human
Can you provide a code to count number of coordinates from an array satisfying the given conditions and the other steps required given the following:
Count number of coordinates from an array satisfying the given conditions | Function to count the number of coordinates from a given set that satisfies the given conditions.
Stores the count of central points.
Find all possible pairs.
Initialize variables c1 , c2 , c3 , c4 to define the status of conditions.
Stores value of each point.
Check the conditions for each point by generating all possible pairs.
If arr [ j ] [ 0 ] > x and arr [ j ] [ 1 ] == y.
If arr [ j ] [ 0 ] < x and arr [ j ] [ 1 ] = = y.
If arr [ j ] [ 1 ] > y and arr [ j ] [ 0 ] == x.
If arr [ j ] [ 1 ] < y and arr [ j ] [ 0 ] = = x.
If all conditions satisfy then point is central point.
Increment the count by 1.
Return the count.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count number of coordinates from an array satisfying the given conditions and the other steps required.
 def centralPoints ( arr , N ) :
	count = 0
	for i in range ( N ) :
		c1 = 0
		c2 = 0
		c3 = 0
		c4 = 0
		x = arr [ i ] [ 0 ]
		y = arr [ i ] [ 1 ]
		for j in range ( N ) :
			if ( arr [ j ] [ 0 ] > x and arr [ j ] [ 1 ] == y ) :
				c1 = 1
			if ( arr [ j ] [ 1 ] > y and arr [ j ] [ 0 ] == x ) :
				c2 = 1
			if ( arr [ j ] [ 0 ] < x and arr [ j ] [ 1 ] == y ) :
				c3 = 1
			if ( arr [ j ] [ 1 ] < y and arr [ j ] [ 0 ] == x ) :
				c4 = 1
		if ( c1 + c2 + c3 + c4 == 4 ) :
			count += 1
	return count
if __name__ == ' _ _ main _ _ ' :
	arr = [ [ 1 , 0 ] , [ 2 , 0 ] , [ 1 , 1 ] , [ 1 , - 1 ] ]
	N = len ( arr )
	print ( centralPoints ( arr , N ) ) ;