human
Find the player with least 0 s after emptying a Binary String by removing non | Function to find the player who wins the game.
Stores total count of 0 s in the string.
Stores count of consecutive 1 s.
Stores Nim - Sum on count of consecutive 1 s.
Stores length of the string.
Traverse the string.
If the current character is 1.
Update cntConOne.
Update nimSum.
Update cntConOne.
Update cntZero.
Update nimSum.
If countZero is an even number.
nimSum is not 0.
If nimSum is zero.
Driver Code"
Solution in Python:

Give me a code to find the player with least 0 s after emptying a Binary String by removing non and the other steps required?
assistant
#Here is code to find the player with least 0 s after emptying a Binary String by removing non and the other steps required.
 def FindwinnerOfGame ( S ) :
	cntZero = 0
	cntConOne = 0
	nimSum = 0
	N = len ( S )
	for i in range ( N ) :
		if ( S [ i ] == '1' ) :
			cntConOne += 1
		else :
			nimSum ^= cntConOne
			cntConOne = 0
			cntZero += 1
	nimSum ^= cntConOne
	if ( cntZero % 2 == 0 ) :
		print ( " Tie " )
	elif ( nimSum ) :
		print ( " player ▁ 1" )
	else :
		print ( " player ▁ 2" )
if __name__ == ' _ _ main _ _ ' :
	S = "0110011"
	FindwinnerOfGame ( S )