human
Give me a code to minimum number of squares whose sum equals to given number N and the other steps required given the following:
Minimum number of squares whose sum equals to given number N | set 2 | Function for finding minimum square numbers.
arr [ i ] of array arr store minimum count of square number to get i.
sqrNum [ i ] store last square number to get i.
Find minimum count of square number for all value 1 to n.
In worst case it will be arr [ i - 1 ] + 1 we use all combination of a [ i - 1 ] and add 1.
Check for all square number less or equal to i.
If it gives less count then update it.
v stores optimum square number whose sum give N.
Driver code.
Calling function.
Printing vector"
How can the above be solved in Python?
assistant
#Here is code to minimum number of squares whose sum equals to given number N and the other steps required.
 def minSqrNum ( n ) :
	arr = [ 0 ] * ( n + 1 )
	sqrNum = [ 0 ] * ( n + 1 )
	v = [ ]
	for i in range ( n + 1 ) :
		arr [ i ] = arr [ i - 1 ] + 1
		sqrNum [ i ] = 1
		k = 1 ;
		while ( k * k <= i ) :
			if ( arr [ i ] > arr [ i - k * k ] + 1 ) :
				arr [ i ] = arr [ i - k * k ] + 1
				sqrNum [ i ] = k * k
			k += 1
	while ( n > 0 ) :
		v . append ( sqrNum [ n ] )
		n -= sqrNum [ n ] ;
	return v
n = 10
v = minSqrNum ( n )
for i in range ( len ( v ) ) :
	print ( v [ i ] , end = " " )
	if ( i < len ( v ) - 1 ) :
		print ( " ▁ + ▁ " , end = " " )