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Count Numbers with N digits which consists of odd number of 0 's | Function to count Numbers with N digits which consists of odd number of 0 's.
Driver code"
Solution in Python:
assistant
#Here is code to count Numbers with N digits which consists of odd number of 0 's and the other steps required.
 def countNumbers ( N ) :
	return ( pow ( 10 , N ) - pow ( 8 , N ) ) // 2
if __name__ == " _ _ main _ _ " :
	n = 5
	print ( countNumbers ( n ) )