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What is a code to arrange N elements in circular fashion such that all elements are strictly less than sum of adjacent elements and the other steps required given the following:
Arrange N elements in circular fashion such that all elements are strictly less than sum of adjacent elements | Function to print the arrangement that satisifes the given condition.
Sort the array initially.
Array that stores the arrangement.
Once the array is sorted Re - fill the array again in the mentioned way in the approach.
Iterate in the array and check if the arrangement made satisfies the given condition or not.
For the first element the adjacents will be a [ 1 ] and a [ n - 1 ].
For the last element the adjacents will be a [ 0 ] and a [ n - 2 ].
If we reach this position then the arrangement is possible.
Driver code"
Solution in Python:
assistant
#Here is code to arrange N elements in circular fashion such that all elements are strictly less than sum of adjacent elements and the other steps required.
 def printArrangement ( a , n ) :
	a = sorted ( a )
	b = [ 0 for i in range ( n ) ]
	low = 0
	high = n - 1
	for i in range ( n ) :
		if ( i % 2 == 0 ) :
			b [ low ] = a [ i ]
			low += 1
		else :
			b [ high ] = a [ i ]
			high -= 1
	for i in range ( n ) :
		if ( i == 0 ) :
			if ( b [ n - 1 ] + b [ 1 ] <= b [ i ] ) :
				print ( " - 1" )
				return
		elif ( i == ( n - 1 ) ) :
			if ( b [ n - 2 ] + b [ 0 ] <= b [ i ] ) :
				print ( " - 1" )
				return
		else :
			if ( b [ i - 1 ] + b [ i + 1 ] <= b [ i ] ) :
				print ( " - 1" )
				return
	for i in range ( n ) :
		print ( b [ i ] , end = " ▁ " )
a = [ 1 , 4 , 4 , 3 , 2 ]
n = len ( a )
printArrangement ( a , n )