human
Count of pairs from 1 to a and 1 to b whose sum is divisible by N | Function to find the distinct pairs from 1 - a & 1 - b such that their sum is divisible by n ..
pairs from 1 to n * ( a / n ) and 1 to n * ( b / n ).
pairs from 1 to n * ( a / n ) and n * ( b / n ) to b.
pairs from n * ( a / n ) to a and 1 to n * ( b / n ).
pairs from n * ( a / n ) to a and n * ( b / n ) to b.
Return answer.
Driver code"
Solution in Python:

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Can you provide a code to count of pairs from 1 to a and 1 to b whose sum is divisible by N and the other steps required?
assistant
#Here is code to count of pairs from 1 to a and 1 to b whose sum is divisible by N and the other steps required.
 def findCountOfPairs ( a , b , n ) :
	ans = 0
	ans += n * int ( a / n ) * int ( b / n )
	ans += int ( a / n ) * ( b % n )
	ans += ( a % n ) * int ( b / n )
	ans += int ( ( ( a % n ) + ( b % n ) ) / n ) ;
	return ans
if __name__ == ' _ _ main _ _ ' :
	a = 5
	b = 13
	n = 3
	print ( findCountOfPairs ( a , b , n ) )