human
Check whether an array can be made strictly decreasing by modifying at most one element | Function that returns true if the array can be made strictly decreasing with at most one change.
To store the number of modifications required to make the array strictly decreasing.
Check whether the last element needs to be modify or not.
Check whether the first element needs to be modify or not.
Loop from 2 nd element to the 2 nd last element.
Check whether arr [ i ] needs to be modified.
Modifying arr [ i ].
Check if arr [ i ] is equal to any of arr [ i - 1 ] or arr [ i + 1 ].
If more than 1 modification is required.
Driver code"
How can the above be solved in Python?

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Write me a code to check whether an array can be made strictly decreasing by modifying at most one element and the other steps required?
assistant
#Here is code to check whether an array can be made strictly decreasing by modifying at most one element and the other steps required.
 def check ( arr , n ) :
	modify = 0
	if ( arr [ n - 1 ] >= arr [ n - 2 ] ) :
		arr [ n - 1 ] = arr [ n - 2 ] - 1
		modify += 1
	if ( arr [ 0 ] <= arr [ 1 ] ) :
		arr [ 0 ] = arr [ 1 ] + 1
		modify += 1
	for i in range ( n - 2 , 0 , - 1 ) :
		if ( arr [ i - 1 ] <= arr [ i ] and arr [ i + 1 ] <= arr [ i ] ) or ( arr [ i - 1 ] >= arr [ i ] and arr [ i + 1 ] >= arr [ i ] ) :
			arr [ i ] = ( arr [ i - 1 ] + arr [ i + 1 ] ) // 2
			modify += 1
			if ( arr [ i ] == arr [ i - 1 ] or arr [ i ] == arr [ i + 1 ] ) :
				return False
	if ( modify > 1 ) :
		return False
	return True
if __name__ == " _ _ main _ _ " :
	arr = [ 10 , 5 , 11 , 3 ]
	n = len ( arr )
	if ( check ( arr , n ) ) :
		print ( " Yes " )
	else :
		print ( " No " )