human
Can you provide a code to minimum number of swaps required to make a number divisible by 60 and the other steps required given the following:
Minimum number of swaps required to make a number divisible by 60 | Function that prminimum number of swap operations required.
Condition if more than one zero exist.
Condition if zero_exist.
Computing total sum of all digits.
Condition if zero does not exist or the sum is not divisible by 3.
Condition to find a digit that is multiple of 2 other than one zero.
Condition if multiple of 2 do not exist.
Condition for zero swaps means the number is already is divisible by 60.
Condition for only one swap.
Otherwise 2 swaps required.
Driver Code"
Solution in Python:
assistant
#Here is code to minimum number of swaps required to make a number divisible by 60 and the other steps required.
 def MinimumSwapOperations ( s ) :
	zero_exist = False
	multiple_of_2 = False
	sum = 0
	index_of_zero = 0
	more_zero = False
	for i in range ( len ( s ) ) :
		val = ord ( s [ i ] ) - ord ( '0' )
		if ( zero_exist == True ) :
			more_zero = True
		if ( val == 0 ) :
			zero_exist = True
			index_of_zero = i
		sum += val
	if ( zero_exist == False or sum % 3 != 0 ) :
		print ( " - 1" )
		return
	for i in range ( len ( s ) ) :
		val = ord ( s [ i ] ) - ord ( '0' )
		if ( val % 2 == 0 and i != index_of_zero ) :
			multiple_of_2 = True
	if ( multiple_of_2 == False ) :
		print ( " - 1" )
		return
	last_val = ord ( s [ len ( s ) - 1 ] ) - ord ( '0' )
	second_last_val = ord ( s [ len ( s ) - 2 ] ) - ord ( '0' )
	if ( last_val == 0 and second_last_val % 2 == 0 ) :
		print ( 0 )
	elif ( ( last_val == 0 and second_last_val % 2 != 0 ) or ( last_val % 2 == 0 and second_last_val == 0 ) ) :
		print ( 1 )
	elif ( more_zero == True and ( last_val == 0 and second_last_val % 2 != 0 ) ) :
		print ( 1 )
	else :
		print ( 2 )
if __name__ == ' _ _ main _ _ ' :
	N = "20"
	MinimumSwapOperations ( N )