human
Blum Integer | Function to cheek if number is Blum Integer.
to store prime numbers from 2 to n.
If prime [ i ] is not changed , then it is a prime.
Update all multiples of p.
to check if the given odd integer is Blum Integer or not.
checking the factors are of 4 t + 3 form or not.
give odd integer greater than 20"
Solution in Python:
assistant
#Here is code to blum Integer and the other steps required.
 def isBlumInteger ( n ) :
	prime = [ True ] * ( n + 1 )
	i = 2
	while ( i * i <= n ) :
		if ( prime [ i ] == True ) :
			for j in range ( i * 2 , n + 1 , i ) :
				prime [ j ] = False
		i = i + 1
	for i in range ( 2 , n + 1 ) :
		if ( prime [ i ] ) :
			if ( ( n % i == 0 ) and ( ( i - 3 ) % 4 ) == 0 ) :
				q = int ( n / i )
				return ( q != i and prime [ q ] and ( q - 3 ) % 4 == 0 )
	return False
n = 249
if ( isBlumInteger ( n ) ) :
	print ( " Yes " )
else :
	print ( " No " )