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Minimize count of increments of each element of subarrays required to make Array non | Function to find the minimum number of operations required to make the array non - increasing.
Stores the count of required operations.
If arr [ i ] > arr [ i + 1 ] , no increments required . Otherwise , add their difference to the answer.
Return the result res.
Driver Code"
Solution in Python:

What is a code to minimize count of increments of each element of subarrays required to make Array non and the other steps required?
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#Here is code to minimize count of increments of each element of subarrays required to make Array non and the other steps required.
 def getMinOps ( arr ) :
	res = 0
	for i in range ( len ( arr ) - 1 ) :
		res += max ( arr [ i + 1 ] - arr [ i ] , 0 )
	return res
arr = [ 1 , 3 , 4 , 1 , 2 ]
print ( getMinOps ( arr ) )