human
Minimum swaps required to bring all elements less than or equal to k together | Utility function to find minimum swaps required to club all elements less than or equals to k together.
Find count of elements which are less than equals to k.
Find unwanted elements in current window of size 'count  .
Initialize answer with ' bad ' value of current window.
Decrement count of previous window.
Increment count of current window.
Update ans if count of ' bad ' is less in current window.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to minimum swaps required to bring all elements less than or equal to k together and the other steps required.
 def minSwap ( arr , n , k ) :
	count = 0
	for i in range ( 0 , n ) :
		if ( arr [ i ] <= k ) :
			count = count + 1
	bad = 0
	for i in range ( 0 , count ) :
		if ( arr [ i ] > k ) :
			bad = bad + 1
	ans = bad
	j = count
	for i in range ( 0 , n ) :
		if ( j == n ) :
			break
		if ( arr [ i ] > k ) :
			bad = bad - 1
		if ( arr [ j ] > k ) :
			bad = bad + 1
		ans = min ( ans , bad )
		j = j + 1
	return ans
arr = [ 2 , 1 , 5 , 6 , 3 ]
n = len ( arr )
k = 3
print ( minSwap ( arr , n , k ) )
arr1 = [ 2 , 7 , 9 , 5 , 8 , 7 , 4 ]
n = len ( arr1 )
k = 5
print ( minSwap ( arr1 , n , k ) )