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Count distinct occurrences as a subsequence | Python3 program to count number of times S appears as a subsequence in T.
T can 't appear as a subsequence in S.
mat [ i ] [ j ] stores the count of occurrences of T ( 1. . i ) in S ( 1. . j ) ..
Initializing first column with all 0 s . x An empty string can 't have another  string as suhsequence.
Initializing first row with all 1 s . An empty string is subsequence of all ..
Fill mat [ ] [ ] in bottom up manner.
If last characters don 't match,  then value is same as the value  without last character in S..
Else value is obtained considering two cases . a ) All substrings without last character in S b ) All substrings without last characters in both ..
Driver Code"
Solution in Python:

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Write me a code to count distinct occurrences as a subsequence and the other steps required?
assistant
#Here is code to count distinct occurrences as a subsequence and the other steps required.
 def findSubsequenceCount ( S , T ) :
	m = len ( T )
	n = len ( S )
	if m > n :
		return 0
	mat = [ [ 0 for _ in range ( n + 1 ) ] for __ in range ( m + 1 ) ]
	for i in range ( 1 , m + 1 ) :
		mat [ i ] [ 0 ] = 0
	for j in range ( n + 1 ) :
		mat [ 0 ] [ j ] = 1
	for i in range ( 1 , m + 1 ) :
		for j in range ( 1 , n + 1 ) :
			if T [ i - 1 ] != S [ j - 1 ] :
				mat [ i ] [ j ] = mat [ i ] [ j - 1 ]
			else :
				mat [ i ] [ j ] = ( mat [ i ] [ j - 1 ] + mat [ i - 1 ] [ j - 1 ] )
	return mat [ m ] [ n ]
if __name__ == " _ _ main _ _ " :
	T = " ge "
	S = " geeksforgeeks "
	print ( findSubsequenceCount ( S , T ) )