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Minimum toggles to partition a binary array so that it has first 0 s then 1 s | Function to calculate minimum toggling required by using Dynamic programming.
Fill entries in zero [ ] such that zero [ i ] stores count of zeroes to the left of i ( exl.
If zero found update zero [ ] array.
Finding the minimum toggle required from every index ( 0 to n - 1 ).
Driver Program"
Solution in Python:

Give me a code to minimum toggles to partition a binary array so that it has first 0 s then 1 s and the other steps required?
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#Here is code to minimum toggles to partition a binary array so that it has first 0 s then 1 s and the other steps required.
 def minToggle ( arr , n ) :
	zero = [ 0 for i in range ( n + 1 + 1 ) ]
	zero [ 0 ] = 0
	for i in range ( 1 , n + 1 ) :
		if ( arr [ i - 1 ] == 0 ) :
			zero [ i ] = zero [ i - 1 ] + 1
		else :
			zero [ i ] = zero [ i - 1 ]
	ans = n
	for i in range ( 1 , n + 1 ) :
		ans = min ( ans , i - zero [ i ] + zero [ n ] - zero [ i ] )
	return ans
arr = [ 1 , 0 , 1 , 1 , 0 ]
n = len ( arr )
print ( minToggle ( arr , n ) )