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Maximize count of corresponding same elements in given Arrays by Rotation | Function that prints maximum equal elements.
List to store the index of elements of array b.
Storing the positions of array B.
Frequency array to keep count of elements with similar difference in distances.
Iterate through all element in arr1 [ ].
Calculate number of shift required to make current element equal.
If d is less than 0.
Store the frequency of current diff.
Compute the maximum frequency stored.
Printing the maximum number of equal elements.
Driver Code.
Given two arrays.
Function Call"
Solution in Python:

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What is a code to maximize count of corresponding same elements in given Arrays by Rotation and the other steps required?
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#Here is code to maximize count of corresponding same elements in given Arrays by Rotation and the other steps required.
 def maximumEqual ( a , b , n ) :
	store = [ 0 ] * 10 ** 5
	for i in range ( n ) :
		store [ b [ i ] ] = i + 1
	ans = [ 0 ] * 10 ** 5
	for i in range ( n ) :
		d = abs ( store [ a [ i ] ] - ( i + 1 ) )
		if ( store [ a [ i ] ] < i + 1 ) :
			d = n - d
		ans [ d ] += 1
	finalans = 0
	for i in range ( 10 ** 5 ) :
		finalans = max ( finalans , ans [ i ] )
	print ( finalans )
if __name__ == ' _ _ main _ _ ' :
	A = [ 6 , 7 , 3 , 9 , 5 ]
	B = [ 7 , 3 , 9 , 5 , 6 ]
	size = len ( A )
	maximumEqual ( A , B , size )