human
Length of smallest subarray required to be removed to make remaining elements consecutive | Function to find the length of the smallest subarray to be removed to make remaining array elements consecutive.
Store the ending index of the longest prefix consecutive array.
Traverse the array to find the longest prefix consecutive sequence.
A [ 0. . . left_index ] is the prefix consecutive sequence.
Store the starting index of the longest suffix consecutive sequence.
Traverse the array to find the longest suffix consecutive sequence.
A [ right_index ... N - 1 ] is the consecutive sequence.
Store the smallest subarray required to be removed.
Check if subarray from the middle can be removed.
Update the right index s . t . A [ 0 , N - 1 ] is consecutive.
If updated_right < N , then update the minimumLength.
Print the required result.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to length of smallest subarray required to be removed to make remaining elements consecutive and the other steps required.
 def shortestSubarray ( A , N ) :
	i = 0
	left_index = 0
	for i in range ( N - 1 ) :
		if ( A [ i ] + 1 != A [ i + 1 ] ) :
			break
	left_index = i
	right_index = 0
	i = N - 1
	while ( i >= 1 ) :
		if ( A [ i ] != A [ i - 1 ] + 1 ) :
			break
		i -= 1
	right_index = i
	updated_right = 0
	minLength = min ( N - left_index - 1 , right_index )
	if ( A [ right_index ] <= A [ left_index ] + 1 ) :
		updated_right = ( right_index + A [ left_index ] - A [ right_index ] + 1 )
		if ( updated_right < N ) :
			minLength = min ( minLength , updated_right - left_index - 1 )
	print ( minLength )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 3 , 7 , 4 , 3 , 5 ]
	N = len ( arr )
	shortestSubarray ( arr , N )