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Count sequences of given length having non | Function to find the Binomial Coefficient C ( n , r ).
Stores the value C ( n , r ).
Update C ( n , r ) = C ( n , n - r ).
Find C ( n , r ) iteratively.
Return the final value.
Function to find number of sequence whose prefix sum at each index is always non - negative.
Find n.
Value of C ( 2 n , n ).
Catalan number.
Print the answer.
Driver Code.
Given M and X.
Function Call"
Solution in Python:
assistant
#Here is code to count sequences of given length having non and the other steps required.
 def binCoff ( n , r ) :
	val = 1
	if ( r > ( n - r ) ) :
		r = ( n - r )
	for i in range ( 0 , r ) :
		val *= ( n - i )
		val //= ( i + 1 )
	return val
def findWays ( M ) :
	n = M // 2
	a = binCoff ( 2 * n , n )
	b = a // ( n + 1 )
	print ( b )
if __name__ == ' _ _ main _ _ ' :
	M = 4
	X = 5
	findWays ( M )