human
Solve the following python programming problem given the following code:
def breadth_first_search(graph, root = None, filter = null ()) : 
    "
    Breadth-first search.

    @type  graph: graph, digraph
    @param graph: Graph.

    @type  root: node
    @param root: Optional root node (will explore only root's connected component)

    @rtype:  tuple
    @return: A tuple containing a dictionary and a list.
        1. Generated spanning tree
        2. Graph's level-based ordering
    " 
    def bfs() : 
        '
        Breadth-first search subfunction.
        ' 
        while (queue != []) : 
            node = queue.pop (0) 
            for other in graph [node] : 
                if ((other not in spanning_tree) and filter (other, node)) : 
                    queue.append (other) 
                    ordering.append (other) 
                    spanning_tree [other] = node 
queue = [] 
    spanning_tree = { 
        
} 
    ordering = [] 
    filter.configure (graph, bfs) 
    if (root is not None) : 
        if filter (root, None) : 
            queue.append (root) 
            ordering.append (root) 
            spanning_tree [root] = None 
            bfs () 
return (spanning_tree, ordering) 
for each in graph : 
        if (each not in spanning_tree) : 
            if filter (each, None) : 
                queue.append (each) 
                ordering.append (each) 
                spanning_tree [each] = None 
                bfs () 
return (spanning_tree, ordering) 

    
    

    Fix the buggy line: filter.configure (graph, bfs)
assistant
#Here is Python code to fix the buggy line: filter.

filter.configure (graph, spanning_tree)