human
Solve the following python programming problem given the following code:
def group_milestones(milestones, include_completed) : 
    'Group milestones into "open with due date", "open with no due date",
    and possibly "completed". Return a list of (label, milestones) tuples.' 
    def category(m) : 
        return (1 if m.is_completed else (2 if m.due else 3)) 
(open_due_milestones, open_not_due_milestones, closed_milestones) = partition ([(m, category (m)) for m in open_due_milestones], (2, 3, 1)) 
    groups = [(_ ('Open (by due date)'), open_due_milestones), (_ ('Open (no due date)'), open_not_due_milestones)] 
    if include_completed : 
        groups.append ((_ ('Closed'), closed_milestones)) 
return groups 

    
    

    Fix the buggy line: (open_due_milestones, open_not_due_milestones, closed_milestones) = partition ([(m, category (m)) for m in open_due_milestones], (2, 3, 1))
assistant
#Here is Python code to fix the buggy line: (open_due_milestones, open_not_due_milestones, closed_milestones) = partition ([(m, category (m)) for m in open_due_milestones], (2, 3, 1))
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(open_due_milestones, open_not_due_milestones, closed_milestones) = partition ([(m, category (m)) for m in milestones], (2, 3, 1))