human
Count quadruples from four sorted arrays whose sum is equal to a given value x | count pairs from the two sorted array whose sum is equal to the given ' value '.
traverse ' arr1 [ ] ' from left to right traverse ' arr2 [ ] ' from right to left.
if the ' sum ' is equal to ' value ' , then increment ' l ' , decrement ' r ' and increment ' count '.
if the ' sum ' is greater than ' value ' , then decrement r.
else increment l.
required count of pairs print ( count ).
function to count all quadruples from four sorted arrays whose sum is equal to a given value x.
generate all pairs from arr1 [ ] and arr2 [ ].
calculate the sum of elements in the pair so generated.
count pairs in the 3 rd and 4 th array having value ' x - p _ sum ' and then accumulate it to ' count '.
required count of quadruples.
four sorted arrays each of size ' n '"
How can the above be solved in Python?
 ... Can you provide a code to count quadruples from four sorted arrays whose sum is equal to a given value x and the other steps required?
assistant
#Here is code to count quadruples from four sorted arrays whose sum is equal to a given value x and the other steps required.
 def countPairs ( arr1 , arr2 , n , value ) :
	count = 0
	l = 0
	r = n - 1
	while ( l < n and r >= 0 ) :
		sum = arr1 [ l ] + arr2 [ r ]
		if ( sum == value ) :
			l += 1
			r -= 1
			count += 1
		elif ( sum > value ) :
			r -= 1
		else :
			l += 1
	return count
def countQuadruples ( arr1 , arr2 , arr3 , arr4 , n , x ) :
	count = 0
	for i in range ( 0 , n ) :
		for j in range ( 0 , n ) :
			p_sum = arr1 [ i ] + arr2 [ j ]
			count += int ( countPairs ( arr3 , arr4 , n , x - p_sum ) )
	return count
arr1 = [ 1 , 4 , 5 , 6 ]
arr2 = [ 2 , 3 , 7 , 8 ]
arr3 = [ 1 , 4 , 6 , 10 ]
arr4 = [ 2 , 4 , 7 , 8 ]
n = len ( arr1 )
x = 30
print ( " Count ▁ = ▁ " , countQuadruples ( arr1 , arr2 , arr3 , arr4 , n , x ) )