human
Count divisors of array multiplication | To count number of factors in a number.
Initialize count with 0.
Increment count for every factor of the given number X ..
Return number of factors.
Returns number of divisors in array multiplication.
Multipliying all elements of the given array ..
Calling function which count number of factors of the number.
Driver code"
Solution in Python:
 ... What is a code to count divisors of array multiplication and the other steps required?
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#Here is code to count divisors of array multiplication and the other steps required.
 def counDivisors ( X ) :
	count = 0
	for i in range ( 1 , X + 1 ) :
		if ( X % i == 0 ) :
			count += 1
	return count
def countDivisorsMult ( arr , n ) :
	mul = 1
	for i in range ( n ) :
		mul *= arr [ i ]
	return counDivisors ( mul )
arr = [ 2 , 4 , 6 ]
n = len ( arr )
print ( countDivisorsMult ( arr , n ) )