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Sum of alternating sign Squares of first N natural numbers | Function to calculate the alternating sign sum.
Variable to store the sum.
Loop to iterate each number from 1 to N.
The alternating sign is put by checking if the number is even or odd.
Add the square with the sign.
Add the square with the sign.
Driver code"
Solution in Python:

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Can you provide a code to sum of alternating sign Squares of first N natural numbers and the other steps required?
assistant
#Here is code to sum of alternating sign Squares of first N natural numbers and the other steps required.
 def summation ( n ) :
	sum = 0 ;
	for i in range ( 1 , n + 1 ) :
		if ( i % 2 == 1 ) :
			sum += ( i * i ) ;
		else :
			sum -= ( i * i ) ;
	return sum ;
if __name__ == " _ _ main _ _ " :
	N = 2 ;
	print ( summation ( N ) ) ;