human
Solve the following python programming problem given the following code:
def diff_cleanupSemanticLossless(self, diffs) : 
    'Look for single edits surrounded on both sides by equalities
    which can be shifted sideways to align the edit to a word boundary.
    e.g: The c<ins>at c</ins>ame. -> The <ins>cat </ins>came.

    Args:
      diffs: Array of diff tuples.
    ' 
    def diff_cleanupSemanticScore(one, two) : 
        'Given two strings, compute a score representing whether the
      internal boundary falls on logical boundaries.
      Scores range from 6 (best) to 0 (worst).
      Closure, but does not reference any external variables.

      Args:
        one: First string.
        two: Second string.

      Returns:
        The score.
      ' 
        if ((not one) or (not two)) : 
            return 6 
char1 = one [(- 1)] 
        char2 = two [0] 
        nonAlphaNumeric1 = (not char1.isalnum ()) 
        nonAlphaNumeric2 = (not char2.isalnum ()) 
        whitespace1 = (nonAlphaNumeric1 and char1.isspace ()) 
        whitespace2 = (nonAlphaNumeric2 and char2.isspace ()) 
        lineBreak1 = (whitespace1 and ((char1 == '\r') or (char1 == '
'))) 
        lineBreak2 = (whitespace2 and ((char2 == '\r') or (char2 == '
'))) 
        blankLine1 = (lineBreak1 and self.BLANKLINEEND.search (one)) 
        blankLine2 = (lineBreak2 and self.BLANKLINESTART.match (two)) 
        if (blankLine1 or blankLine2) : 
            return 5 
else : 
            if (lineBreak1 or lineBreak2) : 
                return 4 
else : 
                if (nonAlphaNumeric1 and (not whitespace1) and whitespace2) : 
                    return 3 
else : 
                    if (whitespace1 or whitespace2) : 
                        return 2 
else : 
                        if (nonAlphaNumeric1 or nonAlphaNumeric2) : 
                            return 1 
return 0 
pointer = 1 
    while (pointer < (len (diffs) - 1)) : 
        if ((diffs [(pointer - 1)] [0] == self.DIFF_EQUAL) and (diffs [(pointer + 1)] [0] == self.DIFF_EQUAL)) : 
            equality1 = diffs [(pointer - 1)] [1] 
            edit =...

    
    

    Fix the buggy line: edit = (self [1 :] + equality2 [0])
assistant
#Here is Python program to fix the buggy line: edit = (self [1 :] + equality2 [0])
.

edit = (edit [1 :] + equality2 [0])