human
Minimum subarray reversals required such that sum of all pairs of adjacent elements is odd | Function to count reversals to separate elements with same parity.
Traverse the given array.
Count size of subarray having integers with same parity only.
Otherwise.
Reversals required is equal to one less than subarray size.
Return the total reversals.
Function to print the array elements.
Function to count the minimum reversals required to make make sum of all adjacent elements odd.
Stores operations required for separating adjacent odd elements.
Stores operations required for separating adjacent even elements.
Maximum of two is the return.
Driver Code.
Given array arr [ ].
Size of array.
Function Call"
How can the above be solved in Python?

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Can you provide a code to minimum subarray reversals required such that sum of all pairs of adjacent elements is odd and the other steps required?
assistant
#Here is code to minimum subarray reversals required such that sum of all pairs of adjacent elements is odd and the other steps required.
 def separate ( arr , n , parity ) :
	count = 1
	res = 0
	for i in range ( 1 , n ) :
		if ( ( ( arr [ i ] + parity ) & 1 ) and ( ( arr [ i - 1 ] + parity ) & 1 ) ) :
			count += 1
		else :
			if ( count > 1 ) :
				res += count - 1
			count = 1
	return res
def printArray ( arr , n ) :
	for i in range ( n ) :
		print ( arr [ i ] , end = " ▁ " )
def requiredOps ( arr , N ) :
	res1 = separate ( arr , N , 0 )
	res2 = separate ( arr , N , 1 )
	print ( max ( res1 , res2 ) )
if __name__ == " _ _ main _ _ " :
	arr = [ 13 , 2 , 6 , 8 , 3 , 5 , 7 , 10 , 14 , 15 ]
	N = len ( arr )
	requiredOps ( arr , N )