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Maximize length of Subarray of 1 's after removal of a pair of consecutive Array elements | Python program to find the maximum count of 1 s.
If arr [ i - 2 ] = = 1 then we increment the count of occurences of 1 's.
Else we initialise the count with 0.
If arr [ i + 2 ] = = 1 then we increment the count of occurences of 1 's.
Else we initialise the count with 0.
We get the maximum count by skipping the current and the next element ..
Driver code"
Solution in Python:

What is a code to maximize length of Subarray of 1 's after removal of a pair of consecutive Array elements and the other steps required?
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#Here is code to maximize length of Subarray of 1 's after removal of a pair of consecutive Array elements and the other steps required.
 def maxLengthOf1s ( arr , n ) :
	prefix = [ 0 for i in range ( n ) ]
	for i in range ( 2 , n ) :
		if ( arr [ i - 2 ] == 1 ) :
			prefix [ i ] = prefix [ i - 1 ] + 1
		else :
			prefix [ i ] = 0
	suffix = [ 0 for i in range ( n ) ]
	for i in range ( n - 3 , - 1 , - 1 ) :
		if ( arr [ i + 2 ] == 1 ) :
			suffix [ i ] = suffix [ i + 1 ] + 1
		else :
			suffix [ i ] = 0
	ans = 0
	for i in range ( n - 1 ) :
		ans = max ( ans , prefix [ i + 1 ] + suffix [ i ] )
	print ( ans )
n = 6
arr = [ 1 , 1 , 1 , 0 , 1 , 1 ]
maxLengthOf1s ( arr , n )