human
Can you provide a code to breaking an Integer to get Maximum Product and the other steps required given the following:
Breaking an Integer to get Maximum Product | method return x ^ a in log ( a ) time.
Method returns maximum product obtained by breaking N.
base case 2 = 1 + 1.
base case 3 = 2 + 1.
breaking based on mod with 3.
If divides evenly , then break into all 3.
If division gives mod as 1 , then break as 4 + power of 3 for remaining part.
If division gives mod as 2 , then break as 2 + power of 3 for remaining part.
Driver code to test above methods"
Solution in Python:
assistant
#Here is code to breaking an Integer to get Maximum Product and the other steps required.
 def power ( x , a ) :
	res = 1
	while ( a ) :
		if ( a & 1 ) :
			res = res * x
		x = x * x
		a >>= 1
	return res
def breakInteger ( N ) :
	if ( N == 2 ) :
		return 1
	if ( N == 3 ) :
		return 2
	maxProduct = 0
	if ( N % 3 == 0 ) :
		maxProduct = power ( 3 , int ( N / 3 ) )
		return maxProduct
	elif ( N % 3 == 1 ) :
		maxProduct = 2 * 2 * power ( 3 , int ( N / 3 ) - 1 )
		return maxProduct
	elif ( N % 3 == 2 ) :
		maxProduct = 2 * power ( 3 , int ( N / 3 ) )
		return maxProduct
maxProduct = breakInteger ( 10 )
print ( maxProduct )