human
Can you provide a code to get maximum items when other items of total cost of an item are free and the other steps required given the following:
Get maximum items when other items of total cost of an item are free | Function to count the total number of items.
Sort the prices.
Choose the last element.
Initial count of item.
Sum to keep track of the total price of free items.
If total is less than or equal to z then we will add 1 to the answer ;"
Solution in Python:
assistant
#Here is code to get maximum items when other items of total cost of an item are free and the other steps required.
 def items ( n , a ) :
	a . sort ( )
	z = a [ n - 1 ]
	x = 1
	s = 0
	for i in range ( 0 , n - 1 ) :
		s += a [ i ]
		if ( s <= z ) :
			x += 1
		else :
			break
	return x
/ * Driver code * /
n = 5
a = [ 5 , 3 , 1 , 5 , 6 ]
print ( items ( n , a ) )