human
Number of submatrices with OR value 1 | Function to find required prefix - count for each row from right to left.
Function to find the count of submatrices with OR value 1.
Array to store prefix count of zeros from right to left for boolean array.
Variable to store the count of submatrices with OR value 0.
Loop to evaluate each column of the prefix matrix uniquely . For each index of a column we will try to determine the number of sub - matrices starting from that index and has all 1 s.
First part of pair will be the value of inserted element . Second part will be the count of the number of elements pushed before with a greater value.
Variable to store the number of submatrices with all 0 s.
Return the final answer.
Driver Code"
How can the above be solved in Python?
 Give me a code to number of submatrices with OR value 1 and the other steps required?
assistant
#Here is code to number of submatrices with OR value 1 and the other steps required.
 def findPrefixCount ( p_arr , arr ) :
	for i in range ( 0 , n ) :
		for j in range ( n - 1 , - 1 , - 1 ) :
			if arr [ i ] [ j ] :
				continue
			if j != n - 1 :
				p_arr [ i ] [ j ] += p_arr [ i ] [ j + 1 ]
			p_arr [ i ] [ j ] += int ( not arr [ i ] [ j ] )
def matrixOrValueOne ( arr ) :
	p_arr = [ [ 0 for i in range ( n ) ] for j in range ( n ) ]
	findPrefixCount ( p_arr , arr )
	count_zero_submatrices = 0
	for j in range ( 0 , n ) :
		i = n - 1
		q = [ ]
		to_sum = 0
		while i >= 0 :
			c = 0
			while ( len ( q ) != 0 and q [ - 1 ] [ 0 ] > p_arr [ i ] [ j ] ) :
				to_sum -= ( ( q [ - 1 ] [ 1 ] + 1 ) * ( q [ - 1 ] [ 0 ] - p_arr [ i ] [ j ] ) )
				c += q . pop ( ) [ 1 ] + 1
			to_sum += p_arr [ i ] [ j ]
			count_zero_submatrices += to_sum
			q . append ( ( p_arr [ i ] [ j ] , c ) )
			i -= 1
	return ( ( n * ( n + 1 ) * n * ( n + 1 ) ) // 4 - count_zero_submatrices )
if __name__ == " _ _ main _ _ " :
	n = 3
	arr = [ [ 0 , 0 , 0 ] , [ 0 , 1 , 0 ] , [ 0 , 0 , 0 ] ]
	print ( matrixOrValueOne ( arr ) )