human
Count Arithmetic Progressions having sum S and common difference equal to D | Function to count the number of APs with sum S and common difference D.
Multiply S by 2.
Stores the count of APs.
Iterate over the factors of 2 * S.
Check if i is the factor or not.
Conditions to check if AP can be formed using factor F.
Return the total count of APs.
Driver Code"
How can the above be solved in Python?

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Can you provide a code to count Arithmetic Progressions having sum S and common difference equal to D and the other steps required?
assistant
#Here is code to count Arithmetic Progressions having sum S and common difference equal to D and the other steps required.
 def countAPs ( S , D ) :
	S = S * 2
	answer = 0
	for i in range ( 1 , S ) :
		if i * i > S :
			break
		if ( S % i == 0 ) :
			if ( ( ( S // i ) - D * i + D ) % 2 == 0 ) :
				answer += 1
			if ( ( D * i - ( S // i ) + D ) % 2 == 0 ) :
				answer += 1
	return answer
if __name__ == ' _ _ main _ _ ' :
	S , D = 12 , 1
	print ( countAPs ( S , D ) ) ;