human
What is a code to form minimum number from given sequence and the other steps required given the following:
Form minimum number from given sequence | Prints the minimum number that can be formed from input sequence of I ' s ▁ and ▁ D ' s.
Initialize current_max ( to make sure that we don 't use repeated character.
Initialize last_entry ( Keeps track for last printed digit ).
Iterate over input array.
Initialize ' noOfNextD ' to get count of next D 's available.
If letter is ' I ' Calculate number of next consecutive D 's  available.
If ' I ' is first letter , print incremented sequence from 1.
Set max digit reached.
If not first letter Get next digit to print.
Print digit for I.
For all next consecutive ' D ' print decremented sequence.
If letter is 'D  .
If ' D ' is first letter in sequence Find number of Next D 's available.
Calculate first digit to print based on number of consecutive D 's.
Print twice for the first time.
Store last entry.
If current ' D ' is not first letter Decrement last_entry.
Driver code"
Solution in Python:
assistant
#Here is code to form minimum number from given sequence and the other steps required.
 def PrintMinNumberForPattern ( arr ) :
	curr_max = 0
	last_entry = 0
	i = 0
	while i < len ( arr ) :
		noOfNextD = 0
		if arr [ i ] == " I " :
			j = i + 1
			while j < len ( arr ) and arr [ j ] == " D " :
				noOfNextD += 1
				j += 1
			if i == 0 :
				curr_max = noOfNextD + 2
				last_entry += 1
				print ( " " , last_entry , end = " " )
				print ( " " , curr_max , end = " " )
				last_entry = curr_max
			else :
				curr_max += noOfNextD + 1
				last_entry = curr_max
				print ( " " , last_entry , end = " " )
			for k in range ( noOfNextD ) :
				last_entry -= 1
				print ( " " , last_entry , end = " " )
				i += 1
		elif arr [ i ] == " D " :
			if i == 0 :
				j = i + 1
				while j < len ( arr ) and arr [ j ] == " D " :
					noOfNextD += 1
					j += 1
				curr_max = noOfNextD + 2
				print ( " " , curr_max , curr_max - 1 , end = " " )
				last_entry = curr_max - 1
			else :
				print ( " " , last_entry - 1 , end = " " )
				last_entry -= 1
		i += 1
	print ( )
if __name__ == " _ _ main _ _ " :
	PrintMinNumberForPattern ( " IDID " )
	PrintMinNumberForPattern ( " I " )
	PrintMinNumberForPattern ( " DD " )
	PrintMinNumberForPattern ( " II " )
	PrintMinNumberForPattern ( " DIDI " )
	PrintMinNumberForPattern ( " IIDDD " )
	PrintMinNumberForPattern ( " DDIDDIID " )