human
Maximum sum of pairs with specific difference | Method to return maximum sum we can get by finding less than K difference pairs.
Sort elements to ensure every i and i - 1 is closest possible pair.
To get maximum possible sum , iterate from largest to smallest , giving larger numbers priority over smaller numbers ..
Case I : Diff of arr [ i ] and arr [ i - 1 ] is less then K , add to maxSum Case II : Diff between arr [ i ] and arr [ i - 1 ] is not less then K , move to next i since with sorting we know , arr [ i ] - arr [ i - 1 ] < arr [ i ] - arr [ i - 2 ] and so on ..
Assuming only positive numbers ..
When a match is found skip this pair.
Driver Code"
Solution in Python:
 Can you provide a code to maximum sum of pairs with specific difference and the other steps required?
assistant
#Here is code to maximum sum of pairs with specific difference and the other steps required.
 def maxSumPairWithDifferenceLessThanK ( arr , N , k ) :
	maxSum = 0
	arr . sort ( )
	i = N - 1
	while ( i > 0 ) :
		if ( arr [ i ] - arr [ i - 1 ] < k ) :
			maxSum += arr [ i ]
			maxSum += arr [ i - 1 ]
			i -= 1
		i -= 1
	return maxSum
arr = [ 3 , 5 , 10 , 15 , 17 , 12 , 9 ]
N = len ( arr )
K = 4
print ( maxSumPairWithDifferenceLessThanK ( arr , N , K ) )