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Euclidâ €“ Mullin Sequence | Function to return the smallest prime factor of n.
Initialize i = 2.
While i <= sqrt ( n ).
If n is divisible by i.
Increment i.
Function to print the first n terms of the required sequence.
To store the product of the previous terms.
Traverse the prime numbers.
Current term will be smallest prime factor of ( 1 + product of all previous terms ).
Print the current term.
Update the product.
Find the first 14 terms of the sequence"
How can the above be solved in Python?
 Can you provide a code to euclidâ €“ Mullin Sequence and the other steps required?
assistant
#Here is code to euclidâ €“ Mullin Sequence and the other steps required.
 def smallestPrimeFactor ( n ) :
	i = 2
	while ( i * i ) <= n :
		if n % i == 0 :
			return i
		i += 1
	return n
def solve ( n ) :
	product = 1
	i = 0
	while i < n :
		num = smallestPrimeFactor ( product + 1 )
		print ( num , end = ' ▁ ' )
		product = product * num
		i += 1
b = 14
solve ( b )