human
Check if K distinct array elements form an odd sum | Function to return if odd sum is possible or not.
Stores distinct odd elements.
Stores distinct even elements.
Iterating through given array.
If element is even.
If element is odd.
If atleast K elements in the array are odd.
Check for all odd frequencies of odd elements whether sufficient even numbers are present or not.
Count of even numbers required.
If required even numbers are present in the array.
Driver Program"
How can the above be solved in Python?
assistant
#Here is code to check if K distinct array elements form an odd sum and the other steps required.
 def oddSum ( A , N , K ) :
	Odd = set ( [ ] )
	Even = set ( [ ] )
	for i in range ( N ) :
		if ( A [ i ] % 2 == 0 ) :
			Even . add ( A [ i ] )
		else :
			Odd . add ( A [ i ] )
	if ( len ( Odd ) >= K ) :
		return True
	flag = False
	for i in range ( 1 , K , 2 ) :
		needed = K - i
		if ( needed <= len ( Even ) ) :
			return True
	return flag
if __name__ == " _ _ main _ _ " :
	K = 5
	A = [ 12 , 1 , 7 , 7 , 26 , 18 ]
	N = 3
	if ( oddSum ( A , N , K ) ) :
		print ( " YES " )
	else :
		print ( " NO " )