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Find N distinct numbers whose Bitwise XOR is equal to K | Function to find N integers having Bitwise XOR equal to K.
Base Cases.
Assign values to P and Q.
Stores Bitwise XOR of the first ( N - 3 ) elements.
Print the first N - 3 elements.
Calculate Bitwise XOR of first ( N - 3 ) elements.
Driver Code.
Function Call"
Solution in Python:
 What is a code to find N distinct numbers whose Bitwise XOR is equal to K and the other steps required?
assistant
#Here is code to find N distinct numbers whose Bitwise XOR is equal to K and the other steps required.
 def findArray ( N , K ) :
	if ( N == 1 ) :
		print ( K , end = " ▁ " )
		return
	if ( N == 2 ) :
		print ( "0" , end = " ▁ " )
		print ( K , end = " ▁ " )
		return
	P = N - 2
	Q = N - 1
	VAL = 0
	for i in range ( 1 , N - 2 ) :
		print ( i , end = " ▁ " )
		VAL ^= i
	if ( VAL == K ) :
		print ( P , end = " ▁ " )
		print ( Q , end = " ▁ " )
		print ( P ^ Q , end = " ▁ " )
	else :
		print ( "0" , end = " ▁ " )
		print ( P , end = " ▁ " )
		print ( P ^ K ^ VAL , end = " ▁ " )
N = 4
X = 6
findArray ( N , X )