human
Count of indices pairs such that product of elements at these indices is equal to absolute difference of indices | Function to count the number of pairs ( i , j ) such that arr [ i ] * arr [ j ] is equal to abs ( i - j ).
Stores the resultant number of pairs.
Iterate over the range [ 0 , N ).
Now , iterate from the value arr [ i ] - ( i % arr [ i ] ) till N with an increment of arr [ i ].
If the given criteria satisfy then increment the value of count.
Return the resultant count.
Driver Code"
How can the above be solved in Python?
 ... Can you provide a code to count of indices pairs such that product of elements at these indices is equal to absolute difference of indices and the other steps required?
assistant
#Here is code to count of indices pairs such that product of elements at these indices is equal to absolute difference of indices and the other steps required.
 def getPairsCount ( arr , n ) :
	count = 0
	for i in range ( 0 , n ) :
		s = arr [ i ] - ( i % arr [ i ] )
		for j in range ( s , n ) :
			if ( i < j and ( arr [ i ] * arr [ j ] ) == abs ( i - j ) ) :
				count += 1
	return count
arr = [ 1 , 1 , 2 , 4 ]
N = len ( arr )
print ( getPairsCount ( arr , N ) )