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Sum of bit differences among all pairs | Python program to compute sum of pairwise bit differences.
traverse over all bits.
count number of elements with i 'th bit set.
Add " count ▁ * ▁ ( n ▁ - ▁ count ) ▁ * ▁ 2" to the answer.
Driver prorgram"
Solution in Python:
 Give me a code to sum of bit differences among all pairs and the other steps required?
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#Here is code to sum of bit differences among all pairs and the other steps required.
 def sumBitDifferences ( arr , n ) :
	for i in range ( 0 , 32 ) :
		count = 0
		for j in range ( 0 , n ) :
			if ( ( arr [ j ] & ( 1 << i ) ) ) :
				count += 1
		ans += ( count * ( n - count ) * 2 ) ;
	return ans
arr = [ 1 , 3 , 5 ]
n = len ( arr )
print ( sumBitDifferences ( arr , n ) )