human
Can you provide a code to maximum number of apples that can be eaten by a person and the other steps required given the following:
Maximum number of apples that can be eaten by a person | Function to find the maximum number of apples a person can eat such that the person eat at most one apple in a day ..
Store count of apples and number of days those apples are edible.
Stores indices of the array.
Stores count of days.
Stores maximum count of edible apples.
Traverse both the arrays.
If top element of the apple is not already expired.
Insert count of apples and their expiration date.
Remove outdated apples.
Insert all the apples produces by tree on current day.
Stores top element of pq.
Remove top element of pq.
If count of apples in curr is greater than 0.
Insert count of apples and their expiration date.
Update total_apples.
Update index.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to maximum number of apples that can be eaten by a person and the other steps required.
 def cntMaxApples ( apples , days ) :
	pq = [ ]
	i = 0
	n = len ( apples )
	total_apples = 0
	while ( i < n or len ( pq ) > 0 ) :
	if ( i < n and apples [ i ] != 0 ) :
		pq . append ( [ i + days [ i ] - 1 , apples [ i ] ] )
		pq . sort ( )
	while ( len ( pq ) > 0 and pq [ 0 ] [ 0 ] < i ) :
		pq . pop ( 0 )
	if ( len ( pq ) > 0 ) :
		curr = pq [ 0 ]
		pq . pop ( 0 )
		if ( len ( curr ) > 1 ) :
		pq . append ( [ curr [ 0 ] , curr [ 1 ] - 1 ] )
		pq . sort ( )
		total_apples += 1
	i += 1
	return total_apples
apples = [ 1 , 2 , 3 , 5 , 2 ]
days = [ 3 , 2 , 1 , 4 , 2 ]
print ( cntMaxApples ( apples , days ) )