human
Count of pairs from 1 to a and 1 to b whose sum is divisible by N | Function to find the distinct pairs from 1 - a & 1 - b such that their sum is divisible by n ..
Iterate over 1 to a to find distinct pairs.
For each integer from 1 to a b / n integers exists such that pair / sum is divisible by n.
If ( i % n + b % n ) >= n one more pair is possible.
Return answer.
Driver code"
How can the above be solved in Python?

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Give me a code to count of pairs from 1 to a and 1 to b whose sum is divisible by N and the other steps required?
assistant
#Here is code to count of pairs from 1 to a and 1 to b whose sum is divisible by N and the other steps required.
 def findCountOfPairs ( a , b , n ) :
	ans = 0
	for i in range ( 1 , a + 1 ) :
		ans += b // n
		ans += 1 if ( i % n + b % n ) >= n else 0
	return ans
a = 5 ; b = 13 ; n = 3
print ( findCountOfPairs ( a , b , n ) )