human
Count ways to form minimum product triplets | function to calculate number of triples.
Sort the array.
Count occurrences of third element.
If all three elements are same ( minimum element appears at l east 3 times ) . Answer is nC3 ..
If minimum element appears once . Answer is nC2 ..
Minimum two elements are distinct . Answer is nC1 ..
Driver code"
How can the above be solved in Python?

Write me a code to count ways to form minimum product triplets and the other steps required?
assistant
#Here is code to count ways to form minimum product triplets and the other steps required.
 def noOfTriples ( arr , n ) :
	arr . sort ( )
	count = 0
	for i in range ( n ) :
		if arr [ i ] == arr [ 2 ] :
			count += 1
	if arr [ 0 ] == arr [ 2 ] :
		return ( count - 2 ) * ( count - 1 ) * ( count ) / 6
	elif arr [ 1 ] == arr [ 2 ] :
		return ( count - 1 ) * ( count ) / 2
	return count
arr = [ 1 , 3 , 3 , 4 ]
n = len ( arr )
print ( noOfTriples ( arr , n ) )