human
Maximum inversions in a sequence of 1 to N after performing given operations at most K times | Function which computes the maximum number of inversions.
' answer ' will store the required number of inversions.
We do this because we will never require more than floor ( n / 2 ) operations.
left pointer in the array.
right pointer in the array.
Doing k operations.
Incrementing ans by number of inversions increase due to this swapping.
Driver Code.
Input 1.
Input 2"
How can the above be solved in Python?

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Give me a code to maximum inversions in a sequence of 1 to N after performing given operations at most K times and the other steps required?
assistant
#Here is code to maximum inversions in a sequence of 1 to N after performing given operations at most K times and the other steps required.
 def maximum_inversion ( n , k ) :
	answer = 0 ;
	k = min ( k , n // 2 ) ;
	left = 1 ;
	right = n ;
	while ( k > 0 ) :
		k -= 1 ;
		answer += 2 * ( right - left ) - 1 ;
		left += 1 ;
		right -= 1 ;
	print ( answer ) ;
if __name__ == ' _ _ main _ _ ' :
	N = 5 ;
	K = 3 ;
	maximum_inversion ( N , K ) ;
	N = 4 ;
	K = 1 ;
	maximum_inversion ( N , K ) ;