human
Complete the below
@register.filter(is_safe=False)
def intword(value):

    ''''Converts a large integer to a friendly text representation. Works best
    for numbers over 1 million. For example, 1000000 becomes \'1.0 million\',
    1200000 becomes \'1.2 million\' and \'1200000000\' becomes \'1.2 billion\'.'
    '''

=====
What is a the Python code you requested?
assistant
#Here is the Python code you requested.
    try:
        value = int(value)
    except (TypeError, ValueError):
        return value
    if (value < 1000000):
        return value
    def _check_for_i18n(value, float_formatted, string_formatted):
        '\n                                Use    the    i18n    enabled    defaultfilters.floatformat    if    possible\n                                '
        if settings.USE_L10N:
            value = defaultfilters.floatformat(value, 1)
            template = string_formatted
        else:
            template = float_formatted
        return (template % {'value': value})
    for (exponent, converters) in intword_converters:
        large_number = (10 ** exponent)
        if (value < (large_number * 1000)):
            new_value = (value / float(large_number))
            return _check_for_i18n(new_value, *converters(new_value))
    return value