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Split array into two subsequences having minimum count of pairs with sum equal to X | Function to split the array into two subsequences.
Stores the two subsequences.
Flag to set / reset to split arrays elements alternately into two arrays.
Traverse the given array.
If 2 * arr [ i ] is less than X.
Push element into the first array.
If 2 * arr [ i ] is greater than X.
Push element into the second array.
If 2 * arr [ i ] is equal to X.
Alternatively place the elements into the two arrays.
Print both the arrays.
Driver Code.
Size of the array.
Function Call"
Solution in Python:
assistant
#Here is code to split array into two subsequences having minimum count of pairs with sum equal to X and the other steps required.
 def solve ( arr , N , X ) :
	A = [ ]
	B = [ ]
	c = 0
	for i in range ( N ) :
		if ( ( 2 * arr [ i ] ) < X ) :
			A . append ( arr [ i ] )
		elif ( ( 2 * arr [ i ] ) > X ) :
			B . append ( arr [ i ] )
		else :
			if ( c % 2 == 0 ) :
				A . append ( arr [ i ] )
			else :
				B . append ( arr [ i ] )
			c += 1
	print ( " The ▁ First ▁ Array ▁ is ▁ - ▁ " , end = " ▁ " )
	for i in range ( len ( A ) ) :
		print ( A [ i ] , end = " ▁ " )
	print ( )
	print ( " The ▁ Second ▁ Array ▁ is ▁ - ▁ " , end = " ▁ " )
	for i in range ( len ( B ) ) :
		print ( B [ i ] , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 5 , 4 , 3 , 6 , 2 , 4 , 3 ]
	X = 7
	N = len ( arr )
	solve ( arr , N , X )