human
Count subsequences with same values of Bitwise AND , OR and XOR | ''function for finding count of possible subsequence.
'' creating a map to count the frequency of each element.
store frequency of each element.
iterate through the map.
add all possible combination for key equal zero.
add all ( odd number of elements ) possible combination for key other than zero.
Driver function"
How can the above be solved in Python?
assistant
#Here is code to count subsequences with same values of Bitwise AND , OR and XOR and the other steps required.
 def countSubseq ( arr , n ) :
	count = 0
	mp = { }
	for x in arr :
		if x in mp . keys ( ) :
			mp [ x ] += 1
		else :
			mp [ x ] = 1
	for i in mp . keys ( ) :
		if ( i == 0 ) :
			count += pow ( 2 , mp [ i ] ) - 1
		else :
			count += pow ( 2 , mp [ i ] - 1 )
	return count
arr = [ 2 , 2 , 2 , 5 , 6 ]
n = len ( arr )
print ( countSubseq ( arr , n ) )