human
Write me a code to append a digit in the end to make the number equal to the length of the remaining string and the other steps required given the following:
Append a digit in the end to make the number equal to the length of the remaining string | Function to return the required digit.
To store the position of the first numeric digit in the string.
To store the length of the string without the numeric digits in the end.
pw stores the current power of 10 and num is to store the number which is appended in the end.
If current character is a numeric digit.
Get the current digit.
Build the number.
If number exceeds the length.
Next power of 10.
Append 0 in the end.
Required number that must be added.
If number is not a single digit.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to append a digit in the end to make the number equal to the length of the remaining string and the other steps required.
 def find_digit ( s , n ) :
	first_digit = - 1
	for i in range ( n - 1 , - 1 , - 1 ) :
		if s [ i ] < '0' or s [ i ] > '9' :
			first_digit = i
			break
	first_digit += 1
	s_len = first_digit
	num = 0
	pw = 1
	i = n - 1
	while i >= 0 :
		if s [ i ] >= '0' and s [ i ] <= '9' :
			digit = ord ( s [ i ] ) - ord ( '0' )
			num = num + ( pw * digit )
			if num >= s_len :
				return - 1
			pw = pw * 10
		i -= 1
	num = num * 10
	req = s_len - num
	if req > 9 or req < 0 :
		return - 1
	return req
if __name__ == " _ _ main _ _ " :
	s = " abcd0"
	n = len ( s )
	print ( find_digit ( s , n ) )