human
Partition a string into palindromic strings of at least length 2 with every character present in a single string | Function to check if a string can be split into palindromic strings of at least length 2 by including every character exactly once.
Stores the frequency of each character.
Store the frequency of characters with frequencies 1 and even respectively.
Traverse the string s.
Iterate over all the characters.
If the frequency is 1.
If frequency is even.
Print the result.
Stores the number of characters with frequency equal to 1 that are not part of a palindromic string.
Iterate over all the characters.
If o becomes less than 0 , then break out of the loop.
If frequency of the current character is > 2 and is odd.
Update the value of o.
If a single character is still remaining.
Increment o by 1.
Set a [ i ] to 1.
Print the result.
Driver Code"
How can the above be solved in Python?
 ... Can you provide a code to partition a string into palindromic strings of at least length 2 with every character present in a single string and the other steps required?
assistant
#Here is code to partition a string into palindromic strings of at least length 2 with every character present in a single string and the other steps required.
 def checkPalindrome ( s ) :
	a = [ 0 ] * 26
	o , e = 0 , 0
	for i in s :
		a [ ord ( i ) - 97 ] += 1
	for i in range ( 26 ) :
		if ( a [ i ] == 1 ) :
			o += 1
		elif ( a [ i ] % 2 == 0 and a [ i ] != 0 ) :
			e += ( a [ i ] // 2 )
	if ( e >= o ) :
		print ( " Yes " )
	else :
		o = o - e
		for i in range ( 26 ) :
			if ( o <= 0 ) :
				break
			if ( o > 0 and a [ i ] % 2 == 1 and a [ i ] > 2 ) :
				k = o
				o = o - a [ i ] // 2
				if ( o > 0 or 2 * k + 1 == a [ i ] ) :
					o += 1
					a [ i ] = 1
		if ( o <= 0 ) :
			print ( " Yes " )
		else :
			print ( " No " )
if __name__ == ' _ _ main _ _ ' :
	S = " abbbaddzcz "
	checkPalindrome ( S )