human
Solve in Python:
Given a string text, we are allowed to swap two of the characters in the string. Find the length of the longest substring with repeated characters.
 
Example 1:
Input: text = "ababa"
Output: 3
Explanation: We can swap the first 'b' with the last 'a', or the last 'b' with the first 'a'. Then, the longest repeated character substring is "aaa", which its length is 3.

Example 2:
Input: text = "aaabaaa"
Output: 6
Explanation: Swap 'b' with the last 'a' (or the first 'a'), and we get longest repeated character substring "aaaaaa", which its length is 6.

Example 3:
Input: text = "aaabbaaa"
Output: 4

Example 4:
Input: text = "aaaaa"
Output: 5
Explanation: No need to swap, longest repeated character substring is "aaaaa", length is 5.

Example 5:
Input: text = "abcdef"
Output: 1

 
Constraints:

1 <= text.length <= 20000
text consist of lowercase English characters only.
assistant
#Here is Python program to find the length of the longest substring with repeated characters.

class Solution:
    def maxRepOpt1(self, text: str) -> int:
        letters = {}
        for i, char in enumerate(text):
            if char in letters:
                letters[char].append(i)
            else:
                letters[char] = [i]
        
        if len(letters) == 1:
            return len(text)
        
        ans = 0
        for letter in letters:
            cur = 0
            prev = 0 
            discarded = False
            maxSoFar = 0
            arr = letters[letter]
            for j, pos in enumerate(arr):
                if not j:
                    cur = 1
                elif pos - arr[j-1] == 1:
                    cur += 1
                else:
                    if not discarded and prev:
                        discarded = True
                    elif not discarded and pos - arr[j-1] > 2:
                        discarded = True

                    if prev + cur > maxSoFar:
                        maxSoFar = prev+cur
                    
                    if pos - arr[j-1] == 2:
                        prev = cur
                        cur = 1
                    else:
                        prev = 0
                        cur = 1
            print((prev+cur))        
            if prev + cur > maxSoFar:
                    maxSoFar = prev+cur
            if discarded:
                maxSoFar+=1
            if maxSoFar > ans:
                ans = maxSoFar
        
        return ans