human
Count ways to make sum of odd and even indexed elements equal by removing an array element | Function to count array indices whose removal makes sum of odd and even indexed elements equal.
If size of the array is 1.
If size of the array is 2.
Stores sum of even - indexed elements of the given array.
Stores sum of odd - indexed elements of the given array.
Traverse the array.
If i is an even number.
Update sumEven.
If i is an odd number.
Update sumOdd.
Stores sum of even - indexed array elements till i - th index.
Stores sum of odd - indexed array elements till i - th index.
Stores count of indices whose removal makes sum of odd and even indexed elements equal.
Stores sum of even - indexed elements after removing the i - th element.
Stores sum of odd - indexed elements after removing the i - th element.
Traverse the array.
If i is an odd number.
Update currOdd.
Update newEvenSum.
Update newOddSum.
If i is an even number.
Update currEven.
Update newOddSum.
Update newEvenSum.
If newEvenSum is equal to newOddSum.
Increase the count.
If sum of even - indexed and odd - indexed elements is equal by removing the first element.
Increase the count.
If length of the array is an odd number.
If sum of even - indexed and odd - indexed elements is equal by removing the last element.
Increase the count.
If length of the array is an even number.
If sum of even - indexed and odd - indexed elements is equal by removing the last element.
Increase the count.
Driver Code"
Solution in Python:

Write me a code to count ways to make sum of odd and even indexed elements equal by removing an array element and the other steps required?
assistant
#Here is code to count ways to make sum of odd and even indexed elements equal by removing an array element and the other steps required.
 def cntIndexesToMakeBalance ( arr , n ) :
	if ( n == 1 ) :
		return 1
	if ( n == 2 ) :
		return 0
	sumEven = 0
	sumOdd = 0
	for i in range ( n ) :
		if ( i % 2 == 0 ) :
			sumEven += arr [ i ]
		else :
			sumOdd += arr [ i ]
	currOdd = 0
	currEven = arr [ 0 ]
	res = 0
	newEvenSum = 0
	newOddSum = 0
	for i in range ( 1 , n - 1 ) :
		if ( i % 2 ) :
			currOdd += arr [ i ]
			newEvenSum = ( currEven + sumOdd - currOdd )
			newOddSum = ( currOdd + sumEven - currEven - arr [ i ] )
		else :
			currEven += arr [ i ]
			newOddSum = ( currOdd + sumEven - currEven )
			newEvenSum = ( currEven + sumOdd - currOdd - arr [ i ] )
		if ( newEvenSum == newOddSum ) :
			res += 1
	if ( sumOdd == sumEven - arr [ 0 ] ) :
		res += 1
	if ( n % 2 == 1 ) :
		if ( sumOdd == sumEven - arr [ n - 1 ] ) :
			res += 1
	else :
		if ( sumEven == sumOdd - arr [ n - 1 ] ) :
			res += 1
	return res
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 1 , 1 ]
	n = len ( arr )
	print ( cntIndexesToMakeBalance ( arr , n ) )