human
Kth diagonal from the top left of a given matrix | Function returns required diagonal.
Initialize values to prupper diagonals.
Initialize values to print lower diagonals.
Traverse the diagonals.
Print its contents.
Driver code"
How can the above be solved in Python?

Give me a code to kth diagonal from the top left of a given matrix and the other steps required?
assistant
#Here is code to kth diagonal from the top left of a given matrix and the other steps required.
 def printDiagonal ( K , N , M ) :
	startrow , startcol = 0 , 0
	if K - 1 < N :
		startrow = K - 1
		startcol = 0
	else :
		startrow = N - 1
		startcol = K - N
	while startrow >= 0 and startcol < N :
		print ( M [ startrow ] [ startcol ] , end = " ▁ " )
		startrow -= 1
		startcol += 1
if __name__ == ' _ _ main _ _ ' :
	N , K = 3 , 4
	M = [ [ 4 , 7 , 8 ] , [ 9 , 2 , 3 ] , [ 0 , 4 , 1 ] ]
	printDiagonal ( K , N , M )