human
I found an interesting problem on https://leetcode.com/problems/distant-barcodes/:
In a warehouse, there is a row of barcodes, where the i-th barcode is barcodes[i].
Rearrange the barcodes so that no two adjacent barcodes are equal.  You may return any answer, and it is guaranteed an answer exists.
 
Example 1:
Input: [1,1,1,2,2,2]
Output: [2,1,2,1,2,1]

Example 2:
Input: [1,1,1,1,2,2,3,3]
Output: [1,3,1,3,2,1,2,1]

 
Note:

1 <= barcodes.length <= 10000
1 <= barcodes[i] <= 10000

I tried it in Python, but could not do it. Can you solve it?

 Write me a the Python code you requested?
assistant
#Here is the Python code you requested.

from collections import Counter
class Solution:
    def rearrangeBarcodes(self, barcodes: List[int]) -> List[int]:
        if barcodes is None or len(barcodes) == 0:
            return []
        if len(barcodes) == 1:
            return barcodes

        counter = Counter(barcodes)
        num_occurrences = sorted(counter, key = lambda x: counter.get(x), reverse=True)
        elements = dict()

        for elem in num_occurrences:
            elements[elem] = counter[elem]

        output = [None] * len(barcodes)
        item_index = 0
        index = 0
        value = num_occurrences[0]
        value_index= 0
        for i in range(len(barcodes)):
            while output[index] is not None or output[index - 1] == value:
                index += 1
                index %= len(barcodes)
            output[index] = value
            item_index += 1
            index += 1
            index %= len(barcodes)
            if elements[value] == 1:
                value_index += 1
                if value_index >= len(num_occurrences):
                    return output
                value = num_occurrences[value_index]
            else:
                elements[value] -= 1

        return output