human
Program to print ' N ' alphabet using the number pattern from 1 to n | Function to print the desired Alphabet N Pattern.
Declaring the values of Right , Left and Diagonal values.
Main Loop for the rows.
For the left Values.
Spaces for the diagonals.
Condition for the diagonals.
Spaces for the Right Values.
For the right values.
Driver Code.
Size of the Pattern.
Calling the function to print the desired Pattern"
How can the above be solved in Python?
assistant
#Here is code to program to print ' N ' alphabet using the number pattern from 1 to n and the other steps required.
 def Alphabet_N_Pattern ( N ) :
	Right = 1
	Left = 1
	Diagonal = 2
	for index in range ( N ) :
		print ( Left , end = " " )
		Left += 1
		for side_index in range ( 0 , 2 * ( index ) , 1 ) :
			print ( " ▁ " , end = " " )
		if ( index != 0 and index != N - 1 ) :
			print ( Diagonal , end = " " )
			Diagonal += 1
		else :
			print ( " ▁ " , end = " " )
		for side_index in range ( 0 , 2 * ( N - index - 1 ) , 1 ) :
			print ( " ▁ " , end = " " )
		print ( Right , end = " " )
		Right += 1
		print ( " " , ▁ end ▁ = ▁ " " )
if __name__ == ' _ _ main _ _ ' :
	Size = 6
	Alphabet_N_Pattern ( Size )