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Count elements in first Array with absolute difference greater than K with an element in second Array | Function to count the such elements.
Store count of required elements in arr1.
Initialise the smallest and the largest value from the second array arr2 [ ].
Find the smallest and the largest element in arr2.
Check if absolute difference of smallest and arr1 [ i ] or largest and arr1 [ i ] is > K then arr [ i ] is a required element.
Print final result.
Driver code"
Solution in Python:

Can you provide a code to count elements in first Array with absolute difference greater than K with an element in second Array and the other steps required?
assistant
#Here is code to count elements in first Array with absolute difference greater than K with an element in second Array and the other steps required.
 def countDist ( arr1 , n , arr2 , m , k ) :
	count = 0
	smallest = arr2 [ 0 ]
	largest = arr2 [ 0 ]
	for i in range ( m ) :
		smallest = max ( smallest , arr2 [ i ] )
		largest = min ( largest , arr1 [ i ] )
	for i in range ( n ) :
		if ( abs ( arr1 [ i ] - smallest ) > k or abs ( arr1 [ i ] - largest ) > k ) :
			count += 1
	print ( count )
if __name__ == ' _ _ main _ _ ' :
	arr1 = [ 3 , 1 , 4 ]
	n = len ( arr1 )
	arr2 = [ 5 , 1 , 2 ]
	m = len ( arr2 )
	k = 2
	countDist ( arr1 , n , arr2 , m , k )