human
Write me a code to count all possible N and the other steps required given the following:
Count all possible N | Function to find the number of vowel permutations possible.
To avoid the large output value.
Initialize 2D dp array.
Initialize dp [ 1 ] [ i ] as 1 since string of length 1 will consist of only one vowel in the string.
Directed graph using the adjacency matrix.
Iterate over the range [ 1 , N ].
Traverse the directed graph.
Traversing the list.
Update dp [ i + 1 ] [ u ].
Stores total count of permutations.
Return count of permutations.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count all possible N and the other steps required.
 def countVowelPermutation ( n ) :
	MOD = 1e9 + 7
	dp = [ [ 0 for i in range ( 5 ) ] for j in range ( n + 1 ) ]
	for i in range ( 5 ) :
		dp [ 1 ] [ i ] = 1
	relation = [ [ 1 ] , [ 0 , 2 ] , [ 0 , 1 , 3 , 4 ] , [ 2 , 4 ] , [ 0 ] ]
	for i in range ( 1 , n , 1 ) :
		for u in range ( 5 ) :
			dp [ i + 1 ] [ u ] = 0
			for v in relation [ u ] :
				dp [ i + 1 ] [ u ] += dp [ i ] [ v ] % MOD
	ans = 0
	for i in range ( 5 ) :
		ans = ( ans + dp [ n ] [ i ] ) % MOD
	return int ( ans )
if __name__ == ' _ _ main _ _ ' :
	N = 2
	print ( countVowelPermutation ( N ) )