human
Can you provide a code to check n ^ 2 and the other steps required given the following:
Check n ^ 2 | Check a number is prime or not.
run a loop upto square of given number.
Check if n ^ 2 - m ^ 2 is prime.
Driver code"
Solution in Python:
assistant
#Here is code to check n ^ 2 and the other steps required.
 def isprime ( x ) :
	for i in range ( 2 , math . sqrt ( x ) ) :
		if ( x % i == 0 ) :
			return False ;
	return True ;
def isNSqMinusnMSqPrime ( m , n ) :
	if ( n - m == 1 and isprime ( m + n ) ) :
		return True ;
	else :
		return False ;
m = 13 ;
n = 16 ;
if ( isNSqMinusnMSqPrime ( m , n ) ) :
	print ( " YES " ) ;
else :
	print ( " NO " ) ;