human
Count total set bits in all numbers from range L to R | Function to count set bits in x.
Base Case.
Recursive Call.
Function that returns count of set bits present in all numbers from 1 to N.
Initialize the result.
Return the setbit count.
Driver Code.
Given L and R.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to count total set bits in all numbers from range L to R and the other steps required.
 def countSetBitsUtil ( x ) :
	if ( x < 1 ) :
		return 0 ;
	if ( x % 2 == 0 ) :
		return 0 ;
	else :
		return 1 + ( countSetBitsUtil ( x / 2 ) ) ;
def countSetBits ( L , R ) :
	bitCount = 0 ;
	for i in range ( L , R + 1 ) :
		bitCount += countSetBitsUtil ( i ) ;
	return bitCount ;
if __name__ == ' _ _ main _ _ ' :
	L = 3 ;
	R = 5 ;
	print ( " Total ▁ set ▁ bit ▁ count ▁ is ▁ " , countSetBits ( L , R ) ) ;