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Check if N is a Balanced Prime number or not | Utility function to check if a number is prime or not.
Corner cases.
This is checked so that we can skip middle five numbers in below loop.
Function that returns true if n is a Balanced prime.
If n is not a prime number or n is the first prime then return false.
Initialize previous_prime to n - 1 and next_prime to n + 1.
Find next prime number.
Find previous prime number.
Arithmetic mean.
If n is a weak prime.
Driver code"
Solution in Python:

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Can you provide a code to check if N is a Balanced Prime number or not and the other steps required?
assistant
#Here is code to check if N is a Balanced Prime number or not and the other steps required.
 def isPrime ( n ) :
	if n <= 1 :
		return False
	if n <= 3 :
		return True
	if n % 2 == 0 or n % 3 == 0 :
		return False
	i = 5
	while i * i <= n :
		if ( n % i == 0 or n % ( i + 2 ) == 0 ) :
			return False
		i += 6
	return True
def isBalancedPrime ( n ) :
	if not isPrime ( n ) or n == 2 :
		return False
	previous_prime = n - 1
	next_prime = n + 1
	while not isPrime ( next_prime ) :
		next_prime += 1
	while not isPrime ( previous_prime ) :
		previous_prime -= 1
	mean = ( previous_prime + next_prime ) / 2
	if n == mean :
		return True
	else :
		return False
n = 53
if isBalancedPrime ( n ) :
	print ( " Yes " )
else :
	print ( " No " )