human
I wrote the below code

    def combine(c1, c2):
        'Return    the    tuple    (a,    m)    which    satisfies    the    requirement\n                                that    n    =    a    +    i*m    satisfy    n    =    a1    +    j*m1    and    n    =    a2    =    k*m2.\n\n                                References\n                                ==========\n\n                                -    http://en.wikipedia.org/wiki/Method_of_successive_substitution\n                                '
        (a1, m1) = c1
        (a2, m2) = c2
        (a, b, c) = (m1, (a2 - a1), m2)
        g = reduce(igcd, [a, b, c])
        (a, b, c) = [(i // g) for i in [a, b, c]]
        if (a != 1):
            (inv_a, _, g) = igcdex(a, c)
            if (g != 1):
                return None
            b *= inv_a
        (a, m) = ((a1 + (m1 * b)), (m1 * c))
        return (a, m)
    rm = remainder_modulus_pairs
    symmetric = hint.get('symmetric', False)
    if hint.get('check', True):
        rm = [(as_int(r), as_int(m)) for (r, m) in rm]
        uniq = {}
        for (r, m) in rm:
            r %= m
            if (m in uniq):
                if (r != uniq[m]):
                    return None
                continue
            uniq[m] = r
        rm = [(r, m) for (m, r) in uniq.items()]
        del uniq
        if all((isprime(m) for (r, m) in rm)):
            (r, m) = list(zip(*rm))
            return crt(m, r, symmetric=symmetric, check=False)
    rv = (0, 1)
    for rmi in rm:
        rv = combine(rv, rmi)
        if (rv is None):
            break
        (n, m) = rv
        n = (n % m)
    else:
        if symmetric:
            return (symmetric_residue(n, m), m)
        return (n, m)

What's a good function header?
 Here's a good function header?
assistant
#Here's a good function header.

def solve_congruence(*remainder_modulus_pairs, **hint):