human
Segmented Sieve | This functions finds all primes smaller than ' limit ' using simple sieve of eratosthenes ..
Create a boolean array " mark [ 0 . . limit - 1 ] " and initialize all entries of it as true . A value in mark [ p ] will finally be false if ' p ' is Not a prime , else true ..
One by one traverse all numbers so that their multiples can be marked as composite ..
If p is not changed , then it is a prime.
Update all multiples of p.
Print all prime numbers and store them in prime"
How can the above be solved in Python?
assistant
#Here is code to segmented Sieve and the other steps required.
 def simpleSieve ( limit ) :
	mark = [ True for i in range ( limit ) ]
	for p in range ( p * p , limit - 1 , 1 ) :
		if ( mark [ p ] == True ) :
			for i in range ( p * p , limit - 1 , p ) :
				mark [ i ] = False
	for p in range ( 2 , limit - 1 , 1 ) :
		if ( mark [ p ] == True ) :
			print ( p , end = " ▁ " )