human
Can you provide a the Python code you requested given the following:
Complete the below
def disjoint_set_label(i, n, simplify=False):

    ''''Return a html formated label for a disjoint set indexed by `i`.'
    '''
assistant
#Here is the Python code you requested.
    intersection = unicodedata.lookup('INTERSECTION')
    comp = 'c'
    def label_for_index(i):
        return chr((ord('A') + i))
    if simplify:
        return ''.join((label_for_index(i) for (i, b) in enumerate(setkey(i, n)) if b))
    else:
        return intersection.join(((label_for_index(i) + ('' if b else (('<sup>' + comp) + '</sup>'))) for (i, b) in enumerate(setkey(i, n))))