human
Minimize count of flips required such that no substring of 0 s have length exceeding K | Function to return minimum number of flips required.
Base Case.
Stores the count of minimum number of flips.
Stores the count of zeros in current sub.
If current character is 0.
Continue ongoing sub.
Start a new sub.
If k consecutive zeroes are obtained.
End segment.
Return the result.
Driver Code.
Function call"
How can the above be solved in Python?

Write me a code to minimize count of flips required such that no substring of 0 s have length exceeding K and the other steps required?
assistant
#Here is code to minimize count of flips required such that no substring of 0 s have length exceeding K and the other steps required.
 def min_flips ( strr , k ) :
	if ( len ( strr ) == 0 ) :
		return 0
	ans = 0
	cnt_zeros = 0
	for ch in strr :
		if ( ch == '0' ) :
			cnt_zeros += 1
		else :
			cnt_zeros = 0
		if ( cnt_zeros == k ) :
			ans += 1
			cnt_zeros = 0
	return ans
if __name__ == ' _ _ main _ _ ' :
	strr = "11100000011"
	k = 3
	print ( min_flips ( strr , k ) )