human
Solve the following python programming problem given the following code:
@ _auth_return_future 
def friendfeed_request(self, path, callback, access_token = None, post_args = None, **args) : 
    'Fetches the given relative API path, e.g., "/bret/friends"

        If the request is a POST, ``post_args`` should be provided. Query
        string arguments should be given as keyword arguments.

        All the FriendFeed methods are documented at
        http://friendfeed.com/api/documentation.

        Many methods require an OAuth access token which you can
        obtain through `~OAuthMixin.authorize_redirect` and
        `~OAuthMixin.get_authenticated_user`. The user returned
        through that process includes an ``access_token`` attribute that
        can be used to make authenticated requests via this
        method.

        Example usage::

            class MainHandler(tornado.web.RequestHandler,
                              tornado.auth.FriendFeedMixin):
                @tornado.web.authenticated
                @tornado.web.asynchronous
                @tornado.gen.coroutine
                def get(self):
                    new_entry = yield self.friendfeed_request(
                        "/entry",
                        post_args={"body": "Testing Tornado Web Server"},
                        access_token=self.current_user["access_token"])

                    if not new_entry:
                        # Call failed.
perhaps missing permission?
                        yield self.authorize_redirect()
                        return
                    self.finish("Posted a message!")

        ' 
    url = ('http://friendfeed-api.com/v2' + path) 
    if access_token : 
        all_args = { 
            
} 
        all_args.update (args) 
        all_args.update ((post_args or { 
            
})) 
        method = ('POST' if (post_args is not None) else 'GET') 
        oauth = self._oauth_request_parameters (url, access_token, all_args, method = method) 
        args.update (oauth) 
if args : 
        url += ('?' + urllib_parse.urlencode (args)) 
callback =...

    
    

    Fix the buggy line: http.fetch (url, method = 'POST', body = urllib_parse.urlencode (args), callback = callback)
assistant
#Here is Python program to fix the buggy line: http.

http.fetch (url, method = 'POST', body = urllib_parse.urlencode (post_args), callback = callback)