human
Give me a code to length of the longest subsegment which is UpDown after inserting atmost one integer and the other steps required given the following:
Length of the longest subsegment which is UpDown after inserting atmost one integer | Function to recursively fill the dp array.
If f ( i , state ) is already calculated then return the value.
Calculate f ( i , state ) according to the recurrence relation and store in dp [ ] [ ].
Function that calls the resucrsive function to fill the dp array and then returns the result.
dp [ ] [ ] array for storing result of f ( i , 1 ) and f ( 1 , 2 ) Populating the array dp [ ] with - 1.
Make sure that longest UD and DU sequence starting at each index is calculated.
Assume the answer to be - 1 This value will only increase.
y is the length of the longest UD sequence starting at i.
If length is even then add an integer and then a DU sequence starting at i + y.
If length is odd then add an integer and then a UD sequence starting at i + y.
Driver Code"
Solution in Python:
assistant
#Here is code to length of the longest subsegment which is UpDown after inserting atmost one integer and the other steps required.
 def f ( i , state , A , dp , N ) :
	if i >= N :
		return 0
	elif dp [ i ] [ state ] != - 1 :
		return dp [ i ] [ state ]
	else :
		if i == N - 1 :
			dp [ i ] [ state ] = 1
		elif state == 1 and A [ i ] > A [ i + 1 ] :
			dp [ i ] [ state ] = 1
		elif state == 2 and A [ i ] < A [ i + 1 ] :
			dp [ i ] [ state ] = 1
		elif state == 1 and A [ i ] <= A [ i + 1 ] :
			dp [ i ] [ state ] = 1 + f ( i + 1 , 2 , A , dp , N )
		elif state == 2 and A [ i ] >= A [ i + 1 ] :
			dp [ i ] [ state ] = 1 + f ( i + 1 , 1 , A , dp , N )
		return dp [ i ] [ state ]
def maxLenSeq ( A , N ) :
	dp = [ [ - 1 , - 1 , - 1 ] for i in range ( 1000 ) ]
	for i in range ( N ) :
		tmp = f ( i , 1 , A , dp , N )
		tmp = f ( i , 2 , A , dp , N )
	ans = - 1
	for i in range ( N ) :
		y = dp [ i ] [ 1 ]
		if ( i + y ) >= N :
			ans = max ( ans , dp [ i ] [ 1 ] + 1 )
		elif y % 2 == 0 :
			ans = max ( ans , dp [ i ] [ 1 ] + 1 + dp [ i + y ] [ 2 ] )
		elif y % 2 == 1 :
			ans = max ( ans , dp [ i ] [ 1 ] + 1 + dp [ i + y ] [ 1 ] )
	return ans
if __name__ == " _ _ main _ _ " :
	A = [ 1 , 10 , 3 , 20 , 25 , 24 ]
	n = len ( A )
	print ( maxLenSeq ( A , n ) )