human
Solve in Python:
Given an array of non-negative integers arr, you are initially positioned at start index of the array. When you are at index i, you can jump to i + arr[i] or i - arr[i], check if you can reach to any index with value 0.
Notice that you can not jump outside of the array at any time.
 
Example 1:
Input: arr = [4,2,3,0,3,1,2], start = 5
Output: true
Explanation: 
All possible ways to reach at index 3 with value 0 are: 
index 5 -> index 4 -> index 1 -> index 3 
index 5 -> index 6 -> index 4 -> index 1 -> index 3 

Example 2:
Input: arr = [4,2,3,0,3,1,2], start = 0
Output: true 
Explanation: 
One possible way to reach at index 3 with value 0 is: 
index 0 -> index 4 -> index 1 -> index 3

Example 3:
Input: arr = [3,0,2,1,2], start = 2
Output: false
Explanation: There is no way to reach at index 1 with value 0.

 
Constraints:

1 <= arr.length <= 5 * 10^4
0 <= arr[i] < arr.length
0 <= start < arr.length

Can you provide a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def canReach(self, arr: List[int], start: int) -> bool:
        q = collections.deque()
        visited = set()
        q.append(start)
        visited.add(start)
        while len(q) > 0:
            curr_idx = q.popleft()
            if arr[curr_idx] == 0:
                return True
            for next_idx in [curr_idx + arr[curr_idx], curr_idx - arr[curr_idx]]:
                if 0 <= next_idx < len(arr):
                    if next_idx not in visited:
                        q.append(next_idx)
                        visited.add(next_idx)
        return False