human
Can you provide a code to find a peak element and the other steps required given the following:
Find a peak element | A binary search based function that returns index of a peak element.
Find index of middle element ( low + high ) / 2.
Compare middle element with its neighbours ( if neighbours exist ).
If middle element is not peak and its left neighbour is greater than it , then left half must have a peak element.
If middle element is not peak and its right neighbour is greater than it , then right half must have a peak element.
A wrapper over recursive function findPeakUtil ( ).
Driver code"
Solution in Python:
assistant
#Here is code to find a peak element and the other steps required.
 def findPeakUtil ( arr , low , high , n ) :
	mid = low + ( high - low ) / 2
	mid = int ( mid )
	if ( ( mid == 0 or arr [ mid - 1 ] <= arr [ mid ] ) and ( mid == n - 1 or arr [ mid + 1 ] <= arr [ mid ] ) ) :
		return mid
	elif ( mid > 0 and arr [ mid - 1 ] > arr [ mid ] ) :
		return findPeakUtil ( arr , low , ( mid - 1 ) , n )
	else :
		return findPeakUtil ( arr , ( mid + 1 ) , high , n )
def findPeak ( arr , n ) :
	return findPeakUtil ( arr , 0 , n - 1 , n )
arr = [ 1 , 3 , 20 , 4 , 1 , 0 ]
n = len ( arr )
print ( " Index ▁ of ▁ a ▁ peak ▁ point ▁ is " , findPeak ( arr , n ) )