human
Count numbers less than N whose modulo with A is equal to B | Function to count numbers less than N , whose modulo with A gives B.
If the value of B at least A.
If the value of B is 0 or not.
Stores the resultant count of numbers less than N.
Update the value of ans.
Print the value of ans.
Driver Code"
How can the above be solved in Python?
 ... Can you provide a code to count numbers less than N whose modulo with A is equal to B and the other steps required?
assistant
#Here is code to count numbers less than N whose modulo with A is equal to B and the other steps required.
 def countValues ( A , B , C ) :
	if ( B >= A ) :
		print ( 0 )
		return
	if ( B == 0 ) :
		print ( C // A )
		return
	ans = C // A
	if ( ans * A + B <= C ) :
		ans += 1
	print ( ans )
if __name__ == ' _ _ main _ _ ' :
	A = 6
	B = 3
	N = 15
	countValues ( A , B , N )