human
Find the number of positive integers less than or equal to N that have an odd number of digits | Function to return the number of positive integers less than or equal to N that have odd number of digits.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to find the number of positive integers less than or equal to N that have an odd number of digits and the other steps required.
 def odd_digits ( n ) :
	if ( n < 10 ) :
		return n ;
	elif ( n / 10 < 10 ) :
		return 9 ;
	elif ( n / 100 < 10 ) :
		return 9 + n - 99 ;
	elif ( n / 1000 < 10 ) :
		return 9 + 900 ;
	elif ( n / 10000 < 10 ) :
		return 909 + n - 9999 ;
	else :
		return 90909 ;
if __name__ == " _ _ main _ _ " :
	n = 893 ;
	print ( odd_digits ( n ) ) ;