human
Can you provide a code to count subarrays with Prime sum and the other steps required given the following:
Count subarrays with Prime sum | Function to count subarrays with Prime sum.
USE SIEVE TO FIND ALL PRIME NUMBERS LESS THAN OR EQUAL TO max_val Create a boolean array " prime [ 0 . . n ] " . A value in prime [ i ] will finally be false if i is Not a prime , else true ..
Remaining part of SIEVE.
If prime [ p ] is not changed , then it is a prime.
Update all multiples of p.
Initialize result.
Traverse through the array.
return answer.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to count subarrays with Prime sum and the other steps required.
 def primeSubarrays ( A , n ) :
	max_val = 10 ** 7
	prime = [ True ] * ( max_val + 1 )
	prime [ 0 ] = False
	prime [ 1 ] = False
	for p in range ( 2 , int ( max_val ** ( 0.5 ) ) + 1 ) :
		if prime [ p ] == True :
			for i in range ( 2 * p , max_val + 1 , p ) :
				prime [ i ] = False
	cnt = 0
	for i in range ( 0 , n - 1 ) :
		val = A [ i ]
		for j in range ( i + 1 , n ) :
			val += A [ j ]
			if prime [ val ] == True :
				cnt += 1
	return cnt
if __name__ == " _ _ main _ _ " :
	A = [ 1 , 2 , 3 , 4 , 5 ]
	n = len ( A )
	print ( primeSubarrays ( A , n ) )