human
Bob watches TV every day. He always sets the volume of his TV to b. However, today he is angry to find out someone has changed the volume to a. Of course, Bob has a remote control that can change the volume.

There are six buttons (-5, -2, -1, +1, +2, +5) on the control, which in one press can either increase or decrease the current volume by 1, 2, or 5. The volume can be arbitrarily large, but can never be negative. In other words, Bob cannot press the button if it causes the volume to be lower than 0.

As Bob is so angry, he wants to change the volume to b using as few button presses as possible. However, he forgets how to do such simple calculations, so he asks you for help. Write a program that given a and b, finds the minimum number of presses to change the TV volume from a to b.

Input

Each test contains multiple test cases. The first line contains the number of test cases T (1 ≤ T ≤ 1 000). Then the descriptions of the test cases follow.

Each test case consists of one line containing two integers a and b (0 ≤ a, b ≤ 10^{9}) — the current volume and Bob's desired volume, respectively.

Output

For each test case, output a single integer — the minimum number of presses to change the TV volume from a to b. If Bob does not need to change the volume (i.e. a=b), then print 0.

Example

Input

3
4 0
5 14
3 9

Output

2
3
2

Note

In the first example, Bob can press the -2 button twice to reach 0. Note that Bob can not press -5 when the volume is 4 since it will make the volume negative. 

In the second example, one of the optimal ways for Bob is to press the +5 twice, then press -1 once.

In the last example, Bob can press the +5 once, then press +1. 
# -*-
assistant
#Here is Python program to find out someone has changed the volume to a.
 coding: utf-8 -*-
import sys
import math
import os
import itertools
import string
import heapq
import _collections
from collections import Counter
from collections import defaultdict
from functools import lru_cache
import bisect
import re
import queue
from decimal import *

class Scanner():
    @staticmethod
    def int():
        return int(sys.stdin.readline().rstrip())

    @staticmethod
    def string():
        return sys.stdin.readline().rstrip()

    @staticmethod
    def map_int():
        return [int(x) for x in Scanner.string().split()]

    @staticmethod
    def string_list(n):
        return [Scanner.string() for i in range(n)]

    @staticmethod
    def int_list_list(n):
        return [Scanner.map_int() for i in range(n)]

    @staticmethod
    def int_cols_list(n):
        return [Scanner.int() for i in range(n)]

class Math():
    @staticmethod
    def gcd(a, b):
        if b == 0:
            return a
        return Math.gcd(b, a % b)

    @staticmethod
    def lcm(a, b):
        return (a * b) // Math.gcd(a, b)

    @staticmethod
    def divisor(n):
        res = []
        i = 1
        for i in range(1, int(n ** 0.5) + 1):
            if n % i == 0:
                res.append(i)
                if i != n // i:
                    res.append(n // i)
        return res

    @staticmethod
    def round_up(a, b):
        return -(-a // b)

    @staticmethod
    def is_prime(n):
        if n < 2:
            return False
        if n == 2:
            return True
        if n % 2 == 0:
            return False
        d = int(n ** 0.5) + 1
        for i in range(3, d + 1, 2):
            if n % i == 0:
                return False
        return True

def pop_count(x):
    x = x - ((x >> 1) & 0x5555555555555555)
    x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333)
    x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f
    x = x + (x >> 8)
    x = x + (x >> 16)
    x = x + (x >> 32)
    return x & 0x0000007f

MOD = int(1e09) + 7
INF = int(1e15)

def solve():
    A, B =...