human
I found an interesting problem on https://leetcode.com/problems/monotone-increasing-digits/:
Given a non-negative integer N, find the largest number that is less than or equal to N with monotone increasing digits.

(Recall that an integer has monotone increasing digits if and only if each pair of adjacent digits x and y satisfy x .)

Example 1:

Input: N = 10
Output: 9


Example 2:

Input: N = 1234
Output: 1234


Example 3:

Input: N = 332
Output: 299


Note:
N is an integer in the range [0, 10^9].

I tried it in Python, but could not do it. Can you solve it?

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Can you provide a Python program to find the largest number that is less than or equal to N with monotone increasing digits?
assistant
#Here is Python program to find the largest number that is less than or equal to N with monotone increasing digits.

class Solution:
     def monotoneIncreasingDigits(self, N):
         N = str(N)
         L = len(N)
         for i in range(L - 1):
             if N[i] > N[i + 1]:
                 return self.monotoneIncreasingDigits(int(N[:i] + str(int(N[i]) - 1) + '9' * (L - i - 1)))
         return int(N)