human
What is a code to number of non and the other steps required given the following:
Number of non | Function to return the required count.
To store the final result.
Two pointer loop.
Initialising j.
Looping till the subarray increases.
Update ret.
Update i.
Return ret.
Driver code"
Solution in Python:
assistant
#Here is code to number of non and the other steps required.
 def findCnt ( arr , n , k ) :
	ret = 0 ;
	i = 0 ;
	while ( i < n ) :
		j = i + 1 ;
		while ( j < n and arr [ j ] >= arr [ j - 1 ] ) :
			j += 1 ;
		x = max ( 0 , j - i - k ) ;
		ret += ( x * ( x + 1 ) ) / 2 ;
		i = j ;
	return ret ;
if __name__ == " _ _ main _ _ " :
	arr = [ 5 , 4 , 3 , 2 , 1 ] ;
	n = len ( arr ) ;
	k = 2 ;
	print ( findCnt ( arr , n , k ) ) ;