human
Count of triplets till N whose product is at most N | Function to find number of triplets ( A , B , C ) having A * B * C <= N.
Stores the count of triplets.
Iterate a loop fixing the value of A.
Iterate a loop fixing the value of A.
Find the total count of triplets and add it to cnt.
Return the total triplets formed.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count of triplets till N whose product is at most N and the other steps required.
 def countTriplets ( N ) :
	cnt = 0 ;
	for A in range ( 1 , N + 1 ) :
		for B in range ( 1 , N // A + 1 ) :
			cnt += N // ( A * B ) ;
	return cnt ;
if __name__ == " _ _ main _ _ " :
	N = 2 ;
	print ( countTriplets ( N ) ) ;