human
Largest number smaller than or equal to n and digits in non | Prints the largest number smaller than s and digits in non - decreasing order ..
array to store digits of number.
conversion of characters of string int number.
variable holds the value of index after which all digits are set 9.
Checking the condition if the digit is less than its left digit.
If first digit is 0 no need to print it.
Driver Code"
How can the above be solved in Python?

Give me a code to largest number smaller than or equal to n and digits in non and the other steps required?
assistant
#Here is code to largest number smaller than or equal to n and digits in non and the other steps required.
 def nondecdigits ( s ) :
	m = len ( s ) ;
	a = [ 0 ] * m ;
	for i in range ( m ) :
		a [ i ] = ord ( s [ i ] ) - ord ( '0' ) ;
	level = m - 1 ;
	for i in range ( m - 1 , 0 , - 1 ) :
		if ( a [ i ] < a [ i - 1 ] ) :
			a [ i - 1 ] -= 1 ;
			level = i - 1 ;
	if ( a [ 0 ] != 0 ) :
		for i in range ( level + 1 ) :
			print ( a [ i ] , end = " " ) ;
		for i in range ( level + 1 , m ) :
			print ( "9" , end = " " ) ;
	else :
		for i in range ( 1 , level ) :
			print ( a [ i ] , end = " " ) ;
		for i in range ( level + 1 , m ) :
			print ( "9" , end = " " ) ;
n = "200" ;
nondecdigits ( n ) ;