human
Check whether the string S1 can be made equal to S2 with the given operation | Function to return the string formed by the odd indexed characters of s.
Function to return the string formed by the even indexed characters of s.
Function that returns true if s1 can be made equal to s2 with the given operation.
Get the string formed by the even indexed characters of s1.
Get the string formed by the even indexed characters of s2.
Get the string formed by the odd indexed characters of s1.
Get the string formed by the odd indexed characters of s2.
Sorting all the lists.
If the strings can be made equal.
Driver code"
Solution in Python:
 What is a code to check whether the string S1 can be made equal to S2 with the given operation and the other steps required?
assistant
#Here is code to check whether the string S1 can be made equal to S2 with the given operation and the other steps required.
 def partOdd ( s ) :
	odd = [ ]
	for i in range ( len ( s ) ) :
		if i % 2 != 0 :
			odd . append ( s [ i ] )
	return odd
def partEven ( s ) :
	even = [ ]
	for i in range ( len ( s ) ) :
		if i % 2 == 0 :
			even . append ( s [ i ] )
	return even
def canBeMadeEqual ( s1 , s2 ) :
	even_s1 = partEven ( s1 )
	even_s2 = partEven ( s2 )
	odd_s1 = partOdd ( s1 )
	odd_s2 = partOdd ( s2 )
	even_s1 . sort ( )
	even_s2 . sort ( )
	odd_s1 . sort ( )
	odd_s2 . sort ( )
	if even_s1 == even_s2 and odd_s1 == odd_s2 :
		return True
	return False
s1 = " cdab "
s2 = " abcd "
if canBeMadeEqual ( s1 , s2 ) :
	print ( " Yes " )
else :
	print ( " No " )