human
Find if an expression has duplicate parenthesis or not | Function to find duplicate parenthesis in a balanced expression.
create a stack of characters.
Iterate through the given expression.
if current character is close parenthesis ' ) '.
pop character from the stack.
stores the number of characters between a closing and opening parenthesis if this count is less than or equal to 1 then the brackets are redundant else not.
push open parenthesis ' ( ' , operators and operands to stack.
No duplicates found.
Driver Code.
input balanced expression"
Solution in Python:

Can you provide a code to find if an expression has duplicate parenthesis or not and the other steps required?
assistant
#Here is code to find if an expression has duplicate parenthesis or not and the other steps required.
 def findDuplicateparenthesis ( string ) :
	Stack = [ ]
	for ch in string :
		if ch == ' ) ' :
			top = Stack . pop ( )
			elementsInside = 0
			while top != ' ( ' :
				elementsInside += 1
				top = Stack . pop ( )
			if elementsInside < 1 :
				return True
		else :
			Stack . append ( ch )
	return False
if __name__ == " _ _ main _ _ " :
	string = " ( ( ( a + ( b ) ) + ( c + d ) ) ) "
	if findDuplicateparenthesis ( string ) == True :
		print ( " Duplicate ▁ Found " )
	else :
		print ( " No ▁ Duplicates ▁ Found " )