human
Minimum cost of flipping characters required to convert Binary String to 0 s only | Function to find the minimum cost to convert given string to 0 s only.
Length of string.
Stores the index of leftmost '1' in str.
Update the index of leftmost '1' in str.
Stores the index of rightmost '1' in str.
Update the index of rightmost '1' in str.
If str does not contain any '1' s.
No changes required.
Stores minimum cost.
Iterating through str form left_1 to right_1.
Stores length of consecutive 0 s.
Calculate length of consecutive 0 s.
If a substring of 0 s exists.
Update minimum cost.
Printing the minimum cost.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to minimum cost of flipping characters required to convert Binary String to 0 s only and the other steps required.
 def convert_to_allzeroes ( st , a , b ) :
	length = len ( st )
	left_1 = 0
	i = 0
	while ( i < length and st [ i ] == '0' ) :
		i += 1
	left_1 = i
	right_1 = 0
	i = length - 1
	while ( i >= 0 and st [ i ] == '0' ) :
		i -= 1
	right_1 = i
	if ( left_1 == length and right_1 == - 1 ) :
		print ( 0 )
		return
	cost = a
	for i in range ( left_1 , right_1 + 1 ) :
		zeroes = 0
		while ( i < length and st [ i ] == '0' ) :
			zeroes += 1
			i += 1
		if ( zeroes ) :
			cost += min ( zeroes * b , a )
	print ( cost )
if __name__ == " _ _ main _ _ " :
	st = "01101110"
	A = 5
	B = 1
	convert_to_allzeroes ( st , A , B )