human
Can you provide a code to print all numbers up to N in words in lexicographical order and the other steps required given the following:
Print all numbers up to N in words in lexicographical order | Function to convert a number to words.
Stores the digits.
Base cases.
Stores strings of unit place.
Stores strings for corner cases.
Stores strings for ten 's place digits.
Stores strings for powers of 10.
If given number contains a single digit.
Iterate over all the digits.
Represent first 2 digits in words.
Represent last 2 digits in words.
Explicitly handle corner cases [ 10 , 19 ].
Explicitly handle corner case 20.
For rest of the two digit numbers i . e . , 21 to 99.
Function to print all the numbers up to n in lexicographical order.
Convert all numbers in words.
Sort all strings.
Print answer.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to print all numbers up to N in words in lexicographical order and the other steps required.
 def convert_to_words ( n ) :
	num = str ( n )
	length = len ( num )
	ans = " "
	if ( length == 0 ) :
		ans += " Empty ▁ String "
		return ans
	single_digits = [ " zero " , " one " , " two " , " three " , " four " , " five " , " six " , " seven " , " eight " , " nine " ]
	two_digits = [ " " , " ten " , " eleven " , " twelve " , " thirteen " , " fourteen " , " fifteen " , " sixteen " , " seventeen " , " eighteen " , " nineteen " ]
	tens_multiple = [ " " , " " , " twenty " , " thirty " , " forty " , " fifty " , " sixty " , " seventy " , " eighty " , " ninety " ]
	tens_power = [ " hundred " , " thousand " ]
	if ( length == 1 ) :
		ans += single_digits [ ord ( num [ 0 ] ) - ord ( '0' ) ]
		return ans
	x = 0
	while ( x < len ( num ) ) :
		if ( length >= 3 ) :
			if ( num [ x ] - '0' != 0 ) :
				ans += single_digits [ ord ( num [ x ] ) - ord ( '0' ) ]
				ans += " ▁ "
				ans += tens_power [ len - 3 ]
				ans += " ▁ "
			length -= 1
		else :
			if ( ord ( num [ x ] ) - ord ( '0' ) == 1 ) :
				sum = ( ord ( num [ x ] ) - ord ( '0' ) + ord ( num [ x ] ) - ord ( '0' ) )
				ans += two_digits [ sum ]
				return ans
			elif ( ord ( num [ x ] ) - ord ( '0' ) == 2 and ord ( num [ x + 1 ] ) - ord ( '0' ) == 0 ) :
				ans += " twenty "
				return ans
			else :
				i = ( ord ( num [ x ] ) - ord ( '0' ) )
				if ( i > 0 ) :
					ans += tens_multiple [ i ]
					ans += " ▁ "
				else :
				ans += " "
				x += 1
				if ( ord ( num [ x ] ) - ord ( '0' ) != 0 ) :
					ans += single_digits [ ord ( num [ x ] ) - ord ( '0' ) ]
		x += 1
	return " "
def lexNumbers ( n ) :
	s = [ ]
	for i in range ( 1 , n + 1 ) :
		s . append ( convert_to_words ( i ) )
	s . sort ( )
	ans = [ ]
	for i in range ( n ) :
		ans . append ( s [ i ] )
	for i in range ( n - 1 ) :
		print ( ans [ i ] , end = " , ▁ " )
	print ( ans [ n - 1 ] , end = " " )
if __name__ == " _ _ main _ _ " :
	n = 5
	lexNumbers ( n )