human
Count characters of a string which when removed individually makes the string equal to another string | Function to count characters from A whose removal makes the strings A and B equal.
Stores the index of the longest prefix.
Stores the index of the longest suffix.
Traverse the B.
Traverse the B.
If N - M is equal to 1 and Y is less than or equal to X.
Print count of characters.
Print positions of the characters.
Otherwise.
Driver Code"
How can the above be solved in Python?
 Write me a code to count characters of a string which when removed individually makes the string equal to another string and the other steps required?
assistant
#Here is code to count characters of a string which when removed individually makes the string equal to another string and the other steps required.
 def RemoveOneChar ( A , B , N , M ) :
	X = 0
	Y = N - 1
	for i in range ( M ) :
		if ( A [ X ] != B [ i ] ) :
			break
		X += 1
	for i in range ( M - 1 , - 1 , - 1 ) :
		if ( A [ Y ] != B [ i ] ) :
			break
		Y -= 1
	if ( N - M == 1 and Y < X ) :
		print ( X - Y + 1 )
		for i in range ( Y , X + 1 ) :
			print ( i + 1 , end = " ▁ " )
		print ( )
	else :
		print ( - 1 )
if __name__ == ' _ _ main _ _ ' :
	A = " abaac "
	B = " abac "
	N = len ( A )
	M = len ( B )
	RemoveOneChar ( A , B , N , M )