human
Maximize sum of remaining elements after every removal of the array half with greater sum | Function to find the maximum sum.
Base case len of array is 1.
Stores the final result.
Traverse the array.
Store left prefix sum.
Store right prefix sum.
Compare the left and right.
If both are equal apply the optimal method.
Update with minimum.
Return the final ans.
Function to print maximum sum.
Dicitionary to store prefix sums.
Traversing the array.
Add prefix sum of the array.
Drivers Code.
Function Call"
Solution in Python:
assistant
#Here is code to maximize sum of remaining elements after every removal of the array half with greater sum and the other steps required.
 def maxweight ( s , e , pre ) :
	if s == e :
		return 0
	ans = 0
	for i in range ( s , e ) :
		left = pre [ i ] - pre [ s - 1 ]
		right = pre [ e ] - pre [ i ]
		if left < right :
			ans = max ( ans , left + maxweight ( s , i , pre ) )
		if left == right :
			ans = max ( ans , left + maxweight ( s , i , pre ) , right + maxweight ( i + 1 , e , pre ) )
		if left > right :
			ans = max ( ans , right + maxweight ( i + 1 , e , pre ) )
	return ans
def maxSum ( arr ) :
	pre = { - 1 : 0 , 0 : arr [ 0 ] }
	for i in range ( 1 , len ( arr ) ) :
		pre [ i ] = pre [ i - 1 ] + arr [ i ]
	print ( maxweight ( 0 , len ( arr ) - 1 , pre ) )
arr = [ 6 , 2 , 3 , 4 , 5 , 5 ]
maxSum ( arr )