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Can you provide a code to minimum flips required to keep all 1 s together in a Binary string and the other steps required given the following:
Minimum flips required to keep all 1 s together in a Binary string | Python implementation for Minimum number of flips required in a binary string such that all the 1 aTMs are together.
Length of the binary string.
Initial state of the dp dp [ 0 ] [ 0 ] will be 1 if the current bit is 1 and we have to flip it.
Initial state of the dp dp [ 0 ] [ 1 ] will be 1 if the current bit is 0 and we have to flip it.
dp [ i ] [ 0 ] = Flips required to make all previous bits zero + Flip required to make current bit zero.
dp [ i ] [ 1 ] = minimum flips required to make all previous states 0 or make previous states 1 satisfying the condition.
Minimum of answer and flips required to make all bits 0.
Driver code"
Solution in Python:
assistant
#Here is code to minimum flips required to keep all 1 s together in a Binary string and the other steps required.
 def minFlip ( a ) :
	n = len ( a )
	dp = [ [ 0 , 0 ] for i in range ( n ) ]
	dp [ 0 ] [ 0 ] = int ( a [ 0 ] == '1' )
	dp [ 0 ] [ 1 ] = int ( a [ 0 ] == '0' )
	for i in range ( 1 , n ) :
		dp [ i ] [ 0 ] = dp [ i - 1 ] [ 0 ] + int ( a [ i ] == '1' )
		dp [ i ] [ 1 ] = min ( dp [ i - 1 ] ) + int ( a [ i ] == '0' )
	answer = 10 ** 18
	for i in range ( n ) :
		answer = min ( answer , dp [ i ] [ 1 ] + dp [ n - 1 ] [ 0 ] - dp [ i ] [ 0 ] )
	return min ( answer , dp [ n - 1 ] [ 0 ] )
s = "1100111000101"
print ( minFlip ( s ) )