human
Count all possible paths from top left to bottom right of a Matrix without crossing the diagonal | Function to calculate Binomial Coefficient C ( n , r ).
C ( n , r ) = C ( n , n - r ).
[ n * ( n - 1 ) * -- - * ( n - r + 1 ) ] / [ r * ( r - 1 ) * -- -- * 1 ].
Function to calculate the total possible paths.
Update n to n - 1.
Stores 2 nCn.
Stores Nth Catalan number.
Stores the required answer.
Driver Code"
How can the above be solved in Python?
 Can you provide a code to count all possible paths from top left to bottom right of a Matrix without crossing the diagonal and the other steps required?
assistant
#Here is code to count all possible paths from top left to bottom right of a Matrix without crossing the diagonal and the other steps required.
 def binCoff ( n , r ) :
	val = 1
	if ( r > ( n - r ) ) :
		r = ( n - r )
	for i in range ( r ) :
		val *= ( n - i )
		val //= ( i + 1 )
	return val
def findWays ( n ) :
	n = n - 1
	a = binCoff ( 2 * n , n )
	b = a // ( n + 1 )
	ans = b
	return ans
if __name__ == " _ _ main _ _ " :
	n = 4
	print ( findWays ( n ) )