human
Minimize the number by changing at most K digits | Function to return the minimized number.
Total digits in the number.
If the string is empty or there are no operations to perform.
"0" is a valid number.
If the first digit is not already 1 then update it to 1 and decrement k.
While there are operations left and the number can still be updated.
If the current digit is not already 0 then update it to 0 and decrement k.
Return the minimised number.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to minimize the number by changing at most K digits and the other steps required.
 def minNum ( num , k ) :
	len_ = len ( num )
	if len_ == 0 or k == 0 :
		return num
	if len_ == 1 :
		return "0"
	if num [ 0 ] != '1' :
		num = '1' + num [ 1 : ]
		k -= 1
	i = 1
	while k > 0 and i < len_ :
		if num [ i ] != '0' :
			num = num [ : i ] + '0' + num [ i + 1 : ]
			k -= 1
		i += 1
	return num
num = "91945"
k = 3
print ( minNum ( num , k ) )