human
What is a code to count the subarray with sum strictly greater than the sum of remaining elements and the other steps required given the following:
Count the subarray with sum strictly greater than the sum of remaining elements | Function to count the number of sub - arrays with sum strictly greater than the remaining elements of array.
For loop for beginning point of a subarray.
For loop for ending point of the subarray.
Initialise subarray_sum and remaining_sum to 0.
For loop to calculate the sum of generated subarray.
For loop to calculate the sum remaining array element.
Checking for condition when subarray sum is strictly greater than remaining sum of array element.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count the subarray with sum strictly greater than the sum of remaining elements and the other steps required.
 def Count_subarray ( arr , n ) :
	subarray_sum , remaining_sum , count = 0 , 0 , 0 ;
	for i in range ( n ) :
		for j in range ( i , n ) :
			subarray_sum = 0 ;
			remaining_sum = 0 ;
			for k in range ( i , j + 1 ) :
				subarray_sum += arr [ k ] ;
			for l in range ( i ) :
				remaining_sum += arr [ l ] ;
			for l in range ( j + 1 , n ) :
				remaining_sum += arr [ l ] ;
			if ( subarray_sum > remaining_sum ) :
				count += 1 ;
	return count ;
if __name__ == ' _ _ main _ _ ' :
	arr = [ 10 , 9 , 12 , 6 ] ;
	n = len ( arr ) ;
	print ( Count_subarray ( arr , n ) ) ;