human
Find the missing digit in given product of large positive integers | Function to find the replaced digit in the product of a * b.
Keeps track of the sign of the current digit.
Stores the value of a % 11.
Find the value of a mod 11 for large value of a as per the derived formula.
Stores the value of b % 11.
Find the value of b mod 11 for large value of a as per the derived formula.
Stores the value of c % 11.
Keeps track of the sign of x.
If the current digit is the missing digit , then keep the track of its sign.
Find the value of x using the derived equation.
Check if x has a negative sign.
Return positive equivaluent of x mod 11.
Driver Code"
Solution in Python:

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Give me a code to find the missing digit in given product of large positive integers and the other steps required?
assistant
#Here is code to find the missing digit in given product of large positive integers and the other steps required.
 def findMissingDigit ( a , b , c ) :
	w = 1
	a_mod_11 = 0
	for i in range ( len ( a ) - 1 , - 1 , - 1 ) :
		a_mod_11 = ( a_mod_11 + w * ( ord ( a [ i ] ) - ord ( '0' ) ) ) % 11
		w = w * - 1
	b_mod_11 = 0
	w = 1
	for i in range ( len ( b ) - 1 , - 1 , - 1 ) :
		b_mod_11 = ( b_mod_11 + w * ( ord ( b [ i ] ) - ord ( '0' ) ) ) % 11
		w = w * - 1
	c_mod_11 = 0
	xSignIsPositive = True
	w = 1
	for i in range ( len ( c ) - 1 , - 1 , - 1 ) :
		if ( c [ i ] == ' x ' ) :
			xSignIsPositive = ( w == 1 )
		else :
			c_mod_11 = ( c_mod_11 + w * ( ord ( c [ i ] ) - ord ( '0' ) ) ) % 11
		w = w * - 1
	x = ( ( a_mod_11 * b_mod_11 ) - c_mod_11 ) % 11
	if ( not xSignIsPositive ) :
		x = - x
	return ( x % 11 + 11 ) % 11
A = "123456789"
B = "987654321"
C = "12193263111x635269"
print ( findMissingDigit ( A , B , C ) )