human
Reverse individual words with O ( 1 ) extra space | Function to resturn the after reversing the individual words.
Pointer to the first character of the first word.
If the current word has ended.
Pointer to the last character of the current word.
Reverse the current word.
Pointer to the first character of the next word.
Driver code"
How can the above be solved in Python?
 ... Can you provide a code to reverse individual words with O ( 1 ) extra space and the other steps required?
assistant
#Here is code to reverse individual words with O ( 1 ) extra space and the other steps required.
 def reverseWords ( Str ) :
	start = 0
	for i in range ( len ( Str ) ) :
		if ( Str [ i ] == ' ▁ ' or i == len ( Str ) - 1 ) :
			end = i - 1
			if ( i == len ( Str ) - 1 ) :
				end = i
			while ( start < end ) :
				Str [ start ] , Str [ end ] = Str [ end ] , Str [ start ]
				start += 1
				end -= 1
			start = i + 1
	return " " . join ( Str )
Str = " Geeks ▁ for ▁ Geeks "
Str = [ i for i in Str ]
print ( reverseWords ( Str ) )