human
Give me a code to check if a Binary String can be split into disjoint subsequences which are equal to "010" and the other steps required given the following:
Check if a Binary String can be split into disjoint subsequences which are equal to "010" | Function to check if the given string can be partitioned into a number of subsequences all of which are equal to "010".
Store the size of the string.
Store the count of 0 s and 1 s.
Traverse the given string in the forward direction.
If the character is '0' , increment count_0 by 1.
If the character is '1' increment count_1 by 1.
If at any point , count_1 > count_0 , return false.
If count_0 is not equal to twice count_1 , return false.
Reset the value of count_0 and count_1.
Traverse the string in the reverse direction.
If the character is '0' increment count_0.
If the character is '1' increment count_1.
If count_1 > count_0 , return false.
Driver Code.
Given string.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to check if a Binary String can be split into disjoint subsequences which are equal to "010" and the other steps required.
 def isPossible ( s ) :
	n = len ( s )
	count_0 , count_1 = 0 , 0
	for i in range ( n ) :
		if ( s [ i ] == '0' ) :
			count_0 += 1
		else :
			count_1 += 1
		if ( count_1 > count_0 ) :
			return False
	if ( count_0 != ( 2 * count_1 ) ) :
		return False
	count_0 , count_1 = 0 , 0
	for i in range ( n - 1 , - 1 , - 1 ) :
		if ( s [ i ] == '0' ) :
			count_0 += 1
		else :
			count_1 += 1
		if ( count_1 > count_0 ) :
			return False
	return True
if __name__ == ' _ _ main _ _ ' :
	s = "010100"
	if ( isPossible ( s ) ) :
		print ( " Yes " )
	else :
		print ( " No " )