human
Print all subsequences of a string | Iterative Method | function to find subsequence.
check if jth bit in binary is 1.
if jth bit is 1 , include it in subsequence.
function to print all subsequences.
map to store subsequence lexicographically by length.
Total number of non - empty subsequence in string is 2 ^ len - 1.
i = 0 , corresponds to empty subsequence.
subsequence for binary pattern i.
storing sub in map.
it . first is length of Subsequence it . second is set < string >.
ii is iterator of type set < string >.
Driver Code"
How can the above be solved in Python?
 ... Can you provide a code to print all subsequences of a string and the other steps required?
assistant
#Here is code to print all subsequences of a string and the other steps required.
 def subsequence ( s , binary , length ) :
	sub = " "
	for j in range ( length ) :
		if ( binary & ( 1 << j ) ) :
			sub += s [ j ]
	return sub
def possibleSubsequences ( s ) :
	sorted_subsequence = { }
	length = len ( s )
	limit = 2 ** length
	for i in range ( 1 , limit ) :
		sub = subsequence ( s , i , length )
		if len ( sub ) in sorted_subsequence . keys ( ) :
			sorted_subsequence [ len ( sub ) ] = tuple ( list ( sorted_subsequence [ len ( sub ) ] ) + [ sub ] )
		else :
			sorted_subsequence [ len ( sub ) ] = [ sub ]
	for it in sorted_subsequence :
		print ( " Subsequences ▁ of ▁ length ▁ = " , it , " are : " )
		for ii in sorted ( set ( sorted_subsequence [ it ] ) ) :
			print ( ii , end = ' ▁ ' )
		print ( )
s = " aabc "
possibleSubsequences ( s )