human
Give me a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/koko-eating-bananas/:
Koko loves to eat bananas.  There are N piles of bananas, the i-th pile has piles[i] bananas.  The guards have gone and will come back in H hours.
Koko can decide her bananas-per-hour eating speed of K.  Each hour, she chooses some pile of bananas, and eats K bananas from that pile.  If the pile has less than K bananas, she eats all of them instead, and won't eat any more bananas during this hour.
Koko likes to eat slowly, but still wants to finish eating all the bananas before the guards come back.
Return the minimum integer K such that she can eat all the bananas within H hours.
 
Example 1:
Input: piles = [3,6,7,11], H = 8
Output: 4
Example 2:
Input: piles = [30,11,23,4,20], H = 5
Output: 30
Example 3:
Input: piles = [30,11,23,4,20], H = 6
Output: 23

 
Constraints:

1 <= piles.length <= 10^4
piles.length <= H <= 10^9
1 <= piles[i] <= 10^9

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution:
    def minEatingSpeed(self, piles: List[int], H: int) -> int:
        min_speed = 1
        max_speed = max(piles)
        while min_speed <=max_speed :
            pivot = min_speed + (max_speed - min_speed)//2  
            r = sum([math.ceil(x/pivot) for x in piles])
            #r=sum(hours)
            if r == H:
                return pivot
            elif min_speed==max_speed and r>=H:
                return pivot+1
            elif r < H:
                max_speed = pivot-1
            elif r > H:
                min_speed = pivot+1
                
        return pivot