human
Find the missing elements from 1 to M in given N ranges | Function to find missing elements from given Ranges.
First of all sort all the given ranges.
store ans in a different vector.
prev is use to store end of last range.
j is used as a counter for ranges.
for last segment.
finally print all answer.
Driver Code.
Store ranges in vector of pair"
Solution in Python:

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Can you provide a code to find the missing elements from 1 to M in given N ranges and the other steps required?
assistant
#Here is code to find the missing elements from 1 to M in given N ranges and the other steps required.
 def findMissingNumber ( ranges , m ) :
	ranges . sort ( )
	ans = [ ]
	prev = 0
	for j in range ( len ( ranges ) ) :
		start = ranges [ j ] [ 0 ]
		end = ranges [ j ] [ 1 ]
		for i in range ( prev + 1 , start ) :
			ans . append ( i )
		prev = end
	for i in range ( prev + 1 , m + 1 ) :
		ans . append ( i )
	for i in range ( len ( ans ) ) :
		if ans [ i ] <= m :
			print ( ans [ i ] , end = " ▁ " )
if __name__ == " _ _ main _ _ " :
	N , M = 2 , 6
	ranges = [ ]
	ranges . append ( [ 1 , 2 ] )
	ranges . append ( [ 4 , 5 ] )
	findMissingNumber ( ranges , M )