human
Rearrange array to maximize count of triplets ( i , j , k ) such that arr [ i ] > arr [ j ] < arr [ k ] and i < j < k | Function to rearrange the array to maximize the count of triplets.
Sort the given array.
Stores the permutations of the given array.
Stores the index of the given array.
Place the first half of the given array.
Place the last half of the given array.
Stores the count of triplets.
Check the given conditions.
Driver Code"
Solution in Python:
 ... What is a code to rearrange array to maximize count of triplets ( i , j , k ) such that arr [ i ] > arr [ j ] < arr [ k ] and i < j < k and the other steps required?
assistant
#Here is code to rearrange array to maximize count of triplets ( i , j , k ) such that arr [ i ] > arr [ j ] < arr [ k ] and i < j < k and the other steps required.
 def ctTriplets ( arr , N ) :
	arr . sort ( )
	temp = [ 0 ] * N
	index = 0
	for i in range ( 1 , N , 2 ) :
		temp [ i ] = arr [ index ]
		index += 1
	for i in range ( 0 , N , 2 ) :
		temp [ i ] = arr [ index ]
		index += 1
	ct = 0
	for i in range ( N ) :
		if ( i > 0 and i + 1 < N ) :
			if ( temp [ i ] < temp [ i + 1 ] and temp [ i ] < temp [ i - 1 ] ) :
				ct += 1
	print ( " Count ▁ of ▁ triplets : " , ct )
	print ( " Array : " , end = " " )
	for i in range ( N ) :
		print ( temp [ i ] , end = " ▁ " )
arr = [ 1 , 2 , 3 , 4 , 5 , 6 ]
N = len ( arr )
ctTriplets ( arr , N )