human
Minimum bit swaps between given numbers to make their Bitwise OR equal to Bitwise AND | Function for counting number of set bit.
Function to return the count of minimum operations required.
cnt to count the number of bits set in A and in B.
If odd numbers of total set bits.
one_zero = 1 in A and 0 in B at ith bit similarly for zero_one.
When bitpos is set in B , unset in B.
When bitpos is set in A , unset in B.
Number of moves is half of number pairs of each group.
Odd number pairs.
Driver code.
Input.
Function call to compute the result"
Solution in Python:
 ... Can you provide a code to minimum bit swaps between given numbers to make their Bitwise OR equal to Bitwise AND and the other steps required?
assistant
#Here is code to minimum bit swaps between given numbers to make their Bitwise OR equal to Bitwise AND and the other steps required.
 def countSetBits ( n ) :
	count = 0
	while ( n ) :
		n = n & ( n - 1 )
		count += 1
	return count
def minOperations ( A , B ) :
	cnt1 = 0
	cnt2 = 0
	cnt1 += countSetBits ( A )
	cnt2 += countSetBits ( B )
	if ( ( cnt1 + cnt2 ) % 2 != 0 ) :
		return - 1
	oneZero = 0
	zeroOne = 0
	ans = 0
	for i in range ( max ( cnt1 , cnt2 ) ) :
		bitpos = 1 << i
		if ( ( not ( bitpos & A ) ) and ( bitpos & B ) ) :
			zeroOne += 1
		if ( ( bitpos & A ) and ( not ( bitpos & B ) ) ) :
			oneZero += 1
	ans = ( zeroOne // 2 ) + ( oneZero // 2 )
	if ( zeroOne % 2 != 0 ) :
		ans += 2
	return ans
if __name__ == ' _ _ main _ _ ' :
	A = 27
	B = 5
	print ( minOperations ( A , B ) )