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Maximize array sum by X increments when each element is divided by 10 | Python3 program for the above problem.
Initialize variables.
Add the current contribution of the element to the answer.
If the value is already maximum then we can 't  change it.
Moves required to move to the next multiple of 10.
No of times we can add 10 to this value so that its value does not exceed 1000..
Sort the array.
Adding the values to increase the numbers to the next multiple of 10.
If the total moves are less than X then increase the answer.
If the moves exceed X then we cannot increase numbers.
If there still remain some moves.
Remaining moves.
Add minimim of increments and remaining / 10 to the answer.
Output the final answer.
Driver Code"
How can the above be solved in Python?

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What is a code to maximize array sum by X increments when each element is divided by 10 and the other steps required?
assistant
#Here is code to maximize array sum by X increments when each element is divided by 10 and the other steps required.
 def maximizeval10 ( a , n , k ) :
	increments = 0
	ans = 0
	v = [ ]
	for i in range ( n ) :
		ans += ( a [ i ] // 10 )
		if ( a [ i ] == 1000 ) :
			continue
		else :
			v . append ( 10 - a [ i ] % 10 )
			increments += ( 100 - ( ( a [ i ] ) // 10 ) - 1 ) ;
	v . sort ( )
	sum = 0
	for i in range ( len ( v ) ) :
		sum += v [ i ]
		if ( sum <= k ) :
			ans += 1
		else :
			break
	if ( sum < k ) :
		remaining = k - sum
		ans += min ( increments , remaining // 10 )
	print ( ans )
if __name__ == " _ _ main _ _ " :
	N = 4
	X = 6
	A = [ 4 , 8 , 8 , 8 ]
	maximizeval10 ( A , N , X )