human
What is a code to count number of integers less than or equal to N which has exactly 9 divisors and the other steps required given the following:
Count number of integers less than or equal to N which has exactly 9 divisors | Function to count factors in O ( N ).
iterate and check if factor or not.
Function to count numbers having exactly 9 divisors.
check for all numbers <= N.
check if exactly 9 factors or not.
Driver Code"
Solution in Python:
assistant
#Here is code to count number of integers less than or equal to N which has exactly 9 divisors and the other steps required.
 def numberOfDivisors ( num ) :
	c = 0
	for i in range ( 1 , num + 1 ) :
		if ( num % i == 0 ) :
			c += 1
	return c
def countNumbers ( n ) :
	c = 0
	for i in range ( 1 , n + 1 ) :
		if ( numberOfDivisors ( i ) == 9 ) :
			c += 1
	return c
if __name__ == " _ _ main _ _ " :
	n = 1000
	print ( countNumbers ( n ) )