human
Lead a life problem | Function that calculates the profit with the earning and cost of expenses.
To store the total Profit.
Loop for n number of days.
If last day , no need to buy food.
Else buy food to gain energy for next day.
Update earning per day.
Update profit with daily spent.
Print the profit.
Driver Code.
Given days.
Given earnings.
Given cost.
Given energy e.
Function call"
Solution in Python:

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Give me a code to lead a life problem and the other steps required?
assistant
#Here is code to lead a life problem and the other steps required.
 def calculateProfit ( n , earnings , cost , e ) :
	profit = 0 ;
	for i in range ( n ) :
		earning_per_day = 0 ;
		daily_spent_food = 0 ;
		if ( i == ( n - 1 ) ) :
			earning_per_day = earnings [ i ] * e ;
			profit = profit + earning_per_day ;
			break ;
		if ( cost [ i ] < earnings [ i ] ) :
			earning_per_day = earnings [ i ] * e ;
			daily_spent_food = cost [ i ] * e ;
			profit = ( profit + earning_per_day - daily_spent_food ) ;
	print ( profit ) ;
if __name__ == ' _ _ main _ _ ' :
	n = 4 ;
	earnings = [ 1 , 8 , 6 , 7 ] ;
	cost = [ 1 , 3 , 4 , 1 ] ;
	e = 5 ;
	calculateProfit ( n , earnings , cost , e ) ;