human
Maximum number of consecutive 1 s after flipping all 0 s in a K length subarray | Function to find the maximum number of consecutive 1 's after flipping all zero in a K length subarray.
Initialize variable.
Iterate unil n - k + 1 as we have to go till i + k.
Iterate in the array in left direction till you get 1 else break.
Iterate in the array in right direction till you get 1 else break.
Compute the maximum length.
Return the length.
Driver code.
Array initialization.
Size of array"
How can the above be solved in Python?
assistant
#Here is code to maximum number of consecutive 1 s after flipping all 0 s in a K length subarray and the other steps required.
 def findmax ( arr , n , k ) :
	trav , i = 0 , 0
	c = 0
	maximum = 0
	while i < n - k + 1 :
		trav = i - 1
		c = 0
		while trav >= 0 and arr [ trav ] == 1 :
			trav -= 1
			c += 1
		trav = i + k
		while ( trav < n and arr [ trav ] == 1 ) :
			trav += 1
			c += 1
		c += k
		if ( c > maximum ) :
			maximum = c
		i += 1
	return maximum
if __name__ == ' _ _ main _ _ ' :
	k = 3
	arr = [ 0 , 0 , 1 , 1 , 0 , 0 , 0 , 0 ]
	n = len ( arr )
	ans = findmax ( arr , n , k )
	print ( ans )