human
Number of ways to reach Nth floor by taking at | Python3 program to reach N - th stair by taking a maximum of K leap.
elements of combo [ ] stores the no of possible ways to reach it by all combinations of k leaps or less.
assuming leap 0 exist and assigning its value to 1 for calculation.
loop to iterate over all possible leaps upto k.
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in this loop we count all possible leaps to reach the jth stair with the help of ith leap or less.
if the leap is not more than the i - j.
calculate the value and store in combo [ j ] to reuse it for next leap calculation for the jth stair.
returns the no of possible number of leaps to reach the top of building of n stairs.
Driver Code.
N i the no of total stairs K is the value of the greatest leap"
How can the above be solved in Python?

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What is a code to number of ways to reach Nth floor by taking at and the other steps required?
assistant
#Here is code to number of ways to reach Nth floor by taking at and the other steps required.
 def solve ( N , K ) :
	combo = [ 0 ] * ( N + 1 )
	combo [ 0 ] = 1
	for i in range ( 1 , K + 1 ) :
		for j in range ( 0 , N + 1 ) :
			if j >= i :
				combo [ j ] += combo [ j - i ]
	return combo [ N ]
if __name__ == " _ _ main _ _ " :
	N , K = 29 , 5
	print ( solve ( N , K ) )