human
Find the original Array using XOR values of all adjacent elements | XOR of all elements from 1 to N.
Function to find the Array from the XOR Array.
Take a vector to store the permutation.
XOR of N natural numbers.
Loop to find the XOR of adjacent elements of the XOR Array.
Loop to find the other elements of the permutation.
Finding the next and next elements.
Driver Code.
Required Permutation"
Solution in Python:

Give me a code to find the original Array using XOR values of all adjacent elements and the other steps required?
assistant
#Here is code to find the original Array using XOR values of all adjacent elements and the other steps required.
 def xor_all_elements ( n ) :
	if n & 3 == 0 :
		return n
	elif n & 3 == 1 :
		return 1
	elif n & 3 == 2 :
		return n + 1
	else :
		return 0
def findArray ( xorr , n ) :
	arr = [ ]
	xor_all = xor_all_elements ( n )
	xor_adjacent = 0
	for i in range ( 0 , n - 1 , 2 ) :
		xor_adjacent = xor_adjacent ^ xorr [ i ]
	last_element = xor_all ^ xor_adjacent
	arr . append ( last_element )
	for i in range ( n - 2 , - 1 , - 1 ) :
		last_element = xorr [ i ] ^ last_element
		arr . append ( last_element )
	return arr
xorr = [ 7 , 5 , 3 , 7 ]
n = 5
arr = findArray ( xorr , n )
for i in range ( n - 1 , - 1 , - 1 ) :
	print ( arr [ i ] , end = " ▁ " )