human
Solve the following python programming problem given the following code:
@ defun 
def legenq(ctx, n, m, z, type = 2, **kwargs) : 
    n = ctx.convert (n) 
    m = ctx.convert (m) 
    z = ctx.convert (z) 
    if (z in (1, (- 1))) : 
        return ctx.nan 
if (type == 2) : 
        def h(n, m) : 
            (cos, sin) = ctx.cospi_sinpi (m) 
            s = ((2 * sin) / ctx.pi) 
            c = cos 
            a = (1 + z) 
            b = (1 - z) 
            u = (m / 2) 
            w = ((1 - z) / 2) 
            T1 = ([s, c, a, b], [(- 1), 1, u, (- u)], [], [(1 - m)], [(- n), (n + 1)], [(1 - m)], w) 
            T2 = ([(- s), a, b], [(- 1), (- u), u], [((n + m) + 1)], [((n - m) + 1), (m + 1)], [(- n), (n + 1)], [(m + 1)], w) 
            return (T1, T2) 
return ctx.hypercomb (h, [n, m], ** kwargs) 
if (type == 3) : 
        if (abs (z) > 1) : 
            def h(n, m) : 
                T1 = ([ctx.expjpi (m), 2, ctx.pi, z, (z - 1), (z + 1)], [1, ((- n) - 1), 0.5, (((- n) - m) - 1), (0.5 * m), (0.5 * m)], [((n + m) + 1)], [(n + 1.5)], [(0.5 * ((2 + n) + m)), (0.5 * ((1 + n) + m))], [(n + 1.5)], (z ** (- 2))) 
                return [T1] 
return ctx.hypercomb (h, [n, m], ** ctx) 
else : 
            def h(n, m) : 
                s = ((2 * ctx.sinpi (m)) / ctx.pi) 
                c = ctx.expjpi (m) 
                a = (1 + z) 
                b = (z - 1) 
                u = (m / 2) 
                w = ((1 - z) / 2) 
                T1 = ([s, c, a, b], [(- 1), 1, u, (- u)], [], [(1 - m)], [(- n), (n + 1)], [(1 - m)], w) 
                T2 = ([(- s), c, a, b], [(- 1), 1, (- u), u], [((n + m) + 1)], [((n - m) + 1), (m + 1)], [(- n), (n + 1)], [(m + 1)], w) 
                return (T1, T2) 
return ctx.hypercomb (h, [n, m], ** kwargs) 
raise ValueError ('requires type=2 or type=3') 

    
    

    Fix the buggy line: return ctx.hypercomb (h, [n, m], ** ctx)
assistant
#Here is Python code to fix the buggy line: return ctx.

return ctx.hypercomb (h, [n, m], ** kwargs)