human
Give me a code to count ancestors with smaller value for each node of a Binary Tree and the other steps required given the following:
Count ancestors with smaller value for each node of a Binary Tree | Function to add an edge between nodes u and v.
Function to perform the DFS Traversal and store parent of each node.
Store the immediate parent.
Traverse the children of the current node.
Recursively call for function dfs for the child node.
Function to count the number of ancestors with values smaller than that of the current node.
Perform the DFS Traversal.
Traverse all the nodes.
Store the number of ancestors smaller than node.
Loop until parent [ node ] != - 1.
If the condition satisfies , increment cnt by 1.
Print the required result for the current node.
Driver Code.
Tree Formation"
Solution in Python:
assistant
#Here is code to count ancestors with smaller value for each node of a Binary Tree and the other steps required.
 def add_edge ( u , v ) :
	global adj
	adj [ u ] . append ( v )
	adj [ v ] . append ( u )
def dfs ( u , par = - 1 ) :
	global adj , parent
	parent [ u ] = par
	for child in adj [ u ] :
		if ( child != par ) :
			dfs ( child , u )
def countSmallerAncestors ( n ) :
	global parent , adj
	dfs ( 1 )
	for i in range ( 1 , n + 1 ) :
		node = i
		cnt = 0
		while ( parent [ node ] != - 1 ) :
			if ( parent [ node ] < i ) :
				cnt += 1
			node = parent [ node ]
		print ( cnt , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	N = 6
	adj = [ [ ] for i in range ( 10 ** 5 ) ]
	parent = [ 0 ] * ( 10 ** 5 )
	add_edge ( 1 , 5 )
	add_edge ( 1 , 4 )
	add_edge ( 4 , 6 )
	add_edge ( 5 , 3 )
	add_edge ( 5 , 2 )
	countSmallerAncestors ( N )