human
Sum of Bitwise OR of each array element of an array with all elements of another array | Function to compute sum of Bitwise OR of each element in arr1 [ ] with all elements of the array arr2 [ ].
Declaring an array of size 32 to store the count of each bit.
Traverse the array arr1 [ ].
Current bit position.
While num exceeds 0.
Checks if i - th bit is set or not.
Increment the count at bit_position by one.
Increment bit_position.
Right shift the num by one.
Traverse in the arr2 [ ].
Store the ith bit value.
Total required sum.
Traverse in the range [ 0 , 31 ].
Check if current bit is set.
Increment the Bitwise sum by N * ( 2 ^ i ).
Right shift num by one.
Left shift valee_at_that_bit by one.
Print the sum obtained for ith number in arr1 [ ].
Given arr1 [ ].
Given arr2 [ ].
Size of arr1 [ ].
Size of arr2 [ ].
Function Call"
How can the above be solved in Python?

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Give me a code to sum of Bitwise OR of each array element of an array with all elements of another array and the other steps required?
assistant
#Here is code to sum of Bitwise OR of each array element of an array with all elements of another array and the other steps required.
 def Bitwise_OR_sum_i ( arr1 , arr2 , M , N ) :
	frequency = [ 0 ] * 32
	for i in range ( N ) :
		bit_position = 0
		num = arr1 [ i ]
		while ( num ) :
			if ( num & 1 != 0 ) :
				frequency [ bit_position ] += 1
			bit_position += 1
			num >>= 1
	for i in range ( M ) :
		num = arr2 [ i ]
		value_at_that_bit = 1
		bitwise_OR_sum = 0
		for bit_position in range ( 32 ) :
			if ( num & 1 != 0 ) :
				bitwise_OR_sum += N * value_at_that_bit
			else :
				bitwise_OR_sum += ( frequency [ bit_position ] * value_at_that_bit )
			num >>= 1
			value_at_that_bit <<= 1
		print ( bitwise_OR_sum , end = " ▁ " )
	return
arr1 = [ 1 , 2 , 3 ]
arr2 = [ 1 , 2 , 3 ]
N = len ( arr1 )
M = len ( arr2 )
Bitwise_OR_sum_i ( arr1 , arr2 , M , N )