human
Can you provide a code to change the array into a permutation of numbers from 1 to n and the other steps required given the following:
Change the array into a permutation of numbers from 1 to n | Python3 code to make a permutation of numbers from 1 to n using minimum changes ..
Store counts of all elements ..
Find next missing element to put in place of current element ..
Replace with next missing and insert the missing element in hash ..
Driver Code"
Solution in Python:
assistant
#Here is code to change the array into a permutation of numbers from 1 to n and the other steps required.
 def makePermutation ( a , n ) :
	count = dict ( )
	for i in range ( n ) :
		if count . get ( a [ i ] ) :
			count [ a [ i ] ] += 1
		else :
			count [ a [ i ] ] = 1 ;
	next_missing = 1
	for i in range ( n ) :
		if count [ a [ i ] ] != 1 or a [ i ] > n or a [ i ] < 1 :
			count [ a [ i ] ] -= 1
			while count . get ( next_missing ) :
				next_missing += 1
			a [ i ] = next_missing
			count [ next_missing ] = 1
A = [ 2 , 2 , 3 , 3 ]
n = len ( A )
makePermutation ( A , n )
for i in range ( n ) :
	print ( A [ i ] , end = " ▁ " )