human
Find the value of N when F ( N ) = f ( a ) + f ( b ) where a + b is the minimum possible and a * b = N | Function to return the value of F ( N ).
Base cases.
Count the number of times a number if divisible by 2.
Return the summation.
Driver code"
How can the above be solved in Python?

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What is a code to find the value of N when F ( N ) = f ( a ) + f ( b ) where a + b is the minimum possible and a * b = N and the other steps required?
assistant
#Here is code to find the value of N when F ( N ) = f ( a ) + f ( b ) where a + b is the minimum possible and a * b = N and the other steps required.
 def getValueOfF ( n ) :
	if ( n == 1 ) :
		return 0
	if ( n == 2 ) :
		return 1
	cnt = 0
	while ( n % 2 == 0 ) :
		cnt += 1
		n /= 2
	return 2 * cnt
n = 20
print ( getValueOfF ( n ) )