human
Print numbers in the range 1 to n having bits in alternate pattern | function to print numbers in the range 1 to nhaving bits in alternate pattern.
first number having bits in alternate pattern.
display.
loop until n < curr_num.
generate next number having alternate bit pattern.
if true then break.
display.
generate next number having alternate bit pattern.
if true then break.
display.
Driven code"
Solution in Python:

What is a code to print numbers in the range 1 to n having bits in alternate pattern and the other steps required?
assistant
#Here is code to print numbers in the range 1 to n having bits in alternate pattern and the other steps required.
 def printNumHavingAltBitPatrn ( n ) :
	curr_num = 1
	print ( curr_num )
	while ( 1 ) :
		curr_num = curr_num << 1 ;
		if ( n < curr_num ) :
			break ;
		print ( curr_num )
		curr_num = ( ( curr_num ) << 1 ) ^ 1 ;
		if ( n < curr_num ) :
			break
		print ( curr_num )
n = 50
printNumHavingAltBitPatrn ( n )