human
Print string of odd length in ' X ' format | Function to print given string in cross pattern.
i and j are the indexes of characters to be displayed in the ith iteration i = 0 initially and go upto length of string j = length of string initially in each iteration of i , we increment i and decrement j , we print character only of k == i or k == j.
driver code"
Solution in Python:
 Give me a code to print string of odd length in ' X ' format and the other steps required?
assistant
#Here is code to print string of odd length in ' X ' format and the other steps required.
 def pattern ( st , length ) :
	for i in range ( length ) :
		j = length - 1 - i
		for k in range ( length ) :
			if ( k == i or k == j ) :
				print ( st [ k ] , end = " " )
			else :
				print ( " ▁ " , end = " " )
		print ( )
if __name__ == " _ _ main _ _ " :
	st = " geeksforgeeks "
	length = len ( st )
	pattern ( st , length )