human
Find the n | utility function which is used to convert binary string into integer.
convert binary string into integer.
function to find nth binary palindrome number.
stores the binary palindrome string.
base case.
add 2 nd binary palindrome string.
runs till the nth binary palindrome number.
remove curr binary palindrome string from queue.
if n == 0 then we find the n 'th binary  palindrome so we return our answer.
calculate length of curr binary palindrome string.
if length is even . so it is our first case we have two choices.
if length is odd . so it is our second case we have only one choice.
Driver code.
Function Call"
How can the above be solved in Python?

Can you provide a code to find the n and the other steps required?
assistant
#Here is code to find the n and the other steps required.
 def convertStringToInt ( s ) :
	ans = 0
	for i in range ( len ( s ) ) :
		ans = ans * 2 + ( ord ( s [ i ] ) - ord ( '0' ) )
	return ans
def getNthNumber ( n ) :
	q = [ ]
	if ( n == 1 ) :
		return 1
	n = n - 1
	q . append ( "11" )
	while ( len ( q ) != 0 ) :
		curr = q . pop ( 0 )
		n -= 1
		if ( n == 0 ) :
			return convertStringToInt ( curr )
		lenn = len ( curr )
		if ( len ( curr ) % 2 == 0 ) :
			q . append ( curr [ 0 : int ( lenn / 2 ) ] + "0" + curr [ int ( lenn / 2 ) : ] )
			q . append ( curr [ 0 : int ( lenn / 2 ) ] + "1" + curr [ int ( lenn / 2 ) : ] )
		else :
			midChar = curr [ int ( lenn / 2 ) ]
			q . append ( curr [ 0 : int ( lenn / 2 ) ] + midChar + curr [ int ( lenn / 2 ) : ] )
	return 0
n = 9
print ( getNthNumber ( n ) )