human
Frequency of an integer in the given array using Divide and Conquer | Function to return the frequency of x in the subarray arr [ low ... high ].
If the subarray is invalid or the element is not found.
If there 's only a single element  which is equal to x.
Divide the array into two parts and then find the count of occurrences of x in both the parts.
Driver code"
Solution in Python:
 ... Can you provide a code to frequency of an integer in the given array using Divide and Conquer and the other steps required?
assistant
#Here is code to frequency of an integer in the given array using Divide and Conquer and the other steps required.
 def count ( arr , low , high , x ) :
	if ( ( low > high ) or ( low == high and arr [ low ] != x ) ) :
		return 0 ;
	if ( low == high and arr [ low ] == x ) :
		return 1 ;
	return count ( arr , low , ( low + high ) // 2 , x ) + count ( arr , 1 + ( low + high ) // 2 , high , x ) ;
if __name__ == ' _ _ main _ _ ' :
	arr = [ 30 , 1 , 42 , 5 , 56 , 3 , 56 , 9 ] ;
	n = len ( arr ) ;
	x = 56 ;
	print ( count ( arr , 0 , n - 1 , x ) ) ;