human
Count of N | Function to calculate and return the reverse of the number.
Function to calculate the total count of N - digit numbers satisfying the necessary conditions.
Initialize two variables.
Calculate the sum of odd and even positions.
Check for divisibility.
Return the answer.
Driver Code"
How can the above be solved in Python?
 ... What is a code to count of N and the other steps required?
assistant
#Here is code to count of N and the other steps required.
 def reverse ( num ) :
	rev = 0 ;
	while ( num > 0 ) :
		r = int ( num % 10 ) ;
		rev = rev * 10 + r ;
		num = num // 10 ;
	return rev ;
def count ( N , A , B ) :
	l = int ( pow ( 10 , N - 1 ) ) ;
	r = int ( pow ( 10 , N ) - 1 ) ;
	if ( l == 1 ) :
		l = 0 ;
	ans = 0 ;
	for i in range ( l , r + 1 ) :
		even_sum = 0 ;
		odd_sum = 0 ;
		itr = 0 ;
		num = reverse ( i ) ;
		while ( num > 0 ) :
			if ( itr % 2 == 0 ) :
				odd_sum += num % 10 ;
			else :
				even_sum += num % 10 ;
			num = num // 10 ;
			itr += 1 ;
		if ( even_sum % A == 0 and odd_sum % B == 0 ) :
			ans += 1 ;
	return ans ;
if __name__ == ' _ _ main _ _ ' :
	N = 2 ;
	A = 5 ;
	B = 3 ;
	print ( count ( N , A , B ) ) ;