human
I found an interesting problem on https://leetcode.com/problems/simplify-path/:
Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

Corner Cases:

       Did you consider the case where path = "/../"?
       In this case, you should return "/".
       Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
       In this case, you should ignore redundant slashes and return "/home/foo".

I tried it in Python, but could not do it. Can you solve it?
assistant
#Here is the Python program you requested.

class Solution:
     def simplifyPath(self, path):
         """
         :type path: str
         :rtype: str
         """
     
         
         places = [tmp for tmp in path.split("/") if tmp!="." and tmp!=""]
         stack = []
         for name in places:
             
             if name == "." or name == "":
                 continue
             elif name == "..":
                 if len(stack) > 0:
                     stack.pop()
             else:
                 stack.append(name)
                     
         return "/" + "/".join(stack)