human
Maximum elements which can be crossed using given units of a and b | Function to find the number of elements crossed.
Keep a copy of a.
Iterate in the binary array.
If no a and b left to use.
If there is no a.
use b and increase a by 1 if arr [ i ] is 1.
simply use b.
Use a if theres no b.
Increase a and use b if arr [ i ] == 1.
Use a.
Driver code"
Solution in Python:
assistant
#Here is code to maximum elements which can be crossed using given units of a and b and the other steps required.
 def findElementsCrossed ( arr , a , b , n ) :
	aa = a
	ans = 0
	for i in range ( n ) :
		if ( a == 0 and b == 0 ) :
			break
		elif ( a == 0 ) :
			if ( arr [ i ] == 1 ) :
				b -= 1
				a = min ( aa , a + 1 )
			else :
				b -= 1
		elif ( b == 0 ) :
			a -= 1
		elif ( arr [ i ] == 1 and a < aa ) :
			b -= 1
			a = min ( aa , a + 1 )
		else :
			a -= 1
		ans += 1
	return ans
arr = [ 1 , 0 , 0 , 1 , 0 , 1 ]
n = len ( arr )
a = 1
b = 2
print ( findElementsCrossed ( arr , a , b , n ) )