human
Sort permutation of N natural numbers using triple cyclic right swaps | Function to sort the permutation with the given operations.
Visited array to check the array element is at correct position or not.
Loop to iterate over the elements of the given array.
Condition to check if the elements is at its correct position.
Condition to check if the element is included in any previous cyclic rotations.
Loop to find the cyclic rotations in required.
Condition to check if the cyclic rotation is a valid rotation.
Loop to find the index of the cyclic rotation for the current index.
Condition to if the cyclic rotation is a valid rotation.
Loop to find athe valid operations required to sort the permutation.
Total operation required.
Driver Code.
Function Call"
How can the above be solved in Python?

Can you provide a code to sort permutation of N natural numbers using triple cyclic right swaps and the other steps required?
assistant
#Here is code to sort permutation of N natural numbers using triple cyclic right swaps and the other steps required.
 def sortPermutation ( arr , n ) :
	ans = [ ]
	p = [ ]
	visited = [ 0 ] * 200005
	for i in range ( 1 , n + 1 ) :
		if ( arr [ i ] == i ) :
			visited [ i ] = 1
			continue
		else :
			if ( visited [ i ] == False ) :
				x = i
				v = [ ]
				while ( visited [ x ] == False ) :
					visited [ x ] = 1
					v . append ( x )
					x = arr [ x ]
				if ( ( len ( v ) - 3 ) % 2 == 0 ) :
					for i in range ( 1 , len ( v ) , 2 ) :
						ans . append ( [ v [ 0 ] , v [ i ] , v [ i + 1 ] ] )
					continue
				p . append ( v [ 0 ] )
				p . append ( v [ len ( v ) - 1 ] )
				for i in range ( 1 , len ( v ) - 1 , 2 ) :
					ans . append ( [ v [ 0 ] , v [ i ] , v [ i + 1 ] ] )
	if ( len ( p ) % 4 ) :
		print ( - 1 )
		return
	for i in range ( 0 , len ( p ) , 4 ) :
		ans . append ( [ p [ i ] , p [ i + 1 ] , p [ i + 2 ] ] )
		ans . append ( p [ i [ + 2 ] , p [ i ] , p [ i + 3 ] ] )
	print ( len ( ans ) )
	for i in ans :
		print ( i [ 0 ] , i [ 1 ] , i [ 2 ] )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 0 , 3 , 2 , 4 , 1 ]
	n = 4
	sortPermutation ( arr , n )