human
DFA that begins with ' a ' but does not contain substring ' aab ' | Function for state A transition.
If at index 0 ' a ' if found then call stateB function with passing n [ 1 : ] to it.
If at index 0 ' b ' if found then call stateQ function with passing n to it.
Function for state B transition.
Length of string become 0 then print Accepted.
If at index 0 ' a ' if found then call stateC function with passing n [ 1 : ] to it.
If at index 0 ' b ' if found then call stateD function with passing n [ 1 : ] to it.
Function for state C transition.
Length of string become 0 then print Accepted.
If at index 0 ' a ' if found then call stateC function with passing n [ 1 : ] to it.
If at index 0 ' b ' if found then call stateQ function with passing n to it.
Function for state D transition.
Length of string become 0 then print Accepted.
If at index 0 ' a ' if found then call stateB function with passing n [ 1 : ] to it.
If at index 0 ' b ' if found then call stateD function with passing n [ 1 : ] to it.
Function for state Q transition.
In dead state it shows string not accepted.
Take string input.
Call stateA to check the input"
How can the above be solved in Python?
assistant
#Here is code to dFA that begins with ' a ' but does not contain substring ' aab ' and the other steps required.
 def stateA ( n ) :
	if ( n [ 0 ] == ' a ' ) :
		stateB ( n [ 1 : ] )
	else :
		stateQ ( n )
def stateB ( n ) :
	if ( len ( n ) == 0 ) :
		print ( " Accepted " )
	else :
		if ( n [ 0 ] == ' a ' ) :
			stateC ( n [ 1 : ] )
		else :
			stateD ( n [ 1 : ] )
def stateC ( n ) :
	if ( len ( n ) == 0 ) :
		print ( " Accepted " )
	else :
		if ( n [ 0 ] == ' a ' ) :
			stateC ( n [ 1 : ] )
		else :
			stateQ ( n )
def stateD ( n ) :
	if ( len ( n ) == 0 ) :
		print ( " Accepted " )
	else :
		if ( n [ 0 ] == ' a ' ) :
			stateB ( n [ 1 : ] )
		else :
			stateD ( n [ 1 : ] )
def stateQ ( n ) :
	print ( " Not ▁ Accepted " )
n = " aaaba "
stateA ( n )