human
Josephus Problem Using Bit Magic | Function to find the position of the Most Significant Bit.
keeps shifting bits to the right until we are left with 0.
Function to return at which place Josephus should sit to avoid being killed.
Getting the position of the Most Significant Bit ( MSB ) . The leftmost '1' . If the number is '41' then its binary is '101001' . So msbPos ( 41 ) = 6.
' j ' stores the number with which to XOR the number ' n ' . Since we need '100000' We will do 1 << 6 - 1 to get '100000.
Toggling the Most Significant Bit . Changing the leftmost '1' to '0' . 101001 ^ 100000 = 001001 ( 9 ).
Left - shifting once to add an extra '0' to the right end of the binary number 001001 = 010010 ( 18 ).
Toggling the '0' at the end to '1' which is essentially the same as putting the MSB at the rightmost place . 010010 | 1 = 010011 ( 19 ).
Driver Code"
How can the above be solved in Python?

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Write me a code to josephus Problem Using Bit Magic and the other steps required?
assistant
#Here is code to josephus Problem Using Bit Magic and the other steps required.
 def msbPos ( n ) :
	pos = 0
	while n != 0 :
		pos += 1
		n = n >> 1
	return pos
def josephify ( n ) :
	position = msbPos ( n )
'
	j = 1 << ( position - 1 )
	n = n ^ j
	n = n << 1
	n = n | 1
	return n
n = 41
print ( josephify ( n ) )