human
Can you provide a code to the Stock Span Problem and the other steps required given the following:
The Stock Span Problem | A stack based efficient method to calculate s.
Create a stack and push index of fist element to it.
Span value of first element is always 1.
Calculate span values for rest of the elements.
Pop elements from stack whlie stack is not empty and top of stack is smaller than price [ i ].
If stack becomes empty , then price [ i ] is greater than all elements on left of it , i . e . price [ 0 ] , price [ 1 ] , . . price [ i - 1 ] . Else the price [ i ] is greater than elements after top of stack.
Push this element to stack.
A utility function to print elements of array.
Driver program to test above function.
Fill the span values in array S [ ].
Print the calculated span values"
Solution in Python:
assistant
#Here is code to the Stock Span Problem and the other steps required.
 def calculateSpan ( price , S ) :
	n = len ( price )
	st = [ ]
	st . append ( 0 )
	S [ 0 ] = 1
	for i in range ( 1 , n ) :
		while ( len ( st ) > 0 and price [ st [ - 1 ] ] <= price [ i ] ) :
			st . pop ( )
		S [ i ] = i + 1 if len ( st ) <= 0 else ( i - st [ - 1 ] )
		st . append ( i )
def printArray ( arr , n ) :
	for i in range ( 0 , n ) :
		print ( arr [ i ] , end = " ▁ " )
price = [ 10 , 4 , 5 , 90 , 120 , 80 ]
S = [ 0 for i in range ( len ( price ) + 1 ) ]
calculateSpan ( price , S )
printArray ( S , len ( price ) )