human
Count elements in the given range which have maximum number of divisors | Function to count the elements with maximum number of divisors.
to store number of divisors initialise with zero.
to store the maximum number of divisors.
to store required answer.
Find the first divisible number.
Count number of divisors.
Find number of elements with maximum number of divisors.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count elements in the given range which have maximum number of divisors and the other steps required.
 def MaximumDivisors ( X , Y ) :
	arr = [ 0 ] * ( Y - X + 1 )
	mx = 0
	cnt = 0
	i = 1
	while i * i <= Y :
		sq = i * i
		if ( ( X // i ) * i >= X ) :
			first_divisible = ( X // i ) * i
		else :
			first_divisible = ( X // i + 1 ) * i
		for j in range ( first_divisible , Y + 1 , i ) :
			if j < sq :
				continue
			elif j == sq :
				arr [ j - X ] += 1
			else :
				arr [ j - X ] += 2
		i += 1
	for i in range ( X , Y + 1 ) :
		if arr [ i - X ] > mx :
			cnt = 1
			mx = arr [ i - X ]
		elif arr [ i - X ] == mx :
			cnt += 1
	return cnt
if __name__ == " _ _ main _ _ " :
	X = 1
	Y = 10
	print ( MaximumDivisors ( X , Y ) )