human
Maximize sum of all elements which are not a part of the Longest Increasing Subsequence | Function to find maximum sum.
Find total sum of array.
Maintain a 2D array.
Update the dp array along with sum in the second row.
In case of greater length update the length along with sum.
In case of equal length find length update length with minimum sum.
Find the sum that need to be subtracted from total sum.
Return the sum.
Driver code"
How can the above be solved in Python?

What is a code to maximize sum of all elements which are not a part of the Longest Increasing Subsequence and the other steps required?
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#Here is code to maximize sum of all elements which are not a part of the Longest Increasing Subsequence and the other steps required.
 def findSum ( arr , n ) :
	totalSum = 0
	for i in range ( n ) :
		totalSum += arr [ i ]
	dp = [ [ 0 ] * n for i in range ( 2 ) ]
	for i in range ( n ) :
		dp [ 0 ] [ i ] = 1
		dp [ 1 ] [ i ] = arr [ i ]
	for i in range ( 1 , n ) :
		for j in range ( i ) :
			if ( arr [ i ] > arr [ j ] ) :
				if ( dp [ 0 ] [ i ] < dp [ 0 ] [ j ] + 1 ) :
					dp [ 0 ] [ i ] = dp [ 0 ] [ j ] + 1
					dp [ 1 ] [ i ] = dp [ 1 ] [ j ] + arr [ i ]
				elif ( dp [ 0 ] [ i ] == dp [ 0 ] [ j ] + 1 ) :
					dp [ 1 ] [ i ] = min ( dp [ 1 ] [ i ] , dp [ 1 ] [ j ] + arr [ i ] )
	maxm = 0
	subtractSum = 0
	for i in range ( n ) :
		if ( dp [ 0 ] [ i ] > maxm ) :
			maxm = dp [ 0 ] [ i ]
			subtractSum = dp [ 1 ] [ i ]
		elif ( dp [ 0 ] [ i ] == maxm ) :
			subtractSum = min ( subtractSum , dp [ 1 ] [ i ] )
	return totalSum - subtractSum
arr = [ 4 , 6 , 1 , 2 , 3 , 8 ]
n = len ( arr )
print ( findSum ( arr , n ) )