human
Can you provide a code to count integers in a range which are divisible by their euler totient value and the other steps required given the following:
Count integers in a range which are divisible by their euler totient value | Function to return a ^ n.
Function to return count of integers that satisfy n % phi ( n ) = 0.
Driver Code"
Solution in Python:
assistant
#Here is code to count integers in a range which are divisible by their euler totient value and the other steps required.
 def power ( a , n ) :
	if n == 0 :
		return 1
	p = power ( a , n // 2 )
	p = p * p
	if n & 1 :
		p = p * a
	return p
def countIntegers ( l , r ) :
	ans , i = 0 , 1
	v = power ( 2 , i )
	while v <= r :
		while v <= r :
			if v >= l :
				ans += 1
			v = v * 3
		i += 1
		v = power ( 2 , i )
	if l == 1 :
		ans += 1
	return ans
if __name__ == " _ _ main _ _ " :
	l , r = 12 , 21
	print ( countIntegers ( l , r ) )