human
Solve in Python:
You have a very large square wall and a circular dartboard placed on the wall. You have been challenged to throw darts into the board blindfolded. Darts thrown at the wall are represented as an array of points on a 2D plane. 
Return the maximum number of points that are within or lie on any circular dartboard of radius r.
 
Example 1:

Input: points = [[-2,0],[2,0],[0,2],[0,-2]], r = 2
Output: 4
Explanation: Circle dartboard with center in (0,0) and radius = 2 contain all points.

Example 2:

Input: points = [[-3,0],[3,0],[2,6],[5,4],[0,9],[7,8]], r = 5
Output: 5
Explanation: Circle dartboard with center in (0,4) and radius = 5 contain all points except the point (7,8).

Example 3:
Input: points = [[-2,0],[2,0],[0,2],[0,-2]], r = 1
Output: 1

Example 4:
Input: points = [[1,2],[3,5],[1,-1],[2,3],[4,1],[1,3]], r = 2
Output: 4

 
Constraints:

1 <= points.length <= 100
points[i].length == 2
-10^4 <= points[i][0], points[i][1] <= 10^4
1 <= r <= 5000

Give me a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def numPoints(self, points: List[List[int]], r: int) -> int:
        ans = 1
        for (x1, y1), (x2, y2) in itertools.combinations(points, 2):
            q = math.sqrt((x1-x2)**2+(y1-y2)**2)
            if q > 2*r + 0.00001:
                continue
            # only need to calculate a circle on one side
            # consider 1-D case
            x0 = (x1+x2)/2 + math.sqrt(r**2-(q/2)**2)*(y1-y2)/q
            y0 = (y1+y2)/2 + math.sqrt(r**2-(q/2)**2)*(x2-x1)/q
            #print(x0, x1)
            ans = max(ans, sum(1 for x, y in points if (x-x0)**2+(y-y0)**2 <= r**2 + 0.00001))
        return ans