human
Bitwise XOR of all odd numbers from a given range | Function to calculate Bitwise XOR of odd numbers in the range [ 1 , N ].
N & 3 is equivalent to n % 4.
If n is multiple of 4.
If n % 4 gives remainder 1.
If n % 4 gives remainder 2.
If n % 4 gives remainder 3.
Function to find the XOR of odd numbers less than or equal to N.
If number is even.
Prthe answer.
If number is odd.
Prthe answer.
Driver Code.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to bitwise XOR of all odd numbers from a given range and the other steps required.
 def findXOR ( n ) :
	if ( n % 4 == 0 ) :
		return n ;
	elif ( n % 4 == 1 ) :
		return 1 ;
	elif ( n % 4 == 2 ) :
		return n + 1 ;
	elif ( n % 4 == 3 ) :
		return 0 ;
def findOddXOR ( n ) :
	if ( n % 2 == 0 ) :
		print ( ( ( findXOR ( n ) ) ^ ( 2 * findXOR ( n // 2 ) ) ) ) ;
	else :
		print ( ( ( findXOR ( n ) ) ^ ( 2 * findXOR ( ( n - 1 ) // 2 ) ) ) ) ;
if __name__ == ' _ _ main _ _ ' :
	N = 11 ;
	findOddXOR ( N ) ;