human
Minimum jumps required to group all 1 s together in a given Binary string | Function to get the minimum jump value.
Store all indices of ones.
Populating one 's indices.
Calculate median.
Jumps required for 1 's  to the left of median.
Jumps required for 1 's  to the right of median.
Return the final answer.
Driver Code"
Solution in Python:
 ... What is a code to minimum jumps required to group all 1 s together in a given Binary string and the other steps required?
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#Here is code to minimum jumps required to group all 1 s together in a given Binary string and the other steps required.
 def getMinJumps ( s ) :
	ones = [ ]
	jumps , median , ind = 0 , 0 , 0
	for i in range ( len ( s ) ) :
		if ( s [ i ] == '1' ) :
			ones . append ( i )
	if ( len ( ones ) == 0 ) :
		return jumps
	median = ones [ len ( ones ) // 2 ]
	ind = median
	for i in range ( ind , - 1 , - 1 ) :
		if ( s [ i ] == '1' ) :
			jumps += ind - i
			ind -= 1
	ind = median
	for i in range ( ind , len ( s ) ) :
		if ( s [ i ] == '1' ) :
			jumps += i - ind
			ind += 1
	return jumps
if __name__ == ' _ _ main _ _ ' :
	s = "00100000010011"
	print ( getMinJumps ( s ) )