human
Maximize sum of assigned weights by flipping at most K bits in given Binary String | Function to find maximum sum of weights of binary string after at most K flips.
Stores lengths of substrings of the form 1. . 00. . 1 s.
Stores the index of last 1 encountered in the string.
Stores the index of first 1 encountered.
Stores lengths of all substrings having of 0 s enclosed by 1 s at both ends.
Traverse the string.
If character is 0.
If character is 1 First Priority.
Second Priority.
Add according to the first priority.
Stores length of the shortest substring of 0 s.
Convert shortest substrings of 0 s to 1 s.
Add according to the first priority.
Add according to the third priority.
If more 0 s can be made into 1 , then check for 0 s at ends.
Update the ans.
If K is non - zero , then flip 0 s at the beginning.
Return the final weights.
Driver Code.
Given string str.
Given K flips.
Function Call"
How can the above be solved in Python?
 ... Give me a code to maximize sum of assigned weights by flipping at most K bits in given Binary String and the other steps required?
assistant
#Here is code to maximize sum of assigned weights by flipping at most K bits in given Binary String and the other steps required.
 def findMax ( s , n , k ) :
	ans = 0 ;
	l = 0 ;
	ind = - 1 ;
	indf = - 1 ;
	ls = set ( [ ] )
	for i in range ( n ) :
		if ( s [ i ] == '0' ) :
			l += 1
		elif ( s [ i ] == '1' and l > 0 and ans != 0 ) :
			ls . add ( l ) ;
			l = 0 ;
		if ( s [ i ] == '1' ) :
			ind = i ;
			l = 0 ;
			if ( indf == - 1 ) :
				indf = i ;
			if ( i > 0 and s [ i - 1 ] == '1' ) :
				ans += 2 ;
			else :
				ans += 1 ;
	curr = 0
	while ( k > 0 and len ( ls ) != 0 ) :
		for i in ls :
		curr = i
		break
		if ( k >= curr ) :
			ans += ( 2 * curr + 1 ) ;
			k -= curr ;
		else :
			ans += ( 2 * k ) ;
			k = 0 ;
		ls . remove ( curr ) ;
	if ( k > 0 ) :
		ans += ( 2 * min ( k , n - ( ind + 1 ) ) - 1 ) ;
		k -= min ( k , n - ( ind + 1 ) ) ;
		if ( ind > - 1 ) :
			ans += 1
	if ( k > 0 ) :
		ans += ( min ( indf , k ) * 2 - 1 ) ;
		if ( indf > - 1 ) :
			ans += 1
	return ans
if __name__ == " _ _ main _ _ " :
	s = "1110000101" ;
	N = len ( s )
	K = 3 ;
	print ( findMax ( s , N , K ) ) ;