human
Count of decreasing pairs formed from numbers 1 to N | Function to count the possible number of pairs.
if the number is even then the answer in ( N / 2 ) - 1.
if the number is odd then the answer in N / 2.
Driver code"
How can the above be solved in Python?

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What is a code to count of decreasing pairs formed from numbers 1 to N and the other steps required?
assistant
#Here is code to count of decreasing pairs formed from numbers 1 to N and the other steps required.
 def divParts ( N ) :
	if ( N % 2 == 0 ) :
		print ( ( N / 2 ) - 1 ) ;
	else :
		print ( N / 2 ) ;
N = 8 ;
divParts ( N ) ;