human
Write me a code to check if Bitwise AND of concatenation of diagonals exceeds that of middle row / column elements of a Binary Matrix and the other steps required given the following:
Check if Bitwise AND of concatenation of diagonals exceeds that of middle row / column elements of a Binary Matrix | Functio to convert obtained binary representation to decimal value.
Stores the resultant number.
Traverse string arr.
Return the number formed.
Function to count the number of set bits in the number num.
Stores the count of set bits.
Iterate until num > 0.
Function to check if the given matrix satisfies the given condition or not.
To get P , S , MR , and MC.
Stores decimal equivalents of binary representations.
Gett the number of set bits.
Print the answer.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to check if Bitwise AND of concatenation of diagonals exceeds that of middle row / column elements of a Binary Matrix and the other steps required.
 def convert ( arr ) :
	ans = 0
	for i in arr :
		ans = ( ans << 1 ) | i
	return ans
def count ( num ) :
	ans = 0
	while num :
		ans += num & 1
		num >>= 1
	return ans
def checkGoodMatrix ( mat ) :
	P = [ ]
	S = [ ]
	MR = [ ]
	MC = [ ]
	for i in range ( len ( mat ) ) :
		for j in range ( len ( mat [ 0 ] ) ) :
			if i == j :
				P . append ( mat [ i ] [ j ] )
			if i + j == len ( mat ) - 1 :
				S . append ( mat [ i ] [ j ] )
			if i == ( len ( mat ) - 1 ) // 2 :
				MR . append ( mat [ i ] [ j ] )
			if j == ( len ( mat ) - 1 ) // 2 :
				MC . append ( mat [ i ] [ j ] )
	S . reverse ( )
	P = convert ( P )
	S = convert ( S )
	MR = convert ( MR )
	MC = convert ( MC )
	setBitsPS = count ( P & S )
	setBitsMM = count ( MR & MC )
	if setBitsPS > setBitsMM :
		print ( " Yes " )
	else :
		print ( " No " )
mat = [ [ 1 , 0 , 1 ] , [ 0 , 0 , 1 ] , [ 0 , 1 , 1 ] ]
checkGoodMatrix ( mat )