human
Maximize difference between the Sum of the two halves of the Array after removal of N elements | Function to print the maximum difference possible between the two halves of the array.
Stores n maximum values from the start.
Insert first n elements.
Update sum of largest n elements from left.
For the remaining elements.
Obtain minimum value in the set.
Insert only if it is greater than minimum value.
Update sum from left.
Remove the minimum.
Insert the current element.
Clear the set.
Store n minimum elements from the end.
Insert the last n elements.
Update sum of smallest n elements from right.
For the remaining elements.
Obtain the minimum.
Insert only if it is smaller than maximum value.
Update sum from right.
Remove the minimum.
Insert the new element.
Compare the difference and store the maximum.
Return the maximum possible difference.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to maximize difference between the Sum of the two halves of the Array after removal of N elements and the other steps required.
 def FindMaxDif ( a , m ) :
	n = m // 3
	l = [ 0 ] * ( m + 5 )
	r = [ 0 ] * ( m + 5 )
	s = [ ]
	for i in range ( 1 , m + 1 ) :
		if ( i <= n ) :
			l [ i ] = a [ i - 1 ] + l [ i - 1 ]
			s . append ( a [ i - 1 ] )
		else :
			l [ i ] = l [ i - 1 ]
			s . sort ( )
			d = s [ 0 ]
			if ( a [ i - 1 ] > d ) :
				l [ i ] -= d
				l [ i ] += a [ i - 1 ]
				s . remove ( d )
				s . append ( a [ i - 1 ] )
	s . clear ( )
	for i in range ( m , 0 , - 1 ) :
		if ( i >= m - n + 1 ) :
			r [ i ] = a [ i - 1 ] + r [ i + 1 ]
			s . append ( a [ i - 1 ] )
		else :
			r [ i ] = r [ i + 1 ]
			s . sort ( )
			d = s [ - 1 ]
			if ( a [ i - 1 ] < d ) :
				r [ i ] -= d
				r [ i ] += a [ i - 1 ]
				s . remove ( d )
				s . append ( a [ i - 1 ] )
	ans = - 9e18
	for i in range ( n , m - n + 1 ) :
		ans = max ( ans , l [ i ] - r [ i + 1 ] )
	return ans
vtr = [ 3 , 1 , 4 , 1 , 5 , 9 ]
n = len ( vtr )
print ( FindMaxDif ( vtr , n ) )