human
Ways to choose three points with distance between the most distant points <= L | Returns the number of triplets with distance between farthest points <= L.
sort to get ordered triplets so that we can find the distance between farthest points belonging to a triplet.
generate and check for all possible triplets : { arr [ i ] , arr [ j ] , arr [ k ] }.
Since the array is sorted the farthest points will be a [ i ] and a [ k ].
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Driver Code.
set of n points on the X axis"
Solution in Python:

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Write me a code to ways to choose three points with distance between the most distant points <= L and the other steps required?
assistant
#Here is code to ways to choose three points with distance between the most distant points <= L and the other steps required.
 def countTripletsLessThanL ( n , L , arr ) :
	arr . sort ( )
	ways = 0
	for i in range ( n ) :
		for j in range ( i + 1 , n ) :
			for k in range ( j + 1 , n ) :
				mostDistantDistance = arr [ k ] - arr [ i ]
				if ( mostDistantDistance <= L ) :
					ways += 1
	return ways
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 , 4 ]
	n = len ( arr )
	L = 3
	ans = countTripletsLessThanL ( n , L , arr )
	print ( " Total ▁ Number ▁ of ▁ ways ▁ = " , ans )