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Perfect totient number | Function to find the Totient number of the given value.
Initialize result as n.
Consider all prime factors of n and subtract their multiples from result.
Check if p is a prime factor ..
If yes , then update N and result.
If n has a prime factor greater than sqrt ( n ) ( There can be at - most one such prime factor ).
Function to check if the number is a perfect totient number.
Store original value of n.
Loop to calculate sum of iterated totients.
Condition for Perfect Totient Number.
Driver Code"
Solution in Python:
 ... What is a code to perfect totient number and the other steps required?
assistant
#Here is code to perfect totient number and the other steps required.
 def phi ( n ) :
	result = n
	for p in range ( 2 , n ) :
		if p * p > n :
			break
		if ( n % p == 0 ) :
			while ( n % p == 0 ) :
				n //= p
			result -= result // p
	if ( n > 1 ) :
		result -= result // n
	return result
def isPerfectTotientNum ( n ) :
	temp = n
	sum = 0
	while ( n > 1 ) :
		sum = sum + phi ( n )
		n = phi ( n )
	if ( sum == temp ) :
		return True
	return False
if __name__ == ' _ _ main _ _ ' :
	n = 9
	if ( isPerfectTotientNum ( n ) ) :
		print ( " Yes " )
	else :
		print ( " No " )