human
Count of permutations of an Array having each element as a multiple or a factor of its index | Function to find the count of desired permutations.
Base case.
If i has not been inserted.
Backtrack.
Insert i.
Recur to find valid permutations.
Remove i.
Return the final count.
Driver Code"
How can the above be solved in Python?

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Give me a code to count of permutations of an Array having each element as a multiple or a factor of its index and the other steps required?
assistant
#Here is code to count of permutations of an Array having each element as a multiple or a factor of its index and the other steps required.
 def findPermutation ( arr , N ) :
	pos = len ( arr ) + 1
	if ( pos > N ) :
		return 1
	res = 0
	for i in range ( 1 , N + 1 ) :
		if ( i not in arr ) :
			if ( i % pos == 0 or pos % i == 0 ) :
				arr . add ( i )
				res += findPermutation ( arr , N )
				arr . remove ( i )
	return res
N = 5
arr = set ( )
print ( findPermutation ( arr , N ) )