human
Minimize remaining array element by removing pairs and replacing them by their absolute difference | Function to find minimize the remaining array element by removing pairs and replacing them by their absolute difference.
Stores sum of array elements.
Traverse the array.
Update totalSum.
Stores half of totalSum.
dp [ i ] : True if sum i can be obtained as a subset sum.
Base case.
Stores closest sum that can be obtained as a subset sum.
Traverse the array.
Iterate over all possible value of sum.
Update dp [ j ].
If sum i can be obtained from array elements.
Update reach.
Driver Code"
How can the above be solved in Python?
 ... Give me a code to minimize remaining array element by removing pairs and replacing them by their absolute difference and the other steps required?
assistant
#Here is code to minimize remaining array element by removing pairs and replacing them by their absolute difference and the other steps required.
 def SmallestElementLeft ( arr , N ) :
	totalSum = 0
	for i in range ( N ) :
		totalSum += arr [ i ]
	req = totalSum // 2
	dp = [ False for i in range ( req + 1 ) ]
	memset ( dp , false , sizeof ( dp ) ) ;
	dp [ 0 ] = True
	reach = 0
	for i in range ( N ) :
		j = req
		while j >= arr [ i ] :
			dp [ j ] = dp [ j ] or dp [ j - arr [ i ] ]
			if ( dp [ j ] ) :
				reach = max ( reach , j )
			j -= 1
	return totalSum - ( 2 * reach )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 2 , 2 ]
	N = len ( arr )
	print ( SmallestElementLeft ( arr , N ) )