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Counting numbers whose difference from reverse is a product of k | Python 3 program to Count the numbers within a given range in which when you subtract a number from its reverse , the difference is a product of k.
function to check if the number and its reverse have their absolute difference divisible by k.
Reverse the number.
Driver code"
Solution in Python:
assistant
#Here is code to counting numbers whose difference from reverse is a product of k and the other steps required.
 def isRevDiffDivisible ( x , k ) :
	n = x ; m = 0
	while ( x > 0 ) :
		m = m * 10 + x % 10
		x = x // 10
	return ( abs ( n - m ) % k == 0 )
def countNumbers ( l , r , k ) :
	count = 0
	for i in range ( l , r + 1 ) :
		if ( isRevDiffDivisible ( i , k ) ) :
			count = count + 1
	return count
l = 20 ; r = 23 ; k = 6
print ( countNumbers ( l , r , k ) )