human
Minimize remaining array sizes by removing equal pairs of first array elements | Function to count the remaining elements in the arrays.
Stores the count of 1 s in L1.
Store the count of 0 s in L2.
Traverse the array L1.
If condition is True.
Increment one by 1.
Increment zero by 1.
Stores the index after which no further removals are possible.
Traverse the array L2.
If condition is True.
Decrement one by 1.
If one < 0 , then break out of the loop.
Decrement zero by 1.
If zero < 0 , then break out of loop.
Print the answer.
Driver Code.
Function Call"
How can the above be solved in Python?
 ... Write me a code to minimize remaining array sizes by removing equal pairs of first array elements and the other steps required?
assistant
#Here is code to minimize remaining array sizes by removing equal pairs of first array elements and the other steps required.
 def countRemainingElements ( L1 , L2 , n ) :
	one = 0 ;
	zero = 0 ;
	for i in range ( n ) :
		if ( L1 [ i ] == 1 ) :
			one += 1 ;
		else :
			zero += 1 ;
	ans = n ;
	for i in range ( n ) :
		if ( L2 [ i ] == 1 ) :
			one -= 1 ;
			if ( one < 0 ) :
				ans = i ;
				break ;
		else :
			zero -= 1 ;
			if ( zero < 0 ) :
				ans = i ;
				break ;
	print ( n - ans ) ;
if __name__ == ' _ _ main _ _ ' :
	L1 = [ 1 , 1 , 0 , 0 ] ;
	L2 = [ 0 , 0 , 0 , 1 ] ;
	N = len ( L1 ) ;
	countRemainingElements ( L1 , L2 , N ) ;