human
Count of ways to form 2 necklace from N beads containing N / 2 beads each | Function to calculate factorial.
Function to count number of ways to make 2 necklace having exactly N / 2 beads if each bead is considered different.
Number of ways to choose N / 2 beads from N beads.
Number of ways to permute N / 2 beads.
Divide ans by 2 to remove repetitions.
Return ans.
Driver Code.
Given Input.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to count of ways to form 2 necklace from N beads containing N / 2 beads each and the other steps required.
 def factorial ( n ) :
	if ( n == 0 ) :
		return 1
	return n * factorial ( n - 1 )
def numOfNecklace ( N ) :
	ans = factorial ( N ) // ( factorial ( N // 2 ) * factorial ( N // 2 ) )
	ans = ans * factorial ( N // 2 - 1 )
	ans = ans * factorial ( N // 2 - 1 )
	ans //= 2
	return ans
if __name__ == ' _ _ main _ _ ' :
	N = 4
	print ( numOfNecklace ( N ) )