human
Solve the following python programming problem given the following code:
def paginate(items, page = 0, max_per_page = 10) : 
    'Simple generic pagination.

    Given an iterable, this function returns:
     * the slice of objects on the requested page,
     * the total number of items, and
     * the total number of pages.

    The `items` parameter can be a list, tuple, or iterator:

    >>> items = range(12)
    >>> items
    [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
    >>> paginate(items)
    ([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 12, 2)
    >>> paginate(items, page=1)
    ([10, 11], 12, 2)
    >>> paginate(iter(items))
    ([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 12, 2)
    >>> paginate(iter(items), page=1)
    ([10, 11], 12, 2)

    This function also works with generators:

    >>> def generate():
    ...     for idx in range(12):
    ...         yield idx
    >>> paginate(generate())
    ([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], 12, 2)
    >>> paginate(generate(), page=1)
    ([10, 11], 12, 2)

    The `max_per_page` parameter can be used to set the number of items that
    should be displayed per page:

    >>> items = range(12)
    >>> paginate(items, page=0, max_per_page=6)
    ([0, 1, 2, 3, 4, 5], 12, 2)
    >>> paginate(items, page=1, max_per_page=6)
    ([6, 7, 8, 9, 10, 11], 12, 2)

    :raises TracError: if `page` is out of the range of the paginated
                       results.
    ' 
    if (not page) : 
        page = 0 
start = (page * max_per_page) 
    stop = (start + max_per_page) 
    count = None 
    if hasattr (items, '__len__') : 
        count = len (items) 
        if (count and (start >= count)) : 
            from trac.util.translation import _ 
            raise TracError (_ ('Page %(page)s is out of range.', page = page)) 
try : 
        retval = items [start : stop] 
except TypeError : 
        retval = [] 
        idx = (- 1) 
        for (idx, item) in enumerate (items) : 
            if (start <= idx < stop) : 
                retval.append (item) 
if ((count is not None) and (count >= stop)) : 
                break 
if (count is None) : 
            count =...

    
    

    Fix the buggy line: if ((count is not None) and (count >= stop)) :
assistant
#Here is Python program to fix the buggy line: if ((count is not None) and (count >= stop)) :
.

if ((count is not None) and (idx >= stop)) :