human
Check if an Array is made up of Subarrays of continuous repetitions of every distinct element | Function to check if the array is made up of subarrays of repetitions.
Base Case.
Stores the size of current subarray.
If a different element is encountered.
If the previous subarray was a single element.
Reset to new subarray.
Increase size of subarray.
If last element differed from the second last element.
Driver code"
Solution in Python:
 ... What is a code to check if an Array is made up of Subarrays of continuous repetitions of every distinct element and the other steps required?
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#Here is code to check if an Array is made up of Subarrays of continuous repetitions of every distinct element and the other steps required.
 def ContinuousElements ( a , n ) :
	if ( n == 1 ) :
		return False
	curr = 1
	for i in range ( 1 , n ) :
		if ( a [ i ] != a [ i - 1 ] ) :
		if ( curr == 1 ) :
			return False
		else :
			curr = 0
			curr += 1
			if ( curr == 1 ) :
			return False
			return True
if __name__ == " _ _ main _ _ " :
	a = [ 1 , 1 , 2 , 2 , 1 , 3 , 3 ]
	n = len ( a )
	if ( ContinuousElements ( a , n ) ) :
		print ( " Yes " )
	else :
		print ( " No " )