human
Give me a code to queries to count array elements greater than or equal to a given number with updates and the other steps required given the following:
Queries to count array elements greater than or equal to a given number with updates | Function to build a segment tree.
Check for base case.
Find mid point.
Recursively build the segment tree.
Function for push down operation on the segment tree.
Function to update the segment tree.
Complete overlap.
Find mid.
Perform push down operation on segment tree.
Recursively update the segment tree.
Function to process the queryy.
Base case.
Find mid.
Perform push down operation on segment tree.
Recursively calculate the result of the queryy.
Return the result.
Function to count the numbers which are greater than the given queryy.
Sort the input array.
Create segment tree of size 4 * n vector < int > sum , add , ans.
Build the segment tree.
Iterate over the queries.
Store result in array.
Update the elements in the given range.
Print the result of queries.
Driver Code.
Function call"
How can the above be solved in Python?
assistant
#Here is code to queries to count array elements greater than or equal to a given number with updates and the other steps required.
 def build ( sum , a , l , r , rt ) :
	if ( l == r ) :
		sum [ rt ] = a [ l - 1 ]
		return
	m = ( l + r ) >> 1
	build ( sum , a , l , m , rt << 1 )
	build ( sum , a , m + 1 , r , rt << 1 1 )
def pushDown ( sum , add , rt , ln , rn ) :
	if ( add [ rt ] ) :
		add [ rt << 1 ] += add [ rt ]
		add [ rt << 1 1 ] += add [ rt ]
		sum [ rt << 1 ] += add [ rt ] * ln
		sum [ rt << 1 1 ] += add [ rt ] * rn
		add [ rt ] = 0
def update ( sum , add , L , R , C , l , r , rt ) :
	if ( L <= l and r <= R ) :
		sum [ rt ] += C * ( r - l + 1 )
		add [ rt ] += C
		return
	m = ( l + r ) >> 1
	pushDown ( sum , add , rt , m - l + 1 , r - m )
	if ( L <= m ) :
		update ( sum , add , L , R , C , l , m , rt << 1 )
	if ( R > m ) :
		update ( sum , add , L , R , C , m + 1 , r , rt << 1 1 )
def queryy ( sum , add , L , R , l , r , rt ) :
	if ( L <= l and r <= R ) :
		return sum [ rt ]
	m = ( l + r ) >> 1
	pushDown ( sum , add , rt , m - l + 1 , r - m )
	ans = 0
	if ( L <= m ) :
		ans += queryy ( sum , add , L , R , l , m , rt << 1 )
	if ( R > m ) :
		ans += queryy ( sum , add , L , R , m + 1 , r , ( rt << 1 1 ) )
	return ans
def sequenceMaintenance ( n , q , a , b , m ) :
	a = sorted ( a )
	sum = [ 0 ] * ( 4 * n )
	add = [ 0 ] * ( 4 * n )
	ans = [ ]
	build ( sum , a , 1 , n , 1 )
	for i in range ( q ) :
		l = 1
		r = n
		pos = - 1
		while ( l <= r ) :
			m = ( l + r ) >> 1
			if ( queryy ( sum , add , m , m , 1 , n , 1 ) >= b [ i ] ) :
				r = m - 1
				pos = m
			else :
				l = m + 1
		if ( pos == - 1 ) :
			ans . append ( 0 )
		else :
			ans . append ( n - pos + 1 )
			update ( sum , add , pos , n , - m , 1 , n , 1 )
	for i in ans :
		print ( i , end = " ▁ " )
if __name__ == ' _ _ main _ _ ' :
	N = 4
	Q = 3
	M = 1
	arr = [ 1 , 2 , 3 , 4 ]
	query = [ 4 , 3 , 1 ]
	sequenceMaintenance ( N , Q , arr , query , M )