human
Can you provide a code to count the numbers which can convert N to 1 using given operation and the other steps required given the following:
Count the numbers which can convert N to 1 using given operation | Function to count the numbers which can convert N to 1 using the given operation.
Store all the divisors of N.
If i is a divisor.
If i is not equal to N / i.
Iterate through all the divisors of N - 1 and count them in answer.
Check if N - 1 is a divisor or not.
Iterate through all divisors and check for N mod d = 1 or ( N - 1 ) mod d = 0.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count the numbers which can convert N to 1 using given operation and the other steps required.
 def countValues ( N ) :
	div = [ ]
	i = 2
	while ( ( i * i ) <= N ) :
		if ( N % i == 0 ) :
			div . append ( i )
			if ( N != i * i ) :
				div . append ( N // i )
		i += 1
	answer = 0
	i = 1
	while ( ( i * i ) <= N - 1 ) :
		if ( ( N - 1 ) % i == 0 ) :
			if ( i * i == N - 1 ) :
				answer += 1
			else :
				answer += 2
		i += 1
	for d in div :
		K = N
		while ( K % d == 0 ) :
			K //= d
		if ( ( K - 1 ) % d == 0 ) :
			answer += 1
	return answer
if __name__ == " _ _ main _ _ " :
	N = 6
	print ( countValues ( N ) )