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What is a code to maximize the minimum difference between any element pair by selecting K elements from given Array and the other steps required given the following:
Maximize the minimum difference between any element pair by selecting K elements from given Array | To check if selection of K elements is possible such that difference between them is greater than dif.
Selecting first element in the sorted array.
prev is the previously selected element initially at index 0 as first element is already selected.
Check if selection of K - 1 elements from array with a minimum difference of dif is possible.
If the current element is atleast dif difference apart from the previously selected element then select the current element and increase the count.
If selection of K elements with a min difference of dif is possible then return true.
Prev will become current element for the next iteration.
If selection of K elements with minimum difference of dif is not possible then return false.
Minimum largest difference possible is 1.
Check if selection of K elements is possible with a minimum difference of dif.
If dif is greater than previous ans we update ans.
Continue to search for better answer . Try finding greater dif.
K elements cannot be selected.
Driver code.
arr should be in a sorted order"
Solution in Python:
assistant
#Here is code to maximize the minimum difference between any element pair by selecting K elements from given Array and the other steps required.
 def isPossibleToSelect ( arr , N , dif , K ) :
	count = 1
	prev = arr [ 0 ]
	for i in range ( 1 , N ) :
		if ( arr [ i ] >= ( prev + dif ) ) :
			count += 1
			if ( count == K ) :
				return True
			prev = arr [ i ]
	return False
def binarySearch ( arr , left , right , K , N ) :
	ans = 1
	while ( left <= right ) :
		dif = left + ( right - left ) // 2
		if ( isPossibleToSelect ( arr , N , dif , K ) ) :
			ans = max ( ans , dif )
			left = dif + 1
		else :
			right = dif - 1
	return ans
if __name__ == " _ _ main _ _ " :
	N = 7
	K = 4
	arr = [ 1 , 4 , 9 , 0 , 2 , 13 , 3 ]
	arr . sort ( )
	print ( binarySearch ( arr , 0 , arr [ N - 1 ] , K , N ) )