human
Find k closest elements to a given value | Function to find the cross over point ( the point before which elements aresmaller than or equal to x and afterwhich greater than x ).
Base cases x is greater than all.
x is smaller than all.
Find the middle point.
If x is same as middle element , then return mid.
If x is greater than arr [ mid ] , then either arr [ mid + 1 ] is ceiling of x or ceiling lies in arr [ mid + 1. . . high ].
This function prints k closest elements to x in arr [ ] . n is the number of elements in arr [ ].
Find the crossover point.
Right index to search.
To keep track of count of elements already printed.
If x is present in arr [ ] , then reduce left index . Assumption : all elements in arr [ ] are distinct.
Compare elements on left and right of crossover point to find the k closest elements.
If there are no more elements on right side , then print left elements.
If there are no more elements on left side , then print right elements.
Driver Code"
How can the above be solved in Python?
 What is a code to find k closest elements to a given value and the other steps required?
assistant
#Here is code to find k closest elements to a given value and the other steps required.
 def findCrossOver ( arr , low , high , x ) :
	if ( arr [ high ] <= x ) :
		return high
	if ( arr [ low ] > x ) :
		return low
	mid = ( low + high ) // 2
	if ( arr [ mid ] <= x and arr [ mid + 1 ] > x ) :
		return mid
	if ( arr [ mid ] < x ) :
		return findCrossOver ( arr , mid + 1 , high , x )
	return findCrossOver ( arr , low , mid - 1 , x )
def printKclosest ( arr , x , k , n ) :
	l = findCrossOver ( arr , 0 , n - 1 , x )
	r = l + 1
	count = 0
	if ( arr [ l ] == x ) :
		l -= 1
	while ( l >= 0 and r < n and count < k ) :
		if ( x - arr [ l ] < arr [ r ] - x ) :
			print ( arr [ l ] , end = " ▁ " )
			l -= 1
		else :
			print ( arr [ r ] , end = " ▁ " )
			r += 1
		count += 1
	while ( count < k and l >= 0 ) :
		print ( arr [ l ] , end = " ▁ " )
		l -= 1
		count += 1
	while ( count < k and r < n ) :
		print ( arr [ r ] , end = " ▁ " )
		r += 1
		count += 1
if __name__ == " _ _ main _ _ " :
	arr = [ 12 , 16 , 22 , 30 , 35 , 39 , 42 , 45 , 48 , 50 , 53 , 55 , 56 ]
	n = len ( arr )
	x = 35
	k = 4
	printKclosest ( arr , x , 4 , n )