human
I found an interesting problem on https://www.codechef.com/problems/SQRSUBMA:
You are given an integer sequence $A_1, A_2, \ldots, A_N$ and an integer $X$. Consider a $N \times N$ matrix $B$, where $B_{i,j} = A_i + A_j$ for each valid $i$ and $j$.
You need to find the number of square submatrices of $B$ such that the sum of their elements is $X$. Formally, find the number of quartets $(x_1, y_1, x_2, y_2)$ such that $1 \le x_1 \le x_2 \le N$, $1 \le y_1 \le y_2 \le N$, $x_2-x_1 = y_2-y_1$ and $\sum_{i=x_1}^{x_2}\sum_{j=y_1}^{y_2} B_{i,j} = X$.

-----Input-----
- The first line of the input contains a single integer $T$ denoting the number of test cases. The description of $T$ test cases follows.
- The first line of each test case contains two space-separated integers $N$ and $X$.
- The second line contains $N$ space-separated integers $A_1, A_2, \ldots, A_N$.

-----Output-----
For each test case, print a single line containing one integer ― the number of square submatrices with sum $X$.

-----Constraints-----
- $1 \le T \le 100$
- $1 \le X \le 10^6$
- $1 \le N \le 10^5$
- $1 \le A_i \le 10^6$ for each valid $i$
- the sum of $N$ over all test cases does not exceed $10^6$

-----Subtasks-----
Subtask #1 (50 points): the sum of $N$ over all test cases does not exceed $1,000$
Subtask #2 (50 points): original constraints

-----Example Input-----
2
5 36
1 2 3 1 12
4 54
3 3 3 3

-----Example Output-----
6
4

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is Python program to find the number of square submatrices of $B$ such that the sum of their elements is $X$.

from datetime import datetime

class dicta(dict):
 def __init__(self, *args, **kwargs):
  super(dicta, self).__init__(*args, **kwargs)
  self.__dict__ = self

# -----------------------------------------------------------------------------
START_TIME = datetime.now()

def debug(**kwargs):

 return
 diff = str(datetime.now() - START_TIME)
 for key, value in list(kwargs.items()):
  if isinstance(value, list):
   print(diff, key + ':')
   for itemKey, item in enumerate(value):
    print('\t\t\t', str(itemKey) + ': ' + str(item))
  elif isinstance(value, dict):
   print(diff, key + ':')
   for itemKey, item in list(value.items()):
    print('\t\t\t', itemKey + ': ' + str(item))
  else:
   print(diff, key + ': ' + str(value))

# -----------------------------------------------------------------------------
def printResult(result):
 if isinstance(result, list):
  print(*result)
 else:
  print(result)

# -----------------------------------------------------------------------------
def main():
 debug(status='started')
 noOfTests = int(input())

 for i in range(noOfTests):
  result = runATest(i)
  if isinstance(result, tuple):
   for line in result:
    printResult(line)
  else:
   printResult(result)
  if noOfTests > 1:
   debug(status='-------------------- finished Test#' + str(i+1) + '                 --------------------')
 debug(status='finished')

def runATest(_testIndex):

 [count, refTotal] = [int(x) for x in input().split()]

 aList = [int(x) for x in input().split()]
 factors = findFactors(refTotal, count)
 # debug(refTotal=refTotal, count=count, factors=factors)

 total = 0
 for factor in factors:
  total += countSquaresOfSize(aList, refTotal, count, factor)
 return total

def findFactors(refTotal, maxFactor):

 outList = [1]

 for i in range(2, int(refTotal/2)+1):
  if i > maxFactor:
   break
  if refTotal % i == 0:
   outList.append(i)

 if refTotal <= maxFactor:
  outList.append(refTotal)

 return outList

def countSquaresOfSize(aList, refTotal, count, size):

 reqSum = int(refTotal / size)
 sumList = [0]...