human
Count of elements to be inserted to make Array sum twice the XOR of Array | Function to find the minimum number of elements that need to be inserted such that the sum of the elements of the array is twice the XOR of the array.
Variable to store the Xor of all the elements.
Variable to store the sum of all elements.
Loop to find the Xor and the sum of the array.
If sum = 2 * Xor.
No need to insert more elements.
We insert one more element which is Sum.
We insert two more elements Sum + Xor and Xor ..
Print the number of elements inserted in the array.
Print the elements that are inserted in the array.
Driver code"
How can the above be solved in Python?

Write me a code to count of elements to be inserted to make Array sum twice the XOR of Array and the other steps required?
assistant
#Here is code to count of elements to be inserted to make Array sum twice the XOR of Array and the other steps required.
 def insert_element ( a , n ) :
	Xor = 0
	Sum = 0
	for i in range ( n ) :
		Xor ^= a [ i ]
		Sum += a [ i ]
	if ( Sum == 2 * Xor ) :
		print ( 0 )
		return
	if ( Xor == 0 ) :
		print ( 1 )
		print ( Sum )
		return
	num1 = Sum + Xor
	num2 = Xor
	print ( 2 )
	print ( num1 , num2 )
if __name__ == " _ _ main _ _ " :
	a = [ 1 , 2 , 3 ]
	n = len ( a )
	insert_element ( a , n )