human
I found an interesting problem on https://leetcode.com/problems/xor-queries-of-a-subarray/:
Given the array arr of positive integers and the array queries where queries[i] = [Li, Ri], for each query i compute the XOR of elements from Li to Ri (that is, arr[Li] xor arr[Li+1] xor ... xor arr[Ri] ). Return an array containing the result for the given queries.
 
Example 1:
Input: arr = [1,3,4,8], queries = [[0,1],[1,2],[0,3],[3,3]]
Output: [2,7,14,8] 
Explanation: 
The binary representation of the elements in the array are:
1 = 0001 
3 = 0011 
4 = 0100 
8 = 1000 
The XOR values for queries are:
[0,1] = 1 xor 3 = 2 
[1,2] = 3 xor 4 = 7 
[0,3] = 1 xor 3 xor 4 xor 8 = 14 
[3,3] = 8

Example 2:
Input: arr = [4,8,2,10], queries = [[2,3],[1,3],[0,0],[0,3]]
Output: [8,0,4,4]

 
Constraints:

1 <= arr.length <= 3 * 10^4
1 <= arr[i] <= 10^9
1 <= queries.length <= 3 * 10^4
queries[i].length == 2
0 <= queries[i][0] <= queries[i][1] < arr.length

I tried it in Python, but could not do it. Can you solve it?

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Can you provide a Python code to compute the XOR of elements from Li to Ri (that is, arr[Li] xor arr[Li+1] xor?
assistant
#Here is Python code to compute the XOR of elements from Li to Ri (that is, arr[Li] xor arr[Li+1] xor .

class Solution:
    def xorQueries(self, arr: List[int], queries: List[List[int]]) -> List[int]:
        xor_arr = [0]*len(arr)
        xor_arr[0] = arr[0]
        for i in range(1,len(arr)):
            xor_arr[i] = xor_arr[i-1] ^ arr[i]

        res = [0]*len(queries)
        for i, (s,e) in enumerate(queries):
            if s == e:
                res[i] = arr[s]
            elif s == 0:
                res[i] = xor_arr[e]
            else:
                res[i] = xor_arr[e] ^ xor_arr[s-1]
                
        return res