human
Solve in Python:
We are given a list schedule of employees, which represents the working time for each employee.

Each employee has a list of non-overlapping Intervals, and these intervals are in sorted order.

Return the list of finite intervals representing common, positive-length free time for all employees, also in sorted order.

Example 1:

Input: schedule = [[[1,2],[5,6]],[[1,3]],[[4,10]]]
Output: [[3,4]]
Explanation:
There are a total of three employees, and all common
free time intervals would be [-inf, 1], [3, 4], [10, inf].
We discard any intervals that contain inf as they aren't finite.

Example 2:

Input: schedule = [[[1,3],[6,7]],[[2,4]],[[2,5],[9,12]]]
Output: [[5,6],[7,9]]



(Even though we are representing Intervals in the form [x, y], the objects inside are Intervals, not lists or arrays.  For example, schedule[0][0].start = 1, schedule[0][0].end = 2, and schedule[0][0][0] is not defined.)

Also, we wouldn't include intervals like [5, 5] in our answer, as they have zero length.

Note:
schedule and schedule[i] are lists with lengths in range [1, 50].
0 .
assistant
#Here is the Python code you requested.

class Solution:
     def intersectionSizeTwo(self, intervals):
         """
         :type intervals: List[List[int]]
         :rtype: int
         """
         intervals.sort(key=lambda x: x[1])
         if len(intervals) <= 1:
             return len(intervals[0])
         s = set()
         for e in intervals:
             if not s:
                 a = e[1] - 1
                 b = e[1]
                 s.add(a)
                 s.add(b)
                 continue
             if e[0] <= a :
                 continue
                 
             if e[0] > a and  e[1] > b >= e[0] :
                 a = b
                 b = e[-1]
                 s.add(b)
                 continue
             a = e[1] - 1
             b = e[1]
             s.add(a)
             s.add(b)
         
         return len(s)