human
A recently found Ancient Prophesy is believed to contain the exact Apocalypse date. The prophesy is a string that only consists of digits and characters "-".

We'll say that some date is mentioned in the Prophesy if there is a substring in the Prophesy that is the date's record in the format "dd-mm-yyyy". We'll say that the number of the date's occurrences is the number of such substrings in the Prophesy. For example, the Prophesy "0012-10-2012-10-2012" mentions date 12-10-2012 twice (first time as "0012-10-2012-10-2012", second time as "0012-10-2012-10-2012").

The date of the Apocalypse is such correct date that the number of times it is mentioned in the Prophesy is strictly larger than that of any other correct date.

A date is correct if the year lies in the range from 2013 to 2015, the month is from 1 to 12, and the number of the day is strictly more than a zero and doesn't exceed the number of days in the current month. Note that a date is written in the format "dd-mm-yyyy", that means that leading zeroes may be added to the numbers of the months or days if needed. In other words, date "1-1-2013" isn't recorded in the format "dd-mm-yyyy", and date "01-01-2013" is recorded in it.

Notice, that any year between 2013 and 2015 is not a leap year.

Input

The first line contains the Prophesy: a non-empty string that only consists of digits and characters "-". The length of the Prophesy doesn't exceed 105 characters.

Output

In a single line print the date of the Apocalypse. It is guaranteed that such date exists and is unique.

Examples

Input

777-444---21-12-2013-12-2013-12-2013---444-777

Output

13-12-2013
assistant
#Here is Python code to print the date of the Apocalypse.

try:
    import re

    st = input()

    dct = {}

    r = re.compile(r'(\d\d-\d\d-\d\d\d\d)')
    r2 = re.compile(r'(\d\d)-(\d\d)-(\d\d\d\d)')

    def judge_date(date):
       rst = r2.match(date)
       d, m, y = map(int, rst.groups())
       if 2013 <= y <= 2015:
           if 1 <= m <= 12:
               if m in (1, 3, 5, 7, 8, 10, 12):
                   if d > 31:
                       return False
               elif m == 2:
                   if d > 28:
                       return False
               else:
                   if d > 30:
                       return False
               if d <= 0:
                   return False
               return True
       return False

    while st:
       rst = r.search(st)
       if rst is None:
           break
       awd = rst.group()
       if judge_date(awd):
           try:
               dct[awd] += 1
           except KeyError:
               dct[awd] = 1
       st = st[rst.start() + 1:]

    print(max(dct.items(), key=lambda x: x[1])[0])
except Exception as e:
    print(e)