human
Maximize partitions such that no two substrings have any common character | Function to calculate and return the maximum number of partitions.
r : Stores the maximum number of partitions k : Stores the ending index of the partition.
Stores the last index of every unique character of the string.
Traverse the and store the last index of every character.
Store the last index of the first character from map.
Update K to find the end of partition.
Otherwise , the end of partition is found.
Increment r.
Update k for the next partition.
Add the last partition.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to maximize partitions such that no two substrings have any common character and the other steps required.
 def maximum_partition ( strr ) :
	i = 0
	j = 0
	k = 0
	c = 0
	r = 0
	m = { }
	for i in range ( len ( strr ) - 1 , - 1 , - 1 ) :
		if ( strr [ i ] not in m ) :
			m [ strr [ i ] ] = i
	i = 0
	k = m [ strr [ i ] ]
	for i in range ( len ( strr ) ) :
		if ( i <= k ) :
			c = c + 1
			k = max ( k , m [ strr [ i ] ] )
		else :
			r = r + 1
			c = 1
			k = max ( k , m [ strr [ i ] ] )
	if ( c != 0 ) :
		r = r + 1
	return r
if __name__ == ' _ _ main _ _ ' :
	strr = " ababcbacadefegdehijhklij "
	print ( maximum_partition ( strr ) )