human
Count maximum concatenation of pairs from given array that are divisible by 3 | Function to count pairs whose concatenation is divisible by 3 and each element can be present in at most one pair.
Stores count of array elements whose remainder is 0 by taking modulo by 3.
Stores count of array elements whose remainder is 1 by taking modulo by 3.
Stores count of array elements whose remainder is 2 by taking modulo by 3.
Traverse the array.
Stores sum of digits of arr [ i ].
Update digitSum.
If remainder of digitSum by by taking modulo 3 is 0.
Update rem0.
If remainder of digitSum by by taking modulo 3 is 1.
Update rem1.
Update rem2.
Driver Code.
To display the result"
How can the above be solved in Python?
assistant
#Here is code to count maximum concatenation of pairs from given array that are divisible by 3 and the other steps required.
 def countDiv ( arr ) :
	rem0 = 0
	rem1 = 0
	rem2 = 0
	for i in arr :
		digitSum = 0
		for digit in str ( i ) :
			digitSum += int ( digit )
		if digitSum % 3 == 0 :
			rem0 += 1
		elif digitSum % 3 == 1 :
			rem1 += 1
		else :
			rem2 += 1
	return ( rem0 // 2 + min ( rem1 , rem2 ) )
arr = [ 5 , 3 , 2 , 8 , 7 ]
print ( countDiv ( arr ) )