human
What is a code to count pairs in an array having sum of elements with their respective sum of digits equal and the other steps required given the following:
Count pairs in an array having sum of elements with their respective sum of digits equal | Function to find the sum of digits of the number N.
Stores the sum of digits.
If the number N is greater than 0.
Return the sum.
Function to find the count of pairs such that arr [ i ] + sumOfDigits ( arr [ i ] ) is equal to ( arr [ j ] + sumOfDigits ( arr [ j ] ).
Stores the frequency of value of arr [ i ] + sumOfDigits ( arr [ i ] ).
Traverse the given array.
Find the value.
Increment the frequency.
Stores the total count of pairs.
Traverse the map mp.
Update the count of pairs.
Return the total count of pairs.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count pairs in an array having sum of elements with their respective sum of digits equal and the other steps required.
 def sumOfDigits ( N ) :
	sum = 0
	while ( N ) :
		sum += ( N % 10 )
		N = N // 10
	return sum
def CountPair ( arr , n ) :
	mp = { }
	for i in range ( n ) :
		val = arr [ i ] + sumOfDigits ( arr [ i ] )
		if val in mp :
			mp [ val ] += 1
		else :
			mp [ val ] = 1
	count = 0
	for key , value in mp . items ( ) :
		val = key
		times = value
		count += ( ( times * ( times - 1 ) ) // 2 )
	return count
if __name__ == ' _ _ main _ _ ' :
	arr = [ 105 , 96 , 20 , 2 , 87 , 96 ]
	N = len ( arr )
	print ( CountPair ( arr , N ) )