human
Check if a non | Utility Function to check whether a subsequence same as the given subarray exists or not.
Check if first element of the subarray is also present before.
Check if last element of the subarray is also present later.
If above two conditions are not satisfied , then no such subsequence exists.
Function to check and prif a subsequence which is same as the given subarray is present or not.
Driver Code.
Function Call"
How can the above be solved in Python?

Write me a code to check if a non and the other steps required?
assistant
#Here is code to check if a non and the other steps required.
 def checkSubsequenceUtil ( arr , L , R , N ) :
	for i in range ( L ) :
		if ( arr [ i ] == arr [ L ] ) :
			return True
	for i in range ( R + 1 , N , 1 ) :
		if ( arr [ i ] == arr [ R ] ) :
			return True
	return False
def checkSubsequence ( arr , L , R , N ) :
	if ( checkSubsequenceUtil ( arr , L , R , N ) ) :
		print ( " YES " )
	else :
		print ( " NO " )
arr = [ 1 , 7 , 12 , 1 , 7 , 5 , 10 , 11 , 42 ]
N = len ( arr )
L = 3
R = 6
checkSubsequence ( arr , L , R , N )