human
Segregate 1 s and 0 s in separate halves of a Binary String | Function to count the minimum number of operations required to segregate all 1 s and 0 s in a binary string.
Stores the count of unequal pair of adjacent characters.
If an unequal pair of adjacent characters occurs.
For odd count.
For even count.
Given string.
Length of the string.
Prints the minimum count of operations required"
Solution in Python:
assistant
#Here is code to segregate 1 s and 0 s in separate halves of a Binary String and the other steps required.
 def minOps ( s , N ) :
	ans = 0
	for i in range ( 1 , N ) :
		if ( s [ i ] != s [ i - 1 ] ) :
			ans += 1
	if ( ans % 2 == 1 ) :
		print ( ( ans - 1 ) // 2 )
		return
	print ( ans // 2 )
str = "01011100"
N = len ( str )
minOps ( str , N )