human
Count Distinct Non | This function counts number of pairs ( x , y ) that satisfy the inequality x * x + y * y < n ..
Find the count of different y values for x = 0..
One by one increase value of x , and find yCount for current x . If yCount becomes 0 , then we have reached maximum possible value of x ..
Add yCount ( count of different possible values of y for current x ) to result.
Increment x.
Update yCount for current x . Keep reducing yCount while the inequality is not satisfied ..
Driver program to test above function"
How can the above be solved in Python?

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Give me a code to count Distinct Non and the other steps required?
assistant
#Here is code to count Distinct Non and the other steps required.
 def countSolutions ( n ) :
	x = 0
	res = 0
	yCount = 0
	while ( yCount * yCount < n ) :
		yCount = yCount + 1
	while ( yCount != 0 ) :
		res = res + yCount
		x = x + 1
		while ( yCount != 0 and ( x * x + ( yCount - 1 ) * ( yCount - 1 ) >= n ) ) :
			yCount = yCount - 1
	return res
print ( " Total ▁ Number ▁ of ▁ distinct ▁ " , , countSolutions ( 6 ) )