human
Can you provide a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/remove-sub-folders-from-the-filesystem/:
Given a list of folders, remove all sub-folders in those folders and return in any order the folders after removing.
If a folder[i] is located within another folder[j], it is called a sub-folder of it.
The format of a path is one or more concatenated strings of the form: / followed by one or more lowercase English letters. For example, /leetcode and /leetcode/problems are valid paths while an empty string and / are not.
 
Example 1:
Input: folder = ["/a","/a/b","/c/d","/c/d/e","/c/f"]
Output: ["/a","/c/d","/c/f"]
Explanation: Folders "/a/b/" is a subfolder of "/a" and "/c/d/e" is inside of folder "/c/d" in our filesystem.

Example 2:
Input: folder = ["/a","/a/b/c","/a/b/d"]
Output: ["/a"]
Explanation: Folders "/a/b/c" and "/a/b/d/" will be removed because they are subfolders of "/a".

Example 3:
Input: folder = ["/a/b/c","/a/b/ca","/a/b/d"]
Output: ["/a/b/c","/a/b/ca","/a/b/d"]

 
Constraints:

1 <= folder.length <= 4 * 10^4
2 <= folder[i].length <= 100
folder[i] contains only lowercase letters and '/'
folder[i] always starts with character '/'
Each folder name is unique.

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution:
    def removeSubfolders(self, folder: List[str]) -> List[str]:
        trie = {}
        tokens = {path: path.split('/') for path in folder}
        for path in folder:
            curr = trie
            for token in tokens[path]:
                if '#' in curr:
                    break
                if token not in curr:
                    curr[token] = {}
                curr = curr[token]
            curr['#'] = True
 
        paths = set(folder)
        for path in folder:
            curr = trie
            for token in tokens[path]:
                if '#' in curr:
                    paths.remove(path)
                    break
                curr = curr[token]    
        return list(paths)