human
Can you provide a code to count of unique palindromic strings of length X from given string and the other steps required given the following:
Count of unique palindromic strings of length X from given string | Function to count different palindromic string of length X from the given string S.
Base case.
Create the frequency array Intitalise frequency array with 0.
Count the frequency in the string.
Store frequency of the char.
Check the frequency which is greater than zero.
No . of different char we can put at the position of the i and x - i.
Iterator pointing to the last element of the set.
Decrease the value of the char we put on the position i and n - i.
Different no of char we can put at the position x / 2.
Return total no of different string.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count of unique palindromic strings of length X from given string and the other steps required.
 def findways ( s , x ) :
	if ( x > len ( s ) ) :
		return 0
	n = len ( s )
	freq = [ 0 ] * 26
	for i in range ( n ) :
		freq [ ord ( s [ i ] ) - ord ( ' a ' ) ] += 1
	se = set ( )
	for i in range ( 26 ) :
		if ( freq [ i ] > 0 ) :
			se . add ( freq [ i ] )
	ans = 1
	for i in range ( x // 2 ) :
		count = 0
		for u in se :
			if ( u >= 2 ) :
				count += 1
		if ( count == 0 ) :
			return 0
		else :
			ans *= count
		p = list ( se )
		val = p [ - 1 ]
		p . pop ( - 1 )
		se = set ( p )
		if ( val > 2 ) :
			se . add ( val - 2 )
	if ( x % 2 != 0 ) :
		count = 0
		for u in se :
			if ( u > 0 ) :
				count += 1
		ans = ans * count
	return ans
if __name__ == ' _ _ main _ _ ' :
	s = " aaa "
	x = 2
	print ( findways ( s , x ) )