human
Complete the below
def _cmp_by_router_id(local_asn, path1, path2):

    ''''Select the route received from the peer with the lowest BGP router ID.
    If both paths are eBGP paths, then we do not do any tie breaking, i.e we do
    not pick best-path based on this criteria.
    RFC: http://tools.ietf.org/html/rfc5004
    We pick best path between two iBGP paths as usual.'
    '''
assistant
#Here is the Python code you requested.
    def get_asn(path_source):
        if (path_source is None):
            return local_asn
        else:
            return path_source.remote_as
    def get_router_id(path, local_bgp_id):
        path_source = path.source
        if (path_source is None):
            return local_bgp_id
        else:
            originator_id = path.get_pattr(BGP_ATTR_TYPE_ORIGINATOR_ID)
            if originator_id:
                return originator_id.value
            return path_source.protocol.recv_open_msg.bgp_identifier
    path_source1 = path1.source
    path_source2 = path2.source
    if ((path_source1 is None) and (path_source2 is None)):
        return None
    asn1 = get_asn(path_source1)
    asn2 = get_asn(path_source2)
    is_ebgp1 = (asn1 != local_asn)
    is_ebgp2 = (asn2 != local_asn)
    if (is_ebgp1 and is_ebgp2):
        return None
    if (((is_ebgp1 is True) and (is_ebgp2 is False)) or ((is_ebgp1 is False) and (is_ebgp2 is True))):
        raise ValueError('This    method    does    not    support    comparing    ebgp    with    ibgp    path')
    if (path_source1 is not None):
        local_bgp_id = path_source1.protocol.sent_open_msg.bgp_identifier
    else:
        local_bgp_id = path_source2.protocol.sent_open_msg.bgp_identifier
    router_id1 = get_router_id(path1, local_bgp_id)
    router_id2 = get_router_id(path2, local_bgp_id)
    if (router_id1 == router_id2):
        return None
    from ryu.services.protocols.bgp.utils.bgp import from_inet_ptoi
    if (from_inet_ptoi(router_id1) < from_inet_ptoi(router_id2)):
        return path1
    else:
        return path2