human
What is a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/cat-and-mouse/:
A game on an undirected graph is played by two players, Mouse and Cat, who alternate turns.
The graph is given as follows: graph[a] is a list of all nodes b such that ab is an edge of the graph.
Mouse starts at node 1 and goes first, Cat starts at node 2 and goes second, and there is a Hole at node 0.
During each player's turn, they must travel along one edge of the graph that meets where they are.  For example, if the Mouse is at node 1, it must travel to any node in graph[1].
Additionally, it is not allowed for the Cat to travel to the Hole (node 0.)
Then, the game can end in 3 ways:

If ever the Cat occupies the same node as the Mouse, the Cat wins.
If ever the Mouse reaches the Hole, the Mouse wins.
If ever a position is repeated (ie. the players are in the same position as a previous turn, and it is the same player's turn to move), the game is a draw.

Given a graph, and assuming both players play optimally, return 1 if the game is won by Mouse, 2 if the game is won by Cat, and 0 if the game is a draw.
 


Example 1:
Input: [[2,5],[3],[0,4,5],[1,4,5],[2,3],[0,2,3]]
Output: 0
Explanation:
4---3---1
|   |
2---5
 \ /
  0

 
Note:

3 <= graph.length <= 50
It is guaranteed that graph[1] is non-empty.
It is guaranteed that graph[2] contains a non-zero element.

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution:
    def catMouseGame(self, graph):
        mem = [[[-1 for i in range(1+2*len(graph))] for i in range(1+2*len(graph))] for i in range(2*len(graph))]
        def storeRet(m,c,t,v):
            mem[m][c][t] = v
            return mem[m][c][t]
        mouseWin = lambda m,c,t:storeRet(m,c,t,1)
        catWin = lambda m,c,t:storeRet(m,c,t,2)
        draw = lambda m,c,t:storeRet(m,c,t,0)
        
        def play(m, c, t):
            if mem[m][c][t]!=-1: return mem[m][c][t] # already visited this game state
            if t >= len(graph)*2: return 0 # repeated states
            if not t % 2: # mouse turn
                drawFound = False
                for n in graph[m]:
                    if n == 0: return mouseWin(m,c,t)
                    if n == c: continue
                    res = play(n, c, t+1)
                    if res == 1: return mouseWin(m,c,t)
                    if res == 0: drawFound = True
                return draw(m,c,t) if drawFound else catWin(m,c,t)
            else: # cat turn
                drawFound=False
                for n in graph[c]:
                    if n == m: return catWin(m,c,t)
                    if n == 0: continue
                    res = play(m, n, t+1)
                    if res == 2: return catWin(m,c,t)
                    if res == 0: drawFound = True
                return draw(m,c,t) if drawFound else mouseWin(m,c,t)
        return play(1,2,0)