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Find sum of exponents of prime factors of numbers 1 to N | Function to implement sieve of erastosthenes.
Create a boolean array and initialize all entries as false.
Initializing smallest factor equal to 2 for all the even numbers.
Iterate for odd numbers less then equal to n.
s ( i ) for a prime is the number itself.
For all multiples of current prime number.
i is the smallest prime factor for number " i * j ".
Function to generate prime factors and its power.
s [ i ] is going to store smallest prime factor of i.
Current prime factor of N.
Power of current prime factor.
Calculating prime factors and their powers sum.
Increment the count and continue the process.
Add count to the sum.
Reinitialize count.
Return the result.
Function to find the sum of all the power of prime factors of N.
Iterate for in [ 2 , N ].
Driver Code.
Given number N.
Function call"
How can the above be solved in Python?
assistant
#Here is code to find sum of exponents of prime factors of numbers 1 to N and the other steps required.
 def sieveOfEratosthenes ( N , s ) :
	prime = [ False ] * ( N + 1 )
	for i in range ( 2 , N + 1 , 2 ) :
		s [ i ] = 2
	for i in range ( 3 , N + 1 , 2 ) :
		if ( prime [ i ] == False ) :
			s [ i ] = i
			j = i
			while ( j * i <= N ) :
				if ( prime [ i * j ] == False ) :
					prime [ i * j ] = True
					s [ i * j ] = i
				j += 2
def generatePrimeFactors ( N ) :
	s = [ 0 ] * ( N + 1 )
	sum = 0
	sieveOfEratosthenes ( N , s )
	curr = s [ N ]
	cnt = 1
	while ( N > 1 ) :
		N //= s [ N ]
		if ( curr == s [ N ] ) :
			cnt += 1
			continue
		sum = sum + cnt
		curr = s [ N ]
		cnt = 1
	return sum
def findSum ( N ) :
	sum = 0
	for i in range ( 2 , N + 1 ) :
		sum += generatePrimeFactors ( i )
	print ( sum )
if __name__ == ' _ _ main _ _ ' :
	N = 4
	findSum ( N )