human
Count pairs with Odd XOR | A function will return number of pair whose XOR is odd.
To store count of XOR pair.
If XOR is odd increase count.
Return count.
Driver Code"
How can the above be solved in Python?
 ... What is a code to count pairs with Odd XOR and the other steps required?
assistant
#Here is code to count pairs with Odd XOR and the other steps required.
 def countXorPair ( arr , n ) :
	count = 0
	for i in range ( n ) :
		for j in range ( i + 1 , n ) :
			if ( ( arr [ i ] ^ arr [ j ] ) % 2 == 1 ) :
				count += 1
	return count
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 ]
	n = len ( arr )
	print ( countXorPair ( arr , n ) )