human
Count ways to reach end from start stone with at most K jumps at each step | Function which returns total no . of ways to reach nth step from sth steps.
Initialize dp array.
Initialize ( s - 1 ) th index to 1.
Iterate a loop from s to n.
starting range for counting ranges.
Calculate Maximum moves to Reach ith step.
For nth step return dp [ n - 1 ].
Driver Code.
no of steps.
Atmost steps allowed.
starting range"
How can the above be solved in Python?
 ... Write me a code to count ways to reach end from start stone with at most K jumps at each step and the other steps required?
assistant
#Here is code to count ways to reach end from start stone with at most K jumps at each step and the other steps required.
 def TotalWays ( n , s , k ) :
	dp = [ 0 ] * n
	dp [ s - 1 ] = 1
	for i in range ( s , n ) :
		idx = max ( s - 1 , i - k )
		for j in range ( idx , i ) :
			dp [ i ] += dp [ j ]
	return dp [ n - 1 ]
if __name__ == " _ _ main _ _ " :
	n = 5
	k = 2
	s = 2
	print ( " Total ▁ Ways ▁ = ▁ " , TotalWays ( n , s , k ) )