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Create a Sorted Array Using Binary Search | Function to create a new sorted array using Binary Search.
Auxiliary Array.
if b is empty any element can be at first place.
Perform Binary Search to find the correct position of current element in the new array.
let the element should be at first index.
if a [ j ] is already present in the new array.
add a [ j ] at mid + 1. you can add it at mid.
if a [ j ] is lesser than b [ mid ] go right side.
means pos should be between start and mid - 1.
else pos should be between mid + 1 and end.
if a [ j ] is the largest push it at last.
here max ( 0 , pos ) is used because sometimes pos can be negative as smallest duplicates can be present in the array.
Print the new generated sorted array.
Driver Code"
Solution in Python:
 Can you provide a code to create a Sorted Array Using Binary Search and the other steps required?
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#Here is code to create a Sorted Array Using Binary Search and the other steps required.
 def createSorted ( a : list , n : int ) :
	b = [ ]
	for j in range ( n ) :
		if len ( b ) == 0 :
			b . append ( a [ j ] )
		else :
			start = 0
			end = len ( b ) - 1
			pos = 0
			while start <= end :
				mid = start + ( end - start ) // 2
				if b [ mid ] == a [ j ] :
					b . insert ( max ( 0 , mid + 1 ) , a [ j ] )
					break
				elif b [ mid ] > a [ j ] :
					pos = end = mid - 1
				else :
					pos = start = mid + 1
				if start > end :
					pos = start
					b . insert ( max ( 0 , pos ) , a [ j ] )
					break
	for i in range ( n ) :
		print ( b [ i ] , end = " ▁ " )
if __name__ == " _ _ main _ _ " :
	a = [ 2 , 5 , 4 , 9 , 8 ]
	n = len ( a )
	createSorted ( a , n )