human
Minimum increments to convert to an array of consecutive integers | Function that return true if the required array can be generated with m as the last element.
Build the desired array.
Check if the given array can be converted to the desired array with the given operation.
Function to return the minimum number of operations required to convert the given array to an increasing AP series with common difference as 1.
Apply Binary Search.
If array can be generated with mid as the last element.
Current ans is mid.
Check whether the same can be achieved with even less operations.
Build the desired array.
Calculate the number of operations required.
Return the number of operations required.
Driver code"
How can the above be solved in Python?
 ... Write me a code to minimum increments to convert to an array of consecutive integers and the other steps required?
assistant
#Here is code to minimum increments to convert to an array of consecutive integers and the other steps required.
 def check ( m , n , arr ) :
	desired = [ 0 ] * n ;
	for i in range ( n - 1 , - 1 , - 1 ) :
		desired [ i ] = m ;
		m -= 1 ;
	for i in range ( n ) :
		if ( arr [ i ] > desired [ i ] or desired [ i ] < 1 ) :
			return False ;
	return True
def minOperations ( arr , n ) :
	start = arr [ n - 1 ] ;
	end = max ( arr ) + n ;
	max_arr = 0 ;
	while ( start <= end ) :
		mid = ( start + end ) // 2 ;
		if ( check ( mid , n , arr ) ) :
			max_arr = mid ;
			end = mid - 1 ;
		else :
			start = mid + 1 ;
	desired = [ 0 ] * n ;
	for i in range ( n - 1 , - 1 , - 1 ) :
		desired [ i ] = max_arr ;
		max_arr -= 1 ;
	operations = 0 ;
	for i in range ( n ) :
		operations += ( desired [ i ] - arr [ i ] ) ;
	return operations ;
if __name__ == " _ _ main _ _ " :
	arr = [ 4 , 4 , 5 , 5 , 7 ] ;
	n = len ( arr ) ;
	print ( minOperations ( arr , n ) ) ;