human
Solve the following python programming problem given the following code:
def debounce(self, wait, immediate = None) : 
    '
        Returns a function, that, as long as it continues to be invoked,
        will not be triggered. The function will be called after it stops
        being called for N milliseconds. If `immediate` is passed, trigger
        the function on the leading edge, instead of the trailing.
        ' 
    wait = (float (debounced) / float (1000)) 
    def debounced(* args, **kwargs) : 
        def call_it() : 
            self.obj (* args, ** kwargs) 
try : 
            debounced.t.cancel () 
except AttributeError : 
            pass 
debounced.t = Timer (wait, call_it) 
        debounced.t.start () 
return self._wrap (debounced) 

    
    

    Fix the buggy line: wait = (float (debounced) / float (1000))
assistant
#Here is Python code to fix the buggy line: wait = (float (debounced) / float (1000))
.

wait = (float (wait) / float (1000))