human
Number of trailing zeros in N * ( N | Function to return the count of trailing 0 s in the given function.
If n is odd.
If n is even.
Find the trailing zeros in n / 2 factorial.
Return the required answer.
Driver code"
Solution in Python:
assistant
#Here is code to number of trailing zeros in N * ( N and the other steps required.
 def findTrailingZeros ( n ) :
	if ( n & 1 ) :
		return 0
	else :
		ans = 0
		n //= 2
		while ( n ) :
			ans += n // 5
			n //= 5
		return ans
n = 12
print ( findTrailingZeros ( n ) )