human
Count of elements which are equal to the XOR of the next two elements | Function to return the count of elements which are equal to the XOR of the next two elements.
To store the required count.
For every element of the array such that it has at least two elements appearing after it in the array.
If current element is equal to the XOR of the next two elements in the array.
Driver code"
Solution in Python:

Can you provide a code to count of elements which are equal to the XOR of the next two elements and the other steps required?
assistant
#Here is code to count of elements which are equal to the XOR of the next two elements and the other steps required.
 def cntElements ( arr , n ) :
	cnt = 0
	for i in range ( n - 2 ) :
		if ( arr [ i ] == ( arr [ i + 1 ] ^ arr [ i + 2 ] ) ) :
			cnt += 1
	return cnt
arr = [ 4 , 2 , 1 , 3 , 7 , 8 ]
n = len ( arr )
print ( cntElements ( arr , n ) )