human
Give me a the Python code you requested given the following:
Complete the below
def dict_subset(dict_, keys, pop=False, must_have=True):

    ''''Return a subset of a dictionary corresponding to a set of keys.
    Parameters
    dict_ : dict
    The dictionary.
    keys : iterable
    The keys of interest.
    pop : bool
    If ``True``, the pairs corresponding to the keys of interest are
    popped from the dictionary.
    must_have : bool
    If ``True``, a ValueError will be raised when trying to retrieve a
    key not present in the dictionary.
    Returns
    result : ``OrderedDict``
    An ordered dictionary of retrieved pairs. The order is the same as
    in the ``keys`` argument.'
    '''
assistant
#Here is the Python code you requested.
    not_found = object()
    def extract(k):
        if pop:
            if must_have:
                return dict_.pop(k)
            return dict_.pop(k, not_found)
        if must_have:
            return dict_[k]
        return dict_.get(k, not_found)
    result = [(key, extract(key)) for key in keys]
    return OrderedDict([(k, v) for (k, v) in result if (v is not not_found)])