human
Write me a code to minimum operations to make sum of neighbouring elements <= X and the other steps required given the following:
Minimum operations to make sum of neighbouring elements <= X | Function to return the minimum number of operations required.
To store total operations required.
First make all elements equal to x which are currenctly greater.
Left scan the array.
Update the current element such that neighbouring sum is < x.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to minimum operations to make sum of neighbouring elements <= X and the other steps required.
 def MinOperations ( n , x , arr ) :
	total = 0
	for i in range ( n ) :
		if ( arr [ i ] > x ) :
			difference = arr [ i ] - x
			total = total + difference
			arr [ i ] = x
	for i in range ( n ) :
		LeftNeigbouringSum = arr [ i ] + arr [ i - 1 ]
		if ( LeftNeigbouringSum > x ) :
			current_diff = LeftNeigbouringSum - x
			arr [ i ] = max ( 0 , arr [ i ] - current_diff )
			total = total + current_diff
	return total
X = 1
arr = [ 1 , 6 , 1 , 2 , 0 , 4 ]
N = len ( arr )
print ( MinOperations ( N , X , arr ) )