human
Find the convex hull of a given set of points P. In other words, find the smallest convex polygon containing all the points of P. Here, in a convex polygon, all interior angles are less than or equal to 180 degrees.

Please note that you should find all the points of P on both corner and boundary of the convex polygon.

Constraints

* 3 ≤ n ≤ 100000
* -10000 ≤ xi, yi ≤ 10000
* No point in the P will occur more than once.

Input

n
x1 y1
x2 y2
:
xn yn

The first integer n is the number of points in P. The coordinate of the i-th point pi is given by two integers xi and yi.

Output

In the first line, print the number of points on the corner/boundary of the convex polygon. In the following lines, print x y coordinates of the set of points. The coordinates should be given in the order of counter-clockwise visit of them starting from the point in P with the minimum y-coordinate, or the leftmost such point in case of a tie.

Examples

Input

7
2 1
0 0
1 2
2 2
4 2
1 3
3 3

Output

5
0 0
2 1
4 2
3 3
1 3

Input

4
0 0
2 2
0 2
0 1

Output

4
0 0
2 2
0 2
0 1
The above is tricky. Write me a correct solution in PYTHON3.
 Give me a Python program to find the convex hull of a given set of points P?
assistant
#Here is Python program to find the convex hull of a given set of points P.

import sys
from operator import itemgetter, attrgetter
from itertools import starmap
import cmath
from math import isinf, sqrt, acos, atan2
readline = sys.stdin.readline
EPS = 1e-9
ONLINE_FRONT = -2
CLOCKWISE = -1
ON_SEGMENT = 0
COUNTER_CLOCKWISE = 1
ONLINE_BACK = 2
class Circle(object):
    __slots__ = ('c', 'r')
    def __init__(self, c, r):
        self.c = c
        self.r = r
class Segment(object):
    __slots__ = ('fi', 'se')
    def __init__(self, fi, se):
        self.fi = fi
        self.se = se
Line = Segment
def cross(a, b):
    return a.real * b.imag - a.imag * b.real
def dot(a, b):
    return a.real * b.real + a.imag * b.imag
def norm(base):
    return abs(base) ** 2
def project(s, p2):
    base = s.fi - s.se
    r = dot(p2 - s.fi, base) / norm(base)
    return s.fi + base * r
def reflect(s, p):
    return p + (project(s, p) - p) * 2.0
def ccw(p1, p2, p3):
    a = p2 - p1
    b = p3 - p1
    if cross(a, b) > EPS: return 1
    if cross(a, b) < -EPS: return -1
    if dot(a, b) < -EPS: return 2
    if norm(a) < norm(b): return -2
    return 0
def intersect4(p1, p2, p3, p4):
    return (ccw(p1, p2, p3) * ccw(p1, p2, p4) <= 0 and
			ccw(p3, p4, p1) * ccw(p3, p4, p2) <= 0)
def intersect2(s1, s2):
    return intersect4(s1.fi, s1.se, s2.fi, s2.se)
def getDistance(a, b):  return abs(a - b)
def getDistanceLP(l, p):
    return abs(cross(l.se - l.fi, p - l.fi) / abs(l.se - l.fi))
def getDistanceSP(s, p):
    if dot(s.se - s.fi, p - s.fi) < 0.0: return abs(p - s.fi)
    if dot(s.fi - s.se, p - s.se) < 0.0: return abs(p - s.se)
    return getDistanceLP(s, p)
def getDistances(s1, s2):
    if intersect2(s1, s2): return 0.0
    return min(getDistanceSP(s1, s2.fi), getDistanceSP(s1, s2.se),
               getDistanceSP(s2, s1.fi), getDistanceSP(s2, s1.se))
def getCrossPoint(s1, s2):
	base = s2.se - s2.fi
	d1 = abs(cross(base, s1.fi - s2.fi))
	d2 = abs(cross(base, s1.se - s2.fi))
	t = d1 / (d1 + d2)
	return s1.fi + (s1.se - s1.fi) * t
def getCrossPointsCL(c, l):
    pr = project(l, c.c)
    e = (l.se - l.fi) /...