human
I found an interesting problem on https://leetcode.com/problems/count-and-say/:
The count-and-say sequence is the sequence of integers with the first five terms as following:

1.     1
2.     11
3.     21
4.     1211
5.     111221


1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.


Given an integer n, generate the nth term of the count-and-say sequence.


Note: Each term of the sequence of integers will be represented as a string.

Example 1:

Input: 1
Output: "1"


Example 2:

Input: 4
Output: "1211"

I tried it in Python, but could not do it. Can you solve it?

=====
What is a the Python program you requested?
assistant
#Here is the Python program you requested.

class Solution:
     def countAndSay(self, n):
         """
         :type n: int
         :rtype: str
         """
         L="1"
         if(n==1):
             return L
         while(n>1):
             M=""
             i=0
             while(i<len(L)):
                 k=1
                 x=L[i];
                 while(i<len(L)-1 and L[i+1]==x):
                     i=i+1
                     k=k+1
                 M=M+str(k)+x
                 i=i+1
             n=n-1
             L=M
         return L