human
Count lexicographically increasing K | Function to count K - length strings from first N alphabets.
To keep track of column sum in dp.
Auxiliary 2d dp array.
Initialize dp [ 0 ] [ i ] = 1 and update the column_sum.
Iterate for K times.
Iterate for N times.
dp [ i ] [ j ] : Stores the number of ways to form i - length strings consisting of j letters.
Update the column_sum.
Print number of ways to arrange K - length strings with N alphabets.
Driver Code.
Given N and K.
Function Call"
How can the above be solved in Python?

Give me a code to count lexicographically increasing K and the other steps required?
assistant
#Here is code to count lexicographically increasing K and the other steps required.
 def waysToArrangeKLengthStrings ( N , K ) :
	column_sum = [ 0 for i in range ( N + 1 ) ]
	i = 0
	j = 0
	dp = [ [ 0 for i in range ( N + 1 ) ] for j in range ( K + 1 ) ]
	for i in range ( N + 1 ) :
		dp [ 0 ] [ i ] = 1
		column_sum [ i ] = 1
	for i in range ( 1 , K + 1 ) :
		for j in range ( 1 , N + 1 ) :
			dp [ i ] [ j ] += column_sum [ j - 1 ]
			column_sum [ j ] += dp [ i ] [ j ]
	print ( dp [ K ] [ N ] )
if __name__ == ' _ _ main _ _ ' :
	N = 5
	K = 2
	waysToArrangeKLengthStrings ( N , K )