human
Can you provide a code to find an array of size N that satisfies the given conditions and the other steps required given the following:
Find an array of size N that satisfies the given conditions | Utility function to print the contents of an array.
Function to generate and print the required array.
Initially all the positions are empty.
To store the count of positions i such that arr [ i ] = s.
To store the final array elements.
Set arr [ i ] = s and the gap between them is exactly 2 so in for loop we use i += 2.
Mark the i 'th position as visited  as we put arr[i] = s.
Increment the count.
Finding the next odd number after s.
If the i 'th position is not visited  it means we did not put any value  at position i so we put 1 now.
Print the final array.
Driver code"
Solution in Python:
assistant
#Here is code to find an array of size N that satisfies the given conditions and the other steps required.
 def printArr ( arr , n ) :
	for i in range ( n ) :
		print ( arr [ i ] , end = " ▁ " ) ;
def findArray ( n , k , s ) :
	vis = [ 0 ] * n ;
	cnt = 0 ;
	arr = [ 0 ] * n ;
	i = 0 ;
	while ( i < n and cnt < k ) :
		arr [ i ] = s ;
		vis [ i ] = 1 ;
		cnt += 1 ;
		i += 2 ;
	val = s ;
	if ( s % 2 == 0 ) :
		val += 1 ;
	else :
		val = val + 2 ;
	for i in range ( n ) :
		if ( vis [ i ] == 0 ) :
			arr [ i ] = val ;
	printArr ( arr , n ) ;
if __name__ == " _ _ main _ _ " :
	n = 8 ; k = 3 ; s = 12 ;
	findArray ( n , k , s ) ;