human
Find the maximum occurring character after performing the given operations | Function to find the maximum occurring character.
Initialize count of zero and one.
Iterate over the given string.
Count the zeros.
Count the ones.
Iterate over the given string.
Check if character is * then continue.
Check if first character after * is X.
Add all * to the frequency of X.
Set prev to the i - th character.
Check if first character after * is Y.
Set prev to the i - th character.
Check if prev character is 1 and current character is 0.
Half of the * will be converted to 0.
Half of the * will be converted to 1.
Check if prev and current are 1.
All * will get converted to 1.
No * can be replaced by either 0 or 1.
Prev becomes the ith character.
Check if prev and current are 0.
All * will get converted to 0.
If frequency of 0 is more.
If frequency of 1 is more.
Given string.
Function call"
How can the above be solved in Python?
 Can you provide a code to find the maximum occurring character after performing the given operations and the other steps required?
assistant
#Here is code to find the maximum occurring character after performing the given operations and the other steps required.
 def solve ( S ) :
	count_0 = 0
	count_1 = 0
	prev = - 1
	for i in range ( len ( S ) ) :
		if ( S [ i ] == '0' ) :
			count_0 += 1
		elif ( S [ i ] == '1' ) :
			count_1 += 1
	for i in range ( len ( S ) ) :
		if ( S [ i ] == ' * ' ) :
			continue
		elif ( S [ i ] == '0' and prev == - 1 ) :
			count_0 = count_0 + i
			prev = i
		elif ( S [ i ] == '1' and prev == - 1 ) :
			prev = i
		elif ( S [ prev ] == '1' and S [ i ] == '0' ) :
			count_0 = count_0 + ( i - prev - 1 ) / 2
			count_1 = count_1 + ( i - prev - 1 ) // 2
			prev = i
		elif ( S [ prev ] == '1' and S [ i ] == '1' ) :
			count_1 = count_1 + ( i - prev - 1 )
			prev = i
		elif ( S [ prev ] == '0' and S [ i ] == '1' ) :
			prev = i
		elif ( S [ prev ] == '0' and S [ i ] == '0' ) :
			count_0 = count_0 + ( i - prev - 1 )
			prev = i
	if ( count_0 > count_1 ) :
		print ( "0" )
	elif ( count_1 > count_0 ) :
		print ( "1" )
	else :
		print ( " - 1" )
str = " * *0 * * 1 * * *0"
solve ( str )