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m Coloring Problem | Backtracking | A utility function to prsolution.
check if the colored graph is safe or not.
check for every edge.
This function solves the m Coloring problem using recursion . It returns false if the m colours cannot be assigned , otherwise , return true and prints assignments of colours to all vertices . Please note that there may be more than one solutions , this function prints one of the feasible solutions ..
if current index reached end.
if coloring is safe.
Prthe solution.
Assign each color from 1 to m.
Recur of the rest vertices.
Driver code.
Create following graph and test whether it is 3 colorable ( 3 ) -- - ( 2 ) | / | | / | | / | ( 0 ) -- - ( 1 ).
Number of colors.
Initialize all color values as 0. This initialization is needed correct functioning of isSafe ( )"
How can the above be solved in Python?

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Write me a code to m Coloring Problem and the other steps required?
assistant
#Here is code to m Coloring Problem and the other steps required.
 def printSolution ( color ) :
	print ( " Solution ▁ Exists : " " ▁ Following ▁ are ▁ the ▁ assigned ▁ colors ▁ " )
	for i in range ( 4 ) :
		print ( color [ i ] , end = " ▁ " )
def isSafe ( graph , color ) :
	for i in range ( 4 ) :
		for j in range ( i + 1 , 4 ) :
			if ( graph [ i ] [ j ] and color [ j ] == color [ i ] ) :
				return False
	return True
def graphColoring ( graph , m , i , color ) :
	if ( i == 4 ) :
		if ( isSafe ( graph , color ) ) :
			printSolution ( color )
			return True
		return False
	for j in range ( 1 , m + 1 ) :
		color [ i ] = j
		if ( graphColoring ( graph , m , i + 1 , color ) ) :
			return True
		color [ i ] = 0
	return False
if __name__ == ' _ _ main _ _ ' :
	graph = [ [ 0 , 1 , 1 , 1 ] , [ 1 , 0 , 1 , 0 ] , [ 1 , 1 , 0 , 1 ] , [ 1 , 0 , 1 , 0 ] , ]
	m = 3
	color = [ 0 for i in range ( 4 ) ]
	if ( not graphColoring ( graph , m , 0 , color ) ) :
		print ( " Solution ▁ does ▁ not ▁ exist " )