human
Solve in Python:
We are given head, the head node of a linked list containing unique integer values.
We are also given the list G, a subset of the values in the linked list.
Return the number of connected components in G, where two values are connected if they appear consecutively in the linked list.
Example 1:
Input: 
head: 0->1->2->3
G = [0, 1, 3]
Output: 2
Explanation: 
0 and 1 are connected, so [0, 1] and [3] are the two connected components.

Example 2:
Input: 
head: 0->1->2->3->4
G = [0, 3, 1, 4]
Output: 2
Explanation: 
0 and 1 are connected, 3 and 4 are connected, so [0, 1] and [3, 4] are the two connected components.

Note: 

If N is the length of the linked list given by head, 1 <= N <= 10000.
The value of each node in the linked list will be in the range [0, N - 1].
1 <= G.length <= 10000.
G is a subset of all values in the linked list.
assistant
#Here is the Python program you requested.

class Solution:
    def numComponents(self, head: ListNode, G: List[int]) -> int:
        tail = head
        components = 0
        connected = False
        while tail is not None:
            if tail.val in G:
                connected = True
            elif connected:
                components += 1
                connected = False
            tail = tail.next
        if connected:
            components += 1
            connected = False
        return components