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Nth natural number after removing all numbers consisting of the digit 9 | Function to find Nth number in base 9.
Stores the Nth number.
Iterate while N is greater than 0.
Update result.
Divide N by 9.
Multiply p by 10.
Return result.
Driver Code"
Solution in Python:

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Write me a code to nth natural number after removing all numbers consisting of the digit 9 and the other steps required?
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#Here is code to nth natural number after removing all numbers consisting of the digit 9 and the other steps required.
 def findNthNumber ( N ) :
	result = 0
	p = 1
	while ( N > 0 ) :
		result += ( p * ( N % 9 ) )
		N = N // 9
		p = p * 10
	return result
if __name__ == ' _ _ main _ _ ' :
	N = 9
	print ( findNthNumber ( N ) )