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Minimum swaps to reach permuted array with at most 2 positions left swaps allowed | This funt merges two sorted arrays and returns inversion count in the arrays ..
i is index for left subarray.
j is index for right subarray.
k is index for resultant merged subarray.
Copy the remaining elements of left subarray ( if there are any ) to temp.
Copy the remaining elements of right subarray ( if there are any ) to temp.
Copy back the merged elements to original array.
An auxiliary recursive function that sorts the input array and returns the number of inversions in the array ..
Divide the array into two parts and call _mergeSortAndCountInv ( ) for each of the parts.
Inversion count will be sum of inversions in left - part , right - part and number of inversions in merging.
Merge the two parts.
This function sorts the input array and returns the number of inversions in the array.
method returns minimum number of swaps to reach permuted array 'arr.
loop over all elements to check Invalid permutation condition.
if an element is at distance more than 2 from its actual position then it is not possible to reach permuted array just by swapping with 2 positions left elements so returning - 1.
If permuted array is not Invalid , then number of Inversion in array will be our final answer.
Driver code to test above methods.
change below example"
Solution in Python:
 ... Can you provide a code to minimum swaps to reach permuted array with at most 2 positions left swaps allowed and the other steps required?
assistant
#Here is code to minimum swaps to reach permuted array with at most 2 positions left swaps allowed and the other steps required.
 def merge ( arr , temp , left , mid , right ) :
	inv_count = 0
i = left
j = mid
k = left
	while ( i <= mid - 1 ) and ( j <= right ) :
		if arr [ i ] <= arr [ j ] :
			temp [ k ] = arr [ i ]
			k , i = k + 1 , i + 1
		else :
			temp [ k ] = arr [ j ]
			k , j = k + 1 , j + 1
			inv_count = inv_count + ( mid - i )
	while i <= mid - 1 :
		temp [ k ] = arr [ i ]
		k , i = k + 1 , i + 1
	while j <= right :
		temp [ k ] = arr [ j ]
		k , j = k + 1 , j + 1
	for i in range ( left , right + 1 ) :
		arr [ i ] = temp [ i ]
	return inv_count
def _mergeSort ( arr , temp , left , right ) :
	inv_count = 0
	if right > left :
		mid = ( right + left ) // 2
		inv_count = _mergeSort ( arr , temp , left , mid )
		inv_count += _mergeSort ( arr , temp , mid + 1 , right )
		inv_count += merge ( arr , temp , left , mid + 1 , right )
	return inv_count
def mergeSort ( arr , array_size ) :
	temp = [ None ] * array_size
	return _mergeSort ( arr , temp , 0 , array_size - 1 )
'
def minSwapToReachArr ( arr , N ) :
	for i in range ( 0 , N ) :
		if ( arr [ i ] - 1 ) - i > 2 :
			return - 1
	numOfInversion = mergeSort ( arr , N )
	return numOfInversion
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 5 , 3 , 4 ]
	N = len ( arr )
	res = minSwapToReachArr ( arr , N )
	if res == - 1 :
		print ( " Not ▁ Possible " )
	else :
		print ( res )