human
Give me a code to check whether product of digits at even places is divisible by sum of digits at odd place of a number and the other steps required given the following:
Check whether product of digits at even places is divisible by sum of digits at odd place of a number | Below function checks whether product of digits at even places is divisible by sum of digits at odd places.
if size is even.
if size is odd.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to check whether product of digits at even places is divisible by sum of digits at odd place of a number and the other steps required.
 def productSumDivisible ( n , size ) :
	sum = 0
	product = 1
	while ( n > 0 ) :
		if ( size % 2 == 0 ) :
			product *= n % 10
		else :
			sum += n % 10
		n = n // 10
		size -= 1
	if ( product % sum == 0 ) :
		return True
	return False
if __name__ == " _ _ main _ _ " :
	n = 1234
	len = 4
	if ( productSumDivisible ( n , len ) ) :
		print ( " TRUE " )
	else :
		print ( " FALSE " )