human
Remove even frequency characters from the string | Function that removes the characters which have even frequencies in the string.
create a map to store the frequency of each character.
to store the new string.
remove the characters which have even frequencies.
if the character has even frequency then skip.
else concatenate the character to the new string.
display the modified string.
Driver code.
remove the characters which have even frequencies"
How can the above be solved in Python?
assistant
#Here is code to remove even frequency characters from the string and the other steps required.
 def solve ( s ) :
	m = dict ( )
	for i in range ( len ( s ) ) :
		if s [ i ] in m :
			m [ s [ i ] ] = m [ s [ i ] ] + 1
		else :
			m [ s [ i ] ] = 1
	new_string = " "
	for i in range ( len ( s ) ) :
		if m [ s [ i ] ] % 2 == 0 :
			continue
		new_string = new_string + s [ i ]
	print ( new_string )
if __name__ == ' _ _ main _ _ ' :
	s = " aabbbddeeecc "
	solve ( s )