human
Give me a Python code to find 2 pairs of integers (l_1, r_1), (l_2, r_2), such that: given the following:
Frodo was caught by Saruman. He tore a pouch from Frodo's neck, shook out its contents —there was a pile of different rings: gold and silver...

"How am I to tell which is the One?!" the mage howled.

"Throw them one by one into the Cracks of Doom and watch when Mordor falls!" 

Somewhere in a parallel Middle-earth, when Saruman caught Frodo, he only found n rings. And the i-th ring was either gold or silver. For convenience Saruman wrote down a binary string s of n characters, where the i-th character was 0 if the i-th ring was gold, and 1 if it was silver.

Saruman has a magic function f, which takes a binary string and returns a number obtained by converting the string into a binary number and then converting the binary number into a decimal number. For example, f(001010) = 10, f(111) = 7, f(11011101) = 221.

Saruman, however, thinks that the order of the rings plays some important role. He wants to find 2 pairs of integers (l_1, r_1), (l_2, r_2), such that:

  * 1 ≤ l_1 ≤ n, 1 ≤ r_1 ≤ n, r_1-l_1+1≥ ⌊ n/2 ⌋ 
  * 1 ≤ l_2 ≤ n, 1 ≤ r_2 ≤ n, r_2-l_2+1≥ ⌊ n/2 ⌋ 
  * Pairs (l_1, r_1) and (l_2, r_2) are distinct. That is, at least one of l_1 ≠ l_2 and r_1 ≠ r_2 must hold.
  * Let t be the substring s[l_1:r_1] of s, and w be the substring s[l_2:r_2] of s. Then there exists non-negative integer k, such that f(t) = f(w) ⋅ k.


Here substring s[l:r] denotes s_ls_{l+1}… s_{r-1}s_r, and ⌊ x ⌋ denotes rounding the number down to the nearest integer.

Help Saruman solve this problem! It is guaranteed that under the constraints of the problem at least one solution exists.

Input

Each test contains multiple test cases.

The first line contains one positive integer t (1 ≤ t ≤ 10^3), denoting the number of test cases. Description of the test cases follows.

The first line of each test case contains one positive integer n (2 ≤ n ≤ 2 ⋅ 10^4) — length of the string.

The second line of each test case contains a non-empty binary string of length n.

It is guaranteed that the sum of n over all test cases does not exceed...
Solve the task in PYTHON3.
assistant
#Here is Python code to find 2 pairs of integers (l_1, r_1), (l_2, r_2), such that:
.

import os,sys
from io import BytesIO,IOBase

def main():
    for _ in range(int(input())):
        n = int(input())
        s = input().strip()
        if s == '1'*n:
            print(1,n-1,2,n)
        else:
            for j in range((n-1)//2,-1,-1):
                if s[j] == '0':
                    print(j+1,n,j+2,n)
                    break
            else:
                for j in range(n//2,n):
                    if s[j] == '0':
                        print(1,j+1,1,j)
                        break

# Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
    newlines = 0
    def __init__(self,file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
    def read(self):
        while True:
            b = os.read(self._fd,max(os.fstat(self._fd).st_size,BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0,2),self.buffer.write(b),self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd,max(os.fstat(self._fd).st_size,BUFSIZE))
            self.newlines = b.count(b"\n")+(not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0,2),self.buffer.write(b),self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
    def flush(self):
        if self.writable:
            os.write(self._fd,self.buffer.getvalue())
            self.buffer.truncate(0),self.buffer.seek(0)
class IOWrapper(IOBase):
    def __init__(self,file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s:self.buffer.write(s.encode("ascii"))
        self.read = lambda:self.buffer.read().decode("ascii")
        self.readline =...