human
Give me a code to count N and the other steps required given the following:
Count N | Function to calculate the power of n ^ k % p.
Update x if it is more than or equal to p.
In case x is divisible by p.
.
If y is odd , multiply x with result.
y must be even now y = y >> 1 y = y / 2.
Function to count the number of arrays satisfying required conditions.
Calculating N ^ K.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count N and the other steps required.
 def power ( x , y , p ) :
	res = 1
	x = x % p
	if ( x == 0 ) :
		return 0
	while ( y > 0 ) :
		if ( y & 1 ) :
			res = ( res * x ) % p
		x = ( x * x ) % p
	return res
def countArrays ( n , k ) :
	mod = 1000000007
	ans = power ( n , k , mod )
	return ans
n = 3
k = 5
ans = countArrays ( n , k )
print ( ans )