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Count ways to remove objects such that exactly M equidistant objects remain | Function to count the number of ways of removing objects such that after removal , exactly M equidistant objects remain.
Store the resultant number of arrangements.
Base Case : When only 1 object is left.
Print the result and return.
Iterate until len <= n and increment the distance in each iteration.
Total length if adjacent objects are d distance apart.
If length > n.
Update the number of ways.
Print the result.
Driver Code"
Solution in Python:
assistant
#Here is code to count ways to remove objects such that exactly M equidistant objects remain and the other steps required.
 def waysToRemove ( n , m ) :
	ans = 0
	if ( m == 1 ) :
		print ( n )
		return
	d = 0
	while d >= 0 :
		length = m + ( m - 1 ) * d
		if ( length > n ) :
			break
		ans += ( n - length ) + 1
		d += 1
	print ( ans )
if __name__ == " _ _ main _ _ " :
	N = 5
	M = 3
	waysToRemove ( N , M )