human
Solve in Python:
Your friend is typing his name into a keyboard.  Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.
You examine the typed characters of the keyboard.  Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.
 
Example 1:
Input: name = "alex", typed = "aaleex"
Output: true
Explanation: 'a' and 'e' in 'alex' were long pressed.

Example 2:
Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: 'e' must have been pressed twice, but it wasn't in the typed output.

Example 3:
Input: name = "leelee", typed = "lleeelee"
Output: true

Example 4:
Input: name = "laiden", typed = "laiden"
Output: true
Explanation: It's not necessary to long press any character.

 
Constraints:

1 <= name.length <= 1000
1 <= typed.length <= 1000
The characters of name and typed are lowercase letters.
 ... Give me a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
    def isLongPressedName(self, name: str, typed: str) -> bool:
        n = 0
        t = 0
        
        while n < len(name) and t < len(typed):
            if name[n] == typed[t]:
                n += 1
                t += 1
            else:
                if t and typed[t] == typed[t - 1]:
                    t += 1
                else:
                    return False
        
        if n != len(name):
            return False
            
        while t < len(typed):
            if typed[t] == typed[t - 1]:
                t += 1
            else:
                return False
        
        return True