human
Can you provide a code to n consecutive ropes problem and the other steps required given the following:
N consecutive ropes problem | Function to return the minimum cost to connect the given ropes.
dp [ i ] [ j ] = minimum cost in range ( i , j ) sum [ i ] [ j ] = sum of range ( i , j ).
Initializing the sum table memset ( sum , 0 , sizeof ( 0 ) ).
.
Computing minimum cost for all the possible interval ( i , j ) Left range.
Right range.
No cost for a single rope.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to n consecutive ropes problem and the other steps required.
 def MinCost ( arr , n ) :
	dp = [ [ 0 for i in range ( n + 5 ) ] for i in range ( n + 5 ) ]
	sum = [ [ 0 for i in range ( n + 5 ) ] for i in range ( n + 5 ) ]
	for i in range ( n ) :
		k = arr [ i ]
		for j in range ( i , n ) :
			if ( i == j ) :
				sum [ i ] [ j ] = k
			else :
				k += arr [ j ]
				sum [ i ] [ j ] = k
	for i in range ( n - 1 , - 1 , - 1 ) :
		for j in range ( i , n ) :
			dp [ i ] [ j ] = 10 ** 9
			if ( i == j ) :
				dp [ i ] [ j ] = 0
			else :
				for k in range ( i , j ) :
					dp [ i ] [ j ] = min ( dp [ i ] [ j ] , dp [ i ] [ k ] + dp [ k + 1 ] [ j ] + sum [ i ] [ j ] )
	return dp [ 0 ] [ n - 1 ]
arr = [ 7 , 6 , 8 , 6 , 1 , 1 ]
n = len ( arr )
print ( MinCost ( arr , n ) )