human
Maximum number of segments that can contain the given points | Function to return the maximum number of segments.
Sort both the vectors.
Initially pointing to the first element of b [ ].
Try to find a match in b [ ].
The segment ends before b [ j ].
The point lies within the segment.
The segment starts after b [ j ].
Return the required count.
Driver code"
Solution in Python:
 ... Write me a code to maximum number of segments that can contain the given points and the other steps required?
assistant
#Here is code to maximum number of segments that can contain the given points and the other steps required.
 def countPoints ( n , m , a , b , x , y ) :
	a . sort ( )
	b . sort ( )
	j , count = 0 , 0
	for i in range ( 0 , n ) :
		while j < m :
			if a [ i ] + y < b [ j ] :
				break
			if ( b [ j ] >= a [ i ] - x and b [ j ] <= a [ i ] + y ) :
				count += 1
				j += 1
				break
			else :
				j += 1
	return count
if __name__ == " _ _ main _ _ " :
	x , y = 1 , 4
	a = [ 1 , 5 ]
	n = len ( a )
	b = [ 1 , 1 , 2 ]
	m = len ( b )
	print ( countPoints ( n , m , a , b , x , y ) )