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Count of all possible numbers not exceeding M having suffix N | Function to count the no . of digits of N.
Function to count all possible numbers having Suffix as N.
Difference of the A . P.
Count of the number of terms.
Driver code"
Solution in Python:
 Give me a code to count of all possible numbers not exceeding M having suffix N and the other steps required?
assistant
#Here is code to count of all possible numbers not exceeding M having suffix N and the other steps required.
 def digitsOf ( num ) :
	return len ( str ( num ) ) ;
def count ( a , tn ) :
	diff = int ( pow ( 10 , digitsOf ( a ) ) ) ;
	return ( ( tn - a ) / diff ) + 1 ;
if __name__ == ' _ _ main _ _ ' :
	n = 25 ; m = 4500 ;
	print ( int ( count ( n , m ) ) ) ;