human
Solve the following python programming problem given the following code:
def _check_antecedents_1(g, x, helper = False) : 
    '
    Return a condition under which the mellin transform of g exists.
    Any power of x has already been absorbed into the G function,
    so this is just int_0^\\infty g dx.

    See [L, section 5.6.1]. (Note that s=1.)

    If ``helper`` is True, only check if the MT exists at infinity, i.e. if
    int_1^\\infty g dx exists.
    ' 
    from sympy import Eq, Not, ceiling, Ne, re, unbranched_argument as arg 
    delta = g.delta 
    (eta, _) = _get_coeff_exp (g.argument, x) 
    (m, n, p, q) = S ([len (g.bm), len (g.an), len (g.ap), len (g.bq)]) 
    xi = ((m + n) - p) 
    if (p > q) : 
        def tr(l) : 
            return [(1 - x) for x in l] 
return _check_antecedents_1 (meijerg (tr (g.bm), tr (g.bother), tr (g.an), tr (g.aother), (x / eta)), x) 
tmp = [] 
    for b in g.bm : 
        tmp += [((- re (b)) < 1)] 
for a in g.an : 
        tmp += [(1 < (1 - re (a)))] 
cond_3 = And (* tmp) 
    for b in g.bother : 
        tmp += [((- re (b)) < 1)] 
for a in g.aother : 
        tmp += [(1 < (1 - re (a)))] 
cond_3_star = And (* tmp) 
    cond_4 = (((- re (g.nu)) + (((q + 1) - p) / 2)) > (q - p)) 
    def debug(* msg) : 
        _debug (* msg) 
debug ('Checking antecedents for 1 function:') 
    debug (('  delta=%s, eta=%s, m=%s, n=%s, p=%s, q=%s' % (delta, eta, m, n, p, q))) 
    debug (('  ap = %s, %s' % (list (g.an), list (g.aother)))) 
    debug (('  bq = %s, %s' % (list (g.bm), list (g.bother)))) 
    debug (('  cond_3=%s, cond_3*=%s, cond_4=%s' % (cond_3, cond_3_star, cond_4))) 
    conds = [] 
    case1 = [] 
    tmp1 = [(1 <= n), (p < q), (1 <= m)] 
    tmp2 = [(1 <= p), (1 <= m), Eq (q, (p + 1)), Not (And (Eq (n, 0), Eq (m, (p + 1))))] 
    tmp3 = [(1 <= p), Eq (q, p)] 
    for k in range ((ceiling ((delta / 2)) + 1)) : 
        tmp3 += [Ne (abs (arg (eta)), ((delta - (2 * k)) * pi))] 
tmp = [(delta > 0), (abs (arg (eta)) < (delta * pi))] 
    extra = [Ne (eta, 0), cond_3] 
    if helper : 
        extra = [] 
for t in [tmp1, tmp2, tmp3] : 
    ...

    
    

    Fix the buggy line: case_extra += [Eq (delta, q), Eq (delta, 0), Eq (arg (eta), 0), Ne (eta, 0)]
assistant
#Here is Python code to fix the buggy line: case_extra += [Eq (delta, q), Eq (delta, 0), Eq (arg (eta), 0), Ne (eta, 0)]
.

case_extra += [Eq (p, q), Eq (delta, 0), Eq (arg (eta), 0), Ne (eta, 0)]