human
Complete the below
def filter_properties_target(namespaces_iter, resource_types, properties_target):

    ''''Filter metadata namespaces.
    Filtering is done based ongiven resource types and a properties target.
    :param namespaces_iter: Metadata namespaces iterable.
    :param resource_types: List of resource type names.
    :param properties_target: Name of the properties target.'
    '''
assistant
#Here is the Python code you requested.
    def filter_namespace(namespace):
        for asn in namespace.get('resource_type_associations'):
            if ((asn.get('name') in resource_types) and (asn.get('properties_target') == properties_target)):
                return True
        return False
    return filter(filter_namespace, namespaces_iter)