human
Form coils in a matrix | Prcoils in a matrix of size 4 n x 4 n.
Number of elements in each coil.
Let us fill elements in coil 1..
First element of coil1 4 * n * 2 * n + 2 * n.
Fill remaining m - 1 elements in coil1 [ ].
Fill elements of current step from down to up.
Next element from current element.
Fill elements of current step from up to down ..
get coil2 from coil1.
Prboth coils.
Driver code"
How can the above be solved in Python?
 ... Can you provide a code to form coils in a matrix and the other steps required?
assistant
#Here is code to form coils in a matrix and the other steps required.
 def printCoils ( n ) :
	m = 8 * n * n
	coil1 = [ 0 ] * m
	coil1 [ 0 ] = 8 * n * n + 2 * n
	curr = coil1 [ 0 ]
	nflg = 1
	step = 2
	index = 1
	while ( index < m ) :
		for i in range ( step ) :
			curr = coil1 [ index ] = ( curr - 4 * n * nflg )
			index += 1
			if ( index >= m ) :
				break
		if ( index >= m ) :
			break
		for i in range ( step ) :
			curr = coil1 [ index ] = curr + nflg
			index += 1
			if ( index >= m ) :
				break
		nflg = nflg * ( - 1 )
		step += 2
	coil2 = [ 0 ] * m
	i = 0
	while ( i < 8 * n * n ) :
		coil2 [ i ] = 16 * n * n + 1 - coil1 [ i ]
		i += 1
	print ( " Coil ▁ 1 ▁ : " , end = " ▁ " )
	i = 0
	while ( i < 8 * n * n ) :
		print ( coil1 [ i ] , end = " ▁ " )
		i += 1
	print ( " Coil 2 : " , ▁ end ▁ = ▁ "   " )
	i = 0
	while ( i < 8 * n * n ) :
		print ( coil2 [ i ] , end = " ▁ " )
		i += 1
n = 1
printCoils ( n )