human
Sort the array in a given index range | Function to sort the elements of the array from index a to index b.
Variables to store start and end of the index range.
Temporary array.
Sort the temporary array.
Modifying original array with temporary array elements.
Print the modified array.
Driver code.
length of the array"
How can the above be solved in Python?
assistant
#Here is code to sort the array in a given index range and the other steps required.
 def partSort ( arr , N , a , b ) :
	l = min ( a , b )
	r = max ( a , b )
	temp = [ 0 for i in range ( r - l + 1 ) ]
	j = 0
	for i in range ( l , r + 1 , 1 ) :
		temp [ j ] = arr [ i ]
		j += 1
	temp . sort ( reverse = False )
	j = 0
	for i in range ( l , r + 1 , 1 ) :
		arr [ i ] = temp [ j ]
		j += 1
	for i in range ( 0 , N , 1 ) :
		print ( arr [ i ] , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 7 , 8 , 4 , 5 , 2 ]
	a = 1
	b = 4
	N = len ( arr )
	partSort ( arr , N , a , b )