human
Count ways to place ' + ' and ' | Function to count number of ways ' + ' and ' - ' operators can be placed in front of array elements to make the sum of array elements equal to K.
Stores sum of the array.
Stores count of 0 s in A [ ].
Traverse the array.
Update sum.
Update count of 0 s.
Conditions where no arrangements are possible which adds up to K.
Required sum.
Dp array.
Base cases.
Fill the dp array.
Return answer.
Driver Code.
Input.
Function call"
How can the above be solved in Python?
 ... What is a code to count ways to place ' + ' and ' and the other steps required?
assistant
#Here is code to count ways to place ' + ' and ' and the other steps required.
 def solve ( A , N , K ) :
	sum = 0
	c = 0
	for i in range ( N ) :
		sum += A [ i ]
		if ( A [ i ] == 0 ) :
			c += 1
	if ( K > sum or ( sum + K ) % 2 ) :
		return 0
	sum = ( sum + K ) // 2
	dp = [ [ 0 for i in range ( sum + 1 ) ] for j in range ( N + 1 ) ]
	for i in range ( sum + 1 ) :
		dp [ 0 ] [ i ] = 0
	for i in range ( N + 1 ) :
		dp [ i ] [ 0 ] = 1
	for i in range ( 1 , N + 1 , 1 ) :
		for j in range ( 1 , sum + 1 , 1 ) :
			if ( A [ i - 1 ] <= j and A [ i - 1 ] ) :
				dp [ i ] [ j ] = ( dp [ i - 1 ] [ j ] + dp [ i - 1 ] [ j - A [ i - 1 ] ] )
			else :
				dp [ i ] [ j ] = dp [ i - 1 ] [ j ]
	return dp [ N ] [ sum ] + pow ( 2 , c )
if __name__ == ' _ _ main _ _ ' :
	A = [ 1 , 1 , 2 , 3 ]
	N = len ( A )
	K = 3
	print ( solve ( A , N , K ) )