human
Minimize array sum by replacing greater and smaller elements of pairs by half and double of their values respectively atmost K times | Function to find the minimum sum of array elements by given operations.
Base case.
Return 0.
Base case.
Perform K operations.
Stores smallest element in the array.
Stores index of the smallest array element.
Stores largest element in the array.
Stores index of the largest array element.
Traverse the array elements.
If current element exceeds largest_element.
Update the largest element.
Update index of the largest array element.
If current element is smaller than smallest_element.
Update the smallest element.
Update index of the smallest array element.
Stores the value of smallest element by given operations.
Stores the value of largest element by given operations.
If the value of a + b less than the sum of smallest and largest element of the array.
Update smallest element of the array.
Update largest element of the array.
Stores sum of elements of the array by given operations.
Traverse the array.
Update ans.
Driver Code"
Solution in Python:
 Write me a code to minimize array sum by replacing greater and smaller elements of pairs by half and double of their values respectively atmost K times and the other steps required?
assistant
#Here is code to minimize array sum by replacing greater and smaller elements of pairs by half and double of their values respectively atmost K times and the other steps required.
 def minimum_possible_sum ( arr , n , k ) :
	if ( n == 0 ) :
		return 0
	if ( n == 1 ) :
		return arr [ 0 ]
	for i in range ( k ) :
		smallest_element = arr [ 0 ]
		smallest_pos = 0
		largest_element = arr [ 0 ]
		largest_pos = 0
		for i in range ( 1 , n ) :
			if ( arr [ i ] >= largest_element ) :
				largest_element = arr [ i ]
				largest_pos = i
			if ( arr [ i ] < smallest_element ) :
				smallest_element = arr [ i ]
				smallest_pos = i
		a = smallest_element * 2
		b = largest_element // 2
		if ( a + b < smallest_element + largest_element ) :
			arr [ smallest_pos ] = a
			arr [ largest_pos ] = b
	ans = 0
	for i in range ( n ) :
		ans += arr [ i ]
	return ans
if __name__ == ' _ _ main _ _ ' :
	arr = [ 50 , 1 , 100 , 100 , 1 ]
	K = 2
	n = len ( arr )
	print ( minimum_possible_sum ( arr , n , K ) )