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Count distinct elements from a range of a sorted sequence from a given frequency array | Function to find the first index with value is at least element.
Update the value of left.
Binary search for the element.
Find the middle element.
Check if the value lies between the elements at index mid - 1 and mid.
Check in the right subarray.
Update the value of left.
Check in left subarray.
Update the value of right.
Function to count the number of distinct elements over the range [ L , R ] in the sorted sequence.
Stores the count of distinct elements.
Create the prefix sum array.
Update the value of count.
Update the value of pref [ i ].
Calculating the first index of L and R using binary search.
Print the resultant count.
Driver Code"
Solution in Python:

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Can you provide a code to count distinct elements from a range of a sorted sequence from a given frequency array and the other steps required?
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#Here is code to count distinct elements from a range of a sorted sequence from a given frequency array and the other steps required.
 def binarysearch ( array , right , element ) :
	left = 1
	while ( left <= right ) :
		mid = ( left + right // 2 )
		if ( array [ mid ] == element ) :
			return mid
		if ( mid - 1 > 0 and array [ mid ] > element and array [ mid - 1 ] < element ) :
			return mid
		elif ( array [ mid ] < element ) :
			left = mid + 1
		else :
			right = mid - 1
	return 1
def countDistinct ( arr , L , R ) :
	count = 0
	pref = [ 0 ] * ( len ( arr ) + 1 )
	for i in range ( 1 , len ( arr ) + 1 ) :
		count += arr [ i - 1 ]
		pref [ i ] = count
	left = binarysearch ( pref , len ( arr ) + 1 , L )
	right = binarysearch ( pref , len ( arr ) + 1 , R )
	print ( right - left + 1 )
if __name__ == " _ _ main _ _ " :
	arr = [ 3 , 6 , 7 , 1 , 8 ]
	L = 3
	R = 7
	countDistinct ( arr , L , R )