human
Count of all values of N in [ L , R ] such that count of primes upto N is also prime | Function to count the number of crazy primes in the given range [ L , R ].
Stores all primes.
Stores count of primes.
Stores if frequency of primes is a prime or not upto each index.
Sieve of Eratosthenes.
Count primes.
If i is a prime.
Stores frequency of primes.
If the frequency of primes is a prime.
Increase count of required numbers.
Return the required count.
Driver Code.
Given Range.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to count of all values of N in [ L , R ] such that count of primes upto N is also prime and the other steps required.
 def count_crazy_primes ( L , R ) :
	prime = [ 0 ] * ( R + 1 )
	countPrime = [ 0 ] * ( R + 1 )
	freqPrime = [ 0 ] * ( R + 1 )
	prime [ 0 ] = prime [ 1 ] = 1
	p = 2
	while p * p <= R :
		if ( prime [ p ] == 0 ) :
			for i in range ( p * p , R + 1 , p ) :
				prime [ i ] = 1
		p += 1
	for i in range ( 1 , R + 1 ) :
		countPrime [ i ] = countPrime [ i - 1 ]
		if ( not prime [ i ] ) :
			countPrime [ i ] += 1
	for i in range ( 1 , R + 1 ) :
		freqPrime [ i ] = freqPrime [ i - 1 ]
		if ( not prime [ countPrime [ i ] ] ) :
			freqPrime [ i ] += 1
	return ( freqPrime [ R ] - freqPrime [ L - 1 ] )
if __name__ == " _ _ main _ _ " :
	L = 4
	R = 12
	print ( count_crazy_primes ( L , R ) )