human
I found an interesting problem on https://leetcode.com/problems/minimize-malware-spread/:
In a network of nodes, each node i is directly connected to another node j if and only if graph[i][j] = 1.
Some nodes initial are initially infected by malware.  Whenever two nodes are directly connected and at least one of those two nodes is infected by malware, both nodes will be infected by malware.  This spread of malware will continue until no more nodes can be infected in this manner.
Suppose M(initial) is the final number of nodes infected with malware in the entire network, after the spread of malware stops.
We will remove one node from the initial list.  Return the node that if removed, would minimize M(initial).  If multiple nodes could be removed to minimize M(initial), return such a node with the smallest index.
Note that if a node was removed from the initial list of infected nodes, it may still be infected later as a result of the malware spread.
 

Example 1:
Input: graph = [[1,1,0],[1,1,0],[0,0,1]], initial = [0,1]
Output: 0

Example 2:
Input: graph = [[1,0,0],[0,1,0],[0,0,1]], initial = [0,2]
Output: 0

Example 3:
Input: graph = [[1,1,1],[1,1,1],[1,1,1]], initial = [1,2]
Output: 1

 
Note:

1 < graph.length = graph[0].length <= 300
0 <= graph[i][j] == graph[j][i] <= 1
graph[i][i] == 1
1 <= initial.length <= graph.length
0 <= initial[i] < graph.length

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python program you requested.

class Solution(object):
    def minMalwareSpread(self, graph, initial):
        def dfs(node, visited):
            for neighbor in range(len(graph[node])):
                if graph[node][neighbor] == 1 and neighbor not in visited:
                    visited.add(neighbor)
                    dfs(neighbor, visited)
        
        res, max_size = min(initial), 0
        i_set = set(initial)
        total_visited = set()
        for node in range(len(graph)):
            if node not in total_visited:
                visited = {node}
                dfs(node, visited)
                infected = visited & i_set
                if len(infected) == 1:
                    if len(visited) > max_size or (len(visited) == max_size and list(infected)[0] < res):
                        res = list(infected)[0]
                        max_size = len(visited)
                total_visited |= visited
        return res