human
Aspiring Number | Function to calculate sum of all proper divisors.
1 is a proper divisor.
Note that this loop runs till square root of n.
If divisors are equal , take only one of them.
Otherwise take both.
Calculate sum of all proper divisors only.
Function to get last number of Aliquot Sequence ..
Calculate next term from previous term.
Returns true if n is perfect.
To store sum of divisors.
Find all divisors and add them.
If sum of divisors is equal to n , then n is a perfect number.
Returns true if n is aspiring else returns false.
Checking condition for aspiring.
Driver Code"
Solution in Python:
 Write me a code to aspiring Number and the other steps required?
assistant
#Here is code to aspiring Number and the other steps required.
 def getSum ( n ) :
	sum = 0
	for i in range ( 1 , int ( ( n ) ** ( 1 / 2 ) ) + 1 ) :
		if not n % i :
		if n // i == i :
			sum += i
		else :
			sum += i
			sum += ( n // i )
	return sum - n
def getAliquot ( n ) :
	s = set ( )
	s . add ( n )
	next = 0
	while ( n > 0 ) :
		n = getSum ( n )
		if n not in s :
		return n
		s . add ( n )
	return 0
def isPerfect ( n ) :
	sum = 1
	for i in range ( 2 , int ( ( n ** ( 1 / 2 ) ) ) + 1 ) :
		if not n % i :
		sum += ( i + n // i )
	if sum == n and n != 1 :
		return True
	return False
def isAspiring ( n ) :
	alq = getAliquot ( n )
	if ( isPerfect ( alq ) and not isPerfect ( n ) ) :
		return True
	else :
		return False
n = 25
if ( isAspiring ( n ) ) :
	print ( " Aspiring " )
else :
	print ( " Not ▁ Aspiring " )