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Number of occurrences of 2 as a digit in numbers from 0 to n | Counts the number of '2' digits in a single number.
Counts the number of '2' digits between 0 and n.
Initialize result.
Count 2 's in every number  from 2 to n.
Driver code"
Solution in Python:
assistant
#Here is code to number of occurrences of 2 as a digit in numbers from 0 to n and the other steps required.
 def number0f2s ( n ) :
	count = 0
	while ( n > 0 ) :
		if ( n % 10 == 2 ) :
			count = count + 1
		n = n // 10
	return count
def numberOf2sinRange ( n ) :
	count = 0
	for i in range ( 2 , n + 1 ) :
		count = count + number0f2s ( i )
	return count
print ( numberOf2sinRange ( 22 ) )
print ( numberOf2sinRange ( 100 ) )