human
Solve the following python programming problem given the following code:
def bencode(canonical) : 
    "
        Turns a dictionary into a bencoded str with alphabetized keys
        e.g., {'spam': 'eggs', 'cow': 'moo'} --> d3:cow3:moo4:spam4:eggse
    " 
    in_dict = dict (encode_int) 
    def encode_str(in_str) : 
        out_str = ((str (len (in_str)) + ':') + in_str) 
        return out_str 
def encode_int(in_int) : 
        out_str = str ((('i' + str (in_int)) + 'e')) 
        return out_str 
def encode_list(in_list) : 
        out_str = 'l' 
        for item in in_list : 
            out_str += encode_item (item) 
else : 
            out_str += 'e' 
return out_str 
def encode_dict(in_dict) : 
        out_str = 'd' 
        keys = sorted (in_dict.keys ()) 
        for key in keys : 
            val = in_dict [key] 
            out_str = ((out_str + encode_item (key)) + encode_item (val)) 
else : 
            out_str += 'e' 
return out_str 
def encode_item(x) : 
        if isinstance (x, str) : 
            return encode_str (x) 
else : 
            if isinstance (x, int) : 
                return encode_int (x) 
else : 
                if isinstance (x, list) : 
                    return encode_list (x) 
else : 
                    if isinstance (x, dict) : 
                        return encode_dict (x) 
return encode_item (in_dict) 

    
    

    Fix the buggy line: in_dict = dict (encode_int)
assistant
#Here is Python code to fix the buggy line: in_dict = dict (encode_int)
.

in_dict = dict (canonical)