human
Balance a string after removing extra brackets | Print balanced and remove extra brackets from string.
Maintain a count for opening brackets Traversing string.
check if opening bracket.
print str [ i ] and increment count by 1.
check if closing bracket and count != 0.
decrement count by 1.
if str [ i ] not a closing brackets print it.
balanced brackets if opening brackets are more then closing brackets.
print remaining closing brackets.
Driver code"
Solution in Python:
 ... What is a code to balance a string after removing extra brackets and the other steps required?
assistant
#Here is code to balance a string after removing extra brackets and the other steps required.
 def balancedString ( str ) :
	count , i = 0 , 0
	n = len ( str )
	for i in range ( n ) :
		if ( str [ i ] == ' ( ' ) :
			print ( str [ i ] , end = " " )
			count += 1
		elif ( str [ i ] == ' ) ' and count != 0 ) :
			print ( str [ i ] , end = " " )
			count -= 1
		elif ( str [ i ] != ' ) ' ) :
			print ( str [ i ] , end = " " )
	if ( count != 0 ) :
		for i in range ( count ) :
			print ( " ) " , end = " " )
if __name__ == ' _ _ main _ _ ' : str = " gau ) ra ) v ( ku ( mar ( rajput ) ) "
	balancedString ( str )