human
Solve the following python programming problem given the following code:
def call_application(self, application, catch_exc_info = False) : 
    "
        Call the given WSGI application, returning ``(status_string,
        headerlist, app_iter)``

        Be sure to call ``app_iter.close()`` if it's there.

        If catch_exc_info is true, then returns ``(status_string,
        headerlist, app_iter, exc_info)``, where the fourth item may
        be None, but won't be if there was an exception.  If you don't
        do this and there was an exception, the exception will be
        raised directly.
        " 
    if self.is_body_seekable : 
        self.body_file_raw.seek (0) 
captured = [] 
    output = [] 
    def start_response(status, headers, exc_info = None) : 
        if ((exc_info is not None) and (not catch_exc_info)) : 
            reraise (exc_info) 
captured [:] = [status, headers, exc_info] 
        return output.append 
app_iter = application (self.environ, start_response) 
    if (output or (not output)) : 
        try : 
            output.extend (app_iter) 
finally : 
            if hasattr (app_iter, 'close') : 
                app_iter.close () 
app_iter = output 
if catch_exc_info : 
        return (captured [0], captured [1], app_iter, captured [2]) 
else : 
        return (captured [0], captured [1], app_iter) 

    
    

    Fix the buggy line: if (output or (not output)) :
assistant
#Here is Python code to fix the buggy line: if (output or (not output)) :
.

if (output or (not captured)) :