human
Count numbers up to N having Kth bit set | Function to return the count of number of 1 's at ith bit in a range [1, n - 1].
Store count till nearest power of 2 less than N.
If K - th bit is set in N.
Add to result the nearest power of 2 less than N.
Return result.
Driver Code.
Function Call"
How can the above be solved in Python?

Can you provide a code to count numbers up to N having Kth bit set and the other steps required?
assistant
#Here is code to count numbers up to N having Kth bit set and the other steps required.
 def getcount ( n , k ) :
	res = ( n >> ( k + 1 ) ) << k
	if ( ( n >> k ) & 1 ) :
		res += n & ( ( 1 << k ) - 1 )
	return res
if __name__ == ' _ _ main _ _ ' :
	N = 14
	K = 2
	print ( getcount ( N + 1 , K ) )