human
Write me a Python program to find turn angles in degrees for each mustache hands given the following:
Do you remember a kind cartoon "Beauty and the Beast"? No, no, there was no firing from machine guns or radiation mutants time-travels!

There was a beauty named Belle. Once she had violated the Beast's order and visited the West Wing. After that she was banished from the castle... 

Everybody was upset. The beautiful Belle was upset, so was the Beast, so was Lumiere the candlestick. But the worst thing was that Cogsworth was upset. Cogsworth is not a human, but is the mantel clock, which was often used as an alarm clock.

Due to Cogsworth's frustration all the inhabitants of the castle were in trouble: now they could not determine when it was time to drink morning tea, and when it was time for an evening stroll. 

Fortunately, deep in the basement are lying digital clock showing the time in the format HH:MM. Now the residents of the castle face a difficult task. They should turn Cogsworth's hour and minute mustache hands in such a way, that Cogsworth began to show the correct time. Moreover they need to find turn angles in degrees for each mustache hands. The initial time showed by Cogsworth is 12:00.

You can only rotate the hands forward, that is, as is shown in the picture: 


As since there are many ways too select such angles because of full rotations, choose the smallest angles in the right (non-negative) direction.

Note that Cogsworth's hour and minute mustache hands move evenly and continuously. Hands are moving independently, so when turning one hand the other hand remains standing still.

Input

The only line of input contains current time according to the digital clock, formatted as HH:MM (00 ≤ HH ≤ 23, 00 ≤ MM ≤ 59). The mantel clock initially shows 12:00.

Pretests contain times of the beginning of some morning TV programs of the Channel One Russia.

Output

Print two numbers x and y — the angles of turning the hour and minute hands, respectively (0 ≤ x, y < 360). The absolute or relative error in the answer should not exceed 10 - 9.

Examples

Input

12:00

Output

0...
Using python3 can you solve the prior task?
assistant
#Here is Python program to find turn angles in degrees for each mustache hands.

#------------------Important Modules------------------#

from sys import stdin,stdout
from bisect import bisect_left as bl
from bisect import bisect_right as br
from heapq import *
input=stdin.readline
prin=stdout.write
from random import sample

from collections import Counter,deque
from math import sqrt,ceil,log2,gcd
#dist=[0]*(n+1)
mod=10**9+7
class DisjSet: 
    def __init__(self, n): 
        # Constructor to create and 
        # initialize sets of n items 
        self.rank = [1] * n 
        self.parent = [i for i in range(n)] 
  
  
    # Finds set of given item x 
    def find(self, x): 
          
        # Finds the representative of the set 
        # that x is an element of 
        if (self.parent[x] != x): 
              
            # if x is not the parent of itself 
            # Then x is not the representative of 
            # its set, 
            self.parent[x] = self.find(self.parent[x]) 
              
            # so we recursively call Find on its parent 
            # and move i's node directly under the 
            # representative of this set 
  
        return self.parent[x] 
  
  
    # Do union of two sets represented 
    # by x and y. 
    def union(self, x, y): 
          
        # Find current sets of x and y 
        xset = self.find(x) 
        yset = self.find(y) 
  
        # If they are already in same set 
        if xset == yset: 
            return
  
        # Put smaller ranked item under 
        # bigger ranked item if ranks are 
        # different 
        if self.rank[xset] < self.rank[yset]: 
            self.parent[xset] = yset 
  
        elif self.rank[xset] > self.rank[yset]: 
            self.parent[yset] = xset 
  
        # If ranks are same, then move y under 
        # x (doesn't matter which one goes where) 
        # and increment rank of x's tree 
        else: 
            self.parent[yset] = xset 
            self.rank[xset] = self.rank[xset] + 1
  
# Driver code 


def f(arr,i,j,d,dist):
    if i==j:
        return 
    nn=max(arr[i:j])
...