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What is a code to minimum given operations required to convert a given binary string to all 1 's and the other steps required given the following:
Minimum given operations required to convert a given binary string to all 1 's | Function to return the number of operations required.
ctr will store the number of consecutive ones at the end of the given binary string.
Loop to find number of 1 s at the end of the string.
If the current character is 1.
If we encounter the first 0 from the LSB position then we 'll break the loop.
Number of operations required is ( l - ctr ).
Function to remove leading zeroes from the string.
Loop until s [ i ] becomes not equal to 1.
If we reach the end of the string , it means that string contains only 0 's.
Return the string without leading zeros.
Driver code.
Removing the leading zeroes"
Solution in Python:
assistant
#Here is code to minimum given operations required to convert a given binary string to all 1 's and the other steps required.
 def changeToOnes ( string ) :
	ctr = 0 ;
	l = len ( string ) ;
	for i in range ( l - 1 , - 1 , - 1 ) :
		if ( string [ i ] == '1' ) :
			ctr += 1 ;
		else :
			break ;
	return l - ctr ;
def removeZeroesFromFront ( string ) :
	s = " " ;
	i = 0 ;
	while ( i < len ( string ) and string [ i ] == '0' ) :
		i += 1 ;
	if ( i == len ( string ) ) :
		s = "0" ;
	else :
		s = string [ i : len ( string ) - i ] ;
	return s ;
if __name__ == " _ _ main _ _ " :
	string = "10010111" ;
	string = removeZeroesFromFront ( string ) ;
	print ( changeToOnes ( string ) ) ;