human
Minimum adjacent swaps required to Sort Binary array | Function to find minimum swaps to sort an array of 0 s and 1 s ..
Array to store count of zeroes.
Count number of zeroes on right side of every one ..
Count total number of swaps by adding number of zeroes on right side of every one ..
Driver code"
How can the above be solved in Python?

=====
Write me a code to minimum adjacent swaps required to Sort Binary array and the other steps required?
assistant
#Here is code to minimum adjacent swaps required to Sort Binary array and the other steps required.
 def findMinSwaps ( arr , n ) :
	noOfZeroes = [ 0 ] * n
	count = 0
	noOfZeroes [ n - 1 ] = 1 - arr [ n - 1 ]
	for i in range ( n - 2 , - 1 , - 1 ) :
		noOfZeroes [ i ] = noOfZeroes [ i + 1 ]
		if ( arr [ i ] == 0 ) :
			noOfZeroes [ i ] = noOfZeroes [ i ] + 1
	for i in range ( 0 , n ) :
		if ( arr [ i ] == 1 ) :
			count = count + noOfZeroes [ i ]
	return count
arr = [ 0 , 0 , 1 , 0 , 1 , 0 , 1 , 1 ]
n = len ( arr )
print ( findMinSwaps ( arr , n ) )