human
Count ways to split a Binary String into three substrings having equal count of zeros | Function to return ways to split a string into three parts with the equal number of 0.
Store total count of 0 s.
Count total no . of 0 s character in given string.
If total count of 0 character is not divisible by 3.
Initialize map to store frequency of k.
Traverse string to find ways to split string.
Increment count if 0 appears.
Increment result if sum equal to 2 * k and k exists in map.
Insert sum in map.
Return result.
Driver Code.
Given string.
Function call"
How can the above be solved in Python?
assistant
#Here is code to count ways to split a Binary String into three substrings having equal count of zeros and the other steps required.
 def count ( s ) :
	cnt = 0
	for c in s :
		if c == '0' :
			cnt += 1
	if ( cnt % 3 != 0 ) :
		return 0
	res = 0
	k = cnt // 3
	sum = 0
	mp = { }
	for i in range ( len ( s ) ) :
		if s [ i ] == '0' :
			sum += 1
		if ( sum == 2 * k and k in mp and i < len ( s ) - 1 and i > 0 ) :
			res += mp [ k ]
		if sum in mp :
			mp [ sum ] += 1
		else :
			mp [ sum ] = 1
	return res
if __name__ == " _ _ main _ _ " :
	st = "01010"
	print ( count ( st ) )