human
Finding a Non Transitive Co | Checks if any possible triplet ( a , b , c ) satifying the condition that ( a , b ) is coprime , ( b , c ) is coprime but ( a , c ) isnt.
Case 1 : Less than 3 numbers between L and R.
Case 2 : More than 3 numbers between L and R.
triplets should always be of form ( 2 k , 2 k + 1 , 2 k + 2 ).
Case 3.1 : Exactly 3 numbers in range of form ( 2 k , 2 k + 1 , 2 k + 2 ).
Case 3.2 : Exactly 3 numbers in range of form ( 2 k - 1 , 2 k , 2 k + 1 ).
flag = True indicates that a pair exists between L and R.
finding possible Triplet between 2 and 10.
finding possible Triplet between 23 and 46"
How can the above be solved in Python?
assistant
#Here is code to finding a Non Transitive Co and the other steps required.
 def possibleTripletInRange ( L , R ) :
	flag = False ;
	possibleA = 0 ;
	possibleB = 0 ;
	possibleC = 0 ;
	numbersInRange = ( R - L + 1 ) ;
	if ( numbersInRange < 3 ) :
		flag = False ;
	elif ( numbersInRange > 3 ) :
		flag = True ;
		if ( ( L % 2 ) > 0 ) :
			L += 1 ;
		possibleA = L ;
		possibleB = L + 1 ;
		possibleC = L + 2 ;
	else :
		if ( ( L % 2 ) == 0 ) :
			flag = True ;
			possibleA = L ;
			possibleB = L + 1 ;
			possibleC = L + 2 ;
		else :
			flag = False ;
	if ( flag == True ) :
		print ( " ( " , possibleA , " , " , possibleB , " , " , possibleC , " ) ▁ is ▁ one ▁ such " , " possible ▁ triplet ▁ between " , L , " and " , R ) ;
	else :
		print ( " No ▁ Such ▁ Triplet ▁ exists ▁ between " , L , " and " , R ) ;
L = 2 ;
R = 10 ;
possibleTripletInRange ( L , R ) ;
L = 23 ;
R = 46 ;
possibleTripletInRange ( L , R ) ;