human
Count of values of x <= n for which ( n XOR x ) = ( n | Function to return the count of valid values of x.
Convert n into binary String.
To store the count of 1 s.
If current bit is 1.
Calculating answer.
Driver code"
How can the above be solved in Python?
 ... What is a code to count of values of x <= n for which ( n XOR x ) = ( n and the other steps required?
assistant
#Here is code to count of values of x <= n for which ( n XOR x ) = ( n and the other steps required.
 def countX ( n ) :
	binary = " { 0 : b } " . format ( n )
	count = 0
	for i in range ( len ( binary ) ) :
		if ( binary [ i ] == '1' ) :
			count += 1
	answer = int ( pow ( 2 , count ) )
	return answer
if __name__ == " _ _ main _ _ " :
	n = 5
	answer = countX ( n )
	print ( answer )