human
Longest Increasing Odd Even Subsequence | function to find the longest increasing odd even subsequence.
lioes [ i ] stores longest increasing odd even subsequence ending at arr [ i ].
to store the length of longest increasing odd even subsequence.
Initialize LIOES values for all indexes.
Compute optimized LIOES values in bottom up manner.
Pick maximum of all LIOES values.
required maximum length.
Driver to test above"
Solution in Python:

Can you provide a code to longest Increasing Odd Even Subsequence and the other steps required?
assistant
#Here is code to longest Increasing Odd Even Subsequence and the other steps required.
 def longOddEvenIncSeq ( arr , n ) :
	lioes = list ( )
	maxLen = 0
	for i in range ( n ) :
		lioes . append ( 1 )
	i = 1
	for i in range ( n ) :
		for j in range ( i ) :
			if ( arr [ i ] > arr [ j ] and ( arr [ i ] + arr [ j ] ) % 2 != 0 and lioes [ i ] < lioes [ j ] + 1 ) :
				lioes [ i ] = lioes [ j ] + 1
	for i in range ( n ) :
		if maxLen < lioes [ i ] :
			maxLen = lioes [ i ]
	return maxLen
arr = [ 1 , 12 , 2 , 22 , 5 , 30 , 31 , 14 , 17 , 11 ]
n = len ( arr )
print ( " Longest ▁ Increasing ▁ Odd ▁ Even ▁ " + " Subsequence : ▁ " , longOddEvenIncSeq ( arr , n ) )