human
Maximize product obtained by taking one element from each array of a given list | Function to return the product of 2 numbers.
If any of the two numbers is None.
Otherwise , return the product.
Function to calculate maximum product by taking only one element from each array present in the list.
Find the maximum and minimum present in the current array.
If last index is reached , then return the highest ( positive ) and lowest ( negative ) values.
Store the positive and negative products returned by calculating for the remaining arrays.
Store highest positive product.
Store product of highest with negative.
Store product of lowest with positive.
Store lowest negative product.
Return the maximum positive and minimum negative product.
Count of given arrays.
Given list of N arrays.
Store the maximum positive and minimum negative product possible.
Print the maximum product"
How can the above be solved in Python?
 Can you provide a code to maximize product obtained by taking one element from each array of a given list and the other steps required?
assistant
#Here is code to maximize product obtained by taking one element from each array of a given list and the other steps required.
 def findProduct ( number_1 , number_2 ) :
	if ( number_1 == None or number_2 == None ) :
		return 0
	else :
		return number_1 * number_2
def calculateProduct ( List , index ) :
	highest = max ( List [ index ] )
	lowest = min ( List [ index ] )
	if ( index + 1 == len ( List ) ) :
		if ( lowest < 0 and highest >= 0 ) :
			return [ highest , lowest ]
		elif ( lowest <= 0 and highest <= 0 ) :
			return [ None , lowest ]
		elif ( lowest >= 0 and highest >= 0 ) :
			return [ highest , None ]
	[ positive , negative ] = calculateProduct ( List , index + 1 )
	highPos = findProduct ( highest , positive )
	highNeg = findProduct ( highest , negative )
	lowPos = findProduct ( lowest , positive )
	lowNeg = findProduct ( lowest , negative )
	if ( lowest < 0 and highest >= 0 ) :
		return [ max ( highPos , lowNeg ) , min ( highNeg , lowPos ) ]
	elif ( lowest <= 0 and highest <= 0 ) :
		return [ lowNeg , lowPos ]
	elif ( lowest >= 0 and highest >= 0 ) :
		return [ max ( lowPos , highPos ) , min ( lowNeg , highNeg ) ]
N = 2
arr = [ [ - 3 , - 4 ] , [ 1 , 2 , - 3 ] ]
positive , negative = calculateProduct ( arr , 0 )
print ( positive )