human
Give me a code to find the kth element in the series generated by the given N ranges and the other steps required given the following:
Find the kth element in the series generated by the given N ranges | Function to return the kth element of the required series.
To store the number of integers that lie upto the ith index.
Compute the number of integers.
Stores the index , lying from 1 to n ,.
Using binary search , find the index in which the kth element will lie.
Find the position of the kth element in the interval in which it lies.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to find the kth element in the series generated by the given N ranges and the other steps required.
 def getKthElement ( n , k , L , R ) :
	l = 1
	h = n
	total = [ 0 for i in range ( n + 1 ) ]
	total [ 0 ] = 0
	for i in range ( n ) :
		total [ i + 1 ] = total [ i ] + ( R [ i ] - L [ i ] ) + 1
	index = - 1
	while ( l <= h ) :
		m = ( l + h ) // 2
		if ( total [ m ] > k ) :
			index = m
			h = m - 1
		elif ( total [ m ] < k ) :
			l = m + 1
		else :
			index = m
			break
	l = L [ index - 1 ]
	h = R [ index - 1 ]
	x = k - total [ index - 1 ]
	while ( l <= h ) :
		m = ( l + h ) // 2
		if ( ( m - L [ index - 1 ] ) + 1 == x ) :
			return m
		elif ( ( m - L [ index - 1 ] ) + 1 > x ) :
			h = m - 1
		else :
			l = m + 1
L = [ 1 , 8 , 21 ]
R = [ 4 , 10 , 23 ]
n = len ( L )
k = 6
print ( getKthElement ( n , k , L , R ) )