human
What is a the Python program you requested given the following:
I found an interesting problem on https://leetcode.com/problems/next-greater-node-in-linked-list/:
We are given a linked list with head as the first node.  Let's number the nodes in the list: node_1, node_2, node_3, ... etc.
Each node may have a next larger value: for node_i, next_larger(node_i) is the node_j.val such that j > i, node_j.val > node_i.val, and j is the smallest possible choice.  If such a j does not exist, the next larger value is 0.
Return an array of integers answer, where answer[i] = next_larger(node_{i+1}).
Note that in the example inputs (not outputs) below, arrays such as [2,1,5] represent the serialization of a linked list with a head node value of 2, second node value of 1, and third node value of 5.
 

Example 1:
Input: [2,1,5]
Output: [5,5,0]

Example 2:
Input: [2,7,4,3,5]
Output: [7,0,5,5,0]

Example 3:
Input: [1,7,5,1,9,2,5,1]
Output: [7,9,9,9,0,5,0,0]

 
Note:

1 <= node.val <= 10^9 for each node in the linked list.
The given list has length in the range [0, 10000].

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python program you requested.

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def nextLargerNodes(self, head: ListNode) -> List[int]:
        ans, stack = [], []
        while head:
            while stack and stack[-1][1] < head.val:
                ans[stack.pop()[0]] = head.val
            stack.append([len(ans), head.val])
            ans.append(0)
            head = head.next
        return ans