human
Sort an array according to count of set bits | Set 2 | function to sort the array according to the number of set bits in elements.
Counting no of setBits in arr [ i ].
The count is subtracted from 32 because the result needs to be in descending order.
Printing the numbers in descending order of set bit count.
Driver code"
Solution in Python:

What is a code to sort an array according to count of set bits and the other steps required?
assistant
#Here is code to sort an array according to count of set bits and the other steps required.
 def sortArr ( arr , n ) :
	mp = [ ]
	for i in range ( n ) :
		count = 0
		k = arr [ i ]
		while ( k ) :
			k = k & k - 1
			count += 1
		mp . append ( ( 32 - count , arr [ i ] ) )
	mp . sort ( key = lambda x : x [ 0 ] )
	for it in mp :
		print ( it [ 1 ] , end = " ▁ " )
if __name__ == " _ _ main _ _ " :
	arr = [ 5 , 2 , 3 , 9 , 4 , 6 , 7 , 15 , 32 ]
	n = len ( arr )
	sortArr ( arr , n )