human
Minimize the non | Function to minimize the non - zero elements in the given array.
To store the min pos needed.
Loop to iterate over the elements of the given array.
If current position A [ i ] is occupied the we can place A [ i ] , A [ i + 1 ] and A [ i + 2 ] elements together at A [ i + 1 ] if exists ..
Driver Code.
Function Call"
Solution in Python:

Can you provide a code to minimize the non and the other steps required?
assistant
#Here is code to minimize the non and the other steps required.
 def minOccupiedPosition ( A , n ) :
	minPos = 0
	i = 0
	while i < n :
		if ( A [ i ] > 0 ) :
			minPos += 1
			i += 2
		i += 1
	return minPos
if __name__ == ' _ _ main _ _ ' :
	A = [ 8 , 0 , 7 , 0 , 0 , 6 ]
	n = len ( A )
	print ( minOccupiedPosition ( A , n ) )