human
Can you provide a code to count unordered pairs of equal elements for all subarrays and the other steps required given the following:
Count unordered pairs of equal elements for all subarrays | Function to count all pairs ( i , j ) such that arr [ i ] equals arr [ j ] in all possible subarrays of the array.
Stores the size of the array.
Stores the positions of all the distinct elements.
Append index corresponding to arr [ i ] in the map.
Traverse the map M.
Traverse the array.
Update the value of ans.
Update the value of the sum.
Print the value of ans.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count unordered pairs of equal elements for all subarrays and the other steps required.
 def countPairs ( arr ) :
	N = len ( arr )
	ans = 0
	M = { }
	for i in range ( len ( arr ) ) :
		if arr [ i ] in M :
			M [ arr [ i ] ] . append ( i )
		else :
			M [ arr [ i ] ] = [ i ]
	for key , value in M . items ( ) :
		v = value
		sum1 = 0
		for j in range ( len ( v ) ) :
			ans += ( sum1 * ( N - v [ j ] ) )
			sum1 += v [ j ] + 1
	print ( ans )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 1 , 1 ]
	countPairs ( arr )