human
Count of ungrouped characters after dividing a string into K groups of distinct characters | Python3 code to implement the above approach.
Create array where index represents alphabets.
Fill count of every alphabet to corresponding array index.
Count for every element how much is exceeding from no . of groups then sum them.
Print answer.
Driver code"
How can the above be solved in Python?
 ... Give me a code to count of ungrouped characters after dividing a string into K groups of distinct characters and the other steps required?
assistant
#Here is code to count of ungrouped characters after dividing a string into K groups of distinct characters and the other steps required.
 def findUngroupedElement ( s , k ) :
	n = len ( s ) ;
	b = [ 0 ] * 26
	for i in range ( n ) :
		p = s [ i ]
		b [ ord ( p ) - ord ( ' a ' ) ] += 1
	sum = 0 ;
	for i in range ( 26 ) :
		if ( b [ i ] > k ) :
			sum += b [ i ] - k
	print ( sum )
s = " stayinghomesaveslife "
k = 1
findUngroupedElement ( s , k )