human
Count Arithmetic Progressions having sum S and common difference equal to D | Function to count the number of APs with sum S and common difference D.
Multiply S by 2.
Stores the count of APs.
Iterate over the factors of 2 * S.
Check if i is the factor or not.
Conditions to check if AP can be formed using factor F.
Return the total count of APs.
Driver Code"
Solution in Python:

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Can you provide a code to count Arithmetic Progressions having sum S and common difference equal to D and the other steps required?
assistant
#Here is code to count Arithmetic Progressions having sum S and common difference equal to D and the other steps required.
 def countAPs ( S , D ) :
	S = S * 2
	answer = 0
	for i in range ( 1 , S ) :
		if i * i > S :
			break
		if ( S % i == 0 ) :
			if ( ( ( S // i ) - D * i + D ) % 2 == 0 ) :
				answer += 1
			if ( ( D * i - ( S // i ) + D ) % 2 == 0 ) :
				answer += 1
	return answer
if __name__ == ' _ _ main _ _ ' :
	S , D = 12 , 1
	print ( countAPs ( S , D ) ) ;