human
Can you provide a the Python program you requested given the following:
Solve in Python:
You are given a series of video clips from a sporting event that lasted T seconds.  These video clips can be overlapping with each other and have varied lengths.
Each video clip clips[i] is an interval: it starts at time clips[i][0] and ends at time clips[i][1].  We can cut these clips into segments freely: for example, a clip [0, 7] can be cut into segments [0, 1] + [1, 3] + [3, 7].
Return the minimum number of clips needed so that we can cut the clips into segments that cover the entire sporting event ([0, T]).  If the task is impossible, return -1.
 
Example 1:
Input: clips = [[0,2],[4,6],[8,10],[1,9],[1,5],[5,9]], T = 10
Output: 3
Explanation: 
We take the clips [0,2], [8,10], [1,9].
a total of 3 clips.
Then, we can reconstruct the sporting event as follows:
We cut [1,9] into segments [1,2] + [2,8] + [8,9].
Now we have segments [0,2] + [2,8] + [8,10] which cover the sporting event [0, 10].

Example 2:
Input: clips = [[0,1],[1,2]], T = 5
Output: -1
Explanation: 
We can't cover [0,5] with only [0,1] and [1,2].

Example 3:
Input: clips = [[0,1],[6,8],[0,2],[5,6],[0,4],[0,3],[6,7],[1,3],[4,7],[1,4],[2,5],[2,6],[3,4],[4,5],[5,7],[6,9]], T = 9
Output: 3
Explanation: 
We can take clips [0,4], [4,7], and [6,9].

Example 4:
Input: clips = [[0,4],[2,8]], T = 5
Output: 2
Explanation: 
Notice you can have extra video after the event ends.

 
Constraints:

1 <= clips.length <= 100
0 <= clips[i][0] <= clips[i][1] <= 100
0 <= T <= 100
assistant
#Here is the Python program you requested.

import math

class Solution:
    def videoStitching(self, clips: List[List[int]], T: int) -> int:
        clips.sort()
        longest = sorted(clips, key=lambda a: a[1])[-1][1]
        memo = [[None for i in range(longest + 1)] for i in range(len(clips))]
        
        def dp(i, start):
            if start >= T:
                return 0
            
            curr = clips[i]
            if curr[0] > start:
                return math.inf
            elif i == len(clips) - 1:
                if curr[1] < T:
                    return math.inf
                return 1
            
            # Pick first clip
            if memo[i + 1][curr[1]] == None:
                memo[i + 1][curr[1]] = dp(i + 1, curr[1])
            
            #Don't pick first clip
            if memo[i + 1][start] == None:
                memo[i + 1][start] = dp(i + 1, start)
            
            return min(1 + memo[i + 1][curr[1]], memo[i + 1][start])
        
        res = dp(0, 0)
        return res if res != math.inf else -1