human
Number of segments where all elements are greater than X | Function to count number of segments.
Iterate in the array.
check if array element greater then X or not.
if flag is true.
After iteration complete check for the last segment.
Driver Code"
How can the above be solved in Python?
 Can you provide a code to number of segments where all elements are greater than X and the other steps required?
assistant
#Here is code to number of segments where all elements are greater than X and the other steps required.
 def countSegments ( a , n , x ) :
	flag = False
	count = 0
	for i in range ( n ) :
		if ( a [ i ] > x ) :
			flag = True
		else :
			if ( flag ) :
				count += 1
			flag = False
	if ( flag ) :
		count += 1
	return count
if __name__ == ' _ _ main _ _ ' :
	a = [ 8 , 25 , 10 , 19 , 19 , 18 , 20 , 11 , 18 ]
	n = len ( a )
	x = 13
	print ( countSegments ( a , n , x ) )