human
Can you provide a the Python program you requested given the following:
I found an interesting problem on https://leetcode.com/problems/flip-columns-for-maximum-number-of-equal-rows/:
Given a matrix consisting of 0s and 1s, we may choose any number of columns in the matrix and flip every cell in that column.  Flipping a cell changes the value of that cell from 0 to 1 or from 1 to 0.
Return the maximum number of rows that have all values equal after some number of flips.
 


Example 1:
Input: [[0,1],[1,1]]
Output: 1
Explanation: After flipping no values, 1 row has all values equal.

Example 2:
Input: [[0,1],[1,0]]
Output: 2
Explanation: After flipping values in the first column, both rows have equal values.

Example 3:
Input: [[0,0,0],[0,0,1],[1,1,0]]
Output: 2
Explanation: After flipping values in the first two columns, the last two rows have equal values.

 
Note:

1 <= matrix.length <= 300
1 <= matrix[i].length <= 300
All matrix[i].length's are equal
matrix[i][j] is 0 or 1

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python program you requested.

class Solution(object):
    def maxEqualRowsAfterFlips(self, matrix):
        patterns = collections.Counter()
        for row in matrix:
            patterns[tuple(row)]+=1
            flip = [1-c for c in row]
            patterns[tuple(flip)]+=1
        return max(patterns.values())