human
Write me a Python program to find this number! given the following:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons: 

  * Tetrahedron. Tetrahedron has 4 triangular faces. 
  * Cube. Cube has 6 square faces. 
  * Octahedron. Octahedron has 8 triangular faces. 
  * Dodecahedron. Dodecahedron has 12 pentagonal faces. 
  * Icosahedron. Icosahedron has 20 triangular faces. 


All five kinds of polyhedrons are shown on the picture below:


Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!

Input

The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton's collection.

Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton's collection. The string can look like this:

  * "Tetrahedron" (without quotes), if the i-th polyhedron in Anton's collection is a tetrahedron. 
  * "Cube" (without quotes), if the i-th polyhedron in Anton's collection is a cube. 
  * "Octahedron" (without quotes), if the i-th polyhedron in Anton's collection is an octahedron. 
  * "Dodecahedron" (without quotes), if the i-th polyhedron in Anton's collection is a dodecahedron. 
  * "Icosahedron" (without quotes), if the i-th polyhedron in Anton's collection is an icosahedron. 

Output

Output one number — the total number of faces in all the polyhedrons in Anton's collection.

Examples

Input

4
Icosahedron
Cube
Tetrahedron
Dodecahedron

Output

42

Input

3
Dodecahedron
Octahedron
Octahedron

Output

28

Note

In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces.
assistant
#Here is Python program to find this number!
.

n=int(input())
m = list(range(n))
for i in range(n):
    m[i] = input()
arr = {}
arr["Tetrahedron"]=4
arr["Cube"]=6
arr["Octahedron"]=8
arr["Dodecahedron"]=12
arr["Icosahedron"]=20
# def triangularFaces(str):
#     if(str=="Tetrahedron"): return 4
#     elif(str=="Cube"): return 6
#     elif(str=="Octahedron"): return 8
#     elif(str=="Dodecahedron"): return 12
#     elif(str=="Icosahedron"): return 20
sum = 0
for i in range(len(m)):
    sum = sum + arr[m[i]]
print(sum)