human
Check if the remainder of N | Function to check if a number holds the condition ( N - 1 ) ! % N = N - 1.
Corner cases.
Number divisible by 2 or 3 are not prime.
Iterate from 5 and keep checking for prime.
Function to check the expression for the value N.
Driver code"
How can the above be solved in Python?

Give me a code to check if the remainder of N and the other steps required?
assistant
#Here is code to check if the remainder of N and the other steps required.
 def isPrime ( n ) :
	if ( n == 1 ) :
		return True
	if ( n <= 3 ) :
		return True
	if ( ( n % 2 == 0 ) or ( n % 3 == 0 ) ) :
		return False
	i = 5
	while ( i * i <= n ) :
		if ( ( n % i == 0 ) or ( n % ( i + 2 ) == 0 ) ) :
			return False ;
			i += 6
	return true ;
def checkExpression ( n ) :
	if ( isPrime ( n ) ) :
		print ( " Yes " )
	else :
		print ( " No " )
if __name__ == ' _ _ main _ _ ' :
	N = 3
	checkExpression ( N )