human
Can you provide a code to count of ways to select K consecutive empty cells from a given Matrix and the other steps required given the following:
Count of ways to select K consecutive empty cells from a given Matrix | Function to Traverse the matrix row wise.
Initialize ans.
Traverse row wise.
Initialize no of consecutive empty cells.
Check if blocked cell is encountered then reset countcons to 0.
Check if empty cell is encountered , then increment countcons.
Check if number of empty consecutive cells is greater or equal to K , increment the ans.
Return the count.
Function to Traverse the matrix column wise.
Initialize ans.
Traverse column wise.
Initialize no of consecutive empty cells.
Check if blocked cell is encountered then reset countcons to 0.
Check if empty cell is encountered , increment countcons.
Check if number of empty consecutive cells is greater than or equal to K , increment the ans.
Return the count.
Driver Code.
If k = 1 only traverse row wise.
Traverse both row and column wise"
How can the above be solved in Python?
assistant
#Here is code to count of ways to select K consecutive empty cells from a given Matrix and the other steps required.
 def rowWise ( v , n , m , k ) :
	ans = 0
	for i in range ( n ) :
		countcons = 0
		for j in range ( m ) :
			if ( v [ i ] [ j ] == '1' ) :
				countcons = 0
			else :
				countcons += 1
			if ( countcons >= k ) :
				ans += 1
	return ans
def colWise ( v , n , m , k ) :
	ans = 0
	for i in range ( m ) :
		countcons = 0
		for j in range ( n ) :
			if ( v [ j ] [ i ] == '1' ) :
				countcons = 0
			else :
				countcons += 1
			if ( countcons >= k ) :
				ans += 1
	return ans
if __name__ == " _ _ main _ _ " :
	n = 3
	m = 3
	k = 1
	v = [ [ '0' , '0' , '0' ] , [ '0' , '0' , '0' ] , [ '0' , '0' , '0' ] ]
	if ( k == 1 ) :
		print ( rowWise ( v , n , m , k ) )
	else :
		print ( colWise ( v , n , m , k ) + rowWise ( v , n , m , k ) )