human
Deserium Number | Returns count of digits in n ..
Returns true if x is Diserium.
Compute powers of digits from right to left ..
If sum of powers is same as given number ..
Driver code"
Solution in Python:

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Give me a code to deserium Number and the other steps required?
assistant
#Here is code to deserium Number and the other steps required.
 def countDigits ( n ) :
	c = 0
	while ( n != 0 ) :
		c += 1
		n = int ( n / 10 )
	return c
def isDeserium ( x ) :
	temp = x
	p = countDigits ( x )
	sum = 0
	while ( x != 0 ) :
		digit = int ( x % 10 )
		sum += pow ( digit , p )
		p -= 1
		x = int ( x / 10 )
	return ( sum == temp )
x = 135
if ( isDeserium ( x ) ) :
	print ( " Yes " )
else :
	print ( " No " )