human
What is a the Python code you requested given the following:
I found an interesting problem on https://leetcode.com/problems/search-a-2d-matrix/:
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

       Integers in each row are sorted from left to right.
       The first integer of each row is greater than the last integer of the previous row.

Example 1:

Input:
matrix = [
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]
target = 3
Output: true

Example 2:

Input:
matrix = [
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]
target = 13
Output: false

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python code you requested.

class Solution:
     def searchMatrix(self, matrix, target):
         """
         :type matrix: List[List[int]]
         :type target: int
         :rtype: bool
         """
         print((len(matrix)))
         if(len(matrix)==0):
             return False
         if len(matrix)==1 and len(matrix[0])==0:
             return False
         existFlag=0
         last=len(matrix[0])-1
         for i in range(len(matrix)):
             if matrix[i][last]<target:
                 continue
             else:
                 print("falg set to 1")
                 existFlag=1
                 break
         if existFlag==1:
             #existFlag=0
             print("yes it is 1")
             for j in range(last,-1,-1):
                 print(("j= ",j))
                 if matrix[i][j]==target:
                     return True
         return False