human
Maximum XOR value of maximum and second maximum element among all possible subarrays | Function to return the maximum possible xor.
To store the final answer.
Borward traversal.
Backward traversal.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to maximum XOR value of maximum and second maximum element among all possible subarrays and the other steps required.
 def maximumXor ( arr : list , n : int ) -> int :
	sForward , sBackward = [ ] , [ ]
	ans = - 1
	for i in range ( n ) :
		while len ( sForward ) > 0 and arr [ i ] < arr [ sForward [ - 1 ] ] :
			ans = max ( ans , arr [ i ] ^ arr [ sForward [ - 1 ] ] )
			sForward . pop ( )
		sForward . append ( i )
		while len ( sBackward ) > 0 and arr [ n - i - 1 ] < arr [ sBackward [ - 1 ] ] :
			ans = max ( ans , arr [ n - i - 1 ] ^ arr [ sBackward [ - 1 ] ] )
			sBackward . pop ( )
		sBackward . append ( n - i - 1 )
	return ans
if __name__ == " _ _ main _ _ " :
	arr = [ 8 , 1 , 2 ]
	n = len ( arr )
	print ( maximumXor ( arr , n ) )