human
Count distinct pairs with given sum | Function to count distinct pairs in array whose sum equal to K.
Stores count of distinct pairs whose sum equal to K.
Sort the array.
Stores index of the left pointer.
Stores index of the right pointer.
Calculate count of distinct pairs whose sum equal to K.
If sum of current pair is equal to K.
Remove consecutive duplicate array elements.
Update i.
Remove consecutive duplicate array elements.
Update j.
Update cntPairs.
Update i.
Update j.
If sum of current pair less than K.
Update i.
Update j.
Driver Code"
How can the above be solved in Python?

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Write me a code to count distinct pairs with given sum and the other steps required?
assistant
#Here is code to count distinct pairs with given sum and the other steps required.
 def cntDisPairs ( arr , N , K ) :
	cntPairs = 0
	arr = sorted ( arr )
	i = 0
	j = N - 1
	while ( i < j ) :
		if ( arr [ i ] + arr [ j ] == K ) :
			while ( i < j and arr [ i ] == arr [ i + 1 ] ) :
				i += 1
			while ( i < j and arr [ j ] == arr [ j - 1 ] ) :
				j -= 1
			cntPairs += 1
			i += 1
			j -= 1
		elif ( arr [ i ] + arr [ j ] < K ) :
			i += 1
		else :
			j -= 1
	return cntPairs
if __name__ == ' _ _ main _ _ ' :
	arr = [ 5 , 6 , 5 , 7 , 7 , 8 ]
	N = len ( arr )
	K = 13
	print ( cntDisPairs ( arr , N , K ) )