human
Minimize cost of flipping or swaps to make a Binary String balanced | Function to find the minimum cost to convert the given into balanced string.
Stores count of 1 ' s ▁ and ▁ 0' s in the string.
Traverse the string.
Increment count1.
Increment count 0.
Stores absolute difference of counts of 0 ' s ▁ and ▁ 1' s.
If consists of only 0 ' s ▁ and ▁ 1' s.
Print the minimum cost.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to minimize cost of flipping or swaps to make a Binary String balanced and the other steps required.
 def findMinimumCost ( s , N ) :
	count_1 , count_0 = 0 , 0
	for i in range ( N ) :
		if ( s [ i ] == '1' ) :
			count_1 += 1
		else :
			count_0 += 1
	k = abs ( count_0 - count_1 )
	if ( count_1 == N or count_0 == N ) :
		print ( - 1 )
	else :
		print ( k // 2 )
if __name__ == ' _ _ main _ _ ' :
	S = "110110"
	N = len ( S )
	findMinimumCost ( S , N )