human
What is a code to check if a given string can be converted to a Balanced Bracket Sequence and the other steps required given the following:
Check if a given string can be converted to a Balanced Bracket Sequence | Function to check if the can be balanced by replacing the ' $ ' with opening or closing brackets.
If string can never be balanced.
Declare 2 stacks to check if all ) can be balanced with ( or $ and vice - versa.
Store the count the occurence of ( , ) and $.
Traverse the string.
Increment closed bracket count by 1.
If there are no opening bracket to match it then return False.
Otherwise , pop the character from the stack.
If current character is an opening bracket or $ , push it to the stack.
Increment symbol count by 1.
Increment open bracket count by 1.
Traverse the string from end and repeat the same process.
If there are no closing brackets to match it.
Otherwise , pop character from stack.
Store the extra ( or ) which are not balanced yet.
Check if $ is available to balance the extra brackets.
Count ramaining $ after balancing extra ( and ).
Check if each pair of $ is convertable in ( ).
Driver Code.
Function Call"
Solution in Python:
assistant
#Here is code to check if a given string can be converted to a Balanced Bracket Sequence and the other steps required.
 def canBeBalanced ( sequence ) :
	if ( len ( sequence ) % 2 ) :
		return False
	stack_ , stack2_ = [ ] , [ ]
	countOpen , countClosed = 0 , 0
	countSymbol = 0
	for i in range ( len ( sequence ) ) :
		if ( sequence [ i ] == ' ) ' ) :
			countClosed += 1
			if ( len ( stack_ ) == 0 ) :
				return False
			else :
				del stack_ [ - 1 ]
		else :
			if ( sequence [ i ] == ' $ ' ) :
				countSymbol += 1
			else :
				countOpen += 1
			stack_ . append ( sequence [ i ] )
	for i in range ( len ( sequence ) - 1 , - 1 , - 1 ) :
		if ( sequence [ i ] == ' ( ' ) :
			if ( len ( stack2_ ) == 0 ) :
				return False
			else :
				del stack2_ [ - 1 ]
		else :
			stack2_ . append ( sequence [ i ] )
	extra = abs ( countClosed - countOpen )
	if ( countSymbol < extra ) :
		return False
	else :
		countSymbol -= extra
		if ( countSymbol % 2 == 0 ) :
			return True
	return False
if __name__ == ' _ _ main _ _ ' :
	S = " ( ) ( $ "
	if ( canBeBalanced ( S ) ) :
		print ( " Yes " )
	else :
		print ( " No " )