human
Can you provide a the Python program you requested given the following:
I am working on the file "01-IPythonHintsAndTips.ipynb".
The first task is:
Class Descriptors
https://twitter.com/jakevdp/status/1121873857973870592/photo/1  

The instance method (aka plain function) remains unbound when retrieved from the class so C.method.__get__ just returns itself. By contrast, the class method gets bound to the class in that case, so it returns a new bound method object.  In the first case both calls point to the same thing. In the second case since it is a classmethod, every call call creates a new instance of the method. I think this kind of explains the whole idea behind classmethods.

In the first cell, C.method evaluates to C.__dict__["method"].
in second cell it evaluates to C.__dict__["method"].__get__(C, None) which turns new objects each time

In the first case, C.method points to the method() function.
In the second case, because the method() function is decorated with a @classmethod decorator, C.method returns an instance of bound method object.  Every time you write C.method a new object is created.

To add to your confusion, id(Example.clsmethod) == id(Example.clsmethod), because method objects use a free list. After the first id() call, the object gets deallocated and the second call can reuse the same object.
Can you write Python program for it?
assistant
#Here is the Python program you requested.

class C:
    def method(self):
        pass
    
C.method is C.method

class C:
    @classmethod
    def method(cls):
        pass
    
print(C.method is C.method)

print(id(C.method)==id(C.method))

a = C.method
b = C.method
print(id(a)==id(b))

C.__dict__

print(type(C.method))
print(type(C.__dict__['method']))