human
Solve in Python:
We have a list of points on the plane.  Find the K closest points to the origin (0, 0).
(Here, the distance between two points on a plane is the Euclidean distance.)
You may return the answer in any order.  The answer is guaranteed to be unique (except for the order that it is in.)
 

Example 1:
Input: points = [[1,3],[-2,2]], K = 1
Output: [[-2,2]]
Explanation: 
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest K = 1 points from the origin, so the answer is just [[-2,2]].

Example 2:
Input: points = [[3,3],[5,-1],[-2,4]], K = 2
Output: [[3,3],[-2,4]]
(The answer [[-2,4],[3,3]] would also be accepted.)

 
Note:

1 <= K <= points.length <= 10000
-10000 < points[i][0] < 10000
-10000 < points[i][1] < 10000
assistant
#Here is Python code to find the K closest points to the origin (0, 0).

class Solution:
    def kClosest(self, points: List[List[int]], k: int) -> List[List[int]]:
        from queue import PriorityQueue as pq
        distance_points = [(-1 * ((x**2 + y**2) ** .5), [x,y]) for x,y in points]
        q = pq()
        for item in distance_points:
            if q.qsize() < k:
                q.put(item) 
            else:
                distance, _ = item
                popped = q.get()
                popped_distance, _ = popped
                if distance > popped_distance:
                    q.put(item)
                else:
                    q.put(popped)
        return [q.get()[1] for _ in range(k)]