human
Count of strings that does not contain Arc intersection | Function to check if there is arc intersection or not.
Traverse the string S.
Insert all the elements in the stack one by one.
Extract the top element.
Pop out the top element.
Check if the top element is same as the popped element.
Otherwise.
If the stack is empty.
Function to check if there is arc intersection or not for the given array of strings.
Stores count of string not having arc intersection.
Iterate through array.
Length of every string.
Function Call.
Print the desired count.
Driver Code.
Function Call"
Solution in Python:
 Can you provide a code to count of strings that does not contain Arc intersection and the other steps required?
assistant
#Here is code to count of strings that does not contain Arc intersection and the other steps required.
 def arcIntersection ( S , lenn ) :
	stk = [ ]
	for i in range ( lenn ) :
		stk . append ( S [ i ] )
		if ( len ( stk ) >= 2 ) :
			temp = stk [ - 1 ]
			del stk [ - 1 ]
			if ( stk [ - 1 ] == temp ) :
				del stk [ - 1 ]
			else :
				stk . append ( temp )
	if ( len ( stk ) == 0 ) :
		return 1
	return 0
def countString ( arr , N ) :
	count = 0
	for i in range ( N ) :
		lenn = len ( arr [ i ] )
		count += arcIntersection ( arr [ i ] , lenn )
	print ( count )
if __name__ == ' _ _ main _ _ ' :
	arr = [ "0101" , "0011" , "0110" ]
	N = len ( arr )
	countString ( arr , N )