human
Can you provide a code to modify a numeric string to a balanced parentheses by replacements and the other steps required given the following:
Modify a numeric string to a balanced parentheses by replacements | Function to check if the given string can be converted to a balanced bracket sequence or not.
Check if the first and last characters are equal.
Initialize two variables to store the count of open and closed brackets.
If the current character is same as the first character.
If the current character is same as the last character.
If count of open brackets becomes less than 0.
Print the new string.
If the current character is same as the first character.
If bracket sequence is not balanced.
Check for unbalanced bracket sequence.
Print the sequence.
Given Input.
Function Call"
Solution in Python:
assistant
#Here is code to modify a numeric string to a balanced parentheses by replacements and the other steps required.
 def balBracketSequence ( str ) :
	n = len ( str )
	if ( str [ 0 ] == str [ n - 1 ] ) :
		print ( " No " , end = " " )
	else :
		cntForOpen = 0
		cntForClose = 0
		check = 1
		for i in range ( n ) :
			if ( str [ i ] == str [ 0 ] ) :
				cntForOpen += 1
			elif str [ i ] == str [ n - 1 ] :
				cntForOpen -= 1
			else :
				cntForOpen += 1
			if ( cntForOpen < 0 ) :
				check = 0
				break
		if ( check and cntForOpen == 0 ) :
			print ( " Yes , ▁ " , end = " " )
			for i in range ( n ) :
				if ( str [ i ] == str [ n - 1 ] ) :
					print ( ' ) ' , end = " " )
				else :
					print ( ' ( ' , end = " " )
			return
		else :
			for i in range ( n ) :
				if ( str [ i ] == str [ 0 ] ) :
					cntForClose += 1
				else :
					cntForClose -= 1
				if ( cntForClose < 0 ) :
					check = 0
					break
			if ( check and cntForClose == 0 ) :
				print ( " Yes , ▁ " , end = " " )
				for i in range ( n ) :
					if ( str [ i ] == str [ 0 ] ) :
						print ( ' ( ' , end = " " )
					else :
						print ( ' ) ' , end = " " )
				return
		print ( " NO " , end = " " )
str = "123122"
balBracketSequence ( str )