human
Check if a Regular Bracket Sequence can be formed with concatenation of given strings | Function to check possible RBS from the given strings.
Stores the values { sum , min_prefix }.
Iterate over the range.
Stores the total sum.
Stores the minimum prefix.
Check for minimum prefix.
Store these values in vector.
Store values according to the mentioned approach.
Sort the positive vector.
Stores the extra count of open brackets.
No valid bracket sequence can be formed.
Sort the negative vector.
Stores the count of the negative elements.
No valid bracket sequence can be formed.
Check if open is equal to negative.
Driver Code"
How can the above be solved in Python?

Can you provide a code to check if a Regular Bracket Sequence can be formed with concatenation of given strings and the other steps required?
assistant
#Here is code to check if a Regular Bracket Sequence can be formed with concatenation of given strings and the other steps required.
 def checkRBS ( S ) :
	N = len ( S )
	v = [ 0 ] * ( N )
	for i in range ( N ) :
		s = S [ i ]
		sum = 0
		pre = 0
		for c in s :
			if ( c == ' ( ' ) :
				sum += 1
			else :
				sum -= 1
			pre = min ( sum , pre )
		v [ i ] = [ sum , pre ]
	pos = [ ]
	neg = [ ]
	for i in range ( N ) :
		if ( v [ i ] [ 0 ] >= 0 ) :
			pos . append ( [ - v [ i ] [ 1 ] , v [ i ] [ 0 ] ] )
		else :
			neg . append ( [ v [ i ] [ 0 ] - v [ i ] [ 1 ] , - v [ i ] [ 0 ] ] )
	pos . sort ( )
	open = 0
	for p in pos :
		if ( open - p [ 0 ] >= 0 ) :
			open += p [ 1 ]
		else :
			print ( " No " )
			return 0
	neg . sort ( )
	negative = 0
	for p in neg :
		if ( negative - p [ 0 ] >= 0 ) :
			negative += p [ 1 ]
		else :
			print ( " No " )
			return 0
	if ( open != negative ) :
		print ( " No " )
		return 0
	print ( " Yes " )
if __name__ == " _ _ main _ _ " : arr = [ " ) " , " ( ) ( " ]
	checkRBS ( arr )