after all layers is even or odd ..
Assuming input x is even ..
Assuming input x is odd ..
Displaying the counts ..
Driver Code"
Solution in Python:

What is a code to number of odd and even results for every value of x in range [ min , max ] after performing N steps and the other steps required?
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#Here is code to number of odd and even results for every value of x in range [ min , max ] after performing N steps and the other steps required.
 def count_even_odd ( min , max , steps ) :
	beven = True
	aeven = False
	n = 2
	for i in range ( 0 , n ) :
		a = steps [ i ] [ 0 ]
		b = steps [ i ] [ 1 ]
		if ( not ( aeven or a & 1 ) ) :
			aeven = True
		if ( beven ) :
			if ( b & 1 ) :
				beven = False
		elif ( not ( a & 1 ) ) :
			if ( not ( b & 1 ) ) :
				beven = True
		else :
			if ( b & 1 ) :
				beven = True
	if ( beven ) :
		even = ( int ( max / 2 ) - int ( ( min - 1 ) / 2 ) )
		odd = 0
	else :
		even = ( int ( max / 2 ) - int ( ( min - 1 ) / 2 ) )
		odd = 0
	if ( not ( beven ^ aeven ) ) :
		even += ( max - min + 1 - int ( max / 2 ) + int ( ( min - 1 ) / 2 ) )
	else :
		odd += ( max - min + 1 - int ( max / 2 ) + int ( ( min - 1 ) / 2 ) )
	print ( " even ▁ = ▁ " , even , " , ▁ odd ▁ = ▁ " , odd , sep = " " )
min = 1
max = 4
steps = [ [ 1 , 2 ] , [ 3 , 4 ] ]
count_even_odd ( min , max , steps )