human
Min operations to reduce N to 1 by multiplying by A or dividing by B | Function to check if it is possible to convert a number N to 1 by a minimum use of the two operations.
For the Case b % a != 0.
Check if n equal to 1.
Check if n is not divisible by b.
Initialize a variable c.
Loop until n is divisible by b.
Count number of divisions.
Loop until n is divisible by c.
Count number of operations.
Check if n is reduced to 1.
Count steps.
Return the total number of steps.
Given n , a and b.
Function Call"
How can the above be solved in Python?
 Can you provide a code to min operations to reduce N to 1 by multiplying by A or dividing by B and the other steps required?
assistant
#Here is code to min operations to reduce N to 1 by multiplying by A or dividing by B and the other steps required.
 def FindIfPossible ( n , a , b ) :
	if ( b % a ) != 0 :
		if n == 1 :
			return 0
		elif ( n % b ) != 0 :
			return - 1
		else :
			return int ( n / b )
	c = b / a
	x = 0
	y = 0
	while ( n % b == 0 ) :
		n /= b
		x += 1
	while ( n % c == 0 ) :
		n /= c
		y += 1
	if n == 1 :
		total_steps = x + 2 * y
		return total_steps
	else :
		return - 1
n = 48
a = 3
b = 12
print ( FindIfPossible ( n , a , b ) )