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Find a number in minimum steps | Python3 program to Find a number in minimum steps.
Steps sequence.
Current sum.
Sign of the number.
Basic steps required to get sum >= required value ..
If we have reached ahead to destination ..
If the last step was an odd number , then it has following mechanism for negating a particular number and decreasing the sum to required number Also note that it may require 1 more step in order to reach the sum ..
If the current time instance is even and sum is odd than it takes 2 more steps and few negations in previous elements to reach there ..
Driver code"
Solution in Python:

Can you provide a code to find a number in minimum steps and the other steps required?
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#Here is code to find a number in minimum steps and the other steps required.
 def find ( n ) :
	ans = [ ]
	Sum = 0
	i = 0
	sign = 0
	if ( n >= 0 ) :
		sign = 1
	else :
		sign = - 1
	n = abs ( n )
	i = 1
	while ( Sum < n ) :
		ans . append ( sign * i )
		Sum += i
		i += 1
	if ( Sum > sign * n ) :
		if ( i % 2 != 0 ) :
			Sum -= n
			if ( Sum % 2 != 0 ) :
				ans . append ( sign * i )
				Sum += i
				i += 1
			ans [ int ( Sum / 2 ) - 1 ] *= - 1
		else :
			Sum -= n
			if ( Sum % 2 != 0 ) :
				Sum -= 1
				ans . append ( sign * i )
				ans . append ( sign * - 1 * ( i + 1 ) )
			ans [ int ( ( sum / 2 ) ) - 1 ] *= - 1
	return ans
n = 20
if ( n == 0 ) :
	print ( " Minimum number of Steps : 0 Step sequence : 0 " )
else :
	a = find ( n )
	print ( " Minimum ▁ number ▁ of ▁ Steps : " , len ( a ) )
	print ( " Step ▁ sequence : " )
	print ( * a , sep = " ▁ " )