human
Can you provide a code to find the K and the other steps required given the following:
Find the K | Function to find the index of number at first position of kth sequence of set of size n.
n_actual_fact = n !.
First position of the kth sequence will be occupied by the number present at index = k / ( n - 1 ) !.
Function to find the kth permutation of n numbers.
Store final answer.
Insert all natural number upto n in set.
Subtract 1 to get 0 based indexing.
Mark the first position.
itr now points to the number at index in set s.
remove current number from the set.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to find the K and the other steps required.
 def findFirstNumIndex ( k , n ) :
	if ( n == 1 ) :
		return 0 , k
	n -= 1
	first_num_index = 0
	n_partial_fact = n
	while ( k >= n_partial_fact and n > 1 ) :
		n_partial_fact = n_partial_fact * ( n - 1 )
		n -= 1
	first_num_index = k // n_partial_fact
	k = k % n_partial_fact
	return first_num_index , k
def findKthPermutation ( n , k ) :
	ans = " "
	s = set ( )
	for i in range ( 1 , n + 1 ) :
		s . add ( i )
	k = k - 1
	for i in range ( n ) :
		itr = list ( s )
		index , k = findFirstNumIndex ( k , n - i )
		ans += str ( itr [ index ] )
		itr . pop ( index )
		s = set ( itr )
	return ans
if __name__ == ' _ _ main _ _ ' :
	n = 3
	k = 4
	kth_perm_seq = findKthPermutation ( n , k )
	print ( kth_perm_seq )