human
Can you provide a code to minimum removals required to convert given array to a Mountain Array and the other steps required given the following:
Minimum removals required to convert given array to a Mountain Array | Utility function to count array elements required to be removed to make array a mountain array.
Stores length of increasing subsequence from [ 0 , i - 1 ].
Stores length of increasing subsequence from [ i + 1 , n - 1 ].
Iterate for each position up to N - 1 to find the length of subsequence.
If j is less than i , then i - th position has leftIncreasing [ j ] + 1 lesser elements including itself.
Check if it is the maximum obtained so far.
Search for increasing subsequence from right.
Find the position following the peak condition and have maximum leftIncreasing [ i ] + rightIncreasing [ i ].
Function to count elements to be removed to make array a mountain array.
Print the answer.
Driver Code.
Given array.
Function Call"
Solution in Python:
assistant
#Here is code to minimum removals required to convert given array to a Mountain Array and the other steps required.
 def minRemovalsUtil ( arr ) :
	result = 0
	if ( len ( arr ) < 3 ) :
		return - 1
	leftIncreasing = [ 0 ] * len ( arr )
	rightIncreasing = [ 0 ] * len ( arr )
	for i in range ( 1 , len ( arr ) ) :
		for j in range ( i ) :
			if ( arr [ j ] < arr [ i ] ) :
				leftIncreasing [ i ] = max ( leftIncreasing [ i ] , leftIncreasing [ j ] + 1 ) ;
	for i in range ( len ( arr ) - 2 , - 1 , - 1 ) :
		j = len ( arr ) - 1
		while j > i :
			if ( arr [ j ] < arr [ i ] ) :
				rightIncreasing [ i ] = max ( rightIncreasing [ i ] , rightIncreasing [ j ] + 1 )
			j -= 1
	for i in range ( len ( arr ) ) :
		if ( leftIncreasing [ i ] != 0 and rightIncreasing [ i ] != 0 ) :
			result = max ( result , leftIncreasing [ i ] + rightIncreasing [ i ] ) ;
	return len ( arr ) - ( result + 1 )
def minRemovals ( arr ) :
	ans = minRemovalsUtil ( arr )
	print ( ans )
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 1 , 1 , 5 , 6 , 2 , 3 , 1 ]
	minRemovals ( arr )