human
Find minimum number of merge operations to make an array palindrome | Returns minimum number of count operations required to make arr [ ] palindrome.
Initialize result.
Start from two corners.
If corner elements are same , problem reduces arr [ i + 1. . j - 1 ].
If left element is greater , then we merge right two elements.
need to merge from tail ..
Else we merge left two elements.
Driver program to test above"
Solution in Python:

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Write me a code to find minimum number of merge operations to make an array palindrome and the other steps required?
assistant
#Here is code to find minimum number of merge operations to make an array palindrome and the other steps required.
 def findMinOps ( arr , n ) :
	ans = 0
	i , j = 0 , n - 1
	while i <= j :
		if arr [ i ] == arr [ j ] :
			i += 1
			j -= 1
		elif arr [ i ] > arr [ j ] :
			j -= 1
			arr [ j ] += arr [ j + 1 ]
			ans += 1
		else :
			i += 1
			arr [ i ] += arr [ i - 1 ]
			ans += 1
	return ans
arr = [ 1 , 4 , 5 , 9 , 1 ]
n = len ( arr )
print ( " Count ▁ of ▁ minimum ▁ operations ▁ is ▁ " + str ( findMinOps ( arr , n ) ) )