human
String obtained by reversing and complementing a Binary string K times | Function to perform K operations upon the string and find modified string.
Number of reverse operations.
Number of complement operations.
If rev is odd parity.
If complement is odd parity.
Complementing each position.
Return the modified string.
Driver Code.
Function call"
How can the above be solved in Python?
assistant
#Here is code to string obtained by reversing and complementing a Binary string K times and the other steps required.
 def ReverseComplement ( s , n , k ) :
	rev = ( k + 1 ) // 2
	complement = k - rev
	if ( rev % 2 ) :
		s = s [ : : - 1 ]
	if ( complement % 2 ) :
		for i in range ( n ) :
			if ( s [ i ] == '0' ) :
				s [ i ] = '1'
			else :
				s [ i ] = '0'
	return s
if __name__ == ' _ _ main _ _ ' :
	str1 = "10011"
	k = 5
	n = len ( str1 )
	print ( ReverseComplement ( str1 , n , k ) )