human
Can you provide a code to maximize count of indices with same element by pairing rows from given Matrices and the other steps required given the following:
Maximize count of indices with same element by pairing rows from given Matrices | Function to find the maximum defined score.
If all students are assigned.
Check if row is not paired yet.
Check for all indexes.
If values at current indexes are same increase curSum.
Further recursive call.
Store the ans for current mask and return.
Utility function to find the maximum defined score.
Create a mask with all set bits 1 -> row is not paired yet 0 -> row is already paired.
Initialise dp array with - 1.
Driver Code"
Solution in Python:
assistant
#Here is code to maximize count of indices with same element by pairing rows from given Matrices and the other steps required.
 def maxScoreSum ( a , b , row , mask , dp ) :
	if ( row >= len ( a ) ) :
		return 0
	if ( dp [ mask ] != - 1 ) :
		return dp [ mask ]
	ans = 0
	for i in range ( len ( a ) ) :
		if ( mask & ( 1 << i ) ) :
			newMask = mask ^ ( 1 << i )
			curSum = 0
			for j in range ( len ( a [ i ] ) ) :
				if ( a [ row ] [ j ] == b [ i ] [ j ] ) :
					curSum += 1
			ans = max ( ans , curSum + maxScoreSum ( a , b , row + 1 , newMask , dp ) )
	dp [ mask ] = ans
	return dp [ mask ]
def maxScoreSumUtil ( a , b , N , M ) :
	row = 0
	mask = pow ( 2 , M ) - 1
	dp = [ - 1 ] * ( mask + 1 )
	return maxScoreSum ( a , b , row , mask , dp )
if __name__ == " _ _ main _ _ " :
	N = 3
	M = 3
	a = [ [ 1 , 1 , 0 ] , [ 1 , 0 , 1 ] , [ 0 , 0 , 1 ] ]
	b = [ [ 1 , 0 , 0 ] , [ 0 , 0 , 1 ] , [ 1 , 1 , 0 ] ]
	print ( maxScoreSumUtil ( a , b , N , M ) )