human
Count of N digit numbers possible which satisfy the given conditions | Function to return the factorial of n.
Function to return the count of numbers possible.
Driver code"
How can the above be solved in Python?
 Can you provide a code to count of N digit numbers possible which satisfy the given conditions and the other steps required?
assistant
#Here is code to count of N digit numbers possible which satisfy the given conditions and the other steps required.
 def fact ( n ) :
	res = 1
	for i in range ( 2 , n + 1 ) :
		res = res * i
	return res
def Count_number ( N ) :
	return ( N * fact ( N ) )
N = 2
print ( Count_number ( N ) )