human
Minimum number of bits required to be flipped such that Bitwise OR of A and B is equal to C | Function to count the number of bit flips required on A and B such that Bitwise OR of A and B is C.
Stores the count of flipped bit.
Iterate over the range [ 0 , 32 ].
Check if i - th bit of A is set.
Check if i - th bit of B is set or not.
Check if i - th bit of C is set or not.
If i - th bit of C is unset.
Check if i - th bit of A is set or not.
Check if i - th bit of B is set or not.
Check if i - th bit of C is set or not.
Check if i - th bit of both A and B is set.
Return the count of bits flipped.
Driver Code"
Solution in Python:
assistant
#Here is code to minimum number of bits required to be flipped such that Bitwise OR of A and B is equal to C and the other steps required.
 def minimumFlips ( A , B , C ) :
	res = 0
	for i in range ( 32 ) :
		x , y , z = 0 , 0 , 0
		if ( A & ( 1 << i ) ) :
			x = 1
		if ( B & ( 1 << i ) ) :
			y = 1
		if ( C & ( 1 << i ) ) :
			z = 1
		if ( z == 0 ) :
			if ( x ) :
				res += 1
			if ( y ) :
				res += 1
		if ( z == 1 ) :
			if ( x == 0 and y == 0 ) :
				res += 1
	return res
if __name__ == ' _ _ main _ _ ' :
	A , B , C = 2 , 6 , 5
	print ( minimumFlips ( A , B , C ) )