human
Check if a String contains any index with more than K active characters | Function to check if any index contains more than K active characters.
Store the last occurrence of each character.
Stores the active characters.
Insert the character.
If the size of set exceeds K.
Remove the character from set if i is the last index of the current character.
Driver code"
Solution in Python:

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Write me a code to check if a String contains any index with more than K active characters and the other steps required?
assistant
#Here is code to check if a String contains any index with more than K active characters and the other steps required.
 def checkString ( s , K ) :
	n = len ( s )
	dict = { }
	for i in range ( n ) :
		dict [ s [ i ] ] = i ;
	st = set ( )
	for i in range ( n ) :
		st . add ( s [ i ] )
		if len ( st ) > K :
			print ( " Yes " )
			return
		if dict [ s [ i ] ] == i :
			st . remove ( s [ i ] )
	print ( " No " )
s = " aabbcdca "
K = 2
checkString ( s , K )