human
Minimize count of swaps of adjacent elements required to make an array increasing | Function to count minimum number of operations required to obtain an increasing array from given array A [ ].
Store the required result.
Traverse the array A [ ].
If the current element is not in its correct position.
Check if it is present at index i - 1.
Check if it is present at index i - 2.
Otherwise , print - 1 ( Since A [ i ] can not be swapped more than twice ).
Print the result.
Driver Code.
Given array.
Store the size of the array"
How can the above be solved in Python?
assistant
#Here is code to minimize count of swaps of adjacent elements required to make an array increasing and the other steps required.
 def minimumOperations ( A , n ) :
	cnt = 0
	for i in range ( n - 1 , - 1 , - 1 ) :
		if ( A [ i ] != ( i + 1 ) ) :
			if ( ( ( i - 1 ) >= 0 ) and A [ i - 1 ] == ( i + 1 ) ) :
				cnt += 1
				A [ i ] , A [ i - 1 ] = A [ i - 1 ] , A [ i ]
			elif ( ( ( i - 2 ) >= 0 ) and A [ i - 2 ] == ( i + 1 ) ) :
				cnt += 2
				A [ i - 2 ] = A [ i - 1 ]
				A [ i - 1 ] = A [ i ]
				A [ i ] = i + 1
			else :
				print ( - 1 )
				return
	print ( cnt )
if __name__ == " _ _ main _ _ " :
	A = [ 7 , 3 , 2 , 1 , 4 ]
	n = len ( A )
	minimumOperations ( A , n )