human
Number of pairs with Pandigital Concatenation | Checks if a given is Pandigital.
digit i is not present thus not pandigital.
Returns number of pairs of strings resulting in Pandigital Concatenations.
iterate over all pair of strings.
Driver code"
How can the above be solved in Python?

=====
Give me a code to number of pairs with Pandigital Concatenation and the other steps required?
assistant
#Here is code to number of pairs with Pandigital Concatenation and the other steps required.
 def isPanDigital ( s ) :
	digits = [ False ] * 10 ;
	for i in range ( 0 , len ( s ) ) :
		digits [ int ( s [ i ] ) - int ( '0' ) ] = True
	for i in range ( 0 , 10 ) :
		if ( digits [ i ] == False ) :
			return False
	return True
def countPandigitalPairs ( v ) :
	pairs = 0
	for i in range ( 0 , len ( v ) ) :
		for j in range ( i + 1 , len ( v ) ) :
			if ( isPanDigital ( v [ i ] + v [ j ] ) ) :
				pairs = pairs + 1
	return pairs
v = [ "123567" , "098234" , "14765" , "19804" ]
print ( countPandigitalPairs ( v ) )