human
Count of N | Function to find count of N - digit numbers with single digit XOR.
Range of numbers.
Calculate XOR of digits.
If XOR <= 9 , then increment count.
Print the count.
Given number.
Function call"
Solution in Python:
assistant
#Here is code to count of N and the other steps required.
 def countNums ( N ) :
	l = pow ( 10 , N - 1 )
	r = pow ( 10 , N ) - 1
	count = 0
	for i in range ( l , r + 1 ) :
		xorr = 0
		temp = i
		while ( temp > 0 ) :
			xorr = xorr ^ ( temp % 10 )
			temp //= 10
		if ( xorr <= 9 ) :
			count += 1
	print ( count )
N = 2
countNums ( N )