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Check if permutation of a given string can be made palindromic by removing at most K characters | Function to check if the satisfies the given conditions or not.
Stores length of given string.
Stores frequency of each character of str.
Update frequency of current character.
Stores count of distinct character whose frequency is odd.
Traverse the cntFreq [ ] array ..
If frequency of character i is odd.
Update cntOddFreq.
If count of distinct character having odd frequency is <= K + 1.
Driver Code.
If str satisfy the given conditions"
Solution in Python:
assistant
#Here is code to check if permutation of a given string can be made palindromic by removing at most K characters and the other steps required.
 def checkPalinK ( str , K ) :
	N = len ( str )
	cntFreq = [ 0 ] * 256
	for i in range ( N ) :
		cntFreq [ ord ( str [ i ] ) ] += 1
	cntOddFreq = 0
	for i in range ( 256 ) :
		if ( cntFreq [ i ] % 2 == 1 ) :
			cntOddFreq += 1
	if ( cntOddFreq <= ( K + 1 ) ) :
		return True
	return False
if __name__ == ' _ _ main _ _ ' :
	str = " geeksforgeeks "
	K = 2
	if ( checkPalinK ( str , K ) ) :
		print ( " Yes " )
	else :
		print ( " No " )