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Digits whose alphabetic representations are jumbled in a given string | Function to convert the jumbled into digits.
Strings of digits 0 - 9.
Initialize vector.
Initialize answer.
Size of the string.
Traverse the string.
Update the elements of the vector.
Print the digits into their original format.
Return answer.
Driver Code"
Solution in Python:

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Can you provide a code to digits whose alphabetic representations are jumbled in a given string and the other steps required?
assistant
#Here is code to digits whose alphabetic representations are jumbled in a given string and the other steps required.
 def finddigits ( s ) :
	num = [ " zero " , " one " , " two " , " three " , " four " , " five " , " six " , " seven " , " eight " , " nine " ]
	arr = [ 0 ] * ( 10 )
	ans = " "
	n = len ( s )
	for i in range ( n ) :
		if ( s [ i ] == ' z ' ) :
			arr [ 0 ] += 1
		if ( s [ i ] == ' w ' ) :
			arr [ 2 ] += 1
		if ( s [ i ] == ' g ' ) :
			arr [ 8 ] += 1
		if ( s [ i ] == ' x ' ) :
			arr [ 6 ] += 1
		if ( s [ i ] == ' v ' ) :
			arr [ 5 ] += 1
		if ( s [ i ] == ' o ' ) :
			arr [ 1 ] += 1
		if ( s [ i ] == ' s ' ) :
			arr [ 7 ] += 1
		if ( s [ i ] == ' f ' ) :
			arr [ 4 ] += 1
		if ( s [ i ] == ' h ' ) :
			arr [ 3 ] += 1
		if ( s [ i ] == ' i ' ) :
			arr [ 9 ] += 1
	arr [ 7 ] -= arr [ 6 ]
	arr [ 5 ] -= arr [ 7 ]
	arr [ 4 ] -= arr [ 5 ]
	arr [ 1 ] -= ( arr [ 2 ] + arr [ 4 ] + arr [ 0 ] )
	arr [ 3 ] -= arr [ 8 ]
	arr [ 9 ] -= ( arr [ 5 ] + arr [ 6 ] + arr [ 8 ] )
	for i in range ( 10 ) :
		for j in range ( arr [ i ] ) :
			ans += chr ( ( i ) + ord ( '0' ) )
	return ans
if __name__ == ' _ _ main _ _ ' :
	s = " owoftnuoer "
	print ( finddigits ( s ) )