human
Write me a code to number of N length sequences whose product is M and the other steps required given the following:
Number of N length sequences whose product is M | Function to calculate the value of ncr effectively.
Initializing the result.
Multiply and divide simultaneously to avoid overflow.
Return the answer.
Function to return the number of sequences of length N such that their product is M.
Hashmap to store the prime factors of M.
Calculate the prime factors of M.
If i divides M it means it is a factor Divide M by i till it could be divided to store the exponent.
Increase the exponent count.
If the number is a prime number greater than sqrt ( M ).
Initializing the ans.
Multiply the answer for every prime factor.
it . second represents the exponent of every prime factor.
Return the result.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to number of N length sequences whose product is M and the other steps required.
 def ncr ( n , r ) :
	res = 1
	for i in range ( 1 , r + 1 ) :
		res *= ( n - r + i )
		res //= i
	return res
def NoofSequences ( N , M ) :
	prime = { }
	for i in range ( 2 , int ( M ** ( .5 ) ) + 1 ) :
		while ( M % i == 0 ) :
			prime [ i ] = prime . get ( i , 0 ) + 1
			M //= i
	if ( M > 1 ) :
		prime [ M ] = prime . get ( M , 0 ) + 1
	ans = 1
	for it in prime :
		ans *= ( ncr ( N + prime [ it ] - 1 , N - 1 ) )
	return ans
N = 2
M = 6
print ( NoofSequences ( N , M ) )