human
Can you provide a code to count of non co and the other steps required given the following:
Count of non co | Recursive program to return gcd of two numbers.
Function to count the number of non co - prime pairs for each query.
Traverse the array arr [ ].
Stores the count of non co - prime pairs.
Iterate over the range [ 1 , x ].
Iterate over the range [ x , y ].
If gcd of current pair is greater than 1.
Driver code.
Given Input.
Function Call"
Solution in Python:
assistant
#Here is code to count of non co and the other steps required.
 def gcd ( a , b ) :
	if b == 0 :
		return a
	return gcd ( b , a % b )
def countPairs ( arr , N ) :
	for i in range ( 0 , N ) :
		count = 0
		for x in range ( 1 , arr [ i ] + 1 ) :
			for y in range ( x , arr [ i ] + 1 ) :
				if gcd ( x , y ) > 1 :
					count += 1
		print ( count , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 5 , 10 , 20 ]
	N = len ( arr )
	countPairs ( arr , N )