human
I found an interesting problem on https://leetcode.com/problems/minimum-falling-path-sum-ii/:
Given a square grid of integers arr, a falling path with non-zero shifts is a choice of exactly one element from each row of arr, such that no two elements chosen in adjacent rows are in the same column.
Return the minimum sum of a falling path with non-zero shifts.
 
Example 1:
Input: arr = [[1,2,3],[4,5,6],[7,8,9]]
Output: 13
Explanation: 
The possible falling paths are:
[1,5,9], [1,5,7], [1,6,7], [1,6,8],
[2,4,8], [2,4,9], [2,6,7], [2,6,8],
[3,4,8], [3,4,9], [3,5,7], [3,5,9]
The falling path with the smallest sum is [1,5,7], so the answer is 13.

 
Constraints:

1 <= arr.length == arr[i].length <= 200
-99 <= arr[i][j] <= 99

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python program you requested.

class Solution:
    def minFallingPathSum(self, arr: List[List[int]]) -> int:
        
        # [[1,2,3],
        #  [4,5,6],
        #  [7,8,9]]
        
        # do a dp where dp(i,j) returns the minimum path starting from (i,j)
        
        if not arr:
            return 0
        
        m = len(arr)
        n = len(arr[0])
        INF = float('inf')
        dp = [[INF]*n for _ in range(m)]
        
        dp[-1] = arr[-1]
        
        for i in range(m-2,-1,-1):
            for j in range(n):
                dp[i][j] = min(dp[i+1][:j]+dp[i+1][j+1:])+arr[i][j]
        print(dp)
        return min(dp[0])