human
Minimum letters to be removed to make all occurrences of a given letter continuous | Function to find the minimum number of deletions required to make the occurrences of the given character K continuous.
Find the first occurrence of the given letter.
Iterate from the first occurrence till the end of the sequence.
Find the index from where the occurrence of the character is not continuous.
Update the answer with the number of elements between non - consecutive occurrences of the given letter.
Update the count for all letters which are not equal to the given letter.
Return the count.
Driver code.
Calling the function.
Calling the function"
Solution in Python:

Can you provide a code to minimum letters to be removed to make all occurrences of a given letter continuous and the other steps required?
assistant
#Here is code to minimum letters to be removed to make all occurrences of a given letter continuous and the other steps required.
 def noOfDeletions ( string , k ) :
	ans = 0 ; cnt = 0 ; pos = 0 ;
	while ( pos < len ( string ) and string [ pos ] != k ) :
		pos += 1 ;
	i = pos ;
	while ( i < len ( string ) ) :
		while ( i < len ( string ) and string [ i ] == k ) :
			i = i + 1 ;
		ans = ans + cnt ;
		cnt = 0 ;
		while ( i < len ( string ) and string [ i ] != k ) :
			i = i + 1 ;
			cnt = cnt + 1 ;
	return ans ;
if __name__ == " _ _ main _ _ " :
	str1 = " ababababa " ;
	k1 = ' a ' ;
	print ( noOfDeletions ( str1 , k1 ) ) ;
	str2 = " kprkkoinkopt " ;
	k2 = ' k ' ;
	print ( noOfDeletions ( str2 , k2 ) ) ;