human
Check if an array can be sorted by swapping pairs from indices consisting of unequal elements in another array | Function to check if array , A [ ] can be converted into sorted array by swapping ( A [ i ] , A [ j ] ) if B [ i ] not equal to B [ j ].
Stores if array A [ ] is sorted in descending order or not.
Traverse the array A [ ].
If A [ i ] is greater than A [ i + 1 ].
Update flag.
If array is sorted in ascending order.
count = 2 : Check if 0 s and 1 s both present in the B [ ].
Traverse the array.
If current element is 0.
Update count.
Traverse the array B [ ].
If current element is 1.
If both 0 s and 1 s are present in the array.
Input array A [ ].
Input array B [ ].
Function call.
If true , print YES.
Else print NO"
How can the above be solved in Python?

What is a code to check if an array can be sorted by swapping pairs from indices consisting of unequal elements in another array and the other steps required?
assistant
#Here is code to check if an array can be sorted by swapping pairs from indices consisting of unequal elements in another array and the other steps required.
 def checkifSorted ( A , B , N ) :
	flag = False
	for i in range ( N - 1 ) :
		if ( A [ i ] > A [ i + 1 ] ) :
		flag = True
		break
	if ( not flag ) :
		return True
	count = 0
	for i in range ( N ) :
		if ( B [ i ] == 0 ) :
		count += 1
		break
	for i in range ( N ) :
		if B [ i ] :
		count += 1
		break
	if ( count == 2 ) :
		return True
	return False
A = [ 3 , 1 , 2 ]
B = [ 0 , 1 , 1 ]
N = len ( A )
check = checkifSorted ( A , B , N )
if ( check ) :
	print ( " YES " )
else :
	print ( " NO " )