human
I found an interesting problem on https://leetcode.com/problems/merge-intervals/:
Given a collection of intervals, merge all overlapping intervals.

Example 1:

Input: [[1,3],[2,6],[8,10],[15,18]]
Output: [[1,6],[8,10],[15,18]]
Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6].

Example 2:

Input: [[1,4],[4,5]]
Output: [[1,5]]
Explanation: Intervals [1,4] and [4,5] are considerred overlapping.

I tried it in Python, but could not do it. Can you solve it?

Write me a the Python code you requested?
assistant
#Here is the Python code you requested.

# Definition for an interval.
 # class Interval:
 #     def __init__(self, s=0, e=0):
 #         self.start = s
 #         self.end = e
 
 class Solution:
     def merge(self, intervals):
         si = sorted(intervals, key=lambda x: (x.start, x.end))
         cur = 1  # index of current tuple
         while cur < len(si):
             # check intersection of current and previous tuple
             # if end of previous is less than begin of current
             # there are the intersection, we should merge them
             # into the bigger interval
             if si[cur - 1].end >= si[cur].start:
                 # change end of the interval(tuple)
                 si[cur - 1] = Interval(si[cur - 1].start, max(si[cur - 1].end, si[cur].end))
                 # delete unnecessary interval(tuple)
                 del si[cur]
             # there are no intersection, go to the next tuple
             else:
                 cur += 1
         return si