human
Solve the following python programming problem given the following code:
def asRGBA(self) : 
    "Return image as RGBA pixels.  Greyscales are expanded into
        RGB triplets.
an alpha channel is synthesized if necessary.
        The return values are as for the :meth:`read` method
        except that the *metadata* reflect the returned pixels, not the
        source image.  In particular, for this method
        ``metadata['greyscale']`` will be ``False``, and
        ``metadata['alpha']`` will be ``True``.
        " 
    (width, height, pixels, meta) = self.asDirect () 
    if (meta ['alpha'] and (not meta ['greyscale'])) : 
        return (width, height, pixels, meta) 
typecode = 'BH' [(meta ['bitdepth'] > 8)] 
    maxval = ((2 ** meta ['bitdepth']) - 1) 
    maxbuffer = ((struct.pack (('=' + typecode), maxval) * 4) * width) 
    def newarray() : 
        return array (typecode, maxbuffer) 
if (meta ['alpha'] and meta ['greyscale']) : 
        def convert() : 
            for row in pixels : 
                a = newarray () 
                pngfilters.convert_la_to_rgba (row, a) 
                (yield a) 
else : 
        if width ['greyscale'] : 
            def convert() : 
                for row in pixels : 
                    a = newarray () 
                    pngfilters.convert_l_to_rgba (row, a) 
                    (yield a) 
else : 
            assert ((not meta ['alpha']) and (not meta ['greyscale'])) 
            def convert() : 
                for row in pixels : 
                    a = newarray () 
                    pngfilters.convert_rgb_to_rgba (row, a) 
                    (yield a) 
meta ['alpha'] = True 
    meta ['greyscale'] = False 
    return (width, height, convert (), meta) 

    
    

    Fix the buggy line: if width ['greyscale'] :
assistant
#Here is Python code to fix the buggy line: if width ['greyscale'] :
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if meta ['greyscale'] :