human
Count all pairs with given XOR | Returns count of pairs in arr [ 0. . n - 1 ] with XOR value equals to x ..
create empty map that stores counts of individual elements of array ..
If there exist an element in map m with XOR equals to x ^ arr [ i ] , that means there exist an element such that the XOR of element with arr [ i ] is equal to x , then increment count ..
Increment count of current element.
return total count of pairs with XOR equal to x.
Driver Code"
Solution in Python:
 ... Write me a code to count all pairs with given XOR and the other steps required?
assistant
#Here is code to count all pairs with given XOR and the other steps required.
 def xorPairCount ( arr , n , x ) :
	m = dict ( )
	for i in range ( n ) :
		curr_xor = x ^ arr [ i ]
		if ( curr_xor in m . keys ( ) ) :
			result += m [ curr_xor ]
		if arr [ i ] in m . keys ( ) :
			m [ arr [ i ] ] += 1
		else :
			m [ arr [ i ] ] = 1
	return result
arr = [ 2 , 5 , 2 ]
n = len ( arr )
x = 0
print ( " Count ▁ of ▁ pairs ▁ with ▁ given ▁ XOR ▁ = ▁ " , xorPairCount ( arr , n , x ) )