human
Solve the following python programming problem given the following code:
def _threaded_method(method_name, sync_name, reactor_name, threadpool_name) : 
    '
    Create a method that calls another method in a threadpool.

    :param str method_name: The name of the method to look up on the "sync"
        object.
    :param str sync_name: The name of the attribute of ``self`` on which to
        look up the other method to run.  This is the "sync" object.
    :param str reactor_name: The name of the attribute of ``self`` referencing
        the reactor to use to get results back to the calling thread.
    :param str threadpool_name: The name of the attribute of ``self``
        referencing a ``twisted.python.threadpool.ThreadPool`` instance to use
        to run the method in a different thread.

    :return: The new thread-using method.  It has the same signature as the
             original method except it returns a ``Deferred`` that fires with
             the original method\'s result.
    ' 
    def _run_in_thread(self, * args, **kwargs) : 
        reactor = getattr (self, reactor_name) 
        sync = getattr (self, sync_name) 
        threadpool = getattr (self, threadpool_name) 
        original = getattr (sync, method_name) 
        return deferToThreadPool (reactor, threadpool, preserve_context (original), * args, ** kwargs) 
return method_name 

    
    

    Fix the buggy line: return method_name
assistant
#Here is Python program to fix the buggy line: return method_name
.

return def _run_in_thread(