human
Solve the following python programming problem given the following code:
def deferLater(clock, delay, callable, * args, **kw) : 
    '
    Call the given function after a certain period of time has passed.

    @type clock: L{IReactorTime} provider
    @param clock: The object which will be used to schedule the delayed
        call.

    @type delay: C{float} or C{int}
    @param delay: The number of seconds to wait before calling the function.

    @param callable: The object to call after the delay.

    @param *args: The positional arguments to pass to C{callable}.

    @param **kw: The keyword arguments to pass to C{callable}.

    @rtype: L{defer.Deferred}

    @return: A deferred that fires with the result of the callable when the
        specified time has elapsed.
    ' 
    def deferLaterCancel(deferred) : 
        delayedCall.cancel () 
d = defer.Deferred (deferLaterCancel) 
    d.addCallback ((lambda ignored : callable (* args, ** kw))) 
    delayedCall = clock.callLater (delay, args.callback, None) 
    return d 

    
    

    Fix the buggy line: delayedCall = clock.callLater (delay, args.callback, None)
assistant
#Here is Python program to fix the buggy line: delayedCall = clock.

delayedCall = clock.callLater (delay, d.callback, None)