human
Number of hours after which the second person moves ahead of the first person if they travel at a given speed | Function to return the number of hours for the second person to move ahead.
Time taken to equalize.
Time taken to move ahead.
Driver code"
Solution in Python:

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What is a code to number of hours after which the second person moves ahead of the first person if they travel at a given speed and the other steps required?
assistant
#Here is code to number of hours after which the second person moves ahead of the first person if they travel at a given speed and the other steps required.
 def findHours ( a , b , k ) :
	if ( a >= b ) :
		return - 1
	time = k // ( b - a )
	time = time + 1
	return time
a = 4
b = 5
k = 1
print ( findHours ( a , b , k ) )