human
Solve the following python programming problem given the following code:
@ staticmethod 
def _preprocess(input) : 
    'Revise wording to match canonical and expected forms.' 
    input = re.sub ('(\\b)a(\\b)', '\\g<1>one\\g<2>', input) 
    input = re.sub ('to the (.*) power', 'to \\g<1>', findImplicitMultiplications) 
    input = re.sub ('to the (.*?)(\\b)', 'to \\g<1>\\g<2>', input) 
    input = re.sub ('log of', 'log', input) 
    input = re.sub ('(square)?root(of)?', 'sqrt', input) 
    input = re.sub ('squared', 'to two', input) 
    input = re.sub ('cubed', 'to three', input) 
    input = re.sub ('divided?(by)?', 'divide', input) 
    input = re.sub ('(\\b)over(\\b)', '\\g<1>divide\\g<2>', input) 
    input = re.sub ('(\\b)EE(\\b)', '\\g<1>e\\g<2>', input) 
    input = re.sub ('(\\b)E(\\b)', '\\g<1>e\\g<2>', input) 
    input = re.sub ('(\\b)pie(\\b)', '\\g<1>pi\\g<2>', input) 
    input = re.sub ('(\\b)PI(\\b)', '\\g<1>pi\\g<2>', input) 
    def findImplicitMultiplications(input) : 
        "Replace omitted 'times' references." 
        def findConstantMultiplications(input) : 
            split = input.split (' ') 
            revision = '' 
            converter = NumberService () 
            for (i, w) in enumerate (split) : 
                if ((i > 0) and (w in MathService.__constants__)) : 
                    if converter.isValid (split [(i - 1)]) : 
                        revision += ' times' 
if (not revision) : 
                    revision = w 
else : 
                    revision += (' ' + w) 
return revision 
def findUnaryMultiplications(input) : 
            split = input.split (' ') 
            revision = '' 
            for (i, w) in enumerate (split) : 
                if ((i > 0) and (w in MathService.__unaryOperators__)) : 
                    last_op = split [(i - 1)] 
                    binary = (last_op in MathService.__binaryOperators__) 
                    unary = (last_op in MathService.__unaryOperators__) 
                    if (last_op and (not (binary or unary))) : 
                        revision += ' times' 
if (not revision) : 
      ...

    
    

    Fix the buggy line: input = re.sub ('to the (.*) power', 'to \\g<1>', findImplicitMultiplications)
assistant
#Here is Python program to fix the buggy line: input = re.

input = re.sub ('to the (.*) power', 'to \\g<1>', input)