human
Maximize the minimum array element by M subarray increments of size S | Function to return index of minimum element in the array.
Initialize a [ 0 ] as minValue.
Traverse the array.
If a [ i ] < existing minValue.
Return the minimum index.
Function that maximize the minimum element of array after incrementing subarray of size S by 1 , M times.
Iterating through the array for M times.
Find minimum element index.
Increment the minimum value.
Storing the left index and right index.
Incrementing S - 1 minimum elements to the left and right of minValue.
Reached extreme left.
Reached extreme right.
Left value is minimum.
Right value is minimum.
Find the minValue in A [ ] after M operations.
Return the minimum value.
Driver Code.
Function Call"
How can the above be solved in Python?
 ... Write me a code to maximize the minimum array element by M subarray increments of size S and the other steps required?
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#Here is code to maximize the minimum array element by M subarray increments of size S and the other steps required.
 def min ( a , n ) :
	minIndex = 0
	minValue = a [ 0 ]
	for i in range ( 1 , n ) :
		if ( a [ i ] < minValue ) :
			minValue = a [ i ]
			minIndex = i
	return minIndex
def maximizeMin ( A , N , S , M ) :
	minIndex , left , right = 0 , 0 , 0
	for i in range ( M ) :
		minIndex = min ( A , N )
		A [ minIndex ] += 1
		left = minIndex - 1
		right = minIndex + 1
		for j in range ( S - 1 ) :
			if ( left == - 1 ) :
				A [ right ] += 1
				right += 1
			elif ( right == N ) :
				A [ left ] += 1
				left -= 1
			else :
				if ( A [ left ] < A [ right ] ) :
					A [ left ] += 1
					left -= 1
				else :
					A [ right ] += 1
					right += 1
	minIndex = min ( A , N )
	return A [ minIndex ]
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 3 , 4 , 5 , 6 ]
	N = len ( arr )
	S = 2
	M = 3
	print ( maximizeMin ( arr , N , S , M ) )