human
Longest subarray with all even or all odd elements | Function to calculate longest substring with odd or even elements.
Initializing dp Initializing dp with 1.
ans will store the final answer.
Traversing the array from index 1 to N - 1.
Checking both current and previous element is even or odd.
Updating dp with ( previous dp value ) + 1.
Storing max element so far to ans.
Returning the final answer.
Input.
Function call"
How can the above be solved in Python?

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What is a code to longest subarray with all even or all odd elements and the other steps required?
assistant
#Here is code to longest subarray with all even or all odd elements and the other steps required.
 def LongestOddEvenSubarray ( A , N ) :
	dp = 1
	ans = 1
	for i in range ( 1 , N ) :
		if ( ( A [ i ] % 2 == 0 and A [ i - 1 ] % 2 == 0 ) or ( A [ i ] % 2 != 0 and A [ i - 1 ] % 2 != 0 ) ) :
			dp = dp + 1
			ans = max ( ans , dp )
		else :
			dp = 1
	return ans
A = [ 2 , 5 , 7 , 2 , 4 , 6 , 8 , 3 ]
N = len ( A )
print ( LongestOddEvenSubarray ( A , N ) )