human
Write me a code to program to build a DFA that checks if a string ends with "01" or "10" and the other steps required given the following:
Program to build a DFA that checks if a string ends with "01" or "10" | End position is checked using the string length value . q0 is the starting state . q1 and q2 are intermediate states . q3 and q4 are final states ..
state transitions 0 takes to q1 , 1 takes to q3.
state transitions 0 takes to q4 , 1 takes to q2.
state transitions 0 takes to q4 , 1 takes to q2.
state transitions 0 takes to q1 , 1 takes to q3.
state transitions 0 takes to q1 , 1 takes to q2.
Driver Code.
all state transitions are printed . if string is accpetable , YES is printed . else NO is printed"
Solution in Python:
assistant
#Here is code to program to build a DFA that checks if a string ends with "01" or "10" and the other steps required.
 def q1 ( s , i ) :
	print ( " q1 - > " , end = " " ) ;
	if ( i == len ( s ) ) :
		print ( " NO " ) ;
		return ;
	if ( s [ i ] == '0' ) :
		q1 ( s , i + 1 ) ;
	else :
		q3 ( s , i + 1 ) ;
def q2 ( s , i ) :
	print ( " q2 - > " , end = " " ) ;
	if ( i == len ( s ) ) :
		print ( " NO " ) ;
		return ;
	if ( s [ i ] == '0' ) :
		q4 ( s , i + 1 ) ;
	else :
		q2 ( s , i + 1 ) ;
def q3 ( s , i ) :
	print ( " q3 - > " , end = " " ) ;
	if ( i == len ( s ) ) :
		print ( " YES " ) ;
		return ;
	if ( s [ i ] == '0' ) :
		q4 ( s , i + 1 ) ;
	else :
		q2 ( s , i + 1 ) ;
def q4 ( s , i ) :
	print ( " q4 - > " , end = " " ) ;
	if ( i == len ( s ) ) :
		print ( " YES " ) ;
		return ;
	if ( s [ i ] == '0' ) :
		q1 ( s , i + 1 ) ;
	else :
		q3 ( s , i + 1 ) ;
def q0 ( s , i ) :
	print ( " q0 - > " , end = " " ) ;
	if ( i == len ( s ) ) :
		print ( " NO " ) ;
		return ;
	if ( s [ i ] == '0' ) :
		q1 ( s , i + 1 ) ;
	else :
		q2 ( s , i + 1 ) ;
if __name__ == " _ _ main _ _ " :
	s = "010101" ;
	print ( " State ▁ transitions ▁ are " , end = " ▁ " ) ;
	q0 ( s , 0 ) ;