human
Check whether the given decoded string is divisible by 6 | Function to return the sum of the digits of n.
Function that return true if the decoded string is divisible by 6.
To store the sum of the digits.
For each character , get the sum of the digits.
If the sum of digits is not divisible by 3.
Get the last digit of the number formed.
If the last digit is not divisible by 2.
Driver code"
Solution in Python:
 ... Can you provide a code to check whether the given decoded string is divisible by 6 and the other steps required?
assistant
#Here is code to check whether the given decoded string is divisible by 6 and the other steps required.
 def sumDigits ( n ) :
	sum = 0 ;
	while ( n > 0 ) :
		digit = n % 10 ;
		sum += digit ;
		n //= 10 ;
	return sum ;
def isDivBySix ( string , n ) :
	sum = 0 ;
	for i in range ( n ) :
		sum += ( ord ( string [ i ] ) - ord ( ' a ' ) + 1 ) ;
	if ( sum % 3 != 0 ) :
		return False ;
	lastDigit = ( ord ( string [ n - 1 ] ) - ord ( ' a ' ) + 1 ) % 10 ;
	if ( lastDigit % 2 != 0 ) :
		return False ;
	return True ;
if __name__ == " _ _ main _ _ " :
	string = " ab " ;
	n = len ( string ) ;
	if ( isDivBySix ( string , n ) ) :
		print ( " Yes " ) ;
	else :
		print ( " No " ) ;