human
XOR of elements in a given range with updates using Fenwick Tree | Returns XOR of arr [ 0. . index ] . This function assumes that the array is preprocessed and partial XORs of array elements are stored in BITree [ ] ..
Traverse ancestors of BITree [ index ].
XOR current element of BIT to ans.
Update index to that of the parent node in getXor ( ) view by subtracting LSB ( Least Significant Bit ).
Updates the Binary Index Tree by replacing all ancestors of index by their respective XOR with val.
Traverse all ancestors and XOR with ' val ' ..
XOR ' val ' to current node of BIT.
Update index to that of the parent node in updateBit ( ) view by adding LSB ( Least Significant Bit ).
Constructs and returns a Binary Indexed Tree for the given array.
Create and initialize the Binary Indexed Tree.
Store the actual values in BITree [ ] using update ( ).
Driver Code.
Create the Binary Indexed Tree.
Solve each query in Q.
Update the values of all ancestors of idx"
How can the above be solved in Python?
 Can you provide a code to xOR of elements in a given range with updates using Fenwick Tree and the other steps required?
assistant
#Here is code to xOR of elements in a given range with updates using Fenwick Tree and the other steps required.
 def getXOR ( BITree , index ) :
	ans = 0
	index += 1
	while ( index > 0 ) :
		ans ^= BITree [ index ]
		index -= index & ( - index )
	return ans
def updateBIT ( BITree , n , index , val ) :
	index = index + 1
	while ( index <= n ) :
		BITree [ index ] ^= val
		index += index & ( - index )
def constructBITree ( arr , n ) :
	BITree = [ 0 ] * ( n + 1 )
	for i in range ( n ) :
		updateBIT ( BITree , n , i , arr [ i ] )
	return BITree
def rangeXor ( BITree , l , r ) :
	return ( getXOR ( BITree , r ) ^ getXOR ( BITree , l - 1 ) )
if __name__ == " _ _ main _ _ " :
	A = [ 2 , 1 , 1 , 3 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ]
	n = len ( A )
	q = [ [ 1 , 0 , 9 ] , [ 2 , 3 , 6 ] , [ 2 , 5 , 5 ] , [ 2 , 8 , 1 ] , [ 1 , 0 , 9 ] ]
	BITree = constructBITree ( A , n )
	for i in range ( len ( q ) ) :
		id = q [ i ] [ 0 ]
		if ( id == 1 ) :
			L = q [ i ] [ 1 ]
			R = q [ i ] [ 2 ]
			print ( " XOR ▁ of ▁ elements ▁ in ▁ " " given ▁ range ▁ is ▁ " , rangeXor ( BITree , L , R ) )
		else :
			idx = q [ i ] [ 1 ]
			val = q [ i ] [ 2 ]
			A [ idx ] ^= val
			updateBIT ( BITree , n , idx , val )