human
Length of the longest subsequence such that XOR of adjacent elements is equal to K | Function to find maximum length of subsequence.
Stores maximum length of subsequence.
HashMap to store the longest length of subsequence ending at an integer , say X.
Stores the maximum length of subsequence ending at index i.
Base case.
Iterate over the range [ 1 , N - 1 ].
If dpj is not NULL.
Update dp [ i ].
Update ans.
Update the maximum length of subsequence ending at element is a [ i ] in HashMap.
Return the ans if ans >= 2. Otherwise , return 0.
Driver Code.
Input.
Print the length of the longest subsequence"
Solution in Python:
 Give me a code to length of the longest subsequence such that XOR of adjacent elements is equal to K and the other steps required?
assistant
#Here is code to length of the longest subsequence such that XOR of adjacent elements is equal to K and the other steps required.
 def xorSubsequence ( a , n , k ) :
	ans = 0
	map = { }
	dp = [ 0 ] * n
	map [ a [ 0 ] ] = 1
	dp [ 0 ] = 1
	for i in range ( 1 , n ) :
		if ( a [ i ] ^ k in map ) :
			dp [ i ] = max ( dp [ i ] , map [ a [ i ] ^ k ] + 1 )
		ans = max ( ans , dp [ i ] )
		if a [ i ] in map :
			map [ a [ i ] ] = max ( map [ a [ i ] ] , dp [ i ] )
		else :
			map [ a [ i ] ] = max ( 1 , dp [ i ] )
	if ans >= 2 :
	return ans
	return 0
if __name__ == " _ _ main _ _ " :
	arr = [ 3 , 2 , 4 , 3 , 5 ]
	N = len ( arr )
	K = 1
	print ( xorSubsequence ( arr , N , K ) )