human
Compute the parity of a number using XOR and table look | Generating the look - up table while pre - processing.
LOOK_UP is the macro expansion to generate the table.
Function to find the parity.
Number is considered to be of 32 bits.
Dividing the number o 8 - bit chunks while performing X - OR.
Masking the number with 0xff ( 11111111 ) to produce valid 8 - bit result.
Driver code.
Result is 1 for odd parity , 0 for even parity.
Printing the desired result"
How can the above be solved in Python?

Give me a code to compute the parity of a number using XOR and table look and the other steps required?
assistant
#Here is code to compute the parity of a number using XOR and table look and the other steps required.
 def P2 ( n , table ) :
	table . extend ( [ n , n ^ 1 , n ^ 1 , n ] )
def P4 ( n , table ) :
	return ( P2 ( n , table ) , P2 ( n ^ 1 , table ) , P2 ( n ^ 1 , table ) , P2 ( n , table ) )
def P6 ( n , table ) :
	return ( P4 ( n , table ) , P4 ( n ^ 1 , table ) , P4 ( n ^ 1 , table ) , P4 ( n , table ) )
def LOOK_UP ( table ) :
	return ( P6 ( 0 , table ) , P6 ( 1 , table ) , P6 ( 1 , table ) , P6 ( 0 , table ) )
table = [ 0 ] * 256
LOOK_UP ( table )
def Parity ( num ) :
	max = 16
	while ( max >= 8 ) :
		num = num ^ ( num >> max )
		max = max // 2
	return table [ num & 0xff ]
if __name__ == " _ _ main _ _ " :
	num = 1742346774
	result = Parity ( num )
	print ( " Odd ▁ Parity " ) if result else print ( " Even ▁ Parity " )