human
I found an interesting problem on https://leetcode.com/problems/angle-between-hands-of-a-clock/:
Given two numbers, hour and minutes. Return the smaller angle (in degrees) formed between the hour and the minute hand.
 
Example 1:

Input: hour = 12, minutes = 30
Output: 165

Example 2:

Input: hour = 3, minutes = 30
Output: 75

Example 3:

Input: hour = 3, minutes = 15
Output: 7.5

Example 4:
Input: hour = 4, minutes = 50
Output: 155

Example 5:
Input: hour = 12, minutes = 0
Output: 0

 
Constraints:

1 <= hour <= 12
0 <= minutes <= 59
Answers within 10^-5 of the actual value will be accepted as correct.

I tried it in Python, but could not do it. Can you solve it?

 Can you provide a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        angle_per_min = 360/(60)
        angle_per_5_min = 5*angle_per_min

        h = hour%12 + minutes/60
        hr_angle = h*angle_per_5_min
        min_angle = minutes*angle_per_min

        # print(f'h={h}, minutes={minutes}, hr_angle={hr_angle}, min_angle={min_angle}')
        r = abs(hr_angle-min_angle)
        return min(360-r, r)