human
Minimize flips on K | Function to find the minimum number K - length subarrays required to be flipped to make all array elements 1.
Stores whether an element can be flipped or not.
Store the required number of flips.
Traverse the array , A [ ].
Find the prefix sum for the indices i > 0.
Check if the current element is required to be flipped.
If subarray of size K is not possible , then print - 1 and return.
Increment ans by 1.
Change the current state of the element.
Decrement isFlipped [ i + K ].
If subarray of size K is not possible , then print - 1 and return.
Increment ans by 1.
Change the current state of the element.
Decrement isFlipped [ i + K ].
Print the result.
Driver Code"
How can the above be solved in Python?
 ... Can you provide a code to minimize flips on K and the other steps required?
assistant
#Here is code to minimize flips on K and the other steps required.
 def minimumOperations ( A , K ) :
	isflipped = [ 0 ] * ( len ( A ) + 1 )
	ans = 0
	for i in range ( len ( A ) ) :
		if ( i > 0 ) :
			isflipped [ i ] += isflipped [ i - 1 ]
			isflipped [ i ] %= 2
		if ( A [ i ] == 0 and not isflipped [ i ] ) :
			if ( ( len ( A ) - i + 1 ) <= K ) :
				print ( - 1 )
				return
			ans += 1
			isflipped [ i ] += 1
			isflipped [ i + K ] -= 1
		elif ( A [ i ] == 1 and isflipped [ i ] ) :
			if ( ( len ( A ) - i + 1 ) <= K ) :
				print ( - 1 )
				return
			ans += 1
			isflipped [ i ] += 1
			isflipped [ i + K ] -= 1
	print ( ans )
if __name__ == " _ _ main _ _ " :
	arr = [ 0 , 1 , 0 ]
	K = 1
	minimumOperations ( arr , K )