human
Complete the below
def clear_lock(remote=None):

    ''''Clear update.lk
    ``remote`` can either be a dictionary containing repo configuration
    information, or a pattern. If the latter, then remotes for which the URL
    matches the pattern will be locked.'
    '''
 ... Write me a the Python program you requested?
assistant
#Here is the Python program you requested.
    def _do_clear_lock(repo):
        def _add_error(errlist, repo, exc):
            msg = 'Unable    to    remove    update    lock    for    {0}    ({1}):    {2}    '.format(repo['url'], repo['lockfile'], exc)
            log.debug(msg)
            errlist.append(msg)
        success = []
        failed = []
        if os.path.exists(repo['lockfile']):
            try:
                os.remove(repo['lockfile'])
            except OSError as exc:
                if (exc.errno == errno.EISDIR):
                    try:
                        shutil.rmtree(repo['lockfile'])
                    except OSError as exc:
                        _add_error(failed, repo, exc)
                else:
                    _add_error(failed, repo, exc)
            else:
                msg = 'Removed    lock    for    {0}'.format(repo['url'])
                log.debug(msg)
                success.append(msg)
        return (success, failed)
    if isinstance(remote, dict):
        return _do_clear_lock(remote)
    cleared = []
    errors = []
    for repo in init():
        if remote:
            try:
                if (remote not in repo['url']):
                    continue
            except TypeError:
                if (six.text_type(remote) not in repo['url']):
                    continue
        (success, failed) = _do_clear_lock(repo)
        cleared.extend(success)
        errors.extend(failed)
    return (cleared, errors)