human
What is a code to channel Assignment Problem and the other steps required given the following:
Channel Assignment Problem | A Depth First Search based recursive function that returns true if a matching for vertex u is possible.
Try every receiver one by one.
If sender u has packets to send to receiver v and receiver v is not already mapped to any other sender just check if the number of packets is greater than '0' because only one packet can be sent in a time frame anyways.
Mark v as visited.
If receiver ' v ' is not assigned to any sender OR previously assigned sender for receiver v ( which is matchR [ v ] ) has an alternate receiver available . Since v is marked as visited in the above line , matchR [ v ] in the following recursive call will not get receiver ' v ' again.
Returns maximum number of packets that can be sent parallely in 1 time slot from sender to receiver.
Initially all receivers are not mapped to any senders.
Count of receivers assigned to senders.
Mark all receivers as not seen for next sender.
Find if the sender ' u ' can be assigned to the receiver.
Driver Code"
How can the above be solved in Python?
assistant
#Here is code to channel Assignment Problem and the other steps required.
 def bpm ( table , u , seen , matchR ) :
	global M , N
	for v in range ( N ) :
		if ( table [ u ] [ v ] > 0 and not seen [ v ] ) :
			seen [ v ] = True
			if ( matchR [ v ] < 0 or bpm ( table , matchR [ v ] , seen , matchR ) ) :
				matchR [ v ] = u
				return True
	return False
def maxBPM ( table ) :
	global M , N
	matchR = [ - 1 ] * N
	result = 0
	for u in range ( M ) :
		seen = [ 0 ] * N
		if ( bpm ( table , u , seen , matchR ) ) :
			result += 1
	print ( " The ▁ number ▁ of ▁ maximum ▁ packets ▁ sent " , " in ▁ the ▁ time ▁ slot ▁ is " , result )
	for x in range ( N ) :
		if ( matchR [ x ] + 1 != 0 ) :
			print ( " T " , matchR [ x ] + 1 , " - > ▁ R " , x + 1 )
	return result
M = 3
N = 4
table = [ [ 0 , 2 , 0 ] , [ 3 , 0 , 1 ] , [ 2 , 4 , 0 ] ]
max_flow = maxBPM ( table )