human
Count pairs of equal array elements remaining after every removal | Function to count pairs of equal elements by removing arr [ i ] from the array.
Stores total count of pairs of equal elements.
Store frequency of each distinct array element.
Traverse the array.
Update frequency of arr [ i ].
Traverse the map.
Stores key of an element.
Traverse the array.
Stores count of pairs of equal element by removing arr [ i ].
Driver Code.
Given Array"
How can the above be solved in Python?

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Can you provide a code to count pairs of equal array elements remaining after every removal and the other steps required?
assistant
#Here is code to count pairs of equal array elements remaining after every removal and the other steps required.
 def pairs_after_removing ( arr , N ) :
	cntPairs = 0
	mp = { }
	for i in arr :
		mp [ i ] = mp . get ( i , 0 ) + 1
	for element in mp :
		i = element
		cntPairs += mp [ i ] * ( mp [ i ] - 1 ) // 2
	for i in range ( N ) :
		pairs_after_arr_i_removed = cntPairs + 1 - mp [ arr [ i ] ]
		print ( pairs_after_arr_i_removed , end = ' ▁ ' )
	return
if __name__ == ' _ _ main _ _ ' :
	arr = [ 2 , 3 , 4 , 3 , 2 ]
	N = len ( arr )
	pairs_after_removing ( arr , N )