human
Minimal operations to make a number magical | function to calculate the minimal changes.
maximum digits that can be changed.
nested loops to generate all 6 digit numbers.
counter to count the number of change required.
if first digit is equal.
if 2 nd digit is equal.
if 3 rd digit is equal.
if 4 th digit is equal.
if 5 th digit is equal.
if 6 th digit is equal.
checks if less then the previous calculate changes.
returns the answer.
driver program to test the above function.
number stored in string.
prints the minimum operations"
Solution in Python:
assistant
#Here is code to minimal operations to make a number magical and the other steps required.
 def calculate ( s ) :
	ans = 6
	for i in range ( 10 ) :
		for j in range ( 10 ) :
			for k in range ( 10 ) :
				for l in range ( 10 ) :
					for m in range ( 10 ) :
						for n in range ( 10 ) :
							if ( i + j + k == l + m + n ) :
								c = 0
								if ( i != ord ( s [ 0 ] ) - ord ( '0' ) ) :
									c += 1
								if ( j != ord ( s [ 1 ] ) - ord ( '0' ) ) :
									c += 1
								if ( k != ord ( s [ 2 ] ) - ord ( '0' ) ) :
									c += 1
								if ( l != ord ( s [ 3 ] ) - ord ( '0' ) ) :
									c += 1
								if ( m != ord ( s [ 4 ] ) - ord ( '0' ) ) :
									c += 1
								if ( n != ord ( s [ 5 ] ) - ord ( '0' ) ) :
									c += 1
								if ( c < ans ) :
									ans = c
	return ans
if __name__ == " _ _ main _ _ " :
	s = "123456"
	print ( calculate ( s ) )