human
Give me a code to round the given number to nearest multiple of 10 and the other steps required given the following:
Round the given number to nearest multiple of 10 | Set | Function to round the given number to the nearest multiple of 10.
If string is empty.
If the last digit is less then or equal to 5 then it can be rounded to the nearest ( previous ) multiple of 10 by just replacing the last digit with 0.
Set the last digit to 0.
Print the updated number.
The number hast to be rounded to the next multiple of 10.
To store the carry.
Replace the last digit with 0.
Starting from the second last digit , add 1 to digits while there is carry.
While there are digits to consider and there is carry to add.
Get the current digit.
Add the carry.
If the digit exceeds 9 then the carry will be generated.
Else there will be no carry.
Update the current digit.
Get to the previous digit.
If the carry is still 1 then it must be inserted at the beginning of the string.
Prin the rest of the number.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to round the given number to nearest multiple of 10 and the other steps required.
 def roundToNearest ( str , n ) :
	if ( str == " " ) :
		return
	if ( ord ( str [ n - 1 ] ) - ord ( '0' ) <= 5 ) :
		str = list ( str )
		str [ n - 1 ] = '0'
		str = ' ' . join ( str )
		print ( str [ 0 : n ] )
	else :
		carry = 0
		str = list ( str )
		str [ n - 1 ] = '0'
		str = ' ' . join ( str )
		i = n - 2
		carry = 1
		while ( i >= 0 and carry == 1 ) :
			currentDigit = ord ( str [ i ] ) - ord ( '0' )
			currentDigit += carry
			if ( currentDigit > 9 ) :
				carry = 1
				currentDigit = 0
			else :
				carry = 0
			str [ i ] = chr ( currentDigit + '0' )
			i -= 1
		if ( carry == 1 ) :
			print ( carry )
		print ( str [ 0 : n ] )
if __name__ == ' _ _ main _ _ ' :
	str = "99999999999999993"
	n = len ( str )
	roundToNearest ( str , n )