human
Give me a code to count of integers up to N which are non divisors and non coprime with N and the other steps required given the following:
Count of integers up to N which are non divisors and non coprime with N | Function to return the count of integers less than N satisfying given conditions.
Stores Euler counts.
Store Divisor counts.
Based on Sieve of Eratosthenes.
Update phi values of all multiples of i.
Update count of divisors.
Return the final count.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count of integers up to N which are non divisors and non coprime with N and the other steps required.
 def count ( n ) :
	phi = [ 0 ] * ( n + 1 )
	divs = [ 0 ] * ( n + 1 )
	for i in range ( 1 , n + 1 ) :
		phi [ i ] += i
		for j in range ( i * 2 , n + 1 , i ) :
			phi [ j ] -= phi [ i ] ;
		for j in range ( i , n + 1 , i ) :
			divs [ j ] += 1
	return ( n - phi [ n ] - divs [ n ] + 1 ) ;
if __name__ == ' _ _ main _ _ ' :
	N = 42
	print ( count ( N ) )