human
Minimum number of distinct elements after removing m items | Function to find distintc id 's.
Store the occurrence of ids.
Store into the list value as key and vice - versa.
Start removing elements from the beginning.
Remove if current value is less than or equal to mi.
Return the remaining size.
Driver code"
Solution in Python:

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Write me a code to minimum number of distinct elements after removing m items and the other steps required?
assistant
#Here is code to minimum number of distinct elements after removing m items and the other steps required.
 def distinctIds ( arr , n , mi ) :
	m = { }
	v = [ ]
	count = 0
	for i in range ( n ) :
		if arr [ i ] in m :
		m [ arr [ i ] ] += 1
		else :
		m [ arr [ i ] ] = 1
	for i in m :
		v . append ( [ m [ i ] , i ] )
	v . sort ( )
	size = len ( v )
	for i in range ( size ) :
		if ( v [ i ] [ 0 ] <= mi ) :
		mi -= v [ i ] [ 0 ]
		count += 1
		else :
		return size - count
	return size - count
arr = [ 2 , 3 , 1 , 2 , 3 , 3 ]
n = len ( arr )
m = 3
print ( distinctIds ( arr , n , m ) )