human
Can you provide a code to euler zigzag numbers ( Alternating Permutation ) and the other steps required given the following:
Euler zigzag numbers ( Alternating Permutation ) | Function to prfirst n zigzag numbers.
To store factorial and n 'th zig zag number.
Initialize factorial upto n.
Set first two zig zag numbers.
Print first two zig zag number.
Print the rest zig zag numbers.
Binomial ( n , k ) * a ( k ) * a ( n - k ).
Store the value.
Print the number.
Driver code.
Function call"
How can the above be solved in Python?
assistant
#Here is code to euler zigzag numbers ( Alternating Permutation ) and the other steps required.
 def ZigZag ( n ) :
	fact = [ 0 for i in range ( n + 1 ) ]
	zig = [ 0 for i in range ( n + 1 ) ]
	fact [ 0 ] = 1
	for i in range ( 1 , n + 1 ) :
		fact [ i ] = fact [ i - 1 ] * i
	zig [ 0 ] = 1
	zig [ 1 ] = 1
	print ( " zig ▁ zag ▁ numbers : ▁ " , end = " ▁ " )
	print ( zig [ 0 ] , zig [ 1 ] , end = " ▁ " )
	for i in range ( 2 , n ) :
		sum = 0
		for k in range ( 0 , i ) :
			sum += ( ( fact [ i - 1 ] // ( fact [ i - 1 - k ] * fact [ k ] ) ) * zig [ k ] * zig [ i - 1 - k ] )
		zig [ i ] = sum // 2
		print ( sum // 2 , end = " ▁ " )
n = 10
ZigZag ( n )