human
Permutation present at the middle of lexicographic ordering of permutations of at most length N made up integers up to K | Function that finds the middle the lexicographical smallest sequence.
If K is even.
First element is K / 2.
Remaining elements of the sequence are all integer K.
Stores the sequence when K is odd.
Iterate over the range [ 0 , N / 2 ].
Check if the sequence ends with in 1 or not.
Remove the sequence ending in 1.
If it doesn 't end in 1.
Decrement by 1.
Insert K to the sequence till its size is N.
Prthe sequence stored in the vector.
Driver Code"
Solution in Python:
 ... What is a code to permutation present at the middle of lexicographic ordering of permutations of at most length N made up integers up to K and the other steps required?
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#Here is code to permutation present at the middle of lexicographic ordering of permutations of at most length N made up integers up to K and the other steps required.
 def lexiMiddleSmallest ( K , N ) :
	if ( K % 2 == 0 ) :
		print ( K // 2 , end = " ▁ " )
		for i in range ( N - 1 ) :
			print ( K , end = " ▁ " )
		print ( )
		return
	a = [ ( K + 1 ) // 2 ] * ( N )
	for i in range ( N // 2 ) :
		if ( a [ - 1 ] == 1 ) :
			del a [ - 1 ]
		else :
			a [ - 1 ] -= 1
			while ( len ( a ) < N ) :
				a . append ( K )
	for i in a :
		print ( i , end = " ▁ " )
	print ( )
if __name__ == ' _ _ main _ _ ' :
	K , N = 2 , 4
	lexiMiddleSmallest ( K , N )