human
Count number of triplets with product not exceeding a given number | Function to count the number of triplets whose product is at most N.
Stores the count of triplets.
Iterate over the range [ 0 , N ].
Iterate over the range [ 0 , N ].
If the product of pairs exceeds N.
Increment the count of possible triplets.
Return the total count.
Driver Code"
Solution in Python:
 ... What is a code to count number of triplets with product not exceeding a given number and the other steps required?
assistant
#Here is code to count number of triplets with product not exceeding a given number and the other steps required.
 def countTriplets ( N ) :
	ans = 0
	for i in range ( 1 , N + 1 ) :
		for j in range ( 1 , N + 1 ) :
			if ( i * j > N ) :
				break
			ans += N // ( i * j )
	return ans
if __name__ == " _ _ main _ _ " :
	N = 10
	print ( countTriplets ( N ) )