human
Decode a string recursively encoded as count followed by substring | Returns decoded string for ' str '.
Traversing the string.
If number , convert it into number and push it into integerstack ..
If closing bracket ' ] ' , pop elemment until ' [ ' opening bracket is not found in the character stack ..
Repeating the popped string ' temo ' count number of times ..
Push it in the character stack ..
If ' [ ' opening bracket , push it into character stack ..
Pop all the elmenet , make a string and return ..
Driven code"
Solution in Python:

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Write me a code to decode a string recursively encoded as count followed by substring and the other steps required?
assistant
#Here is code to decode a string recursively encoded as count followed by substring and the other steps required.
 def decode ( Str ) :
	integerstack = [ ]
	stringstack = [ ]
	temp = " "
	result = " "
	i = 0
	while i < len ( Str ) :
		count = 0
		if ( Str [ i ] >= '0' and Str [ i ] <= '9' ) :
			while ( Str [ i ] >= '0' and Str [ i ] <= '9' ) :
				count = count * 10 + ord ( Str [ i ] ) - ord ( '0' )
				i += 1
			i -= 1
			integerstack . append ( count )
		elif ( Str [ i ] == ' ] ' ) :
			temp = " "
			count = 0
			if ( len ( integerstack ) != 0 ) :
				count = integerstack [ - 1 ]
				integerstack . pop ( )
			while ( len ( stringstack ) != 0 and stringstack [ - 1 ] != ' [ ' ) :
				temp = stringstack [ - 1 ] + temp
				stringstack . pop ( )
			if ( len ( stringstack ) != 0 and stringstack [ - 1 ] == ' [ ' ) :
				stringstack . pop ( )
			for j in range ( count ) :
				result = result + temp
			for j in range ( len ( result ) ) :
				stringstack . append ( result [ j ] )
			result = " "
		elif ( Str [ i ] == ' [ ' ) :
			if ( Str [ i - 1 ] >= '0' and Str [ i - 1 ] <= '9' ) :
				stringstack . append ( Str [ i ] )
			else :
				stringstack . append ( Str [ i ] )
				integerstack . append ( 1 )
		else :
			stringstack . append ( Str [ i ] )
		i += 1
	while len ( stringstack ) != 0 :
		result = stringstack [ - 1 ] + result
		stringstack . pop ( )
	return result
if __name__ == ' _ _ main _ _ ' :
	Str = "3 [ b2 [ ca ] ] "
	print ( decode ( Str ) )