human
Solve the following python programming problem given the following code:
def insertRelationshipSets(self) : 
    self.showStatus ('insert relationship sets') 
    aspectQnamesUsed = set () 
    for (i, relationshipSetKey) in enumerate (self.relationshipSets) : 
        (arcrole, linkrole, linkqname, arcqname) = relationshipSetKey 
        if linkqname : 
            aspectQnamesUsed.add (linkqname) 
if arcqname : 
            aspectQnamesUsed.add (arcqname) 
self.insertAspectProxies (aspectQnamesUsed) 
    relationshipSets = self.report ['relationshipSets'] 
    relSetIds = { 
        
} 
    for (i, relationshipSetKey) in enumerate (self.relationshipSets) : 
        (arcrole, linkrole, linkqname, arcqname) = relationshipSetKey 
        if ((arcrole not in ('XBRL-formulae', 'Table-rendering', 'XBRL-footnotes')) and linkrole and linkqname and arcqname) : 
            relSetId = '{}/{}'.format (os.path.basename (arcrole), os.path.basename (linkrole)) 
            relSetIds [relationshipSetKey] = relSetId 
            relationshipSets [relSetId] = relationshipSet = { 
                'arcrole' : arcrole, 
                'linkrole' : linkrole, 
                'arcname' : self.aspectQnameProxyId (arcqname), 
                'linkname' : self.aspectQnameProxyId (linkqname), 
                'report' : self.reportURI, 
                'roots' : [], 
                'relationships' : [], 
} 
relE = [] 
    resources = set () 
    aspectQnamesUsed = set () 
    resourceIDs = { 
        
} 
    def walkTree(rels, parentRelId, seq, depth, relationshipSetKey, relationshipSet, visited, relSetId, doVertices) : 
        for rel in rels : 
            if (rel not in visited) : 
                visited.add (rel) 
                if (not doVertices) : 
                    _relProp = { 
                        'seq' : seq, 
                        'depth' : depth, 
                        'order' : rel.orderDecimal, 
                        'priority' : rel.priority, 
                        'relSetId' : relSetId, 
} 
if isinstance (rel.fromModelObject, ModelConcept) : 
                    if...

    
    

    Fix the buggy line: for (j, rel) in enumerate (k) :
assistant
#Here is Python code to fix the buggy line: for (j, rel) in enumerate (k) :
.

for (j, rel) in enumerate (relE) :