human
Check if any point overlaps the given Circle and Rectangle | Function to check if any point overlaps the given Circle and Rectangle.
Find the nearest point on the rectangle to the center of the circle.
Find the distance between the nearest point and the center of the circle Distance between 2 points , ( x1 , y1 ) & ( x2 , y2 ) in 2D Euclidean space is ( ( x1 - x2 ) * * 2 + ( y1 - y2 ) * * 2 ) * * 0.5.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to check if any point overlaps the given Circle and Rectangle and the other steps required.
 def checkOverlap ( R , Xc , Yc , X1 , Y1 , X2 , Y2 ) :
	Xn = max ( X1 , min ( Xc , X2 ) )
	Yn = max ( Y1 , min ( Yc , Y2 ) )
	Dx = Xn - Xc
	Dy = Yn - Yc
	return ( Dx ** 2 + Dy ** 2 ) <= R ** 2
if ( __name__ == " _ _ main _ _ " ) :
	R = 1
	Xc , Yc = 0 , 0
	X1 , Y1 = 1 , - 1
	X2 , Y2 = 3 , 1
	print ( checkOverlap ( R , Xc , Yc , X1 , Y1 , X2 , Y2 ) )