human
Remaining array element after repeated removal of the smallest element from pairs with absolute difference of 2 or 0 | Function to find the last remaining array element after repeatedly removing the smallest from pairs having absolute difference 2 or 0.
Sort the given array in ascending order.
Traverse the array.
If difference between adjacent elements is not equal to 0 or 2.
If operations can be performed.
Driver Code"
How can the above be solved in Python?
 Can you provide a code to remaining array element after repeated removal of the smallest element from pairs with absolute difference of 2 or 0 and the other steps required?
assistant
#Here is code to remaining array element after repeated removal of the smallest element from pairs with absolute difference of 2 or 0 and the other steps required.
 def findLastElement ( arr , N ) :
	arr . sort ( ) ;
	i = 0 ;
	for i in range ( 1 , N ) :
		if ( arr [ i ] - arr [ i - 1 ] != 0 \ and arr [ i ] - arr [ i - 1 ] != 2 ) :
			print ( " - 1" ) ;
			return ;
	print ( arr [ N - 1 ] ) ;
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 4 , 6 , 8 , 0 , 8 ] ;
	N = len ( arr ) ;
	findLastElement ( arr , N ) ;