human
Count ways to remove pairs from a matrix such that remaining elements can be grouped in vertical or horizontal pairs | Function to count ways to remove pairs such that the remaining elements can be arranged in pairs vertically or horizontally.
Store the size of matrix.
If N is odd , then no such pair exists.
Store the number of required pairs.
Initialize an auxiliary matrix and fill it with 0 s.
Traverse the matrix v [ ] [ ].
Check if i + j is odd or even.
Increment the value dp [ v [ i ] [ j ] - 1 ] [ 0 ] by 1.
Increment the value dp [ v [ i ] [ j ] - 1 ] [ 1 ] by 1.
Iterate in range [ 0 , k - 1 ] using i.
Iterate in range [ i + 1 , k - 1 ] using j.
Update the ans.
Print the answer.
Driver code"
Solution in Python:

Write me a code to count ways to remove pairs from a matrix such that remaining elements can be grouped in vertical or horizontal pairs and the other steps required?
assistant
#Here is code to count ways to remove pairs from a matrix such that remaining elements can be grouped in vertical or horizontal pairs and the other steps required.
 def numberofpairs ( v , k ) :
	n = len ( v )
	if ( n % 2 == 1 ) :
		print ( 0 )
		return
	ans = 0
	dp = [ [ 0 for i in range ( 2 ) ] for j in range ( k ) ]
	for i in range ( k ) :
		for j in range ( 2 ) :
			dp [ i ] [ j ] = 0
	for i in range ( n ) :
		for j in range ( n ) :
			if ( ( i + j ) % 2 == 0 ) :
				dp [ v [ i ] [ j ] - 1 ] [ 0 ] += 1
			else :
				dp [ v [ i ] [ j ] - 1 ] [ 1 ] += 1
	for i in range ( k ) :
		for j in range ( i + 1 , k ) :
			ans += dp [ i ] [ 0 ] * dp [ j ] [ 1 ]
			ans += dp [ i ] [ 1 ] * dp [ j ] [ 0 ]
	print ( ans )
mat = [ [ 1 , 2 ] , [ 3 , 4 ] ]
K = 4
numberofpairs ( mat , K )