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Count of palindromic strings of size upto N consisting of first K alphabets occurring at most twice | Function of return the number of palindromic strings of length N with first K alphabets possible.
If N is odd , half + 1 position can be filled to cope with the extra middle element.
K is reduced by one , because count of choices for the next position is reduced by 1 as a element can only once.
Return the possible count.
Function to find the count of palindromic string of first K characters according to the given criteria.
If N = 1 , then only K palindromic strings possible ..
If N = 2 , the 2 * K palindromic strings possible , K for N = 1 and K for N = 2.
Initialize ans with the count of strings possible till N = 2.
Return the possible count.
Driver Code"
Solution in Python:

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Write me a code to count of palindromic strings of size upto N consisting of first K alphabets occurring at most twice and the other steps required?
assistant
#Here is code to count of palindromic strings of size upto N consisting of first K alphabets occurring at most twice and the other steps required.
 def lengthNPalindrome ( N , K ) :
	half = N // 2 ;
	if ( N & 1 ) :
		half += 1 ;
	ans = 1 ;
	for i in range ( 1 , half + 1 ) :
		ans *= K ;
		K -= 1 ;
	return ans ;
def palindromicStrings ( N , K ) :
	if ( N == 1 ) :
		return K ;
	if ( N == 2 ) :
		return 2 * K ;
	ans = 0 ;
	ans += ( 2 * K ) ;
	for i in range ( 3 , N + 1 ) :
		ans += lengthNPalindrome ( i , K ) ;
	return ans ;
if __name__ == " _ _ main _ _ " :
	N = 4 ; K = 3 ;
	print ( palindromicStrings ( N , K ) ) ;