human
Print first N Mosaic numbers | Function to return the nth mosaic number.
Iterate from 2 to the number.
If i is the factor of n.
Find the count where i ^ count is a factor of n.
Divide the number by i.
Increase the count.
Multiply the answer with count and i.
Return the answer.
Function to print first N Mosaic numbers.
Driver code"
Solution in Python:
assistant
#Here is code to print first N Mosaic numbers and the other steps required.
 def mosaic ( n ) :
	ans = 1
	for i in range ( 2 , n + 1 ) :
		if ( n % i == 0 and n > 0 ) :
			count = 0 ;
			while ( n % i == 0 ) :
				n = n // i
				count += 1 ;
			ans *= count * i ;
	return ans ;
def nMosaicNumbers ( n ) :
	for i in range ( 1 , n + 1 ) :
		print mosaic ( i ) ,
n = 10 ;
nMosaicNumbers ( n ) ;