human
Check if a string is the typed name of the given name | Check if the character is vowel or not.
Returns true if ' typed ' is a typed name given str.
Traverse through all characters of str.
If current characters do not match.
If not vowel , simply move ahead in both.
Count occurrences of current vowel in str.
Count occurrence of current vowel in typed.
Driver code"
How can the above be solved in Python?
 Can you provide a code to check if a string is the typed name of the given name and the other steps required?
assistant
#Here is code to check if a string is the typed name of the given name and the other steps required.
 def isVowel ( c ) :
	vowel = " aeiou "
	for i in range ( len ( vowel ) ) :
		if ( vowel [ i ] == c ) :
			return True
	return False
def printRLE ( str , typed ) :
	n = len ( str )
	m = len ( typed )
	j = 0
	for i in range ( n ) :
		if str [ i ] != typed [ j ] :
			return False
		if isVowel ( str [ i ] ) == False :
			j = j + 1
			continue
		count1 = 1
		while ( i < n - 1 and ( str [ i ] == str [ i + 1 ] ) ) :
			count1 = count1 + 1
			i = i + 1
		count2 = 1
		while ( j < m - 1 and typed [ j ] == str [ i ] ) :
			count2 = count2 + 1
			j = j + 1
		if count1 > count2 :
			return False
	return True
name = " alex "
typed = " aaalaeex "
if ( printRLE ( name , typed ) ) :
	print ( " Yes " )
else :
	print ( " No " )