human
Check if the given string is vowel prime | Function that returns true if c is a vowel.
Function that returns true if all the vowels in the given string are only at prime indices.
Create a boolean array " prime [ 0 . . n ] " and initialize all entries in it as true . A value in prime [ i ] will finally be false if i is Not a prime , else true ..
0 and 1 are not prime.
If prime [ p ] is not changed , then it is a prime.
Update all multiples of p greater than or equal to the square of it numbers which are multiple of p and are less than p ^ 2 are already been marked ..
For every character of the given String.
If current character is vowel and the index is not prime.
Driver code"
How can the above be solved in Python?

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Can you provide a code to check if the given string is vowel prime and the other steps required?
assistant
#Here is code to check if the given string is vowel prime and the other steps required.
 def isVowel ( c ) :
	if ( c == ' a ' or c == ' e ' or c == ' i ' or c == ' o ' or c == ' u ' ) :
		return True
	return False
def isVowelPrime ( Str , n ) :
	prime = [ True for i in range ( n ) ]
	prime [ 0 ] = False
	prime [ 1 ] = False
	for p in range ( 2 , n ) :
		if p * p > n :
			break
		if ( prime [ p ] == True ) :
			for i in range ( 2 * p , n , p ) :
				prime [ i ] = False
	for i in range ( n ) :
		if ( isVowel ( Str [ i ] ) and prime [ i ] == False ) :
			return False
	return True
Str = " geeksforgeeks " ;
n = len ( Str )
if ( isVowelPrime ( Str , n ) ) :
	print ( " Yes " )
else :
	print ( " No " )