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Can you provide a code to first N natural can be divided into two sets with given difference and co and the other steps required given the following:
First N natural can be divided into two sets with given difference and co | Python3 code to determine whether numbers 1 to N can be divided into two sets such that absolute difference between sum of these two sets is M and these two sum are co - prime.
function that returns boolean value on the basis of whether it is possible to divide 1 to N numbers into two sets that satisfy given conditions ..
initializing total sum of 1 to n numbers.
since ( 1 ) total_sum = sum_s1 + sum_s2 and ( 2 ) m = sum_s1 - sum_s2 assuming sum_s1 > sum_s2 . solving these 2 equations to get sum_s1 and sum_s2.
total_sum = sum_s1 + sum_s2 and therefore.
if total sum is less than the absolute difference then there is no way we can split n numbers into two sets so return false.
check if these two sums are integers and they add up to total sum and also if their absolute difference is m ..
Now if two sum are co - prime then return true , else return false ..
if two sums don 't add up to total  sum or if their absolute difference  is not m, then there is no way to  split n numbers, hence return false.
Driver code.
function call to determine answer"
Solution in Python:
assistant
#Here is code to first N natural can be divided into two sets with given difference and co and the other steps required.
 def __gcd ( a , b ) :
	return a if ( b == 0 ) else __gcd ( b , a % b ) ;
def isSplittable ( n , m ) :
	total_sum = ( int ) ( ( n * ( n + 1 ) ) / 2 ) ;
	sum_s1 = int ( ( total_sum + m ) / 2 ) ;
	sum_s2 = total_sum - sum_s1 ;
	if ( total_sum < m ) :
		return False ;
	if ( sum_s1 + sum_s2 == total_sum and sum_s1 - sum_s2 == m ) :
		return ( __gcd ( sum_s1 , sum_s2 ) == 1 ) ;
	return False ;
n = 5 ;
m = 7 ;
if ( isSplittable ( n , m ) ) :
	print ( " Yes " ) ;
else :
	print ( " No " ) ;