human
What is a code to count numbers whose maximum sum of distinct digit and the other steps required given the following:
Count numbers whose maximum sum of distinct digit | Function to find the digit - sum of a number.
Loop to iterate the number digit - wise to find digit - sum.
variable to store last digit.
Function to find the count of number.
Vector to store the Sum of Digits.
Sum of digits for each element in vector.
Sorting the digitSum vector.
Removing the duplicate elements.
Count variable to store the Count.
Finding the Count of Numbers.
Driver Code.
Function Call"
Solution in Python:
assistant
#Here is code to count numbers whose maximum sum of distinct digit and the other steps required.
 def SumofDigits ( digit ) :
	sum = 0
	while ( digit != 0 ) :
		rem = digit % 10
		sum += rem
		digit //= 10
	return sum
def findCountofNumbers ( arr , n , M ) :
	SumDigits = [ ]
	for i in range ( n ) :
		s = SumofDigits ( arr [ i ] )
		SumDigits . append ( s )
	SumDigits . sort ( )
	ip = list ( set ( SumDigits ) )
	count = 0
	sum = 0
	for i in range ( len ( SumDigits ) ) :
		if ( sum > M ) :
			break
		sum += SumDigits [ i ]
		if ( sum <= M ) :
			count += 1
	return count
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 45 , 16 , 17 , 219 , 32 , 22 ]
	M = 10
	n = len ( arr )
	print ( findCountofNumbers ( arr , n , M ) )