human
Minimize cost of increments or decrements such that same indexed elements become multiple of each other | Function to find the minimum cost to make A [ i ] multiple of B [ i ] or vice - versa for every array element.
Stores the minimum cost.
Traverse the array.
Case 1 : Update A [ i ].
Case 2 : Update B [ i ].
Add the minimum of the above two cases.
Return the resultant cost.
Driver Code"
Solution in Python:

Can you provide a code to minimize cost of increments or decrements such that same indexed elements become multiple of each other and the other steps required?
assistant
#Here is code to minimize cost of increments or decrements such that same indexed elements become multiple of each other and the other steps required.
 def MinimumCost ( A , B , N ) :
	totalCost = 0
	for i in range ( N ) :
		mod_A = B [ i ] % A [ i ]
		totalCost_A = min ( mod_A , A [ i ] - mod_A )
		mod_B = A [ i ] % B [ i ]
		totalCost_B = min ( mod_B , B [ i ] - mod_B )
		totalCost += min ( totalCost_A , totalCost_B )
	return totalCost
A = [ 3 , 6 , 3 ]
B = [ 4 , 8 , 13 ]
N = len ( A )
print ( MinimumCost ( A , B , N ) )