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Sum of an array of large numbers | Function to prthe result of the summation of numbers having K - digit.
Reverse the array to obtain the result.
Print every digit of the answer.
Function to calculate the total sum.
Stores the array of large numbers in integer format.
Convert each element from character to integer.
Stores the carry.
Stores the result of summation.
Initialize the sum.
Calculate sum.
Update the sum by adding existing carry.
Store the number of digits.
Increase count of digits.
If the number exceeds 9 , Store the unit digit in carry.
Store the rest of the sum.
Append digit by digit into result array.
Append result until carry is 0.
Print the result.
Driver Code.
Given N array of large numbers"
Solution in Python:

What is a code to sum of an array of large numbers and the other steps required?
assistant
#Here is code to sum of an array of large numbers and the other steps required.
 def printResult ( result ) :
	result = result [ : : - 1 ]
	i = 0
	while ( i < len ( result ) ) :
		print ( result [ i ] , end = " " )
		i += 1
def sumOfLargeNumbers ( v , k , N ) :
	x = [ [ ] for i in range ( 1000 ) ]
	for i in range ( k ) :
		for j in range ( N ) :
			x [ i ] . append ( ord ( v [ i ] [ j ] ) - ord ( '0' ) )
	carry = 0
	result = [ ]
	for i in range ( N - 1 , - 1 , - 1 ) :
		sum = 0
		for j in range ( k ) :
			sum += x [ j ] [ i ]
		sum += carry
		temp = sum
		count = 0
		while ( temp > 9 ) :
			temp = temp % 10
			count += 1
		l = pow ( 10 , count )
		if ( l != 1 ) :
			carry = sum / l
		sum = sum % 10
		result . append ( sum )
	while ( carry != 0 ) :
		a = carry % 10
		result . append ( a )
		carry = carry // 10
	printResult ( result )
if __name__ == ' _ _ main _ _ ' :
	K = 10
	N = 5
	arr = [ "1111111111" , "1111111111" , "1111111111" , "1111111111" , "1111111111" ]
	sumOfLargeNumbers ( arr , N , K )