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Split N powers of 2 into two subsets such that their difference of sum is minimum | Python3 program to find the minimum difference possible by splitting all powers of 2 up to N into two sets of equal size.
Store the largest.
Form two separate groups.
Initialize the sum for two groups as 0.
Insert 2 ^ n in the first group.
Calculate the sum of least n / 2 - 1 elements added to the first set.
sum of remaining n / 2 - 1 elements.
Min Difference between the two groups.
Driver code"
Solution in Python:
 ... Give me a code to split N powers of 2 into two subsets such that their difference of sum is minimum and the other steps required?
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#Here is code to split N powers of 2 into two subsets such that their difference of sum is minimum and the other steps required.
 def MinDiff ( n ) :
	val = 2 ** n
	sep = n // 2
	grp1 = 0
	grp2 = 0
	grp1 = grp1 + val
	for i in range ( 1 , sep ) :
		grp1 = grp1 + 2 ** i
	for i in range ( sep , n ) :
		grp2 = grp2 + 2 ** i
	print ( abs ( grp1 - grp2 ) )
if __name__ == ' _ _ main _ _ ' :
	n = 4
	MinDiff ( n )