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Maximize length of subarray having equal elements by adding at most K | Function to find the maximum number of indices having equal elements after adding at most k numbers.
Sort the array in ascending order.
Make prefix sum array.
Initialize variables.
Update mid.
Check if any subarray can be obtained of length mid having equal elements.
Decrease max to mid.
Function to check if a subarray of length len consisting of equal elements can be obtained or not.
Sliding window.
Last element of the sliding window will be having the max size in the current window.
The current number of element in all indices of the current sliding window.
If the current number of the window , added to k exceeds totalNumbers.
Driver Code.
Function call"
Solution in Python:
assistant
#Here is code to maximize length of subarray having equal elements by adding at most K and the other steps required.
 def maxEqualIdx ( arr , k ) :
	arr . sort ( )
	prefixSum = [ 0 ] * ( len ( arr ) + 1 )
	prefixSum [ 1 ] = arr [ 0 ]
	for i in range ( 1 , len ( prefixSum ) - 1 , 1 ) :
		prefixSum [ i + 1 ] = prefixSum [ i ] + arr [ i ]
	max = len ( arr )
	min = 1
	ans = 1
	while ( min <= max ) :
		mid = ( max + min ) // 2
		if ( check ( prefixSum , mid , k , arr ) ) :
			ans = mid
			min = mid + 1
		else :
			max = mid - 1
	return ans
def check ( pSum , lenn , k , a ) :
	i = 0
	j = lenn
	while ( j <= len ( a ) ) :
		maxSize = a [ j - 1 ]
		totalNumbers = maxSize * lenn
		currNumbers = pSum [ j ] - pSum [ i ]
		if ( currNumbers + k >= totalNumbers ) :
			return True
		else :
			i += 1
			j += 1
	return False
arr = [ 1 , 1 , 1 ]
k = 7
print ( maxEqualIdx ( arr , k ) )