human
Count the number of common divisors of the given strings | Function that returns true if sub - string s [ 0. . . k ] is repeated a number of times to generate String s.
Function to return the count of common divisors.
If the length of the sub - string divides length of both the strings.
If prefixes match in both the strings.
If both the strings can be generated.
Driver code"
How can the above be solved in Python?
assistant
#Here is code to count the number of common divisors of the given strings and the other steps required.
 def check ( s , k ) :
	for i in range ( 0 , len ( s ) ) :
		if ( s [ i ] != s [ i % k ] ) :
			return False
	return True
def countCommonDivisors ( a , b ) :
	ct = 0
	n = len ( a )
	m = len ( b )
	for i in range ( 1 , min ( n , m ) + 1 ) :
		if ( n % i == 0 and m % i == 0 ) :
			if ( a [ 0 : i ] == b [ 0 : i ] ) :
				if ( check ( a , i ) and check ( b , i ) ) :
					ct = ct + 1
	return ct
a = " xaxa "
b = " xaxaxaxa "
print ( countCommonDivisors ( a , b ) )