human
Find a number containing N | Function to return the generated by appending "10" n - 1 times.
Initialising as empty.
Function to return the decimal equivaLent of the given binary string.
Initializing base value to 1 i . e 2 ^ 0.
Function that calls the constructString and binarytodecimal and returns the answer.
Driver code"
Solution in Python:
 ... Write me a code to find a number containing N and the other steps required?
assistant
#Here is code to find a number containing N and the other steps required.
 def constructString ( n ) :
	s = " "
	for i in range ( n ) :
		s += "10"
	return s
def binaryToDecimal ( n ) :
	num = n
	dec_value = 0
	base = 1
	Len = len ( num )
	for i in range ( Len - 1 , - 1 , - 1 ) :
		if ( num [ i ] == '1' ) :
			dec_value += base
		base = base * 2
	return dec_value
def findNumber ( n ) :
	s = constructString ( n - 1 )
	num = binaryToDecimal ( s )
	return num
n = 4
print ( findNumber ( n ) )