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Understanding The Coin Change Problem With Dynamic Programming | We have input values of N and an array Coins that holds all of the coins . We use data type of because long we want to be able to test large values without integer overflow.
Create the ways array to 1 plus the amount to stop overflow.
Set the first way to 1 because its 0 and there is 1 way to make 0 with 0 coins.
Go through all of the coins.
Make a comparison to each index value of ways with the coin value ..
Update the ways array.
return the value at the Nth position of the ways array ..
Driver code"
Solution in Python:
 Give me a code to understanding The Coin Change Problem With Dynamic Programming and the other steps required?
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#Here is code to understanding The Coin Change Problem With Dynamic Programming and the other steps required.
 def getNumberOfWays ( N , Coins ) :
	ways = [ 0 ] * ( N + 1 ) ;
	ways [ 0 ] = 1 ;
	for i in range ( len ( Coins ) ) :
		for j in range ( len ( ways ) ) :
			if ( Coins [ i ] <= j ) :
				ways [ j ] += ways [ ( int ) ( j - Coins [ i ] ) ] ;
	return ways [ N ] ;
def printArray ( coins ) :
	for i in coins :
		print ( i ) ;
if __name__ == ' _ _ main _ _ ' :
	Coins = [ 1 , 5 , 10 ] ;
	print ( " The ▁ Coins ▁ Array : " ) ;
	printArray ( Coins ) ;
	print ( " Solution : " , end = " " ) ;
	print ( getNumberOfWays ( 12 , Coins ) ) ;