human
Can you provide a code to search an element in a sorted and rotated array and the other steps required given the following:
Search an element in a sorted and rotated array | Returns index of key in arr [ l . . h ] if key is present , otherwise returns - 1.
If arr [ l ... mid ] is sorted.
As this subarray is sorted , we can quickly check if key lies in half or other half.
If key not lies in first half subarray , Divide other half into two subarrays , such that we can quickly check if key lies in other half.
If arr [ l . . mid ] is not sorted , then arr [ mid ... r ] must be sorted.
Driver program"
How can the above be solved in Python?
assistant
#Here is code to search an element in a sorted and rotated array and the other steps required.
 def search ( arr , l , h , key ) :
	if l > h :
		return - 1
	mid = ( l + h ) // 2
	if arr [ mid ] == key :
		return mid
	if arr [ l ] <= arr [ mid ] :
		if key >= arr [ l ] and key <= arr [ mid ] :
			return search ( arr , l , mid - 1 , key )
		return search ( arr , mid + 1 , h , key )
	if key >= arr [ mid ] and key <= arr [ h ] :
		return search ( a , mid + 1 , h , key )
	return search ( arr , l , mid - 1 , key )
arr = [ 4 , 5 , 6 , 7 , 8 , 9 , 1 , 2 , 3 ]
key = 6
i = search ( arr , 0 , len ( arr ) - 1 , key )
if i != - 1 :
	print ( " Index : ▁ % ▁ d " % i )
else :
	print ( " Key ▁ not ▁ found " )