human
Write me a the Python program you requested given the following:
I found an interesting problem on https://leetcode.com/problems/shortest-subarray-to-be-removed-to-make-array-sorted/:
Given an integer array arr, remove a subarray (can be empty) from arr such that the remaining elements in arr are non-decreasing.
A subarray is a contiguous subsequence of the array.
Return the length of the shortest subarray to remove.
 
Example 1:
Input: arr = [1,2,3,10,4,2,3,5]
Output: 3
Explanation: The shortest subarray we can remove is [10,4,2] of length 3. The remaining elements after that will be [1,2,3,3,5] which are sorted.
Another correct solution is to remove the subarray [3,10,4].
Example 2:
Input: arr = [5,4,3,2,1]
Output: 4
Explanation: Since the array is strictly decreasing, we can only keep a single element. Therefore we need to remove a subarray of length 4, either [5,4,3,2] or [4,3,2,1].

Example 3:
Input: arr = [1,2,3]
Output: 0
Explanation: The array is already non-decreasing. We do not need to remove any elements.

Example 4:
Input: arr = [1]
Output: 0

 
Constraints:

1 <= arr.length <= 10^5
0 <= arr[i] <= 10^9

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python program you requested.

class Solution(object):
    def findLengthOfShortestSubarray(self, A):
        N = len(A)
        j = N - 1
        while j and A[j] >= A[j - 1]:
            j -= 1
        # A[j:] is monotone increasing
        
        ans = j
        for i in range(j):
            if i and A[i] < A[i-1]:
                break
            # A[..i] is monotone increasing
            while j < N and A[i] > A[j]:
                j += 1
            # j is the smallest such that A[i] <= A[j]
            # Remove A[i+1..j-1] which has length j - i - 1
            ans = min(ans, j - i - 1)
        
        return ans