human
Queries on substring palindrome formation | Query type 1 : update str1ing position i with character x ..
Pr " Yes " if range [ L . . R ] can form palindrome , else pr " No " ..
Find the frequency of each character in S [ L ... R ] ..
Checking if more than one character have frequency greater than 1..
Driver Code"
Solution in Python:

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Write me a code to queries on substring palindrome formation and the other steps required?
assistant
#Here is code to queries on substring palindrome formation and the other steps required.
 def qType1 ( l , x , str1 ) :
	str1 [ l - 1 ] = x
def qType2 ( l , r , str1 ) :
	freq = [ 0 for i in range ( 27 ) ]
	for i in range ( l - 1 , r ) :
		freq [ ord ( str1 [ i ] ) - ord ( ' a ' ) ] += 1
	count = 0
	for j in range ( 26 ) :
		if ( freq [ j ] % 2 ) :
			count += 1
	if count <= 1 :
		print ( " Yes " )
	else :
		print ( " No " )
str1 = " geeksforgeeks "
str2 = [ i for i in str1 ]
n = len ( str2 )
qType1 ( 4 , ' g ' , str2 )
qType2 ( 1 , 4 , str2 )
qType2 ( 2 , 3 , str2 )
qType1 ( 10 , ' t ' , str2 )
qType2 ( 10 , 11 , str2 )