human
Can you provide a code to count of subarrays with X as the most frequent element , for each value of X from 1 to N and the other steps required given the following:
Count of subarrays with X as the most frequent element , for each value of X from 1 to N | Function to calculate the number of subarrays where X ( 1 <= X <= N ) is the most frequent element.
array to store the final answers.
Array to store current frequencies.
Variable to store the current most frequent element.
Update frequency array.
Update answer.
Pranswer.
Driver code.
Input.
Function call"
How can the above be solved in Python?
assistant
#Here is code to count of subarrays with X as the most frequent element , for each value of X from 1 to N and the other steps required.
 def mostFrequent ( arr , N ) :
	ans = [ 0 ] * N
	for i in range ( N ) :
		count = [ 0 ] * N
		best = 0
		for j in range ( i , N ) :
			count [ arr [ j ] - 1 ] += 1
			if ( count [ arr [ j ] - 1 ] > count [ best - 1 ] or ( count [ arr [ j ] - 1 ] == count [ best - 1 ] and arr [ j ] < best ) ) :
				best = arr [ j ]
			ans [ best - 1 ] += 1
	print ( * ans )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 1 , 2 , 3 ]
	N = len ( arr )
	mostFrequent ( arr , N )