human
What is a code to count of triplets in an Array with odd sum and the other steps required given the following:
Count of triplets in an Array with odd sum | Function to count the number of unordered triplets such that their sum is an odd integer.
Count the number of odd and even integers in the array.
Number of ways to create triplets using one odd and two even integers.
Number of ways to create triplets using three odd integers.
Return answer.
Driver Code.
Function Call.
Print Answer"
Solution in Python:
assistant
#Here is code to count of triplets in an Array with odd sum and the other steps required.
 def countTriplets ( arr , n ) :
	odd = 0
	even = 0
	for i in range ( n ) :
		if ( arr [ i ] & 1 ) :
			odd += 1
		else :
			even += 1
	c1 = odd * ( even * ( even - 1 ) ) // 2
	c2 = ( odd * ( odd - 1 ) * ( odd - 2 ) ) // 6
	return c1 + c2
arr = [ 4 , 5 , 6 , 4 , 5 , 10 , 1 , 7 ]
n = len ( arr )
ans = countTriplets ( arr , n )
print ( ans )