human
Can you provide a the minimum number of operations he needs given the following:
A matrix of size n × m is called nice, if all rows and columns of the matrix are palindromes. A sequence of integers (a_1, a_2, ... , a_k) is a palindrome, if for any integer i (1 ≤ i ≤ k) the equality a_i = a_{k - i + 1} holds.

Sasha owns a matrix a of size n × m. In one operation he can increase or decrease any number in the matrix by one. Sasha wants to make the matrix nice. He is interested what is the minimum number of operations he needs.

Help him!

Input

The first line contains a single integer t — the number of test cases (1 ≤ t ≤ 10). The t tests follow.

The first line of each test contains two integers n and m (1 ≤ n, m ≤ 100) — the size of the matrix.

Each of the next n lines contains m integers a_{i, j} (0 ≤ a_{i, j} ≤ 10^9) — the elements of the matrix.

Output

For each test output the smallest number of operations required to make the matrix nice.

Example

Input

2
4 2
4 2
2 4
4 2
2 4
3 4
1 2 3 4
5 6 7 8
9 10 11 18

Output

8
42

Note

In the first test case we can, for example, obtain the following nice matrix in 8 operations:
    
    
      
    2 2  
    4 4  
    4 4  
    2 2  
    

In the second test case we can, for example, obtain the following nice matrix in 42 operations:
    
    
      
    5 6 6 5  
    6 6 6 6  
    5 6 6 5  
    
#   A
assistant
#Here is the minimum number of operations he needs.
uthor: yumtam
#   Created at: 2020-10-05 14:50

from __future__ import division, print_function
_interactive = False

from collections import defaultdict
from itertools import product

def main():
    for _ in range(int(input())):
        n, m = input_as_list()
        A = input_as_matrix(n, m)

        d = defaultdict(list)
        for i, j in product(range(n), range(m)):
            x = A[i][j]
            i = min(i, n-i-1)
            j = min(j, m-j-1)
            d[(i, j)].append(x)

        debug_print(d)
        ans = 0
        for lst in d.itervalues():
            pivot = sorted(lst)[len(lst)//2]
            ans += sum(abs(x-pivot) for x in lst)

        print(ans)

# Constants
INF = float('inf')
MOD = 10**9+7

# Python3 equivalent names
import os, sys, itertools
if sys.version_info[0] < 3:
    input = raw_input
    range = xrange

    filter = itertools.ifilter
    map = itertools.imap
    zip = itertools.izip

# print-flush in interactive problems
if _interactive:
    flush = sys.stdout.flush
    def printf(*args, **kwargs):
        print(*args, **kwargs)
        flush()

# Debug print, only works on local machine
LOCAL = "LOCAL_" in os.environ
debug_print = (print) if LOCAL else (lambda *x, **y: None)

# Fast IO
if (not LOCAL) and (not _interactive):
    from io import BytesIO
    from atexit import register
    sys.stdin = BytesIO(os.read(0, os.fstat(0).st_size))
    sys.stdout = BytesIO()
    register(lambda: os.write(1, sys.stdout.getvalue()))
    input = lambda: sys.stdin.readline().rstrip('\r\n')

# Some utility functions(Input, N-dimensional lists, ...)
def input_as_list():
    return [int(x) for x in input().split()]

def input_with_offset(o):
    return [int(x)+o for x in input().split()]

def input_as_matrix(n, m):
    return [input_as_list() for _ in range(n)]

def array_of(f, *dim):
    return [array_of(f, *dim[1:]) for _ in range(dim[0])] if dim else f()

# Start of external code templates...
# End of external code templates.

main()