human
Solve in Python:
Given a set of N people (numbered 1, 2, ..., N), we would like to split everyone into two groups of any size.
Each person may dislike some other people, and they should not go into the same group. 
Formally, if dislikes[i] = [a, b], it means it is not allowed to put the people numbered a and b into the same group.
Return true if and only if it is possible to split everyone into two groups in this way.
 





Example 1:
Input: N = 4, dislikes = [[1,2],[1,3],[2,4]]
Output: true
Explanation: group1 [1,4], group2 [2,3]

Example 2:
Input: N = 3, dislikes = [[1,2],[1,3],[2,3]]
Output: false

Example 3:
Input: N = 5, dislikes = [[1,2],[2,3],[3,4],[4,5],[1,5]]
Output: false



 
Constraints:

1 <= N <= 2000
0 <= dislikes.length <= 10000
dislikes[i].length == 2
1 <= dislikes[i][j] <= N
dislikes[i][0] < dislikes[i][1]
There does not exist i != j for which dislikes[i] == dislikes[j].
assistant
#Here is the Python program you requested.

from collections import defaultdict
class Solution:
    def possibleBipartition(self, N: int, dislikes: List[List[int]]) -> bool:
        
        graph = defaultdict(list)
        
        for _from, to in dislikes:
            graph[_from].append(to)
            graph[to].append(_from)
            
        colors = {}
        
        for i in range(1,N+1):
            if i not in colors and i <= len(graph)-1:
                stack = [(i, True)]
                
                while stack:
                    keys, color = stack.pop()
                    colors[keys] = color
                    
                    for adj in graph[keys]:
                        if adj in colors:
                            if colors[adj] == colors[keys]:

                                return False
                        else:
                            stack.append((adj, not colors[keys]))
        return all([colors[i] != all(colors[j] for j in graph[i]) for i in colors if graph[i]!=[]])