human
Solve the following python programming problem given the following code:
@ dispatch (Join, ClauseElement, ClauseElement) 
def compute_up(t, lhs, rhs, **kwargs) : 
    if isinstance (lhs, ColumnElement) : 
        lhs = select (lhs) 
if isinstance (rhs, ColumnElement) : 
        rhs = select (rhs) 
if (name (lhs) == name (rhs)) : 
        (left_suffix, right_suffix) = t.suffixes 
        lhs = lhs.alias (('%s%s' % (name (lhs), left_suffix))) 
        rhs = rhs.alias (('%s%s' % (name (rhs), right_suffix))) 
lhs = alias_it (lhs) 
    rhs = alias_it (rhs) 
    if isinstance (lhs, Select) : 
        lhs = lhs.alias (next (aliases)) 
        left_conds = [lhs.c.get (c) for c in listpack (t.on_left)] 
else : 
        ldict = dict (((c.name, c) for c in inner_columns (lhs))) 
        left_conds = [ldict.get (c) for c in listpack (t.on_left)] 
if isinstance (rhs, Select) : 
        rhs = rhs.alias (next (aliases)) 
        right_conds = [rhs.c.get (c) for c in listpack (t.on_right)] 
else : 
        rdict = dict (((c.name, c) for c in inner_columns (rhs))) 
        right_conds = [rdict.get (c) for c in listpack (t.on_right)] 
condition = reduce (and_, map (eq, left_conds, right_conds)) 
    if (t.how == 'inner') : 
        join = _join_selectables (lhs, rhs, condition = condition) 
        main = lhs 
else : 
        if (t.how == 'left') : 
            (main, other) = (lhs, rhs) 
            join = _join_selectables (lhs, rhs, condition = condition, isouter = True) 
else : 
            if (t.how == 'right') : 
                join = _join_selectables (rhs, lhs, condition = condition, isouter = True) 
                main = rhs 
else : 
                raise ValueError ("SQLAlchemy doesn't support full outer Join") 
"
    We now need to arrange the columns in the join to match the columns in
    the expression.  We care about order and don't want repeats
    " 
    if isinstance (join, Select) : 
        def cols(x) : 
            if isinstance (x, Select) : 
                return list (x.inner_columns) 
else : 
                return list (x.columns) 
else : 
        cols = (lambda x :...

    
    

    Fix the buggy line: columns += [_clean_join_name (right_names, left_suffix, left_suffix) for c in left_cols if ((c.name in fields) and (c.name not in t._on_left))]
assistant
#Here is Python code to fix the buggy line: columns += [_clean_join_name (right_names, left_suffix, left_suffix) for c in left_cols if ((c.

columns += [_clean_join_name (right_names, left_suffix, c) for c in left_cols if ((c.name in fields) and (c.name not in t._on_left))]