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Minimize operations to reduce N to 2 by repeatedly reducing by 3 or dividing by 5 | Function to find the minimum number of operations to reduce N to 2 by dividing N by 5 or decrementing by 3.
Initialize the dp array.
Initialize the array dp [ ].
For N = 2 number of operations needed is zero.
Iterating over the range [ 1 , N ].
If it 's not possible to  create current N.
Multiply with 5.
Adding the value 3.
Checking if not possible to make the number as 2.
Return the minimum number of operations.
Driver Code"
Solution in Python:
assistant
#Here is code to minimize operations to reduce N to 2 by repeatedly reducing by 3 or dividing by 5 and the other steps required.
 def minimumOperations ( N ) :
	dp = [ 0 for i in range ( N + 1 ) ]
	for i in range ( N + 1 ) :
		dp [ i ] = 1000000000
	dp [ 2 ] = 0
	for i in range ( 2 , N + 1 , 1 ) :
		if ( dp [ i ] == 1000000000 ) :
			continue
		if ( i * 5 <= N ) :
			dp [ i * 5 ] = min ( dp [ i * 5 ] , dp [ i ] + 1 )
		if ( i + 3 <= N ) :
			dp [ i + 3 ] = min ( dp [ i + 3 ] , dp [ i ] + 1 )
	if ( dp [ N ] == 1000000000 ) :
		return - 1
	return dp [ N ]
if __name__ == ' _ _ main _ _ ' :
	N = 25
	print ( minimumOperations ( N ) )