human
Check for balanced parentheses in an expression | O ( 1 ) space | Function1 to match closing bracket.
Function1 to match opening bracket.
Function to check balanced parentheses.
helper variables.
Handling case of opening parentheses.
Handling case of closing parentheses.
If corresponding matching opening parentheses doesn 't lie in given  interval return 0.
else continue.
If corresponding closing parentheses doesn 't lie in given interval, return 0.
if found , now check for each opening and closing parentheses in this interval.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to check for balanced parentheses in an expression and the other steps required.
 def matchClosing ( X , start , end , open , close ) :
	c = 1
	i = start + 1
	while ( i <= end ) :
		if ( X [ i ] == open ) :
			c += 1
		elif ( X [ i ] == close ) :
			c -= 1
		if ( c == 0 ) :
			return i
		i += 1
	return i
def matchingOpening ( X , start , end , open , close ) :
	c = - 1
	i = end - 1
	while ( i >= start ) :
		if ( X [ i ] == open ) :
			c += 1
		elif ( X [ i ] == close ) :
			c -= 1
		if ( c == 0 ) :
			return i
		i -= 1
	return - 1
def isBalanced ( X , n ) :
	for i in range ( n ) :
		if ( X [ i ] == ' ( ' ) :
			j = matchClosing ( X , i , n - 1 , ' ( ' , ' ) ' )
		elif ( X [ i ] == ' { ' ) :
			j = matchClosing ( X , i , n - 1 , ' { ' , ' } ' )
		elif ( X [ i ] == ' [ ' ) :
			j = matchClosing ( X , i , n - 1 , ' [ ' , ' ] ' )
		else :
			if ( X [ i ] == ' ) ' ) :
				j = matchingOpening ( X , 0 , i , ' ( ' , ' ) ' )
			elif ( X [ i ] == ' } ' ) :
				j = matchingOpening ( X , 0 , i , ' { ' , ' } ' )
			elif ( X [ i ] == ' ] ' ) :
				j = matchingOpening ( X , 0 , i , ' [ ' , ' ] ' )
			if ( j < 0 or j >= i ) :
				return False
			continue
		if ( j >= n or j < 0 ) :
			return False
		start = i
		end = j
		for k in range ( start + 1 , end ) :
			if ( X [ k ] == ' ( ' ) :
				x = matchClosing ( X , k , end , ' ( ' , ' ) ' )
				if ( not ( k < x and x < end ) ) :
					return False
			elif ( X [ k ] == ' ) ' ) :
				x = matchingOpening ( X , start , k , ' ( ' , ' ) ' )
				if ( not ( start < x and x < k ) ) :
					return False
			if ( X [ k ] == ' { ' ) :
				x = matchClosing ( X , k , end , ' { ' , ' } ' )
				if ( not ( k < x and x < end ) ) :
					return False
			elif ( X [ k ] == ' } ' ) :
				x = matchingOpening ( X , start , k , ' { ' , ' } ' )
				if ( not ( start < x and x < k ) ) :
					return False
			if ( X [ k ] == ' [ ' ) :
				x = matchClosing ( X , k , end , ' [ ' , ' ] ' )
				if ( not ( k < x and x < end ) ) :
					return False
			elif ( X [ k ] == ' ] ' ) :
				x = matchingOpening ( X , start , k , ' [ ' , ' ] ' )
				if ( not ( start < x and x < k ) ) :
					return...