human
Count of elements not divisible by any other elements of Array | Function to count the number of elements of array which are not divisible by any other element of same array.
Length for boolean array.
Hash map for storing the element and it 's frequency.
Update the maximum element.
Boolean array of size of the max element + 1.
Marking the multiples as false.
To store the final count.
Traverse boolean array.
Check if i is not divisible by any other array elements and appears in the array only once.
Return the final Count.
Driver Code.
Given array.
Function Call"
How can the above be solved in Python?

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Give me a code to count of elements not divisible by any other elements of Array and the other steps required?
assistant
#Here is code to count of elements not divisible by any other elements of Array and the other steps required.
 def countEle ( a , n ) :
	len = 0
	hmap = { }
	for i in range ( n ) :
		len = max ( len , a [ i ] )
		hmap [ a [ i ] ] = hmap . get ( a [ i ] , 0 ) + 1
	v = [ True for i in range ( len + 1 ) ]
	for i in range ( n ) :
		if ( v [ a [ i ] ] == False ) :
			continue
		for j in range ( 2 * a [ i ] , len + 1 , a [ i ] ) :
			v [ j ] = False
	count = 0
	for i in range ( 1 , len + 1 ) :
		if ( v [ i ] == True and ( i in hmap ) and hmap [ i ] == 1 ) :
			count += 1
	return count
if __name__ == ' _ _ main _ _ ' :
	arr = [ 86 , 45 , 18 , 4 , 8 , 28 , 19 , 33 , 2 ]
	n = len ( arr )
	print ( countEle ( arr , n ) )