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Minimize cost to reduce array to a single element by replacing K consecutive elements by their sum | Function to find the minimum cost to reduce given array to a single element by replacing consecutive K array elements.
Stores length of arr.
If ( N - 1 ) is not multiple of ( K - 1 ).
Store prefix sum of the array.
Iterate over the range [ 1 , N ].
Update prefixSum [ i ].
dp [ i ] [ j ] : Store minimum cost to merge array elements interval [ i , j ].
L : Stores length of interval [ i , j ].
Iterate over each interval [ i , j ] of length L in in [ 0 , N ].
Stores index of last element of the interval [ i , j ].
If L is greater than K.
Update dp [ i ] [ j ].
If ( L - 1 ) is multiple of ( K - 1 ).
Update dp [ i ] [ j ].
Return dp [ 0 ] [ N - 1 ].
Driver Code.
Function Call"
How can the above be solved in Python?
 ... What is a code to minimize cost to reduce array to a single element by replacing K consecutive elements by their sum and the other steps required?
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#Here is code to minimize cost to reduce array to a single element by replacing K consecutive elements by their sum and the other steps required.
 def minimumCostToMergeK ( arr , K ) :
	N = len ( arr )
	if ( N - 1 ) % ( K - 1 ) != 0 :
		return - 1
	prefixSum = [ 0 ] * ( N + 1 )
	for i in range ( 1 , N + 1 ) :
		prefixSum [ i ] = ( prefixSum [ i - 1 ] + arr [ i - 1 ] )
	dp = [ [ 0 ] * N for _ in range ( N ) ]
	for L in range ( K , N + 1 ) :
		for i in range ( N - L + 1 ) :
			j = i + L - 1
			if L > K :
				dp [ i ] [ j ] = ( min ( [ dp [ i ] [ x ] + dp [ x + 1 ] [ j ] for x in range ( i , j , K - 1 ) ] ) )
			if ( L - 1 ) % ( K - 1 ) == 0 :
				dp [ i ] [ j ] += ( prefixSum [ j + 1 ] - prefixSum [ i ] )
	return dp [ 0 ] [ N - 1 ]
if __name__ == " _ _ main _ _ " :
	arr = [ 3 , 5 , 1 , 2 , 6 ]
	K = 3
print ( minimumCostToMergeK ( arr , K ) )