human
Write me a code to largest lexicographical string with at most K consecutive elements and the other steps required given the following:
Largest lexicographical string with at most K consecutive elements | Function to find the largest lexicographical string with given constraints ..
Vector containing frequency of each character ..
Assigning frequency to.
Empty string of string class type.
Loop to iterate over maximum priority first ..
If frequency is greater than or equal to k ..
Temporary variable to operate in - place of k ..
concatenating with the resultant string ans ..
Handling k case by adjusting with just smaller priority element ..
Condition to verify if index j does have frequency greater than 0.
.
if no such element is found than string can not be processed further ..
If frequency is greater than 0 and less than k ..
Here we don 't need to fix K  consecutive element criteria..
Otherwise check for next possible element ..
Driver code"
How can the above be solved in Python?
assistant
#Here is code to largest lexicographical string with at most K consecutive elements and the other steps required.
 def getLargestString ( s , k ) :
	frequency_array = [ 0 ] * 26
	for i in range ( len ( s ) ) :
		frequency_array [ ord ( s [ i ] ) - ord ( ' a ' ) ] += 1
	ans = " "
	i = 25
	while i >= 0 :
		if ( frequency_array [ i ] > k ) :
			temp = k
			st = chr ( i + ord ( ' a ' ) )
			while ( temp > 0 ) :
				ans += st
				temp -= 1
			frequency_array [ i ] -= k
			j = i - 1
			while ( frequency_array [ j ] <= 0 and j >= 0 ) :
				j -= 1
			if ( frequency_array [ j ] > 0 and j >= 0 ) :
				str1 = chr ( j + ord ( ' a ' ) )
				ans += str1
				frequency_array [ j ] -= 1
			else :
				break
		elif ( frequency_array [ i ] > 0 ) :
			temp = frequency_array [ i ]
			frequency_array [ i ] -= temp
			st = chr ( i + ord ( ' a ' ) )
			while ( temp > 0 ) :
				ans += st
				temp -= 1
		else :
			i -= 1
	return ans
if __name__ == " _ _ main _ _ " :
	S = " xxxxzza "
	k = 3
	print ( getLargestString ( S , k ) )