human
Queries On Array with disappearing and reappearing elements | Function to perform the queries.
Size of the array with 1 - based indexing.
Number of queries.
Iterating through the queries.
If m is more than the size of the array.
Count of turns.
Find the remainder.
If the remainder is 0 and turn is odd then the array is empty.
If the remainder is 0 and turn is even then array is full and is in its initial state.
If the remainder is not 0 and the turn is even.
Current size of the array.
Current size of the array.
Print the result.
Driver code.
The initial array , - 1 is for 1 base indexing.
Queries in the form of the pairs of ( t , M )"
How can the above be solved in Python?

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What is a code to queries On Array with disappearing and reappearing elements and the other steps required?
assistant
#Here is code to queries On Array with disappearing and reappearing elements and the other steps required.
 def PerformQueries ( a , vec ) :
	ans = [ ] ;
	n = len ( a ) - 1 ;
	q = len ( vec ) ;
	for i in range ( q ) :
		t = vec [ i ] [ 0 ] ;
		m = vec [ i ] [ 1 ] ;
		if ( m > n ) :
			ans . append ( - 1 ) ;
			continue ;
		turn = t // n ;
		rem = t % n ;
		if ( rem == 0 and turn % 2 == 1 ) :
			ans . append ( - 1 ) ;
			continue ;
		if ( rem == 0 and turn % 2 == 0 ) :
			ans . append ( a [ m ] ) ;
			continue ;
		if ( turn % 2 == 0 ) :
			cursize = n - rem ;
			if ( cursize < m ) :
				ans . append ( - 1 ) ;
				continue ;
			ans . append ( a [ m + rem ] ) ;
		else :
			cursize = rem ;
			if ( cursize < m ) :
				ans . append ( - 1 ) ;
				continue ;
			ans . append ( a [ m ] ) ;
	for i in ans :
		print ( i ) ;
if __name__ == " _ _ main _ _ " :
	a = [ - 1 , 1 , 2 , 3 , 4 , 5 ] ;
	vec = [ [ 1 , 4 ] , [ 6 , 1 ] , [ 3 , 5 ] ] ;
	PerformQueries ( a , vec ) ;