human
Solve in Python:
The palindromic number `595` is interesting because it can be written as the sum of consecutive squares: `6^2 + 7^2 + 8^2 + 9^2 + 10^2 + 11^2 + 12^2 = 595`.

There are exactly eleven palindromes below one-thousand that can be written as consecutive square sums. Note that `1 = 0^2 + 1^2` has not been included as this problem is concerned with the squares of positive integers.

Given an input `n`, find the count of all the numbers less than `n` that are both palindromic and can be written as the sum of consecutive squares.

For instance: `values(1000) = 11`. See test examples for more cases.  

Good luck!

This Kata is borrowed from [Project Euler #125](https://projecteuler.net/problem=125)

If you like this Kata, please try:

[Fixed length palindromes](https://www.codewars.com/kata/59f0ee47a5e12962cb0000bf)

[Divisor harmony](https://www.codewars.com/kata/59bf97cd4f98a8b1cd00007e)

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What is a Python code to find the count of all the numbers less than `n` that are both palindromic and can be written as the sum of consecutive squares?
assistant
#Here is Python code to find the count of all the numbers less than `n` that are both palindromic and can be written as the sum of consecutive squares.

def values(limit):
    def is_palindrome(n):
        n = str(n)
        if len(n) in [0, 1]:
            return True
        return n[0] == n[-1] and is_palindrome(n[1:-1])

    print("Limit: {}".format(limit))
    current = 2
    totals = [1]
    list_pal = []
    while True:
        number = current ** 2 + totals[-1]
        totals = [i for i in totals if number - i < limit]
        if len(totals) == 1 and totals != [1]:
            break
        for i in totals[:-1]:
            if is_palindrome(number - i) and not (number - i) in list_pal and limit > (number - i):
                list_pal.append(number - i)
        if is_palindrome(number) and not number in list_pal and limit > number:
            list_pal.append(number)
        totals.append(number)
        current += 1
    print("Number of Palindrome in list: {}".format(len(list_pal)))
    print("List of Palindrome: {}".format(list_pal))
    return len(list_pal)