human
Give me a code to count array elements with rank not exceeding K and the other steps required given the following:
Count array elements with rank not exceeding K | Function to find count of array elements with rank less than or equal to k.
Initialize rank and position.
Sort the given array.
Traverse array from right to left.
Update rank with position , if adjacent elements are unequal.
Return position - 1 , if rank greater than k.
Increase position.
Driver Code.
Given array.
Given K.
Function Call"
Solution in Python:
assistant
#Here is code to count array elements with rank not exceeding K and the other steps required.
 def rankLessThanK ( arr , k , n ) :
	rank = 1 ;
	position = 1 ;
	arr = sorted ( arr )
	for i in range ( n - 1 , - 1 , - 1 ) :
		if ( i == n - 1 or arr [ i ] != arr [ i + 1 ] ) :
			rank = position ;
			if ( rank > k ) :
				return position - 1 ;
		position += 1 ;
	return n ;
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 2 , 3 , 4 , 5 ] ;
	N = len ( arr ) ;
	K = 4 ;
	print ( rankLessThanK ( arr , K , N ) ) ;