human
Count minimum number of moves to front or end to sort an array | Function that counts the minimum moves required to covert arr [ ] to brr [ ].
Base Case.
If arr [ i ] < arr [ j ].
Include the current element.
Otherwise , excluding the current element.
Function that counts the minimum moves required to sort the array.
If both the arrays are equal.
No moves required.
Otherwise.
Print minimum operations required.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count minimum number of moves to front or end to sort an array and the other steps required.
 def minOperations ( arr1 , arr2 , i , j ) :
	if arr1 == arr2 :
		return 0
	if i >= len ( arr1 ) or j >= len ( arr2 ) :
		return 0
	if arr1 [ i ] < arr2 [ j ] :
		return 1 + minOperations ( arr1 , arr2 , i + 1 , j + 1 )
	return max ( minOperations ( arr1 , arr2 , i , j + 1 ) , minOperations ( arr1 , arr2 , i + 1 , j ) )
def minOperationsUtil ( arr ) :
	brr = sorted ( arr ) ;
	if ( arr == brr ) :
		print ( "0" )
	else :
		print ( minOperations ( arr , brr , 0 , 0 ) )
arr = [ 4 , 7 , 2 , 3 , 9 ]
minOperationsUtil ( arr )