human
Make all the elements of array even with given operations | Function to count the total number of operations needed to make all array element even.
Traverse the given array.
If an odd element occurs then increment that element and next adjacent element by 1.
Traverse the array if any odd element occurs then return - 1.
Returns the count of operations.
Driver code"
Solution in Python:

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Give me a code to make all the elements of array even with given operations and the other steps required?
assistant
#Here is code to make all the elements of array even with given operations and the other steps required.
 def countOperations ( arr , n ) :
	count = 0 ;
	for i in range ( n - 1 ) :
		if ( arr [ i ] & 1 ) :
			arr [ i ] += 1 ;
			arr [ i + 1 ] += 1 ;
			count += 2 ;
	for i in range ( n ) :
		if ( arr [ i ] & 1 ) :
			return - 1 ;
	return count ;
if __name__ == " _ _ main _ _ " :
	arr = [ 2 , 3 , 4 , 5 , 6 ] ;
	n = len ( arr ) ;
	print ( countOperations ( arr , n ) ) ;