human
Split an array into minimum number of non | Function to split the array into minimum count of subarrays such that each subarray is either non - increasing or non - decreasing.
Initialize variable to keep track of current sequence.
Stores the required result.
Traverse the array , arr [ ].
If current sequence is neither non - increasing nor non - decreasing.
If previous element is greater.
Update current.
If previous element is equal to the current element.
Update current.
Otherwise.
Update current.
If current sequence is in non - decreasing.
I f previous element is less than or equal to the current element.
Otherwise.
Update current as N and increment answer by 1.
If current sequence is Non - Increasing.
If previous element is greater or equal to the current element.
Otherwise.
Update current as N and increment answer by 1.
Print the answer.
Driver Code.
Given array.
Given size of array"
How can the above be solved in Python?
assistant
#Here is code to split an array into minimum number of non and the other steps required.
 def minimumSubarrays ( arr , n ) :
	current = ' N '
	answer = 1
	for i in range ( 1 , n ) :
		if ( current == ' N ' ) :
			if ( arr [ i ] < arr [ i - 1 ] ) :
				current = ' D '
			elif ( arr [ i ] == arr [ i - 1 ] ) :
				current = ' N '
			else :
				current = ' I '
		elif ( current == ' I ' ) :
			if ( arr [ i ] >= arr [ i - 1 ] ) :
				current = ' I '
			else :
				current = ' N '
				answer += 1
		else :
			if ( arr [ i ] <= arr [ i - 1 ] ) :
				current = ' D '
			else :
				current = ' N '
				answer += 1
	print ( answer )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 3 , 9 , 5 , 4 , 6 , 8 ]
	n = len ( arr )
	minimumSubarrays ( arr , n )