human
What is a code to search an element in an unsorted array using minimum number of comparisons and the other steps required given the following:
Search an element in an unsorted array using minimum number of comparisons | function to search an element in minimum number of comparisons.
1 st comparison.
no termination condition and thus no comparison.
this would be executed at - most n times and therefore at - most n comparisons.
replace arr [ n - 1 ] with its actual element as in original 'arr[]  .
if ' x ' is found before the ' ( n - 1 ) th ' index , then it is present in the array final comparison.
else not present in the array.
Driver Code"
Solution in Python:
assistant
#Here is code to search an element in an unsorted array using minimum number of comparisons and the other steps required.
 def search ( arr , n , x ) :
	if ( arr [ n - 1 ] == x ) :
		return " Found "
	backup = arr [ n - 1 ]
	arr [ n - 1 ] = x
	i = 0
	while ( i < n ) :
		if ( arr [ i ] == x ) :
			arr [ n - 1 ] = backup
			if ( i < n - 1 ) :
				return " Found "
			return " Not ▁ Found "
		i = i + 1
arr = [ 4 , 6 , 1 , 5 , 8 ]
n = len ( arr )
x = 1
print ( search ( arr , n , x ) )