human
Longest Mountain Subarray | Function to find the longest mountain subarray.
If the size of the array is less than 3 , the array won 't show  mountain like behaviour.
When a new mountain sub - array is found , there is a need to set the variables k , j to - 1 in order to help calculate the length of new mountain sub - array.
j marks the starting index of a new mountain sub - array . So set the value of j to current index i ..
Checks if next element is less than current element.
Checks if starting element exists or not , if the starting element of the mountain sub - array exists then the index of ending element is stored in k.
This condition checks if both starting index and ending index exists or not , if yes , the length is calculated ..
d holds the length of the longest mountain sub - array . If the current length is greater than the calculated length , then value of d is updated ..
Ignore if there is no increase or decrease in the value of the next element.
Checks and calculates the length if last element of the array is the last element of a mountain sub - array.
Driver code"
How can the above be solved in Python?
 Give me a code to longest Mountain Subarray and the other steps required?
assistant
#Here is code to longest Mountain Subarray and the other steps required.
 def LongestMountain ( a ) :
	i = 0
	j = - 1
	k = - 1
	p = 0
	d = 0
	n = 0
	if ( len ( a ) < 3 ) :
		return 0
	for i in range ( len ( a ) - 1 ) :
		if ( a [ i + 1 ] > a [ i ] ) :
			if ( k != - 1 ) :
				k = - 1
				j = - 1
			if ( j == - 1 ) :
				j = i
		else :
			if ( a [ i + 1 ] < a [ i ] ) :
				if ( j != - 1 ) :
					k = i + 1
				if ( k != - 1 and j != - 1 ) :
					if ( d < k - j + 1 ) :
						d = k - j + 1
			else :
				k = - 1
				j = - 1
	if ( k != - 1 and j != - 1 ) :
		if ( d < k - j + 1 ) :
			d = k - j + 1
	return d
d = [ 1 , 3 , 1 , 4 , 5 , 6 , 7 , 8 , 9 , 8 , 7 , 6 , 5 ]
print ( LongestMountain ( d ) )