human
Count of pairs having even and odd LCM from an array | Function to find count of distinct pairs having even LCM and odd LCM.
Store the total number of pairs.
Stores the count of odd numbers in the array.
Traverse the array arr [ ].
Update the count of pairs with odd LCM.
Print the count of required pairs.
Driver Code"
How can the above be solved in Python?
 Can you provide a code to count of pairs having even and odd LCM from an array and the other steps required?
assistant
#Here is code to count of pairs having even and odd LCM from an array and the other steps required.
 def LCMPairs ( arr , N ) :
	total_pairs = ( N * ( N - 1 ) ) / 2
	odd = 0
	for i in range ( N ) :
		if ( arr [ i ] & 1 ) :
			odd += 1
	odd = ( odd * ( odd - 1 ) ) // 2
	print ( " Even ▁ = " , int ( total_pairs - odd ) , " , " , " ▁ Odd ▁ = " , odd )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 3 , 6 , 5 , 4 ]
	N = len ( arr )
	LCMPairs ( arr , N )