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Smallest pair of indices with product of subarray co | Function to calculate GCD of two integers.
Recursively calculate GCD.
Function to find the lexicographically smallest pair of indices whose product is co - prime with the product of the subarrays on its left and right.
Stores the suffix product of array elements.
Set 0 / 1 if pair satisfies the given condition or not.
Initialize array right_prod.
Update the suffix product.
Stores product of all elements.
Stores the product of subarray in between the pair of indices.
Iterate through every pair of indices ( i , j ).
Store product of A [ i , j ].
Check if product is co - prime to product of either the left or right subarrays.
If no such pair is found , then pr - 1.
Driver Code.
Function Call"
How can the above be solved in Python?
 Can you provide a code to smallest pair of indices with product of subarray co and the other steps required?
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#Here is code to smallest pair of indices with product of subarray co and the other steps required.
 def gcd ( a , b ) :
	if ( b == 0 ) :
		return a
	return gcd ( b , a % b )
def findPair ( A , N ) :
	right_prod = [ 0 ] * N
	flag = 0
	right_prod [ N - 1 ] = A [ N - 1 ]
	for i in range ( N - 2 , 0 , - 1 ) :
		right_prod [ i ] = right_prod [ i + 1 ] * A [ i ]
	total_prod = right_prod [ 0 ]
	product = 1
	for i in range ( 1 , N - 1 ) :
		product = 1
		for j in range ( i , N - 1 ) :
			product *= A [ j ]
			if ( gcd ( product , right_prod [ j + 1 ] ) == 1 or gcd ( product , total_prod / right_prod [ i ] ) == 1 ) :
				flag = 1
				print ( " ( " , ( i - 1 ) , " , ▁ " , ( j + 1 ) , " ) " )
				break
		if ( flag == 1 ) :
			break
	if ( flag == 0 ) :
		print ( - 1 )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 4 , 1 , 3 , 7 ]
	N = len ( arr )
	findPair ( arr , N )