human
Count pairs from a given range having equal Bitwise OR and XOR values | Function to calculate ( x ^ y ) % MOD.
Initialize result.
Update x if it is more than or equal to MOD.
If y is odd , multiply x with result.
y must be even now y = y / 2.
Return ( x ^ y ) % MOD.
Function to count total pairs.
The upper bound is 2 ^ N.
Stores the count of pairs.
Generate all possible pairs.
Find XOR of both integers.
Find OR of both integers.
If both are equal.
Increment count.
Print count % MOD.
Driver Code.
Function Call"
Solution in Python:
 ... Can you provide a code to count pairs from a given range having equal Bitwise OR and XOR values and the other steps required?
assistant
#Here is code to count pairs from a given range having equal Bitwise OR and XOR values and the other steps required.
 def power ( x , y ) :
	MOD = 1000000007
	res = 1
	x = x % MOD
	while ( y > 0 ) :
		if ( y & 1 ) :
			res = ( res * x ) % MOD
		y = y >> 1
		x = ( x * x ) % MOD
	return res
def countPairs ( N ) :
	MOD = 1000000007
	high = power ( 2 , N )
	count = 0
	for i in range ( high ) :
		for j in range ( high ) :
			X = ( i ^ j )
			Y = ( i j )
			if ( X == Y ) :
				count += 1
	print ( count % MOD )
N = 10
countPairs ( N )