human
Solve the following python programming problem given the following code:
def assert_unordered_result(self, result, cls, * expected) : 
    'As assert_result, but the order of objects is not considered.

        The algorithm is very expensive but not a big deal for the small
        numbers of rows that the test suite manipulates.
        ' 
    class immutabledict (dict) : 
        def __hash__(self) : 
            return id (self) 
found = util.IdentitySet (result) 
    expected = set ([immutabledict (e) for e in found_item]) 
    for wrong in util.itertools_filterfalse ((lambda o : isinstance (o, cls)), found) : 
        fail (('Unexpected type "%s", expected "%s"' % (type (wrong).__name__, cls.__name__))) 
if (len (found) != len (expected)) : 
        fail (('Unexpected object count "%s", expected "%s"' % (len (found), len (expected)))) 
NOVALUE = object () 
    def _compare_item(obj, spec) : 
        for (key, value) in spec.items () : 
            if isinstance (value, tuple) : 
                try : 
                    self.assert_unordered_result (getattr (obj, key), value [0], * value [1]) 
except AssertionError : 
                    return False 
else : 
                if (getattr (obj, key, NOVALUE) != value) : 
                    return False 
return True 
for expected_item in expected : 
        for found_item in found : 
            if _compare_item (found_item, expected_item) : 
                found.remove (found_item) 
                break 
else : 
            fail (('Expected %s instance with attributes %s not found.' % (cls.__name__, repr (expected_item)))) 
return True 

    
    

    Fix the buggy line: expected = set ([immutabledict (e) for e in found_item])
assistant
#Here is Python program to fix the buggy line: expected = set ([immutabledict (e) for e in found_item])
.

expected = set ([immutabledict (e) for e in expected])