human
Minimize the total number of teddies to be distributed | Python implementation of the above approach.
Initializing one tablet for each student.
if left adjacent is having higher marks review and change all the dp values assigned before until assigned dp values are found wrong according to given constrains.
if right adjacent is having higher marks add one in dp of left adjacent and assign to right one.
n number of students.
marks of students.
solution of problem"
Solution in Python:
 ... Give me a code to minimize the total number of teddies to be distributed and the other steps required?
assistant
#Here is code to minimize the total number of teddies to be distributed and the other steps required.
 def fun ( marks , n ) :
	dp = [ 1 for i in range ( 0 , n ) ]
	for i in range ( 0 , n - 1 ) :
		if marks [ i ] > marks [ i + 1 ] :
			temp = i
			while True :
				if marks [ temp ] > marks [ temp + 1 ] and temp >= 0 :
					if dp [ temp ] > dp [ temp + 1 ] :
						temp -= 1
						continue
					else :
						dp [ temp ] = dp [ temp + 1 ] + 1
						temp -= 1
				else :
					break
		elif marks [ i ] < marks [ i + 1 ] :
			dp [ i + 1 ] = dp [ i ] + 1
	return ( sum ( dp ) )
n = 6
marks = [ 1 , 4 , 5 , 2 , 2 , 1 ]
print ( fun ( marks , n ) )