human
Maximize average of the ratios of N pairs by M increments | Function to find the change in the ratio in pair after applying operation.
Stores the current ratio.
Stores the new ratio.
Stores the increase in ratio.
Returns the change.
Function to find the maximum average of the ratio of the pairs by applying M increments.
Stores the required result.
Declare a priority queue for storing the increments.
Store the increase in the ratio after applying one operation.
Push the increased value and index value in priority queue.
Store the ratio.
Update the value of sum.
Iterate while M > 0.
Add the maximum change to the sum.
Remove the element from the priority queue.
Increase the pairs elements by 1 on which operation is applied.
Push the updated change of the pair in priority queue.
Decrease the operation count.
Update the value of the sum by dividing it by N.
Return the result.
Driver Code"
How can the above be solved in Python?
 Give me a code to maximize average of the ratios of N pairs by M increments and the other steps required?
assistant
#Here is code to maximize average of the ratios of N pairs by M increments and the other steps required.
 def change ( pas , total ) :
	currentPassRatio = pas / total
	newPassRatio = ( pas + 1 ) / ( total + 1 )
	increase = newPassRatio - currentPassRatio
	return increase
def maximumAverage ( v , M , N ) :
	sum = 0
	increase , average = 0 , 0
	pq = [ ]
	for i in range ( N ) :
		increase = change ( v [ i ] [ 0 ] , v [ i ] [ 1 ] )
		pq . append ( [ increase , i ] )
		average = v [ i ] [ 0 ] * 1.0 / v [ i ] [ 1 ]
		sum += average
	pq = sorted ( pq )
	while ( M > 0 ) :
		sum += pq [ - 1 ] [ 0 ]
		i = pq [ - 1 ] [ 1 ]
		del pq [ - 1 ]
		v [ i ] [ 0 ] += 1
		v [ i ] [ 1 ] += 1
		pq . append ( [ change ( v [ i ] [ 0 ] , v [ i ] [ 1 ] ) , i ] )
		M -= 1
		pq = sorted ( pq )
	ans = sum / N
	return ans
if __name__ == ' _ _ main _ _ ' :
	V = [ [ 1 , 2 ] , [ 3 , 5 ] , [ 2 , 2 ] ]
	M = 2
	N = len ( V )
	print ( round ( maximumAverage ( V , M , N ) , 6 ) )