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Count the number of carry operations required to add two numbers | Function to count the number of carry operations.
Initialize the value of carry to 0.
Counts the number of carry operations.
Initialize len_a and len_b with the sizes of strings.
Assigning the ascii value of the character.
Add both numbers / digits.
If sum > 0 , increment count and set carry to 1.
Else , set carry to 0.
Driver code"
Solution in Python:
 What is a code to count the number of carry operations required to add two numbers and the other steps required?
assistant
#Here is code to count the number of carry operations required to add two numbers and the other steps required.
 def count_carry ( a , b ) :
	carry = 0 ;
	count = 0 ;
	len_a = len ( a ) ;
	len_b = len ( b ) ;
	while ( len_a != 0 or len_b != 0 ) :
		x = 0 ;
		y = 0 ;
		if ( len_a > 0 ) :
			x = int ( a [ len_a - 1 ] ) + int ( '0' ) ;
			len_a -= 1 ;
		if ( len_b > 0 ) :
			y = int ( b [ len_b - 1 ] ) + int ( '0' ) ;
			len_b -= 1 ;
		sum = x + y + carry ;
		if ( sum >= 10 ) :
			carry = 1 ;
			count += 1 ;
		else :
			carry = 0 ;
	return count ;
a = "9555" ;
b = "555" ;
count = count_carry ( a , b ) ;
if ( count == 0 ) :
	print ( "0" ) ;
elif ( count == 1 ) :
	print ( "1" ) ;
else :
	print ( count ) ;