human
Count ways to partition a string such that both parts have equal distinct characters | Function to count the distinct characters in the string.
Frequency of each character.
Loop to count the frequency of each character of the string.
If frequency is greater than 0 then the character occured.
Function to count the number of ways to partition the string such that each partition have same number of distinct character.
Loop to choose the partition index for the string.
Divide in two parts.
Check whether number of distinct characters are equal.
Driver Code"
Solution in Python:
 Write me a code to count ways to partition a string such that both parts have equal distinct characters and the other steps required?
assistant
#Here is code to count ways to partition a string such that both parts have equal distinct characters and the other steps required.
 def distinctChars ( s ) :
	freq = [ 0 ] * 26 ;
	count = 0 ;
	for i in range ( len ( s ) ) :
		freq [ ord ( s [ i ] ) - ord ( ' a ' ) ] += 1 ;
	for i in range ( 26 ) :
		if ( freq [ i ] > 0 ) :
			count += 1 ;
	return count ;
def waysToSplit ( s ) :
	n = len ( s ) ;
	answer = 0 ;
	for i in range ( 1 , n ) :
		left = s [ 0 : i ] ;
		right = s [ i : n ] ;
		if ( distinctChars ( left ) == distinctChars ( right ) ) :
			answer += 1 ;
	return answer ;
if __name__ == " _ _ main _ _ " :
	s = " ababa " ;
	print ( waysToSplit ( s ) ) ;