human
Place k elements such that minimum distance is maximized | Returns true if it is possible to arrange k elements of arr [ 0. . n - 1 ] with minimum distance given as mid ..
Place first element at arr [ 0 ] position.
Initialize count of elements placed ..
Try placing k elements with minimum distance mid ..
Place next element if its distance from the previously placed element is greater than current mid.
Return if all elements are placed successfully.
Returns largest minimum distance for k elements in arr [ 0. . n - 1 ] . If elements can 't be placed, returns -1..
Sort the positions.
Initialize result ..
Consider the maximum possible distance.
Do binary search for largest minimum distance.
If it is possible to place k elements with minimum distance mid , search for higher distance ..
Change value of variable max to mid iff all elements can be successfully placed.
If not possible to place k elements , search for lower distance.
Driver code"
How can the above be solved in Python?

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Give me a code to place k elements such that minimum distance is maximized and the other steps required?
assistant
#Here is code to place k elements such that minimum distance is maximized and the other steps required.
 def isFeasible ( mid , arr , n , k ) :
	pos = arr [ 0 ]
	elements = 1
	for i in range ( 1 , n , 1 ) :
		if ( arr [ i ] - pos >= mid ) :
			pos = arr [ i ]
			elements += 1
			if ( elements == k ) :
				return True
	return 0
def largestMinDist ( arr , n , k ) :
	arr . sort ( reverse = False )
	res = - 1
	left = 1
	right = arr [ n - 1 ]
	while ( left < right ) :
		mid = ( left + right ) / 2
		if ( isFeasible ( mid , arr , n , k ) ) :
			res = max ( res , mid )
			left = mid + 1
		else :
			right = mid
	return res
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 2 , 8 , 4 , 9 ]
	n = len ( arr )
	k = 3
	print ( largestMinDist ( arr , n , k ) )