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Check if any valid sequence is divisible by M | Function to check if any valid sequence is divisible by M.
DEclare mod array.
Calculate the mod array.
Check if sum is divisible by M.
Check if sum is not divisible by 2.
Remove the first element from the ModArray since it is not possible to place minus on the first element.
Decrease the size of array.
Sort the array.
Loop until the pointer cross each other.
Check if sum becomes equal.
Increase and decrease the pointer accordingly.
Driver code.
Function call"
Solution in Python:

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Can you provide a code to check if any valid sequence is divisible by M and the other steps required?
assistant
#Here is code to check if any valid sequence is divisible by M and the other steps required.
 def func ( n , m , A ) :
	ModArray = [ 0 ] * n
	Sum = 0
	for i in range ( n ) :
		ModArray [ i ] = A [ i ] % m
		Sum += ModArray [ i ]
	Sum = Sum % m
	if ( Sum % m == 0 ) :
		print ( " True " )
		return
	if ( Sum % 2 != 0 ) :
		print ( " False " )
	else :
		ModArray . pop ( 0 )
		i = 0
		j = len ( ModArray ) - 1
		ModArray . sort ( )
		Sum = Sum // 2
		while ( i <= j ) :
			s = ModArray [ i ] + ModArray [ j ]
			if ( s == Sum ) :
				i1 = i
				i2 = j
				print ( " True " )
				break
			elif ( s > Sum ) :
				j -= 1
			else :
				i += 1
m = 2
a = [ 1 , 3 , 9 ]
n = len ( a )
func ( n , m , a )