human
Rearrange a string S1 such that another given string S2 is not its subsequence | Function to rearrange characters in S1 such that S2 is not a subsequence of it.
Store the frequencies of characters of s2.
Traverse the s2.
Update the frequency.
Find the number of unique characters in s2.
Increment unique by 1 if the condition satisfies.
Check if the number of unique characters in s2 is 1.
Store the unique character frequency.
Store occurence of it in s1.
Find count of that character in the s1.
Increment count by 1 if that unique character is same as current character.
If count count_in_s1 is less than count_in_s2 , then prs1 and return.
Otherwise , there is no possible arrangement.
Checks if any character in s2 is less than its next character.
Iterate the string , s2.
If s [ i ] is greater than the s [ i + 1 ].
Set inc to 0.
If inc = 1 , prs1 in decreasing order.
Otherwise , prs1 in increasing order.
Driver code"
Solution in Python:
 ... Can you provide a code to rearrange a string S1 such that another given string S2 is not its subsequence and the other steps required?
assistant
#Here is code to rearrange a string S1 such that another given string S2 is not its subsequence and the other steps required.
 def rearrangeString ( s1 , s2 ) :
	cnt = [ 0 ] * 26
	for i in range ( len ( s2 ) ) :
		cnt [ ord ( s2 [ i ] ) - ord ( ' a ' ) ] += 1
	unique = 0
	for i in range ( 26 ) :
		if ( cnt [ i ] != 0 ) :
			unique += 1
	if ( unique == 1 ) :
		count_in_s2 = len ( s2 )
		count_in_s1 = 0
		for i in range ( len ( s1 ) ) :
			if ( s1 [ i ] == s2 [ 0 ] ) :
				count_in_s1 += 1
		if ( count_in_s1 < count_in_s2 ) :
			print ( s1 , end = " " )
			return
		print ( - 1 , end = " " )
	else :
		inc = 1
		for i in range ( len ( s2 ) - 1 ) :
			if ( s2 [ i ] > s2 [ i + 1 ] ) :
				inc = 0
		if ( inc == 1 ) :
			s1 = sorted ( s1 ) [ : : - 1 ]
			print ( " " . join ( s1 ) , end = " " )
		else :
			s1 = sorted ( s1 )
			print ( " " . join ( s1 ) , end = " " )
if __name__ == ' _ _ main _ _ ' :
	s1 , s2 = " abcd " , " ab "
	rearrangeString ( s1 , s2 )