human
Write me a code to count of N and the other steps required given the following:
Count of N | Function to return the count of n - digit numbers that satisfy the given conditions.
Base case.
If 0 wasn 't chosen previously.
If 0 wasn 't chosen previously.
Driver code"
Solution in Python:
assistant
#Here is code to count of N and the other steps required.
 def count_numbers ( k , n , flag ) :
	if ( n == 1 ) :
		if ( flag ) :
			return ( k - 1 )
		else :
			return 1
	if ( flag ) :
		return ( k - 1 ) * ( count_numbers ( k , n - 1 , 0 ) + count_numbers ( k , n - 1 , 1 ) )
	else :
		return count_numbers ( k , n - 1 , 1 )
n = 3
k = 10
print ( count_numbers ( k , n , True ) )