human
I found an interesting problem on https://leetcode.com/problems/word-break/:
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

Note:

       The same word in the dictionary may be reused multiple times in the segmentation.
       You may assume the dictionary does not contain duplicate words.

Example 1:

Input: s = "leetcode", wordDict = ["leet", "code"]
Output: true
Explanation: Return true because "leetcode" can be segmented as "leet code".

Example 2:

Input: s = "applepenapple", wordDict = ["apple", "pen"]
Output: true
Explanation: Return true because "applepenapple" can be segmented as "apple pen apple".
             Note that you are allowed to reuse a dictionary word.

Example 3:

Input: s = "catsandog", wordDict = ["cats", "dog", "sand", "and", "cat"]
Output: false

I tried it in Python, but could not do it. Can you solve it?

Can you provide a Python program to determine if s can be segmented into a space-separated sequence of one or more dictionary words?
assistant
#Here is Python program to determine if s can be segmented into a space-separated sequence of one or more dictionary words.

class Solution:
     def wordBreak(self, s, wordDict):
         """
         :type s: str
         :type wordDict: List[str]
         :rtype: bool
         """
         ok = [True]
         for i in range(1, len(s)+1):
             ok += (any(ok[j] and s[j:i] in wordDict for j in range(i))),
             print(ok)
         return ok[-1]