human
What is a code to count prime numbers that can be expressed as sum of consecutive prime numbers and the other steps required given the following:
Count prime numbers that can be expressed as sum of consecutive prime numbers | Function to check if a number is prime or not.
Base Case.
Iterate till [ 5 , sqrt ( N ) ] to detect primality of numbers.
If N is divisible by i or i + 2.
Return 1 if N is prime.
Function to count the prime numbers which can be expressed as sum of consecutive prime numbers.
Initialize count as 0.
Stores prime numbers.
If i is prime.
Initialize the sum.
Find all required primes upto N.
Add it to the sum.
Return the final count.
Given number N.
Function call"
How can the above be solved in Python?
assistant
#Here is code to count prime numbers that can be expressed as sum of consecutive prime numbers and the other steps required.
 def isprm ( n ) :
	if ( n <= 1 ) :
		return 0
	if ( n <= 3 ) :
		return 1
	if ( n % 2 == 0 or n % 3 == 0 ) :
		return 0
	i = 5
	while ( i * i <= n ) :
		if ( n % i == 0 or n % ( i + 2 ) == 0 ) :
			return 0
		i = i + 6
	return 1
def countprime ( n ) :
	count = 0
	primevector = [ ]
	for i in range ( 2 , n + 1 ) :
		if ( isprm ( i ) == 1 ) :
			primevector . append ( i )
	sum = primevector [ 0 ]
	for i in range ( 1 , len ( primevector ) ) :
		sum += primevector [ i ]
		if ( sum > n ) :
			break
		if ( isprm ( sum ) == 1 ) :
			count += 1
	return count
N = 45
print ( countprime ( N ) )