human
Solve the following python programming problem given the following code:
def _sendDeferred(self, stanza) : 
    '
        Send presence stanza, adding a deferred with a timeout.

        @param stanza: The presence stanza to send over the wire.
        @type stanza: L{generic.Stanza}

        @param timeout: The number of seconds to wait before the deferred is
            timed out.
        @type timeout: C{int}

        The deferred object L{defer.Deferred} is returned.
        ' 
    def onResponse(element) : 
        if (element.getAttribute ('type') == 'error') : 
            d.errback (error.exceptionFromStanza (element)) 
else : 
            d.callback (UserPresence.fromElement (element)) 
def onTimeout() : 
        d.errback (xmlstream.TimeoutError ('Timeout waiting for response.')) 
def cancelTimeout(result) : 
        if call.active () : 
            call.cancel () 
return result 
def recordOccupant(presence) : 
        occupantJID = presence.sender 
        roomJID = occupantJID.userhostJID () 
        self._roomOccupantMap [roomJID] = occupantJID 
        return presence 
call = self._reactor.callLater (DEFER_TIMEOUT, onTimeout) 
    d = defer.Deferred () 
    d.addBoth (cancelTimeout) 
    d.addCallback (recordOccupant) 
    query = ("/presence[@from='%s' or (@from='%s' and @type='error')]" % (stanza.recipient.full (), stanza.recipient.userhost ())) 
    self.xmlstream.addOnetimeObserver (onTimeout, onResponse, priority = (- 1)) 
    self.xmlstream.send (stanza.toElement ()) 
    return d 

    
    

    Fix the buggy line: self.xmlstream.addOnetimeObserver (onTimeout, onResponse, priority = (- 1))
assistant
#Here is Python code to fix the buggy line: self.

self.xmlstream.addOnetimeObserver (query, onResponse, priority = (- 1))