human
Longest Possible Chunked Palindrome | Here curr_str is the string whose LCP is needed leng is length of string evaluated till now and s is original string.
If there is nothing at all ! !.
If a single letter is left out.
For each length of substring chunk in string.
If left side chunk and right side chunk are same.
Call LCP for the part between the chunks and add 2 to the result . Length of string evaluated till now is increased by ( i + 1 ) * 2.
Wrapper over LPCRec ( ).
Driver code"
How can the above be solved in Python?

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Can you provide a code to longest Possible Chunked Palindrome and the other steps required?
assistant
#Here is code to longest Possible Chunked Palindrome and the other steps required.
 def LPCRec ( curr_str , count , leng , s ) :
	if not curr_str :
		return 0
	if len ( curr_str ) <= 1 :
		if count != 0 and len ( s ) - leng <= 1 :
			return ( count + 1 )
		else :
			return 1
	n = len ( curr_str )
	for i in range ( n // 2 ) :
		if ( curr_str [ 0 : i + 1 ] == curr_str [ n - 1 - i : n ] ) :
			return LPCRec ( curr_str [ i + 1 : n - 1 - i ] , count + 2 , leng + ( i + 1 ) * 2 , s )
	return count + 1
def LPC ( s ) :
	return LPCRec ( s , 0 , 0 , s )
print ( " V ▁ : " , LPC ( " V " ) )
print ( " VOLVO ▁ : " , LPC ( " VOLVO " ) )
print ( " VOLVOV ▁ : " , LPC ( " VOLVOV " ) )
print ( " ghiabcdefhelloadamhelloabcdefghi ▁ : " , LPC ( " ghiabcdefhelloadamhelloabcdefghi " ) )
print ( " ghiabcdefhelloadamhelloabcdefghik ▁ : " , LPC ( " ghiabcdefhelloadamhelloabcdefghik " ) )
print ( " antaprezatepzapreanta ▁ : " , LPC ( " antaprezatepzapreanta " ) )