human
Compositorial of a number | Function to check if a number is composite ..
Corner cases.
This is checked so that we can skip the middle five numbers in the below loop.
This function stores all Composite numbers less than N.
Function to calculate the Compositorial of n.
Multiply first n composite number.
Driver code.
Vector to store all the composite less than N"
Solution in Python:

Can you provide a code to compositorial of a number and the other steps required?
assistant
#Here is code to compositorial of a number and the other steps required.
 def isComposite ( n ) :
	if ( n <= 3 ) :
		return False
	if ( n % 2 == 0 or n % 3 == 0 ) :
		return True
	i = 5
	while ( i * i <= n ) :
		if ( n % i == 0 or n % ( i + 2 ) == 0 ) :
			return True
		i = i + 6
	return False
def Compositorial_list ( n ) :
	l = 0
	for i in range ( 4 , 10 ** 6 ) :
		if l < n :
			if isComposite ( i ) :
				compo . append ( i )
				l += 1
def calculateCompositorial ( n ) :
	result = 1
	for i in range ( n ) :
		result = result * compo [ i ]
	return result
if __name__ == " _ _ main _ _ " :
	n = 5
	compo = [ ]
	Compositorial_list ( n )
	print ( calculateCompositorial ( n ) )