human
Remainder with 7 for large numbers | Function which return Remainder after dividing the number by 7.
This series is used to find remainder with 7.
Index of next element in series.
Initialize result.
Traverse num from end.
Find current digit of num.
Add next term to result.
Move to next term in series.
Make sure that result never goes beyond 7..
Make sure that remainder is positive.
Driver Code"
How can the above be solved in Python?

What is a code to remainder with 7 for large numbers and the other steps required?
assistant
#Here is code to remainder with 7 for large numbers and the other steps required.
 def remainderWith7 ( num ) :
	series = [ 1 , 3 , 2 , - 1 , - 3 , - 2 ] ;
	series_index = 0 ;
	result = 0 ;
	for i in range ( ( len ( num ) - 1 ) , - 1 , - 1 ) :
		digit = ord ( num [ i ] ) - 48 ;
		result += digit * series [ series_index ] ;
		series_index = ( series_index + 1 ) % 6 ;
		result %= 7 ;
	if ( result < 0 ) :
		result = ( result + 7 ) % 7 ;
	return result ;
str = "12345" ;
print ( " Remainder ▁ with ▁ 7 ▁ is " , remainderWith7 ( str ) ) ;