human
Give me a Python program to print the information of each node in the following format ordered by IDs: given the following:
A graph G = (V, E) is a data structure where V is a finite set of vertices and E is a binary relation on V represented by a set of edges. Fig. 1 illustrates an example of a graph (or graphs).

Fig. 1

A free tree is a connnected, acyclic, undirected graph. A rooted tree is a free tree in which one of the vertices is distinguished from the others. A vertex of a rooted tree is called "node."

Your task is to write a program which reports the following information for each node u of a given rooted tree T:

* node ID of u
* parent of u
* depth of u
* node type (root, internal node or leaf)
* a list of chidlren of u


If the last edge on the path from the root r of a tree T to a node x is (p, x), then p is the parent of x, and x is a child of p. The root is the only node in T with no parent.

A node with no children is an external node or leaf. A nonleaf node is an internal node

The number of children of a node x in a rooted tree T is called the degree of x.

The length of the path from the root r to a node x is the depth of x in T.

Here, the given tree consists of n nodes and evey node has a unique ID from 0 to n-1.

Fig. 2 shows an example of rooted trees where ID of each node is indicated by a number in a circle (node). The example corresponds to the first sample input.

Fig. 2

Note

You can use a left-child, right-sibling representation to implement a tree which has the following data:

* the parent of u
* the leftmost child of u
* the immediate right sibling of u

Constraints

* 1 ≤ n ≤ 100000

Input

The first line of the input includes an integer n, the number of nodes of the tree.

In the next n lines, the information of each node u is given in the following format:

id k c1 c2 ... ck

where id is the node ID of u, k is the degree of u, c1 ... ck are node IDs of 1st, ... kth child of u. If the node does not have a child, the k is 0.

Output

Print the information of each node in the following format ordered by IDs:

node id: parent = p, depth = d, type, [c1...ck]

p is ID of its parent....
Using python3 can you solve the prior task?
assistant
#Here is Python program to print the information of each node in the following format ordered by IDs:
.

class Node:
    def __init__(self):
        self.parent_id = -1
        self.depth = 0
        self.children = []

global nodes

def calc_depth(node_id,arg_depth):
    nodes[node_id].depth = arg_depth
    for child in nodes[node_id].children:
        calc_depth(child, arg_depth+1)

V = int(input())

nodes = []
# V個のノードを用意
for loop in range(V):
    node = Node()
    nodes.append(node)

# 親子関係取得
for loop in range(V):
    table = list(map(int,input().split()))
    node_id = table[0]
    num = table[1]

    for i in range(num):
        child_id = table[2+i]
        nodes[node_id].children.append(child_id)
        nodes[child_id].parent_id = node_id

# 値を探して深さを計算する
for i in range(V):
    if nodes[i].parent_id == -1:
        calc_depth(i,0)
        break

for i in range(V):
    print("node %d: parent = %d, depth = %d, "%(i,nodes[i].parent_id,nodes[i].depth),end = "")

    if nodes[i].parent_id == -1:
        print("root,",end ="") #根
    else:
        if len(nodes[i].children) == 0: #葉
            print("leaf,",end ="")
        else: #節
            print("internal node,",end ="")
    print(" [",end = "")
    print(", ".join(map(str,nodes[i].children)),end = "")
    print("]")