human
Count Pronic numbers from a given range | Function to count pronic numbers in the range [ A , B ].
Check upto sqrt N.
If product of consecutive numbers are less than equal to num.
Return N - 1.
Function to count pronic numbers in the range [ A , B ].
Subtract the count of pronic numbers which are <= ( A - 1 ) from the count f pronic numbers which are <= B.
Driver Code.
Function call to count pronic numbers in the range [ A , B ]"
How can the above be solved in Python?
 ... Give me a code to count Pronic numbers from a given range and the other steps required?
assistant
#Here is code to count Pronic numbers from a given range and the other steps required.
 def pronic ( num ) :
	N = int ( num ** ( 1 / 2 ) ) ;
	if ( N * ( N + 1 ) <= num ) :
		return N ;
	return N - 1 ;
def countPronic ( A , B ) :
	return pronic ( B ) - pronic ( A - 1 ) ;
if __name__ == " _ _ main _ _ " :
	A = 3 ;
	B = 20 ;
	print ( countPronic ( A , B ) ) ;