human
Number of ordered points pair satisfying line equation | Checks if ( i , j ) is valid , a point ( i , j ) is valid if point ( arr [ i ] , arr [ j ] ) satisfies the equation y = mx + c And i is not equal to j.
check if i equals to j.
Equation LHS = y , and RHS = mx + c.
Returns the number of ordered pairs ( i , j ) for which point ( arr [ i ] , arr [ j ] ) satisfies the equation of the line y = mx + c.
for every possible ( i , j ) check if ( a [ i ] , a [ j ] ) satisfies the equation y = mx + c.
( firstIndex , secondIndex ) is same as ( i , j ).
check if ( firstIndex , secondIndex ) is a valid point.
Driver Code.
equation of line is y = mx + c"
How can the above be solved in Python?
 ... Can you provide a code to number of ordered points pair satisfying line equation and the other steps required?
assistant
#Here is code to number of ordered points pair satisfying line equation and the other steps required.
 def isValid ( arr , i , j , m , c ) :
	if ( i == j ) :
		return False
	lhs = arr [ j ] ;
	rhs = m * arr [ i ] + c
	return ( lhs == rhs )
def findOrderedPoints ( arr , n , m , c ) :
	counter = 0
	for i in range ( 0 , n ) :
		for j in range ( 0 , n ) :
			firstIndex = i
			secondIndex = j
			if ( isValid ( arr , firstIndex , secondIndex , m , c ) ) :
				counter = counter + 1
	return counter
arr = [ 1 , 2 , 3 , 4 , 2 ]
n = len ( arr )
m = 1
c = 1
print ( findOrderedPoints ( arr , n , m , c ) )