human
Check if all disks can be placed at a single rod based on given conditions | Function to check if it is possible to move all disks to a single rod.
Stores if it is possible to move all disks to a single rod.
Traverse the array.
If i - th element is smaller than both its adjacent elements.
If flag is true.
Otherwise.
Driver Code"
Solution in Python:
 ... What is a code to check if all disks can be placed at a single rod based on given conditions and the other steps required?
assistant
#Here is code to check if all disks can be placed at a single rod based on given conditions and the other steps required.
 def check ( a , n ) :
	flag = 0
	for i in range ( 1 , n - 1 ) :
		if ( a [ i + 1 ] > a [ i ] and a [ i ] < a [ i - 1 ] ) :
			flag = 1
	if ( flag != 0 ) :
		return False
	else :
		return True
arr = [ 1 , 3 , 5 , 2 ]
N = len ( arr )
if ( check ( arr , N ) != 0 ) :
	print ( " YES " )
else :
	print ( " NO " )