human
Solve in Python:
Given a binary string s and an integer k.
Return True if every binary code of length k is a substring of s. Otherwise, return False.
 
Example 1:
Input: s = "00110110", k = 2
Output: true
Explanation: The binary codes of length 2 are "00", "01", "10" and "11". They can be all found as substrings at indicies 0, 1, 3 and 2 respectively.

Example 2:
Input: s = "00110", k = 2
Output: true

Example 3:
Input: s = "0110", k = 1
Output: true
Explanation: The binary codes of length 1 are "0" and "1", it is clear that both exist as a substring. 

Example 4:
Input: s = "0110", k = 2
Output: false
Explanation: The binary code "00" is of length 2 and doesn't exist in the array.

Example 5:
Input: s = "0000000001011100", k = 4
Output: false

 
Constraints:

1 <= s.length <= 5 * 10^5
s consists of 0's and 1's only.
1 <= k <= 20
 ... Give me a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def hasAllCodes(self, s: str, k: int) -> bool:
        l = len(s)
        r = set()
        for i in range(0, l-k+1):
            r.add(
                s[i:i+k]
            )
            if len(r) == 2**k:
                return True

        for i in product(['0','1'], repeat=k):
            _ = ''.join(i)
            if _ not in r:
                return False
        return True