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Count all pairs of an array which differ in K bits | Utility function to count total ones in a number.
Function to count pairs of K different bits.
initialize final answer.
Check for K differ bit.
Driver code"
Solution in Python:

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Can you provide a code to count all pairs of an array which differ in K bits and the other steps required?
assistant
#Here is code to count all pairs of an array which differ in K bits and the other steps required.
 def bitCount ( n ) :
	count = 0
	while ( n ) :
		if ( n & 1 ) :
			count += 1
		n >>= 1
	return count
def countPairsWithKDiff ( arr , n , k ) :
	ans = 0
	for i in range ( 0 , n - 1 , 1 ) :
		for j in range ( i + 1 , n , 1 ) :
			xoredNum = arr [ i ] ^ arr [ j ]
			if ( k == bitCount ( xoredNum ) ) :
				ans += 1
	return ans
if __name__ == ' _ _ main _ _ ' :
	k = 2
	arr = [ 2 , 4 , 1 , 3 , 1 ]
	n = len ( arr )
	print ( " Total ▁ pairs ▁ for ▁ k ▁ = " , k , " are " , countPairsWithKDiff ( arr , n , k ) )