human
Count unique numbers that can be generated from N by adding one and removing trailing zeros | Function to count the unique numbers.
If the number has already been visited.
Insert the number to the set.
First step.
Second step remove trailing zeros.
Recur again for the new number.
Driver code"
How can the above be solved in Python?

What is a code to count unique numbers that can be generated from N by adding one and removing trailing zeros and the other steps required?
assistant
#Here is code to count unique numbers that can be generated from N by adding one and removing trailing zeros and the other steps required.
 def count_unique ( s , n ) :
	if ( s . count ( n ) ) :
		return ;
	s . append ( n ) ;
	n += 1 ;
	while ( n % 10 == 0 ) :
		n = n // 10 ;
	count_unique ( s , n ) ;
if __name__ == " _ _ main _ _ " :
	n = 10
	s = [ ]
	count_unique ( s , n )
	print ( len ( s ) )