human
Check if a given number N has at least one odd divisor not exceeding N | Function to check whether N has at least one odd divisor not exceeding N - 1 or not.
Stores the value of N.
Reduce the given number N by dividing it by 2.
If N is divisible by an odd divisor i.
Check if N is an odd divisor after reducing N by dividing it by 2.
Otherwise.
Driver Code.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to check if a given number N has at least one odd divisor not exceeding N and the other steps required.
 def oddDivisor ( N ) :
	X = N
	while ( N % 2 == 0 ) :
		N //= 2
	i = 3
	while ( i * i <= X ) :
		if ( N % i == 0 ) :
			return " Yes "
		i += 2
	if ( N != X ) :
		return " Yes "
	return " No "
N = 10
print ( oddDivisor ( N ) )