human
Numbers having difference with digit sum more than s | function for digit sum.
function to calculate count of integer s . t . integer - digSum > s.
if n < s no integer possible.
iterate for s range and then calculate total count of such integer if starting integer is found.
if no integer found return 0.
driver code"
How can the above be solved in Python?
assistant
#Here is code to numbers having difference with digit sum more than s and the other steps required.
 def digitSum ( n ) :
	digSum = 0
	while ( n > 0 ) :
		digSum += n % 10
		n //= 10
	return digSum
def countInteger ( n , s ) :
	if ( n < s ) :
		return 0
	for i in range ( s , min ( n , s + 163 ) + 1 ) :
		if ( ( i - digitSum ( i ) ) > s ) :
			return ( n - i + 1 )
	return 0
n = 1000
s = 100
print ( countInteger ( n , s ) )