human
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.

She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:

If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then

  * if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie. 
  * if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie. 


After that:

  * If there is at least one cookie of the selected type, the guest eats one. 
  * Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home. 


Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.

For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).

Output

For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".

You can print each letter in any case (upper or lower).

Example

Input

6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000

Output

Yes
No
No
Yes
No
Yes

Note

In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:

  * The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1...
"""
 ... Can you provide a Python program to print the answer in one line?
assistant
#Here is Python program to print the answer in one line.
   Satwik_Tiwari ;) .
    28 june , 2020  - Sunday
"""

#===============================================================================================
#importing some useful libraries.
from __future__ import division, print_function

from fractions import Fraction
import sys
import os
from io import BytesIO, IOBase

import bisect
from heapq import *
from math import *
from collections import deque
from collections import Counter as counter  # Counter(list)  return a dict with {key: count}
from itertools import combinations as comb # if a = [1,2,3] then print(list(comb(a,2))) -----> [(1, 2), (1, 3), (2, 3)]
from itertools import permutations as permutate
from bisect import bisect_left as bl
#If the element is already present in the list,
# the left most position where element has to be inserted is returned.
from bisect import bisect_right as br
from bisect import bisect
#If the element is already present in the list,
# the right most position where element has to be inserted is returned

#==============================================================================================

BUFSIZE = 8192

class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
       ...