human
I found an interesting problem on https://leetcode.com/problems/binary-tree-pruning/:
We are given the head node root of a binary tree, where additionally every node's value is either a 0 or a 1.
Return the same tree where every subtree (of the given tree) not containing a 1 has been removed.
(Recall that the subtree of a node X is X, plus every node that is a descendant of X.)
Example 1:
Input: [1,null,0,0,1]
Output: [1,null,0,null,1]
 
Explanation: 
Only the red nodes satisfy the property "every subtree not containing a 1".
The diagram on the right represents the answer.


Example 2:
Input: [1,0,1,0,0,0,1]
Output: [1,null,1,null,1]



Example 3:
Input: [1,1,0,1,1,0,1,0]
Output: [1,1,0,1,1,null,1]



Note: 

The binary tree will have at most 200 nodes.
The value of each node will only be 0 or 1.

I tried it in Python, but could not do it. Can you solve it?

 Write me a the Python code you requested?
assistant
#Here is the Python code you requested.

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def pruneTree(self, root: TreeNode) -> TreeNode:
        
        if not root:
            return None 
        
        root.left =self.pruneTree(root.left)
        
        root.right= self.pruneTree(root.right)
        if not root.left and not root.right and root.val ==0:
            return None
        
        return root