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Count of all possible pairs having sum of LCM and GCD equal to N | Recursive function to return gcd of a and b.
Function to calculate and return LCM of two numbers.
Function to count pairs whose sum of GCD and LCM is equal to N.
Driver code"
Solution in Python:
 ... Can you provide a code to count of all possible pairs having sum of LCM and GCD equal to N and the other steps required?
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#Here is code to count of all possible pairs having sum of LCM and GCD equal to N and the other steps required.
 def __gcd ( a , b ) :
	if b == 0 :
		return a
	else :
		return __gcd ( b , a % b )
def lcm ( a , b ) :
	return ( a * b ) // __gcd ( a , b )
def countPair ( N ) :
	count = 0
	for i in range ( 1 , N + 1 ) :
		for j in range ( 1 , N + 1 ) :
			if ( __gcd ( i , j ) + lcm ( i , j ) == N ) :
				count += 1
	return count
if __name__ == " _ _ main _ _ " :
	N = 14
	print ( countPair ( N ) )