human
Solve in Python:
Implement pow(x, n), which calculates x raised to the power n (xn).

Example 1:

Input: 2.00000, 10
Output: 1024.00000

Example 2:

Input: 2.10000, 3
Output: 9.26100

Example 3:

Input: 2.00000, -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25

Note:

       -100.0 < x < 100.0
       n is a 32-bit signed integer, within the range [−231, 231 − 1]
 ... What is a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
     def myPow(self, x, n):
         """
         :type x: float
         :type n: int
         :rtype: float
         """
         if n<0:return 1/self.myPow(x,-n)
         elif n==0:return 1
         elif n>1000:return self.myPow(self.myPow(x,1000),n//1000)*self.myPow(x,n%1000)
         else: return x*self.myPow(x,n-1)