human
Give me a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/bulb-switcher-ii/:
There is a room with n lights which are turned on initially and 4 buttons on the wall. After performing exactly m unknown operations towards buttons, you need to return how many different kinds of status of the n lights could be.


Suppose n lights are labeled as number [1, 2, 3 ..., n], function of these 4 buttons are given below:

Flip all the lights.
Flip lights with even numbers.
Flip lights with odd numbers.
Flip lights with (3k + 1) numbers, k = 0, 1, 2, ...



Example 1:

Input: n = 1, m = 1.
Output: 2
Explanation: Status can be: [on], [off]



Example 2:

Input: n = 2, m = 1.
Output: 3
Explanation: Status can be: [on, off], [off, on], [off, off]



Example 3:

Input: n = 3, m = 1.
Output: 4
Explanation: Status can be: [off, on, off], [on, off, on], [off, off, off], [off, on, on].


Note:
n and m both fit in range [0, 1000].

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution(object):
     def flipLights(self, n, m):
         """
         :type n: int
         :type m: int
         :rtype: int
         """
         if not n: return 0
         n,b=min(6,n),set()
         b.add(tuple([1]*n))
         for j in range(m):
             c=set()
             for x in b:
                 for t in tuple([(x[i]+1)%2 for i in range(n)]),tuple([x[i] if i%2==0 else (x[i]+1)%2 for i in range(n)]),tuple([(x[i]+1)%2 if i%2==0 else x[i] for i in range(n)]),tuple([(x[i]+1)%2 if i%3==0 else x[i] for i in range(n)]):
                     if t not in c:
                         c.add(t)
             b=c
             if len(b)==8: return 8
         return len(b)