human
Count set bits in the Kth number after segregating even and odd from N natural numbers | Function to return the kth element of the Odd - Even sequence of length n.
Finding the index from where the even numbers will be stored.
Return the kth element.
Function to return the count of set bits in the kth number of the odd even sequence of length n.
Required kth number.
Return the count of set bits.
Driver code"
Solution in Python:
 ... Give me a code to count set bits in the Kth number after segregating even and odd from N natural numbers and the other steps required?
assistant
#Here is code to count set bits in the Kth number after segregating even and odd from N natural numbers and the other steps required.
 def findK ( n , k ) :
	if ( n % 2 == 0 ) :
		pos = n // 2 ;
	else :
		pos = ( n // 2 ) + 1 ;
	if ( k <= pos ) :
		return ( k * 2 - 1 ) ;
	else :
		return ( ( k - pos ) * 2 ) ;
def countSetBits ( n , k ) :
	kth = findK ( n , k ) ;
	return bin ( kth ) . count ( '1' ) ;
if __name__ == " _ _ main _ _ " :
	n = 18 ; k = 12 ;
	print ( countSetBits ( n , k ) ) ;