human
Sum of non | Function to return a vector which consists the sum of four portions of the matrix.
Iterating through the matrix.
Condition for selecting all values before the second diagonal of metrics.
Top portion of the matrix.
Left portion of the matrix.
Bottom portion of the matrix.
Right portion of the matrix.
Adding all the four portions into a vecto.
Driver code"
How can the above be solved in Python?
 Write me a code to sum of non and the other steps required?
assistant
#Here is code to sum of non and the other steps required.
 def sumOfParts ( arr , N ) :
	sum_part1 , sum_part2 , sum_part3 , sum_part4 = 0 , 0 , 0 , 0
	totalsum = 0
	for i in range ( N ) :
		for j in range ( N ) :
			if i + j < N - 1 :
				if ( i < j and i != j and i + j ) :
					sum_part1 += arr [ i ] [ j ]
				elif i != j :
					sum_part2 += arr [ i ] [ j ]
			else :
				if i > j and i + j != N - 1 :
					sum_part3 += arr [ i ] [ j ]
				else :
					if i + j != N - 1 and i != j :
						sum_part4 += arr [ i ] [ j ]
	return sum_part1 + sum_part2 + sum_part3 + sum_part4
N = 4
arr = [ [ 1 , 2 , 3 , 4 ] , [ 5 , 6 , 7 , 8 ] , [ 9 , 10 , 11 , 12 ] , [ 13 , 14 , 15 , 16 ] ]
print ( sumOfParts ( arr , N ) )