human
Can you provide a code to check if an array can be converted to another given array by swapping pairs of unequal elements and the other steps required given the following:
Check if an array can be converted to another given array by swapping pairs of unequal elements | Function to check if arr1 [ ] can be converted to arr2 [ ] by swapping pair ( i , j ) such that i < j and arr [ i ] is 1 and arr [ j ] is 0.
Stores the differences of prefix sum of arr1 and arr2.
Stores the count of 1 and zero of arr1.
Stores the count of 1 and zero of arr2.
Iterate in the range [ 0 , N - 1 ].
If arr1 [ i ] is 1 , then increment arr1_one by one.
Otherwise increment arr1_zero by one.
If arr2 [ i ] is 1 , then increment arr2_one by one.
Otherwise increment arr2_zero by one.
Check if number of 1 s and 0 s of arr1 is equal to number of 1 s and 0 s of arr2 respectievly.
Iterate over the range [ 0 , N - 1 ].
Increment count by differences arr1 [ i ] and arr2 [ i ].
Check if number of 1 's in  arr2 are more than arr1 and  then print "No".
Finally , print " Yes ".
Driver Code.
Given input a.
Size of the array.
Function Call"
How can the above be solved in Python?
assistant
#Here is code to check if an array can be converted to another given array by swapping pairs of unequal elements and the other steps required.
 def canMakeEqual ( arr1 , arr2 , N ) :
	count = 0
	arr1_one = 0
	arr1_zero = 0
	arr2_one = 0
	arr2_zero = 0
	for i in range ( N ) :
		if ( arr1 [ i ] == 1 ) :
			arr1_one += 1
		elif ( arr1 [ i ] == 0 ) :
			arr1_zero += 1
		if ( arr2 [ i ] == 1 ) :
			arr2_one += 1
		elif ( arr2 [ i ] == 0 ) :
			arr2_zero += 1
	if ( arr1_one != arr2_one or arr1_zero != arr2_zero ) :
		print ( " No " )
		return
	for i in range ( N ) :
		count = count + ( arr1 [ i ] - arr2 [ i ] )
		if ( count < 0 ) :
			print ( " No " )
			return
	print ( " Yes " )
if __name__ == ' _ _ main _ _ ' :
	arr1 = [ 0 , 1 , 1 , 0 ]
	arr2 = [ 0 , 0 , 1 , 1 ]
	N = len ( arr1 )
	canMakeEqual ( arr1 , arr2 , N )