human
Write me a code to longest subarray with GCD greater than 1 and the other steps required given the following:
Longest subarray with GCD greater than 1 | Function to build the Segment Tree from the given array to process range queries in log ( N ) time.
Termination Condition.
Find the mid value.
Left and Right Recursive Call.
Update the Segment Tree Node.
Function to return the GCD of the elements of the Array from index l to index r.
Base Case.
Find the middle range.
Find the GCD and return.
Function to print maximum length of the subarray having GCD > one.
Stores the Segment Tree.
Function call to build the Segment tree from array [ ] arr.
Store maximum length of subarray.
Starting and ending pointer of the current window.
Case where the GCD of the current window is 1.
Update the maximum length.
Print answer.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to longest subarray with GCD greater than 1 and the other steps required.
 def build_tree ( b , seg_tree , l , r , vertex ) :
	if ( l == r ) :
		seg_tree [ vertex ] = b [ l ]
		return
	mid = int ( ( l + r ) / 2 )
	build_tree ( b , seg_tree , l , mid , 2 * vertex )
	build_tree ( b , seg_tree , mid + 1 , r , 2 * vertex + 1 )
	seg_tree [ vertex ] = __gcd ( seg_tree [ 2 * vertex ] , seg_tree [ 2 * vertex + 1 ] )
def __gcd ( a , b ) :
	if b == 0 :
		return b
	else :
		return __gcd ( b , a % b )
def range_gcd ( seg_tree , v , tl , tr , l , r ) :
	if ( l > r ) :
		return 0
	if ( l == tl and r == tr ) :
		return seg_tree [ v ]
	tm = int ( ( tl + tr ) / 2 )
	return __gcd ( range_gcd ( seg_tree , 2 * v , tl , tm , l , min ( tm , r ) ) , range_gcd ( seg_tree , 2 * v + 1 , tm + 1 , tr , max ( tm + 1 , l ) , r ) )
def maxSubarrayLen ( arr , n ) :
	seg_tree = [ 0 ] * ( 4 * n + 1 )
	build_tree ( arr , seg_tree , 0 , n - 1 , 1 )
	maxLen = 0
	l , r = 0 , 0
	while ( r < n and l < n ) :
		if ( range_gcd ( seg_tree , 1 , 0 , n - 1 , l , r ) == 1 ) :
			l += 1
		maxLen = max ( maxLen , r - l - 1 )
		r += 1
	print ( maxLen , end = " " )
arr = [ 410 , 52 , 51 , 180 , 222 , 33 , 33 ]
N = len ( arr )
maxSubarrayLen ( arr , N )