human
Can you provide a code to minimize replacements to make every element in an array exceed every element in another given array and the other steps required given the following:
Minimize replacements to make every element in an array exceed every element in another given array | Function to find the minimize replacements to make every element in the array A [ ] strictly greater than every element in B [ ] or vice - versa.
Store the final result.
Create two arrays and initialize with 0 s.
Traverse the array a [ ].
Increment prefix_a [ a [ i ] ] by 1.
Traverse the array b [ ].
Increment prefix_b [ b [ i ] ] by 1.
Calculate prefix sum of the array a [ ].
Calculate prefix sum of the array b [ ].
Iterate over the range [ 0 , 9 ].
Make every element in array a [ ] strictly greater than digit i and make every element in the array b [ ] less than digit i.
Make every element in array b [ ] strictly greater than digit i and make every element in array a [ ] less than digit i.
Print the answer.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to minimize replacements to make every element in an array exceed every element in another given array and the other steps required.
 def MinTime ( a , b , n , m ) :
	ans = float ( ' inf ' )
	prefix_a = [ 0 ] * 10
	prefix_b = [ 0 ] * 10
	for i in range ( n ) :
		prefix_a [ a [ i ] ] += 1
	for i in range ( m ) :
		prefix_b [ b [ i ] ] += 1
	for i in range ( 1 , 10 ) :
		prefix_a [ i ] += prefix_a [ i - 1 ]
	for i in range ( 1 , 10 ) :
		prefix_b [ i ] += prefix_b [ i - 1 ]
	for i in range ( 1 , 10 ) :
		ans = min ( ans , prefix_a [ i ] + m - prefix_b [ i ] )
		ans = min ( ans , n - prefix_a [ i ] + prefix_b [ i ] )
	print ( ans )
A = [ 0 , 0 , 1 , 3 , 3 ]
B = [ 2 , 0 , 3 ]
N = len ( A )
M = len ( B )
MinTime ( A , B , N , M )