human
Minimum adjacent swaps to group similar characters together | Function to find minimum adjacent swaps required to make all the same character adjacent.
Initialize answer.
Create a 2D array of size 26.
Traverse the string.
Get character.
Append the current index in the corresponding vector.
Traverse each character from a to z.
Add difference of adjacent index.
Return answer.
Driver Code.
Given string.
Size of string.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to minimum adjacent swaps to group similar characters together and the other steps required.
 def minSwaps ( S , n ) :
	swaps = 0
	arr = [ [ ] for i in range ( 26 ) ]
	for i in range ( n ) :
		pos = ord ( S [ i ] ) - ord ( ' a ' )
		arr [ pos ] . append ( i )
	for ch in range ( ord ( ' a ' ) , ord ( ' z ' ) + 1 ) :
		pos = ch - ord ( ' a ' )
		for i in range ( 1 , len ( arr [ pos ] ) ) :
			swaps += abs ( arr [ pos ] [ i ] - arr [ pos ] [ i - 1 ] - 1 )
	return swaps
if __name__ == ' _ _ main _ _ ' :
	S = " abbccabbcc "
	N = len ( S )
	print ( minSwaps ( S , N ) )