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Give me a code to count Negative Numbers in a Column and the other steps required given the following:
Count Negative Numbers in a Column | Recursive binary search to get last negative value in a row between a start and an end.
Base case.
Get the mid for binary search.
If current element is negative.
If it is the rightmost negative element in the current row.
Check in the right half of the array.
Check in the left half of the array.
Function to return the count of negative numbers in the given matrix.
Initialize result.
To store the index of the rightmost negative element in the row under consideration.
Iterate over all rows of the matrix.
If the first element of the current row is positive then there will be no negatives in the matrix below or after it.
Run binary search only until the index of last negative Integer in the above row.
Driver code"
Solution in Python:
assistant
#Here is code to count Negative Numbers in a Column and the other steps required.
 def getLastNegativeIndex ( array , start , end , n ) :
	if ( start == end ) :
		return start
	mid = start + ( end - start ) // 2
	if ( array [ mid ] < 0 ) :
		if ( mid + 1 < n and array [ mid + 1 ] >= 0 ) :
			return mid
		return getLastNegativeIndex ( array , mid + 1 , end , n )
	else :
		return getLastNegativeIndex ( array , start , mid - 1 , n )
def countNegative ( M , n , m ) :
	count = 0
	nextEnd = m - 1
	for i in range ( n ) :
		if ( M [ i ] [ 0 ] >= 0 ) :
			break
		nextEnd = getLastNegativeIndex ( M [ i ] , 0 , nextEnd , 4 )
		count += nextEnd + 1
	return count
M = [ [ - 3 , - 2 , - 1 , 1 ] , [ - 2 , 2 , 3 , 4 ] , [ 4 , 5 , 7 , 8 ] ]
r = 3
c = 4
print ( countNegative ( M , r , c ) )