human
Find Kth number from sorted array formed by multiplying any two numbers in the array | Function to find number of pairs.
Negative and Negative.
Add Possible Pairs.
Positive and Positive.
Add Possible pairs.
Negative and Positive.
Add Possible pairs.
Function to find the kth element in the list.
Separate Positive and Negative elements.
Sort the Elements.
Binary search.
Return the required answer.
Driver code.
Function call"
How can the above be solved in Python?
assistant
#Here is code to find Kth number from sorted array formed by multiplying any two numbers in the array and the other steps required.
 def check ( x , pos , neg , k ) :
	pairs = 0
	p = len ( neg ) - 1
	nn = len ( neg ) - 1
	pp = len ( pos ) - 1
	for i in range ( len ( neg ) ) :
		while ( p >= 0 and neg [ i ] * neg [ p ] <= x ) :
			p -= 1
		pairs += min ( nn - p , nn - i )
	p = 0
	for i in range ( len ( pos ) - 1 , - 1 , - 1 ) :
		while ( p < len ( pos ) and pos [ i ] * pos [ p ] <= x ) :
			p += 1
		pairs += min ( p , i )
	p = len ( pos ) - 1
	for i in range ( len ( neg ) - 1 , - 1 , - 1 ) :
		while ( p >= 0 and neg [ i ] * pos [ p ] <= x ) :
			p -= 1
		pairs += pp - p
	return ( pairs >= k )
def kth_element ( a , n , k ) :
	pos , neg = [ ] , [ ]
	for i in range ( n ) :
		if ( a [ i ] >= 0 ) :
			pos . append ( a [ i ] )
		else :
			neg . append ( a [ i ] )
	pos = sorted ( pos )
	neg = sorted ( neg )
	l = - 10 ** 18
	ans = 0
	r = 10 ** 18
	while ( l <= r ) :
		mid = ( l + r ) >> 1
		if ( check ( mid , pos , neg , k ) ) :
			ans = mid
			r = mid - 1
		else :
			l = mid + 1
	return ans
a = [ - 4 , - 2 , 3 , 3 ]
k = 3
n = len ( a )
print ( kth_element ( a , n , k ) )