human
Find Next number having distinct digits from the given number N | Function to find the next distinct digits number.
Loop to find the distinct digits using hash array and the number of digits.
Loop to find the most significant distinct digit of the next number.
Condition to check if the number is possible with the same number of digits count.
Condition to check if the desired most siginificant distinct digit is found.
Loop to find the minimum next digit which is not present in the number.
Computation of the number.
Condition to check if the number is greater than the given number.
Driver Code"
Solution in Python:
 ... Give me a code to find Next number having distinct digits from the given number N and the other steps required?
assistant
#Here is code to find Next number having distinct digits from the given number N and the other steps required.
 def findNextNumber ( n ) :
	h = [ 0 for i in range ( 10 ) ]
	i = 0
	msb = n
	rem = 0
	next_num = - 1
	count = 0
	while ( msb > 9 ) :
		rem = msb % 10
		h [ rem ] = 1
		msb //= 10
		count += 1
	h [ msb ] = 1
	count += 1
	for i in range ( msb + 1 , 10 , 1 ) :
		if ( h [ i ] == 0 ) :
			next_num = i
			break
	if ( next_num == - 1 ) :
		for i in range ( 1 , msb , 1 ) :
			if ( h [ i ] == 0 ) :
				next_num = i
				count += 1
				break
	if ( next_num > 0 ) :
		for i in range ( 0 , 10 , 1 ) :
			if ( h [ i ] == 0 ) :
				msb = i
				break
		for i in range ( 1 , count , 1 ) :
			next_num = ( ( next_num * 10 ) + msb )
		if ( next_num > n ) :
			print ( next_num )
		else :
			print ( " Not ▁ Possible " )
	else :
		print ( " Not ▁ Possible " )
if __name__ == ' _ _ main _ _ ' :
	n = 2019
	findNextNumber ( n )