human
PYTHON3 solution for "You have a string s and a chip, which you can place onto any character of this string. 

After placing the chip, you move it to the right several (maybe zero) times, i. e. you perform the following operation several times: if the current position of the chip is i, you move it to the position i + 1. Of course, moving the chip to the right is impossible if it is already in the last position.

After moving the chip to the right, you move it to the left several (maybe zero) times, i. e. you perform the following operation several times: if the current position of the chip is i, you move it to the position i - 1. Of course, moving the chip to the left is impossible if it is already in the first position.

When you place a chip or move it, you write down the character where the chip ends up after your action. For example, if s is abcdef, you place the chip onto the 3-rd character, move it to the right 2 times and then move it to the left 3 times, you write down the string cdedcb.

You are given two strings s and t. Your task is to determine whether it's possible to perform the described operations with s so that you write down the string t as a result.

Input

The first line contains one integer q (1 ≤ q ≤ 500) — the number of test cases.

Each test case consists of two lines. The first line contains the string s (1 ≤ |s| ≤ 500), the second line contains the string t (1 ≤ |t| ≤ 2 ⋅ |s| - 1). Both strings consist of lowercase English characters.

It is guaranteed that the sum of |s| over all test cases does not exceed 500.

Output

For each test case, print "YES" if you can obtain the string t by performing the process mentioned in the statement with the string s, or "NO" if you cannot.

You may print each letter in any case (YES, yes, Yes will all be recognized as positive answer, NO, no and nO will all be recognized as negative answer).

Example

Input

6
abcdef
cdedcb
aaa
aaaaa
aab
baaa
ab
b
abcdef
abcdef
ba
baa

Output

YES
YES
NO
YES
YES
NO

Note

Consider the examples.

The first test case is described in...":


 Give me a Python code to determine whether it's possible to perform the described operations with s so that you write down the string t as a result?
assistant
#Here is Python code to determine whether it's possible to perform the described operations with s so that you write down the string t as a result.
 import math
# region fastio
import os
import sys
from io import BytesIO, IOBase

BUFSIZE = 8192

class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)

class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")

sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")

# endregion
for _ in range(int(input())):
    s = input()
    n = len(s)
    arr = input()
    nn = len(arr)
    an = False
    if s == arr:
        print("Yes")
    else:
        for k in range(n):
            for j in range(k, n):
                c = s[k:j] + s[:j+1][::-1]
                if...