human
Modify array by removing ( arr [ i ] + arr [ i + 1 ] ) th element exactly K times | Function to modify array by removing every K - th element from the array.
Check if current element is the k - th element.
Stores the elements after removing every kth element.
Append the current element if it is not k - th element.
Return the new array after removing every k - th element.
Function to print the array.
Traverse the array l [ ].
Function to print the array after performing the given operations exactly k times.
Store first N natural numbers.
Iterate over the range [ 0 , k - 1 ].
Store sums of the two consecutive terms.
Remove every p - th element from the array.
Increment x by 1 for the next iteration.
Print the resultant array.
Given arrays.
Function Call"
How can the above be solved in Python?

Give me a code to modify array by removing ( arr [ i ] + arr [ i + 1 ] ) th element exactly K times and the other steps required?
assistant
#Here is code to modify array by removing ( arr [ i ] + arr [ i + 1 ] ) th element exactly K times and the other steps required.
 def removeEveryKth ( l , k ) :
	for i in range ( 0 , len ( l ) ) :
		if i % k == 0 :
			l [ i ] = 0
	arr = [ 0 ]
	for i in range ( 1 , len ( l ) ) :
		if l [ i ] != 0 :
			arr . append ( l [ i ] )
	return arr
def printArray ( l ) :
	for i in range ( 1 , len ( l ) ) :
		print ( l [ i ] , end = " ▁ " )
	print ( )
def printSequence ( n , k ) :
	l = [ int ( i ) for i in range ( 0 , n + 1 ) ]
	x = 1
	for i in range ( 0 , k ) :
		p = l [ x ] + l [ x + 1 ]
		l = removeEveryKth ( l , p )
		x += 1
	printArray ( l )
N = 8
K = 2
printSequence ( N , K )