human
Number of Groups of Sizes Two Or Three Divisible By 3 | Program to find groups of 2 or 3 whose sum is divisible by 3.
Initialize groups to 0.
Increment group with specified remainder.
Return groups using the formula.
Driver code"
How can the above be solved in Python?

Give me a code to number of Groups of Sizes Two Or Three Divisible By 3 and the other steps required?
assistant
#Here is code to number of Groups of Sizes Two Or Three Divisible By 3 and the other steps required.
 def numOfCombinations ( arr , N ) :
	C = [ 0 , 0 , 0 ]
	for i in range ( N ) :
		C [ arr [ i ] % 3 ] = C [ arr [ i ] % 3 ] + 1
	return ( C [ 1 ] * C [ 2 ] + C [ 0 ] * ( C [ 0 ] - 1 ) / 2 + C [ 0 ] * ( C [ 0 ] - 1 ) * ( C [ 0 ] - 2 ) / 6 + C [ 1 ] * ( C [ 1 ] - 1 ) * ( C [ 1 ] - 2 ) / 6 + C [ 2 ] * ( C [ 2 ] - 1 ) * ( C [ 2 ] - 2 ) / 6 + C [ 0 ] * C [ 1 ] * C [ 2 ] )
arr1 = [ 1 , 5 , 7 , 2 , 9 , 14 ]
print ( int ( numOfCombinations ( arr1 , 6 ) ) )
arr2 = [ 3 , 6 , 9 , 12 ]
print ( int ( numOfCombinations ( arr2 , 4 ) ) )