human
Print all non | Utility function to print array arr [ 0. . n - 1 ].
Recursive Function to generate all non - increasing sequences with sum x arr [ ] -- > Elements of current sequence curr_sum -- > Current Sum curr_idx -- > Current index in arr [ ].
If current sum is equal to x , then we found a sequence.
Try placing all numbers from 1 to x - curr_sum at current index.
The placed number must also be smaller than previously placed numbers and it may be equal to the previous stored value , i . e . , arr [ curr_idx - 1 ] if there exists a previous number.
Place number at curr_idx.
Recur.
Try next number.
A wrapper over generateUtil ( ).
Array to store sequences on by one.
Driver program"
How can the above be solved in Python?
assistant
#Here is code to print all non and the other steps required.
 def printArr ( arr , n ) :
	for i in range ( 0 , n ) :
		print ( arr [ i ] , end = " ▁ " )
	print ( " " )
def generateUtil ( x , arr , curr_sum , curr_idx ) :
	if ( curr_sum == x ) :
		printArr ( arr , curr_idx )
		return
	num = 1
	while ( num <= x - curr_sum and ( curr_idx == 0 or num <= arr [ curr_idx - 1 ] ) ) :
		arr [ curr_idx ] = num
		generateUtil ( x , arr , curr_sum + num , curr_idx + 1 )
		num += 1
def generate ( x ) :
	arr = [ 0 ] * x
	generateUtil ( x , arr , 0 , 0 )
x = 5
generate ( x )