human
Maximum number of 0 s that can be flipped such that Array has no adjacent 1 s | Maximum number of 0 s that can be replaced by 1.
Check for three consecutive 0 s.
Flip the bit.
Increase the count.
Driver code"
Solution in Python:
 ... Give me a code to maximum number of 0 s that can be flipped such that Array has no adjacent 1 s and the other steps required?
assistant
#Here is code to maximum number of 0 s that can be flipped such that Array has no adjacent 1 s and the other steps required.
 def canReplace ( arr , n ) :
	i = 0
	count = 0
	while ( i < n ) :
		if ( arr [ i ] == 0 and ( i == 0 or arr [ i - 1 ] == 0 ) and ( i == n - 1 or arr [ i + 1 ] == 0 ) ) :
			arr [ i ] = 1
			count += 1
		i += 1
	return count
if __name__ == ' _ _ main _ _ ' :
	arr = [ 1 , 0 , 0 , 0 , 1 ]
	print ( canReplace ( arr , 5 ) )