human
Longest subarray with sum not divisible by X | Function to print the longest subarray with sum of elements not divisible by X.
Pref [ ] stores the prefix sum Suff [ ] stores the suffix sum.
If array element is divisibile by x.
Increase count.
If all the array elements are divisible by x.
No subarray possible.
Reverse v to calculate the suffix sum.
Calculate the suffix sum.
Reverse to original form.
Reverse the suffix sum array.
Calculate the prefix sum.
Stores the starting index of required subarray.
Stores the ending index of required subarray.
If suffix sum till i - th index is not divisible by x.
Update the answer.
If prefix sum till i - th index is not divisible by x.
Update the answer.
Print the longest subarray.
Driver code"
How can the above be solved in Python?
 Give me a code to longest subarray with sum not divisible by X and the other steps required?
assistant
#Here is code to longest subarray with sum not divisible by X and the other steps required.
 def max_length ( N , x , v ) :
	preff , suff = [ ] , [ ]
	ct = 0
	for i in range ( N ) :
		a = v [ i ]
		if a % x == 0 :
			ct += 1
	if ct == N :
		print ( - 1 )
		return
	v . reverse ( )
	suff . append ( v [ 0 ] )
	for i in range ( 1 , N ) :
		suff . append ( v [ i ] + suff [ i - 1 ] )
	v . reverse ( )
	suff . reverse ( )
	preff . append ( v [ 0 ] )
	for i in range ( 1 , N ) :
		preff . append ( v [ i ] + preff [ i - 1 ] )
	ans = 0
	lp = 0
	rp = N - 1
	for i in range ( N ) :
		if suff [ i ] % x != 0 and ans < N - 1 :
			lp = i
			rp = N - 1
			ans = max ( ans , N - i )
		if preff [ i ] % x != 0 and ans < i + 1 :
			lp = 0
			rp = i
			ans = max ( ans , i + 1 )
	for i in range ( lp , rp + 1 ) :
		print ( v [ i ] , end = " ▁ " )
x = 3
v = [ 1 , 3 , 2 , 6 ]
N = len ( v )
max_length ( N , x , v )