human
Can you provide a the Python code you requested given the following:
Complete the below
def hrm_competency_controller():

    ''''RESTful CRUD controller
    - used for Searching for people by Skill
    - used for Adding/Editing on Profile page'
    '''
assistant
#Here is the Python code you requested.
    T = current.T
    s3db = current.s3db
    s3 = current.response.s3
    def prep(r):
        if (r.method in ('create', 'create.popup', 'update', 'update.popup')):
            table = r.table
            get_vars = r.get_vars
            person_id = get_vars.get('~.person_id', None)
            if person_id:
                try:
                    person_id = int(person_id)
                except ValueError:
                    pass
                else:
                    field = table.person_id
                    field.default = person_id
                    field.readable = field.writable = False
                skill_type_name = get_vars.get('~.skill_id$skill_type_id$name')
                if skill_type_name:
                    ttable = s3db.hrm_skill_type
                    query = (ttable.name == skill_type_name)
                    rows = current.db(query).select(ttable.id)
                    skill_type_ids = [row.id for row in rows]
                    if skill_type_ids:
                        field = table.skill_id
                        requires = field.requires
                        if isinstance(requires, IS_EMPTY_OR):
                            requires = requires.other
                        if hasattr(requires, 'set_filter'):
                            requires.set_filter(filterby='skill_type_id', filter_opts=skill_type_ids)
        elif (not r.id):
            filter_widgets = [S3TextFilter(['person_id$first_name', 'person_id$middle_name', 'person_id$last_name', 'person_id$hrm_human_resource.job_title_id$name'], label=T('Search'), comment=T("You    can    search    by    job    title    or    person    name    -    enter    any    of    the    first,    middle    or    last    names,    separated    by    spaces.    You    may    use    %    as    wildcard.    Press    'Search'    without    input    to    list    all    persons.")), S3OptionsFilter('skill_id', label=T('Skills'), options=(lambda : s3_get_filter_opts('hrm_skill', translate=True))),...