human
Solve the following python programming problem given the following code:
def ExecuteAfterDelay(time_s, func, * args, **kwargs) : 
    'A function that executes the given function after a delay.

  Executes func in a separate thread after a delay, so that this function
  returns immediately.  Note that any exceptions raised by func will be
  ignored (but logged).  Also, if time_s is a PolledTimeout with no expiration,
  then this method simply returns immediately and does nothing.

  Args:
    time_s: Delay in seconds to wait before executing func, may be a
      PolledTimeout object.
    func: Function to call.
    *args: Arguments to call the function with.
    **kwargs: Keyword arguments to call the function with.
  ' 
    timeout = PolledTimeout.FromSeconds (timeout) 
    def Target() : 
        time.sleep (timeout.remaining) 
        try : 
            func (* args, ** kwargs) 
except Exception : 
            _LOG.exception ('Error executing %s after %s expires.', func, timeout) 
if (timeout.remaining is not None) : 
        thread = threading.Thread (target = Target) 
        thread.start () 

    
    

    Fix the buggy line: timeout = PolledTimeout.FromSeconds (timeout)
assistant
#Here is Python program to fix the buggy line: timeout = PolledTimeout.

timeout = PolledTimeout.FromSeconds (time_s)