human
XOR of elements in a given range with updates using Fenwick Tree | Returns XOR of arr [ 0. . index ] . This function assumes that the array is preprocessed and partial XORs of array elements are stored in BITree [ ] ..
Traverse ancestors of BITree [ index ].
XOR current element of BIT to ans.
Update index to that of the parent node in getXor ( ) view by subtracting LSB ( Least Significant Bit ).
Updates the Binary Index Tree by replacing all ancestors of index by their respective XOR with val.
Traverse all ancestors and XOR with ' val ' ..
XOR ' val ' to current node of BIT.
Update index to that of the parent node in updateBit ( ) view by adding LSB ( Least Significant Bit ).
Constructs and returns a Binary Indexed Tree for the given array.
Create and initialize the Binary Indexed Tree.
Store the actual values in BITree [ ] using update ( ).
Driver Code.
Create the Binary Indexed Tree.
Solve each query in Q.
Update the values of all ancestors of idx"
Solution in Python:
assistant
#Here is code to xOR of elements in a given range with updates using Fenwick Tree and the other steps required.
 def getXOR ( BITree , index ) :
	ans = 0
	index += 1
	while ( index > 0 ) :
		ans ^= BITree [ index ]
		index -= index & ( - index )
	return ans
def updateBIT ( BITree , n , index , val ) :
	index = index + 1
	while ( index <= n ) :
		BITree [ index ] ^= val
		index += index & ( - index )
def constructBITree ( arr , n ) :
	BITree = [ 0 ] * ( n + 1 )
	for i in range ( n ) :
		updateBIT ( BITree , n , i , arr [ i ] )
	return BITree
def rangeXor ( BITree , l , r ) :
	return ( getXOR ( BITree , r ) ^ getXOR ( BITree , l - 1 ) )
if __name__ == " _ _ main _ _ " :
	A = [ 2 , 1 , 1 , 3 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ]
	n = len ( A )
	q = [ [ 1 , 0 , 9 ] , [ 2 , 3 , 6 ] , [ 2 , 5 , 5 ] , [ 2 , 8 , 1 ] , [ 1 , 0 , 9 ] ]
	BITree = constructBITree ( A , n )
	for i in range ( len ( q ) ) :
		id = q [ i ] [ 0 ]
		if ( id == 1 ) :
			L = q [ i ] [ 1 ]
			R = q [ i ] [ 2 ]
			print ( " XOR ▁ of ▁ elements ▁ in ▁ " " given ▁ range ▁ is ▁ " , rangeXor ( BITree , L , R ) )
		else :
			idx = q [ i ] [ 1 ]
			val = q [ i ] [ 2 ]
			A [ idx ] ^= val
			updateBIT ( BITree , n , idx , val )