human
Construct an Array of size N in which sum of odd elements is equal to sum of even elements | Function to construct the required array.
To construct first half , distinct even numbers.
To construct second half , distinct odd numbers.
Calculate the last number of second half so as to make both the halves equal.
Function to construct the required array.
check if size is multiple of 4 then array exist.
function call to construct array.
Driver code"
Solution in Python:
 Give me a code to construct an Array of size N in which sum of odd elements is equal to sum of even elements and the other steps required?
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#Here is code to construct an Array of size N in which sum of odd elements is equal to sum of even elements and the other steps required.
 def arrayConstruct ( N ) :
	for i in range ( 2 , N + 1 , 2 ) :
		print ( i , end = " ▁ " )
	for i in range ( 1 , N - 1 , 2 ) :
		print ( i , end = " ▁ " )
	print ( N - 1 + ( N // 2 ) )
def createArray ( N ) :
	if ( N % 4 == 0 ) :
		arrayConstruct ( N )
	else :
		cout << - 1 << endl
if __name__ == ' _ _ main _ _ ' :
	N = 8
	createArray ( N )