human
Solve in Python:
Given an array A of 0s and 1s, we may change up to K values from 0 to 1.
Return the length of the longest (contiguous) subarray that contains only 1s. 
 

Example 1:
Input: A = [1,1,1,0,0,0,1,1,1,1,0], K = 2
Output: 6
Explanation: 
[1,1,1,0,0,1,1,1,1,1,1]
Bolded numbers were flipped from 0 to 1.  The longest subarray is underlined.

Example 2:
Input: A = [0,0,1,1,0,0,1,1,1,0,1,1,0,0,0,1,1,1,1], K = 3
Output: 10
Explanation: 
[0,0,1,1,1,1,1,1,1,1,1,1,0,0,0,1,1,1,1]
Bolded numbers were flipped from 0 to 1.  The longest subarray is underlined.

 
Note:

1 <= A.length <= 20000
0 <= K <= A.length
A[i] is 0 or 1

Give me a the Python code you requested?
assistant
#Here is the Python code you requested.

class Solution:
    def longestOnes(self, A: List[int], K: int) -> int:
        res = 0
        start, end = 0, 0
        cnt = 0
        while end < len(A) and start < len(A):
            if A[end] == 1:
                res = max(res, end - start + 1)
                end += 1
            elif A[end] == 0 and cnt < K:
                res = max(res, end - start + 1)
                cnt += 1
                end += 1
            else:
                if A[start] == 0 and K > 0:
                    cnt -= 1
                start += 1
                if start > end:
                    end = start
        return res