human
Find Largest Special Prime which is less than or equal to a given number | Function to check whether the number is a special prime or not.
While number is not equal to zero.
If the number is not prime return false ..
Else remove the last digit by dividing the number by 10..
If the number has become zero then the number is special prime , hence return true.
Function to find the Largest Special Prime which is less than or equal to a given number.
Initially all numbers are considered Primes ..
There is always an answer possible.
Checking if the number is a special prime or not.
If yes print the number and break the loop ..
Else decrement the number ..
Driver code"
Solution in Python:

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Can you provide a code to find Largest Special Prime which is less than or equal to a given number and the other steps required?
assistant
#Here is code to find Largest Special Prime which is less than or equal to a given number and the other steps required.
 def checkSpecialPrime ( sieve , num ) :
	while ( num ) :
		if ( not sieve [ num ] ) :
			return False
		num //= 10
	return True
def findSpecialPrime ( N ) :
	sieve = [ True ] * ( N + 10 )
	sieve [ 0 ] = sieve [ 1 ] = False ;
	for i in range ( 2 , N + 1 ) :
		if ( sieve [ i ] ) :
			for j in range ( i * i , N + 1 , i ) :
				sieve [ j ] = False
	while ( True ) :
		if ( checkSpecialPrime ( sieve , N ) ) :
			print ( N )
			break
		else :
			N -= 1
if __name__ == " _ _ main _ _ " :
	findSpecialPrime ( 379 )
	findSpecialPrime ( 100 )