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Kth smallest element from an array of intervals | Function to get the Kth smallest element from an array of intervals.
Store all the intervals so that it returns the minimum element in O ( 1 ).
Insert all Intervals into the MinHeap.
Stores the count of popped elements.
Iterate over MinHeap.
Stores minimum element from all remaining intervals.
Remove minimum element.
Check if the minimum of the current interval is less than the maximum of the current interval.
Insert new interval.
Driver Code.
Intervals given.
Size of the arr"
Solution in Python:
 Can you provide a code to kth smallest element from an array of intervals and the other steps required?
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#Here is code to kth smallest element from an array of intervals and the other steps required.
 def KthSmallestNum ( arr , n , k ) :
	pq = [ ]
	for i in range ( n ) :
		pq . append ( [ arr [ i ] [ 0 ] , arr [ i ] [ 1 ] ] )
	cnt = 1
	while ( cnt < k ) :
		pq . sort ( reverse = True )
		interval = pq [ 0 ]
		pq . remove ( pq [ 0 ] )
		if ( interval [ 0 ] < interval [ 1 ] ) :
			pq . append ( [ interval [ 0 ] + 1 , interval [ 1 ] ] )
		cnt += 1
	pq . sort ( reverse = True )
	return pq [ 0 ] [ 0 ] + 1
if __name__ == ' _ _ main _ _ ' :
	arr = [ [ 5 , 11 ] , [ 10 , 15 ] , [ 12 , 20 ] ]
	n = len ( arr )
	k = 12
	print ( KthSmallestNum ( arr , n , k ) )