human
Count of obtuse angles in a circle with ' k ' equidistant points between 2 given points | C ++ program to count number of obtuse angles for given two points ..
There are two arcs connecting a and b . Let us count points on both arcs ..
Both arcs have same number of points.
Points on smaller arc is answer.
Driver code"
How can the above be solved in Python?

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Write me a code to count of obtuse angles in a circle with ' k ' equidistant points between 2 given points and the other steps required?
assistant
#Here is code to count of obtuse angles in a circle with ' k ' equidistant points between 2 given points and the other steps required.
 def countObtuseAngles ( a , b , k ) :
	c1 = ( b - a ) - 1
	c2 = ( k - b ) + ( a - 1 )
	if ( c1 == c2 ) :
	return 0
	return min ( c1 , c2 )
k , a , b = 6 , 1 , 3
print countObtuseAngles ( a , b , k )