human
Arrange a binary string to get maximum value within a range of indices | Python implementation of the approach.
Storing the count of 1 's in the string.
Query of l and r.
Applying range update technique ..
Taking prefix sum to get the range update values.
Final array which will store the arranged string.
if after maximizing the ranges any 1 is left then we maximize the string lexicographically ..
Driver Code"
How can the above be solved in Python?

Can you provide a code to arrange a binary string to get maximum value within a range of indices and the other steps required?
assistant
#Here is code to arrange a binary string to get maximum value within a range of indices and the other steps required.
 def arrange ( s ) :
	cc = 0
	for i in range ( len ( s ) ) :
		if ( s [ i ] == "1" ) :
			cc += 1
	a = [ 0 ] * ( len ( s ) + 1 )
	qq = [ ( 2 , 3 ) , ( 5 , 5 ) ]
	n = len ( qq )
	for i in range ( n ) :
		l , r = qq [ i ] [ 0 ] , qq [ i ] [ 1 ]
		l -= 1
		r -= 1
		a [ l ] += 1
		a [ r + 1 ] -= 1
	for i in range ( 1 , len ( a ) ) :
		a [ i ] = a [ i ] + a [ i - 1 ]
	zz = [ 0 ] * len ( s )
	for i in range ( len ( a ) - 1 ) :
		if ( a [ i ] > 0 ) :
			if ( cc > 0 ) :
				zz [ i ] = 1
				cc -= 1
			else :
				break
		if ( cc == 0 ) :
			break
	if ( cc > 0 ) :
		for i in range ( len ( s ) ) :
			if ( zz [ i ] == 0 ) :
				zz [ i ] = 1
				cc -= 1
			if ( cc == 0 ) :
				break
	print ( * zz , sep = " " )
str = "11100"
arrange ( str )