human
Count of N | Function to find the value of X to the power Y.
Stores the value of X ^ Y.
If y is odd , multiply x with result.
Update the value of y and x.
Return the result.
Function to count number of arrays having element over the range [ 0 , 2 ^ K - 1 ] with Bitwise AND value 0 having maximum possible sum.
Print the value of N ^ K.
Driver Code"
How can the above be solved in Python?

Give me a code to count of N and the other steps required?
assistant
#Here is code to count of N and the other steps required.
 def power ( x , y ) :
	res = 1
	while ( y > 0 ) :
		if ( y & 1 ) :
			res = res * x
		y = y >> 1
		x = x * x
	return res
def countArrays ( N , K ) :
	print ( power ( N , K ) )
N = 5 ;
K = 6 ;
countArrays ( N , K )