human
Split given arrays into subarrays to maximize the sum of maximum and minimum in each subarrays | Function to find the maximum sum of differences of subarrays by splitting array into non - overlapping subarrays.
Stores the answer for prefix and initialize with zero.
Assume i - th index as right endpoint.
Choose the current value as the maximum and minimum.
Find the left endpoint and update the array dp [ ].
Return answer.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to split given arrays into subarrays to maximize the sum of maximum and minimum in each subarrays and the other steps required.
 def maxDiffSum ( arr , n ) :
	dp = [ 0 ] * n
	for i in range ( n ) :
		maxVal = arr [ i ]
		minVal = arr [ i ]
		for j in range ( i , - 1 , - 1 ) :
			minVal = min ( minVal , arr [ j ] )
			maxVal = max ( maxVal , arr [ j ] )
			if ( j - 1 >= 0 ) :
				dp [ i ] = max ( dp [ i ] , maxVal - minVal + dp [ j - 1 ] )
			else :
				dp [ i ] = max ( dp [ i ] , maxVal - minVal )
	return dp [ n - 1 ]
arr = [ 8 , 1 , 7 , 9 , 2 ]
N = len ( arr )
print ( maxDiffSum ( arr , N ) )