human
Minimum number of flips with rotation to make binary string alternating | Function that finds the minimum number of flips to make the binary string alternating if left circular rotation is allowed.
Initialize prefix arrays to store number of changes required to put 1 s at either even or odd position.
If i is odd.
Update the oddone and evenone count.
Else i is even.
Update the oddone and evenone count.
Initialize minimum flips.
Check if substring [ 0 , i ] is appended at end how many changes will be required.
Return minimum flips.
Given String.
Length of given string.
Function call"
How can the above be solved in Python?
assistant
#Here is code to minimum number of flips with rotation to make binary string alternating and the other steps required.
 def MinimumFlips ( s , n ) :
	a = [ 0 ] * n
	for i in range ( n ) :
		a [ i ] = 1 if s [ i ] == '1' else 0
	oddone = [ 0 ] * ( n + 1 )
	evenone = [ 0 ] * ( n + 1 )
	for i in range ( n ) :
		if ( i % 2 != 0 ) :
			if ( a [ i ] == 1 ) :
				oddone [ i + 1 ] = oddone [ i ] + 1
			else :
				oddone [ i + 1 ] = oddone [ i ] + 0
			if ( a [ i ] == 0 ) :
				evenone [ i + 1 ] = evenone [ i ] + 1
			else :
				evenone [ i + 1 ] = evenone [ i ] + 0
		else :
			if ( a [ i ] == 0 ) :
				oddone [ i + 1 ] = oddone [ i ] + 1
			else :
				oddone [ i + 1 ] = oddone [ i ] + 0
			if ( a [ i ] == 1 ) :
				evenone [ i + 1 ] = evenone [ i ] + 1
			else :
				evenone [ i + 1 ] = evenone [ i ] + 0
	minimum = min ( oddone [ n ] , evenone [ n ] )
	for i in range ( n ) :
		if ( n % 2 != 0 ) :
			minimum = min ( minimum , oddone [ n ] - oddone [ i + 1 ] + evenone [ i + 1 ] )
			minimum = min ( minimum , evenone [ n ] - evenone [ i + 1 ] + oddone [ i + 1 ] )
	return minimum
S = "000001100"
n = len ( S )
print ( MinimumFlips ( S , n ) )