human
What is a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/possible-bipartition/:
Given a set of N people (numbered 1, 2, ..., N), we would like to split everyone into two groups of any size.
Each person may dislike some other people, and they should not go into the same group. 
Formally, if dislikes[i] = [a, b], it means it is not allowed to put the people numbered a and b into the same group.
Return true if and only if it is possible to split everyone into two groups in this way.
 





Example 1:
Input: N = 4, dislikes = [[1,2],[1,3],[2,4]]
Output: true
Explanation: group1 [1,4], group2 [2,3]

Example 2:
Input: N = 3, dislikes = [[1,2],[1,3],[2,3]]
Output: false

Example 3:
Input: N = 5, dislikes = [[1,2],[2,3],[3,4],[4,5],[1,5]]
Output: false



 
Constraints:

1 <= N <= 2000
0 <= dislikes.length <= 10000
dislikes[i].length == 2
1 <= dislikes[i][j] <= N
dislikes[i][0] < dislikes[i][1]
There does not exist i != j for which dislikes[i] == dislikes[j].

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

from collections import defaultdict
class Solution:
    def possibleBipartition(self, N: int, dislikes: List[List[int]]) -> bool:
        
        graph = defaultdict(list)
        
        for _from, to in dislikes:
            graph[_from].append(to)
            graph[to].append(_from)
            
        colors = {}
        
        for i in range(1,N+1):
            if i not in colors and i <= len(graph)-1:
                stack = [(i, True)]
                
                while stack:
                    keys, color = stack.pop()
                    colors[keys] = color
                    
                    for adj in graph[keys]:
                        if adj in colors:
                            if colors[adj] == colors[keys]:

                                return False
                        else:
                            stack.append((adj, not colors[keys]))
        return all([colors[i] != all(colors[j] for j in graph[i]) for i in colors if graph[i]!=[]])