human
Write me a code to set all even bits of a number and the other steps required given the following:
Set all even bits of a number | return msb set number.
set all bits.
return msb increment n by 1 and shift by 1.
return even seted number.
get msb here.
generate even bits like 101010. ..
if bits is odd then shift by 1.
return even set bits number.
set all even bits here.
take or with even set bits number ;"
How can the above be solved in Python?
assistant
#Here is code to set all even bits of a number and the other steps required.
 def getmsb ( n ) :
	n |= n >> 1
	n |= n >> 2
	n |= n >> 4
	n |= n >> 8
	n |= n >> 16
	return ( n + 1 ) >> 1
def getevenbits ( n ) :
	n = getmsb ( n )
	n |= n >> 2
	n |= n >> 4
	n |= n >> 8
	n |= n >> 16
	if ( n & 1 ) :
		n = n >> 1
	return n
def setallevenbits ( n ) :
	return n | getevenbits ( n )
/ * Driver code * /
n = 10
print ( setallevenbits ( n ) )