human
Write me a Python program to print m integers — the responses to Eugene's queries in the order they occur in the input given the following:
Eugeny has array a = a1, a2, ..., an, consisting of n integers. Each integer ai equals to -1, or to 1. Also, he has m queries:

  * Query number i is given as a pair of integers li, ri (1 ≤ li ≤ ri ≤ n). 
  * The response to the query will be integer 1, if the elements of array a can be rearranged so as the sum ali + ali + 1 + ... + ari = 0, otherwise the response to the query will be integer 0. 


Help Eugeny, answer all his queries.

Input

The first line contains integers n and m (1 ≤ n, m ≤ 2·105). The second line contains n integers a1, a2, ..., an (ai = -1, 1). Next m lines contain Eugene's queries. The i-th line contains integers li, ri (1 ≤ li ≤ ri ≤ n).

Output

Print m integers — the responses to Eugene's queries in the order they occur in the input.

Examples

Input

2 3
1 -1
1 1
1 2
2 2

Output

0
1
0

Input

5 5
-1 1 1 1 -1
1 1
2 3
3 5
2 5
1 5

Output

0
1
0
1
0
Solve the task in PYTHON3.
assistant
#Here is Python program to print m integers — the responses to Eugene's queries in the order they occur in the input.

import math,itertools,fractions,heapq,collections,bisect,sys,queue,copy

sys.setrecursionlimit(10**7)
inf=10**20
mod=10**9+7
dd=[(-1,0),(0,1),(1,0),(0,-1)]
ddn=[(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]

def LI(): return [int(x) for x in sys.stdin.readline().split()]
# def LF(): return [float(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return input()

# Summarize count of factor within list -- START --
def summarizeList(l):
  sl=sorted(l)

  a=sl[0]
  c=1
  res=[]

  for x in sl[1:]:
    if x==a:
      c+=1
    else:
      res.append([a,c])
      a=x
      c=1
  res.append([a,c])

  return res
# Summarize count of factor within list --- END ---

def main():
  n,k=LI()
  l=LI()
  sl=summarizeList(l)

  ans=[]
  for _ in range(k):
    a,b=LI()
    x=b-a+1

    if x%2==1:
      ans.append(0)
    else:
      if len(sl)==1:
        ans.append(0)
      else:
        if sl[0][1]>=x//2 and sl[1][1]>=x//2:
          ans.append(1)
        else:
          ans.append(0)

  for x in ans:
    print(x)

main()
# print(main())