human
Maximize sum of remaining elements after every removal of the array half with greater sum | Function to find the maximum sum.
Base Case.
Create a key to map the values.
Check if mapped key is found in the dictionary.
Traverse the array.
Store left prefix sum.
Store right prefix sum.
Compare the left and right values.
Store the value in dp array.
Return the final answer.
Function to print maximum sum.
Stores prefix sum.
Store results of subproblems.
Traversing the array.
Add prefix sum of array.
Print the answer.
Driver Code.
Function Call"
How can the above be solved in Python?

Can you provide a code to maximize sum of remaining elements after every removal of the array half with greater sum and the other steps required?
assistant
#Here is code to maximize sum of remaining elements after every removal of the array half with greater sum and the other steps required.
 def maxweight ( s , e , pre , dp ) :
	if s == e :
		return 0
	key = ( s , e )
	if key in dp :
		return dp [ key ]
	ans = 0
	for i in range ( s , e ) :
		left = pre [ i ] - pre [ s - 1 ]
		right = pre [ e ] - pre [ i ]
		if left < right :
			ans = max ( ans , left + maxweight ( s , i , pre , dp ) )
		if left == right :
			ans = max ( ans , left + maxweight ( s , i , pre , dp ) , right + maxweight ( i + 1 , e , pre , dp ) )
		if left > right :
		ans = max ( ans , right + maxweight ( i + 1 , e , pre , dp ) )
		dp [ key ] = ans
	return dp [ key ]
def maxSum ( arr ) :
	pre = { - 1 : 0 , 0 : arr [ 0 ] }
	dp = { }
	for i in range ( 1 , len ( arr ) ) :
		pre [ i ] = pre [ i - 1 ] + arr [ i ]
	print ( maxweight ( 0 , len ( arr ) - 1 , pre , dp ) )
arr = [ 6 , 2 , 3 , 4 , 5 , 5 ]
maxSum ( arr )