human
Can you provide a code to count pairs from an array with absolute difference not less than the minimum element in the pair and the other steps required given the following:
Count pairs from an array with absolute difference not less than the minimum element in the pair | Function to find the number of pairs ( i , j ) such that abs ( a [ i ] - a [ j ] ) is at least the minimum of ( a [ i ] , a [ j ] ).
Stores the resultant count of pairs.
Iterate over the range [ 0 , n ].
Iterate from arr [ i ] - ( i % arr [ i ] ) till n with an increment of arr [ i ].
Count the possible pairs.
Return the total count.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count pairs from an array with absolute difference not less than the minimum element in the pair and the other steps required.
 def getPairsCount ( arr , n ) :
	count = 0
	for i in range ( n ) :
		for j in range ( arr [ i ] - ( i % arr [ i ] ) , n , arr [ i ] ) :
			if ( i < j and abs ( arr [ i ] - arr [ j ] ) >= min ( arr [ i ] , arr [ j ] ) ) :
				count += 1
	return count
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 2 , 3 ]
	N = len ( arr )
	print ( getPairsCount ( arr , N ) )