human
What is a code to count number of triplets ( a , b , c ) from first N natural numbers such that a * b + c = N and the other steps required given the following:
Count number of triplets ( a , b , c ) from first N natural numbers such that a * b + c = N | Function to find the count of triplets ( a , b , c ) with a * b + c = N.
Stores count of triplets of 1 st N natural numbers which are of the form a * b + c = N.
Iterate over the range [ 1 , N ].
If N is divisible by i.
Update cntTriplet.
Update cntTriplet.
Driver code"
Solution in Python:
assistant
#Here is code to count number of triplets ( a , b , c ) from first N natural numbers such that a * b + c = N and the other steps required.
 def findCntTriplet ( N ) :
	cntTriplet = 0 ;
	for i in range ( 1 , N ) :
		if ( N % i != 0 ) :
			cntTriplet += N // i ;
		else :
			cntTriplet += ( N // i ) - 1 ;
	return cntTriplet ;
if __name__ == ' _ _ main _ _ ' :
	N = 3 ;
	print ( findCntTriplet ( N ) ) ;