human
Number of ways a convex polygon of n + 2 sides can split into triangles by connecting vertices | Returns value of Binomial Coefficient C ( n , k ).
Since C ( n , k ) = C ( n , n - k ).
Calculate value of [ n * ( n - 1 ) * -- - * ( n - k + 1 ) ] / [ k * ( k - 1 ) * -- - * 1 ].
A Binomial coefficient based function to find nth catalan number in O ( n ) time.
Calculate value of 2 nCn.
return 2 nCn / ( n + 1 ).
Driver code"
How can the above be solved in Python?

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Give me a code to number of ways a convex polygon of n + 2 sides can split into triangles by connecting vertices and the other steps required?
assistant
#Here is code to number of ways a convex polygon of n + 2 sides can split into triangles by connecting vertices and the other steps required.
 def binomialCoeff ( n , k ) :
	res = 1 ;
	if ( k > n - k ) :
		k = n - k ;
	for i in range ( k ) :
		res *= ( n - i ) ;
		res /= ( i + 1 ) ;
	return res ;
def catalan ( n ) :
	c = binomialCoeff ( 2 * n , n ) ;
	return int ( c / ( n + 1 ) ) ;
n = 3 ;
print ( catalan ( n ) ) ;