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Queries to find the maximum array element after removing elements from a given range | Function to find the maximum element after removing elements in range [ l , r ].
Store prefix maximum element.
Store suffix maximum element.
Prefix max till first index is first index itself.
Traverse the array to fill prefix max array.
Store maximum till index i.
Suffix max till last index is last index itself.
Traverse the array to fill suffix max array.
Store maximum till index i.
Traverse all queries.
Store the starting and the ending index of the query.
Edge Cases.
Otherwise.
Driver Code"
Solution in Python:
 What is a code to queries to find the maximum array element after removing elements from a given range and the other steps required?
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#Here is code to queries to find the maximum array element after removing elements from a given range and the other steps required.
 def findMaximum ( arr , N , Q , queries ) :
	prefix_max = [ 0 ] * ( N + 1 )
	suffix_max = [ 0 ] * ( N + 1 )
	prefix_max [ 0 ] = arr [ 0 ]
	for i in range ( 1 , N ) :
		prefix_max [ i ] = max ( prefix_max [ i - 1 ] , arr [ i ] )
	suffix_max [ N - 1 ] = arr [ N - 1 ]
	for i in range ( N - 2 , - 1 , - 1 ) :
		suffix_max [ i ] = max ( suffix_max [ i + 1 ] , arr [ i ] )
	for i in range ( Q ) :
		l = queries [ i ] [ 0 ]
		r = queries [ i ] [ 1 ]
		if ( l == 0 and r == ( N - 1 ) ) :
			print ( "0" )
		elif ( l == 0 ) :
			print ( suffix_max [ r + 1 ] )
		elif ( r == ( N - 1 ) ) :
			print ( prefix_max [ l - 1 ] )
		else :
			print ( max ( prefix_max [ l - 1 ] , suffix_max [ r + 1 ] ) )
if __name__ == ' _ _ main _ _ ' :
	arr = [ 5 , 6 , 8 , 10 , 15 ]
	N = len ( arr )
	queries = [ [ 0 , 1 ] , [ 0 , 2 ] , [ 1 , 4 ] ]
	Q = len ( queries )
	findMaximum ( arr , N , Q , queries )