human
Finding a Non Transitive Co | Function to return gcd of a and b.
function to check for gcd.
a and b are coprime if their gcd is 1..
Checks if any possible triplet ( a , b , c ) satifying the condition that ( a , b ) is coprime , ( b , c ) is coprime but ( a , c ) isnt.
Generate and check for all possible triplets between L and R.
if we find any such triplets set flag to true.
flag = True indicates that a pair exists between L and R.
finding possible Triplet between 2 and 10.
finding possible Triplet between 23 and 46"
Solution in Python:
assistant
#Here is code to finding a Non Transitive Co and the other steps required.
 def gcd ( a , b ) :
	if ( a == 0 ) :
		return b ;
	return gcd ( b % a , a ) ;
def coprime ( a , b ) :
	return ( gcd ( a , b ) == 1 ) ;
def possibleTripletInRange ( L , R ) :
	flag = False ;
	possibleA = 0 ;
	possibleB = 0 ;
	possibleC = 0 ;
	for a in range ( L , R + 1 ) :
		for b in range ( a + 1 , R + 1 ) :
			for c in range ( b + 1 , R + 1 ) :
				if ( coprime ( a , b ) and coprime ( b , c ) and coprime ( a , c ) == False ) :
					flag = True ;
					possibleA = a ;
					possibleB = b ;
					possibleC = c ;
					break ;
	if ( flag == True ) :
		print ( " ( " , possibleA , " , " , possibleB , " , " , possibleC , " ) ▁ is ▁ one ▁ such " , " possible ▁ triplet ▁ between " , L , " and " , R ) ;
	else :
		print ( " No ▁ Such ▁ Triplet ▁ exists ▁ between " , L , " and " , R ) ;
L = 2 ;
R = 10 ;
possibleTripletInRange ( L , R ) ;
L = 23 ;
R = 46 ;
possibleTripletInRange ( L , R ) ;