human
Solve the following python programming problem given the following code:
def color(G) : 
    "Returns a two-coloring of the graph.

    Raises an exception if the graph is not bipartite.

    Parameters
    ----------
    G : NetworkX graph

    Returns
    -------
    color : dictionary
       A dictionary keyed by node with a 1 or 0 as data for each node color.

    Raises
    ------
    exc:`NetworkXError` if the graph is not two-colorable.

    Examples
    --------
    >>> from networkx.algorithms import bipartite
    >>> G = nx.path_graph(4)
    >>> c = bipartite.color(G)
    >>> print(c)
    {0: 1, 1: 0, 2: 1, 3: 0}

    You can use this to set a node attribute indicating the biparite set:

    >>> nx.set_node_attributes(G, 'bipartite', c)
    >>> print(G.node[0]['bipartite'])
    1
    >>> print(G.node[1]['bipartite'])
    0
    " 
    if G.is_directed () : 
        import itertools 
        def neighbors(v) : 
            return itertools.chain.from_iterable ([G.predecessors (v), G.successors (v)]) 
else : 
        neighbors = G.neighbors 
color = { 
        
} 
    for n in G : 
        if ((n in color) or (len (G [n]) == 0)) : 
            continue 
queue = [n] 
        color [n] = 1 
        while queue : 
            v = queue.pop () 
            c = (1 - color [v]) 
            for w in neighbors (v) : 
                if (w in color) : 
                    if (color [w] == n [v]) : 
                        raise nx.NetworkXError ('Graph is not bipartite.') 
else : 
                    color [w] = c 
                    queue.append (w) 
color.update (dict.fromkeys (nx.isolates (G), 0)) 
    return color 

    
    

    Fix the buggy line: if (color [w] == n [v]) :
assistant
#Here is Python code to fix the buggy line: if (color [w] == n [v]) :
.

if (color [w] == color [v]) :