human
Minimum and maximum count of elements at D distance from arr [ i ] in either direction | ''Function to find the minimum and maximum number of points included in a range of distance D.
'' Stores the minimum and maximum  number of points that lies  over the distance of D.
'' Iterate the array.
'' Count of elements included  to left of point at index i.
'' Update the minimum number  of points.
'' Update the maximum number  of points.
'' Count of elements included  to right of point at index i.
'' Update the minimum number  of points.
'' Update the maximum number  of points.
'' Return the array.
''Function to perform the Binary Search to the left of arr[i] over the given range.
'' Base Case.
'' Binary Search for index to left.
'' update index.
'' Return the number of elements  by subtracting indices.
''Function to perform the Binary Search to the right of arr[i] over the given range.
'' Base Case.
'' Binary Search for index to right.
'' Update the index.
'' Return the number of elements  by subtracting indices.
''Driver Code.
''Function Call"
How can the above be solved in Python?

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What is a code to minimum and maximum count of elements at D distance from arr [ i ] in either direction and the other steps required?
assistant
#Here is code to minimum and maximum count of elements at D distance from arr [ i ] in either direction and the other steps required.
 def minMaxRange ( arr , D , N ) :
	Max = 1
	Min = N
	for i in range ( N ) :
		dist = leftSearch ( arr , arr [ i ] - D , i )
		Min = min ( Min , dist )
		Max = max ( Max , dist )
		dist = rightSearch ( arr , arr [ i ] + D , i )
		Min = min ( Min , dist )
		Max = max ( Max , dist )
	return [ Min , Max ]
def leftSearch ( arr , val , i ) :
	if ( i == 0 ) :
		return 1
	left = 0
	right = i - 1
	ind = - 1
	while ( left <= right ) :
		mid = ( left + right ) // 2
		if ( arr [ mid ] < val ) :
			left = mid + 1
		else :
			right = mid - 1
			ind = mid
	return i - ind + 1 if ind != - 1 else 1
def rightSearch ( arr , val , i ) :
	if ( i == len ( arr ) - 1 ) :
		return 1
	left = i + 1
	right = len ( arr ) - 1
	ind = - 1
	while ( left <= right ) :
		mid = ( left + right ) // 2
		if ( arr [ mid ] > val ) :
			right = mid - 1
		else :
			left = mid + 1
			ind = mid
	return ind - i + 1 if ind != - 1 else 1
arr = [ 1 , 3 , 5 , 9 , 14 ]
N = len ( arr )
D = 4
minMax = minMaxRange ( arr , D , N )
print ( f " { minMax [ 0 ] } ▁ { minMax [ 1 ] } " )