human
What is a code to perfect Cube factors of a Number and the other steps required given the following:
Perfect Cube factors of a Number | Function that returns the count of factors that are perfect cube.
To store the count of number of times a prime number divides N.
To store the count of factors that are perfect cube.
Count number of 2 's that divides N.
Calculate ans according to above formula.
Check for all possible numbers that can divide it.
Loop to check the number of times prime number i divides it.
Calculate ans according to above formula.
.
Given number.
Function call"
How can the above be solved in Python?
assistant
#Here is code to perfect Cube factors of a Number and the other steps required.
 def noofFactors ( N ) :
	if N == 1 :
		return 1
	count = 0
	ans = 1
	while ( N % 2 == 0 ) :
		count += 1
		N //= 2
	ans *= ( ( count // 3 ) + 1 )
	i = 3
	while ( ( i * i ) <= N ) :
		count = 0
		while ( N % i == 0 ) :
			count += 1
			N //= i
		ans *= ( ( count // 3 ) + 1 )
		i += 2
/ * Return final count * /
	return ans
N = 216
print ( noofFactors ( N ) )