human
Can you provide a code to minimum number of reversals to reach node 0 from every other node and the other steps required given the following:
Minimum number of reversals to reach node 0 from every other node | Function to find minimum reversals.
Add all adjacent nodes to the node in the graph.
Insert edges in the graph.
Insert edges in the reversed graph.
Create array visited to mark all the visited nodes.
Stores the number of edges to be reversed.
BFS Traversal.
Pop the current node from the queue.
mark the current node visited.
Intitialize count of edges need to be reversed to 0.
Push adjacent nodes in the reversed graph to the queue , if not visited.
Push adjacent nodes in graph to the queue , if not visited count the number of nodes added to the queue.
Update the reverse edge to the final count.
Return the result.
Driver Code.
Given edges to the graph.
Number of nodes.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to minimum number of reversals to reach node 0 from every other node and the other steps required.
 def minRev ( edges , n ) :
	graph = dict ( )
	graph_rev = dict ( )
	for i in range ( len ( edges ) ) :
		x = edges [ i ] [ 0 ] ;
		y = edges [ i ] [ 1 ] ;
		if x not in graph :
			graph [ x ] = [ ]
		graph [ x ] . append ( y ) ;
		if y not in graph_rev :
			graph_rev [ y ] = [ ]
		graph_rev [ y ] . append ( x ) ;
	q = [ ]
	visited = [ 0 for i in range ( n ) ]
	q . append ( 0 ) ;
	ans = 0 ;
	while ( len ( q ) != 0 ) :
		curr = q [ 0 ]
		visited [ curr ] = 1 ;
		count = 0 ;
		q . pop ( 0 ) ;
		if curr in graph_rev :
			for i in range ( len ( graph_rev [ curr ] ) ) :
				if ( not visited [ graph_rev [ curr ] [ i ] ] ) :
					q . append ( graph_rev [ curr ] [ i ] ) ;
		if curr in graph :
			for i in range ( len ( graph [ curr ] ) ) :
				if ( not visited [ graph [ curr ] [ i ] ] ) :
					q . append ( graph [ curr ] [ i ] ) ;
					count += 1
		ans += count ;
	return ans ;
if __name__ == ' _ _ main _ _ ' :
	edges = [ ]
	edges = [ [ 0 , 1 ] , [ 1 , 3 ] , [ 2 , 3 ] , [ 4 , 0 ] , [ 4 , 5 ] ] ;
	n = 6 ;
	print ( minRev ( edges , n ) )