human
Number of substrings with each character occurring even times | Function to count substrings having even frequency of each character.
Stores the count of a character.
Stores bitmask.
Stores the count of substrings with even count of each character.
Traverse the string S.
Flip the ord ( i ) - 97 bits in pre.
Increment the count by hash [ pre ].
Increment count of pre in hash.
Return the total count obtained.
Driver Code"
Solution in Python:

Give me a code to number of substrings with each character occurring even times and the other steps required?
assistant
#Here is code to number of substrings with each character occurring even times and the other steps required.
 def subString ( s , n ) :
	hash = { 0 : 1 }
	pre = 0
	count = 0
	for i in s :
		pre ^= ( 1 << ord ( i ) - 97 )
		count += hash . get ( pre , 0 )
		hash [ pre ] = hash . get ( pre , 0 ) + 1
	return count
S = " abbaa "
N = len ( S )
print ( subString ( S , N ) )