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Search element in a Spirally sorted Matrix | Function to return the ring , the number x belongs to ..
Returns - 1 if number x is smaller than least element of arr.
l and r represent the diagonal elements to search in.
Returns - 1 if number x is greater than the largest element of arr.
Function to perform binary search on an array sorted in increasing order l and r represent the left and right index of the row to be searched.
Function to perform binary search on a particular column of the 2D array t and b represent top and bottom rows.
Function to perform binary search on an array sorted in decreasing order.
Function to perform binary search on a particular column of the 2D array.
Function to find the position of the number x.
Finding the ring.
To store row and column.
Edge case if n is odd.
Check which of the 4 sides , the number x lies in.
Printing the position.
Driver code"
Solution in Python:

Give me a code to search element in a Spirally sorted Matrix and the other steps required?
assistant
#Here is code to search element in a Spirally sorted Matrix and the other steps required.
 def findRing ( arr , x ) :
	if arr [ 0 ] [ 0 ] > x :
		return - 1
	l , r = 0 , ( n + 1 ) // 2 - 1
	if n % 2 == 1 and arr [ r ] [ r ] < x :
		return - 1
	if n % 2 == 0 and arr [ r + 1 ] [ r ] < x :
		return - 1
	while l < r :
		mid = ( l + r ) // 2
		if arr [ mid ] [ mid ] <= x :
			if ( mid == ( n + 1 ) // 2 - 1 or arr [ mid + 1 ] [ mid + 1 ] > x ) :
				return mid
			else :
				l = mid + 1
		else :
			r = mid - 1
	return r
def binarySearchRowInc ( arr , row , l , r , x ) :
	while l <= r :
		mid = ( l + r ) // 2
		if arr [ row ] [ mid ] == x :
			return mid
		elif arr [ row ] [ mid ] < x :
			l = mid + 1
		else :
			r = mid - 1
	return - 1
def binarySearchColumnInc ( arr , col , t , b , x ) :
	while t <= b :
		mid = ( t + b ) // 2
		if arr [ mid ] [ col ] == x :
			return mid
		elif arr [ mid ] [ col ] < x :
			t = mid + 1
		else :
			b = mid - 1
	return - 1
def binarySearchRowDec ( arr , row , l , r , x ) :
	while l <= r :
		mid = ( l + r ) // 2
		if arr [ row ] [ mid ] == x :
			return mid
		elif arr [ row ] [ mid ] < x :
			r = mid - 1
		else :
			l = mid + 1
	return - 1
def binarySearchColumnDec ( arr , col , t , b , x ) :
	while t <= b :
		mid = ( t + b ) // 2
		if arr [ mid ] [ col ] == x :
			return mid
		elif arr [ mid ] [ col ] < x :
			b = mid - 1
		else :
			t = mid + 1
	return - 1
def spiralBinary ( arr , x ) :
	f1 = findRing ( arr , x )
	r , c = None , None
	if f1 == - 1 :
		print ( " - 1" )
		return
	if n % 2 == 1 and f1 == ( n + 1 ) // 2 - 1 :
		print ( f1 , f1 )
		return
	if x < arr [ f1 ] [ n - f1 - 1 ] :
		c = binarySearchRowInc ( arr , f1 , f1 , n - f1 - 2 , x )
		r = f1
	elif x < arr [ n - f1 - 1 ] [ n - f1 - 1 ] :
		c = n - f1 - 1
		r = binarySearchColumnInc ( arr , n - f1 - 1 , f1 , n - f1 - 2 , x )
	elif x < arr [ n - f1 - 1 ] [ f1 ] :
		c = binarySearchRowDec ( arr , n - f1 - 1 , f1 + 1 , n - f1 - 1 , x )
		r = n - f1 - 1
	else :
		r = binarySearchColumnDec ( arr , f1 , f1 + 1 , n - f1 - 1 , x )
		c = f1
	if c == - 1 or r == - 1 :
		print ( " - 1" )
	else :
		print ( " { 0 } ▁ { 1 } "...