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Find root of a number using Newton 's method | Function to return the square root of a number using Newtons method.
Assuming the sqrt of n as n only.
To count the number of iterations.
Calculate more closed x.
Check for closeness.
Update root.
Driver code"
Solution in Python:

Can you provide a code to find root of a number using Newton 's method and the other steps required?
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#Here is code to find root of a number using Newton 's method and the other steps required.
 def squareRoot ( n , l ) :
	x = n
	count = 0
	while ( 1 ) :
		count += 1
		root = 0.5 * ( x + ( n / x ) )
		if ( abs ( root - x ) < l ) :
			break
		x = root
	return root
if __name__ == " _ _ main _ _ " :
	n = 327
	l = 0.00001
	print ( squareRoot ( n , l ) )