human
I found an interesting problem on https://leetcode.com/problems/mini-parser/:
Given a nested list of integers represented as a string, implement a parser to deserialize it.

Each element is either an integer, or a list -- whose elements may also be integers or other lists.

Note:
You may assume that the string is well-formed:

String is non-empty.
String does not contain white spaces.
String contains only digits 0-9, [, - ,, ].


Example 1:

Given s = "324",

You should return a NestedInteger object which contains a single integer 324.


Example 2:

Given s = "[123,[456,[789]]]",

Return a NestedInteger object containing a nested list with 2 elements:

1. An integer containing value 123.
2. A nested list containing two elements:
    i.  An integer containing value 456.
    ii. A nested list with one element:
         a. An integer containing value 789.

I tried it in Python, but could not do it. Can you solve it?

Write me a the Python code you requested?
assistant
#Here is the Python code you requested.

# """
 # This is the interface that allows for creating nested lists.
 # You should not implement it, or speculate about its implementation
 # """
 #class NestedInteger:
 #    def __init__(self, value=None):
 #        """
 #        If value is not specified, initializes an empty list.
 #        Otherwise initializes a single integer equal to value.
 #        """
 #
 #    def isInteger(self):
 #        """
 #        @return True if this NestedInteger holds a single integer, rather than a nested list.
 #        :rtype bool
 #        """
 #
 #    def add(self, elem):
 #        """
 #        Set this NestedInteger to hold a nested list and adds a nested integer elem to it.
 #        :rtype void
 #        """
 #
 #    def setInteger(self, value):
 #        """
 #        Set this NestedInteger to hold a single integer equal to value.
 #        :rtype void
 #        """
 #
 #    def getInteger(self):
 #        """
 #        @return the single integer that this NestedInteger holds, if it holds a single integer
 #        Return None if this NestedInteger holds a nested list
 #        :rtype int
 #        """
 #
 #    def getList(self):
 #        """
 #        @return the nested list that this NestedInteger holds, if it holds a nested list
 #        Return None if this NestedInteger holds a single integer
 #        :rtype List[NestedInteger]
 #        """
 
 class Solution:    
     def convertListToNestedInteger(self, nestList):
         if type(nestList) == type(0):
             return NestedInteger(nestList)
         rtype = NestedInteger()
         for item in nestList:
             if type(item) == type(0):
                 rtype.add(item)
             else:
                 nestedList = self.convertListToNestedInteger(item)
                 rtype.add(nestedList)
         return rtype
         
     def deserializeHelper(self, st):
         if len(st) > 0:
             if st[0] != '[':
                 return int(st)
         assert(len(st) > 1)
         assert(st[0] == '[')
         assert(st[-1] == ']')
        ...