human
Can you provide a code to program to convert a given number to words and the other steps required given the following:
Program to convert a given number to words | A function that prints given number in words.
Get number of digits in given number.
Base cases.
The first string is not used , it is to make array indexing simple.
The first string is not used , it is to make array indexing simple.
The first two string are not used , they are to make array indexing simple.
Used for debugging purpose only.
For single digit number.
Iterate while num is not '\0.
Code path for first 2 digits.
here len can be 3 or 4.
Code path for last 2 digits.
Need to explicitly handle 10 - 19. Sum of the two digits is used as index of " two _ digits " array of strings.
Need to explicitely handle 20.
Rest of the two digit numbers i . e . , 21 to 99"
How can the above be solved in Python?
assistant
#Here is code to program to convert a given number to words and the other steps required.
 def convert_to_words ( num ) :
	l = len ( num )
	if ( l == 0 ) :
		print ( " empty ▁ string " )
		return
	if ( l > 4 ) :
		print ( " Length ▁ more ▁ than ▁ 4 ▁ is ▁ not ▁ supported " )
		return
	single_digits = [ " zero " , " one " , " two " , " three " , " four " , " five " , " six " , " seven " , " eight " , " nine " ]
	two_digits = [ " " , " ten " , " eleven " , " twelve " , " thirteen " , " fourteen " , " fifteen " , " sixteen " , " seventeen " , " eighteen " , " nineteen " ]
	tens_multiple = [ " " , " " , " twenty " , " thirty " , " forty " , " fifty " , " sixty " , " seventy " , " eighty " , " ninety " ]
	tens_power = [ " hundred " , " thousand " ]
	print ( num , " : " , end = " ▁ " )
	if ( l == 1 ) :
		print ( single_digits [ ord ( num [ 0 ] ) - 48 ] )
		return
'
	x = 0
	while ( x < len ( num ) ) :
		if ( l >= 3 ) :
			if ( ord ( num [ x ] ) - 48 != 0 ) :
				print ( single_digits [ ord ( num [ x ] ) - 48 ] , end = " ▁ " )
				print ( tens_power [ l - 3 ] , end = " ▁ " )
			l -= 1
		else :
			if ( ord ( num [ x ] ) - 48 == 1 ) :
				sum = ( ord ( num [ x ] ) - 48 + ord ( num [ x + 1 ] ) - 48 )
				print ( two_digits [ sum ] )
				return
			elif ( ord ( num [ x ] ) - 48 == 2 and ord ( num [ x + 1 ] ) - 48 == 0 ) :
				print ( " twenty " )
				return
			else :
				i = ord ( num [ x ] ) - 48
				if ( i > 0 ) :
					print ( tens_multiple [ i ] , end = " ▁ " )
				else :
					print ( " " , end = " " )
				x += 1
				if ( ord ( num [ x ] ) - 48 != 0 ) :
					print ( single_digits [ ord ( num [ x ] ) - 48 ] )
		x += 1