human
Solve the following python programming problem given the following code:
def parse_xcodeproject_xml(text, dictionarytype = dict) : 
    'We parse the XML format by transforming the document into a simplified plist format
    and handing this off to our plist parser.
    ' 
    structures = { 
        'dict' : '{};', 
        'array' : '(),', 
} 
    stack = ['dummy'] 
    tokens = [] 
    def emit(s) : 
        tokens.append (s) 
def emit_text(s) : 
        emit (quoted_string (s)) 
def emit_terminator(parent) : 
        structure_markers = structures.get (parent) 
        if (structure_markers is not None) : 
            emit (structure_markers [(- 1)]) 
            emit ('
') 
def iterxml(buf) : 
        try : 
            for (event, elem) in ETree.iterparse (buf, events = ('start', 'end')) : 
                tag = elem.tag 
                if (event == 'start') : 
                    stack.append (tag) 
else : 
                    stack.pop () 
parent = stack [(- 1)] 
                if (event == 'end') : 
                    if (tag == 'key') : 
                        emit_text (elem.text) 
                        emit ('=') 
else : 
                        if (tag == 'string') : 
                            emit_text (elem.text) 
                            emit_terminator (parent) 
structure_markers = structures.get (tag) 
                if structure_markers : 
                    if (event == 'start') : 
                        emit (structure_markers [0]) 
else : 
                        emit (structure_markers [1]) 
                        emit_terminator (parent) 
except ETree.ParseError as e : 
            (linenr, column, errortext) = error_report_from ('XML', text, text_type (e)) 
            return { 
                'error_column' : column, 
                'error_line_number' : linenr, 
                'error_text' : errortext, 
} 
return None 
errorparseinfo = iterxml (BytesIO (bytestr (text))) 
    if (errorparseinfo is not None) : 
        return (None, errorparseinfo) 
text = ''.join (tokens) 
    (root, parseinfo) = parse_xcodeproject_plist...

    
    

    Fix the buggy line: (root, parseinfo) = parse_xcodeproject_plist (errorparseinfo, dictionarytype = dictionarytype)
assistant
#Here is Python program to fix the buggy line: (root, parseinfo) = parse_xcodeproject_plist (errorparseinfo, dictionarytype = dictionarytype)
.

(root, parseinfo) = parse_xcodeproject_plist (text, dictionarytype = dictionarytype)