human
Count subsets consisting of each element as a factor of the next element in that subset | Function to find number of subsets satisfying the given condition.
Stores number of required sets.
Stores maximum element of arr [ ] that defines the size of sieve.
Iterate through the arr [ ].
If current element > maxE , then update maxE.
Declare an array sieve of size N + 1.
Mark all elements corresponding in the array , by one as there will always exists a singleton set.
Iterate from range [ 1 , N ].
If element is present in array.
Traverse through all its multiples <= n.
Update them if they are present in array.
Iterate from the range [ 1 , N ].
Update the value of cnt.
Prthe result.
Driver Code.
Function Call"
Solution in Python:
 ... What is a code to count subsets consisting of each element as a factor of the next element in that subset and the other steps required?
assistant
#Here is code to count subsets consisting of each element as a factor of the next element in that subset and the other steps required.
 def countSets ( arr , n ) :
	cnt = 0
	maxE = - 1
	for i in range ( n ) :
		if ( maxE < arr [ i ] ) :
			maxE = arr [ i ]
	sieve = [ 0 ] * ( maxE + 1 )
	for i in range ( n ) :
		sieve [ arr [ i ] ] = 1
	for i in range ( 1 , maxE + 1 ) :
		if ( sieve [ i ] != 0 ) :
			for j in range ( i * 2 , maxE + 1 , i ) :
				if ( sieve [ j ] != 0 ) :
					sieve [ j ] = ( sieve [ j ] + sieve [ i ] ) % 1000000007
	for i in range ( maxE + 1 ) :
		cnt = ( cnt % 1000000007 + sieve [ i ] % 1000000007 ) % 1000000007
	print ( cnt % 1000000007 )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 16 , 18 , 6 , 7 , 2 , 19 , 20 , 9 ]
	N = len ( arr )
	countSets ( arr , N )