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Check if a Binary String can be converted to another by reversing substrings consisting of even number of 1 s | Function to check if string A can be transformed to string B by reversing substrings of A having even number of 1 s.
Store the size of string A.
Store the size of string B.
Store the count of 1 s in A and B.
Stores cntA for string A and cntB for string B.
Traverse the string A.
If current character is 1.
Increment 1 s count.
Otherwise , update odd1A or even1A depending whether count1A is odd or even.
Traverse the string B.
If current character is 1.
Increment 1 s count.
Otherwise , update odd1B or even1B depending whether count1B is odd or even.
If the condition is satisfied.
If True , prYes.
Otherwise , prNo.
Driver Code.
Function Call"
Solution in Python:
 Can you provide a code to check if a Binary String can be converted to another by reversing substrings consisting of even number of 1 s and the other steps required?
assistant
#Here is code to check if a Binary String can be converted to another by reversing substrings consisting of even number of 1 s and the other steps required.
 def canTransformStrings ( A , B ) :
	n1 = len ( A ) ;
	n2 = len ( B ) ;
	count1A = 0 ;
	count1B = 0 ;
	odd1A = 0 ; odd1B = 0 ;
	even1A = 0 ; even1B = 0 ;
	for i in range ( n1 ) :
		if ( A [ i ] == '1' ) :
			count1A += 1 ;
		else :
			if ( ( count1A & 1 ) == 1 ) :
				odd1A += 1 ;
			else :
				even1A += 1 ;
	for i in range ( n2 ) :
		if ( B [ i ] == '1' ) :
			count1B += 1 ;
		else :
			if ( ( count1B & 1 ) == 1 ) :
				odd1B += 1 ;
			else :
				even1B += 1 ;
	if ( count1A == count1B and odd1A == odd1B and even1A == even1B ) :
		print ( " Yes " ) ;
	else :
		print ( " No " ) ;
if __name__ == ' _ _ main _ _ ' :
	A = "10011" ;
	B = "11100" ;
	canTransformStrings ( A , B ) ;