human
Can you provide a code to find Binary string by converting all 01 or 10 to 11 after M iterations and the other steps required given the following:
Find Binary string by converting all 01 or 10 to 11 after M iterations | Function to find the modified binary string after M iterations.
Set the value of M to the minimum of N or M ..
Declaration of current string state.
Loop over M iterations.
Set the current state as null before each iteration.
Check if this zero has exactly one 1 as neighbour.
Flip the zero.
If there is no change , then no need for further iterations ..
Set the current state as the new previous state.
Driver Code.
Given String.
Number of Iterations.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to find Binary string by converting all 01 or 10 to 11 after M iterations and the other steps required.
 def findString ( str , M ) :
	N = len ( str )
	M = min ( M , N )
	s1 = " "
	while ( M != 0 ) :
		s1 = " "
		for i in range ( N - 1 ) :
			if ( str [ i ] == '0' ) :
				if ( ( str [ i - 1 ] == '1' and str [ i + 1 ] != '1' ) or ( str [ i - 1 ] != '1' and str [ i + 1 ] == '1' ) ) :
					s1 += '1'
				else :
					s1 += '0'
			else :
				s1 += '1'
		if ( str == s1 ) :
			break
		s1 += '1'
		str = s1
		M -= 1
	print ( s1 )
if __name__ == ' _ _ main _ _ ' :
	str = "0110100"
	M = 3
	findString ( str , M )