human
Maximum product of indexes of next greater on left and right | Method to find the next greater value in left side.
Checking if current element is greater than top.
Pop the element till we can 't  get the larger value then  the current value.
Else push the element in the stack.
Method to find the next greater value in right.
Checking if current element is greater than top.
Pop the element till we can 't  get the larger value then  the current value.
Else push the element in the stack.
For each element storing the index of just greater element in left side.
For each element storing the index of just greater element in right side.
Finding the max index product.
Driver Code"
How can the above be solved in Python?

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What is a code to maximum product of indexes of next greater on left and right and the other steps required?
assistant
#Here is code to maximum product of indexes of next greater on left and right and the other steps required.
 def nextGreaterInLeft ( a ) :
	left_index = [ 0 ] * len ( a )
	s = [ ]
	for i in range ( len ( a ) ) :
		while len ( s ) != 0 and a [ i ] >= a [ s [ - 1 ] ] :
			s . pop ( )
		if len ( s ) != 0 :
			left_index [ i ] = s [ - 1 ]
		else :
			left_index [ i ] = 0
		s . append ( i )
	return left_index
def nextGreaterInRight ( a ) :
	right_index = [ 0 ] * len ( a )
	s = [ ]
	for i in range ( len ( a ) - 1 , - 1 , - 1 ) :
		while len ( s ) != 0 and a [ i ] >= a [ s [ - 1 ] ] :
			s . pop ( )
		if len ( s ) != 0 :
			right_index [ i ] = s [ - 1 ]
		else :
			right_index [ i ] = 0
		s . append ( i )
	return right_index
def LRProduct ( arr ) :
	left = nextGreaterInLeft ( arr )
	right = nextGreaterInRight ( arr )
	ans = - 1
	for i in range ( 1 , len ( left ) - 1 ) :
		if left [ i ] == 0 or right [ i ] == 0 :
			ans = max ( ans , 0 )
		else :
			temp = ( left [ i ] + 1 ) * ( right [ i ] + 1 )
			ans = max ( ans , temp )
	return ans
arr = [ 5 , 4 , 3 , 4 , 5 ]
print ( LRProduct ( arr ) )