human
Find sub | Function to print the valid indices in the array.
Function to find sub - arrays from two different arrays with equal sum.
Map to store the indices in A and B which produce the given difference.
Find the smallest j such that b [ j ] >= a [ i ].
Difference encountered for the second time.
b [ j ] - a [ i ] = b [ idx . second ] - a [ idx . first ] b [ j ] - b [ idx . second ] = a [ i ] = a [ idx . first ] So sub - arrays are a [ idx . first + 1. . . i ] and b [ idx . second + 1. . . j ].
Store the indices for difference in the map.
Utility function to calculate the cumulative sum of the array.
Driver code.
Function to update the arrays with their cumulative sum.
Swap is true as a and b are swapped during function call"
Solution in Python:
 Write me a code to find sub and the other steps required?
assistant
#Here is code to find sub and the other steps required.
 def printAns ( x , y , num ) :
	print ( " Indices ▁ in ▁ array " , num , " : " , end = " ▁ " )
	for i in range ( x , y ) :
		print ( i , end = " , ▁ " )
	print ( y )
def findSubarray ( N , a , b , swap ) :
	index = { }
	difference , j = 0 , 0
	index [ 0 ] = ( - 1 , - 1 )
	for i in range ( 0 , N ) :
		while b [ j ] < a [ i ] :
			j += 1
		difference = b [ j ] - a [ i ]
		if difference in index :
			if swap :
				idx = index [ b [ j ] - a [ i ] ]
				printAns ( idx [ 1 ] + 1 , j , 1 )
				printAns ( idx [ 0 ] + 1 , i , 2 )
			else :
				idx = index [ b [ j ] - a [ i ] ]
				printAns ( idx [ 0 ] + 1 , i , 1 )
				printAns ( idx [ 1 ] + 1 , j , 2 )
			return
		index [ difference ] = ( i , j )
	print ( " - 1" )
def cumulativeSum ( arr , n ) :
	for i in range ( 1 , n ) :
		arr [ i ] += arr [ i - 1 ]
if __name__ == " _ _ main _ _ " :
	a = [ 1 , 2 , 3 , 4 , 5 ]
	b = [ 6 , 2 , 1 , 5 , 4 ]
	N = len ( a )
	cumulativeSum ( a , N )
	cumulativeSum ( b , N )
	if b [ N - 1 ] > a [ N - 1 ] :
		findSubarray ( N , a , b , False )
	else :
		findSubarray ( N , b , a , True )