human
Maximum length of consecutive 1 s or 0 s after flipping at most K characters | Function to find the maximum length continuos segment of character c after flipping at most K characters.
Stores the maximum length.
Stores the count of char 'c.
Start of window.
Remove the extra ' c ' from left.
Increment the value of the left.
Update the resultant maximum length of character ch.
Function to find the maximum length of consecutive 0 s or 1 s by flipping at most K characters of the string.
Print the maximum of the maximum length of 0 s or 1 s.
Driver Code"
Solution in Python:
 ... What is a code to maximum length of consecutive 1 s or 0 s after flipping at most K characters and the other steps required?
assistant
#Here is code to maximum length of consecutive 1 s or 0 s after flipping at most K characters and the other steps required.
 def maxLength ( str , n , c , k ) :
	ans = - 1
'
	cnt = 0
	left = 0
	for right in range ( 0 , n ) :
		if ( str [ right ] == c ) :
			cnt += 1
		while ( cnt > k ) :
			if ( str [ left ] == c ) :
				cnt -= 1
			left += 1
		ans = max ( ans , right - left + 1 )
	return ans
def maxConsecutiveSegment ( S , K ) :
	N = len ( S )
	return max ( maxLength ( S , N , '0' , K ) , maxLength ( S , N , '1' , K ) )
if __name__ == " _ _ main _ _ " :
	S = "1001"
	K = 1
	print ( maxConsecutiveSegment ( S , K ) )