human
Complete the below
def jn_zeros(n, k, method='sympy', dps=15):

    ''''Zeros of the spherical Bessel function of the first kind.
    This returns an array of zeros of jn up to the k-th zero.
    * method = "sympy": uses :func:`mpmath.besseljzero`
    * method = "scipy": uses the
    `SciPy\'s sph_jn <http://docs.scipy.org/doc/scipy/reference/generated/scipy.special.jn_zeros.html>`_
    and
    `newton <http://docs.scipy.org/doc/scipy/reference/generated/scipy.optimize.newton.html>`_
    to find all
    roots, which is faster than computing the zeros using a general
    numerical solver, but it requires SciPy and only works with low
    precision floating point numbers.  [The function used with
    method="sympy" is a recent addition to mpmath, before that a general
    solver was used.]
    Examples
    >>> from sympy import jn_zeros
    >>> jn_zeros(2, 4, dps=5)
    [5.7635, 9.095, 12.323, 15.515]
    See Also
    jn, yn, besselj, besselk, bessely'
    '''
assistant
#Here is Python code to find all
.
    from math import pi
    if (method == 'sympy'):
        from mpmath import besseljzero
        from mpmath.libmp.libmpf import dps_to_prec
        from sympy import Expr
        prec = dps_to_prec(dps)
        return [Expr._from_mpmath(besseljzero(S((n + 0.5))._to_mpmath(prec), int(l)), prec) for l in range(1, (k + 1))]
    elif (method == 'scipy'):
        from scipy.optimize import newton
        try:
            from scipy.special import spherical_jn
            f = (lambda x: spherical_jn(n, x))
        except ImportError:
            from scipy.special import sph_jn
            f = (lambda x: sph_jn(n, x)[0][(-1)])
    else:
        raise NotImplementedError('Unknown    method.')
    def solver(f, x):
        if (method == 'scipy'):
            root = newton(f, x)
        else:
            raise NotImplementedError('Unknown    method.')
        return root
    root = (n + pi)
    root = solver(f, root)
    roots = [root]
    for i in range((k - 1)):
        root = solver(f, (root + pi))
        roots.append(root)
    return roots