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What is a code to number of times an array can be partitioned repetitively into two subarrays with equal sum and the other steps required given the following:
Number of times an array can be partitioned repetitively into two subarrays with equal sum | Recursion Function to calculate the possible splitting.
If there are less than two elements , we cannot partition the sub - array ..
Iterate from the start to end - 1..
Recursive call to the left and the right sub - array ..
If there is no such partition , then return 0.
Function to find the total splitting.
Prefix array to store the prefix - sum using 1 based indexing.
Store the prefix - sum.
Function Call to count the number of splitting.
Given array.
Function call"
Solution in Python:
assistant
#Here is code to number of times an array can be partitioned repetitively into two subarrays with equal sum and the other steps required.
 def splitArray ( start , end , arr , prefix_sum ) :
	if ( start >= end ) :
		return 0
	for k in range ( start , end ) :
		if ( ( prefix_sum [ k ] - prefix_sum [ start - 1 ] ) == ( prefix_sum [ end ] - prefix_sum [ k ] ) ) :
			return ( 1 + splitArray ( start , k , arr , prefix_sum ) + splitArray ( k + 1 , end , arr , prefix_sum ) )
	return 0
def solve ( arr , n ) :
	prefix_sum = [ 0 ] * ( n + 1 )
	prefix_sum [ 0 ] = 0
	for i in range ( 1 , n + 1 ) :
		prefix_sum [ i ] = ( prefix_sum [ i - 1 ] + arr [ i - 1 ] )
	print ( splitArray ( 1 , n , arr , prefix_sum ) )
arr = [ 12 , 3 , 3 , 0 , 3 , 3 ]
N = len ( arr )
solve ( arr , N )