human
Find the minimum element in a sorted and rotated array | Function to find minimum element.
Driver code"
How can the above be solved in Python?
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#Here is code to find the minimum element in a sorted and rotated array and the other steps required.
 def findMin ( arr , low , high ) :
	while ( low < high ) :
		mid = low + ( high - low ) // 2 ;
		if ( arr [ mid ] == arr [ high ] ) :
			high -= 1 ;
		elif ( arr [ mid ] > arr [ high ] ) :
			low = mid + 1 ;
		else :
			high = mid ;
	return arr [ high ] ;
if __name__ == ' _ _ main _ _ ' :
	arr1 = [ 5 , 6 , 1 , 2 , 3 , 4 ] ;
	n1 = len ( arr1 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr1 , 0 , n1 - 1 ) ) ;
	arr2 = [ 1 , 2 , 3 , 4 ] ;
	n2 = len ( arr2 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr2 , 0 , n2 - 1 ) ) ;
	arr3 = [ 1 ] ;
	n3 = len ( arr3 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr3 , 0 , n3 - 1 ) ) ;
	arr4 = [ 1 , 2 ] ;
	n4 = len ( arr4 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr4 , 0 , n4 - 1 ) ) ;
	arr5 = [ 2 , 1 ] ;
	n5 = len ( arr5 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr5 , 0 , n5 - 1 ) ) ;
	arr6 = [ 5 , 6 , 7 , 1 , 2 , 3 , 4 ] ;
	n6 = len ( arr6 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr6 , 0 , n6 - 1 ) ) ;
	arr7 = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 ] ;
	n7 = len ( arr7 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr7 , 0 , n7 - 1 ) ) ;
	arr8 = [ 2 , 3 , 4 , 5 , 6 , 7 , 8 , 1 ] ;
	n8 = len ( arr8 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr8 , 0 , n8 - 1 ) ) ;
	arr9 = [ 3 , 4 , 5 , 1 , 2 ] ;
	n9 = len ( arr9 ) ;
	print ( " The ▁ minimum ▁ element ▁ is ▁ " , findMin ( arr9 , 0 , n9 - 1 ) ) ;