human
Sum of numbers obtained by the count of set and non | Functino to find the number after processing the diagonal elements.
Store the required number.
Checking for each position.
Store the number of set bits & non - set bits at position i.
Traverse the diagonal elements.
Update count of S if current element is set at position i.
Else update NS.
If number of set bits is > number of non - set bits , add set bits value to the ans.
Return the answer.
Function to find the sum of the numbers generated after processing both the diagonals of the matrix.
Store the primary diagonal elements.
Store the secondary diagonal elements.
Function Call to get the required numbers and return their sum.
Driver Code.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to sum of numbers obtained by the count of set and non and the other steps required.
 def processDiagonal ( arr ) :
	ans = 0
	getBit = 1
	for i in range ( 32 ) :
		S = 0
		NS = 0
		for j in arr :
		if getBit & j :
			S += 1
		else :
			NS += 1
		if S > NS :
		ans += 2 ** i
		getBit <<= 1
	return ans
def findSum ( mat ) :
	i = 0
	j = 0
	priDiag = [ ]
	while i < len ( mat ) :
		priDiag . append ( mat [ i ] [ j ] )
		i += 1
		j += 1
	i = 0
	j = len ( mat ) - 1
	secDiag = [ ]
	while i < len ( mat ) :
		secDiag . append ( mat [ i ] [ j ] )
		i += 1
		j -= 1
	return processDiagonal ( priDiag ) + processDiagonal ( secDiag )
mat = [ [ 1 , 2 , 3 ] , [ 4 , 5 , 6 ] , [ 7 , 8 , 9 ] ]
print ( findSum ( mat ) )