human
Sum of product of all subsets formed by only divisors of N | Function to find the sum of product of all the subsets formed by only divisors of N.
Vector to store all the divisors of n.
Loop to find out the divisors of N.
Both ' i ' and ' n / i ' are the divisors of n.
Check if ' i ' and ' n / i ' are equal or not.
Calculating the answer.
Excluding the value of the empty set.
Driver Code"
Solution in Python:
 Write me a code to sum of product of all subsets formed by only divisors of N and the other steps required?
assistant
#Here is code to sum of product of all subsets formed by only divisors of N and the other steps required.
 def GetSum ( n ) :
	divisors = [ ]
	i = 1
	while i * i <= n :
		if ( n % i == 0 ) :
			divisors . append ( i )
			if ( i != n // i ) :
				divisors . append ( n // i )
		i += 1
	ans = 1
	for i in divisors :
		ans *= ( i + 1 )
	ans = ans - 1
	return ans
if __name__ == " _ _ main _ _ " :
	N = 4
	print ( GetSum ( N ) )