human
Rearrange sorted array such that all odd indices elements comes before all even indices element | Function to print the array.
Function to rearrange the array such that odd indexed elements come before even indexed elements.
Reduces the size of array by one because last element does not need to be changed in case N = odd.
Initialize the variables.
Iterate over the range.
Add the modified element at the odd position.
Iterate over the range.
Add the modified element at the even position.
Iterate over the range.
Divide by the maximum element.
Driver Code"
How can the above be solved in Python?
 ... Give me a code to rearrange sorted array such that all odd indices elements comes before all even indices element and the other steps required?
assistant
#Here is code to rearrange sorted array such that all odd indices elements comes before all even indices element and the other steps required.
 def printArray ( arr , n ) :
	for i in range ( N ) :
		print ( arr [ i ] , end = " ▁ " )
	print ( " " )
def rearrange ( arr , N ) :
	if ( N & 1 ) :
		N -= 1
	odd_idx = 1
	even_idx = 0
	max_elem = arr [ N - 1 ] + 1
	for i in range ( N // 2 ) :
		arr [ i ] += ( arr [ odd_idx ] % max_elem ) * max_elem
		odd_idx += 2
	for i in range ( N // 2 , N ) :
		arr [ i ] += ( arr [ even_idx ] % max_elem ) * max_elem
		even_idx += 2
	for i in range ( N ) :
		arr [ i ] = arr [ i ] // max_elem
if __name__ == " _ _ main _ _ " :
	arr = [ 1 , 2 , 3 , 4 , 5 , 16 , 18 , 19 ]
	N = len ( arr )
	rearrange ( arr , N )
	printArray ( arr , N ) ;