human
Maximize count of 3 | Function to count the maximum number of palindrome subsequences of length 3 considering the same index only once.
Index of the S.
Stores the frequency of every character.
Stores the pair of frequency containing same characters.
Number of subsequences having length 3.
Counts the frequency.
Counts the pair of frequency.
Returns the minimum value.
Driver Code"
How can the above be solved in Python?
 ... Can you provide a code to maximize count of 3 and the other steps required?
assistant
#Here is code to maximize count of 3 and the other steps required.
 def maxNumPalindrome ( S ) :
	i = 0
	freq = [ 0 ] * 26
	freqPair = 0
	ln = len ( S ) // 3
	while ( i < len ( S ) ) :
		freq [ ord ( S [ i ] ) - ord ( ' a ' ) ] += 1
		i += 1
	for i in range ( 26 ) :
		freqPair += ( freq [ i ] // 2 )
	return min ( freqPair , ln )
if __name__ == ' _ _ main _ _ ' :
	S = " geeksforg "
	print ( maxNumPalindrome ( S ) )