human
Lexicographically largest N | Function to find the lexicographically largest bitonic sequence of size N elements lies in the range [ low , high ].
Store index of highest element.
If high_index > ( N - 1 ) / 2 , then remaining N / 2 elements cannot be placed in bitonic order.
If high_index <= 0 , then set high_index as 1.
Stores the resultant sequence.
Store the high value.
Maintain strictly decreasing sequence from index high_index to 0 starting with temp.
Store the value and decrement the temp variable by 1.
Maintain the strictly decreasing sequence from index high_index + 1 to N - 1 starting with high - 1.
Store the value and decrement high by 1.
Print the resultant sequence.
Driver Code.
Function Call"
How can the above be solved in Python?

Write me a code to lexicographically largest N and the other steps required?
assistant
#Here is code to lexicographically largest N and the other steps required.
 def LargestArray ( N , low , high ) :
	high_index = N - ( high - low + 1 )
	if ( high_index > ( N - 1 ) // 2 ) :
		print ( " Not ▁ Possible " )
		return
	if ( high_index <= 0 ) :
		high_index = 1
	A = [ 0 ] * N
	temp = high
	for i in range ( high_index , - 1 , - 1 ) :
		A [ i ] = temp
		temp = temp - 1
	high -= 1
	for i in range ( high_index + 1 , N ) :
		A [ i ] = high
		high = high - 1
	for i in range ( N ) :
		print ( A [ i ] , end = " ▁ " )
N = 5
low = 2
high = 6
LargestArray ( N , low , high )