human
Can you provide a code to find the number in a range having maximum product of the digits and the other steps required given the following:
Find the number in a range having maximum product of the digits | Returns the product of digits of number x.
This function returns the number having maximum product of the digits.
Converting both integers to strings.
Let the current answer be r.
Stores the current number having current digit one less than current digit in b.
Replace all following digits with 9 to maximise the product.
Convert string to number.
Check if it lies in range and its product is greater than max product.
Driver Code"
Solution in Python:
assistant
#Here is code to find the number in a range having maximum product of the digits and the other steps required.
 def product ( x ) :
	prod = 1
	while ( x ) :
		prod *= ( x % 10 )
		x //= 10 ;
	return prod
def findNumber ( l , r ) :
	a = str ( l ) ;
	b = str ( r ) ;
	ans = r
	for i in range ( len ( b ) ) :
		if ( b [ i ] == '0' ) :
			continue
		curr = list ( b )
		curr [ i ] = str ( ( ( ord ( curr [ i ] ) - ord ( '0' ) ) - 1 ) + ord ( '0' ) )
		for j in range ( i + 1 , len ( curr ) ) :
			curr [ j ] = str ( ord ( '9' ) )
		num = 0
		for c in curr :
			num = num * 10 + ( int ( c ) - ord ( '0' ) )
		if ( num >= l and product ( ans ) < product ( num ) ) :
			ans = num
	return ans
if __name__ == " _ _ main _ _ " :
	l , r = 1 , 10
	print ( findNumber ( l , r ) )
	l , r = 51 , 62
	print ( findNumber ( l , r ) )