human
Give me a code to subarray permutation that satisfies the given condition and the other steps required given the following:
Subarray permutation that satisfies the given condition | Function that returns true if the required subarray exists in the given array.
Map to store the positions of each integer in the original permutation.
To store the address of each entry in arr [ n ] but with 1 - based indexing.
To track minimum position sumcur for sum of a positions ti this position.
Summing up addresses.
Tracking minimum address encountered ti now.
The sum of the addresses if it forms the required subarray.
If current sum of address is equal to val.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to subarray permutation that satisfies the given condition and the other steps required.
 def subArray ( arr , n , m ) :
	i = 0
	mp = dict ( )
	for i in range ( n ) :
		mp [ arr [ i ] ] = i + 1
	sumcur = 0
	p = 10 ** 9
	ans = [ ]
	for i in range ( 1 , m + 1 ) :
		sumcur += mp [ i ]
		p = min ( p , mp [ i ] )
		val = p * i - i + ( i * ( i + 1 ) ) / 2
		if ( i == m ) :
			if ( val == sumcur ) :
				return True
			else :
				return False
arr = [ 4 , 5 , 1 , 3 , 2 , 6 ]
n = len ( arr )
m = 3
if ( subArray ( arr , n , m ) ) :
	print ( " Yes " )
else :
	print ( " No " )