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Find all rectangles filled with 0 | Python program to find all rectangles filled with 0.
flag to check column edge case , initializing with 0.
flag to check row edge case , initializing with 0.
loop breaks where first 1 encounters.
set the flag.
pass because already processed.
loop breaks where first 1 encounters.
set the flag.
fill rectangle elements with any number so that we can exclude next time.
when end point touch the boundary.
when end point touch the boundary.
retrieving the column size of array.
output array where we are going to store our output.
It will be used for storing start and end location in the same index.
storing initial position of rectangle.
will be used for the last position.
driver code"
Solution in Python:

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What is a code to find all rectangles filled with 0 and the other steps required?
assistant
#Here is code to find all rectangles filled with 0 and the other steps required.
 def findend ( i , j , a , output , index ) :
	x = len ( a )
	y = len ( a [ 0 ] )
	flagc = 0
	flagr = 0
	for m in range ( i , x ) :
		if a [ m ] [ j ] == 1 :
			flagr = 1
			break
		if a [ m ] [ j ] == 5 :
			pass
		for n in range ( j , y ) :
			if a [ m ] [ n ] == 1 :
				flagc = 1
				break
			a [ m ] [ n ] = 5
	if flagr == 1 :
		output [ index ] . append ( m - 1 )
	else :
		output [ index ] . append ( m )
	if flagc == 1 :
		output [ index ] . append ( n - 1 )
	else :
		output [ index ] . append ( n )
def get_rectangle_coordinates ( a ) :
	size_of_array = len ( a )
	output = [ ]
	index = - 1
	for i in range ( 0 , size_of_array ) :
		for j in range ( 0 , len ( a [ 0 ] ) ) :
			if a [ i ] [ j ] == 0 :
				output . append ( [ i , j ] )
				index = index + 1
				findend ( i , j , a , output , index )
	print ( output )
tests = [ [ 1 , 1 , 1 , 1 , 1 , 1 , 1 ] , [ 1 , 1 , 1 , 1 , 1 , 1 , 1 ] , [ 1 , 1 , 1 , 0 , 0 , 0 , 1 ] , [ 1 , 0 , 1 , 0 , 0 , 0 , 1 ] , [ 1 , 0 , 1 , 1 , 1 , 1 , 1 ] , [ 1 , 0 , 1 , 0 , 0 , 0 , 0 ] , [ 1 , 1 , 1 , 0 , 0 , 0 , 1 ] , [ 1 , 1 , 1 , 1 , 1 , 1 , 1 ] ]
get_rectangle_coordinates ( tests )