human
Can you provide a code to smallest odd digits number not less than N and the other steps required given the following:
Smallest odd digits number not less than N | function to return the smallest number with all digits odd.
convert the number to string to perform operations.
find out the first even number.
if no even numbers are there , than n is the answer.
add all digits till first even.
increase the even digit by 1.
add 1 to the right of the even number.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to smallest odd digits number not less than N and the other steps required.
 def smallestNumber ( n ) :
	num = 0
	s = " "
	duplicate = n
	while ( n ) :
		s = chr ( n % 10 + 48 ) + s
		n //= 10
	index = - 1
	for i in range ( len ( s ) ) :
		digit = ord ( s [ i ] ) - ord ( '0' )
		if ( ( digit & 1 ) == 0 ) :
			index = i
			break
	if ( index == - 1 ) :
		return duplicate
	for i in range ( index ) :
		num = num * 10 + ( ord ( s [ i ] ) - ord ( '0' ) )
	num = num * 10 + ( ord ( s [ index ] ) - ord ( '0' ) + 1 )
	for i in range ( index + 1 , len ( s ) ) :
		num = num * 10 + 1
	return num
if __name__ == " _ _ main _ _ " :
	N = 2397
	print ( smallestNumber ( N ) )