human
Count of pairs of strings which differ in exactly one position | Function to return the count of same pairs.
Function to return total number of strings which satisfy required condition.
Dictionary changed will store strings with wild cards Dictionary same will store strings that are equal.
Iterating for all strings in the given array.
If we found the string then increment by 1 Else it will get default value 0.
Iterating on a single string.
Incrementing the string if found Else it will get default value 0.
Return counted pairs - equal pairs.
Driver code"
Solution in Python:
assistant
#Here is code to count of pairs of strings which differ in exactly one position and the other steps required.
 def pair_count ( d ) :
	return sum ( ( i * ( i - 1 ) ) // 2 for i in d . values ( ) )
def Difference ( array , m ) :
	changed , same = { } , { }
	for s in array :
		same [ s ] = same . get ( s , 0 ) + 1
		for i in range ( m ) :
			changed [ t ] = changed . get ( t , 0 ) + 1
	return pair_count ( changed ) - pair_count ( same ) * m
if __name__ == " _ _ main _ _ " :
	n , m = 3 , 3
	array = [ " abc " , " abd " , " bbd " ]
	print ( Difference ( array , m ) )